At the Fisher farm, the weights of zucchini squash are Normally distributed. Which standardized weight represents the top 10% of the zucchinis?
Find the z-table here.
–1. 64
–1. 28
1. 28
1. 64
The standardized weight which represents the top 10% of the zucchinis from the z-score for the fisher farm the weights of zucchini squash are Normally distributed is 1.28.
Standardized normal distribution = Z given by ,
Z = (X - μ)/σ
Here, X is sample, is μ mean and is σ standard deviation.
At the Fisher farm, the weights of zucchini squash are Normally distributed.
For the normal distribution,
The value mean be 0 and standard deviation be 1.
Z = (X - μ)/σ
μ = 0 , σ = 1
Z = (X -0)/1
Z = X
For the top 10% of the zucchinis, the value of α is 0.9. From the table for this value the z score is,
Z = X
Z = 1.28
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the intersection of two events a and b is the event that: a) both a and b occur. b) the union of ac and bc occurs. c) the union of a and b does not occur. d) either a or b or both occur. e) either a or b, but not both. f) none of the above.
The intersection of two evens a and b is the event that both a and b occur that is option A is correct.
The intersection of two events A and B is defined as the event that occurs when both A and B occur simultaneously. It is denoted by A ∩ B, where the symbol ∩ represents intersection.
For example, if event A is "getting a head when flipping a coin" and event B is "rolling a 6 on a fair die", then the intersection of A and B would be the event "getting a head when flipping a coin and rolling a 6 on a fair die".
For example, suppose A represents the event "rolling an even number on a dice" and B represents the event "rolling a number greater than 3 on a dice". The intersection of A and B is the event that "rolling a number that is both even and greater than 3 on a dice", which consists of the outcomes {4, 6}.
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Complete Question:
the intersection of two events a and b is the event that:
a) both a and b occur.
b) the union of ac and bc occurs.
c) the union of a and b does not occur.
d) either a or b or both occur.
e) either a or b, but not both.
f) none of the above.
what percent is equivalent to 1/20
Answer:
1/20 is 5%
Step-by-step explanation:
1/20 = 5%
20/20 = 100%
100 ÷ 20 = 5%
1/20 x 100 = 0.05 x 100 = 5%
Step-by-step explanation:
\(1 \div 20 =( 1 \times 5) \div (20 \times 5) = \\ 5 \div 100 = 5\%\)
Determine the number of solutions for the linear equation shown below?
4(3x+8)−9=2(6x−8)−15
Answer:
0 = -54
Step-by-step explanation:
4(3x + 8) − 9 = 2(6x − 8) − 15
12x + 32 - 9 = 12x - 16 - 15
12x + 23 = 12x - 31
12x = 12x - 54
0 = -54
No solutions.
Best of Luck!
Which is not a way to write the answer to this problem?
Answer:
D) .
Step-by-step explanation:
913 ÷ 29 ≈ 31
You want to buy a new case for your iPhone. The case is $37 and the tax is 6%. WHAT IS THE TOTAL?
Answer:
$39.22
Step-by-step explanation:
The case costs $37. $37 is 100% of the price of the case.
The tax is 6% of the cost of the case. When you add 6% to 100% you get 106%.
The total price including tax is 106% of the price of the case.
106% of $37 = 1.06 * $37 = $39.22
Answer: $39.22
There are 5 positions available in the new school. Of the applicant, 12 are men and 8 are women. In how many ways can 3 men and 2 women be chosen if they are equally considered?
There are 3080 ways 3 men and 2 women can be chosen if they are equally considered, using the multiplication principle of counting
What is the multiplication principle of countingThe multiplication principle states that if there are m ways to perform one task and n ways to perform another task, then there are m x n ways to perform both tasks together.
To find the number of ways to choose 3 men from the 12 men, we can use the formula for combination, which is: ⁿCᵣ = n! / (r! (n-r)!).
where n is the total number of men and r is the number of men chosen
so, the number of ways to choose 3 men from the 12 men = ¹²C₃ = 1.
