Answer:
3.
Step-by-step explanation:
3 divided by 1 equals 3.
Please mark me brainliest I need it!!!
squared root of -100 =
Step-by-step explanation:
Please this is a wrong question. If you mean square root of 100 then it's 10. As for -100, it's an error.
\( \frac{18}{100} \)
is what percent
A. 36%
B. 8%
C. 9:
D. 18%
Algebra transformation
f(x) =
f(x) =
f(x) =
f(x) =
Algebra transformation
for Graph1 f(x)=f(x)+4
for Graph2 f(x)=-f(x-4)
for Graph3 f(x)=f(x-7)
for Graph4 f(x)=f(x-2)-5
Define reflection of graphIn mathematics, the reflection of a graph is a transformation that produces a mirror image of the original graph across a specific line or point. The line or point across which the reflection occurs is called the axis of reflection.
Graph1
Transform the graph by +4 units in y direction.
f(x)=f(x)+4
Graph2
Transform the graph by +4 units in x direction.
f(x)=f(x-4)
Now take the reflection of graph about x axis
f(x)=-f(x-4)
Graph3
Transform the graph by +7 units in x direction.
f(x)=f(x-7)
Graph5
Transform the graph by -5 units in y direction.
f(x)=f(x)-5
Now Transform the graph by -2 units in x direction.
f(x)=f(x-2)-5
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Please help me in this math problem
Answer:
Step-by-step explanation: well, you will more than likely get it at least 60%-80% of the time! If this doesn't help i can try to explain in a lot more detail unless someone does for me!
10.5% of the population is 65 or older. Find the probability that the following number of persons selected at random from 25 people are 65 or older.The probability that at most 2 are 65 or older is(Round to three decimal places as needed)
Given:
The sample size n=25
Probability of population is 65 or older is 10.5%.
This date follows the binomial distribution,
\(\begin{gathered} n=25,p=0.105 \\ X\rightarrow B(n=25,p=0.105) \end{gathered}\)To find the probability that at most 2 are 65 or older,
\(\begin{gathered} P(X=x)=^nC_x(p)^x(1-p)^{n-x} \\ P(0\leq X\leq2)=P(X=0)+P(X=1)+P(X=2) \\ =^{25}C_0(0.105)^0(1-0.105)^{25-0}+^{25}C_1(0.105)^1(1-0.105)^{25-1}+^{25}C_2(0.105)^2(1-0.105)^{25-2} \\ =0.0625+0.1832+0.2579 \\ =0.5036 \\ \approx0.504 \end{gathered}\)Answer: Probability is 0.504 .
trigonometry help; how would I even do these?
The possible answers are
0.6
0.8
0.750
Answer:
0?8
Step-by-step explanation:
Cos(A) = Adjacent/hypotenuse
Cos(A) = 36/45
=0.8
* (ii). A uniform beam is 12m long and has a mass of 50kg and masses of 30kg and 40kg are suspended from its ends, at what point must the beam be supported so that it may rest horizontally?.
The point at which the beam must be supported so that it may rest horizontally is; 9 meters from the left side
How to solve Uniform Beam problems?
The parameters are;
Mass of beam = 50 kg
Length of beam = 12 m
Mass suspended at left end = 30kg
Mass suspended at right end = 40 kg
Let the support that will make the beam rest horizontally be x from the left side.
Thus, taking moment about the point x from the left side is;
30x + 50(6 - x) = 40(12 - x)
30x + 300 - 50x = 480 - 40x
20x = 180
x = 180/20
x = 9 m
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Hello, I need some assistance with this precalculus question, please?HW Q7
The solution
Now
The final answer
Drag the tiles with the correct pairs
Help me please can someone tell me how to do this
Find y.
7.54
6.76
18.55
29.83
The length of y in the triangle is 18.55 units.
How to find the side of a triangle?A triangle is a polygon with three sides. The sum of angles in a triangle is 180 degrees. The side y of the triangle can be found using sine law.
