What is the speed of sound (in m/s) in carbon dioxide at the normal boiling temperature of water?

The light's peak wavelength gets shorter as it emits more light. Black-body radiation is the thermal electromagnetic radiation that a black body emits when it is in thermodynamic equilibrium with its surroundings.

It possesses a distinct, continuous spectrum of wavelengths that are inversely correlated with intensity and solely dependent on the body's temperature, which is considered to be homogeneous and constant for the purposes of computations and theory.

A black body's intensity falls along with its temperature, and its peak shifts to longer wavelengths. The traditional Rayleigh-Jeans law and its ultraviolet catastrophe are displayed for comparison. If a hole is cut in the wall of a fully insulated container that is thermally equilibrated internally, the hole will still radiate black body radiation as long as it doesn't significantly affect the equilibrium.

Many common things will spontaneously release thermal radiation that can be roughly compared to black-body radiation.

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Answer:

most likely just 1

Explanation:

I sucked at sig figs in middle school, in fact it was the lowest test grade i ever received, but it is relatively simple.

because there is only one sig fig involved in each number, there can't be multiple sig figs here. 3000/500=6

500/3000=2(round up from 1.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666) you get the point.

Kinetic energy is the energy when a object is in motion. ...  energy gets transferred to the object,  The energy transferred is kinetic energy, and it depends on the mass and speed.

Explanation:

Answer:

32.0 Ω

Explanation:

Ohm's law:

V = IR

128 V = (4.00 A) R

R = 32.0 Ω

If 128 volts are required to push 4.00 A of current through a resistor, then the resistance of the resistor is 32 ohms, and Ohm's Law is used to solve for the resistance of the resistor.

Ohm's Law is a fundamental law of electricity that relates the three basic electrical quantities of voltage, current, and resistance, and states that the current flowing through a conductor is directly proportional to the voltage applied across it and is calculated below,

Ohm's Law is used to solve for the resistance of the resistor

Ohm's Law: V = IR

(Here, V =the voltage (in volts), I =the current (in amperes), and R =the resistance (in ohms) )

Given , 128 V is required to push 4.00 A of current through the resistor, one can substitute these values into Ohm's Law and R is solved,

R = V/I

R = 128 V / 4.00 A

R = 32 Ω

Hence, if 128 volts are required to push 4.00 A of current through a resistor, then the resistance of the resistor is 32 ohms.

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The slowly fluctuating harmonic patterns by composer philip glass, used in his quatsi trilogy, represent minimalism musical style.

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When heat flows through a glass windowpane, the primary heat transfer mechanisms involved are conduction and radiation.

Conduction occurs as heat moves through the solid glass material, with molecules transferring energy to their neighbors. Radiation is the emission of infrared energy from the warm side of the glass to the cooler side, transferring heat in the form of electromagnetic waves without the need for direct contact or a medium. Convection is less significant in this context since it involves the transfer of heat through fluid motion, which doesn't occur within the solid glass windowpane.

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Answer:

Explanation:

The mass of an object given it's force and acceleration can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{15}{5} = 3 \\ \)

We have the final answer as

Hope this helps you

How hard you must push down on the handle is by applying a force of 215.63 N

The moment of a force about a point is the turning effect of the force about that point.

The moment of a force M = Fd where

Now, for you to lift up the car, the moment due to your force about the fulcrum, M equals the moment due to the force on back of car. M'

M = M'

FD = F'd where

Making F subject of the formula,we have

F = F'd/D

Substituting the values of the variables into the equation,we have

F = F'd/D

F = 6900 N × 0.050 m/1.6 m

F = 345 Nm/1.6 m

F = 215.625 N

F ≅ 215.63 N

So, how hard you must push down on the handle is by applying a force of 215.63 N

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Answer:

S=29.298m/s

Explanation:

Use S=d/t

So, S=120m/4.1s= 29.298m/s

Given

d: diameter

d = 41 cm

We need radius information so we will calculate it:

r: radius

r = d/2

r = 41/2

r = 20.5 cm

Rotating speed

w = 242 rpm

Procedure

At a distance r from the center of the rotation, a point on the object has a linear speed equal to the angular speed multiplied by the distance r. The units of linear speed are meters per second, m/s.

But before using the formula we need to have all the units in the same system. So we need to go from rpm to rad/s and from cm to m

Now we can calculate the linear velocity of the belt.

Answer

The linear velocity of the belt would be 5.2 m/s.

The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.

