What is the slope of the line on the graph?​

Answer:

The percentage increase from 8000 to 10000 is 25%.

The percent of increase from 8000 to 10000 is given as 25%.

A percentage is a value that indicates 100th part of any quantity.

A percentage can be converted into a fraction or a decimal by dividing it by 100. The percent of increase or decrease can be found by taking the ratio of the increased or decreased value to the initial value.

The given numbers are 8000 and 10000.

The percent increase can be obtained as follows,

The increased value ÷ Initial number × 100

⇒ (10000 - 8000) ÷ 8000 × 100

⇒ 2000 ÷ 8000 × 100

⇒ 25%

Hence, the percent increase is obtained as 25%.

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Answer:

\(2 \sqrt[]{7} , and -2\sqrt[]{7}\)

Step-by-step explanation:

or:

x=5.29150262…,−5.29150262

Answer:

16.26

Step-by-step explanation:

I am not completely sure what the problem is asking, but I believe that you are just supposed to take the inverse of sine. So, in your calculator, make sure it is in degrees mode, then usually you have to click the 2nd key and then sine. You use the inverse of sine when two sides are given, but you are not given the angle.

It should look like:

\(sin^{-1}(\frac{7}{25})\), which is approximately 16.26.

Hopefully this is right, if not, please let me know. Good luck.

Answer:

9.6

Step-by-step explanation:

Answer:

7. -

a. 3.5 or 7/2 hours

b. 24.5

c. After 7 hours (and at the beginning when t=0)

8. -

a. 4 seconds

b. 1 second

c. 54 meters

Step-by-step explanation:

7. M(t)=-2t^2+14t

M’(t)=-4t+14

a)

-4t+14=0

4t=14

2t=7

t=7/2

b) M(7/2)=24.5

c)

M(t)=0

-2t^2+14t=0

t^2-7t=0

t(t-7)=0

t=0, 7

8.

a)

h(t)=0

-6t^2+12t+48=0

t^2-2t-8=0

(t-4)(t+2)=0

t=-2, 4

t=4

b)

h(t)=-6t^2+12t+48

h’(t)=-12t+12

h’(t)=0

-12t+12=0

12t=12

t=1

c) h(1)=54

I hope this helps; please vote brainliest!

Answer:

g(x) has a larger slope

Step-by-step explanation:

If you look closely, g(x) has a slope of 5.

A control group is a comparison group treated like the other group, except for the manipulated factor.

A control group is a comparison group used in an experiment that is treated like the other group, except for the factor that is being manipulated. The purpose of a control group is to have a baseline to compare the results of the experiment with. It allows the researcher to measure the effects of the manipulated factor on the results. A control group is often used in medical trials, such as drug trials, to compare the effects of a new drug to the effects of a placebo. In other types of experiments, the control group is used to measure the effects of the manipulated factor, such as the effects of different teaching methods on student learning. The control group is also used to rule out any other factors that could be influencing the results of the experiment.

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Answer:

\(9\text{ cm}\)

Step-by-step explanation:

We can write the following proportion:

\(\frac{\text{old perimeter}}{\text{scaled perimeter}}=\frac{\text{old scale factor}}{\text{new scale factor}}\)

We know that the original perimeter of the Pentagon is 921 feet. So, substitute 921 for "old perimeter."

We are going to use a scale of 3 cm = 307 feet. Since the 307 feet corresponds to the original perimeter, we are going to substitute 307 for "old scale factor" and 3 for "new scale factor."

This gives us:

\(\frac{921}{x}=\frac{307}{3}\)

So, to find our scaled perimeter, we just need to find x.

Cross multiply:

\(307x=2763\)

Divide both sides by 307:

\(x=9\)

In other words, the total perimeter of Sawyer's drawing will be 9cm.

And we're done!

Answer:

let Cedric's age be c

tyshon= 3c-3

3c-3 +c =3c+c-3 = 4c-3

4c-3=57

4c=60

c=15

tyshon=15×3-3 = 42

Answer:

16

Step-by-step explanation:

57dvied by 3 -3=16

The trigonometric values for a right triangle can be obtained through the measurements of the different sides,

this can be found in a triangle like this,

then, identify the measurements in the given triangle

then,

The volume of the described solid is V = 16r³/3

A solid line S should be drawn between z = a and z = b. If S has a cross-sectional area of Px through x and is perpendicular to the x-axis, then  A(x).

Volume of S = limₙ→∞ ∑i=₁ⁿ A(xi) Δx = \(\int\limits^a_b {A(x)} \, dx\)

The equation of circle x² + y² = r² where r is the radius of the circle.

