Answer:
1/5
Step-by-step explanation:
To find the slope between two points, we use the formula
m = ( y2-y1)/(x2-x1)
= ( 6-4)/(4 - -6)
= ( 6-4)/(4+6)
= 2/10
= 1/5
Help will give brainist
Answer:
C
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
14. The function f(x)=√x+2-3 is moved 3 units left and 1 unit up. Which of
the following is the correct equation for the new function?
The equation of the function is g(x) = √(x + 5) - 2
How to determine the equation of the functionFrom the question, we have the following parameters that can be used in our computation:
f(x)=√(x + 2) - 3
The transformation is given as:
3 units left and 1 unit up
This is represented as
(x + 3, y + 1)
Substitute the known values in the above equation, so, we have the following representation
g(x) = √(x + 2 + 3) - 3 + 1
Evaluate
g(x) = √(x + 5) - 2
Hence, the equation is g(x) = √(x + 5) - 2
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For the rotation 588^{\circ}588 ∘ , find the coterminal angle from 0^{\circ}\leq\theta<360^{\circ}0 ∘ ≤θ<360 ∘ , the quadrant, and the reference angle.
The coterminal angle is 330°, which lies in Quadrant fourth, with a reference angle of 258 degrees.
We have 588 ° between 0° ≤θ<360
Coterminal angle in [0, 360°) range is 330°, located in the fourth quadrant.
Then for the reference angle will be
588 -330= 258
Thus, the reference angle is 258°
Therefore, we can conclude that coterminal angle is 330°, which lies in Quadrant fourth, with a reference angle of 258 degrees.
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how many variables are in the following expression 3x+4y+z
Answer:
3
Step-by-step explanation:
Answer: 3
Step-by-step explanation:
X,Y,Z
Kerrville, Kerrville Municipal Airport/Louis Schreiner Field (KERV) During the 24 hour period between 4pm on 12/26/2015 and ending at 4pm∗1 point on 12/27/2015, Dew Point Temperature Did not Change much during the period. Changed Substantially during the period. Between 00:00 (12am) and 6:00 (6am) on 12/27/2020, Dew Point * 1 point Temperature Reamined the Same Decreased Substantially Increased Substantially Based on what we know about dew point, we can safely say that water * 1 point vapor content: Didn't Change Much between 12am and 6 am Decreased Substantially between 12am and 6am Increased Substantially between 12am and 6am During the same 6 hour period, Air Temperature * 1 point Remained the Same Increased Decreased Based on what we know, we can safely say that Water Vapor Capacity: * 1 point Did not change much between 12 am and 6 am Increased between 12 am and 6 am Decreased between 12am and 6am The biggest change in temperature and dew point happened: * 1 point Between 2:55am and 3:15am Between 2:15am and 2:35am Between 3:15 am and 3:35 am In the same period you mentioned above, Relative Humidity * 1 point Increased substantially (a change of over 20% ) Decreased substantially (a change of over 20% ) Didn't really change much (a change less than 20% ) During the 6 hour period from 12am to 6 am, How did Relative Humidity * 1 point Change with Temperature? Relative Humidity Increased slighty when Temperature Decreased Relative Humidity Increased slightly when Temperature Increased Relative Humidity didn't change with Temperature at all However, during that same 6 hour period: * 1 point Relative Humidity Increased even when Dew Point Temperature Decreased Relative Humidity Also Decreased when Dew Point Temperature Decreased Based on the information above, what mainly affected Relative Humidity * 1 point during the entire 24 hour period? (Hint: Even though water vapor content had a huge drop, did Relative Humidity see the same drop?) Water Vapor Content (Dew Point) Had a Substantial Impact Water Vapor Capacity (Temperature) Had a Substantial Impact Both Content and Capacity Had a Substantial Impact on Relative Humidity during this period.
During the 24-hour period between 4pm on 12/26/2015 and 4pm on 12/27/2015, the dew point temperature changed substantially. The water vapor content and relative humidity were also affected by this change.
