What is the value of x?

What Is The Value Of X?

Answers

Answer 1

Answer:

14

Step-by-step explanation:

x+8=? x= 6. i do know it


Related Questions

PLEASE HELP ASAP!
What is the equation of the line that passes through the point (-4,8) and has a slope of -1?

Answers

The equation of the line that passes through the point (-4,8) and has a slope of -1 is y = -x +4

What is the equation of a line?

A line's equation is a unified representation of all of the line's points. Any point on a line will satisfy the equation in its general version, which is of the type ax + by + c = 0. The slope of the line and a point on the line are the two essential elements needed to create the equation of a line.

Here, we have

point (-4,8) and slope = -1

If we have a non-vertical line that passes through any point(x₁, y₁) and has a gradient m. then general point (x, y) must satisfy the equation

y-y₁ = m(x-x₁)

This is the required equation of a line in a point-slope form.

We know that Point-Slope Form:

y - y₁ = m(x- x₁)  

Where x₁ - x coordinate and y₁ - y coordinate

m - slope

Point (-4,8)

Then Slope m = -1

Now the equation as;

y - 8 = -1(x+4)

y  = -x -4+8

y = -x +4

Hence, the equation of the line that passes through the point (-4,8) and has a slope of -1 is; y = -x+4

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Before sending track and field athletes to the Olympics, the U.S. holds a qualifying meet.
The upper box plot shows the top
12
1212 men's long jumpers at the U.S. qualifying meet. The lower box plot shows the distances (in meters) achieved in the men's long jump at the
2012
20122012 Olympic games.
2 horizontal boxplots titled U.S. Qualifier and Olympics are graphed on the same horizontal axis, labeled Distance, in meters. The boxplot titled U.S. Qualifier has a left whisker which extends from 7.68 to 7.7. The box extends from 7.7 to 7.89 and is divided into 2 parts by a vertical line segment at 7.74. The right whisker extends from 7.9 to 7.99. The boxplot titled Olympics has a left whisker which extends from 7.7 to 7.83. The box extends from 7.83 to 8.12 and is divided into 2 parts by a vertical line segment at 8.04. The right whisker extends from 8.12 to 8.31. All values estimated.
Which pieces of information can be gathered from these box plots?

Answers

These box plots allow us to compare the distribution of distances achieved in the men's long jump at the U.S. qualifying meet and the Olympic games, and to see how they differ in terms of range, IQR, median, and distribution.

We have,

From these box plots,

We can gather the following pieces of information:

- The range of distances achieved in the men's long jump at both the U.S. qualifying meet and the Olympic games.

For the U.S. qualifier, the range is from approximately 7.68 meters to 7.99 meters.

For the Olympics, the range is from approximately 7.7 meters to 8.31 meters.

- The interquartile range (IQR) of distances achieved in the men's long jump at both the U.S. qualifying meet and the Olympic games.

For the U.S. qualifier, the IQR is from approximately 7.7 meters to 7.89 meters.

For the Olympics, the IQR is from approximately 7.83 meters to 8.12 meters.

- The median distance achieved in the men's long jump at both the U.S. qualifying meet and the Olympic games.

For the U.S. qualifier, the median is approximately 7.74 meters.

For the Olympics, the median is approximately 8.04 meters.

- The distribution of distances achieved in the men's long jump at both the U.S. qualifying meet and the Olympic games.

For the U.S. qualifier, the distances achieved are relatively tightly clustered around the median, with a few outliers on both ends.

For the Olympics, the distances achieved are more spread out, with a few outliers on the high end.

Thus,

These box plots allow us to compare the distribution of distances achieved in the men's long jump at the U.S. qualifying meet and the Olympic games, and to see how they differ in terms of range, IQR, median, and distribution.

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Answer: A

Step-by-step explanation: Khan

suppose x is normally distributed with mean 5 and standard deviation 4 find each of the following probablties

Answers

If  x is normally distributed with mean 5 and standard deviation 4, the probabilities are

a) P(X < 3) =  0.3085.

b)  P(X > 8) = 0.2266.

c) P(1 < X < 9) = 0.6826.

We need to use the standard normal distribution to solve these problems, so we will first standardize the variable x.

