What is the value of k in the equation k/3-5=34

Answer: A

Step-by-step explanation:

We can use the logarithmic identity logb(a^n) = n*logb(a) to solve this problem.

First, we need to express 4 as a power of 2. We know that 2^2 = 4, so we can write:

log4 = log2^2

Then we can use the identity to rewrite this as:

log4 = 2*log2

Now we can use the given approximation log2 ≈ 0.4307 to approximate log4:

log4 ≈ 2 * 0.4307

log4 ≈ 0.8614

Therefore, the answer is (A) 0.8614.

9514 1404 393

Answer:

  a) attached

  b) 100 square inches, 1/4 of the total

  c) square root of area

  d) multiply by 4

Step-by-step explanation:

a) A diagram is attached

__

b) If the total area consists of 4 squares of the same size, then the area of one square will be 1/4 of the total area. 1/4 of 400 square inches is 100 square inches, the area of one square.

__

c) The area of a square is the square of the side length. You find the side length by finding the square root of the area. √(100 in²) = 10 in, the side length of each square.

__

d) The rectangle is 4 squares laid side by side, so its length is 4 times the side length of one square: 4×10 in = 40 in.

We want to determine the 40 percent of 70, so we have to multiply 70 by 40%:

Answer:

The probability plot of this distribution shows that it is approximately normally distributed..

Check explanation for the reasons.

Step-by-step explanation:

The complete question is attached to this solution provided.

From the cumulative probability plot for this question, we can see that the plot is almost linear with no points outside the band (the fat pencil test).

The cumulative probability plot for a normal distribution isn't normally linear. It's usually fairly S shaped. But, when the probability plot satisfies the fat pencil test, we can conclude that the distribution is approximately linear. This is the first proof that this distribution is approximately normal.

Also, the p-value for the plot was obtained to be 0.541.

For this question, we are trying to check the notmality of the distribution, hence, the null hypothesis would be that the distribution is normal and the alternative hypothesis would be that the distribution isn't normal.

The interpretation of p-valies is that

When the p-value is greater than the significance level, we fail to reject the null hypothesis (normal hypothesis) and but if the p-value is less than the significance level, we reject the null hypothesis (normal hypothesis).

For this distribution,

p-value = 0.541

Significance level = 0.05 (Evident from the plot)

Hence,

p-value > significance level

So, we fail to reject the null or normality hypothesis. Hence, we can conclude that this distribution is approximately normal.

Hope this Helps!!!

Answer:

C

Step-by-step explanation:

Points are written as (x,y)

So in (4,-1) x = 4 and y = -1

Looking at a graph if you go to the right 4 units the x axis and down one unit you will be at point (4,-1)

The graph that shows this would be c

Answer:

According to the Central Limit Theorem, the sampling distribution of sample means would have a mean of 5.4 years.

Step-by-step explanation:

For a normally distributed random variable X, with mean and standard deviation, the sampling distribution of sample means with size n can be approximated to a normal distribution with mean and standard deviation.

As long as n is at least 30, the Central Limit Theorem can also be applied to skewed variables.

We have the following problem:

Answer:

Step-by-step explanation:

The mean of the sampling distribution of sample means can be calculated using the formula:

μM = μ

where μ is the population mean and M is the sample mean.

Thus, μM = μ = 5.4 years.

Therefore, the mean of the sampling distribution of sample means would also be 5.4 years.

==============================================================

Explanation:

f(x) is equal to both x^2-2x+3 and also -6x at the same time. Set those two expressions equal to one another and solve for x.

x^2-2x+3 = -6x

x^2-2x+3+6x = 0

x^2+4x+3 = 0

(x+3)(x+1) = 0 .... see note below

x+3 = 0 or x+1 = 0

x = -3 or x = -1

Note: 3 and 1 multiply to 3, and also add to 4.

---------------------

Once we get the x values, we plug them into either equation to find the y value.

So if x = -3, then

f(x) = x^2-2x+3

f(-3) = (-3)^2-2(-3)+3

f(-3) = 9 + 6 + 3

f(-3) = 18

or we could say

f(x) = -6x

f(-3) = -6(-3)

f(-3) = 18

Both versions produce the same output when x = -3.

The second version is easier to work with.

Since x = -3 leads to y = 18, we know that (-3, 18) is one of the solutions. That explains where your teacher got (-3, 18) from.

