What is the speed of a wave that has a frequency of 125 hz and a wavelength of 1. 25 meters? express your answer to the nearest whole number.

Answers

Answer 1

The speed of the wave with a frequency of 125 Hz and a wavelength of 1.25 meters is 156 m/s approximately.

To determine the speed of a wave that has a frequency of 125 Hz and a wavelength of 1.25 meters, we use the formula:

v = fλ

where:v is the velocity (speed) of the wave,f is the frequency of the wave, and λ is the wavelength of the wave.

We can now substitute the given values into the formula:

v = fλ

v = (125 Hz)(1.25 m)

v = 156.25 m/s

Thus, the speed of the wave is approximately 156 m/s when it has a frequency of 125 Hz and a wavelength of 1.25 meters. To sum up, when a wave has a frequency of 125 Hz and a wavelength of 1.25 meters, it has a speed of approximately 156 m/s.

Therefore, the speed of the wave with a frequency of 125 Hz and a wavelength of 1.25 meters is 156 m/s approximately.

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Related Questions

Predict the product, if any, of reaction between methyl propanoate and aniline.

Answers

The product of the reaction between methyl propanoate and aniline is N-methylphenylpropanamide.

The reaction between methyl propanoate and aniline is a nucleophilic substitution reaction. Aniline is a nucleophile, which attacks the carbonyl group in methyl propanoate. The carbonyl group undergoes nucleophilic addition and an intermediate is formed. The intermediate is an imine. The imine is unstable and gets hydrolyzed immediately.

The hydrolysis of the imine intermediate gives N-methylphenylpropanamide. The hydrolysis of the imine is the addition of water to the imine. It is catalyzed by an acid or a base.

N-methylphenylpropanamide is the product formed as a result of the reaction between methyl propanoate and aniline.

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can anyone help me with this please​

can anyone help me with this please

Answers

Answer:

1270 J

Explanation:

Recall that the mechanical energy of a system is the addition of the Potential energy and the Kinetic energy at any given time.

As the skier descends, potential energy is converted into kinetic energy, but the total mechanical energy should remain the same.

We see that it is not the case, so that difference is what has gone into thermal energy;  19500 J - 18230 J = 1270 J

A 10.0 kg rock is at the top of a 20.0 m. tall hill. How much potential energy does it have?

Answers

Answer:

2000 J

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 10 × 10 × 20 = 2000

We have the final answer as

2000 J

Hope this helps you

Answer:

\(\boxed {\boxed {\sf 1,960 \ J}}\)

Explanation:

Potential energy is the energy an object possesses due to its position. It is calculated using the following formula:

\(PE= mgh\)

The mass (m) of the rock is 10.0 kilograms. The rock is on top of a hill that is 20.0 meters tall (h). Assuming this situation is occurring on Earth, the acceleration due to gravity is 9.8 meters per second squared (g).

m= 10.0 kg g= 9.8 m/s²h= 20.0 m  

Substitute the values into the formula.

\(PE= (10.0 \ kg)(9.8 \ m/s^2)(20.0 \ m)\)

Multiply the first two values together.

\(PE=(98 \ kg*m/s^2)(20.0 \ m)\)

Multiply again.

\(PE= 1960 \ kg*m^2/s^2\)

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 1960 kg*m²/s² is equal to 1960 J.

\(PE= 1960 \ J\)

The rock has 1,960 Joules of potential energy.

Convert 800 cm to meters.

Answers

Answer:8 meters

Explanation:100cm is a meter

Answer:

8 meters

Explanation:

800 cm * 0.01 m/1 cm = 8.0 m


HELP ME PLEASE *50 points*
Use the diagram on the answer document to answer the following:
A. How much force is necessary to start the object moving?
B. How much force is necessary to keep this object moving?
C. If it starts at rest, will the object start to slide?
D. Depending on "C" either find the acceleration of the object or the additional force
necessary to move it.

Answers

their is no document for us to look at , can you add it so i can help you

660 newtons

830 newtons

no

additional force would be 350 newtons

What is exothermic .Is it a reaction?

Answers

Answer:(of a reaction or process) accompanied by the release of heat.

Explanation: trust moi

Exothermic is a reaction, it is a process that objects or substances go through when releasing heat.

Please I need help its timed-
Students in a science class observed that when a strip of magnesium (Mg) metal was placed in a test tube containing hydrochloric acid (HCl), the magnesium began to bubble as hydrogen gas and magnesium chloride are formed. Which of the following choices show both the correctly balanced equation and identify the type of reaction?


A.

