what is the uncertainty in the position (in m) of an electron moving 30.0 m/s accurate up to 0.00100 %

Answer:

camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )

Answer: camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )

Answer:

100.390407

Explanation:

To find acceleration, you would use the formula a=f/m (acceleration equals force divided by mass) and then once you enter those numbers in the formula, a=180/1.793. Then you divide 180 divided by 1.793 which gets you an answer of 100.390407.

The density of the cube measured will be 6047 kg/m³. It is determined by the researcher in the lab, may be calculated using the relativistic density equations and the Lorentz factor to be 2.747.

In order to solve this puzzle, you must determine the density of a cube while it travels at 89% the speed of light through a laboratory. The cube weighs 2200 kg/m³ at rest.

We can write a formula

ρ' = γρ

ρ' ⇒ density that measured by experimenter

γ ⇒ Lorentz factor

ρ ⇒ at rest the cube's density

The density of an item changes as its velocity changes, according to special relativity.

Cube is moving at 89.0% of the speed of light means v = 0.890c

c ⇒ Speed of light

Lorentz Factor γ = 1/√(1 - v²/c²) = 1/√(1 - (0.890c)²/c²) = 2.747

Now ρ' = γρ = 2.747 × 2200 kg/m³ = 6047 kg/m^3

This indicates that the cube's high velocity caused the experimenter to perceive it as being denser.

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Hi :)

The formula for velocity is

v = displacement / change in time

velocity = 100 m / 4 seconds

velocity = 25 m/s

The formula for velocity is

v = displacement / change in time

velocity = 100 m / 4 seconds

velocity = 25 m/s

The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.

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If a fish looks upward at 45 degrees with respect to the water's surface, it will see option a, the sky and possibly some hills.

When a fish looks upward at a 45-degree angle with respect to the water's surface, it will see the sky and possibly some hills. This is because light rays refract when they pass from one medium to another with different optical densities.

As light travels from air to water, it slows down, and its path bends towards the normal, which is perpendicular to the water's surface. This bending of light is called refraction. When the fish looks upwards, it sees the light that has been refracted by the water, and this light carries information about the sky and the surrounding landscape.

However, the amount of refraction depends on the angle of incidence of the light ray, so the fish will not see the entire sky but only a portion of it. At a 45-degree angle, the fish will see a wider view of the sky and possibly some hills, depending on the surrounding topography. Therefore, the fish will not see the bottom of the pond, which is below its line of sight.

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The problem states that the rate at which the intensity of a vertical beam of light decreases in a transparent medium is proportional to the thickness of the medium. It is given that in clear seawater, the intensity 1 meter below the surface is 25% of the initial intensity of the incident beam. The task is to find the intensity of the beam 6 meters below the surface.

Let's denote the initial intensity of the incident beam as I₀. According to the given information, the intensity 1 meter below the surface is 25% of I₀, which means it is 0.25I₀.

Since the rate of intensity decrease is proportional to the thickness of the medium, we can set up a proportion using the ratio of intensities:

I₁ / I₀ = \(e^{-kt}\)

where I₁ is the intensity at a depth of t meters, and k is the proportionality constant.

To find the intensity 6 meters below the surface, we substitute t = 6 into the equation:

I = I₀ *  \(e^{-6k}\)

We don't have the specific value of k or I₀, but we can still determine the ratio of intensities:

I / I₀ =  \(e^{-6k}\)

Using the given information, we can write the equation:

0.25I₀ / I₀ =  \(e^{-6k}\)

Simplifying the equation, we find:

0.25 = \(e^{-6k}\)

To solve for the intensity I, we substitute this value back into the equation:

I = I₀ * 0.25.

Therefore, the intensity of the beam 6 meters below the surface is 0.25 times the initial intensity I₀.

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The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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Answer:

d

\(f(x) = {x}^{2} - 5x + 3 \\ f( - 1) = {( - 1)}^{2} - 5( - 1) + 3 \\ = 9\)

The specific heat of the iron is 681.5 J/kg•°C.   We can use the equation for heat transfer to solve this problem:

Q = mcΔT

where Q is the heat transferred, m is the mass of the iron, c is the specific heat capacity of the iron, and ΔT is the change in temperature.