Let Z be the standard normal random variable, then

Z = (X - μ) / σ

where μ = 5 and σ = 4.

a) P(X < 3)

Standardizing, we have

Z = (3 - 5) / 4 = -0.5

Using a standard normal table or calculator, we find that P(Z < -0.5) = 0.3085.

Therefore, probabilities of P(X < 3) = 0.3085.

b) P(X > 8)

Standardizing, we have

Z = (8 - 5) / 4 = 0.75

Using a standard normal table or calculator, we find that P(Z > 0.75) = 0.2266.

Therefore, P(X > 8) = 0.2266.

c) P(1 < X < 9)

Standardizing, we have

Z1 = (1 - 5) / 4 = -1

Z2 = (9 - 5) / 4 = 1

Using a standard normal table or calculator, we find that P(Z < -1) = 0.1587 and P(Z < 1) = 0.8413.

Therefore, P(1 < X < 9) = P(-1 < Z < 1) = P(Z < 1) - P(Z < -1) = 0.8413 - 0.1587 = 0.6826.

Your question is incomplete but most probably your full question was

Suppose x is normally distributed with mean 5 and standard deviation 4 find each of the following probabilities

a) P(X < 3)

b) P(X > 8)

c) P(1 < X < 9)

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solve for x, please

solve for x, please

Answers

Answer:

x = 20

Step-by-step explanation:

4x + 20

60 + 20 = 80

80 ÷ 4 = 20

x = 20

I need help with this

I need help with this

Answers

there is no hole bc you aren’t having to cancel anything out

Mrs. Jean said that 4/12 of the test items are multiple choice, 5/12 or short answer and the rest are matching. What fraction of these items are either multiple choice or short answer

Answers

Answer:

3/4

Step-by-step explanation:

THE fraction of these items are either multiple choice or short answer would be the sum of the fractions of the multiple choice and short answer

4/12 + 5 / 12 = 9/12

to simplify , divide both numerator and denominator by 3

3/4

Evaluate the given integral Q. = f ²* f+ (x − y2³²) dy dz dx - 0 0 Your answer 2. Give the (upper, lower, lateral) boundaries of the solid S of integration of the integral Q in No. 1.

Answers

The Upper, Lower and Lateral Boundaries of the solid S of integration of the integral Q is given as: Upper Boundaries: $z = \sqrt{1-x^2}$ Lower Boundaries: $z = 2 - x - y$ Lateral Boundaries: $x^2 + y^2 = 1$, $x + y + z = 2$

Given Integral : $Q = \int\int\int_S f^2f+(x-y^{2^3})dV$Upper, Lower and Lateral Boundaries of the Solid S of Integration for the Integral QThe integral Q is expressed as $Q = \int\int\int_S f^2f+(x-y^{2^3})dV$ which is a volume integral. For the calculation of a triple integral, a three-dimensional region is necessary. Therefore, the solid S of integration needs to be defined. Lower and Upper Boundaries :The equation of the plane is given by $x + y + z = 2$The cylinder is given by $x^2 + y^2 = 1$.

Using cylindrical polar coordinates, the integral becomes $Q = \int_{0}^{2\pi} \int_{0}^{1} \int_{z = 2 - x - y}^{ \sqrt{1-x^2} } f^2f+(x-y^{2^3}) r dz dr d\theta$. The integration of Q with respect to z is done with respect to the plane's lower boundary at $z = 2 - x - y$ and the upper boundary at $z = \sqrt{1-x^2}$The integration with respect to x and y is carried out over the lateral region of the solid S. The cylinder is defined as $x^2 + y^2 = 1$ and the plane is defined as $x + y + z = 2$. When z is 0, the plane intersects the xy-plane, and when x is 0, the plane intersects the yz-plane. When y is 0, the plane intersects the xz-plane.

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HELP
WILL MARK DOWN BRAINLIEST

HELP WILL MARK DOWN BRAINLIEST

Answers

Answer:

i think b

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

slope = m = rise/run

slope/m= 50/2 = 25

so it has to have 25x in the answer which is C

it has nothing adding to it because it's y-intercept is 0 which doesn't need to be written

I need help asap please I’ll give you brainlest

I need help asap please Ill give you brainlest

Answers

Answer:

B

Step-by-step explanation:

Trust me

It Table b I’m sure of it

Pleasee helppp answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!

Pleasee helppp answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!

Answers

Answer:

5y 6x

-7y 1x

Step-by-step explanation:

Divide.

five-eights divded by two-thirds?