Therefore,
a / sin A = b / sin B = c / sin C
Applying the sine law,
y / sin 106 = 15 / sin 51
cross multiply
y sin 51° = 15 sin 106°
divide both sides by sin 51°
y sin 51° / sin 51° = 15 sin 106° / sin 51°
y = 15 sin 106° / sin 51°
Therefore,
y = 15 × 0.96126169593 / 0.77714596145
y = 14.4189254391 / 0.77714596145
y = 18.5536589719
Hence,
y = 18.55 units
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do you have a cat and if so how old is he or she
Rahmi bought 1 pair of jeans and 2 T-shirts. How much did rahmi spend? Write equations to solve. Use a letter to represent the unknown quantity
Answer:
1x + 2y = (The answer/money spent)
Step-by-step explanation:
Which parent functions have a range of (-infinity , infinity) select all that apply
A. a parent even-degree power function
B. a parent odd-degree power function
C. a parent even-degree root function
D. a parent odd-degree root function
E. a parent exponential function with a base greater than 1
F. a parent exponential function with a base between 0 and 1
G. a parent logarithmic function with a base greater than 1
H. a parent logarithmic function with a base between 0 and 1
Answer:b,d,g,h
Step-by-step explanation:
A function assigns the value of each element of one set to the other specific element of another set. The correct option is B, D, G, and H.
What are the domain and range of a function?A function assigns the value of each element of one set to the other specific element of another set.
The domain is the set of values for which the given function is defined.The range is the set of all values which the given function can output.From the given functions the function that has a range of (-∞, ∞) can be found by plotting the graph. Therefore, the parent function that has a range of (-∞, ∞) are:
B. a parent odd-degree power function
D. a parent odd-degree root function
G. a parent logarithmic function with a base greater than 1
H. a parent logarithmic function with a base between 0 and 1
Hence, the correct option is B, D, G, and H.
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compare: These two equations
Using translation concepts, we have that:
Function f(x) underwent a reflection over the y-axis.Function g(x) underwent a reflection over the x-axis.What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.
For function f(x), the multiplication by -1 of the function is in the output, meaning that it was a reflection over the y-axis. For function g(x), the multiplication is in the input, the domain, hence the reflection was over the x-axis.
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City planners will use 1/3 of a new park as a section for sports activities. Soccer fields will be 2/5 of the sports section. Which fraction of the entire park will be soccer fields? answer it please no links please 50 pionts!!!
Answer:
2/15
Step-by-step explanation:
Take the fractions of the park for sports and multiply the fraction of the sports that is for soccer. That will give the fraction of the park that is for soccer
1/3 * 2/5 = 2/15
This is the answer but can someone do the work plss??
An economics professor is interested in seeing if the mean hours worked by ISU students in a week at part time or full time jobs (including work study) is greater than 10. To accomplish this, the professor randomly selected 50 students from the university. It was found that the distribution was right skewed and unimodal. The sample mean was 11 hours with a sample standard deviation of 3. The professor then did a hypothesis test. Please find the test statistic for this hypothesis test Group of answer choices
Answer:
2.3574
Step-by-step explanation:
This question requires us to find the t test statistic given the data in the question.
H0: u = 10
H1: u > 10
Population variance is not known
T = (barX - u)/(s/√n)
u = 10 hours
BarX = 11 hours
Sd = 3 hours
n = 50
(11-10)/(3/√50)
t test = 1/(3/√50)
= 1/0.4242
Test statistic = 2.3574
Hubble's constant H is about 70 km/sec per megaparsec. (The prefix "mega" means million.) Convert this value for Hubble's constant to km/s/million LY. Hint: -A parsec is 3.26 light-years, and therefore a megaparsec is 3.26 million LY. If you take the given value of the Hubble constant (namely, 70 km/s per megaparsec) and replace the megaparsec with 3.26 million LY, then you will have converted to the desired units.
Hubble's constant in units of km/s/million LY is approximately 21.47.
what is approximately ?
Approximately means close to or nearly, but not exactly. It is used to indicate that a value or number is an estimation or approximation, rather than an exact value. It is often used when a precise value is not necessary or when the exact value is unknown or difficult to determine.
In the given question,
To convert Hubble's constant from km/s/Mpc to km/s/million LY, we need to multiply it by a conversion factor that accounts for the difference in distance units. We can use the fact that 1 Mpc is equal to 3.26 million LY:
1 Mpc = 3.26 million LY
Therefore, to convert Hubble's constant from km/s/Mpc to km/s/million LY, we can use the following conversion factor:
1 Mpc / 3.26 million LY
Multiplying Hubble's constant by this conversion factor gives:
H = 70 km/s/Mpc x (1 Mpc / 3.26 million LY) = 21.47 km/s/million LY
Therefore, Hubble's constant in units of km/s/million LY is approximately 21.47.
