What is the value of g 0?

Answer:

its c

Step-by-step explanation:

i promise you

Answer:

Its c

Step-by-step explanation:

The interval of time for which the height of the ball greater than or equal to 52 feet is  [1 , 3] .

In the question ,

it is given that ,

The equation that model the path of ball after Carl hit it is -16t² + 64t + 4 .

we have to find the interval of time ,

where the height of the ball is greater than or equal to 52 feet,

that is represented as

-16t² + 64t + 4 ≥ 52

-16t² + 64t + 4 - 52 ≥ 0

-16t² + 64t - 48 ≥ 0

multiplying both sides of the inequality by 9-1) , we get

16t² - 64t + 48 ≤ 0

Dividing both sides of the inequality by 16 , we get

t² - 4t + 3 ≤ 0

t² - 3t - t + 3 ≤ 0

t(t - 3) -1(t - 3) ≤ 0

(t - 1)(t - 3) ≤ 0

which means

1 ≤ t ≤ 3 , and is represented as  [1 , 3] .

Therefore , The interval of time for which the height of the ball greater than or equal to 52 feet is  [1 , 3] .

The given question is incomplete , the complete question is

During baseball practice, Carl hit a ball into outfield. The equation -16t² + 64t + 4 , can be used to model the path of the ball once Carl hit it. For which interval of time, in seconds, is the height of the ball greater than or equal to 52 feet ?

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Answer:

7. 15

8. -10

9. 22

Step-by-step explanation:

7. mulitply 5 and 3

8. add 4 and -14

9. 6(2) +10 = 12+10

Answer:

Apothem:

radius is the same length as the base/length of each side of the hexagon.

r = 8

use pythagorean theorem to calculate the apothem

\(4^2+a^2=8^2\\\\16+a^2=64\\\\a^2=48\\\\a= 6.928\)

≈ 6.9

Area

\(A = \frac{3\sqrt{3} }{2} *a^2\\\\=\frac{3\sqrt{3} }{2}(6.928)^2\\\\=124.7\)

Answer:

D, X^2 -18 + 81 = -45 + 81

Step-by-step explanation:

it is complating squer method that used for solving x in a quadratic equetion . in this step you will add

(y/2)^2 if y is the cofitient of x .

A proportional relationship between two variables means that they are related by a constant ratio.

To determine which table represents a proportional relationship between x and y, we need to check if the ratio between y and x remains constant throughout the table. Let's examine the tables: Table 1:

x: 0, 1, 2, 3

y: 0, 3, 6, 9

The ratio between y and x is:

0/0 = undefined

3/1 = 3

6/2 = 3

9/3 = 3

Table 2:

x: 0, 2, 3, 4

y: 0, 4, 8, 12

The ratio between y and x is:

0/0 = undefined

4/2 = 2

8/3 ≈ 2.67

12/4 = 3

Table 3:

x: 0, 1, 2, 3

y: 0, 2, 6, 12

The ratio between y and x is:

0/0 = undefined

2/1 = 2

6/2 = 3

12/3 = 4

Based on the ratios calculated, we can see that Table 1 has a constant ratio of 3 between y and x. Therefore, Table 1 represents a proportional relationship between x and y.

So, the correct table that represents a proportional relationship is:

x: 0, 1, 2, 3

y: 0, 3, 6, 9

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This is a contradiction, which means that our initial assumption that there are n children is incorrect. Therefore, there is no solution to this problem that satisfies the given conditions.

Let's assume that there are n children in the Smith family.