-----------

We'll use this idea for x = -1 now

f(x) = x^2-2x+3

f(-1) = (-1)^2-2(-1)+3

f(-1) = 1 + 2 + 3

f(-1) = 6

or we could say

f(x) = -6x

f(-1) = -6(-1)

f(-1) = 6

Like before, both versions of f(x) produce the same output when the input is x = -1.

The other solution is (-1, 6)

Answer: -2

I hope this helps and may God bless you! Have a nice day, bye! :)

Answer:

Its about a 16 percent decrease

The population in 2019 would be about 160,080

Step-by-step explanation:

So To find percent change you just do \(\frac{new-old}{old}\). No wwe get about 16 percent

Now to find the population just multipy the latest one by 0.16 and use that product to add to the population in 2013 and you’ll get 160,080

Answer:

no ;)

Step-by-step explanation:

Answer:

8.15

Step-by-step explanation:

We have 4 quoters in an hour. 15, 30, 45, 60(00)

so 09 minutes is closer to 15 than to 00. making 8.15 the correct answer.

The supplement of BIE equals the supplement of GMD is a false assertion if lines BG and CF are parallel.

Angles with a supplementary sum are those whose sum is 180 degrees. For instance, the total of angle 130° and angle 50° is 180°, hence they are supplementary angles.

Lines BG and CF are parallel, as shown in the figure.

If BIE = X, then its supplement of BIE will be 180 - X;

similarly, if GMD = Y, then its supplement of GMD will be 180 - Y.

Since BG and CF are parallel, the supplements of BIE and GMD are interior angles on the same side ( as shown in figure)

and for parallel line the interior angle on the same side is 180

so 180 - X and 180 -Y there sum should be 180

They cannot be equal

line BG and CF are parallel, then the supplement of BIE = the supplement of GMD are not equal.

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The value of x from the triangle is 12

Given the sides as;

Using the Pythagorean theorem

Hypotenuse square = opposite square + adjacent square

Substitute the value, we have;

15² = x ² + 9²²

Find the squares

225= x² + 81

collect like terms

225 - 81 = x²

144 = x²

Take the square root of both sides

x √144

x = 12

Thus, the value of x from the triangle is 12

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Answer:

The point estimate for the true difference between the population means is 0.13.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

Step-by-step explanation:

To solve this question, before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When we subtract two normal variables, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 263 cars owned by students had an average age of 7.25 years. The population standard deviation for cars owned by students is 3.77 years.

This means that:

\(\mu_s = 7.25, \sigma_s = 3.77, n = 263, s_s = \frac{3.77}{\sqrt{263}} = 0.2325\)

A sample of 291 cars owned by faculty had an average age of 7.12 years. The population standard deviation for cars owned by faculty is 2.99 years.

This means that:

\(\mu_f = 7.12, \sigma_f = 2.99, n = 291, s_f = \frac{2.99}{\sqrt{291}} = 0.1753\)

Difference between the true mean ages for cars owned by students and faculty.

Distribution s - f. So

\(\mu = \mu_s - \mu_f = 7.25 - 7.12 = 0.13\)

This is also the point estimate for the true difference between the population means.

\(s = \sqrt{s_s^2+s_f^2} = \sqrt{0.2325^2+0.1753^2} = 0.2912\)

90% confidence interval for the difference:

We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\(\alpha = \frac{1 - 0.9}{2} = 0.05\)

Now, we have to find z in the Ztable as such z has a pvalue of \(1 - \alpha\).

That is z with a pvalue of \(1 - 0.05 = 0.95\), so Z = 1.645.

Now, find the margin of error M as such

\(M = zs = 1.645*0.2912 = 0.48\)

The lower end of the interval is the sample mean subtracted by M. So it is 0.13 - 0.48 = -0.35 years

The upper end of the interval is the sample mean added to M. So it is 0.13 + 0.48 = 0.61 years.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

Answer:

The two answers on the first row are correct

Step-by-step explanation:

PLATO

Answer:

5.5

7.5 =

h

23.5

7.5h = 129.25

h = 17.2

3

The flagpole is 17.2 feet long.

The measure of height of flagpole is 40.25 feet.

Given that, a flagpole casts a shadow that is 23 feet long.

Heights and Distances is a study about the applications of Trigonometry. It has many real-life applications, such as measuring the object’s height, depth of the object, the distance between two celestial objects etc. The formulas and the ratios of trigonometry are helpful in the study of heights and distances.