Mg + 2HCl →2H2 + MgCl2 (single replacement)


B.

Mg + 2HCl →H2 + MgCl2 (single replacement)


C.

Mg + 2HCl →H2 + MgCl2 (synthesis)


D.

2Mg + HCl →H2 + 2MgCl2 (synthesis)

Answers

Answer:

c

Explanation:

Question 4 (2 points)
Your friend just challenged you to a race. You know in order to beat him, you must run 50 meters within 60 seconds in an eastern direction.
What does your average velocity need to be to win the race? (2 points)
5 meters per second, east
Оа
Ob
.83 meters per second, east
Ос
1.2 meters per second, east
Od
3000 meters per second, east

Answers

Answer:

0.83m/s,east

Explanation:

velocity=d/t

v=50/60

v=0.83m/s,east

A 3.0- resistor is connected in parallel with a 6.0- resistor. This combination is connected in series with a 4.0- resistor. The resistors are connected to a 12-volt battery. How much power is dissipated in the 3.0- resistor

Answers

Answer:

5.33 w

Explanation:

parallel resistors equivalent r  =  r1 r2 /(r1+r2) = 2 ohm

in series with 4 ohm resistor makes total r = 6 ohms

    12 v / 6 ohm = 2 amps current

2/3 of the current will go through the 3 resistor

   2/3 * 2 = 4/3 amp

power = I^2 R =  4/3 ^2 * 3 = 5.33 watts

What is the range of motion for wrist flexion in degrees?

Answers

The range of motion for wrist flexion can vary depending on the individual and their flexibility. On average, the normal range of motion for wrist flexion is about 80 to 90 degrees. This means that when you flex your wrist, you can bring your hand closer to the inside of your forearm by about 80 to 90 degrees.

To better understand this, you can perform a simple experiment. Start by placing your arm on a table with your palm facing down. Then, bend your wrist upward as much as you can, trying to bring your palm closer to your forearm. The angle formed between your forearm and your hand is the range of motion for wrist flexion.
It's important to note that some individuals may have a larger or smaller range of motion due to factors such as flexibility, joint health, and previous injuries. Additionally, different activities and sports may require greater or more specific ranges of motion for wrist flexion.
Overall, the range of motion for wrist flexion is the degree to which you can bend your wrist upward towards your forearm, typically ranging from 80 to 90 degrees.

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Please Hurry will mark Brainliest

which equation can be used to calculate the normal force of an object if you know the speed of the object the coefficient of kinetic friction and the force of kinetic friction

Answers

The equation that can be used to calculate the normal force of an object if you know the speed of the object, the coefficient of kinetic friction, and the force of kinetic friction is given by:

N = mg - f_k

where N is the normal force, m is the mass of the object, g is the acceleration due to gravity, and f_k is the force of kinetic friction.

The normal force is the force that acts perpendicularly to the surface of the object. It is a contact force. The force acting on an object is perpendicular to the surface that the object is resting upon.

For example, when an object rests on a surface, the normal force acting on it will be the same as the weight of the object.

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A massless rod is attached to the ceiling by a string. Two weights are hung from the rod: a 0.4-lb weight at its left end and a 1.2-lb weight at its right end. The length of the rod is L and a string is attached (3L/4 from its left end) so that the rod (with attached weights) is horizontal. What is the tension in the string supporting the rod and the attached weights

Answers

The tension in the string supporting the rod and the attached weights is 7.11 N.

Tension in the string supporting the rod

The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.

T = (m1 + m2)g

where;

m1 and m2 are the two masses supported

0.4lb + 1.2lb = 1.6lb = 0.725 kg

T = 0.725 x 9.8

T = 7.11 N

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As a pendulum moves toward the equilibrium position, velocity and acceleration . As the pendulum moves away from the equilibrium position, velocity and acceleration . Velocity is at a when acceleration is zero.

Answers

Answer:

As a pendulum moves toward the equilibrium position, velocity increases and acceleration decreases. As the pendulum moves away from the equilibrium position, velocity decreases and acceleration increases.

Explanation:

Using the law of conservation of energy, we know that Em1=Em2.

Em1 (at the highest point) = Eg + Ek, where Ek is 0

Em2 (at the equilibrium point) = Eg +Ek, where Eg is 0

This makes sense. At the highest point, the pendulum is at its maximum height. At this point, however, it stops moving, so its velocity is 0. At the equilibrium point, the pendulum is at its lowest height (i.e. h=0). At this point, however, its moving at its maximum velocity. This velocity is constant, which means that acceleration is 0.

