What is the surface area of a pyramid with measurements of 4cm by 4cm by 7cm

Answers

Answer 1

Answer:

Area of one face of pyramid equal 18.55

Step-by-step explanation:

Area of pyramid equal 18.55x4=74.2


Related Questions

please help with 6-8 ! will give brainliest !! :)

please help with 6-8 ! will give brainliest !! :)

Answers

Answer:

6:6=x

7:16=y

8:20=z

Step-by-step explanation:

For 6, since BD is a perpendicuar bisector, that means 15x=90. Divide 90 by 15 and you get 6

for 7, if bd is a angle bisector, you can set 3y=48. divide 48 by 3 and you get 16

for 8, since Bd is a median, you can set 2z-3=z+17. Isolate the variable and you will get 2z-z=17+3. Add like terms together and you get z=20

Just so you know, a perpendicular bisector will make both angles equal to 90, an angle bisector make both angles equal to each other, and medians make it so that it hit a line in the center therefor you can set both sides of the line to be equal

-0 overline 32. is it irrational or rational?

Answers

Answer:

irrational

Step-by-step explanation:

What is the axis of symmtry

Answers

Answer:

The axis of symmetry of a parabola is a line about which the parabola is symmetrical.

Step-by-step explanation:

The axis of symmetry of a parabola is a line about which the parabola is symmetrical. When the parabola is vertical, the line of symmetry is vertical. When a quadratic function is graphed in the coordinate plane, the resulting parabola and corresponding axis of symmetry are vertical.

The middle of a parabola

verify each identity
3) csc x (csc x + 1) = sinx+1/ sin^2 x

Answers

Given identity is `csc x (csc x + 1) = (sinx+1)/ sin^2 x

To verify the identity `csc x (csc x + 1) = (sinx+1)/ sin^2 x`, we will use the identities:

`cosec θ = 1 / sin θ`and `1 + tan^2 θ = sec^2 θ`

In order to use the identity, we first have to convert `cosec θ` into `sin θ`.`

cosec θ = 1 / sin θ

``1 / (cosec θ + 1) = sin θ`

We will replace `cosec θ` with `1 / sin θ` in the left side of the given identity.

`csc x (csc x + 1) = (sinx+1)/ sin^2 x`

We replace `csc x` with `1 / sin x` to get the new identity.

`1/sinx (1/sinx + 1) = (sinx + 1) / sin^2 x`

Now, we will replace `1 / (sin x + 1)` with `cos x / sin x` (from the identity `1 + tan^2 θ = sec^2 θ` with `θ` as `x`).

`1 / sin x + 1 = cos x / sin x``1 / sin x (cos x / sin x) = (sinx + 1) / sin^2 x`

On simplifying, we get:

`cos x + 1 = sin x + 1`

This is true. Thus, we have verified the identity `csc x (csc x + 1) = (sinx+1)/ sin^2 x`.

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Single-case designs, by definition, do not incorporate control groups. What is the standard for comparison purposes to evaluate the treatment effects

Answers

In single-case designs, the standard for comparison purposes to evaluate the treatment effects is typically the individual's own performance during different phases of the study. Here's a step-by-step explanation:

1. Baseline Phase: The study begins by collecting data on the individual's behavior or performance without any intervention. This phase is called the baseline and serves as a reference point for comparison.

2. Intervention Phase: After establishing the baseline, the researcher introduces the treatment or intervention. The individual's performance during this phase is then compared to their performance during the baseline phase.

3. Reversal or Withdrawal Phase (optional): In some single-case designs, the intervention is withdrawn to see if the individual's performance returns to baseline levels. This phase helps to further establish the treatment's effectiveness.

4. Replication (optional): The study can be replicated with the same individual or with other individuals to demonstrate the treatment's effectiveness across different cases.

By comparing the individual's performance across these different phases, researchers can evaluate the treatment effects without the need for a control group.

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the weights of cars passing over a bridge have a mean of 3550 lb and a standard deviation of 870 pounds. Assume that the weights of cars passing over the bridge or never distributed. Use the empirical rule to estimate the probability that a randomly-selected car going over the bridge will weigh less than 940 lbs

the weights of cars passing over a bridge have a mean of 3550 lb and a standard deviation of 870 pounds.

Answers

Answer:

  a.  0.15%

Step-by-step explanation:

The Z-score of 940 pounds is ...