First, we need to calculate the heat transferred to the iron block when it is heated to 275°C on the burner:

Q1 = m1c1Δ1

where m1 is the mass of the iron block, c1 is the specific heat capacity of the iron block, and Δ1 is the change in temperature of the iron block. We can calculate these values as follows:

m1 = 175 g

c1 = 0.48 J/g°C

Δ1 = 275°C - 25°C = 250°C

Q1 = 175 g x 0.48 J/g°C x 250°C = 44 J

Next, we need to calculate the heat transferred to the beaker of water when the iron block is placed in it:

Q2 = m2c2Δ2

where m2 is the mass of the iron block, c2 is the specific heat capacity of the water, and Δ2 is the change in temperature of the water. We can calculate these values as follows:

m2 = m1 + 75 g = 175 g + 75 g = 250 g

c2 = 4.182 J/g°C

Δ2 = 75°C - 25°C = 50°C

Q2 = 250 g x 4.182 J/g°C x 50°C = 637.5 J

Finally, we can calculate the specific heat of the iron by subtracting the heat transferred to the beaker from the total heat transferred:

c = Q1 + Q2 - Q3

= 44 J + 637.5 J - Q3

where Q3 is the heat transferred to the iron block and the water equilibrate at 75°C.

We can assume that the heat transferred to the water is negligible, so Q3 = 0.

Therefore, the specific heat of the iron is:

c = 44 J + 637.5 J - 0 J

= 681.5 J/g°C

The units of specific heat are J/g°C, so we need to convert 681.5 J/g°C to J/g•C.

681.5 J/g°C = 681.5 J/g x 1000 g/kg x 1000 kg/1000 g = 681.5 J/kg•°C

Therefore, the specific heat of the iron is 681.5 J/kg•°C.  

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First you get the data:

Time conversion: hours to seconds:

\(\bf{2\not{h}*\left(\dfrac{3600 \ seg}{1\not{h}}\right)=7200 \ seg }\)

We calculate the distance, using the formula:

                           \(\bf{d=t*v }\)

                           \(\bf{d=3600\not{seg}*3\frac{m}{\not{m}} }\)

                           \(\bf{d=21600 \ m}\)

Answer: I travel to 21600 meters.

Answer:

we should not drop a magnet on the floor because the magnets tend to lose magnetism gradually and become weak over a period of time if they are not stored properly.

Answer:

Well depending on the floor like say if it was a wooden floor the magnet might lose it magnetism, if concrete floor the magnetic brake and still lose it magnetism, if a metal floor the magnet would stick not sure if it wood lose it magnetism or not but the possibilities still there, basically what I'm saying is the magnet would lose its magnetism if it were to interact with the floor maybe temporary or maybe permanently.

for those with with a learning disability it's a

Explanation:

Answer:

Rubber, Copper and Aluminium

Answer:

Explanation:

Tick (✓) the correct answer:

rubber, copper, and aluminium.

Answer:

Explanation:

By being close to an atom that will gladly take the electrons being offered.

Suppose you are talking about Be. It is in the second column. It has two outer electrons that can be given away. It will not give away one of the two remaining electrons because they are too close to the + nucleus.

Along comes a Fluorine atom. It has 7 electrons in its outer ring. The chemistry of the situation allows it to take on one of the two electrons Be is offering. It is all a matter of charges and attractions.

Another Fluorine atom will take on the remaining electron from the Be. The outer ring cannot take on more than 1 electron, but that is enough

The final speed of the car is: (3) 16 m/s.Given the following data:Initial speed = 0 m/s (since ...

Answer:

bshghhxhgdyxhsygfhtgedhrugrugdjifgu

rolling of a ball uses motion his bushy we I his own shaken his known fish of his jus on

The energy of a photon is given by:E = hc/λwhere h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.