Similarly, we evaluate the number of ways to choose 2 women from the 8 women
as = ⁸C₂ = 14
Now, using the multiplication principle, we can find the total number of ways 3 men and 2 women be chosen if they are equally considered.
220 x 14 = 3080
Therefore, there are 3080 ways 3 men and 2 women can be chosen if they are equally considered, using the multiplication principle of counting
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What term is used to describe an error that occurs when numbers are moved to the right or left in an amount column?.
The term used to describe an error that occurs when numbers are moved to the right or left in an amount column is "Slide".
Slide:
An accounting slide is a mistake that happens when the decimal point of a number is moved to the left or right of where it should be.
For instance, a bookkeeper would enter $1,200.50 in place of $12,005 in the revenue account or $250.75 in place of $2,507.50 in the monthly insurance expenses. In general, bookkeeping mistakes and accounting blunders lead to financial record misstatements.
"Slide" is the name for a mistake that happens when numbers are moved to the right or left in an amount column.
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Let f: DC be a function, with D being the domain and C being the codomain. Show that for any C₁, C₂ CC
f(C₁ C₂) = f(C₁) f(C₂)"
The function f respects the structure of the codomain, ensuring that combining elements in the codomain and applying f to the combination is equivalent to applying f to the individual elements and then combining their images.
To show that for any elements C₁ and C₂ in the codomain C, we have f(C₁C₂) = f(C₁)f(C₂), we need to demonstrate that the function f preserves the binary operation in the codomain. This means that applying the function f to the combination of two elements should be equal to the combination of their individual images under f.
Let's consider C₁ and C₂ as arbitrary elements in the codomain C. We want to show that f(C₁C₂) = f(C₁)f(C₂).
Since f is a function, for any element x in the domain D, there exists a unique image f(x) in the codomain C. This means that we can evaluate the function f on C₁ and C₂ individually to obtain their respective images.
Now, let's consider the combination C₁C₂. According to the binary operation in the codomain C, this combination results in an element in C. We want to show that applying the function f to this combination yields the same result as applying f to C₁ and C₂ separately and then combining their images.
Formally, we have:
f(C₁C₂) = f(C₁)f(C₂).
This equation states that the function f preserves the binary operation in the codomain. In other words, the function f respects the structure of the codomain, ensuring that combining elements in the codomain and applying f to the combination is equivalent to applying f to the individual elements and then combining their images.
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The types of transformations of geometric figures in the coordinate plane can be described as a slide, a flip, or a turn. What are the other names used to identify these transformations?
The other names used to identify the transformation of geometric figures is translation or reflection and rotation.
Given that the types of transformations of geometric figures in the coordinate plane can be described as a slide, a flip, or turn.
We are required to find the other names used to identify the above transformations.
The other names used to identify the transformation of geometric figures is translation or reflection and rotation.
Translation means the displacement of a figure from one place to another. In translation a figure can move upward, downward,right , Iift or anywhere in the coordinate system. In translation, the position of the object changes, its size remains the same.
Reflection is a type of transformation that flips a shape in a mirror line so that each point is the same distance from the mirror line as its reflected point.
Rotation is a motion of a space that preserves at least one point.
Hence the other names used to identify the transformation of geometric figures is translation or reflection and rotation.
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Please help me I am really confused and need help with this.
Answer:
Step-by-step explanation:
y=10
Please help, 30 points plus brainliest.
What are the coordinates of a point P(x, y) after a dilation with respect to the origin by a scale factor of k?
Answer:
(kx, ky)Step-by-step explanation:
Dilation with respect to origin by a scale factor k will result in:
P(x, y) → P'(kx, ky)Can someone help me with this question? A Ferris wheel has: a diameter of 80ft, an axel height of 60ft, and completes 3 turns in 1 minute. What would the graph look like?