  (X -µ)/σ = (940 -3550)/870 = -3

The empirical rule tells you that 99.7% of the normal distribution lies within Z = ±3. Half of the remaining 0.3% lies below Z = -3, which is the set of weights of interest.

The probability that a car weighs less than 940 lbs is about 0.15%.

The tendency to perceive meaningful patterns in random sequences of outcomes often leads us to underestimate the extent to which outcomes result from.

Answers

The tendency to perceive meaningful patterns in random sequences of outcomes often leads us to underestimate the extent to which outcomes result from CHANCE .

The word "chance" describes unpredictability or the unexpected in relation to things like events that happen without a clear reason why and without human intention.

The conclusion is that chance is the tendency of people to recognize different kinds of significant patterns in a random order or sequence in addition to evaluating any kind of outcome. Because chance can also result in an underestimating of a system's conclusion or result, it is crucial to consider it when conducting an investigation.

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if a farm that’s for sale measures one and three-quarter square miles, how many acres is it?

Answers

The farm for sale measures 1120 acres.  

How many acres are equivalent to one square mile?

1 square mile= 640 acres.

To convert square miles to acres, we need to know that there are 640 acres in one square mile.

Given that the farm for sale measures one and three-quarter square miles, we can calculate the number of acres as follows:

1 and 3/4 square miles = 1.75 square miles  

Number of acres = 1.75 square miles * 640 acres/square mile

Number of acres = 1120 acres

Therefore, the farm for sale measures 1120 acres.

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How to solve this? I have no clue and also teach me on how to solve this! Thank you!!!

How to solve this? I have no clue and also teach me on how to solve this! Thank you!!!

Answers

Answer:

90 counterclockwise or 270 clockwise

Step-by-step explanation:

just trust me bro lolskies

2 Answers:B) 90 degrees counterclockwiseD) 270 degrees clockwise

====================================================

Explanation:

Through some strange formatting error, the tickmarks are not in the proper locations. They should be to the right and slightly above the letter. They should be close by, and not far away like that.  

It looks like the purple figure is the image while the blue figure is the preimage. If that's the case, then we've applied a 90 degree counterclockwise rotation to go from blue to purple.

Notice how angle AQA' is 90 degrees as shown by the green segments in the diagram below. So are BQB' and CQC' and DQD' as well.

We could also rotate the blue figure 270 degrees clockwise to arrive at the same purple image. Note how 90+270 = 360 which is a full circle.

How to solve this? I have no clue and also teach me on how to solve this! Thank you!!!

Question 3 The Schwarzschild metric is given by 2M 2M ds² -(₁-²M) di² + (1-²¹)- 1- dr² +r² (d0² + sin² 0 dó²). There are Killing vectors associated with time invariance and angular momen- tum invariance in the direction in this geometry leading to the conserved quantities e = (1-2) and l= r² sin² 0 dr From this one can derive an analog to the radial energy equation in Newtonian mechanics by orienting the coordinates so that the orbits are confined to the equatorial plane where 0 = π/2 and u = 0. One finds 2 1 dr + Veff (r) = E 2 dr (e²_ -1) where E = and Veft(r) = - + 2/²/²2 - Mp³². Further, for circular orbits one can show that M | [₁ + √/₁−12 (+1)]. r+= | 2M Finally, for circular orbits of radius R do 1/2 M dt R³ (a) Which value of r corresponds to the Schwarzschild radius of stable circular orbits: r or r? Justify your answer. [3 marks] (b) Show that for circular orbits of radius R do 1/2 M -1/2 3M (²) ¹² (1-³) dT R³ R where is the proper time. [6 marks] (c) A free particle is moving in a circular orbit around a spherical source of curvature of mass M. The Schwarzschild radius of the orbit is 8M. Use the equivalence principle to argue that the period as measured at infinity should be larger than that measured by the particle. [4 marks] (d) Find the period of the orbit as measured by an observer at infinity. Find the period of the orbit as measured by the particle. [7 marks] M

Answers

(A) Circular orbits of stable particles are possible at radii greater than three times the Schwarzschild radius for the non-rotating spherically symmetric mass.

This represents the radius of a black hole's event horizon, within which nothing can escape. The Schwarzschild radius is the event horizon radius of a black hole with mass M.

