what is the speed of an electron with a de broglie wavelength of 0.30 nm ?

Answers

Answer 1

The speed of an electron with a de Broglie wavelength of 0.30 nm is 1.21 × 10^6 m/s.

We have de Broglie's formula that can help us to find the speed of an electron. It is given by;λ = h/mv

Where, λ is the wavelength of an electron.

h is the Planck's constant.

m is the mass of an electron.

v is the velocity of an electron.

We can rearrange this formula to get;

v = h/mλ

Now we know that;

λ = 0.30 nm = 0.30 × 10⁻⁹ m

Also, h = 6.626 × 10⁻³⁴ J·s (Planck's constant)

m = 9.11 × 10⁻³¹ kg (mass of an electron)

Substituting these values, we get;

v = h/mλ= (6.626 × 10⁻³⁴)/(9.11 × 10⁻³¹ × 0.30 × 10⁻⁹)

= 1.21 × 10^6 m/s

Therefore, the speed of an electron with a de Broglie wavelength of 0.30 nm is 1.21 × 10^6 m/s.

The speed of an electron with a de Broglie wavelength of 0.30 nm is 1.21 × 10^6 m/s.

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Related Questions

in the compound CaCO3 at the end of the compound represents the number of

Answers

Answer:

Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3).

Solution —

Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g

No. of moles of CaCO3

= No. of molecules/Avogadro constant

= 6.022 × 1023/ 6.022 × 1023

= 1 mole

Mass of CaCO3

= No. of moles × molar mass

= 1 × 100 g = 100 g.

Is it possible for both the pressure and volume of a monatomic ideal gas to change without causing the internal energy of the gas to change?
Explain how this could occur.

Answers

Yes, it is possible for both the pressure and volume of a monatomic ideal gas to change without causing the internal energy of the gas to change. This occurs when the gas undergoes an adiabatic process, meaning there is no heat transfer between the gas and its surroundings.

In an adiabatic process, the change in internal energy (ΔU) is solely dependent on the work done on or by the gas (W). According to the first law of thermodynamics, ΔU = Q + W, where Q is the heat transfer. Since Q = 0 in an adiabatic process, ΔU = W.

For the internal energy of the gas to remain constant (ΔU = 0), the work done on or by the gas must also be zero. This can be achieved through a specific path in the pressure-volume (PV) diagram, where the gas expands and does work on its surroundings, followed by compression, with the surroundings doing an equal amount of work on the gas. The net work done over this process will be zero, ensuring the internal energy remains unchanged.

In summary, it is possible for both the pressure and volume of a monatomic ideal gas to change without affecting its internal energy by undergoing an adiabatic process with zero net work done.

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A test rocket is launched by accelerating it along a 200.0 m, 35 degree incline at 1.25 m/s/s starting

from rest. The instant the rocket leaves the incline, its engines turn off, it is subject only to gravity,

and air resistance can be ignored. Find

a) the maximum height above the ground the rocket reaches

Answers

Answer:

The maximum height above the ground the rocket reaches is 123.1 m.

Explanation:

Let's find the final velocity at a distance of 200 m:

\( v_{f}^{2} = v_{0}^{2} + 2ad \)

Where:

\(v_{f}\) is the final speed =?

v₀ is the initial speed =0

a is the acceleration = 1.25 m/s²

d is the distance = 200 m

\(v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s\)    

Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:

\( v_{fy}^{2} = v_{0y}^{2} - 2gh \)

Where:

\(v_{f}\) = 0

\(h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m\)

Finally, the maximum height above the ground is:

\( h_{max} = h + H \)

Where H is the vertical component of the 200.0 meters.

\(h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m\)

Therefore, the maximum height above the ground the rocket reaches is 123.1 m.