The Ferris wheel's graph can be a sinusoidal curve with an amplitude of 40 feet as well as a period of 1/3 minutes (or 20 seconds), oscillating between 20 feet and 100 feet.
The procedures can be used to graph the Ferris wheel, which has axle height of 60 feet, a diameter of 80 feet, along with a rotational speed of three spins per minute:
Find the equation that describes how a rider's height changes with time on a Ferris wheel.
The equation referred to as h(t) = a + b cos(ct), where is the height of the axle, b is the wheel's half-diameter, as well as c is the number of full cycles per second substituting the values provided.
The vertical axis shows height in feet, as well as the horizontal axis shows time in minutes.
Thus, the graph will usually have a sinusoidal curve with an amplitude of 40 feet, a period of 1/3 minutes, and an oscillation between 20 feet and 100 feet.
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In each case, () find a basis of ker T, and (i) find a basis of im T. You may assume that Tis linear (a) T:P2 → R2; T(a + bx + cy?) = (a, b) (b) T: P2 → R", Tig(x)) = (p(0), p(1)) (c) T:R'--R,T(c, y, z) (x+y,x+y,0)
The basis of the image of T is formed by the set of vectors in the x-y plane, by using the concept of Linear transformation.
For the given question, we will use the concept of Linear transformation.
A linear transformation is a function that maps one vector space to another vector space, and that preserves the vector space operations like addition and scalar multiplication. It is also known as linear mapping or linear operator and has the property that
T(ku) = kT(u) and T(u + v) = T(u) + T(v) ∀ vectors u and v and all scalars k.
There are different methods to find the basis of ker T, and im T, such as using the rank-nullity theorem, finding the reduced row echelon form of the matrix representation of T, or finding the eigenvectors and eigenvalues of T.
Let's find the basis of ker T, and the basis of im T for the given cases.
(a) T: P2 → R2; T(a + bx + cy2) = (a, b)
The kernel of T is the set of polynomials in P2 such that T(p) = (0, 0), or equivalently, a = b = 0.
Thus, the basis of ker T is {c2}, the set of polynomials of degree less than or equal to 1.
The image of T is the set of vectors in R2 that can be written as (a, b) = T(p) for some polynomial p in P2.
Thus, the image of T is the entire R2, and the basis of im T is {(1,0), (0,1)}.
(b) T: P2 → R2; T(p) = (p(0), p(1))
The kernel of T is the set of polynomials in P2 such that T(p) = (0, 0), or equivalently, p(x) = 0 for all x.
Thus, the basis of ker T is {x(x - 1)}.
The image of T is the set of vectors in R2 that can be written as (a, b) = T(p) for some polynomial p in P2.
Thus, the image of T is the set of linear combinations of the two vectors (1,0) and (0,1), which form a basis of im T.
(c) T: R3 → R3; T(x,y,z) = (x + y, x + y, 0)
The kernel of T is the set of vectors in R3 such that T(x, y, z) = (0, 0, 0), or equivalently, x + y = 0 and z = 0. Thus, the basis of ker T is {(1,-1,0), (0,0,1)}.
The image of T is the set of vectors in R3 that can be written as T(x, y, z) = (a, b, 0) for some a and b.
Thus, the image of T is the set of vectors in the x-y plane, which form a basis of im T.
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Professor Mallory determines the distribution of students on five variables in her target population. She then uses nonprobability sampling to select students who fill the pre-established proportions of people in each combination of variables. Which sampling strategy did she use
The sampling strategy she use was a quota.
Quotas are meant to establish boundaries on the number of specific goods that are allowed to be lawfully imported into the country throughout a distinct period of time. In that, quotas are similar embargoes, except quotas don´t have explicit political purposes as embargoes do.
A Fixed quota would be a maximum amount not to be surpassed, while a tariff rate surcharge allows it, but with a higher duty.
Please Help! will give brainlest! Locks in an hour!