Answer:

1) Increases

2) Decreases

3) Decreases

4) Increases

5) Maximum

Explanation:

As a pendulum moves toward the equilibrium position, velocity

✔ increases

and acceleration

✔ decreases

. As the pendulum moves away from the equilibrium position, velocity

✔ decreases

and acceleration

✔ increases

. Velocity is at a

✔ maximum

when acceleration is zero.

Lúc 6 giờ sáng một học sinh đi học từ nhà đến trường mất 10 phút quãng đường từ nhà đến trường là 6 km hỏi học sinh đi với vận tốc là bao nhiêu

Answers

Lúc 6 giờ sáng một học sinh đi học từ nhà đến trường mất 10 phút quãng đường từ nhà đến trường là 6 km hỏi học sinh đi với vận tốc là bao nhiêu

In a closed system that has 45 J of mechanical energy, the gravitational
potential energy of a ball rolling down an inclined plane decreases from 8 J to
5 J. How does the system's kinetic energy change if there is no friction??
O A. It increases from 45 J to 50 J.
B. It decreases from 40 J to 37 J.
O C. It decreases from 48 J to 43 J.
D. It increases from 37 J to 40 J.​

Answers

Answer: The answer is D

Explanation: When potential energy decreases kinetic energy increases

Answer: The answer is D

Explanation: When potential energy decreases kinetic energy increases

Imagine that you are able to take a photograph of a rolling ball which is slowing down. What pattern would you expect to see? Make a sketch to show your idea.​

Answers

Wehn we take a photograph of rolling ball which is slowing down we can understand the point of application of the different forces which take place.

What will be noticed in the picture?

During the ball's ruling, the force of friction acts in a backward direction. This produces a torque that causes the ball to rotate. The force of gravity is one of the additional forces.

We can determine the ball's axis of rotation by watching how it moves. The diagram below shows the various forces that are at work on the ball. The ball can roll without slipping at the final stage.

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Imagine that you are able to take a photograph of a rolling ball which is slowing down. What pattern

The components of a 10.8-meters-per-second velocity at an angle of 34.° above the horizontal are

9.0 m/s vertical and 6.0 m/s horizontal

13 m/s vertical and 7.5 m/s horizontal

7.5 m/s vertical and 13 m/s horizontal

6.0 m/s vertical and 9.0 m/s horizontal

Answers

Answer:

6.0 m/s vertical and 9.0 m/s horizontal

Explanation:

For the vertical component, we use the formula:

Sin(34°) = y / 10.8

Then we solve for y:

0.559 = y / 10.8y = 6.0

And for the horizontal component, we use the formula:

Cos(34°) = x / 10.8

Then we solve for x:

0.829 = x / 10.8y = 9.0

So the answer is " 6.0 m/s vertical and 9.0 m/s horizontal".

The breaking distance of a car is directly proportional to
its speed squared. A car takes 32m to stop when travelling at
12m/s. Calculate the breaking distance when travelling at
18m/s

Answers

Answer:

72 meters

Explanation:

Breaking distance is directly proportional to the speed squared.

d = k v²

When v = 12 m/s, d = 32 m.

32 = k (12)²

k = 2/9

d = 2/9 v²

When v = 18 m/s:

d = 2/9 (18)²

d = 72

The data table shows the world population every five years between 2000 and 2015. Based on these data, what happened to the world population during this time frame?

Answers

The populaton of the world increase at a higher rate due to more children were born as compared to death ratio.

What happened to the world population during this time frame?

The world population during this time frame, the world population increase at a higher rate because of unawareness and lack of education. People produce more children without knowing their impact on the environment and earth system.

So we can conclude that the populaton of the world increase at a higher rate due to more children were born as compared to death ratio.

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Answer:

The population got a bit older

Explanation:

Assuming your question is the same as mine, that's the answer I got. This would've been way easier to answer if you at least included answer choices.

10- The voltage across the generator of
the circuit of figure 13 is 12V and
the voltmeter V2 indicates 8V:
А
ס
N.
V
L1
L2
B
L
Fig.13
a- What would the voltmeter V3 indicate?
Justify the answer
b- What would the voltmeter Vi indicate?
Justify the answer

Answers

hey! i just wanted to ask if you found the answer because i’m looking for it

the question below is my question

the question below is my question

Answers

Answer:

Explanation:

0.1

Bobo the clown carries two red balloons that rub against a circus elephant, causing thr baloons to seperate. Each balloon aquires 1.2x10^-7 of charge. How large is the electric orce between them when the balloons are seperated by a distance of 0.5m

Answers

The electric force between the two balloons is approximately 1.04 x \(10^{-12}\) N.

