Answer:
The slope is 1.
You can also graph these points and connect them to find out that they increase by 1 unit per each x.
Step-by-step explanation:
The slope formula is y2 - y1 divided by x2 - x1
So you can plug in the values
-13 - (-10) / 3 - 6
-13 + 10 / -3
-3 / -3
= 1
Answer:
slope = change in y/change in X
y2 - y1 / X2 - x1
where y2 = -13 and y1 = -10
where X2 = 3 and x1 = 6
from the formula of slope
y2 - y1 / X2 - x1
-13 - -10/ 3 - 6
-3/-3
==> 1
what expression is the sane as 1/2 x 5
Answer:
5 divided by 2
Step-by-step explanation:
1/2 * 5 = 5/2
5/2 = 5 divided by 2
Find an equation of the line that satisfies the given conditions.Through (−9, −11); perpendicular to the line passing through (−6, 1) and (−2, −1)
The equation of the line passing through (9,11) and perpendicular to the line passing through (6,1) and (2,1) is x = 6
Find the slope of the line passing through (6,1) and (2,1):
The slope of a line passing through two points (x1,y1) and (x2,y2) is given by:
slope = (y2 - y1) / (x2 - x1)
Substituting the given coordinates, we get:
slope = (1 - 1) / (2 - 6) = 0
Therefore, the slope of the line passing through (6,1) and (2,1) is 0.
Find the slope of the line perpendicular to the line passing through (6,1) and (2,1):
The slope of a line perpendicular to a line with slope m is given by:
perpendicular slope = -1/m
Substituting the slope of the line passing through (6,1) and (2,1), we get:
perpendicular slope = -1/0 (which is undefined)
This means that the line perpendicular to the line passing through (6,1) and (2,1) is a vertical line passing through the point (6,1) and (2,1).
Write the equation of the line passing through (9,11) and perpendicular to the line passing through (6,1) and (2,1):
Since the line passing through (6,1) and (2,1) is a horizontal line with equation y = 1, the line perpendicular to it is a vertical line passing through the point (6,1) and (2,1). The equation of a vertical line passing through a point (a,b) is given by:
x = a
Substituting the value of x = 6 (since the vertical line passes through (6,1) and (2,1)), we get:
x = 6
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The number of newly reported crime cases in a county in New York State is shown in the accompanying table, where x represents the number of years since 1995, and y represents number of new cases. Write the linear regression equation that represents this set of data, rounding all coefficients to the nearest hundredth. Using this equation, estimate the calendar year in which the number of new cases would reach 1282.
The nearest year, we can estimate that the number of new cases would reach 1282 in the year 2017.
Find the linear regression equation and estimate the year when the number of new cases would reach 1282 for a county in New York state, given the accompanying table.
To find the linear regression equation, we need to use the formula:
y = a + bx
where y is the number of new cases, x is the number of years since 1995, a is the y-intercept and b is the slope of the line.
Using the given data, we can find the values of a and b using the formulas:
b = (nΣxy - ΣxΣy) / (nΣ\(x^2\) - (Σx)\(^2)\)
a = (Σy - bΣx) / n
where n is the number of data points, Σxy is the sum of the products of x and y, Σx is the sum of x, Σy is the sum of y, and Σ\(x^2\) is the sum of squares of x.
Using these formulas and the given data, we get:
n = 9
Σx = 36
Σy = 7386
Σx^2 = 162
Σxy = 3330
b = (93330 - 367386) / (9*162 - 36^2) ≈ -75.44
a = (7386 - (-75.44)*36) / 9 ≈ 2612.67
Therefore, the linear regression equation is:
y ≈ 2612.67 - 75.44x
To estimate the year in which the number of new cases would reach 1282, we can substitute y = 1282 into the equation and solve for x:
1282 ≈ 2612.67 - 75.44x
75.44x ≈ 2612.67 - 1282
x ≈ 22.36
This means that the number of new cases would reach 1282 approximately 22.36 years after 1995. Adding this to 1995 gives us an estimate of the calendar year:
1995 + 22.36 ≈ 2017.36
Rounding to the nearest year, we can estimate that the number of new cases would reach 1282 in the year 2017.
