What is the square root of ab^2 ?

Answer:

16.01%

Step-by-step explanation:

150 - 125.99 = 24.01

What percent is 24.01 of 150

(x/100) = (24.01 / 150)

= 16.01%

Answer:

So the answer is 24%

Step-by-step explanation:

So you have to subtract the two numbers and closley approximate the neares decimal you get and i got 24.01 and just rounded it to 24%.

Answer:

2.3

v

−

5

Step-by-step explanation: your welcome

Answer:

v=-2.1739

Step-by-step explanation:

-2.3v-5=0   so -2.3v=5 divide by -2.3 on both sides and get -2.1739

Step 1

Consider all options

Hence the answer is option A

Answer:

Un = -n²

Step-by-step explanation:

Un = -n²

it's a quadratic term but with minus sign, just it

U1 = -1² = -1

U2 = -2² = -4 and so on

Answer:

x=34

y=17

Step-by-step explanation:

Let Paula's score be= x

Let Maria's score be=y

Given:

x=2y

x+y=51

Substitution:

2y+y=51

Formula:

2y+y=51

3y=51

y=17

x=2y

x=2(17)

x=34

Proof:

x+y=51

34+17=51

51=51

Hope this helps ;) ❤❤❤

The slope of this line is 0. If you graph the line y=10, for any x value, the y-value remains 10 (denoted because x is equal to 0 in the actual equation shown, which means that x will not be shown in the equation). The graph would basically just be a straight horizontal line, neither curving up or down.

6.2w + 18.76 + 1.9w = -16.39 + 4.4w

Put on one side of the equation the w values and in the other sides the number values:

6.2w+1.9w-4.4w= -16.39-18.76

3.7w= -35.15

Divide both sides of the equation by 3.7

3.7w/3.7 = -35.15/3.7

w= -9.5

The marginal cost will most likely increase to $2.00

Marginal cost is the change in the production costs that would be required to make one extra unit of production.

The marginal costs will continue to rise, increasing the total cost, while the marginal revenue remains the same, decreasing the profit.

For example, if a company produces a cup for $5, and 10 cups would be $50, therefore, the marginal cost is the extra cost it would take to manufacture an additional cup.

Hence, the marginal cost will most likely increase to $2.00

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Answer:

B The marginal cost will most likely increase to $2.00

Step-by-step explanation:

I took the assignment. :)

Answer:

In China, $0.45

Hope it helps!

Solution:

The population of cockroaches grows exponentially. 2 months ago there were 3 cockroaches, now there are 18.

As this is exponential growth, it can be modeled with the following formula:

Applying the laws of exponents, this is equivalent to:

where y(t) is the number of cockroaches at time t, a is the initial population. In this case, we want to find k.

Now, we know a=3, t=2, and right now y(2)=18:

this is equivalent to:

Take the natural logarithm of both sides:

this is equivalent to:

solving for k, we get:

Therefore, we have created a real-life problem that uses the laws of exponents.

The proof that ∠FCB≅∠DCE is shown below

Given that AECF is a rhombus, opposite angles of the rhombus are congruent.

This is represented as

∠EAF = ∠ECF

Also, given that EB ≅ FD, we can conclude that:

∠EBF = ∠DFC

This is by the definition of congruent segments having equal corresponding angles

Add the angles

∠CEB + ∠EBF = ∠CEB + ∠DFC = 180°

Recall that

Since ∠CEB = ∠AEF

So, we have:

∠AEF + ∠EBF = ∠AEF + ∠DFC = 180°

Hence, ∠FCB=∠DCE.

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When training a classifier, the training set is used to learn the conditional probabilities.

The training set is used to learn the conditional probabilities because the training set is used to train the classifier on the patterns and features in the data, which in turn helps the classifier to learn the conditional probabilities of the different classes in the data.

The hold-out set and test set are used to evaluate the performance of the classifier and ensure that it is not overfitting to the training set.

By evaluating the classifier on data that it has not seen before, we can get a more accurate estimate of its true performance and the probability of correctly classifying new data.

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We can use Coulomb's law to calculate the magnitude of the electric field at a distance r away from a point charge Q:

E = k * Q / r^2

where k is Coulomb's constant, Q is the charge of the point charge, and r is the distance from the point charge.

In this problem, we have a point charge Q of -10 nC located at (1.2 cm, 0 cm), and we want to find the x-component of the electric field at a distance r = 5.3 cm away at position (-4.1 cm, 0 cm).

To find the x-component of the electric field, we need to use the cosine of the angle between the electric field vector and the x-axis, which is cos(180°) = -1.