We know that the father is 48 years old, so the sum of the ages of the mother and children is:

Total age = (n + 1) * 20 (as there are n children and 1 father)

And we also know that the average age of the mother and children is 16, so we can write:

Total age / (n + 1) = 16

Combining these two equations, we get:

(n + 1) * 20 / (n + 1) = 16

Simplifying, we get:

20 = 16

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Answer:

30/80

3/8x100

37.5

Step-by-step explanation:

Step-by-step explanation:

so, we have

2x² - 3×sqrt(3x) - 15 = 0

2x² - 15 = 3×sqrt(3x)

now, let's square both sides

(2x² - 15)² = 9×3x = 27x

4x⁴ - 60x² + 225 = 27x

4x⁴ - 60x² - 27x + 225 = 0

that leads to enormous terms and expressions.

now, could it be that the actual problem is

2x² - 3×sqrt(3)×x - 15

hmmm ?

to be considered : with the square root of the variable in the expression this is officially not a polygon ...

because then we could solve for a quadratic equation.

a quadratic equation

ax²c+ bx + c = 0

has the general solutions

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 2

b = -3×sqrt(3)

c = -15

x = (3×sqrt(3) ± sqrt(9×3 - 4×2×-15))/(2×2) =

= (3×sqrt(3) ± sqrt(27 + 120))/4 =

= (3×sqrt(3) ± sqrt(147))/4 =

= (3×sqrt(3) ± sqrt(49×3))/4 =

= (3×sqrt(3) ± 7×sqrt(3))/4

x1 = (3×sqrt(3) + 7×sqrt(3))/4 = 10×sqrt(3)/4 =

= 5/2 × sqrt(3)

x2 = (3×sqrt(3) - 7×sqrt(3))/4 = -4×sqrt(3)/4 =

= - sqrt(3)

about the relationship between zeros and coefficients of the polynomial :

the sum of both zeros = -b/a = 3×sqrt(3)/2

5/2 × sqrt(3) + - sqrt(3) = 5/2 × sqrt(3) - sqrt(3) =

= 3/2 × sqrt(3)

correct.

the product of both zeros = c/a = -15/2

5/2 × sqrt(3) × - sqrt(3) = 5/2 × -3 = -15/2

correct.

========================================================

Explanation:

Plane symmetry only applies to objects in 3D space. So choice A won't apply.

Point symmetry is where we can rotate the object some number of degrees (between 0 and 360 excluding the endpoints) and have it line up with itself. We can't do such a rotation, so this figure has no point symmetry. We rule out choice B.

Choice C works since we can reflect the upper half of the letter over the horizontal midline to have its reflection line up with the lower half, and vice versa. There is only one line of symmetry here.

Choice D is not true since choice C was shown to be true.

Answer: Is c-line

Step-by-step explanation:

The guy above me got it right I just did the quiz

The expression sin(e^37) does not have a well-defined limit as x approaches 0 from the left side since the argument e^37 is not an angle and is a constant.

To find the limit of the function sin(e^37) as x approaches 0 from the left side, we need to evaluate the limit and analyze the behavior of the function near 0.

The expression sin(e^37) represents the sine of a very large number, approximately equal to 5.32048241 × 10^16. The sine function oscillates between -1 and 1 as the input increases, but it does so in a periodic manner.

As x approaches 0 from the left side (x < 0), the function sin(e^37x) will oscillate rapidly between -1 and 1. However, since the argument of the sine function (e^37) is an extremely large constant, the oscillations will occur at a much higher frequency.

To calculate the limit, we can directly evaluate the function at x = 0 from the left side.

sin(e^37 * 0) = sin(0) = 0.

Therefore, the limit of sin(e^37) as x approaches 0 from the left side is equal to 0.

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Answer:

2(9x-32)

Step-by-step explanation:

9x(2)-64

18x-64

=2(9x-32)

\( {9x}^{2} - 64\)

\( {(3x)}^{2} - (8)^{2} \\ \)

\((3x - 8)(3x + 8)\)

Answer:

(3x - 8)(3x + 8)

Hope you could understand.

If you have any query, feel free to ask.

Given line is, r(t)=<3,2,-1>+t<2,1,4>Let's find the direction vector of the line r(t).

r(t)=<3,2,-1>+t<2,1,4>=> r(t) = <3+2t, 2+t, -1+4t>

Therefore, direction vector of the line r(t) is <2, 1, 4>For two lines to be perpendicular to each other, their direction vectors are to be orthogonal to each other.

For a plane, the normal vector is orthogonal to every vector lying on the plane.

Now, let the normal vector of the plane be.

The given plane is -4x+ _______ y-8z=16

Let the missing term be "d".