Answers

Answer:15/16 or 0.9375

The temperature at 10 A.M. is 12 degrees Fahrenheit. The temperature at 6:00 A.M.
was -7
degrees Fahrenheit. How many degrees did the temperature rise?

Answers

Answer:

19 degrees Fahrenheit.

Step-by-step explanation:

19-7=12

An audience of 120 people are watching a magician.
The ratio of males to females in the audience is 3:2
The magician chooses three members of the
audience at random to help him.
What is the probability that the first person picked
will be female?
(write your answer as a decimal number)

Answers

The probability that the first person picked will be female is 2/5.

Explain the term ratio of numbers?

Two quantities are compared to form a ratio. Discover how to calculate the ratio of two items, such as apples to oranges.

Total audience = 120

Ratio of males to females; 3:2

Total males : 3*120/ 5 = 72

Total females: 2*120/5 = 48

Probability that the first person picked will be female = total females / total audience

Probability = 48 / 120

Probability = 2/5

Thus, the probability that the first person picked will be female is 2/5.

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HELP :)
Find the Domain and Range of the following Relation.(Add 1 space after your domain answer)

1. {(3,5), (4,15), (5,20), (6,25), (7,30)
2. {(-1,2), (-1,4), (-1,6), (-1,8), (-1,10)}
3. {(-6,1), (-5,0), (-4,-1), (-3,-2), (-2,-3)}​

Answers

The domain and range of each given relation is:

1. Domain - {3, 4, 5, 6, 7}

Range - {5, 15, 20, 25, 30}

2. Domain - {-1}

Range - {2, 4, 6, 8, 10}

3. Domain - {-6, -5, -3, -2}

Range - {1, 0, -1, -2, -3}

What is the Domain and Range of a Relation?A pair of values of a relation is represented as (x, y).The domain of a relation consists of all x-values.Range consist of all y-values.

Thus, the domain and range of each given relation is:

1. Domain - {3, 4, 5, 6, 7}

Range - {5, 15, 20, 25, 30}

2. Domain - {-1}

Range - {2, 4, 6, 8, 10}

3. Domain - {-6, -5, -3, -2}

Range - {1, 0, -1, -2, -3}

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Answers for 18 , 19 , and 20 please (urgent)

Answers for 18 , 19 , and 20 please (urgent)

Answers

Answer:

150

adjacent (probably)

90-30 = abf

Step-by-step explanation:

Answer:

18 =150°. 19=it is angle between two straight line. 20=180-90+30

A golfer hit a golf ball from a tee box that is 6 yards above the ground. The graph shows the height in yards of the golf ball above the ground as a quadratic function of x, the horizontal distance in yards of the golf ball from the tee box. What is the domain of the function for this situation?

Answers

Answer: C. 0 ≤ x ≤ 230

When the  A golfer hit a golf ball from a tee box that is 6 yards above the ground so the domain of the function is [0,260].

Calculation of the domain of the equation:

Here the domain is the values of 'x' in the function f(x).

the position at which the golfer is hit the ball is (0,6) and the position where the ball hits the ground is (230,0)

So, the domain of the function for this situation is [0,260].

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y=−29x+3 in standard form using integers

Answers

Standard form Ax + Bx = C
Subtract y and 3 from both sides
-29x - y = -3

pls say the right answer

pls say the right answer

Answers

The completed table showing the features of different metals and non-metals has been attached as image.

Explanation of Features

- Sonorous: Metals like iron and copper are sonorous, meaning they produce a ringing sound when struck. Non-metals like phosphorus and sulphur are not sonorous.

- Ductile/Malleable: Metals such as iron, copper, and aluminium are ductile and malleable, which means they can be stretched into wires (ductile) and hammered into thin sheets (malleable). Non-metals like phosphorus and sulphur are not ductile or malleable.

- Conducts Electricity: Metals, including iron, copper, aluminium, and gold, are good conductors of electricity. They allow electric current to flow through them. Non-metals like phosphorus and sulphur are poor conductors of electricity.

- Lustre: Metals exhibit a characteristic metallic lustre, reflecting light and appearing shiny. Non-metals like phosphorus and sulphur do not have a metallic lustre.

- Brittle: Metals such as iron, copper, and gold are not brittle and can withstand deformation without breaking easily. Non-metals like phosphorus and sulphur are brittle, meaning they are prone to breaking or shattering when subjected to stress.