Equation of upper semicircle yu= √(r²-x²)  and

Equation of lower semicircle yl = -√(r²-x²)

Area of cross-section A(x) = (yu² - yl²)

Substitute yu and yl values

A(x) = [√(r²-x²) - (-√(r²-x²) )]² = 4(r² -x²)        (1)

The limit for volume v varies from -r to r

Thus Volume v = \(\int\limits^{r}_{-r} {A(x)} \, dx\)

Substitute A(x) from (1)

V = \(\int\limits^{r}_{-r} {4(r^{2}-x^2 )} \, dx\)

V = 4[r²x - x³/3 ]

V = 4(r³ - r³/3) - 4(-r³ + r³/3) = 4[2 (r³ - r³/3)] = 16r³/3

The volume of the described solid S where the base is a circular disk or radius r and parallel cross sections perpendicular to the base are squares is V = 16r³/3

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a

Step-by-step explanation:

The value after multiplying the given mixed fractions is 7/6   .

In the question ,

it is given that ,

the two mixed fraction are given as \(-2\frac{1}{4}\)  and \(-1\frac{1}{3}\)  ,

we need to find their value after multiplication .

we first convert the mixed fractions into improper fraction ,

So ,

\(-2\frac{1}{4}\) = (-2×4+1)/4 = (-8+1)/4 = -7/4

and

\(-1\frac{1}{3}\) = (-1×3+1)/3 = (-3+1)/3 = -2/3

So , the product of -7/4 and -2/3 is written as

= -7/4 × -2/3

= (-7 × -2)/(4 × 3)

= 14/12

after simplifying ,

= 7/6

Therefore , The value after multiplying the given mixed fractions is 7/6   .

The given question is incomplete , the complete question is

Find the value after multiplying the given mixed fraction \(-2\frac{1}{4} \times -1\frac{1}{3}\)   .

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The value of a that makes \(fx(x)\) a valid probability density function is a = 2/3.

We need to find the value of a that makes \(fx(x)\) a valid probability density function. For \(fx(x)\) to be a valid probability density function, it must satisfy the following conditions:

Condition 1 is satisfied because \(x^2\) is always non-negative for all values of x, and a is a positive constant.

To satisfy condition 2, we need to integrate \(fx(x)\) over the given interval and set the result equal to 1. That is,

∫[-1,1] \(x^2\)/a dx = 1

Simplifying the integral, we get:

[\(x^3\)/(3a)] [-1,1] = 1

[(\(1^3\)/(3a)) - \(((-1)^3\)/(3a))] = 1

(2/3a) = 1

a = 2/3

Therefore, the value of a that makes \(fx(x)\) a valid probability density function is a = 2/3.

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The probability of finding 0 contaminated pieces in  225 g of chocolate is 5.57 X 10⁻⁷.

Here the number of contaminated fragments follows a Poisson process. Hence, let the distribution for the same be X.

Hence we get X ~ Poi(λt)

where λ is the mean no. of contaminated pieces and t is the no. of bars consumed.

For P(X = x) we get [(λt)ˣ  e^(-λt)]/x!

Here λ = 14.4 and t = 1 Hence we will get

P(X = x) = [(14.4)ˣ e⁻¹⁴°⁴]/x!

Here we need to find the probability of the no. of contaminated pieces = 0

Therefore

P(X = 0) = [(14.4)⁰ e⁻¹⁴°⁴]/0!

Hence the probability of finding 0 contaminated pieces in a bar of chocolate is

P(X = 0) =  e⁻¹⁴°⁴

= 5.57 X 10⁻⁷

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Answer:

B = 94.9

Step-by-step explanation:

If we know 2 of the 3 angles of the triangle, we can estimate the base of the triangle as 90ft, after calculation, if the base was 90ft, side r would be 71.97584 which rounds to 94.9.

Result

Obtuse Scalene Triangle

Side r = 71.97584

Side 53* = 50.39643

Side 34* = 90

C=93°B=34°A=53°b=50.396a=71.976c=90

The Choice D is that the best answer in keeping with the passage. This  represent that They gave bees an opportunity to settle on between beetle-free enhanced flowers and beetle-free normal flowers.

According to the statement

we have to seek out the proper statement with the assistance of the given passage.

So, For this purpose, we all know that the

According to the passage,

Choice A is inaccurate because the passage states only that the scientists observed the bees and beetles on the flowers as soon as they opened (lines 59-61), not both before and after they opened. Choice B is inaccurate because although the passage does state that the experiment only befell during the “August flowering season” (line 35), it doesn’t state that this was a variable within the experiment or had any effect thereon. Choice C is inaccurate because comparing gourds supported the kind of pollination isn't associated with the problem of what repelled bees from the fragrance-enhanced plants.