In the given problem, the wavelength is 325 nm, so the energy of one photon is:E = hc/λ= (6.63 × 10^-34 J s) × (3.00 × 10^8 m/s) / (325 × 10^-9 m)= 1.94 × 10^-19 JNext, we can calculate the total energy of the photons collected by the photodetector:

Total energy = energy per photon × number of photons= (1.94 × 10^-19 J/photon) × (8.0 × 10^7 photons)= 1.55 × 10^-11 JNow, we can use the formula for power:Power = energy / time= (1.55 × 10^-11 J) / (3.8 × 10^-3 s)= 4.08 × 10^-9 WTherefore, the average power output of the photodetector is 4.08 × 10^-9 W.

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Answer:

A comet

Explanation:

The picture is of an elliptical orbit of a comet. You can tell it is a comet because of the tail. Also, I just took the test and it was a comet.

Therefore, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s.

The photoelectric effect is observed on two metal surfaces. If light of wavelength 300.0 nm is incident on a metal that has a work function of 2.80 eV, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s. What is the photoelectric effect? The photoelectric effect, also known as the Hertz–Lenard effect, is a phenomenon in which electrons are emitted from a metal surface when light is shone on it. The photoelectric effect was initially studied by Heinrich Hertz in 1887 and later by Philipp Lenard in 1902.Latex-free answer: To calculate the maximum speed of emitted electrons using the photoelectric effect equation, we can use the following formula: KEmax = hν - φwhere KE max is the maximum kinetic energy of the ejected electron, h is Planck's constant, ν is the frequency of the incident light, and φ is the work function of the metal. Using the equation, we can convert the given wavelength of 300.0 nm to frequency by using the formula c = λν where c is the speed of light and λ is the wavelength. c = λνν = c/λν = (3.0 x 10⁸ m/s) / (300.0 x 10⁻⁹ m)ν = 1.0 x 10¹⁵ Hz, Now we can plug in the values in the equation: KE max = (6.626 x 10⁻³⁴ J s) (1.0 x 10¹⁵ Hz) - (2.80 eV)(1.60 x 10⁻¹⁹ J/eV)KE max = 1.06 x 10⁻¹⁹ J - 4.48 x 10⁻¹⁹ JKE max = -3.42 x 10⁻¹⁹ J. Since KE max is a positive value, we can convert the value to speed using the equation KE = 1/2mv² where m is the mass of the electron and v is the velocity of the electron: v = √(2KE/m)v = √[(2)(3.42 x 10⁻¹⁹ J)/(9.11 x 10⁻³¹ kg)]v = 1.62 x 10⁶ m/s. Therefore, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s.

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Answer:

There’s a tangential velocity and centripetal force. The object moves in a circle because it’s falling towards the center of the circle (point directly under string) but the velocity is such that the object never gets closer to the center

Explanation:

Answer:

107.5 mph

Explanation:

m/s converted to mph, then calculate difference in speed is relativity

Please find attached photograph for your answer. Do comment whether it is useful or not. Mark as Brainliest if you like my answer.

The change in kinetic energy of the system of the three spheres as a result of the collision is -0.145 J

Kinetic energy of a system is the energy the system has due to the motion of the system.

Part of the question includes: Mass of sphere A = 0.020 kg

Velocity of A = 1.50 m/s in the -ve x-direction

Mass of B = 0.030 kg

Velocity of B = 0.50 m/s in the direction South 30° West

Mass of C = 0.050 kg

The spheres stick together after collision

Part A: The resultant velocity of the spheres = 0.50 m/s in the +ve x-direction:

Which gives: Velocity of A = -1.5·i

Velocity of B = -0.5×cos(60°)·i - 0.5×sin(60°)·j

Resultant velocity = 0.50·i

Which gives: \(\overset{\rightharpoonup}{v}_C\) = 0.50·i - (-0.5×cos(60°)·i - 0.5×sin(60°)·j -1.5·i) = \(\dfrac{9}{4} \cdot \mathbf{i}+\dfrac{\sqrt{3} }{4} \cdot \mathbf{j}\)