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What is the slope of the line
Answer:
2/3
Step-by-step explanation:
rise over run is 2 over 3, and it is positive because the y increases as the x increases!
Shaylyn measured her house as 5 meters tall.Which of these is an equivalent measurement
A. 0.3 miles
B. 7.3 yards
C. 16.4 feet
D. 27.2 inches
|x|=6
pls help its for homework and I forget
Answer:
x=-6, x=6
Step-by-step explanation:
|x| means the distance that x is from zero, so there are only two real possibilities. The only two numbers are +-6.
What is the basic ratio of red to white for a paint mixture
of 14 pints of red paint and 35 pints of white paint?
If a patient suffers from hypervolemia, which of the following hypotheses might explain the cause?
The patient's aldosterone secretion is too high. Therefore, too much salt is reabsorbed and as a consequence, water is also retained to counterbalance salt concentrations.
Too few natriuretic peptides are released. As a result, stretching of the atria due to excess water volume does not trigger inhibition of ADH or aldosterone.
Too much antidiuretic hormone is secreted. Thus, there is an excess retention of water and the thirst centers are stimulated.
All of the mentioned hypotheses can potentially explain the cause of hypervolemia in a patient.
1. High aldosterone secretion: Increased aldosterone secretion leads to excessive salt reabsorption, causing water retention to maintain salt concentration balance.
2. Insufficient natriuretic peptides: When there are too few natriuretic peptides released, the stretching of the atria due to excess water volume does not inhibit ADH or aldosterone, causing hypervolemia.
3. Excess antidiuretic hormone secretion: Over-secretion of antidiuretic hormone results in excessive water retention and stimulation of thirst centers, leading to hypervolemia.
Hypervolemia can be caused by various factors, including increased aldosterone secretion, insufficient natriuretic peptides, and excess antidiuretic hormone secretion. Identifying the specific cause in a patient requires further examination and testing.
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Which of these graphs represents a function?
5NW&S
4
1
43-2-1₁ 1 2 3 4 5
-2
-3
-4
-5
W.
N.
1
-5-4-3-2-1 1 2 3 4 5
JANM
-5
-2
Y.
A
X
२४
-3-2-
>
८
4
3
1
-5-4-3-2-1 1 2 3 4
-2
-3
-4
-5
>
X.
V
5
4
-2
-3
-4
5
Z.
HE
४
+X
1 2 3 4 5
Answer: W
Step-by-step explanation:
The graph must pass the vertical line test.
How do you write an equation of a line given y-intercept -8 and slope 3/4
Answer:
\(y = \frac{3}{4} x-8\)
Step-by-step explanation:
You can us the equation y = m x + c to answer this question.
In ,
y = m x + c
m = slope
c = y - intercept
So, they have already given in the question that,
m = 3/4
c = (-8)
Therefore, you can simply put 3/4 and (-8) instead of m and c respectively like this.
y = m x + c
y = 3/4x - 8
Hope this helps you.
Let me know if you have any other questions :-)
Asia can rake her yard's leaves in 2 hours. It takes Isaac 6 hours to rake the yard's
leaves by himself. How long would it take if Asia and isoac work together?
Is will be 1 hour and 30 minutes
Answer:
I think i would be 2hours and 30 mins. Srry if it's wrong
Step-by-step explanation:
What is the volume of a square
pyramid with the base length of
24in and a height of 18in?
Answer:
V=3456
Step-by-step explanation:
V=\(a^{2}\)\(\frac{h}{3\\}\)
Show the fragmentations that give rise to the meaks at m/z 43, 57, and 85 in the mass spectrum of 2,4-dimethylpentane
The peaks at m/z 43, 57, and 85 in the mass spectrum of 2,4-dimethylpentane can be attributed to the fragments resulting from different fragmentation pathways, including the loss of a methyl group, an ethyl group, and the cleavage of the C-C bond between the two methyl groups.
The mass spectrum of 2,4-dimethylpentane shows peaks at m/z 43, 57, and 85. These peaks correspond to the fragments resulting from the fragmentation of the molecule. Let's examine the possible fragmentations that give rise to these peaks:
1. Fragment at m/z 43:
The peak at m/z 43 suggests the presence of a small fragment in the mass spectrum. One possible fragmentation pathway could involve the loss of a methyl group (CH3) from the parent molecule. This would result in a fragment with a molecular weight of 43, corresponding to a methyl radical (•CH3).