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pls say the right answer

what is 16 / 8 x 2^2

Answers

Answer:

8

Step-by-step explanation:

16/8 × 2²

= 2 × 4

= 8

hope this helps

Step-by-step explanation:

16/8 ×2^2

=16/8 × 4

=2 × 4

=8

If Cos A = 9/41 and tan B = 28/45 angle A and B are in quadrant I find the value of Tan(A+B)

Answers

Answer: i just need points
Explanation: i need points so 3/4572

What is the slope? What is the y-intercept? What is the equation of the line (slope intercept form?)

What is the slope? What is the y-intercept? What is the equation of the line (slope intercept form?)

Answers

Answer:

                The slope is: m = -²/₅

               The y-intercept is:  b = -2

               The equation of the line: y = -²/₅x - 2

Step-by-step explanation:

  The equation of a line in slope intercept form: y = mx + b

The slope:   \(m=\dfrac{y_2-y_1}{x_2-x_1}\)

(-5, 0)   ⇒  x₁ = -5,  y₁ = 0

(0, -2)   ⇒  x₂ = 0,  y₂ = -2

So:

     \(m=\dfrac{-2-0}{0-(-5)}=-\dfrac25\)

Idil is deciding between two different movie streaming sites to subscribe to. Plan A costs $18 per month plus $1 per movie watched. Plan B costs $8 per month plus $3 per movie watched. Let AA represent the monthly cost of Plan A if Idil watches x per month, and let B represent the monthly cost of Plan B if Idil watches x movies per month. Write an equation for each situation, in terms of x, and determine which plan would be cheaper if Idil plans on watching 6 movies each month.

Answers

The cheaper plan here would be plan A. The equation that is written in terms of the plans on movies is  0 < x < 5

How to solve the equation

For the plan A, we would have the function to be given as

A = 1x + 18

This is due to thge fact that this plan is said to cost  $18 per month plus $1 per movie watched.

For plan B the function would have to be:

B = 3x + 8

The equation that we would have here would be

1x + 18 <  3x + 8

= x - 3x < 8 - 18

= -2x < -10

x < 5

Hence we would have the equation as 0 < x < 5

Cheaper plan

1x6 + 18  = 24

3x 6+ 8 = 18 + 8 = 26

Plan A id cheaper

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4x+7y=83 and 5+6y=90 solved by substion

Answers

Why is there no x value

PLS HELP ASAP IDK ‍♀️

PLS HELP ASAP IDK

Answers

Answer:

Multiply by 6. x should equal 24.

Step-by-step explanation:

im different ¯\_(ツ)_/¯

Sutton is working as at a nonprofit where the hourly salary is 23 dollars per hour. If the nonprofit announces that it will be decreasing the salary of employees by 14% , then what is Sutton's new wage?

Answers

Answer:

400 is the answer for this math question

Step-by-step explanation:

So find out Sutton’s new wage we need to know what is 14% of 23 is.

So, we do 23 * 0.14 = 3.22

14% of 23 is 3.22

Now we subtract that 14% from 23:

23 - 3.22 = 19.78

Sutton’s new wage is $19.78

Identify the area of the figure rounded to the nearest tenth

Identify the area of the figure rounded to the nearest tenth

Answers

Answer:

118.7 inches squared.

Step-by-step explanation:

What is the area?

The area is the total space taken up by a flat (2-D) surface or shape. The area is always measured in square units.

What is diameter?

Diameter is the length across the entire circle, the line splitting the circle into two identical semicircles.

The expression for solving the area of a circle is A = π × \(r^{2}\).

To solve for the semicircle above, we can divide the diameter into 2 to get the radius.

12 ÷ 2 = 6

So, the radius of the upper semicircle is 6 inches.

If the radius of a circle is 6 inches, then you can substitute r for 6 into the formula.

A = π × \(6^{2}\)

This simplifies to A = 36π. If a semicircle if half the size of a normal circle, then it will be A = 18π, because 36 ÷ 2 = 18.

To solve for the lower semicircle, we can do the same this as we did above.

A = π × \(r^{2}\)

But wait, we don't know the radius or diameter!

No worries! To solve for the diameter of the circle, we can take the line that is parallel to the semicircle (the one that has a length of 12in) and subtract 6 from it. We subtract 6 from it because the semicircle takes up the remaining length of the line, not including the 6in.