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Determine the utilization and the efficiency for each situations:A. A loan processing operation that processes an average of 7 loans per day. The operation has a design capacity of 10 loans per day and an effective capacity of 8 loans per day.B. A furnace repair team that services and average of four furnaces a day if the design capacity is six furnaces a day and the effective capacity is five furnaces a day.
Answer:
A) Utilization = 70%
Efficiency = 87.5%
B) Utilization = 66.67%
Efficiency = 80%
Step-by-step explanation:
Determine the utilization and the efficiency for each situations:
A. A loan processing operation that processes an average of 7 loans per day. The operation has a design capacity of 10 loans per day and an effective capacity of 8 loans per day.
Formula for Utilization = Actual Output /
Design Capacity × 100
Actual output = 7 loans per day
Design capacity = 10 loans per day
Utilization = 7/10 × 100
= 70%
Efficiency = Actual output / Effective capacity × 100
Actual output = 7 loans per day
Effective capacity = 8 loans per day
Efficiency = 7/8 × 100
= 87.5%
B. A furnace repair team that services and average of four furnaces a day if the design capacity is six furnaces a day and the effective capacity is five furnaces a day.
Formula for Utilization = Actual Output /
Design Capacity × 100
Actual output = four furnaces a day
Design capacity = six furnaces a day
Utilization = 4/6 × 100
= 66.67%
Efficiency = Actual output / Effective capacity × 100
Actual output = four furnaces a day
Effective capacity = five furnaces a day
Efficiency = 4/5 × 100
= 80%
For Exercises 1 and 2, use the table. It shows the types of
and prices of Jolly Juice Orange Juice.
Bottles of Jolly Juice Orange Juic
Containers
Price
8 oz
$0.96
16 oz
$1.60
32 oz
$2.56
64 oz
$3.84
1. Find the unit rate for an 8-ounce
container of Jolly Juice. Explain your
answer.
2. Find the unit rate for each size. Then order the sizes from least to greatest unit rate
Answer:
I have 5 apples and give u 2 how much I have
please give me the answer i really need my grade up :(
Answer:
the correct option is
C. m<1 + m<2 = 90
Hope it will help :)❤
In Jamie's closet the ratio of pairs of boots to pairs of sneakers is 3:6. If she has 6 more pairs of sneakers
than boots, how many pairs of boots does she have?
if a * b= a + a/b find y if (3-2)*-y= 25-9sqrt5
Answer:
the value of y is -25 + 9√5.
give me brainlist
occurs when three or more people work together interdependently for the purpose of accomplishing a task.
A small group communication occurs when three or more people work together interdependently for the purpose of accomplishing a task.
Small Group Communication
Small group communication is the term used to describe face-to-face conversation between more than two people. This kind of internal communication exists.
A small group is typically thought of as a collection of three or less people, with a maximum number of twelve to fifteen. A group would not be considered tiny if it had more than fifteen members or if it had just two.
Since almost all businesses and organisations employ people in small squads, there are advantages or even strengths to small group communication. When compared to one individual working alone on a project, it has been found to be more appropriate and produce better results.
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For Field Day, the 72 students in fourth grade will be divided into tears with the same number of students on each team. The 60 students in third grade will be divided into teams that each have the same number of students as the fourth grade teams. What is the largest number of students that a team could have? Help meeee
suppose annual salaries for sales associates from a particular store have a mean of $32,500 and a standard deviation of $2,500
. a. Calculate and interpret the z-score for a sales associate who makes $36,000.
b. Use Chebyshev's theorem to calculate the percentage of sales associates with salaries between $26,250 and $38,750
. c. Suppose that the distribution of annual salaries for sales associates at this store is bell-shaped. Use the empirical rule to calculate the percentage of sales associates with salaries between $27,500 and $37,500.
d. Use the empirical rule to determine the percentage of sales associates with salaries less than $27,500. e. Still suppose that the distribution of annual salaries for sales associates at this store is bell-shaped. A sales associate makes $42,000. Should this salary be considered an outlier? Explain.
a) The z-score for a sales associate who makes $36,000 is 1.4
b) The percentage of sales associates with salaries between $26,250 and $38,750 is 84%
c) The percentage of sales associates with salaries between $27,500 and $37,500 is 95.4%
d) The percentage of sales associates with salaries less than $27,500 is 2.3%
e) Yes, the salary of $42000 should be considered as outlier.