I hope it helps you!                                                          

Exercises
Question-5 (doable)
A magnified, inverted image is located a distance of 38.0 cm from a converging lens with a focal
length of 10.0 cm. Determine the object distance and tell whether the image is real or virtual
[ 13.6 cm )

Answers

\(\\ \rm\Rrightarrow \dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}\)

\(\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{1}{-10}+\dfrac{1}{38}\)

\(\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-19+5}{190}\)

\(\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-14}{190}\)

\(\\ \rm\Rrightarrow u=\dfrac{190}{-14}\)

\(\\ \rm\Rrightarrow u=13.6cm\)

Real

on a hot sumer afternoon, keith and nate are out fishing in their rowboat when they decide to jump into the water and go for a swim. keith, whose mass is 65.0 kg, jumps straight off the front of the boat with a speed of 2.00 m/s relative to the boat, while nate propels his 68.0-kg body simultaneously off the back of the boat at 4.00 m/s relative to the boat. if the 100.-kg boat is initially traveling forward at 3.00 m/s, what is its velocity after both boys jump?

Answers

The velocity of the boat after both boys jump is -6.46 m/s. The velocity is negative, which means the boat is moving backwards after both of the boys jumps.

How are speed and velocity different?

Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion. In other words, speed is a scalar value, but velocity is a vector.

How can we determined this?

We can use the principle of conservation of momentum,

In this case, the closed system is the boat and the two boys. Before they jump, the total momentum of the system is the momentum of the boat (mass * velocity). After they jump, the total momentum of the system is the momentum of the boat plus the momentum of Keith plus the momentum of Nate.

The initial momentum of the boat is 100 kg * 3 m/s = 300 kgm/s

The momentum of Keith as he jumps off the boat is 65 kg * 2 m/s = 130 kgm/s

The momentum of Nate as he jumps off the boat is 68 kg * 4 m/s = 272 kg*m/s

The total momentum of the system before the boys jump is 300 kgm/s

The total momentum of the system after the boys jump is 300 kgm/s + 130 kgm/s + 272 kgm/s = 702 kg*m/s

So, we can set the initial momentum equal to the final momentum:

300 kg*m/s = 100 kg * vf + 130 kg * 2 m/s + 272 kg * 4 m/s

where vf is the final velocity of the boat.

Solving for vf,

vf = (702 kgm/s - 130 kg * 2 m/s - 272 kg * 4 m/s) / 100 kg

vf = (702 - 260 - 1088) kgm/s / 100 kg

vf = -646 kg*m/s / 100 kg

vf = -6.46 m/s

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Convection can occur in which two substances?

wood and air
ice and wood
water and ice
air and water

Answers

After considering all the given options we come to the conclusion that the required answer to the given question is Option D.


Convection is generally known as the property that aids the transfer of thermal energy through the movement of particles from one specified area to another. It typically seen to take place  in fluids .
When we talk about convection, particles that have a lot of heat energy inside a liquid or gas dominate over the particles that have less heat energy by taking their dedicated space. Then , convection can occur in air and water.
some famous examples of convection are:
Boiling water
Land and sea breeze
Air conditioner
Radiator
Refrigerator
Hot air popper
Hot air balloon
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A wood block is placed on a rough surface. The surface starts horizontal, and one end is then raised so that the angle the surface makes with the horizontal gradually increases until, at an angle θ , the block begins to move down the surface, as shown in the figure. From this observation, which of the following can be concluded for angles greater than θ ?


A) there is no frictional force on the block.

B) The gravitational force is equal to the frictional force.

C)The component of the gravitational force along the surface is greater than the frictional force.

D)The normal force is equal to the gravitational force.

E )The component of the normal force along the surface is greater than the gravitational force.

A wood block is placed on a rough surface. The surface starts horizontal, and one end is then raised

Answers

Answer:

The correct option is;

C) The component of the gravitational force along the surface is greater than the friction force.

Explanation:

The force of static friction acts along the plane in opposite direction to the component of the force of the weight acting down (along) the plane.