2. Fragment at m/z 57:
The peak at m/z 57 indicates the presence of another fragment in the mass spectrum. One possible fragmentation pathway could involve the loss of an ethyl group (C2H5) from the parent molecule. This would result in a fragment with a molecular weight of 57, corresponding to an ethyl radical (•C2H5).
3. Fragment at m/z 85:
The peak at m/z 85 suggests the presence of a larger fragment in the mass spectrum. One possible fragmentation pathway could involve the cleavage of the C-C bond between the two methyl groups in the parent molecule. This would result in a fragment with a molecular weight of 85, corresponding to a butyl radical (•C4H9).
It's important to note that these fragmentations are just examples and there could be other possible fragmentations contributing to the mass spectrum. The specific fragmentation pathways can vary depending on the instrument and conditions used for the mass spectrometry analysis.
In summary, the peaks at m/z 43, 57, and 85 in the mass spectrum of 2,4-dimethylpentane can be attributed to the fragments resulting from different fragmentation pathways, including the loss of a methyl group, an ethyl group, and the cleavage of the C-C bond between the two methyl groups.
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Solve A=1/2(bh) for h
Answer: 2A/b = h
Step-by-step explanation: First, get rid of the fraction by multiplying both sides of the equation by 2. That gives us 2A = bh.
Don't be thrown off by the capital A in this problem.
Just treat it like any other variable.
To get h by itself on the right side of the equation, we now simply
divide both sides of the equation by b and our answer is 2A/b = h.
Take a look back at the formula now in the
original problem, A = 1/2bh, does that look familiar?
3. 3(2x - 1) + 4 = 3 - 5(1 - x)
Answer:
= -3
Step-by-step explanation:
Answer:
x = -3
Step-by-step explanation:
Show that δ(x^2-a^2)=1/2a[δ(x-a)+ δ(x+a)]
δ(c0sθ- cosθ)= δ(θ-θ’)/sin θ’= δ (θ- θ’)/ sin θ
By using Dirac delta function, δ(c0sθ- cosθ)= δ(θ-θ’)/sin θ’= δ (θ- θ’)/ sin θ.
Here's how to show that δ(x^2-a^2)=1/2a[δ(x-a)+ δ(x+a)]
To show that δ(x^2-a^2)=1/2a[δ(x-a)+ δ(x+a)],
we can use the definition of Dirac delta function.
Dirac delta function is defined as follows:∫δ(x)dx=1and 0 if x≠0
In order to solve the given expression, we have to take the integral of both sides from negative infinity to infinity, which is given below:∫δ(x^2-a^2)dx=∫1/2a[δ(x-a)+ δ(x+a)]dx
To compute the left-hand side, we use a substitution u=x^2-a^2 du=2xdxWhen x=-a, u=a^2-a^2=0 and when x=a, u=a^2-a^2=0.
Therefore,-∞∫∞δ(x^2-a^2)dx=-∞∫∞δ(u)1/2adx=1/2a
Similarly, the right-hand side becomes:∫1/2a[δ(x-a)+ δ(x+a)]dx=1/2a∫δ(x-a)dx +1/2a∫δ(x+a)dx=1/2a + 1/2a=1/2a
Therefore,∫δ(x^2-a^2)dx=∫1/2a[δ(x-a)+ δ(x+a)]dxHence, δ(x^2-a^2)=1/2a[δ(x-a)+ δ(x+a)].
Next, we can show that δ(c0sθ- cosθ)= δ(θ-θ’)/sin θ’= δ (θ- θ’)/ sin θ as follows:We know that cosθ = cosθ' which implies θ=θ'+2nπ or θ=-θ'-2nπ.
Therefore, c0sθ-cosθ'=c0s(θ'-2nπ)-cosθ'=c0sθ'-cosθ' = sinθ'c0sθ-sinθ'cosθ'.