Based on the information provided, it is indicated that the dew point temperature changed substantially during the 24-hour period. The dew point temperature is the temperature at which air becomes saturated, causing water vapor to condense into dew or fog. A substantial change in the dew point temperature suggests a significant shift in the moisture content of the air.
As a result, the water vapor content and relative humidity are also affected. Water vapor content refers to the amount of water vapor present in the air, while relative humidity measures the percentage of moisture in the air compared to its maximum capacity at a given temperature. When the dew point temperature changes substantially, it implies that the air's capacity to hold water vapor has also changed, thus influencing the relative humidity.
Therefore, the main conclusion is that the change in the dew point temperature had a substantial impact on both the water vapor content and the relative humidity during the entire 24-hour period.
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2. What function types can be multiplied together to build a
new function of degree 5? How many total zeros will the
function have? How many can be imaginary?
Answer:
To get a function of degree 5, either functions of degree 1 and 4 or functions of degree 2 and 3 should be multiplied.
This function will have a total of 5 zeros, same as its degree.
The function of degree 5 will have at least one and up to five real zeros
The rest of the zero's are imaginary.
So if has 2 real zeros, then the remaining 3 will be imaginary.
Maximum number of imaginary zero's is 4.
The distance between City A and City B is 200 miles. A length of 1.5 feet represents this distance on a certain wall map. City C and City D are 3.5 feet apart on this map. What is the actual distance between City C and City D?
The actual distance between City C and City D is 466.67 miles.Therefore, the actual distance between City C and City D is 466.67 miles.
To find the actual distance between City C and City D, we can use the scale on the map. We know that 1.5 feet represents 200 miles, so we can set up a proportion:
1.5 feet : 200 miles = 3.5 feet : x miles
Cross-multiplying, we get:
1.5 feet * x miles = 3.5 feet * 200 miles
Simplifying, we get:
x miles = (3.5 feet * 200 miles) / 1.5 feet
x miles = 466.67 miles
Therefore, the actual distance between City C and City D is 466.67 miles.
Using the given information, we can set up a proportion to find the actual distance between City C and City D.
On the map:
1.5 feet represents 200 miles (between City A and City B)
Let x be the actual distance between City C and City D:
3.5 feet represents x miles
Now we can set up a proportion:
1.5 feet / 200 miles = 3.5 feet / x miles
Cross-multiply and solve for x:
1.5 * x = 3.5 * 200
1.5x = 700
Now divide by 1.5:
x = 700 / 1.5
x = 466.67 miles (approximately)
The actual distance between City C and City D is approximately 466.67 miles.
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PLEASEEE HELP I BEGGG
Answer:
B and then A
Step-by-step explanation:
volume is × so the . means times
so it's the only option
and then the second area is
6×3×4= 72cm³
If your dad picks your nose and he takes out two boogies and eats one boogy, how many boogies does he have left ;) btw ya'll should give me brainliest, just saying
Answer:
one
Step-by-step explanation:
For her softball uniform, Meredith has a green, white, or striped jersey. She also has white or green shorts. If Meredith chooses a
jersey and shorts randomly, what is the probability that she will go to softball practice in a striped jersey and green shorts?
1
5/6
1/5
1/6
Answer:
Mabey B) if someone else says other wise follow them.
The probability that she will go to softball practice in a striped jersey and green shorts is 1/6.
what is Probability?The ratio of good outcomes to all possible outcomes of an event is known as the probability. The number of positive results for an experiment with 'n' outcomes can be represented by the symbol x. The probability of an event can be calculated using the following formula.
Probability(Event) = Favorable Outcomes/Total Outcomes = x/n
Given:
Meredith has a green, white, or striped jersey.
So, probability that she will go to softball practice in a striped jersey and green shorts
= 1/3 x 1/3
= 1/6
Hence, probability that she will go to softball practice in a striped jersey and green shorts is 1/6.
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the population of a city can be modeled using the formula , where t is the number of years after and p is the city's population. which of the following equations can be used to find the number of years after that the population will triple to ?
The equation that can be used is the exponential growth equation p = p0 * e^(kt), where p0 is the initial population, e is Euler's number, k is the growth rate constant, and t is the number of years after.