So, the selection D is that the best answer in step with the passage. within the passage Theis surmises that honey bees were likely repelled not by the improved fragrance of the dimethoxybenzene-treated flowers but “by the abundance of beetles”

(lines 71-72) found on them. She was ready to make that assumption because the honey bees were ready to make a choice from both normal flowers and fragrance-enhanced flowers with none beetles on them, because one in all the parameters of the research was that “every half hour throughout the experiments, the team plucked all the beetles off of half the fragrance-enhanced flowers and half the control flowers, allowing bees to retort to the blossoms with and without interference by beetles” (lines 45-50).

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Answer:

The answer is 16.4 inches

Step-by-step explanation:

The result is calculated by adding all the values together. 3.3+10.6+2.5=16.4

\(Answer: 2+(-1)+(-4)+...+(-238)=-9558.\\\sum\limits_{k=1}^{89}(5k+1)=20114.\)

Step-by-step explanation:

\(2+(-1)+(-4)+...+(-238)=\\a_1=2\ \ \ \ \ a_n=-238.\\d=(-1)-2\\d=-3.\\a_n=a_1+(n-1)*d\\-238=2+(n-1)*(-3)\\-238=2-3n+3\\-238=5-3n\\-243=-3n\\-3*81=-3*n\\Divide\ both \ sides\ of\ the\ equation\ by\ -3:\\81=n.\\\)

                   \(\diplaystyle\\\\\boxed {S=\frac{a_1+a_n}{2}*n }\)

 \(\displaystyle\\S=\frac{2+(-238)}{2} *81\\S=\frac{-236}{2}*81\\ S=-118*81\\S=-9558.\)

\(\displaystyle\\\sum\limits_{k=1}^{89}(5k+1)=\\a_1=5*1+1\\a_1=5+1\\a_1=6\\a_2=5*2+1\\a_2=10+1\\a_2=11.\\d=a_2-a_1\\d=11-6\\d=5.\)

                   \(\displaystyle\\\boxed {S=\frac{2a_1+(n-1)*d}{2}*n }\)  

\(\displaystyle\\S=\frac{2*6+(89-1)*5}{2}*89\\\\ S=\frac{12+88*5}{2} *89\\\\S=\frac{12+440}{2}*89\\\\ S=\frac{452}{2} *89\\\\S=226*89\\\\S=20114.\)

Maria gets 1/12 of the chips.

Lilly has 1/3 of chips. She gives Maria 1/4 of what she has to Maria. To find the fraction that Maria gets, we need to multiply the fraction Lilly gives to Maria (1/4) by the fraction of chips Lilly has (1/3).

Multiplying fractions involves multiplying the numerators and multiplying the denominators. So, multiplying 1/4 and 1/3 gives us (1 * 1) / (4 * 3), which simplifies to 1/12.

Therefore, Maria gets 1/12 of the chips.

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In order to find the mean of the data summarized in the given frequency distribution, we can use the following formula\(:$$\bar{x}=\frac{\sum{f_ix_i}}{\sum{f_i}}$$Where,$$\bar{x}= \text{Mean value}$$$$f_i= \text{Frequency}$$$$x_i= \text{Mid value}$$\)

We need to calculate the mid-value for each class interval, as follows:Low Temperature​ (circle◦​F)Frequency Mid value\($$40 - 44$$ 33 $$\frac{40+44}{2}=42$$ $$45 - 49$$ 77 $$\frac{45+49}{2}=47$$ $$50 - 54$$ 99 $$\frac{50+54}{2}=52$$ $$55 - 59$$ 77 $$\frac{55+59}{2}=57$$ $$60 - 64$$ 0 $$\frac{60+64}{2}=62$$\)Now, we can plug the values into the formula to calculate the mean as follows:\($$\begin{aligned}\bar{x}&=\frac{\sum{f_ix_i}}{\sum{f_i}}\\&=\frac{(33)(42)+(77)(47)+(99)(52)+(77)(57)+(0)(62)}{33+77+99+77+0}\\&=\frac{76716}{286}\\&\approx268.09\\\end{aligned}$$\)

The computed mean is approximately 268.09. Let us compare it with the actual mean of 56.5. We can observe that the computed mean is more than 100 degrees more than the actual mean of 56.5. This can be explained by the fact that the data is skewed towards the higher end, as there are more observations in the higher intervals as compared to the lower ones. As a result, the computed mean is influenced by the higher values and is pulled up, leading to a significant difference from the actual mean.\(:$$\bar{x}=\frac{\sum{f_ix_i}}{\sum{f_i}}$$Where,$$\bar{x}= \text{Mean value}$$$$f_i= \text{Frequency}$$$$x_i= \text{Mid value}$$\).