The magnitude of the frictional force, \(F_{fr}\) is given by the following formula;

\(F_{fr}\) = μ·N = (m·g·cos(θ))·μ

The magnitude of the weight acting along the incline plane = m·g·sin(θ)

As θ increases, sin(θ) increases, and cos(θ) decreases, such that magnitude of the weight acting downwards, along the inclined plane becomes larger than the frictional force acting upwards along the incline plane.

In 1992, Ukrainian Sergei Bubka ued a hort pole to jump to a height of 6.13 m. If the maximum potential energy aociated with Bubka wa 4.80 kJ at the midpoint of hi jump, what wa hi ma?

Answers

At the middle of his jump, Ukrainian Sergei Bubka had a mass of 79.8 kJ.

What is mass's straightforward definition?

The amount of matter in a particle or object is represented by its mass, which is denoted by the symbol m. In the International System (SI), the kilogram serves as the default unit of mass (kg).

The resistance of the body to acceleration (change of velocity) when a net force is applied is known as inertia, and inertia may be measured experimentally using mass.

h=6.13 meters, mg=9.81 m/s2,

PEg= 4.80 ×10^3J

We will use the equation for gravitational potential energy and rearrange it to solve for mass because the mass is unknown.

PEg = mgh as a result.

PEg/gh = mass

mass = 4.80 ×10^3 / 9.81 x 6.13

79.8 kJ / mass.

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A box that weighs 5.00×10^2 N is sliding down a ramp at a constant speed. The angle the ramp makes with the horizontal is 25°. What is the coefficient of friction between the box and the ramp?

Answers

Answer:

0.466 (3 sig. fig.)

Explanation:

Frictional force acting on the box = 5.00×10^2xsin25

Normal force acting on the box = 5.00×10^2xcos25

coefficient of friction = 0.466 (3 sig. fig.)

Pendulum In this task, you’ll make a pendulum and analyze its swing. a hand holding a swinging pendulum shown in three positions Estimated time to complete: 20 minutes You will need these materials: goggles golf ball (or similar size ball) plastic sandwich bag tape hole punch or scissors 1 foot of string metal lid or pan Stay safe! Always wear your safety goggles. Part A Place the ball in the plastic bag, and twist the top so the ball is secure in the bag. Wrap the twisted portion with tape so it stays tight. Use the hole punch or scissors to poke a hole in the part of the bag that’s above the ball. Slip an end of the string through the hole, and tie a knot. This is your pendulum. Hold the loose end of the string still with one hand. With the other hand, raise the ball in an arc so that it’s almost level with the hand holding the string. With the string taut, let the ball go. What do you observe? Font Sizes Characters used: 0 / 15000 Part B Why did the pendulum stop swinging? Where did the energy go? Font Sizes Characters used: 0 / 15000 Part C Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic energy is the energy of motion, and potential energy is stored energy. At the top of its swing, does the pendulum have kinetic or potential energy? Font Sizes Characters used: 0 / 15000 Part D At the bottom of its swing, does the pendulum have kinetic or potential energy? Font Sizes Characters used: 0 / 15000 Part E Think about the process of raising the pendulum to one side and letting it go. For this event, create a list of each form of energy associated with the pendulum as it cycles. Font Sizes Characters used: 0 / 15000 Part F How could you give the pendulum more energy? Font Sizes Characters used: 0 / 15000 Part G Now raise the pendulum and let it hit a metal lid or pan. When the ball strikes the lid, what forms of energy can you identify?

Answers

Answer:

A: Place the ball in the plastic bag, and twist the top so the ball is secure in the bag. Wrap the twisted portion with tape so it stays tight. Use the hole punch or scissors to poke a hole in the part of the bag that’s above the ball. Slip an end of the string through the hole, and tie a knot. This is your pendulum. Hold the loose end of the string still with one hand. With the other hand, raise the ball in an arc so that it’s almost level with the hand holding the string. With the string taut, let the ball go. What do you observe?