In this case, we need to solve for t when p = 3p0. The given formula for modeling population growth, p = p0 * e^(kt), is an exponential growth equation. In this equation, p0 represents the initial population, e is Euler's number (approximately 2.71828), k is the growth rate constant, and t is the number of years after.
To find the number of years after which the population triples, we need to solve for t when p = 3p0. Substituting 3p0 for p in the equation, we get 3p0 = p0 * e^(kt). By canceling out p0 on both sides, we have 3 = e^(kt). To solve for t, we take the natural logarithm of both sides to eliminate the exponential term. Applying the natural logarithm to both sides gives us ln(3) = ln(e^(kt)). Since the natural logarithm and exponential functions are inverse operations, the exponential term simplifies to kt. Therefore, t = ln(3) / k.
By substituting the specific growth rate constant value, we can determine the exact number of years after which the population will triple.
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If f(x) is an exponential functionwhere f(-2) = 1 and f(7) = = 63,then find the value of f(1) , to thenearest hundredth.
An exponential function has the form
\(y=ab^x\)Therefore, to find an exponential function that satisfies our condition, we need to find a and b.
From f(-2) = 1, we have
\(1=ab^{-2}\: ^{}\: \: \: \: \; ^{}\: \: \: \: \; (1)\)and from f(7) = 63, we have
\(63=ab^7\: \: \: \: \; ^{}\: \: \: \: \; (2)\)Solving for a in equation (1) gives
\(a=b^2\)substituting this value of a into equation (2) gives
\(63=b^2\cdot b^7\)\(63=b^8\)\(\begin{gathered} \therefore b=\sqrt[8]{63} \\ b=1.6785 \end{gathered}\)With the value of b in hand, we now find the value of a:
\(\begin{gathered} a=b^2 \\ \therefore a=2.8173 \end{gathered}\)Hence, the exponential function is
\(f(x)=(2.8173)(1.6785)^x\)Evaluating the above function at x = 1 gives
\(\begin{gathered} f(1)=(2.8173)(1.6785)^1 \\ \boxed{\therefore f(1)=4.73.} \end{gathered}\)which is our answer!
Moussa is preheating his oven before using it to bake. The initial temperature of the
oven is 65° and the temperature will increase at a rate of 20° per minute after being
turned on. What is the temperature of the oven 15 minutes after being turned on?
What is the temperature of the oven t minutes after being turned on?
Temp after 15 minutes:
Temp after t minutes:
Answer:
365°, (65 +20t)°
Step-by-step explanation:
Temperature of oven
= initial temperature + 20°(number of minutes passed after it was turned on)
Temperature of oven after 15 minutes
= 65 +20(15)
= 65 +300
= 365°
Temperature after t minutes
= (65 +20t)°
how to solve problems with positive and negative numbers
Answer:
Step-by-step explanation:
When the signs of the two numbers are the same, the answer will be positive.
When the signs of the two numbers are different, the answer will be negative.
In each of Problems 1 through 10 find the general solution of the given differential equation. 1. y" – 2y' + y = 0 2. 9y" + 6y' + y = 0 3. 4y" – 4y' – 3y = 0) 4. 4y" + 12y' +9y = 0 5. y" – 2y' + 10y = 0) 6. y" – 6y' +9y = 0 7. 4y" + 17y' + 4y = 0 8. 16y" + 24y' +9y = 0 9. 25y" – 20y' + 4y = 0 10. 2y" + 2y' + y = 0
1) General solution for second order differential equation, y" – 2y' + y = 0, is y = (c₁x + c₂)eˣ .
2) General solution for differential equation, 9y" + 6y' + y = 0, is y =(c₁x + c₂)e⁻³ˣ.
3) General solution for differential equation, 4y"- 4y'- 3y = 0, is y = c₁ e⁶ˣ+ c₂e⁻⁴ˣ.
4) General solution for differential equation, 4y" + 12y' +9y = 0, is y = (c₁x + c₂)e⁻⁶ˣ.
5) General solution for differential equation, y" – 2y' + 10y = 0, is y = eˣ (c₁cos(6x) + c₂sin(6x)).