Then, the normal vector of the plane is < -4, d, -8 >

The direction vector of the line r(t) is <2, 1, 4>.

For r(t) to be perpendicular to the plane, the direction vector of r(t) should be orthogonal to the normal vector of the plane.

<2, 1, 4>.< -4, d, -8 > = 0

=> 2*-4 + 1*d + 4*-8 = 0

=> -8 + d - 32 = 0

=> d = 40

So, the given plane is -4x+ 40y -8z = 16.

Hence, the missing term in the given plane is 40.

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Answer:

359°

Step-by-step explanation:

When an image is rotated by a multiple of 360 degrees, it returns to its original position because it has completed one full revolution. However, if the image is rotated by any angle less than 360 degrees, it will not return to its exact original position.

For example, if an image is rotated by 45 degrees, it will not return to its exact original position, but will instead be in a new and unique position. If the image is then rotated by another 45 degrees, it will again be in a new and unique position, and so on.

Therefore, the highest number of degrees an image can rotate without returning to its exact original position is 359 degrees.

Answer: 359 degrees

Step-by-step explanation:

If you rotate any object exactly 360 degrees, it returns to it's original position. Remember that phrase "360 no-scope?" It involves spinning until you're back where you started; try doing it right now. You'll be back where you were. But this question wants to know how far you can rotate an object without it being back where it was. I would usually say 359.999999999, but it's a whole number answer, so we'll stick with 359. Hope this helps!

1. f'(a) is approximately 118.7 when a = 5.

2. f'(k) is approximately 98.7 when k = 7.

To find the derivative of a function at a specific point, we can use the rules of differentiation.

For f(x) = 0.8e^(x)arctan(x), we can find f'(a) by taking the derivative of the function and then evaluating it at x = a.

f'(x) = 0.8(e^x * arctan(x))'

= 0.8(e^x * (1/(1+x^2)) + e^x * arctan(x)')

= 0.8(e^x/(1+x^2) + e^x * (1/(1+x^2)) + e^x * 1)

= 0.8(e^x/(1+x^2) + e^x/(1+x^2) + e^x)

Now, substitute x = a = 5:

f'(5) = 0.8(e^5/(1+5^2) + e^5/(1+5^2) + e^5)

≈ 0.8(0.0081 + 0.0081 + 148.4132)

≈ 0.8(148.4294)

≈ 118.7435

Therefore, f'(a) is approximately 118.7 when a = 5.

For f(x) = 0.09exx, we need to find f'(k) when k = 7.

f'(x) = 0.09(e^x * x + e^x * 1)

= 0.09(e^x(x+1))

Now, substitute x = k = 7:

f'(7) = 0.09(e^7(7+1))

≈ 0.09(1096.6332)

≈ 98.6969

Therefore, f'(k) is approximately 98.7 when k = 7.

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Answer : x = 30 degrees

< JKL and < MKQ are complementary

Let < MKQ = x

Angle JKL is twice the measure of angle MKQ

JKL = 2 x MKQ

Sum of a complementary angles = 90 degrees

< JKL + < MKQ = 90

< JKL = 2MKQ

Substitute the value of < jkl

2(<2MKQ + Since, Therefore,

2x + x = 90

3x = 90

Divide both sides by 3

3x / 3 = 90/3

x = 30 degrees

Answer:

105 degrees

Step-by-step explanation:

Hope this helps!

According to the information, the price change of $ 6 to $ 2 would generate an elasticity in the demand of 0.33

The price elasticity of demand is an economic term that refers to the measure used to show the amount demanded of a good or service to changes in the price of said good or service.

To find the demand elasticity we must perform the following mathematical procedure:

Price elasticity = (P1 + P2)/(Q1 + Q2) x (Q2 - Q1)/(P2 - P1)

Q1 = 5, p1 = 6

Q2 = 7, p2 = 2

PE = 8/12 x 2/-4 = - 0.33

According to the above, we can establish that the elasticity in demand with a price change of $ 6 to $ 2 would be 0.33.