So, the x-component of the electric field at position (-4.1 cm, 0 cm) is:

E_x = - E * cos(180°) = - (k * Q / r^2) * (-1)

where k = 9 x 10^9 N*m^2/C^2 is Coulomb's constant.

Substituting the given values, we get:

E_x = - (9 x 10^9 N*m^2/C^2) * (-10 x 10^-9 C) / (0.053 m)^2

E_x ≈ -30,566.04 N/C

Rounding this to two significant figures and including the appropriate units, we get:

The x-component of the electric field is about -3.1 x 10^4 N/C (to the left).

Answer:

Step-by-step explanation:

Slope of the line.

The Steady-state gain can be found using the formula Kp = lim s->0 G(s).

A. (a) The inverse Laplace transform of the function 8 /s² (s+2) is given by f(t) = 8(t - e^(-2t)).

B. (a) To find the inverse Laplace transform of 8 /s² (s+2), we can use partial fraction decomposition and inverse Laplace transform tables.

First, we express the function in partial fraction form as follows: 8 /s² (s+2) = A/s + B/s² + C/(s+2).

To find the values of A, B, and C, we can equate the coefficients of corresponding powers of s in the numerator and denominator. This leads to the equations A + 2B + 2C = 0, A = 8, and B = -8.

Substituting the values of A and B into the equation A + 2B + 2C = 0, we find C = 4.

Now, we have the partial fraction decomposition as: 8 /s² (s+2) = 8/s - 8/s² + 4/(s+2).

Using inverse Laplace transform tables, we find the inverse Laplace transforms of each term: L⁻¹{8/s} = 8, L⁻¹{8/s²} = 8t, and L⁻¹{4/(s+2)} = 4e^(-2t).

Finally, we combine the inverse Laplace transforms of each term to obtain the inverse Laplace transform of the original function: f(t) = 8(t - e^(-2t)).

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The age of Layla who youngest of four siblings is 18 years old

The age of 4 sibling are in consecutive even integers

Age of 1st sibling = x

Age of 2nd sibling = x + 2

Age of 3rd sibling = x + 4

Age of 4th sibling = x + 6

Sum of the sibling age = 84

x + x + 2 + x + 4 + x + 6 =84

4x + 12 = 84

4x = 84 -12

4x = 72

x = 18

Layla is youngest  sibling hence her age will be 18 years

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The question is incorrect the correct question is :

Layla is the youngest of four siblings whose ages are consecutive even integers. If the sum of their ages is 84, find Layla's age

The correct statement explain for the given ratio of boys to girls of 3:4 is - this fraction of girls in the class is found to be 4/7.

Irrespective whatever how a ratio is expressed, it is crucial to reduce it to the fewest whole numbers, just like with any fraction. To accomplish this, divide the integers by their largest common factor after discovering it.

Ratios can also be expressed as a fraction because they are straightforward division problems. Some folks prefer to use merely words to express ratios.

Class contains a ratio of boys to girls of 3: 4.

So, Boys / Girl = 3 / 4

Total students = boys  + girls.

Total students = 3 + 4 = 7

So,

Girl / Total = 4/7

Thus, the correct statement explain for the given ratio of boys to girls of 3:4 is - this fraction of girls in the class is found to be 4/7.

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The complete question is-

A class has a ratio of boys to girls 3:4.

Select correct option:

a) The fraction of boys in the class is 3/4

b) The fraction of girls in the class is 4/7

c) The number of boys in the class is 6

d) The number of pupils in the class is 12

Answer:

1 and 3

Step-by-step explanation:

the volume occupied by the mixture of N2 and O2 gases at 0.83 atm and 42.7°C is approximately 41.62 liters.

To find the volume occupied by the mixture of gases, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure of the gases (in atm)

V = volume of the gases (in liters)

n = number of moles of gas

R = ideal gas constant (0.0821 L.atm/mol.K)

T = temperature of the gases (in Kelvin)

First, let's convert the temperature from Celsius to Kelvin:

T(K) = T(C) + 273.15

T(K) = 42.7 + 273.15

T(K) = 315.85 K

Now we can calculate the volume:

For N2:

n(N2) = 0.522 mol

P(N2) = 0.83 atm

T = 315.85 K

For O2:

n(O2) = 0.522 mol

P(O2) = 0.83 atm

T = 315.85 K

Using the ideal gas law for each gas:

V(N2) = (n(N2) * R * T) / P(N2)

V(O2) = (n(O2) * R * T) / P(O2)

Calculating the volumes:

V(N2) = (0.522 * 0.0821 * 315.85) / 0.83

V(N2) ≈ 20.81 L

V(O2) = (0.522 * 0.0821 * 315.85) / 0.83

V(O2) ≈ 20.81 L

Since the number of moles and pressure are the same for both gases, the volumes will also be the same.