The initial kinetic energy of the system before collision is therefore:

K.E. = 0.5×m×v²

\(K.E._A =0.5\times 0.02 \times 1.5^2 = 0.0225\)

\(K.E._B =0.5\times 0.03 \times 0.5^2 = 0.00375\)

The magnitude of the velocity of C = \(|\overset{\rightharpoonup}{v}_C|=\sqrt{\left(\dfrac{9}{4} \right)^2+\left(\dfrac{\sqrt{3} }{4} \right)^2} = \dfrac{\sqrt{21} }{2}\)\(K.E._C=0.5\times 0.05\times \left( \dfrac{\sqrt{21} }{2}\right)^2= 0.13125\)

The initial energy in the system, K.E.₁ = 0.0225 + 0.00375 + 0.13125 = 0.1575

The final kinetic energy of the system, K.E.₂ = 0.5×(0.02+0.03+0.05)×0.5² = 0.0125

The change in kinetic energy of the system, ΔK.E. is therefore:

ΔK.E. = K.E.₂ - K.E.₁

Which gives:

ΔK.E. = 0.0125 - 0.1575 = -0.145

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The moment of inertia of the cylinder about the horizontal axis parallel and tangent to the cylinder is 3MR²/2.

The moment of inertia (Icm) of the cylinder about its symmetrical axis is calculated using the formula MR^2/2, where M represents the mass of the cylinder and R represents its radius.

To find the moment of inertia of the cylinder about the axis parallel and tangent to the cylinder, we can use the parallel axis theorem. According to the parallel axis theorem, the moment of inertia about an axis parallel to and at a distance 'd' from the axis passing through the center of mass is given by:

I = Icm + Md^2

In this case, the axis of rotation is parallel and tangent to the cylinder, so the distance 'd' from the axis passing through the center of mass is equal to the radius 'R'. Substituting the values into the equation:

I = Icm + MR^2

I = MR^2/2 + MR^2

I = (1/2 + 1)MR^2

I = (3/2)MR^2

Therefore, the moment of inertia of the cylinder about the given axis is (3/2)MR^2.

The correct answer is (D) 3MR^2/2.

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The reverse both the direction of the magnetic field and the flow of current in a conductor at the same time, the direction of the Lorentz Force would also reverse.

The current flows through a conductor in a magnetic field, the Lorentz Force acts in a direction perpendicular to both the current and the magnetic field. This causes the conductor to experience a force, which can be used to perform work or generate electricity. If the direction of the magnetic field or the current is reversed, the direction of the Lorentz Force will also reverse, causing the conductor to experience a force in the opposite direction. This phenomenon is used in many applications, including electric motors and generators. By reversing the direction of the magnetic field and the current, the direction of the Lorentz Force can be changed, allowing for the creation of torque or electrical energy. Understanding the interaction between magnetic fields and conductors is crucial for many technological advancements and has led to the development of many innovative devices and systems.

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When is the average velocity of an object equal to the instantaneous velocity is C. This is the case only when the velocity is constant.

The instantaneous velocity of an object is equal to the average velocity of an object when the velocity is constant or when the acceleration is zero, this is the case only when the velocity is constant. When an object has a constant velocity, the instantaneous velocity of the object is equivalent to the average velocity of the object. This is true because the velocity of the object remains constant over time.

For example, if an object travels at a speed of 20 meters per second for a time period of 5 seconds, then the instantaneous velocity at the end of the 5 seconds is 20 meters per second, and the average velocity of the object over the 5 seconds is also 20 meters per second. This is because the velocity remained constant throughout the entire time period. Therefore, option c is correct, this is the case only when the velocity is constant.

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Answer:

Cuba, Jamaica, Dominican Republic, Haiti, Turks & Caicos, and The Bahamas

Explanation:

Answer:

Cuba, Jamaica, Dominican Republic, Haiti, Turks & Ciacos & Bahamas's.

Answer:8h

Explanation:

Answer: 8 h

Explanation:

I got it right