Answer:
3 we divid them to gather
Step-by-step explanation:
it is number3 3
X and y are int variables. True/False a/b/c/d) 4. Suppose that X and y are i nt variables. Which of the following is a valid input statement? b.cin >>x>>y; d.cout<
Among the given options for input statements involving int variables X and y, the valid option is b) cin >> x >> y.
This statement uses the extraction operator (>>) to read input values and assign them to the variables x and y consecutively. The extraction operator allows for multiple inputs in a single line, separated by spaces or other delimiters.
This statement ensures that two integer values can be entered and stored correctly in the variables x and y. The extraction operator (>>) is commonly used with the cin object in C++ for input operations. It facilitates convenient and efficient input handling for multiple variables in a single statement.
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CAN SOMEONE HELP ME REALLY QUICK
if 25% of Y is 30, what is 60% of Y
A) 72
B) 50
C) 20
Explain how you know this answer is correct
What else must you know to prove the angles congruent by SAS?
To prove the angles congruent by SAS, you need to know that two sides of one triangle are congruent to two sides of another triangle, and the included angle between the congruent sides is congruent.
To prove that angles are congruent by SAS (Side-Angle-Side), you must know the following:
1. Side: You need to know that two sides of one triangle are congruent to two sides of another triangle.
2. Angle: You need to know that the included angle between the two congruent sides is congruent.
For example, let's say we have two triangles, Triangle ABC and Triangle DEF. To prove that angle A is congruent to angle D using SAS, you must know the following:
1. Side: You need to know that side AB is congruent to side DE and side AC is congruent to side DF.
2. Angle: You need to know that angle B is congruent to angle E.
By knowing that side AB is congruent to side DE, side AC is congruent to side DF, and angle B is congruent to angle E, you can conclude that angle A is congruent to angle D.
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Consider the vectors: a=(1,1,2),b=(5,3,λ),c=(4,4,0),d=(2,4), and e=(4k,3k)
Part(a) [3 points] Find k such that the area of the parallelogram determined by d and e equals 10 Part(b) [4 points] Find the volume of the parallelepiped determined by vectors a,b and c. Part(c) [5 points] Find the vector component of a+c orthogonal to c.
The value of k is 1, the volume of the parallelepiped is 12 + 4λ, and the vector component of a + c orthogonal to c is (1,1,1.5).
a) Here the area of the parallelogram determined by d and e is given as 10. The area of the parallelogram is given as `|d×e|`.
We have,
d=(2,4)
and e=(4k,3k)
Then,
d×e= (2 * 3k) - (4 * 4k) = -10k
Area of parallelogram = |d×e|
= |-10k|
= 10
As we know, area of parallelogram can also be given as,
|d×e| = |d||e| sin θ
where, θ is the angle between the two vectors.
Then,10 = √(2^2 + 4^2) * √((4k)^2 + (3k)^2) sin θ
⇒ 10 = √20 √25k^2 sin θ
⇒ 10 = 10k sin θ
∴ k sin θ = 1
Therefore, sin θ = 1/k
Hence, the value of k is 1.
Part(b) The volume of the parallelepiped determined by vectors a, b and c is given as,
| a . (b × c)|
Here, a=(1,1,2),
b=(5,3,λ), and
c=(4,4,0)
Therefore,
b × c = [(3 × 0) - (λ × 4)]i + [(λ × 4) - (5 × 0)]j + [(5 × 4) - (3 × 4)]k
= -4i + 4λj + 8k
Now,| a . (b × c)|=| (1,1,2) .
(-4,4λ,8) |=| (-4 + 4λ + 16) |
=| 12 + 4λ |
Therefore, the volume of the parallelepiped is 12 + 4λ.
Part(c) The vector component of a + c orthogonal to c is given by [(a+c) - projc(a+c)].
Here, a=(1,1,2) and
c=(4,4,0).