Note: This Question is incomplete. Here is the complete information:

Attached Image

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1)The slope of the line is C) 13. 2)It would be inefficient since it is not the most optimal use of resources.the correct option is C. 3)The equilibrium price and quantity are D) $25 and 10 dozens of roses per day, respectively.

1) Y = 13X + 38, where Y is a function of X.

The slope of the line is 13.

Therefore, the correct option is C.

2) Kolin catches 25 fish and gathers 70 fruits. If we consider the combination, then it would be inefficient since it is not the most optimal use of resources.

Therefore, the correct option is C.

3) Using the given figure, we can see that the point where the demand and supply curves intersect is the equilibrium point. At this point, the equilibrium price is $25 and the equilibrium quantity is 10 dozens of roses per day.

Therefore, the correct option is D. The equilibrium price and quantity are $25 and 10 dozens of roses per day, respectively.

Note that this is the point of intersection between the demand and supply curves, which represents the market equilibrium.

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Answer:

$2500

Step-by-step explanation:

Given that:

Darcy's weekly earning = $982 plus 18% commission on food sales

Harper's weekly earning = $807 plus 25% commision

amount of food sales will result in Darcy and Harper earning the same amount for the week

Let amount of food sales = f

Darcy's earning = Harper's earning

(982 + 18%*f) = (807 + 25% * f)

(982 + 0.18f) = (807 + 0.25f)

982 + 0.18f = 807 + 0.25f

982 - 807 = 0.25f - 0.18f

175 = 0.07f

f = 175 / 0.07

f = 2500

Hence amount of food sales that will result in both Darcy and Harper earning the same amount = $2500

Step-by-step explanation:

4x + 2y = 6       'Solve for y '   will be slope-intercept from

2y = -4x + 6

y =  -2 x + 3        Done.

Answer: Your answer is D y = -2x+3

Hope it helped :D

Please mark me brainliest

Answer:

can you send in a better photo i cannot see it clearly

Step-by-step explanation:

To make a kite, you need 222 wooden sticks and 1.5 square feet of paper. For a lamp, you need 12 wooden sticks and 88 square feet of paper.

Now, let's calculate the number of wooden sticks and square feet of paper needed for the kite and the lamp separately.

For the kite:
- Number of wooden sticks: 222
- Square feet of paper: 1.5

For the lamp:
- Number of wooden sticks: 12
- Square feet of paper: 88

it takes 222 wooden sticks and 1.5 square feet of paper to make a kite, while it takes 12 wooden sticks and 88 square feet of paper to make a lamp.

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Measure of segment DC is 24

Measure of segment C'B' is 16

Measure of segment AD is 10

Measure of segment A'B' is 7

Measure of angle C is 49 degrees

Measure of angle A' is 111 degrees

Measure of angle D' is 65 degrees

Measure of angle B' is 135 degrees

Measure of angle A is 111 degrees

To determine the measures, we need to know the properties of parallelograms, we have;

We have that the two parallelograms are equal

Now, trace the angles from one to other

Angle A = 360 - (49 + 135 + 65)

add the values, we have;

Angle A = 360 -249

Angle A =111 degrees

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These three expressions

6x ÷ 6 = 20 ÷ 6

6x + 5 = 20 + 5

6x − 1 = 20 − 1

will be equal to the given expression.

Operators, constants, and variables all come together to form an expression. A value can be produced by an expression using one or more operands and zero or more operators.

We have to check which equation will be equal to 6x = 20

6x ÷ 6 = 20 ÷ 6

After Multiplying both sides by 6.

We get, 6x = 20

6x ÷ 6 = 20 ÷ 20

After simplifying we get,

x = 1

Multiplying both sides by 6

6x = 6, Hence it doesn't satisfy.

6x + 5 = 20 + 5

Subtract 5 both sides of the equation

We get, 6x = 20

6x − 1 = 20 − 1

Adding 1 both sides of the equation,

We get, 6x = 20

6x × 6 = 20 × 20

After simplifying, we get

36x = 400

Hence, only

6x ÷ 6 = 20 ÷ 6

6x + 5 = 20 + 5

6x − 1 = 20 − 1

will be equal to the given expression.

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