Mine was swaying perfectly fine. after a little bit it gradually started swinging slower until stopped.

B: Why did the pendulum stop swinging? Where did the energy go?

gravity was pulling it towards the ground, however the weight and momentum of the ball helped it keep swinging for a good while.

C: Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic [THE ENERGY OF MOTION IN A BODY] energy is the energy of motion, and potential energy [THE STORED ENERGY IN AN OBJECT] is stored energy. At the top of its swing, does the pendulum have kinetic or potential energy?

when its at the very top of the swing it does have a very small amount of time until it starts going back down again but during that time it is potential energy

D: At the bottom of its swing, does the pendulum have kinetic or potential energy?

the pendulum still has kinetic energy when it is the closest to the ground since it is still swinging

E: Think about the process of raising the pendulum to one side and letting it go. For this event, create a list of each form of energy associated with the pendulum as it cycles.

when its in my hand: potential energy

when it starts swinging: kinetic energy

when its going upwards: kinetic energy

when it stops swinging: potential energy

F: How could you give the pendulum more energy?

one way you could possibly make it have more energy is if you make the string longer

G: Now raise the pendulum and let it hit a metal lid or pan. When the ball strikes the lid, what forms of energy can you identify?

I could hear sound energy when the two made contact but for the most part it was kinetic energy

Answer:

I could hear sound energy when the two made contact but for the most part it was kinetic energy

Explanation:

"You have discovered a new planet! When you visit this planet,
you measure a mountain (density 3.2 g/cm^3) sticking up 4400 meters
above the exposed mantle (density of 4.1 g/cm^3). Assuming that this"

Answers

Answer:

3433.4m

Explanation:

Volume_submerged = (Density_mantle / Density_mountain) * Volume_exposed

Volume_submerged_meters = Volume_submerged / 1000000

Weight_submerged = Density_mantle * Volume_submerged_meters * g

Weight_submerged = Weight_exposed

Density_mantle * Volume_submerged_meters * g = Density_mountain * Volume_exposed * g

Volume_submerged_meters = (Density_mountain / Density_mantle) * Volume_exposed

Volume_submerged_meters = (3.2 g/cm^3 / 4.1 g/cm^3) * 4400 meters

Volume_submerged_meters = (0.7805) * 4400 meters

Therefore, the total height of the mountain is 3433.4 meters.

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All traditional oriental medicine recognizes that an energy force called _____ flows through the body.

Answers

All traditional oriental medicine recognizes that an energy force called Qi flows through the body.

Traditional Chinese medicine is predicated on the idea that qi, or the body's life force, travels along meridian channels and maintains equilibrium in a person's physical, mental, emotional, and spiritual well-being. The Feldenkrais technique is a type of somatic education that combines focused attention and gentle movement to improve human function and mobility. You can broaden your range of motion, boost your comfort level, and enhance your flexibility and coordination by using this method. This could involve your food, your workout routine, psychotherapy, relationship counseling, and more. therapies that are complementary or alternative, including acupuncture, chiropractic adjustments, homeopathy, massage, naturopathy, and others.

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even with infinitely powerful telescopes, we can look back in time only until:

Answers

Even with infinitely powerful telescopes, we can look back in time only until the Cosmic Microwave Background (CMB), around 380,000 years after the Big Bang.

The Cosmic Microwave Background is the earliest observable stage of the universe's history. Before the CMB, the universe was in a hot, dense state known as the "opaque plasma" where photons were constantly scattered by charged particles, making it impossible to see through.

Approximately 380,000 years after the Big Bang, the universe cooled down enough for atoms to form, allowing photons to travel freely. This event is called "recombination," and the released photons created the CMB. Even with infinitely powerful telescopes, we cannot observe anything prior to the CMB because light did not travel freely in the opaque plasma.

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An electromagnetic wave with a wave length about the same as the diameter of an apple would be?
1. x-ray.
2. UV.
3. infrared.
4. microwave.
5. radio wave.