Coulomb's Law:

The electric force between two charged objects can be calculated using Coulomb's Law, which states that the magnitude of the electric force F between two charged objects is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:

F = k * (q1 * q2) / r²

where k is the Coulomb constant, which has a value of approximately 9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\).

In this case, each balloon acquires a charge of 1.2 x \(10^{-7}\) C, so the total charge on both balloons is 2 * 1.2 x \(10^{-7}\)C = 2.4 x \(10^{-7}\)C. The distance between the balloons is 0.5 m.

Plugging in these values into Coulomb's Law, we get:

F = (9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\)) * [(1.2)²x (\(10^{-7}\) C)²/ (0.5m)²]

Simplifying this expression gives:

F = 1.0368 x \(10^{-12}\) N

Therefore, the electric force between the two balloons is approximately 1.04 x\(10^{-12}\)    N.

What is magnitude?

Magnitude refers to the size or extent of something, usually measured in numerical or quantitative terms. It can refer to a physical quantity, such as length, mass, or volume, or it can refer to other measurable attributes, such as brightness, intensity, or force. In general, magnitude is a relative measure, meaning that it is typically expressed as a comparison between two or more things.

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two buses are moving in the opposite directories with the velocities 36km/hr and 108km/hr .find the distance between them in 20 minutes. ​

Answers

The distance between the two buses is 48km.

Let us assume that the velocity of the first bus is 36 km/h and that of the second bus is 108 km/h.

To find the distance between them, we will consider that both buses move in opposite directions.

Distance travelled by bus 1 in 20 minutes = 36 km/h × 20 min ÷ 60 min/h = 12 km

Distance travelled by bus 2 in 20 minutes = 108 km/h × 20 min ÷ 60 min/h = 36 km

Total distance between them = distance travelled by bus 1 + distance travelled by bus 2= 12 km + 36 km= 48 km

Therefore, the distance between them in 20 minutes is 48 km.

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If the output force is greater than the input force for a simple machine, the mechanical advantage is greater than one.

Answers

Yes, if the output force is greater than the input force for a simple machine, the mechanical advantage is greater than one.


Mechanical advantage is a measure of how much a machine multiplies force or changes the direction of force. It is calculated by dividing the output force by the input force. If the output force is greater than the input force, the mechanical advantage will be greater than one.


If the output force is greater than the input force for a simple machine, it means that the machine is able to multiply the force applied to it. This is reflected in the mechanical advantage, which is a ratio of the output force to the input force. A mechanical advantage greater than one indicates that the machine is able to amplify the force.

For example, if the input force is 10 N and the output force is 30 N, the mechanical advantage would be 3 (30 N / 10 N), indicating that the machine is able to multiply the force by a factor of 3.

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explain how it is possible for a colliding proton and antiproton to produce a particle with six times the mass of either.

Answers

The production of a particle with six times the mass of a colliding proton and antiproton is possible due to mass-energy equivalence and conservation of energy and momentum.

According to Einstein's theory of relativity, mass and energy are interchangeable, as expressed by the equation E = mc², where E is energy, m is mass, and c is the speed of light. In particle collisions, energy can be converted into mass, allowing for the creation of particles with higher masses than the colliding particles themselves.

When a proton and an antiproton collide, their kinetic energy is converted into mass, resulting in the formation of new particles. In this scenario, the total energy before the collision is equivalent to the total energy after the collision, preserving the principle of energy conservation.

During the collision, the combined momentum of the proton and antiproton is also conserved. The resulting particles may have higher masses because the excess energy from the collision is transformed into the additional mass of the new particle.

Therefore, by harnessing the energy-mass equivalence and ensuring the conservation of energy and momentum, it is possible for a colliding proton and antiproton to produce a particle with a mass six times greater than either of the initial particles.

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If the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27o, find the refractive index of the material

Answers

The refractive index of the material is 0.

When the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27°, the refractive index of the material can be determined. The formula for Snell’s law is used to calculate refractive index. It states that: `sin i / sin r = n where i is the angle of incidence, r is the angle of refraction and n is the refractive index`.Snell’s law can be re-arranged to make n the subject of the formula to be: `n = sin i / sin r`Hence, we can calculate the refractive index as follows:

For the incident ray, i = 360° and the angle of refraction within the material, r = 27°.n = sin i / sin r= sin 360°/ sin 27°= 0/1 (since sin 360° = 0)= 0Therefore, the refractive index of the material is 0. T

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7. The Voyager 1 space probe was launched in the 1970's and is now the furthest
man-made object from earth - it has actually left the solar system. At its current speed it
could travel across the US, a distance of about 4500 km in 265 seconds (a little less
than 5 minutes!) What is its average speed in kilometers per second?