M can be calculated using the formula: r+ = 2Mwhere r+ is the radius of the event horizon.

(B)  1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ R. This is the required expression.

Tau is the proper time of the particle moving around a circular orbit. Hence, by making use of the formula given above:1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ dt.

(C) Time passes differently in different gravitational fields, and it follows that the period as measured at infinity should be larger than that measured by the particle.

The principle of equivalence can be defined as the connection between gravitational forces and the forces we observe in non-inertial frames of reference. It's basically the idea that an accelerating reference frame feels identical to a gravitational force.

(D) The period of the orbit as measured by an observer at infinity is 16π M^(1/2) and the period of the orbit as measured by the particle is 16π M^(1/2)(1 + 9/64 M²).

The period of orbit as measured by an observer at infinity can be calculated using the formula: T = 2π R³/2/√(M). Substitute the given values in the above formula: T = 2π (8M)³/2/√(M)= 16π M^(1/2).The period of the orbit as measured by the particle can be calculated using the formula: T = 2π R/√(1-3M/R).

Substitute the given values in the above formula: T = 2π (8M)/√(1-3M/(8M))= 16π M^(1/2)(1 + 9/64 M²).

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It is not possible to have more than one optimal solution to a linear programming problem. true. false.

Answers

No it is not possible,

[please mark brainliest!!]

gary has $227.36 in his bank account. her must maintain a minimum balance of $550 in his account to avoid paying monthly service fee. how much money can gary deposit into his account to avoid paying this fee?

Answers

Answer:322.64 (I think)

Step-by-step explanation:

550-227.36=322.64

Answer:

what the other person said here

Hi this is the question that I have. I don’t know if the one that I have chose is right or not. Please help me

Hi this is the question that I have. I dont know if the one that I have chose is right or not. Please

Answers

To answer this question we must carefully understand the scope of the numbers of the table.

* It represents the number of adults that listen to audiobooks or not. But not all adults, just the surveyed adults.

* Nothing is said about books, only about audiobooks.

Some of the choices are tricky. For example, second and fourth choices talk about books, so they must be discarded.

The third choice refers to all adults, but the table refers only to the 640 adults that were asked.

The first choice is the best question that can be answered using the table.

Given 9²m-¹x 9⁵ = 9m+², calculate the value of m.​

Answers

The value of m is 1/3.

To solve the equation 9²m⁻¹ × 9⁵ = 9m², we can simplify the equation and solve for the value of m.

Let's simplify the equation step by step:

9²m⁻¹ × 9⁵ = 9m²

Expanding the exponents:

(9²)(9⁵)(m⁻¹) = 9m²

Simplifying the exponents:

9^(2+5)(m⁻¹) = 9m²

Using the property\(a^{(m+n)\)= \(a^m \times a^n\):

9^7(m⁻¹) = 9m²

Applying the power of 9⁷:

9m⁻¹ = 9m²

Dividing both sides by 9m⁻¹:

1 = 9m²/m⁻¹

Dividing with the same base and different exponents, we subtract the exponents:

1 = \(9m^{(2-(-1))\)

Simplifying the exponents:

1 = 9m³

Now, we can solve for m by isolating it on one side of the equation:

m³ = 1/9

Taking the cube root of both sides:

m = ∛(1/9)

The cube root of 1/9 is the same as raising 1/9 to the power of 1/3:

m = \((1/9)^{(1/3)\)

Simplifying the cube root:

m = 1/3

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the average residential electrical power use (in hundreds of watts) per hour is given in the following table.

Answers

The average residential electrical power use refers to the amount of electrical energy consumed by households. It is typically measured in hundreds of watts per hour. By examining the provided table, you can identify the specific values for average power consumption in a residential setting.

According to the given table, the average residential electrical power use is measured in kilowatt-hours (kWh) per month, not hundreds of watts per hour. However, to convert it to the requested unit, we can divide the monthly average by the number of hours in a month (720 hours) and then multiply by 100 to get the average residential electrical power use in hundreds of watts per hour.

So, for example, if the monthly average is 600 kWh, the hourly average would be (600 kWh / 720 hours) x 100 = 83.33hundreds of watts per hour.

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According to a Nielsen survey, radio reaches 88% of children each week. Suppose we took weekly random
samples of n = 125 children from this population and computed the proportion of children in each sample
whom radio reaches.
What will be the shape of the sampling distribution of the proportions of children the radio reaches?