6) General solution for differential equation, y" – 6y' +9y = 0 is y = (c₁x + c₂)e³ˣ.
7) General solution for differential equation, 4y" + 17y' + 4y = 0, is y = c₁e⁻ˣ + c₂e⁻¹⁶ˣ.
8) General solution for differential equation, 16y" + 24y' +9y = 0, is y = (c₁x + c₂)e⁻¹²ˣ.
9) General solution for differential equation, 25y" – 20y' + 4y = 0, is y = (c₁x + c₂)e¹⁰ˣ.
10) General solution for differential equation, 2y" + 2y' + y = 0, is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)).
General solution is also called complete solution and complete solution = complemantory function + particular Solution
Here right hand side is zero so particular solution is equals to zero. Therefore, evaluating the complementary function will be sufficient to determine the general solution to the differential equation.
1) y"-2y' + y = 0, --(1)
put D = d/dx, so (D² - 2D + 1)y =0
Auxiliary equation for (1) can be written as, m² - 2m + 1 = 0 , a quadratic equation solving it by using quadratic formula,
\(m =\frac{-(- 2) ± \sqrt { 4 - 4}}{2}\)
=> m = 1 , 1
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)eˣ .
2) 9y" + 6y' + y = 0 or (9D² + 6D + 1)y =0 Auxiliary equation can be written as, 9m² + 6m + 1 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (6) ± \sqrt {36 - 4×4}}{2}\)
=> m = - 6/2
=> m = -3 , -3
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻³ˣ.
3) 4y"- 4y'- 3y = 0
put D = d/dx, so (4D² - 4D - 3)y = 0
Auxiliary equation can be written as, 4m² - 4m - 3 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{-(-4) ± \sqrt {16 - 4×4×(-3)}}{2}\)
=> m = (4 ± 8)/2
=> m = -4 , 6
The roots of equation are real and equal. So, general solution is y = c₁ e⁶ˣ + c₂e⁻⁴ˣ.
4) 4y" + 12y' +9y = 0 or (4D² + 12D + 9)y= 0
Auxiliary equation can be written as, 4m² + 12m + 9= 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{-(12) ± \sqrt{144 - 4×4×9}}{2}\)
=> m = -12/2
=> m = -6 , -6
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻⁶ˣ.
5) y" – 2y' + 10y = 0 or (D² - 2D + 10)y = 0 Auxiliary equation can be written as, m² - 2m + 10 = 0 , a quadratic equation
solving it by using quadratic formula,
\(m =\frac{ - (-2) ± \sqrt {4 - 4×1×10}}{2}\)
=> m = (2 ± 6i)/2 ( since, √-1 = i)
=> m = 1 + 6i , 1-6i
The roots of equation are imaginary and unequal. So, general solution is y =eˣ (c₁cos(6x) + c₂sin(6x)).
6) y" – 6y' +9y = 0 or (D²- 6D + 9)y =0
Auxiliary equation can be written as, m² - 6m + 9 = 0 , a quadratic equation
solving it by using quadratic formula,
\(m =\frac{ - (-6) ± \sqrt {36 - 4×1×9}}{2}\)
=> m = 6/2 = 3,3
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e³ˣ.
7) 4y" + 17y' + 4y = 0 or (4D²+ 17D + 4)y=0
Auxiliary equation can be written as, 4m² + 17m + 4 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{- (-17) ± \sqrt {16 - 4×4×17}}{2}\)
=> m = ( -17 ± 15)/2
=> m = (-17 + 15)/2, (- 17 - 15)/2= -1, -16
The roots of equation are real and unequal. So, general solution is y = c₁e⁻ˣ + c₂e⁻¹⁶ˣ.
8) 16y"+24y'+9y =0 or (16D²+ 24D + 9)y= 0
Auxiliary equation can be written as, 16m² + 24m + 9 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (24) ± \sqrt {576 - 4×9×16}}{2}\)
=> m = (-24 ± 0)/2
=> m = -12,-12
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e⁻¹²ˣ.