Given:

Current (I) = 5 mA = 5 * 10^(-3) A

Resistance (R) = 18 kΩ = 18 * 10^(3) Ω

Using Ohm's Law, we can calculate the voltage drop (V):

V = I * R

= (5 * 10^(-3) A) * (18 * 10^(3) Ω)

= 90 V

Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

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Answer:

60°

Explanation:

Formula

360/n (if the number is an odd number) or

360/n-1 (if the number is even) (to arrive at an odd number)

SO. 5 is an odd number but not a multiple of 360, so we will use 6 an even number.

360/60-1

360/60=6 images

6-1 =5 images

Thus. the images formed will be 5.

Answer:

It's D, they're all radioactive. This is due to the molecules that it is made up of

Answer:

the answer is A

Explanation:

I hope it helps you

Answer:

Work hasn't been done by Michael because no distance was covered.

Explanation:

Workdone is given by the formula;

\( Workdone = F * s\)

Where;

W is the work done

F represents the force acting on a body.

s represents the distance covered by the body.

Hence, work hasn't been done by Michael because no distance was covered, as the table didn't move at all. Therefore, work done is zero.

The density of water is 1.0 g/cm³. It's required to determine the mass of water displaced by a submerged 120-cm³ block and the buoyant force on the block.To find the mass of water displaced by a 120 cm³ block, we first need to know the mass of 1 cm³ of water, which is equal to its density, which is 1.0 g/cm³.

The volume of the block is 120 cm³, so we can calculate its mass by multiplying its volume by the density of water. Therefore, the mass of the block submerged in water is:120 cm³ × 1.0 g/cm³ = 120 gTo find the number of kilograms, we divide the value obtained by 1000. Therefore, 120 g = 0.12 kg.The buoyant force is equal to the weight of the water displaced by the block. The buoyant force equals the weight of water displaced by the object.

The weight of 1 cm³ of water is 9.8 N (newtons), which is equal to the weight of 1 g of water. We can use this to calculate the weight of water displaced by the block as follows:120 cm³ × 1.0 g/cm³ × 9.8 N/g = 1176 NTherefore, the buoyant force acting on the block is 1176 N (Newtons).

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Explanation:

No. Surface contact area also no. The main issue is the types of materials in contact. Surface roughness somewhat matters. Certain surfaces such as ice are special in that pressure melts the ice.

Answer:

C

Explanation:

Quantization of electron energy states in an atom is a fundamental concept in atomic physics and quantum mechanics. It refers to the discrete and distinct energy levels that an electron can occupy in an atom.

This quantization is better understood in terms of the electron's wave-like nature. The electron behaves like a wave, and its energy is related to the wavelength and frequency of the wave.
The wave-like behavior of the electron was first proposed by Louis de Broglie in 1924, and it was later confirmed by experiments. According to de Broglie's theory, electrons have wave-particle duality, meaning that they can exhibit both wave-like and particle-like behavior. When an electron is confined to an atom, its wave-like behavior leads to the quantization of energy levels.
The quantization of energy levels in an atom arises from the fact that electrons can only occupy specific orbitals around the nucleus. These orbitals have specific energies associated with them, and the electron can only exist in one of these energy levels. When an electron absorbs or emits energy, it must do so in discrete packets or quanta, which correspond to the energy difference between the energy levels.
In summary, the quantization of electron energy states in an atom is a consequence of the wave-like nature of the electron. It arises from the fact that electrons can only occupy specific orbitals around the nucleus, and their energies are quantized in these orbitals. This concept is fundamental to our understanding of atomic structure and has important implications for a wide range of fields, including chemistry, materials science, and electronics.

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Answer:

Moonlight; phases; eight; 29 days; sunlit; earth; sun; moon.

Explanation:

A moon generally do not have or possess light but rather it reflects the light from the sun.

The moon is lit by light bouncing off of it. That light reaches Earth as moonlight. The different shapes that the moon appears to have are called phases. The moon goes through eight (8) phases as it revolves around the earth every 29 days. The phase that we see depends on how much of the sunlit part of the moon we can see. This depends on the positions of the earth, sun, and moon.

The eight (8) phases of the moon include the following;

1. Last quarter half moon.

2. Waning crescent moon.

3. New moon.

4. Waxing crescent moon.

5. First quarter half moon.

6. Waxing Gibbous moon.

7. Full moon.

8. Waning Gibbous moon.

The larger resistance is R₂ =12Ω.