Given,
Mean, \(\mu\)=32500
Standard deviation, \(\sigma\)=2500
a)
\(z=\frac{x-\mu}{\sigma}\\\\z=\frac{36000-32500}{2500}=1.40\)
The sales associate who makes 36000 is 1.4 standard deviation above the mean salary.
b)
As per chebyshev's theorem, \((1-\frac{1}{k^2})\) of the observations fall within k standard deviation of the mean, i.e. within \(\mu\pm k\sigma\)
\(z_1=\frac{x_1-\mu}{\sigma}\\\\z_1=\frac{26250-32500}{2500}=-2.50\\\\z_2=\frac{x_2-\mu}{\sigma}\\\\z_2=\frac{38750-32500}{2500}=2.50\)
Hence, we need to find proportion of observations within \(\mu\pm2.5\sigma\)
k=2.5
\((1-\frac{1}{k^2})=1-\frac{1}{2.5^2}=0.84=84\%\)
Hence, 84% of sales associates have salaries between 26250 and 38750.
c)
As per empirical rule for a bell shaped distribution:
68.3% of the observations fall within 1 standard deviation of the mean i.e. within \(\mu\pm 1\sigma\)95.4% of the observations fall within 2 standard deviation of the mean i.e. within \(\mu\pm 2\sigma\)99.7% of the observations fall within 3 standard deviation of the mean i.e. within \(\mu\pm 3\sigma\)\(z_1=\frac{x_1-\mu}{\sigma}\\\\z_1=\frac{27500-32500}{2500}=-2\\\\z_2=\frac{x_2-\mu}{\sigma}\\\\z_2=\frac{37500-32500}{2500}=2\)
Hence, we need to find the proportion of observations within \mu \pm 2\sigma
As per empirical rule, 95.4% of the observations fall within 2 standard deviation of the mean .i.e within \(\mu \pm 2\simga\) .Therefore, percentage of sales associates with salaries between 27500 and 37500=95.4%
d)
\(z_1=\frac{x_1-\mu}{\sigma}\\\\z_1=\frac{27500-32500}{2500}=-2\)
Percentage of sales associates with salaries less than 27500 will be equal to the area under the normal curve to the left z=-2
As per empirical rule 95.4% of the observations fall within 2 standard deviation of the mean
Therefore, the percentage of sales associates with salaries less than 27500 : \(\frac{100-95.4}{2}=2.3\%\)
e)
\(z_1=\frac{x_1-\mu}{\sigma}\\\\z_1=\frac{42000-32500}{2500}=3.8\)
A z-value greater than 3 is considered as an outlier.
Hence, the salary of 42000 should be considered as outlier.
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Jacob spent 5 hours skiing and snowboarding. He skied for 2 hours 10 minutes.
How long did he spend snowboarding?
Answer:
he spent 2hours 50minutes snowboarding
the time he spent skiing and snowboarding minus the time he skied
5hours minus 2hours 10minutes
not really sure what to do here??
Answer:
\(d=-6\)
\(a_9=-49\)
Step-by-step explanation:
If the first term of a sequence is \(-1\) and the second term is \(-7\), then each successive term in the sequence is \(6\) less than the previous term. The common difference is \(-6\) ( \(d=-6\) ).
The formula representing the arithmetic sequence is:
\(a_n=-6n+5\)
Therefore, the ninth term in the sequence is:
\(a_9=-6(9)+5\)
\(a_9=-54+5\)
\(a_9=-49\)
The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with grams of a radioactive isotope, how much will be left after 4 half-lives?
After 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.
The amount of a radioactive isotope remaining after a certain number of half-lives can be calculated using the formula:
Amount remaining = Initial amount × (1/2)^(number of half-lives)
In this case, we are given the initial amount as "grams" and we want to find out the amount remaining after 4 half-lives.
So, the equation becomes:
Amount remaining = Initial amount × (1/2)^4
Since each half-life reduces the quantity to half, (1/2)^4 represents the fraction of the initial amount that will remain after 4 half-lives.
Simplifying the equation:
Amount remaining = Initial amount × (1/16)
Therefore, after 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.
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