We can use the following identity to simplify the above expression:c0sA-B= c0sAcosB-sinAsinB
Therefore,c0sθ-cosθ' =sinθ'c0sθ-sinθ'cosθ'=sinθ'[c0sθ-sinθ'cosθ']/sinθ' =δ(θ-θ')/sinθ'
Hence,δ(c0sθ- cosθ)= δ(θ-θ’)/sin θ’= δ (θ- θ’)/ sin θ.
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What would happen if you subtracted the equation for x from the equation for 10x?
Answer:
9 x
Step-by-step explanation:
If you have 10 x and you subtract one, you get left with 9 x.
Think of it as objects. You have 10 apples and someone takes an apple, what do you have left? 9 x = 3
A
B
C
Neither of them
One positive number is 6 times another number. The difference between the two numbers is 205. Find the numbers. (Enter your answers as a comma-separated list.)
Answer:
Hence the positive numbers are 246, and 41
(246, 41)
Step-by-step explanation:
From the question,
One positive number is 6 times another numberLet the first positve number be \(x\)
and the other number be \(y\)
Hence,
\(x = 6y\) ....... (1)
Also,
The difference between the two numbers is 205That is,
\(x - y =205\) ........(2).
To solve for the two unknowns, substitute the value of \(x\) in equation (1) into equation (2).
Since,
\(x = 6y\)
Then
\(x - y =205\) becomes
\((6y) - y =205\\\)
Then,
\(6y - y = 205\\5y = 205\\\)
Divide both sides by 5
\(\frac{5y}{5} = \frac{205}{5} \\ y = 41\\\)
∴ the value of \(y\) is 41
Now, substitute the value of y into equation (1) to find \(x\)
Then,
\(x = 6y\) becomes
\(x = 6(41)\\x = 246\\\)
∴ the value of \(x\) is 246
Hence the positive numbers are 246, and 41
(246, 41)
Use Descartes' Rule of Signs to determine how many positive and how many negative real zeros the polynomial can have. Then determine the possible total number of real zeros. (Enter your answers as comma-separated lists.)
P(x) = x^3 − x^2 − x − 5
number of positive zeros possible number of negative zeros possible number of real zeros possible
According to Descartes' Rule of Signs, there is 1 positive real zero and 2 or 0 negative real zeroes of the polynomial.
Descarte's Rule of Signs determines the number of real zeros in polynomial functions.
This indicates that -
The number of positive real zeros in the polynomial function f(x) is less than or equal to an even number depending on the sign change of the coefficients.
The number of negative real zeros in f(x) is an even number equal to or less than the number of sign changes of the coefficients of f(-x) terms.
Here, the polynomial function is given as -
\(P(x)=x^{3}-x^{2} -x-5\) ----- (1)
We have to find out the number of positive and negative real zeros that the given polynomial can have.
The given polynomial already has its variables in the descending powers. So, we can easily determine the number of sign changes in the coefficients of P(x).
So, the coefficients of the variables in P(x) are -
1, -1, -1, -5
From above, we see that -
There is a sign change in the first and second variable coefficients
There is no sign change in the second and third variable coefficients
There is no sign change in the third and fourth variable coefficients
According to Descartes' Rule of Signs, there can be exactly three positive real zeros or less than three but an odd number of zeros.
So, we can determine that the number of positive real zeroes of the given polynomial can be 1.
To find out the negative real zeroes of the given polynomial, we have to find out P(-x) and determine the sign changes in the variable coefficients of P(-x).
From equation (1), we can write P(-x) as -
\(P(x)=x^{3}-x^{2} -x-5\\= > P(-x)=(-x)^{3}-(-x)^{2} -(-x)-5\\= > P(-x)=-x^{3}-x^{2} +x-5\)----- (2)
So, the coefficients of the variables in P(-x) are -
-1, -1, +1, -5
From above, we see that -
There is no sign change in the first and second variable coefficients
There is a sign change in the second and third variable coefficients
There is a sign change in the third and fourth variable coefficients
According to Descartes' Rule of Signs, since there are two sign changes of the coefficient variables, there can be two negative real zeros or less than two but an even number of zeros.
So, we can determine that the number of negative real zeroes of the given polynomial can be 2 or 0.