Choose 1 answer:

A. Skewed to the left
B. Skewed to the right
C. Approximately normal
D. Uniform

Answers

Answer:

C. Approximately normal

Step-by-step explanation:

We know that when we have,  np≥10, and  n(1−p)≥10, and both of these are true, where n is the sample size, and p is the sample of proportions, the sampling proportions of sample distributions, will be normal in shape.

Expected successes : np=125(0.88)=110≥10

Expected failures : n(1−p)=125(1−0.88)=15≥10

Write an equivalent expression in standard form for (6z-3)(8z+9)-13(45-7z-z^2).

Answers

Answer:

61 z ^2 + 121 z − 612

Step-by-step explanation:

Using y/x = k, what is the value of k for Jack's data?

Using y/x = k, what is the value of k for Jack's data?

Answers

Answer:

1

Step-by-step explanation:

a box contains some green marbles and exactly four red marbles. the probability of selecting a red marble is $x\%$. if the number of green marbles is doubled, the probability of selecting one of the four red marbles from the box is $(x - 15)\%$. how many green marbles are in the box before the number of green marbles is doubled?

Answers

The number of green marbles in the box before the number of green marbles is doubled is given by \($\frac{4 - 4x + 60}{2x - 30}$\\\), where x is the probability of selecting a red marble before the number of green marbles is doubled.

Let the number of green marbles be 'g'.

The probability of selecting a red marble before the number of green marbles is doubled is\($\frac{4}{g+4} * 100 = x\%$\)

The probability of selecting one of the four red marbles from the box after the number of green marbles is doubled is \($\frac{4}{2g+4} * 100 = (x - 15)\%$\)

Rearranging the equations and solving for g, we get:

\(\frac{4}{g+4} * 100 = x$\frac{4}{2g+4} * 100 = (x - 15)$$2g+4 = \frac{4}{x-15}$$g = \frac{4 - 4x + 60}{2x - 30}$\)

Therefore, the number of green marbles before the number of green marbles is doubled is \($\frac{4 - 4x + 60}{2x - 30}\)

The number of green marbles in the box before the number of green marbles is doubled is given by \($\frac{4 - 4x + 60}{2x - 30}$\\\), where x is the probability of selecting a red marble before the number of green marbles is doubled.

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player
100%
X Pri
A total of 400 students were surveyed at a college to see if they live in on-campus dorms or if they live off-campus. The table shows the results of
the survey
Dorms Off-Campus Total
Freshman 88 12 100
Sophomore 62 38 100
Junior 43
57 100
Senior 25 75 100
Total 218 182 400
What percentage of the students surveyed live off-campus?
O A 18.25
OB. 41.29
OC 45.55
OD 83.55
RESET
Question #24
DELL

Answers

Answer:

\(\%Off-Campus = 45.5\%\)

Step-by-step explanation:

Given

----------------------Dorms ---- Off-Campus ---- Total

Freshman -------- 88  ------  ---------12   ------- 100

Sophomore  ------62  ---------------38  --------- 100

Junior --------------43 -----------------  57  ---------- 100

Senior -------------25  -----------------75  ------------ 100

Total ---------------218 -------------182  --------------400

Required

Determine the percentage of off-campus students

From the above table, we have that:

\(Off-Campus = 182\)

\(Total\ Surveyed = 400\)

The percentage is then calculated as follows;

\(\%Off-Campus = \frac{Off-Campus}{Total-Surveyed} * 100\%\)

\(\%Off-Campus = \frac{182}{400} * 100\%\)

\(\%Off-Campus = 0.455 * 100\%\)

\(\%Off-Campus = 45.5\%\)

Hence, option C answers the question

Answer:

oh 45%

Step-by-step explanation:

Here is a restaurant's menu.
Starter
Prawn Cocktail
Duck Spring Rolls
Lamb Meatballs
Leaf Salad (V)
Mushroom Soup (V)
(V) denotes vegetarian
Main
Hunter's Chicken
Beef Curry
Steak
Fish Pie
Lasagne
Egg Salad (V)
Vegetable Hot Pot (V)
Macaroni Cheese (V)
Dessert
Trifle
Ice Cream
Cheesecake
Chocolate Cake
Bakewell Tart
Fruit Salad (V)
Cherry Pie (V)
(a) A 3-course meal consists of one starter, one main and one dessert.
Work out how many different 3-course meals can be chosen from the menu.