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8 children are divided into 2 teams each containing 4 children to play a game against each other. 105 different divisions are possible.

Permutation:

In mathematics, permutation refers to the process of placing all members of a set into an order or sequence. In other words, if the set is already ordered, the permutation of its elements is called permutation. Substitutions occur in more or less noticeable ways in almost all areas of mathematics. They often occur when different orders are considered in a particular finite set.

Combination:

Combining is a way of selecting items from a collection, and (unlike permutation) the order of selection does not matter. In smaller cases you can count the number of combinations. Combining refers to combining n things, taken k times at once, without repetition.

According to the Question:

The first team can be chosen in ⁸C₂ = 28 ways.

After that, there are 6 people left, from which there are ⁶C₂ = 15 ways to choose the second team.

Then, there are 4 people left, out of which ⁴C₂ = 6 ways he can choose the third team. There is only one way to choose the fourth and final team from the remaining two.

In the above procedure, each occasion of splitting eight into her two his four teams counted as 4!= 24 times.

Thus,

The number of ways to divide a group of 8 people into 4 teams of 2 people = 28 × 15 × 6 / 24

            = 105

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Answer:

74 is the answer bruhh

Step-by-step explanation:

180 - 106 = 74

The value of x is 13.85.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

From the figure,

(7x + 1)° and (6x - 1)° makes a straight angle.

This means,

(7x + 1) + (6x - 1) = 180

7x + 1 + 6x - 1 = 180

13x = 180

x = 180/13

x = 13.85

Thus,

x is 13.85°

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a. True. Pivot columns of an echelon form of A form a basis for the column space of A.
b. True. Row operations preserve linear dependence relations among the rows of A.
c. False. The dimension of the null space of A is the number of columns of A minus the number of pivot columns.

18. a. If B is any echelon form of A, then the pivot columns of B form a basis for the column space of A.

This statement is true. An echelon form of a matrix is obtained by performing row operations on the original matrix to transform it into a specific triangular form. In this form, the pivot columns correspond to the columns containing the leading entries in each row. The pivot columns of an echelon form of matrix A will also be pivot columns of matrix A itself.

The column space of a matrix is the span of its column vectors. Since the pivot columns of B are a subset of the column vectors of A, they will also span the column space of A. Therefore, the pivot columns of B form a basis for the column space of A.

b. Row operations preserve the linear dependence relations among the rows of A.

This statement is true. When we perform row operations on a matrix, such as multiplying a row by a scalar, adding rows together, or swapping rows, the resulting matrix will have the same row space as the original matrix. This means that the linear dependence relations among the rows of the original matrix will be preserved in the transformed matrix.

c. The dimension of the null space of A is the number of columns of A that are not pivot columns.

This statement is false. The dimension of the null space of A, also known as the nullity of A, is the number of free variables in the reduced row echelon form of A. It is equal to the number of columns of A minus the number of pivot columns. Therefore, the dimension of the null space of A is the number of columns of A minus the number of pivot columns, rather than the other way around.

To summarize:
a. True. Pivot columns of an echelon form of A form a basis for the column space of A.
b. True. Row operations preserve linear dependence relations among the rows of A.
c. False. The dimension of the null space of A is the number of columns of A minus the number of pivot columns.

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Answer:

price of an adult ticket = a = $7

price of a student ticket = s = $6

Step-by-step explanation:

price of an adult ticket = a

price of a student ticket = s

7a + 7s = 91 (1)

14a + 12s = 170 (2)

Multiply (1) by 2

7a + 7s = 91 (1) × 2

14a + 14s = 182 (3)

14a + 12s = 170 (2)

Subtract (2) from (3) to eliminate x

14s - 12s = 182 - 170

2s = 12

s = 12/2

s = 6

Substitute s = 6 into (1)

7a + 7s = 91 (1)

7a + 7(6) = 91

7a + 42 = 91

7a = 91 - 42

7a = 49

a = 49/7

a = 7

price of an adult ticket = a = $7

price of a student ticket = s = $6

Answer:

Step-by-step explanation:

To get from blue to red you need to multiply the blue dimensions by 1.5.

4*x = 6       Divide by 4

x = 6/4

x = 1.5

The surface area is a different ball game.

SA of the blue figure

Surface area of 1 side = 4 *  4 = 16

The total surface area = 16* 6 = 96

SA of the red figure

Surface area of 1 face = 6*6

Surface area of  6 faces = 6 * 36 = 216

So what's the ratio ?

Ratio = red surface area/ blue surface area

Ratio = 216 / 96 = 2.25

Notice that if you square the dimensional ratio, you get the area ratio

1.5^2 = 2.25

Answer:

150÷30 =5

20×5 =100 so in 150 seconds he will bounce the ball 100 times