Then, a + c = (1+4, 1+4, 2+0)
= (5, 5, 2)
Now, projecting (a+c) onto c, we get,
projc(a+c) = [(a+c).c / |c|^2] c
= [(5×4 + 5×4) / (4^2 + 4^2)] (4,4,0)
= (4,4,0.5)
Therefore, [(a+c) - projc(a+c)] = (5,5,2) - (4,4,0.5)
= (1,1,1.5)
Therefore, the vector component of a + c orthogonal to c is (1,1,1.5).
Conclusion: The value of k is 1, the volume of the parallelepiped is 12 + 4λ, and the vector component of a + c orthogonal to c is (1,1,1.5).
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I am willing to give a brainliest to anybody, just please help !!!
During which game is she more effective serving?
How did you find this answer and please show your work?
Answer: The First game with 16/19 serves
Step-by-step explanation: Fraction also means division. So once you divide both fractions, you'll see that 16/19 > 13/16. That shows that she was more effective in the first game.
work out the y-4 when y=10
Find the next three terms in each geometric sequence.
1. 638, -216, 72.......
2. 1/6, 1/2, 4.......
3. 72, 36, 18.......
The next three terms in each geometric sequence is 72, 36, 18, 9, 4.5, 2.25.
What is the general form of geometric progression?The general form of Geometric Progression is: a, ar, ar 2, ar 3, ar 4,…,a n. Where,
a = First term.
r = common ratio.
a n = nth term.
General Term or Nth Term of GP.
Let a be the first term
And, r be the common ratio for a G.P.
The general form of Geometric Progression is:
GP-series
Where,
a = First term
r = common ratio
arⁿ ⁻¹ = nth term
The next three terms of the GP is :
2.25 + 2.25 = 4.5
4.5 + 4.5 = 9
9 + 9 = 18
18 + 18 = 36
36 + 36 = 72
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PLEASE ANSWER QUICKLY ASAP
ANSWER QUESTION A AND B
Answer:
a) \(a+b+c=\begin{pmatrix}-2\\-3\end{pmatrix}\)
b) (i) \(a+2c=\begin{pmatrix}-4\\2\end{pmatrix}\)
(ii) \(k=2\)
Step-by-step explanation:
It is given that,
\(a=\begin{pmatrix}4\\-10\end{pmatrix},b=\begin{pmatrix}-2\\1\end{pmatrix},c=\begin{pmatrix}-4\\6\end{pmatrix}\)
a)
We need to find the value of a+b+c.
\(a+b+c=\begin{pmatrix}4\\-10\end{pmatrix}+\begin{pmatrix}-2\\1\end{pmatrix}+\begin{pmatrix}-4\\6\end{pmatrix}\)
\(a+b+c=\begin{pmatrix}4+(-2)+(-4)\\-10+1+6\end{pmatrix}\)
\(a+b+c=\begin{pmatrix}-2\\-3\end{pmatrix}\)
b)
(i) We need to find the value of a+2c.
\(a+2c=\begin{pmatrix}4\\-10\end{pmatrix}+2\begin{pmatrix}-4\\6\end{pmatrix}\)
\(a+2c=\begin{pmatrix}4\\-10\end{pmatrix}+\begin{pmatrix}-8\\12\end{pmatrix}\)
\(a+2c=\begin{pmatrix}4+(-8)\\-10+12\end{pmatrix}\)
\(a+2c=\begin{pmatrix}-4\\2\end{pmatrix}\)
(ii) It is given that a+2c=kb, where k is an integer. We need to find the value of k.
\(a+2c=k\begin{pmatrix}-2\\1\end{pmatrix}\)
\(\begin{pmatrix}-4\\2\end{pmatrix}=\begin{pmatrix}-2k\\k\end{pmatrix}\)
On comparing both sides, we get
\(k=2\)
A school offers band and chorus classes. The table shows the percents of the 1200 students in the school who are enrolled in band, chorus, or neither class. How many students are enrolled in both classes?
Using Venn probabilities, it is found that 240 students are enrolled in both classes.