Answers

Answer:6

Step-by-step explanation:

A woman bought 50 meters of cloth at 60 cedis . she sold the cloth at 1.50 cedis per meter. Find her percentage profit.​

Answers

Answer:

25 %

Step-by-step explanation:

Cost price = 60 Ghana cedis for 50 metres

Selling price = 1.50 cedis for 1 meter

x cedis for 50 meters

Cross multiply

Selling price = 75 cedis

Profit = Selling price - Cost price

75 - 60

Profit = 15

Profit % =

\( \frac{profit}{cost \: price} \times \frac{100}{1} \\ \frac{15}{60} \times \frac{100}{1} \\ \\ \)

Profit % = 25 %

how many ways can six of the letters of the word algorithm be selected and written in a row if the first two letters must be or?

Answers

There are 840 ways to six letters of ALGORITHM be written in a row with first two letters OR.

Given in the question:

The word ALGORITHM has 9 letters. We want them to be written in a row, which means, order of the letters are important, so, we will use Permutation.

Formula for Permutation:

P(n,r) = n!/(n-r)!

we will use 7 letters out of 9 letters and 4 letters

n= 7 and r = 4

Now, we will put values in the formula:

P(7,4) = 7! / (7-4)!

P(7,4) = 7! / 3!

P(7,4) = 7 × 6 × 5 × 4

= 840.

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15 points look at picture

15 points look at picture

Answers

Answer:

The line that represents a proportional relationship is y3 which is letter C in the Cartesian Plane

Explanation:

The line that goes through the origin of where x-axis and y-axis meet or intersect at the same point is called a proportional relationship

Beth and Carly are selling candy bars to raise money for New cheerleading uniforms Beth has sold one less than twice the number of candy bars that Carly has sold if they have sold 188 candy bars and all how many has Beth sold

Answers

The number of candy bars that Beth has sold, given the total they have sold and the amount sold by Carly, is 125 candy bars

How to find the number of candy bars sold ?

To find the number of candy bars that Beth has sold, you can assume that the amount of candy sold by Carly is denoted as x.

This means that the amount of candy bars sold by Beth is:

= 2x - 1

The total sold by both Beth and Carly is therefore:

= 2x - 1 + x

The number of candy bars sold by Carly is:

188 = 2x - 1 + x

188 = 3x - 1

3x = 188 + 1

x = 189 / 3

x = 63

This means that the candy bars sold by Beth is:

= 2 ( 63 ) - 1

= 126 - 1

= 125 candy bars

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A student drops a ball from the top of a tall building and it takes 3 seconds for the ball to reach the ground. What is the height of the building in meters? Round your answer to one decimal place.

Answers

The height of the building is approximately 44.1 meters.

To find the height of the building, we can use the equation of motion for an object in free fall:

h = (1/2) * g * t^2,

where h is the height, g is the acceleration due to gravity, and t is the time taken.

Given that the time taken for the ball to reach the ground is 3 seconds, and the acceleration due to gravity is approximately 9.8 m/s^2, we can substitute these values into the equation to find the height:

h = (1/2) * 9.8 m/s^2 * (3 s)^2

h ≈ 44.1 meters.

Explanation:

When an object is dropped from a height, it experiences free fall due to the force of gravity. The height of the building can be determined by considering the time it takes for the ball to reach the ground.

Using the equation h = (1/2) * g * t^2, where h is the height, g is the acceleration due to gravity, and t is the time taken, we can solve for the height.

Given that the time taken for the ball to reach the ground is 3 seconds, and the acceleration due to gravity is approximately 9.8 m/s^2 on Earth, we can substitute these values into the equation:

h = (1/2) * 9.8 m/s^2 * (3 s)^2

Simplifying the equation, we have:

h = 4.9 m/s^2 * 9 s^2

h = 44.1 meters

Therefore, the height of the building is approximately 44.1 meters.

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What is the nth term of the sequence below?

2, 6, 12, 20, . . .