To solve for the lower semicircle, we can divide the diameter by 2 to get the radius.

6 ÷ 2 = 3

So, the radius of the circle is 3.

Now we can insert 3 into the expression.

A = π × \(3^{2}\)

This simplifies to A = 9π. If a semicircle if half the size of a normal circle, then it will be A = 4.5π because like above, 9 ÷ 2 = 4.5.

Adding the two semicircles together:

18π + 4.5π = 22.5π22.5 × π ≈ 70.6858

So, the area of both semicircles is approximately 70.6858 square inches.

To solve for the area of a rectangle we use the expression:

A = length × width

Inserting the dimensions of the rectangle:

8 × 6 = 48

So, the area of the rectangle is 48 square inches.

Adding the two areas together:

70.6858 + 48 = 118.6858 ≈ 118.7

Therefore, the area of the entire figure, rounded to the nearest tenth is \(118.7\) \(in^{2}\).

Branden and Janna are analyzing the same conditional statement. Branden finds multiple examples that validate the conditional statement. Janna finds one example that satisfies the hypothesis of the conditional statement, but not the conclusion. Which must be true? The conditional statement is true. There are more examples that validate the statement than there are that do not. The conditional statement is true. There is at least one example that validates the statement. The conditional statement is false. There is at least one counterexample for the statement. The conditional statement is false. There must be exactly one example that validates the statement.

Answers

Answer:

C. The conditional statement is false. There is at least one counterexample for the statement.  

Step-by-step explanation:

took the quiz

Chapter 7 of the jiuzhang suanshu presents a problem of two linear equations involving acres of land and their respective prices. one of the two equations can be translated to:

Answers

Chapter 7 of the Jiuzhang Suan Shu presents a problem involving two linear equations related to acres of land and their prices. One of the equations can be translated as:

Let "x" represent the number of acres of land.
Let "y" represent the price of the land per acre.

The equation can be written as: y = 20x + 150.

In this equation, the coefficient of "x" is 20, which represents the rate at which the price of the land increases per acre. The constant term of 150 represents the initial price of the land.

To solve this equation, you can substitute different values for "x" and find the corresponding values of "y". This will give you pairs of values (x, y) that satisfy the equation. For example, if you substitute x = 5, you would get y = 20(5) + 150 = 250.

By solving the equation in this manner, you can generate multiple pairs of values that represent different combinations of acres and prices. This helps in understanding the relationship between the two variables and can be used to make predictions or solve related problems.

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The length of a planet's orbit around a star is approximately 22,200,000 km. It takes the planet about 1230 Earth days to complete a full orbit. What is the planet's average speed in kmh-1 to 3sf?​

Answers

Answer:

Approximately \(12.9\; \rm km \cdot h^{-1}\), assuming that this orbit is circular.

Step-by-step explanation:

The question is asking for a tangential velocity with the unit \(\rm km \cdot h^{-1}\). The unit of the given distance is already in \(\rm km\) as required. Convert the unit of the orbital period to hours:

\(\begin{aligned}T &= 1230\; \text{day} \times \frac{24\; \rm h}{1\; \text{day}}. = 29520\; \rm h\end{aligned}\).

Calculate the angular velocity \(\omega\) of this planet from its orbital period:

\(\begin{aligned}\omega &= \frac{2\, \pi}{T} \\ &= \frac{2\, \pi}{29520\; \rm h} \approx 2.1285 \times 10^{-4}\; \rm h^{-1}\end{aligned}\).

Given the radius \(r\) of the orbit of this planet, the tangential velocity \(v_{\perp}\) of this planet would be:

\(\begin{aligned}v_{\perp} &= \omega\, r \\ &\approx 2.1285 \times 10^{-4}\; \rm h^{-1} \times 2.22\times 10^{7}\; \rm km \\ &\approx 4.73 \times 10^{3}\; \rm km \cdot h^{-1}\end{aligned}\).

If the orbit of this planet is circular, the velocity of the planet would be equal to its tangential velocity: \(4.73\times 10^{3}\; \rm km \cdot h^{-1}\).

7^2 + 4^3 ÷ 2^5
Lol please help

Answers

Answer:

51

Step-by-step explanation:

Answer: Your answer will be 51.

Hope this helps good luck!

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