Jorge is 5.25 feet tall, and while standing near the flagpole he casts a shadow that is 3 feet long.

Let the height of the flagpole be x.

Now, tan θ=5.25/3 -------(I)

and tan θ=x/23 -------(II)

Equation (I)=(II), we get

5.25/3 = x/23

⇒ 3x=5.25×23

⇒ 3x=120.75

⇒ x=120.75/3

⇒ x=40.25 feet

Therefore, the measure of height of flagpole is 40.25 feet.

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The inequality in vertex form represents the region containing the results of the year is y < -2(x - 25)² + 200 option (D) is correct.

It is defined as the graph of a quadratic function that has something bowl-shaped.

(x - h)² = 4a(y - k)

(h, k) is the vertex of the parabola:

a = √[(c-h)² + (d-k²]

(c, d) is the focus of the parabola:

From the graph:

The vertex is:

(25, 200)

The vertex form of the parabola:

y = a(x - h)² + k

y = a(x - 25)² + 200

Plug x = 30 and y = 150

a = --2

y = -2(x - 25)² + 200

The inequality will be:

y < -2(x - 25)² + 200

Thus, the inequality in vertex form represents the region containing the results of the year is y < -2(x - 25)² + 200 option (D) is correct.

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Answer:

(5,-3)

Step-by-step explanation:

Given that,

The coordinates of Q = (3,1)

The midpoint of QR = (4,-1)

We need to find the coordinates of point R.

We know that, according to mid-point theorem,

\((x_m,y_m)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})\)

Let (x₂,y₂) be the coordinates of point R.

So,

\((4,-1)=(\dfrac{3+x_2}{2},\dfrac{1+y_2}{2})\\\\\dfrac{3+x_2}{2}=4\ and\ \dfrac{1+y_2}{2}=-1\\\\3+x_2=8\ and\ y_2+1=-2\\\\x_2=5\ and\ y_2=-3\)

So, the coordinates of point R is (5,-3).

Answer:

\(Opposite = Adjacent= 5\)

Step-by-step explanation:

Given

\(Hypotenuse^2 = 50\)

\(Opposite = Adjacent\)

Required

Find the length of each leg

This is calculated using Pythagoras Theorem

\(Opposite^2 + Adjacent^2 = Hypotenuse^2\)

\(Opposite^2 + Adjacent^2 = 50\)

Represent the opposite and adjacent with x

\(x^2 + x^2= 50\)

\(2x^2 = 50\)

Divide both sides by 2

\(x^2 = 25\)

Take square roots

\(x = 5\)

Hence:

\(Opposite = Adjacent= 5\)

Answer:

y = x + 1

Step-by-step explanation:

Parallel lines have same slope.

y = x - 1

Compare with the equation of line in slope y-intercept form: y = mx +b

Here, m is the slope and b is the y-intercept.

m =1

Now, the equation is,

         y = x + b

The required line passes through (-3 ,-2). Substitute in the above equation and find y-intercept,

        -2 = -3 + b

  -2 + 3 = b

         \(\boxed{b= 1}\)

    Equation of line in slope-intercept form:

                  \(\boxed{\bf y = x + 1}\)      

The equation is :

Solution:

If two lines are parallel to each other, then their slopes are equal. The slope of y = x - 1 is 1. Hence, the slope of the line that is parallel to that line is 1.

We shouldn't forget about a point on the line : (-3, -2).

I plug that into a point-slope which is :

\(\sf{y-y_1=m(x-x_1)}\)

Slope is 1 so

\(\sf{y-y_1=1(x-x_1)}\)

Simplify

\(\sf{y-y_1=x-x_1}\)

Now I plug in the other numbers.

-3 and -2 are x and y, respectively.

\(\sf{y-(-2)=x-(-3)}\)

Simplify

\(\sf{y+2=x+3}\)

We're almost there, the objective is to have an equation in y = mx + b form.

So now I subtract 2 from each side

\(\sf{y=x+1}\)

From the given equation, the value of b is, \(b = \frac{v}{h}\).

What is volume?

Each thing in three dimensions takes up some space. The volume of this area is what is being measured. The space occupied within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.

The given equation is,  V = bh

where, b is the base area and h is the height.

To solve the equation for b.

Dividing both sides by h, we get

\(\frac{V}{h} = \frac{bh}{h}\)

\(\frac{V}{h} = b\\ b = \frac{V}{h}\)

Therefore, the value of b is, \(b = \frac{v}{h}\).