Resistance values are expressed in ohms (Ω). when an electron differential exists among terminals, energy will float from excessive to low. Resistance counteracts that waft. The greater the resistance, the lower the current. Conversely, the decrease in the resistance, the extra the modern.

series connection:- R equivalent = R₁ + R₂

                                     R₁ + R₂ = 13.6 Ω

R₁ = 13.6 Ω - R₂

parallel connection:- R equival;ent =  R₁R₂ / R₁ + R₂

                                       2.40 = R₁R₂ / R₁ + R₂

2.40 = R₁R₂ / 13.6 Ω

R₁R₂ = 2.40 × 13.6 Ω

 R₁R₂ = 32.64 Ω

2.40 = R₁R₂ / R₁ + R₂

R₁ + R₂ =  32.64 Ω /  2.40 Ω

R₁ + R₂ = 13.6.

​  must be 4.0Ω and 13.6Ω, respectively.

(a) The smaller resistance is R₁ =4.0Ω

(b) The larger resistance is R₂ =12Ω

An electric-powered cutting-edge flows when electrons flow through a conductor, consisting of a metallic cord. The moving electrons can collide with the ions in the steel. This makes it greater tough for the present day to flow, and reasons for resistance.

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Final velocity = 57.8m/s

What is acceleration?

In mechanics, acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object

Acceleration = (Initial velocity - Final velocity) /time

Given,

time = 3.4s

Acceleration = 17 m/s^2

17 = (0-v)/3.4

final velocity = 17 X 3.4 = 57.8 m/s

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Answer:c 40kg

Explanation:

Answer:

B. 30 kg * m/s

Explanation:

college board answer

Answer:

90%

Explanation:

if you lose 10% of a 100 you get 90

Answer:

Explanation:

Let the magnitude of magnetic field be B .

flux passing through the coil's  = area of coil x field x no of turns

Φ = 3.13 x 10⁻⁴ x B x 135 = 422.55 x 10⁻⁴ B .

emf induced = dΦ / dt , Φ is magnetic flux.

current i = dΦ /dt x 1/R

charge through the coil = ∫ i dt

= ∫   dΦ /dt x 1/R dt

= 1 / R ∫ dΦ

= Φ / R

Total resistance R = 61.1 + 44.4 = 105.5 ohm .

3.44 x 10⁻⁵ = 422.55 x 10⁻⁴ B / 105.5

B = 3.44 x 10⁻⁵ x 105.5  / 422.55 x 10⁻⁴

= .86 x 10⁻¹

= .086 T .

Computerized axial tomography is a noninvasive roentgenography diagnostic technique.

Tomography can be described as imaging by sections or sectioning that uses any type of penetrating wave. The method is used in biology, radiology, archaeology, geophysics, atmospheric science, oceanography, plasma physics, astrophysics, materials science, quantum information, and other areas of science.

In some cases, the production of images will be based on the mathematical procedure of tomographic reconstruction, such as X-ray computed tomography being produced from projectional radiographs.

Most algorithms come into these two categories: filtered back projection (FBP) and iterative reconstruction (IR). Optical coherence tomography is transmission methods, they do not require movement of the transmitter to need data from different directions.

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Trench collapses typically involve large areas of falling dirt that weigh approximately 200 lb per cubic foot.

Trench collapses occur when the walls of a trench or excavation fail and collapse inward, leading to a significant amount of dirt or soil falling into the trench. The weight of the falling dirt can exert considerable pressure and pose a serious hazard to workers. The weight of the dirt per cubic foot is approximately 200 lb. This weight can vary depending on the type of soil and its moisture content, but 200 lb per cubic foot is a common estimate. It is important to note that the weight of the soil can increase significantly when it becomes saturated with water, making trench collapses even more dangerous.The weight of the falling dirt is a critical factor in trench safety, as it can contribute to the force exerted on individuals trapped in the trench and make rescue operations challenging. Proper protective measures, such as shoring, sloping, or trench boxes, should be implemented to prevent trench collapses and protect workers from the weight and pressure of falling dirt.

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An agreement between a company and a labor union that represents most of its employees would be most appropriately considered part of a company's: contractual infrastructure.

A worker's guild (English) or trade guild (American English), frequently basically alluded to as an association, is an association of laborers expectation on "keeping up with or working on the states of their employment", for example, accomplishing better wages and advantages, working on working circumstances, further developing security principles, laying out grievance methods, creating rules overseeing status of representatives (rules overseeing advancements, worthwhile motivation conditions for end) and safeguarding and expanding the dealing force of laborers.

Union dues, which are fees that are imposed on a regular basis, are how most trade unions pay for the functions of their head office and legal team. The association delegates in the labor force are normally comprised of working environment volunteers who are frequently selected by individuals through inside equitable races. The rank-and-file members of the trade union negotiate labor contracts (collective bargaining agreements) with employers on their behalf through an elected leadership and bargaining committee.

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The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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Answer:

0.543 kilogram

Explanation:

thats the answer