Answers

An electromagnetic wave with a wavelength about the same as the diameter of an apple would be infrared radiation.

What is a wave?

The term "wave" refers to a disturbance or oscillation that travels through a medium or space, carrying energy from one place to another. In the case of an electromagnetic wave, this oscillation is created by the interaction of electric and magnetic fields, and the wave carries energy in the form of photons. The wavelength of an electromagnetic wave is the distance between two consecutive peaks or troughs of the oscillation. Shorter wavelengths correspond to higher energy photons, while longer wavelengths correspond to lower energy photons.

Wave with a wavelength the same as the diameter of an apple:

In the case of an electromagnetic wave with a wavelength about the same as the diameter of an apple, the most likely option would be infrared radiation. This is because infrared radiation has wavelengths ranging from about 700 nanometers to 1 millimeter, which overlaps with the size of an apple (which is around 8-10 centimeters in diameter). Infrared radiation has lower energy than x-rays or UV radiation, but higher energy than microwave or radio waves.

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which particles most likely will be dispositive first as a velocity of a stream carrying a mixture of particles decreases

Answers

As the velocity of a stream carrying a mixture of particles decreases, the heaviest particles will most likely be deposited first. This phenomenon is known as sedimentation.

The process of sedimentation separates particles of different sizes and densities from a mixture by allowing them to settle at different rates due to gravity. The heavier particles settle faster than lighter ones. Therefore, they are the first to be deposited.Sedimentation can occur naturally or artificially. For example, in a river, sedimentation can occur naturally due to changes in water flow and velocity. Artificial sedimentation can be used in water treatment plants to remove impurities from water

The heaviest particles will most likely be deposited first as the velocity of a stream carrying a mixture of particles decreases.Explanation: This is due to the process of sedimentation, which separates particles of different sizes and densities from a mixture by allowing them to settle at different rates due to gravity. The heavier particles settle faster than lighter ones, and hence they are the first to be deposited.

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When there are two light sources then there will be two shadows. Given below is a case where there are two light sources but one of the light sources is brighter than the other. Can you tell which shadow will be darker? Give explanation.

Answers

neither, a shadow cant be darker unless your closer to the surface your pointing the light at.

research in wind energy systems is conducted at its primary facility in colorado by the _____.

Answers

Research in wind energy systems is conducted at its primary facility in Colorado by the National Renewable Energy Laboratory (NREL).

Research in wind energy systems is conducted at its primary facility in Colorado by the National Renewable Energy Laboratory (NREL). NREL is a federally funded research and development center dedicated to advancing renewable energy technologies, including wind energy. It is operated by the Alliance for Sustainable Energy, LLC, on behalf of the U.S. Department of Energy. NREL's facility in Colorado, known as the National Wind Technology Center (NWTC), provides a comprehensive testing and research environment for wind turbines and related technologies, aiming to improve their performance, reliability, and integration into the electric grid.

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Which is NOT something that might make Jovian planets warm, so they give off more energy than they receive from the Sun?

Some Jovian planets may be slightly shrinking

They have nuclear fusion like the Sun does

It is thought some Jovian planets may still have heat left over from their formation

Some Jovian planets may have helium rain, the droplets releasing energy as they fall

Answers

The option that is NOT something that might make Jovian planets warm, so they give off more energy than they receive from the Sun is:

- They have nuclear fusion like the Sun does

Jovian planets, also known as gas giants, do not possess the conditions required for nuclear fusion to occur. Unlike stars like the Sun, which generate energy through the fusion of hydrogen atoms, Jovian planets do not have sufficient mass or temperature to sustain nuclear fusion reactions. Therefore, this option is not applicable to the warming and energy emission processes of Jovian planets.

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hen approaching a curve, it is best to: A. Search for possible collision traps and escape paths B. Stay close to the centerline if there is oncoming traffic C. Squeeze the clutch lever to slow down D. Shift to a higher gear

Answers

Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.