Thus, according to Descartes' Rule of Signs, there is 1 positive real zero and 2 or 0 negative real zeroes of the polynomial.
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please help ASAP! no BS!
Answer:
\(y=-\frac{1}{3}x +4\)
Step-by-step explanation:
slope= 1-7/9- -9= -1/3
y-intercept: 7 = -1/3(-9)+b, b=4
If r(t) =e2t,e-2t,te2t, find T(0),r''(0), and r'(t) r''(t)
The values of T(0) = e(0) = 1, r''(0) = 8, r'(t) = 2e^(2t) - 2e^(-2t), r''(t) = 8e^(2t) + 8e^(-2t).
We are given that r(t) = e^(2t), e^(-2t), te^(2t). To find T(0), we need to evaluate the unit tangent vector T(t) at t=0. The formula for the unit tangent vector is T(t) = r'(t)/|r'(t)|, where |r'(t)| is the magnitude of r'(t).
r'(t) = 2e^(2t) - 2e^(-2t), so r'(0) = 2 - 2 = 0.
Thus, T(0) = r'(0)/|r'(0)| = 0/|0|, which is undefined.
However, since r'(0) = 0, we can use the normal vector instead to find the direction of the tangent line at t=0.
The normal vector N(0) is given by N(t) = T'(t)/|T'(t)|. To find T'(t), we differentiate r'(t) with respect to t:
r''(t) = 4e^(2t) + 4e^(-2t)
So, r''(0) = 4 + 4 = 8. Thus, T'(0) = r''(0)/|r'(0)| = 8/0, which is undefined.
To find r'(t), we can differentiate r(t) using the product rule:
r'(t) = 2e^(2t), -2e^(-2t), 2te^(2t) + e^(2t)
To find r''(t), we can differentiate r'(t):
r''(t) = 4e^(2t), 4e^(-2t), 4te^(2t) + 4e^(2t)
Thus, r'(t) = 2e^(2t) - 2e^(-2t), and r''(t) = 8e^(2t) + 8e^(-2t).
Therefore, T(0) = e^(0) = 1, r''(0) = 8, r'(t) = 2e^(2t) - 2e^(-2t), and r''(t) = 8e^(2t) + 8e^(-2t).
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Test for the commutative property of union and intersection of the sets P = { x : x is all real numbers between 2 and 7} and Q = { x : x is all rational numbers between 2 and 7}
Answer:
Step-by-step explanation:
P = {x : x is a real number between 2 and 7}
{x: 3,4,5,6}
Q = {x : x is all rational number between 2 and 7}
{4 }
We know that P contains all the rational numbers between 2 and 7.
And P ∪ Q and Q ∪ P each of them contain all the real numbers which are between 2 and 7.
{3,4,5,6}
Here Q is the proper subset of P
P ∩ Q = Q ∩ P = Q= {4}
At the Middleton School festival, a tent covers a rectangular space 30 1/2 yards long and 9 1/3 yards wide. What is the area, in square yards, covered by the tent?
What is the smallest positive integer that is both a multiple of $7$ and a multiple of $4$?
The smallest positive integer that is both multiple of 4 and 7 is 2
What are multiples?In mathematics, multiples are the results of multiplying an integer by a given number.
The given numbers for this problem are 4 and 7. The positive multiples of 4 and 7 will be listed and the first number that appeared in the both multiples s the smallest positive integer that is both a multiple of 7 and a multiple of 4.
The multiples of 4
4 8 12 16 20 24 28 32 36 .......
The multiples of 7:
7 14 21 28 35 42 49 56 63 70 77 84 91 98 .....
The smallest common multiple is 28
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Can some help please
Answer:
D
Step-by-step explanation:
3 months start with J, so its 9/12, meaning D is correct
JANUARY February March April May JUNE JULY Agugust September October November December
A car travelled a distance of 50km in an hour.what distance did it travel in 30min at the same speed?
1 hour = 60 minutes
Distance travelled in 60 minutes = 50 km
Distance travelled in 1 minute = 50/60
Distance travelled in 30 minutes = 50/60×30
50/60×30 = 25 km
OR
A car travelled 50 km in 60 minutes. For 30 minutes, half the distance that is 25 km.
how do you use 4 8 2 7 4 9 to get 100?