Venn probabilities:The events are:
Event A: A student is enrolled in band.Event B: A student is enrolled in chorus.The supposed percentages, which also represents the probabilities involving a single student, are:
50% of the students involved in the band, hence \(P(A) = 0.5\).40% of the students involved in the chorus, hence \(P(B) = 0.4\).30% involved in neither, hence \(1 - P(A \cup B) = 0.3 \rightarrow P(A \cup B) = 0.7\).The percentage involved in both is:
\(P(A \cap B) = P(A) + P(B) - P(A \cup B)\)
Hence:
\(P(A \cap B) = 0.5 + 0.4 - 0.7 = 0.2\)
Then, out of 1200 students:
\(0.2(1200) = 240\)
240 students are enrolled in both classes.
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it has been observed that some persons who suffer colitis, again suffer colitis within one year of the first episode. this is due, in part, to damage from the first episode. the performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. in order to do this two groups of people suffering a first episode are selected. there are 55 people in the first group and this group will be administered the new drug. there are 45 people in the second group and this group will be administered a placebo. after one year, 11% of the first group has a second episode and 9% of the second group has a second episode. conduct a hypothesis test to determine, at the significance level 0.1, whether there is reason to believe that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode? select the [alternative hypothesis, value of the test statistic].
The value of the test statistic is 0.
The alternative hypothesis states that there is a difference between the true percentage of the first group who suffer a second episode and the true percentage of the second group who suffer a second episode.
The null hypothesis states that there is no difference between the true percentage
of the first group who suffer a second episode and the true percentage of the second group who suffer a second episode. Let us compute the value of the test
statistic
First, let us determine the proportion of people in each group who suffer a second episode:First group: p1 = 11/55 = 0.2Second group: p2 = 9/45 = 0.2
The sample proportion
of both groups is 0.2. Let us now calculate the standard error of the difference of proportions:SE(p1 - p2) = sqrt{ [p1(1 - p1) / n1 ] + [ p2(1 - p2) / n2 ] }= sqrt{ [0.2(0.8) / 55] + [0.2(0.8) / 45] }= sqrt{ 0.0029 + 0.0044 }= sqrt{ 0.0073 }= 0.0853
Now we can calculate the test statistic:Z = [(p1 - p2) - 0] / SE(p1 - p2)Z = [(0.2 - 0.2) - 0] / 0.0853Z = 0 / 0.0853Z = 0
The value of the test statistic is 0. The alternative hypothesis states that there is a difference between the true percentage of the first group who suffer a second episode and the true percentage of the second group who suffer a second episode. However, the test statistic is 0.
Therefore, there is no evidence to support the alternative hypothesis. The value of the test statistic is 0.
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To calculate the test statistic, we can use the formula (p1 - p2) / sqrt((p1*(1-p1)/n1) + (p2*(1-p2)/n2)), where p1 and p2 are the sample proportions, and n1 and n2 are the sample sizes.
Given that p1 = 0.11, p2 = 0.09, n1 = 55, and n2 = 45, we can substitute these values into the formula to find the test statistic:
Test statistic = (0.11 - 0.09) / sqrt((0.11*(1-0.11)/55) + (0.09*(1-0.09)/45))
To conduct a hypothesis test, we need to define our null and alternative hypotheses. In this case, our null hypothesis (H0) states that the true percentage of those in the first group who suffer a second episode is the same as the true percentage of those in the second group who suffer a second episode. Our alternative hypothesis (Ha) states that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode.
Next, we calculate the test statistic, which is the difference between the sample proportions of the two groups. The sample proportion for the first group is 11% (or 0.11), and for the second group is 9% (or 0.09). The test statistic can be calculated as (p1 - p2) / sqrt((p1*(1-p1)/n1) + (p2*(1-p2)/n2)), where p1 and p2 are the sample proportions, and n1 and n2 are the sample sizes.
Substituting the values, the test statistic is (0.11 - 0.09) / sqrt((0.11*(1-0.11)/55) + (0.09*(1-0.09)/45)).