9) 25y"- 20y' +4y =0 or (25D²-20D + 4)y = 0
Auxiliary equation can be written as, 25m²- 20m + 4 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (-20) ± \sqrt {400 - 4×4×25}}{2}\)
=> m = 20/2
=> m = 10 , 10
The roots of equation are real and equal. So, general solution is y = (c₁x + c₂)e¹⁰ˣ.
10) 2y" + 2y' + y = 0 or (2D²+ 2D + 1)y =0
Auxiliary equation can be written as, 2m² + 2m + 1 = 0 , a quadratic equation solving it by using quadratic formula, \(m =\frac{ - (2) ± \sqrt {4 - 4×1×2}}{2}\)
=> m = (- 2 ± 4i)/2 ( since, √-1 = i)
=> m = -1 + 2i , -1 - 2i
The roots of equation are imaginary and unequal. So, general solution is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)). Hence, required solution of differential equation is y = e⁻ˣ (c₁cos(2x) + c₂sin(2x)).
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The volume of a cylinder is 117.1 cubic feet, and its height is 15 ft. Find the diameter of the base of the cylinder.
Answer:
3.15 ft
Step-by-step explanation:
V
Volume of a cylinder: πr²h. Solving for r², we get r² = ---------
πh
Here, we get r² = (117.1 ft³) / (3.14·15 ft) = 2.48 ft² and r = √(2.48 ft²), or
1.58 ft, so that the diameter is 2r, or 3.15 ft
The diameter of the base of the cylinder is 3.15 ft.
Let j=+5 - 5+ |-5 x 1/5
What is the value of+J?
Answer:
j=|x|
Step-by-step explanation:
What is the period of y = csc(x)?
1. Pi
2. 2pi
3. 3 pi
4. 4pi
Answer:
2pi
Step-by-step explanation:
Simplify the equation
3+7x-(2+9x)
3 + 7x - (2 + 9x )
3 + 7x - 2 -9x
1-2x
Answer:
1-2x
Step-by-step explanation:
3+7x-(2-9x)
(if there's a minus in front of parenthesis then you have to change the sign in the parenthesis)
3+7x-2-9x(take out from parenthesis)
1-2x(combine/simplify like terms)
Is -y/4 = 2x -5 linear
find the value of x pls help
Evaluate.
{4−[−2−(1+3)]}⋅(−6)
(answers)
−13
−32
−48
−60
Answer:
-60
Step-by-step explanation:
Evaluate:First do the operation in the inner most brackets.
{4 - [-2 - (1 + 3)] }*(-6) ={ 4 - [-2 - 4] } * (-6)
= { 4- [ -2 - 4] } * (-6)
= {4 - [-6] } * (-6)
= { 4 + 6} * (-6)
= 10 * (-6)
= -60
Classify the triangle as acute, right, or obtuse and classify it as equilateral, isoceles, or scalene.
A. obtuse, isosceles
B. acute, equilateral
C. obtuse, scalene
D. obtuse, equilateral
Answer:
C
Step-by-step explanation:
An obtuse triangle has ONLY one greater-than-180 angle measure, so this fact rules out B. An equilateral triangle has 3 exact same sides and an isosceles triangle has 2 equal side lengths. Since the "tally marks" is all different, this mean it's neither equilateral nor isosceles, so this fact also rules out A and D. Since a scalene triangle has no equal side length, and the only option available is C. SO THE FINAL ANSWER IS C
The given triangle is obtuse and scalene. Therefore, the correct answer is option C.
Isosceles triangles are those triangles that have at least two sides of equal measure and two base angles are equal.
In the triangle, all the sides are unequal and one of the angle measure greater than 90 degree.
The definition of an obtuse angle in geometry states that 'an angle whose measure is greater than 90° and less than 180° is called an obtuse angle.
So, it is obtuse angled triangle
If all the sides of triangle are unequal, then it is scalene triangle.
Therefore, the correct answer is option C.
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Work out the value of:
:
a? – 4b + 2c
2
when a = 1,b = -3 and c= 2
Answer:
The answer is 17
Step-by-step explanation:
Given;a² – 4b + 2ca = 1, b = (-3) and c = 2To Find;The value of a² – 4b + 2cNow, Evaluate
a² – 4b + 2c
(1)² – 4(-3) + 2(2)
1 + 12 + 4 = 17
Thus, The value is 17
-TheUnknownScientist 72
Lines AB and CD are parallel. If 6 measures (3x - 33)°, and 5 measures 123°, what is the value of x?