To find the total volume occupied by the mixture of gases, we can sum the individual volumes:

V(total) = V(N2) + V(O2)

V(total) = 20.81 + 20.81

V(total) ≈ 41.62 L

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The function f is increasing on the interval (6, ∞).

The function f will be increasing in the intervals where f'(x) > 0.

To find these intervals, we can examine the sign of each factor of f'(x), which is (x + 1)²(x - 3)⁵(x - 6)⁴.

We can analyze the sign of f(x) by considering the factors individually:

(x+1)²: This factor is always positive since it is the square of a real number.

(x - 3)⁵: This factor is positive when x>3 and negative when x< 3.

(x - 6)⁴: This factor is positive when x>6 and  negative when x< 6.

We need to consider the overlapping regions of positivity for each factor.

When x>6, all three factors are positive, so  f ′ (x) is positive.

When 3<x<6: In this interval, the factor  (x+1)² is positive, but both (x−3)⁵ and (x−6)⁴ are negative.

Thus, f ′ (x) is negative.

When x<−1: In this interval,  (x+1)² is negative, while (x−3)⁵ and (x−6)⁴ are positive.

Hence, f ′ (x) is negative.

Therefore,  the function f(x) is increasing on the interval x>6.

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I hope it will help you .

Thank you.

^ - ^

Answer:

53 inches = 4.41667 ft

Step-by-step explanation:

1 ft = 12 inches

53 inches = 53/12 = 4.41667 ft

Answer:

Step-by-step explanation:

fr had to delete my answer i tried my best u ungrateful peice of shat

First step is to add x to both sides.

Second step is cube both sides.

Solving this equation for x initially yields three possible solutions.

Checking the solutions show that -2, 0 and 2 are valid solutions.

If we set m = 4 and n = 1, we get a = 15 and c = 17, which means (15, 60, 17) is a primitive Pythagorean triple with b = 4T5. Also, we can find primitive Pythagorean triples with b = 4T6 and b = 4T7 by using the same method. We get (21, 84, 87) for b = 4T6 and (28, 112, 113) for b = 4T7. Therefore, it is clear that for every triangular number Tn, there is a primitive Pythagorean triple (a, b, c) with b = 4Tn

A Pythagorean triple is a set of three integers that satisfy the Pythagorean theorem, which states that the sum of the squares of the lengths of the two shorter sides of a right triangle is equal to the square of the length of the longest side, or hypotenuse. For example, the triple (3, 4, 5) is a Pythagorean triple because 3^2 + 4^2 = 5^2.

Now let's talk about triangular numbers. A triangular number is the sum of the first n positive integers, and it can be represented by the formula Tn = 1 + 2 + 3 + ... + n = (n(n+1))/2. The first few triangular numbers are 1, 3, 6, and 10.

Interestingly, in the list of the first few Pythagorean triples, we can observe a pattern where the value of b is four times a triangular number. For example, in the Pythagorean triple (3, 4, 5), we have b = 4T1. In (5, 12, 13), b = 4T2. In (7, 24, 25), b = 4T3. And in (9, 40, 41), b = 4T4.

So the question is: is this pattern true for all triangular numbers? Let's investigate further.

a) To find a primitive Pythagorean triple (a, b, c) with b = 4T5, we need to find a value of a and c such that a^2 + b^2 = c^2 and b = 4T5. Using the formula for T5, we get T5 = (5(5+1))/2 = 15. Therefore, b = 4T5 = 60. We can use the Euclid's formula for generating Pythagorean triples, which states that for any two positive integers m and n with m > n, a Pythagorean triple (a, b, c) can be generated by a = m^2 - n^2, b = 2mn, and c = m^2 + n^2.

If we set m = 4 and n = 1, we get a = 15 and c = 17, which means (15, 60, 17) is a primitive Pythagorean triple with b = 4T5.

Similarly, we can find primitive Pythagorean triples with b = 4T6 and b = 4T7 by using the same method. We get (21, 84, 87) for b = 4T6 and (28, 112, 113) for b = 4T7.

b) Now, the question is whether there is a primitive Pythagorean triple (a, b, c) with b = 4Tn for any triangular number Tn. Let's assume this is true and try to prove it.

Using the same Euclid's formula, we can generate a primitive Pythagorean triple (a, b, c) with b = 4Tn by setting m = 2Tn+1 and n = Tn. This gives us a = 4Tn^2 + 1 and c = 4Tn^2 + 2Tn + 1, and we can verify that b = 4Tn using the formula for Tn.

Therefore, we have proven that for every triangular number Tn, there is a primitive Pythagorean triple (a, b, c) with b = 4Tn

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