What is Clutch?

This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.

Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.

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Q20 Using the equation for Newton’s 2nd Law for uniform circular motion and the parameters currently set in your interactive, calculate the magnitude of the force acting on the object to keep it in circular motion.

Values are:

Vo= 0 m/s

g = 9.8 m/s m = 5 kg angle = 20 degrees Us = 0.26 Uk = 0.15

Answers

To calculate the magnitude of the force acting on the object to keep it in circular motion, we can use the equation for Newton's 2nd Law of motion for uniform circular motion, which states that the net force acting on an object moving in a circular path of radius r with a constant speed v is given by:

Fnet = mv²/r

where m is the mass of the object and v is its speed or velocity. Here, we have the following values:

Vo = 0 m/s (initial velocity)

g = 9.8 m/s² (acceleration due to gravity)

m = 5 kg (mass of the object)

angle = 20 degrees (inclination angle)

Us = 0.26 (coefficient of static friction)

Uk = 0.15 (coefficient of kinetic friction)

However, we don't have the radius of the circular path, which is required to calculate the net force using the above formula. So, we cannot determine the magnitude of the force acting on the object to keep it in circular motion.

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Write two daily life examples for each of the following:
- Specular Reflection - Diffuse Reflection

Answers

Answer:

Hey there here is your ans

Explanation:

Specular Reflection- bathroom mirror , glare on a pair of eyeglasses

Diffuse Reflection- reflection are the reading of a notebook

Tq

Specular reflection: glare on a pair of eyeglasses, bathroom mirror.

Diffuse reflection involves reading a notepad.

What is reflection?

The direction in which a wavefront travels at an interface between two distinct media changes during the process of reflection. This allows the wavefront to go back into the medium in which it was first generated. Light, music, and water waves are all examples of common phenomena that may be reflected.

The following is a list of the three most common forms of reflection:

Regular Reflection.Reflection that is DiffusedMultiple Reflection

Glare on a pair of eyeglasses or the mirror in the bathroom is an example of specular reflection. Reading from a notebook is an example of diffuse reflection.

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Un prisma rectangular con un volumen de 80 m^3 se sumerge hasta la mitad en agua, calcular la fuerza de empuje que recibe.(rho_(del agua)=1000 kg/m^3)

Answers

Answer:

400 kN

Explanation:

El principio de Arquímedes establece que, cuando un cuerpo está total o parcialmente sumergido en un fluido, experimenta un empuje hacia arriba que es igual al peso del fluido desplazado.

Dado que;

Volumen del bloque = 80m ^ 3

Densidad del agua = 1000 kg / m ^ 3

Empuje hacia arriba = 1/2 * 80 * 1000 * 10

Empuje hacia arriba = 400 kN

Help
A. 12,240
B. 6,120

HelpA. 12,240B. 6,120

Answers

Answer:

A. 12,240.

Explanation:

1,530 times 8.0 = 12,240.

hope this helped :)

explain in your own word, what would happen to the size of the wildflower population if
all of the badgers in the environment were eliminated? Why

Answers

Answer:

okay here's how

Explanation:

so if the badgers eat the wildflowers, they are keeping them producing at a considerablly contact rate, but if all of the badgers were eliminated there would be nothing to controll the wild flowers, so there would be a huge wild flower boom (huge increase of flowers/ wild flower population, that would probably eventually over run the space that they are in)

Which refers to the ends of a magnet where the forces are strongest?
A) attracting forces
B) opposing forces
C) magnetic fields
D) magnetic poles

Answers

A material that produces magnetic field are called magnets. Magnetic poles refers to the ends of a magnet where the forces are strongest.

What are magnetic poles?

Magnetic poles are the regions at each end of a magnet where the external magnetic field is strongest.

A bar magnet suspended in the Earth's magnetic field orients itself north-south. A north magnetic pole is the north-seeking pole of such a magnet or any similar pole.