A.
x = 237
B.
x = 123
C.
x = 20
D.
x = 30
The value of x from the figure is 30 degrees
Parallel linesParallel lines are lines that have the same slope and have 0 degrees as the angle between them.
The sum of angle 5 and angle 6 are supplementary. Hence;
m<5 + m<6 = 180
3x - 33 + 123 = 180
3x + 90 = 180
3x = 180 - 90
3x = 90
Divide both sides by 3
3x/3 = 90/3
x = 30
Hence the value of x from the figure is 30 degrees
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Consider all the students attending the course Merged - DSAD-SEZG519/SSZG519 sitting in a room. Use the fwo algorithms mentioned beiow to find if anyone in the class has attended the same number of classes as you - Algorithm 1: You tell the number of classes you attended to the first person, and ask if they have attended the same number of classes; it they say no, you tell the number of classes you attended to the second person and ask whether they have attended the same number of classes. Repeat this process for all the people in the room. - Algorithm 2: You only ask the number of classes attended to person 1, who only asks to person 2, who only asks to person 3 and so on. ie You tell person 1 the number of classes you attended, and ask if they have attended the same number of classes; if they say no, you ask them to find out about person 2. Person 1 asks person 2 and tells you the answer. If it is not same, you ask person 1 to find out about person 3. Person 1 asks person 2, person 2 asks person 3 and so on. 1. In the worst case, how many questions will be asked for the above two algorithms? (2M) For each algorithm, mention whether it is constant, linear, or quadratic in the problem size in the worst case (1M)
Algorithm 1: Worst case - M questions, linear time complexity. Algorithm 2: Worst case - M questions, linear time complexity. Both algorithms have the same worst-case behavior and time complexity, as they require the same number of questions to be asked.
Algorithm 1: In the worst case, Algorithm 1 will ask a total of M questions, where M is the number of people in the room. This is because for each person, you ask them if they have attended the same number of classes as you. So, if there are M people in the room, you will need to ask M questions in the worst case. In terms of complexity, Algorithm 1 has a linear time complexity since the number of questions asked is directly proportional to the number of people in the room.
Algorithm 2: In the worst case, Algorithm 2 will also ask a total of M questions, where M is the number of people in the room. This is because you only ask the number of classes attended to person 1, who then asks person 2, and so on until person M. Each person asks only one question to the next person in line. So, if there are M people in the room, you will need to ask M questions in the worst case. In terms of complexity, Algorithm 2 also has a linear time complexity since the number of questions asked is directly proportional to the number of people in the room.
To summarize:
- Algorithm 1: Worst case - M questions, linear time complexity.
- Algorithm 2: Worst case - M questions, linear time complexity.
Both algorithms have the same worst-case behavior and time complexity, as they require the same number of questions to be asked.
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Gretta is 1 1/2 meters tall. Which of the following is equivalent to 1 1/2 meters?
the area is ___ square units
Answer:
392 square units
Step-by-step explanation:
We can make 2 right trapezoids out of this shape.
The area of a trapezoid would be 1/2×(b1+b2)×h or (b1+b2)×h ÷ 2.
If we do 1 half it would be 1/2×(14+14)×14 = 196
Now if we multiply by 2 (because we have 2 trapezoids) it would be 392.
Work out the volume of this cylinder. Give your answer rounded to the nearest whole number. 28mm 45mm
if radius is 45
V≈1.78×10^5
if radius is 28
V≈1.11×10^5
volume = pi times radius squared times height
if radius is 45
volume = pi times 45 squared times 28
Find the measure of the indicated arc
Answer:
m(WXY) = 224°
Step-by-step explanation:
<C is an inscribed angle.
Arc(WXY) is an intercepted arc whose end points are on <C.
Thus:
m(WXY) = 2(m<C)
Substitute
m(WXY) = 2(112°)
m(WXY) = 224°