A. \(n {}^{2} \: + \: 1\)

B. \(3n\)

C. \(n(n \: + \: 1)\)

D. \( {n}^{2} \: - \: 1\)

Answers

Answer:

Option C

Kindly award branliest

Step-by-step explanation:

Tn = n(n + 1)

T1 = 1(1 +1) = 1(2) = 2

T2 = 2(2+1) = 2(3) =6

T3 = 3(3 + 1) = 3(4) = 12

T4 = 4(4 + 1) = 4(5) = 20

... It obeys

How do you describe the lengths of the third side of the two triangles?

Answers

The lengths of the third side of the triangles can be achieved by using the Pythagorean theorem, which says in a right triangle, the sum of the squares of the two shorter sides is equal to the square of the hypotenuse.

How to illustrate the information?

Three vertices make up the three-sided polygon known as a triangle. There is a point where the three sides are joined end to end.

A triangle's third side must always have a length that falls between (but not exactly equal to) the sum and difference of the other two sides. Consider the examples 2, 6, and 7 as an example. The third side length must therefore be greater than 4 and less than 8.

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.Given the following Venn diagram, find n[ A ∪ ( B ∩ C ) ].
a) 76
b) 78
c) 74
d) 79
e) 73
f) None of the above.

Answers

The answer is (f) None of the above.

How do we find n?

We can use the inclusion-exclusion principle to find the cardinality of the set A ∪ (B ∩ C). The formula is:

n(A ∪ (B ∩ C)) = n(A) + n(B) + n(C) - n(B ∪ C) - n(A ∩ B ∩ C)

We are given the values of n(A), n(B), n(C), n(A ∩ B), n(B ∩ C), and n(C ∩ A) from the Venn diagram. We can use these values to find n(B ∪ C) and n(A ∩ B ∩ C) as follows:

n(B ∪ C) = n(B) + n(C) - n(B ∩ C)

n(A ∩ B ∩ C) = n(A) + n(B) + n(C) - n(A ∪ B) - n(B ∪ C) - n(C ∪ A) + n(A ∩ B ∩ C)

Substituting the values from the Venn diagram, we get:

n(B ∪ C) = 50 + 28 - 16 = 62

n(A ∩ B ∩ C) = 18 + 16 + 28 - 50 - 62 - 20 + 10 = 0

Therefore,

n(A ∪ (B ∩ C)) = n(A) + n(B) + n(C) - n(B ∪ C) - n(A ∩ B ∩ C) = 32 + 50 + 20 - 62 - 0 = 40

So the answer is (f) None of the above.

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Pls answer fast A 4-column table with 4 rows. Column 1 is labeled Principal (dollars) with entries 3,300, 3,300, 3,300, 3,300. Column 2 is labeled Interest Rate with entries 0.045, b, 0.045, 0.045. Column 3 is labeled Years with entries 1, 3, 7, c. Column 4 is labeled Interest (dollars) with entries a, 445.50, 1,039.50, 1,188.00. Find the values to complete the table. a = b = c =

Answers

Answer:

a=148.50

b=0.045

c=8

Step-by-step explanation:

i just took the quiz on edgeunity

All the value of variables are,

a = 148.50, b = 0.05, and c = 8

Now, For the values of a, b, and c in the table, we can use the formula for simple interest:

I = Prt

where I is the interest earned in dollars,

P is the principal in dollars,

r is the interest rate per year as a decimal, and t is the time in years.

Hence, By Using this formula, we can solve for the missing values in the table as follows:

For the first row, we have

P = 3300, r = 0.045, and t = 1.

We can plug in these values and the given value of a = into the formula to solve for a:

a = Prt

a = 3300 x 0.045 x 1

a = 148.50

Therefore, a = 148.50 for the first row.

For the second row, we have P = 3300, t = 3, and I = 445.50.

We can plug in these values and solve for r:

I = Prt

445.50 = 3300 x r x 3

r = 0.05

Therefore, b = 0.05 for the second row.

For the third row, we have P = 3300, t = 7, and I = 1039.50. We can plug in these values and solve for r:

I = Prt

1039.50 = 3300 x r x 7

r = 0.045

Therefore, c = 7 for the third row.

For the fourth row, we have P = 3300, t = c, and I = 1188.00. We can plug in these values and solve for c:

I = Prt

1188.00 = 3300 x 0.045 x c

c = 8

Therefore, c = 8 for the fourth row.

Thus, we have a = 148.50, b = 0.05, and c = 8 to complete the table.

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