Finally, we compare the test statistic to the critical value at the significance level of 0.1. If the test statistic falls outside the critical value range, we reject the null hypothesis and conclude that there is reason to believe that the true percentages are different. Otherwise, we fail to reject the null hypothesis.
In this case, the alternative hypothesis is that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode. The value of the test statistic can be calculated using the formula provided above.
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(a)[2 pts] what is the notation of the sample mean? find the sample mean. (b)[3 pts] find the five-number summary of the sample.
a) Sample mean is arithmetic average of data values. The sample mean of provide data values is 10.
b) The five-number summary of the sample is minimum = 4, Q1 = 4.5, median = 9 , Q3 = 15.5 and maximum= 16.
The population mean is denoted by greek letter, μ and sample mean is a random variable; which is written as x-bar and x-bar stands for individual values it takes. The sample mean is a statistic measure obtained by calculating the arithmetic mean of sample values ( values of variable in sample). The sample mean formula is: x-bar = ( Σxᵢ) / n
x-bar represents the “sample mean”Summation notation, Σ, which means “sum up”xᵢ, all of the x-values or data values n means the number of values in the sampleNow, we have to calculate sample mean of following data values, 12,8,15,16,5,4.
Sum of values, Σ xi = 12 + 8 + 15 + 5 + 4 + 16 = 60
Number of values = 6
So, Sample mean, = ( Σ xi ) / n = 60/6 = 10
The five-number summary includes following :
Minimum data value.Q₁ (the first quartile ).Median.Q₃ (the third quartile).maximum data value.So, Steps to determine the five-number summary:
Put your numbers in ascending order.Determine minimum( smallest number) and maximum (largest number) value.Determine the median. The median is the middle number, in case of odd number of data values and in case even set of data the meadian is equals to average of the (n/2)ᵗʰ and the (n/2 + 1)ᵗʰ terms.Place parentheses around the numbers above and below the median.Determine Q₁ and Q₃. Q₁ is median in the lower half of the data, and Q₃ is median for the upper half of data.Now, the sample set is 12,8,15,16,5,4. Arrange the data values in ascending order, 4,5,6,12,15,16. So, Minimum value
= 4 , Maximum value = 16 ,Median = mean of 6 and 12 = (6 + 12)/2 = 9. The vales written as(4, 5, ) 6, 12, (15, 16 ). The value of first quartile, Q₁ = median of lower ( 4,5) = (4+5)/2
= 9/2 = 4.5. Similarly, Third quartile, Q₃
= (15+16)/2= 31/2 = 15.5. Thus, the five-numer summary is minimum = 4, Q₁
= 4.5, median = 9 , Q₃ = 15.5 and
maximum = 16.
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Complete question:
Consider the sample set 12,8,15,16,5,4 and answer the below questions:
(a)[2 pts] what is the notation of the sample mean? find the sample mean.
(b)[3 pts] find the five-number summary of the sample.
Which set of data contains two outliers? 113, 115, 103, 114, 109, 111, 119 141, 151, 138, 142, 149, 140, 150 99, 113, 91, 104, 109, 114, 97 101, 135, 131, 99, 138, 136, 140
Answer: 99,113,91,104,109,114,97
Step-by-step explanation:
Got 100% on the quiz :)
Answer:
D: 101, 135, 131, 99, 138, 136, 140
Step-by-step explanation:
edg2021 (do not get this confused with the question: "which set contains no outliers" hope this helps, please mark me brainliest if it does
10 degrees celcius risen to 30 degrees celcius
From the statement, we conclude that the temperature is risen by 20°C.
What is a numerical expression?A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.
Given, 10°C risen to 30°C.
From the statement initially it was 10°C and it has risen to 30°C.
Therefore, The amount of temperature risen is,
= (30 - 10)°C.
= 20°C.
So, The temperature was risen by 20°C.
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given f(x)=3x^6, findf^-1(x)
Answer:
Step-by-step explanation:
Dhddhhfjvjvmx,sfkiritifkflf,gjgi*jfckblhog