PLEASE HELP I NEED THE FORMULA AND ANSWER THANK YOU!!

Answers

Answer:

v = 16.98 km/s

Explanation:

Given that,

Distance, d = 4500 km

Time, t = 265 s

We need to find its average speed. The total distance covered divided by total time taken is called average speed of an object. So,

\(v=\dfrac{4500\ km}{265\ s}\\\\=16.98\ km/s\)

So, the average speed is 16.98 km/s.

Use coefficients to balance the following equation: (if no coefficient is needed, use "1", do not leave
any box blank!)

Use coefficients to balance the following equation: (if no coefficient is needed, use "1", do not leaveany

Answers

Answer:

P₄ + 3O₂ → 2P₂O₃

Explanation:

To balance an equation we take each element one by one on each side and balance their atoms.

Like P₄ (Tetraphosphorus) in the left side has 4 atoms of phosphorus.

While on the right side P₂O₃ (Diphosphorus Trioxide) has 2 Phosphorus atoms.

So place 2 as a coefficient in front of P₂O₃.

Now Phosphorus atoms (4 atoms) are balanced on each side.

Now number of Oxygen atoms in P₂O₃ = 2 × 3 = 6

On the left left side number of Oxygen atoms in O₂ = 2

To balance Oxygen atoms in each side, place 3 as a coefficient before O₂ on the left.

Therefore, balance equation will be,

P₄ + 3O₂ → 2P₂O₃

a student designs a clock using a mass and a spring. each oscillation of the mass advances the clock by one second. when the student builds the clock, he discovers he erred and each oscillation takes two seconds. what change can he make to fix the clock?

Answers

The student can fix the clock by increasing the spring constant by a factor of 4. This can be done by either increasing the stiffness of the spring or by adding more springs in parallel.

The spring constant (k) is a measure of the stiffness of a spring. It represents the amount of force required to stretch or compress a spring by a certain distance. The spring constant is defined as the ratio of the force applied to the displacement produced, and its unit is newtons per meter (N/m).

The spring constant is an important parameter in many physics applications, such as Hooke's law, which states that the force applied to a spring is directly proportional to the displacement of the spring. The spring constant can also be used to determine the potential energy stored in the spring when it is compressed or stretched. the spring constant is a fundamental concept in the study of mechanics and is used to describe the behavior of various mechanical systems that involve springs, such as in oscillators and in simple harmonic motion.

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A 45 kg mass is dragged 50 m over a surface. If 1.0 kW of power is produced over 10 seconds,
what is the coefficient of friction for the surface?

Answers

Answer:

Approximately \(0.45\) (assuming that the surface is level, the mass is moving at constant velocity, and that \(g = 9.81\; {\rm m\cdot s^{-2}}\).)

Explanation:

With a power of \(P = 1.0\; {\rm kW} = 1.0\times 10^{3} \; {\rm W}\), the work that would be done over \(t = 10\; {\rm s}\) would be:

\(\begin{aligned}(\text{work}) &= (\text{power})\, (\text{time}) \\ &= (1.0\times 10^{3}\; {\rm W})\, (10\; {\rm s}) \\ &= 1.0 \times 10^{4}\; {\rm J}\end{aligned}\).

Divide work by distance to find the force that did the work:

\(\begin{aligned} (\text{force}) &= \frac{(\text{work})}{(\text{distance})} \\ &= \frac{1.0\times 10^{4}\; {\rm J}}{50\; {\rm m}} \\ &= 200\; {\rm N}\end{aligned}\).

If this mass is moving at a constant velocity, the magnitude of friction on this mass will be equal to that of the external force, \(200\; {\rm N}\).

If the surface is level, the magnitude of the normal force on this mass will be equal to that of weight:

\(\begin{aligned}(\text{weight}) &= (\text{mass})\, g \\ &= (45\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-2}}) \\ &\approx 4.41 \times 10^{3}\; {\rm N}\end{aligned}\).

Divide the magnitude of friction by normal force to find the coefficient of friction:

\(\begin{aligned}& (\text{coefficient of friction}) \\ =\; & \frac{(\text{friction})}{(\text{normal force})} \\ \approx\; & \frac{200\; {\rm N}}{(45\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}))} \\ \approx \; & 0.45\end{aligned}\).

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