Answer:
i using multiplication to get 100
Step-by-step explanation:
Answer:
You can add multiply divide or subtract I think
Step-by-step explanation:
PLEASE HELP!! MATHH
SUPER DESPERATE EVEN 1 ANSWER IS FINE
Answer:
4 x 3 x 2
Step-by-step explanation:
Hope that helps, I'm like 95% sure that's the answer.
Answer:
Question 1: C. 4 × 3 × 2 × \(\frac{1}{8}\) × \(\frac{1}{8}\) × \(\frac{1}{8}\)
Question 2: The volume is \(\frac{1}{12}\) or 0.083333333
Question 3: The volume fo the solid figure is 234
Step-by-step explanation:
1. Volume of a rectangular prism = (length × width × height) cubic units
Length = 4 × \(\frac{1}{8}\)
Width = 3 × \(\frac{1}{8}\)
Height = 2 × \(\frac{1}{8}\)
Volume = 4 × \(\frac{1}{8}\) × 3 × \(\frac{1}{8}\) × 2 × \(\frac{1}{8}\)
Volume = 4 × 3 × 2 × \(\frac{1}{8}\) × \(\frac{1}{8}\) × \(\frac{1}{8}\)
So the correct option is:
C. 4 × 3 × 2 × \(\frac{1}{8}\) × \(\frac{1}{8}\) × \(\frac{1}{8}\)
2.
We have to fold the shape into a rectangular prism, look at the picture
Volume of a right rectangular prism = (length × width × height)
Length = \(\frac{1}{3}\)
Width = \(\frac{1}{3}\)
Height = \(\frac{3}{4}\)
Volume = \(\frac{1}{3}\) × \(\frac{1}{3}\) × \(\frac{3}{4}\)
Multiply \(\frac{1}{3}\) times \(\frac{1}{3}\) by multiplying numerator times numerator and denominator times denominator.
\(\dfrac{ 1 \times 1 }{ 3 \times 3 } \times \left( \dfrac{ 3 }{ 4 } \right)\)
Do the multiplications in the fraction \(\dfrac{ 1 \times 1 }{ 3 \times 3 }\)
\(\dfrac{ 1 }{ 9 } \times \left( \dfrac{ 3 }{ 4 } \right)\)
Multiply \(\frac{1}{9}\) times \(\frac{3}{4}\) by multiplying numerator times numerator and denominator times denominator.
\(\dfrac{ 1 \times 3 }{ 9 \times 4 }\)
Do the multiplications in the fraction \(\dfrac{ 1 \times 3 }{ 9 \times 4 }\)
\(\frac{3}{36}\)
Reduce the fraction \(\frac{3}{36}\) to the lowest terms by extracting and canceling out 3
Fraction form: \(\frac{1}{12}\)
or
Decimal form: 0.083333333
So the volume of the right rectangular prism is \(\frac{1}{12}\)
3. Look at the picture with the solid figure labeled
We can think of this shape as two different prisms ( A and B)
Volume of A = 4.5 × 6 × 6.5 = 175.5
Volume of B = 3 × 3 × 6.5 = 58.5
Total volume of the whole figure = 175.5 + 58.5
175.5 + 58.5 = 234
So the volume of the solid figure is 234
I need help question number 6
Part a
we have that
the volume of the box is equal to
V=L*W*H
so
In this problem
the height H is equal to H=x
L=(10-2x) in
W=(8-2x) in
substitute in the formula
V=(10-2x)(8-2x)(x) in3
apply distributive property
V=(80-20x-16x+4x^2)(x)
V=(4x^3-36x^2+80x) in3
Part b
For x=0.7 in
V=4(0.7)^3-36(0.7)^2+80(0.7)
V=39.732 in3
For x=2.3 in
V=4(2.3)^3-36(2.3)^2+80(2.3)
V=42.228 in3
so
the change in the box volume increases (42.228-39.732)=2.5 in3
For x=3.2 in
V=4(3.2)^3-36(3.2)^2+80(3.2)
V=18.432 in3
the change in the box volume decreases (42.228-18.432)=23.8 in3