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Answer:

16.6666666667

Step-by-step explanation:

Answer: 50/3 or 16 2/3 or 16.67

Step-by-step explanation:

Given

18-3k÷9

Substitute [k] value into the given expression

 18-3k÷9

=18-3(4)÷9 ⇒ Substitute the value

=18-12÷9 ⇒ Expand the parenthesis

=18-4/3 ⇒ First do division

=54/3-4/3 ⇒ Convert an integer into a fraction

=50/3=16 2/3=16.67

Hope this helps!! :)

Please let me know if you have any questions

This is the graph of a quadratic function.

The y-intercept of the graph is the function value y = 0.

The x-intercepts of the graph (in order from least to greatest) are located at x = 0 and x = 6.

The greatest value of y is y = 9.

For x between x = 0 and x = 6, the function value y > 0.

In Mathematics, the graph of a quadratic function always form a parabolic curve or arc because it is u-shaped. Based on the graph of this quadratic function, we can logically deduce that the graph is a downward parabola because the coefficient of x² is negative and the value of "a" is greater than zero (0).

The y-intercept of the graph is represented by (0, 0) and the x-intercepts of the graph listed in order from least to greatest are located at the following points;

x = 0 ⇒ (0, 0)

x = 6 ⇒ (0, 6).

The greatest value or vertex (maximum value) of y is at y = 9. For x between x = 0 and x = 6, the function value y is always greater than 0.

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\( - 13 = \frac{w}{9} - 6 \\ - 13 + 6 = \frac{w}{9} \\ - 7 = \frac{w}{9} \\ w = - 63\)

so only -63 is the solution, the rest three are NOT solution for this equation.

The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

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The students answered 150 questions correctly in total based on proportions concept if points are given.

If the first paper scored 30 points and the second scored 50 points, then the total score is 30 + 50 = 80 points. Since each question answered correctly is worth 2 points, we can divide the total score by 2 to find the number of questions answered correctly altogether.

80 / 2 = 40

Therefore, the students answered 40 questions correctly in total.

Another way to approach this problem is to use proportions. Let's say that the number of questions answered correctly on the first paper is x, and the number of questions answered correctly on the second paper is y. Then we can set up a proportion:

x/15 + y/25 = 1

where 15 and 25 are the total number of questions on each paper, and 1 represents the total proportion of questions answered correctly.

Multiplying LHS and RHS by least common multiple of 15 and 25, which is 75:

5x + 3y = 75

If we know that x = 30 and y = 50, we substitute these values into equation and check that if its true:

5(30) + 3(50) = 150 + 150 = 300

Dividing sides by 2 to get:

300 / 2 = 150

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Answer:

\(\begin{aligned}SA &= 7.125\pi \text{ in}^2\\& \approx 22.4 \text{ in}^2 \end{aligned}\)

Step-by-step explanation:

We can find the Surface Area of the can by adding the areas of each of its parts:

\(SA = 2( A_{\text{base}}) + A_\text{side}\)

First, we can calculate the area of the circular base:

\(A_{\text{circle}} = \pi r^2\)

\(A_{\text{base}} = \pi (0.75 \text{ in})^2\)

\(A_{\text{base}} = 0.5625\pi \text{ in}^2\)

Next, we can calculate the area of the rectangular side:

\(A_\text{rect} = l \cdot w\)

\(A_\text{side} = (4\text{ in}) \cdot C_\text{base}\)

Since the width of the side is the circumference of the base, we need to calculate that first.

\(C_\text{circle} = 2 \pi r\)

\(C_\text{base} = 2 \pi (0.75 \text{ in})\)

\(C_\text{base} = 1.5 \pi \text{ in}\)

Now, we can plug that back into the equation for the area of the side:

\(A_\text{side} = (4\text{ in}) (1.5\pi \text{ in})\)

\(A_\text{side} = 6\pi \text{ in}^2\)

Finally, we can solve for the surface area of the can by adding the area of each of its parts.

\(SA = 2( A_{\text{base}}) + A_\text{side}\)

\(SA = 2(0.5625\pi \text{ in}^2) + 6\pi \text{ in}^2\)

\(\boxed{SA = 7.125\pi \text{ in}^2}\)

\(\boxed{SA \approx 22.4 \text{ in}^2}\)