Thus, the correct option is D.

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Answer:

D magnetic poles-

Explanation:took test

A rock is dropped from a height of 3.4 m. How much time does it take to hit
the ground?
O .83 s
O 1.17 s
O 0.59 s
O 33.32 s

Answers

Answer: 33.32 s

Explanation: gravity =9.8m/s2 which means that 3.4mx9.8m/s2=33.32s

I hope this helped ! Sorry if it’s wrong :)

Based on the Previous two questions: According to Newton's Second Law, how much force does Marisa need to apply in order to stop the sled?

a
0.048 kg m/s
b
-0.075 N
c
2.50 N
d
-0.048 N

Answers

Answer:

See explanation

Explanation:

The question is incomplete, as the required parameters are missing. The general solution to this is as follows;

First, get the mass (m) and the acceleration (a) of the sled

So, the force (f) to stop the sled is:

\(f = ma\) ---- Newton 2nd law

However, the force to stop the sled will be in the opposite direction of the sled.

So:

\(f =-ma\)

Assume that:

\(m \to 5kg\)

\(a \to 6m/s^2\)

The required force is:

\(f =-ma\)

\(f =-5kg * 6m/s^2\)

\(f = -30N\)

which phase of the ism is most opaque to visible light?

Answers

The most opaque phase of matter to visible light is the solid phase.

In solids, the atoms or molecules are closely packed and have strong interactions with each other. As a result, visible light has difficulty passing through the solid material, leading to high levels of opacity. The orderly arrangement of particles in a solid causes the light to scatter and be absorbed or reflected, preventing it from transmitting through the material with ease.

Materials such as metals, wood, rocks, and opaque plastics are examples of solid substances that exhibit high opacity to visible light. The dense and tightly bonded nature of solid structures contributes to their ability to block or absorb light, making them appear opaque or non-translucent.

In contrast, gases and liquids are generally more transparent to visible light compared to solids. The molecules or atoms in gases and liquids are more dispersed and have weaker interactions, allowing light to pass through with less obstruction and resulting in lower opacity.

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Which statement is best supported by the table?
Wave Wand Y are light waves.
Wave X is a sound wave.
Wave W is a light wave.
Waves X and Y are sound waves.
Waves Y is a sound wave.
Waves X and W are light waves.
o Wave W is a sound wave.
Waves X and Y are light waves.

Which statement is best supported by the table?Wave Wand Y are light waves.Wave X is a sound wave.Wave

Answers

Answer:

wave w is a sound wave

wave x and y are light waves

Answer:

D

Explanation:

a motor bout is heading due north and crosses a wide with a speed of 4m/s relative to the water the water in the river has a una form speed of 3.00 mis due east relative to the earth Determine the disceton of the motion of the motorbeet relection to earth

Answers

To determine the direction of the motion of the motorboat relative to the
Earth, we need to consider the vector addition of the boat's velocity relative to the water and the water's velocity relative to the Earth.|

The motorboat has a velocity of 4 m/s due north relative to the water. The water in the river has a velocity of 3.00 m/s due east relative to the Earth.
To find the resultant velocity of the motorboat relative to the Earth, we can use vector addition. We can treat the velocities as vectors and add them together:
Resultant velocity = Velocity of motorboat relative to water + Velocity of water relative to Earth
Since the velocities are at right angles to each other, we can use the Pythagorean theorem to find the magnitude of the resultant velocity:
Resultant velocity = √((4 m/s)^2 + (3.00 m/s)^2) ≈ 5.00 m/s
The direction of the resultant velocity can be determined using trigonometry. The angle θ can be calculated as:
θ = arctan((Velocity of water relative to Earth) / (Velocity of motorboat relative to water))
θ = arctan(3.00 m/s / 4 m/s) ≈ 36.87 degrees
Therefore, the motion of the motorboat relative to the Earth is approximately 5.00 m/s at an angle of 36.87 degrees north of east.

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