What is the slope from (−4, 6) to (2, 2/3)

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here, d is the distance covered.

And t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

Here, t1 is the average time for the first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

v2 = d2/t2

v2 = 0.50 /t2

here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

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Answer:

21

Step-by-step explanation:

Since the girls have the same age, let their age be x.
Then, their average is

\(\frac{x+x}{2} = \frac{2x}{2} = x\)

Let \(S_{i}\) denote the age of 'i' girls.
Then, \(S_{8} = S_{6} + x + x - eq(1)\)

Also, we have,

\(\frac{S_{8}}{8} =15 - eq(2)\)

\(\frac{S_{6}}{6} =13 - eq(3)\)

Then eq(2):

(from eq(1) and eq(3))

\(\frac{S_{6} + 2x}{8} =15\\\\\frac{13*6 + 2x}{8} = 15\\\\78+2x = 120\\\\2x = 120-78\\\\x = 21\)

The average of the other two girls with equal age​ is 21

Step-by-step explanation:

x = number of years after 2007.

x = 0 for 2007.

PC(x) is a function that calculates how many pounds of chicken the average adult will eat every year (x) after 2007 (up to 2012).

PC(x) = 0.8x + 52

0 <= x <= 5

in 2007 (x = 0) the average adult ate 52 pounds.

in every year after 2007 until 2012 0.8 pounds get added to the amount of the previous year.

so, in 2012 (x = 5) the average adult will eat

PC(5) = 0.8×5 + 52 = 4 + 52 = 56 pounds of chicken.

Answer:

173x^2+107x+24

Step-by-step explanation:

9x-x^2+7x+8+10x-x^2+19x+8-x^2+26x+88x^2+10x+88x^2+26x+8

173x^2+107x+24

Floridyne would use an equivalent unit labor of 166,340 unit to calculate the cost per equivalent unit for direct labor.

Under weighted average, we do not make distinction between started and finished and just finished. Thus we work with finished and ending WIP only:

Finished         162,000

Ending - WIP    6,200 ending at 70% complete

Equivalent units for labor = Finished + Percentage of completion ending units

= 162,000 + 6,200 x 70%

= 166,340

Therefore, he would use an equivalent unit labor of 166,340 unit to calculate the cost per equivalent unit for direct labor.

Missing word "Floridyne, Inc. manufactures mouthwash. They had no finished goods inventory at the beginning of 2019. They have only one processing department for this product. A review of the company’s inventory records shows the following: At the beginning of January 2019, Floridyne has 4,500 gallons of mouthwash in process. (costs $8,410 for materials, 1,663 for labor and 4,990 for overhead) During 2019, Floridyne finishes/transfers 162,000 gallons of mouthwash. On December 31, 2019, Floridyne has 6,200 gallons of mouthwash that is 70% complete. Direct materials are added half at the beginning of the process and half after the process is 60% complete. During 2019 $349,000 of direct materials and $92,500 of direct labor were added. Using the weighted average approach to process costing,"

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Answer:

it is 3,3 or X<3 you can use either one

D is the answer

Step-by-step explanation:

Given:

Amy spent $90 at the store.

She spent \(\dfrac{1}{3}\) of her money on food, \(\dfrac{1}{6}\) of her money on school supplies, and \(\dfrac{1}{9}\) of her money on soda.

To find:

How much did she spend on school supplies?

Solution:

According to the given information, Amy spend \(\dfrac{1}{6}\) of her money on school supplies.

Amy spent $90 at the store. So,

Money spend on school supplies = \(\dfrac{1}{6}\times 90\)

                                                        = \(15\)

Therefore, Amy spend $15 on school supplies.

Square - a rectangle (4 sided shape) whose sides are equal length

Rectangle - a polygon that has 4 sides and 4 right angles - two pairs of parallel lines

Triangle: a polygon with 3 sides and 3 angles. The angles add up to a total of 180 degrees. There are 3 kinds of triangles

Parallelogram - a polygon with 4 sides, 2 pair of parallel lines, 2 obtuse angles and 2 acute angles.  

Trapezoid - a polygon with 4 sides and only 1 pair of parallel lines

Circle: a shape with no sides, angles, or parallel lines. Any point in the circumference to the center of the circle is the same length.

Happy to help!

Answer:

1). Triangle - Has 3 equal sides and angles of 60°.

2). Square - A quadrilateral with 4 equal sides and angles (all the angles are right angles).

3). Rectangle - A quadrilateral with 2 equal parallel sides horizontal and vertical. All the angles are equal because they are right angles.

4). Pentagon - It has 5 equal sides with equal angles of 108°.

5). Hexagon - It has 6 equal sides with equal angles of 120°.

PROPERTIES OF A CIRCLE:

It has no sides with no angles. The radius in any direction from the point are of the same length.

First, we plot the graph of the equation y=-4x+3, to do this, we only need two points

In green it is shaded the ponts that satisfy the inequality, that is because the y value must be below (that's why it has the sigh <) this graph.

Answer: 106

Step-by-step explanation: See attached images

Answer:

Karen asked for the manager

Step-by-step explanation:

Karen asked for the maneger because that is what karens do. you’re lucky that you are not black, becuase she would falsely accuse you of murder after slightly bumping into her on accident.

Answer:

You still need help? :P

Step-by-step explanation:

The expression  \(68^{1/3}\) can be written in the form of \(\sqrt[n]{}\)as  \(\sqrt[3]{68}\).

Whole numbers are defined as natural numbers plus zero (0). We are aware that the term "natural numbers" refers to a group of counting numbers beginning with 1, 2, 3, 4, and so forth. So the whole number is 0, 1, 2, 3 up to infinity.

Given:

\(68^{1/3}\)

Simplify as shown below,

\(a^{m/n} = \sqrt[n]{a^{m} }\)

Substitute the values,

\(68^{1/3} = \sqrt[3]{68^1}\) = \(\sqrt[3]{68}\)

Therefore, the expression \(68^{1/3}\) can be written in the form of \(\sqrt[n]{}\)as  \(\sqrt[3]{68}\).

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The cylindrical shell is subjected to an internal pressure of 70MPa. The shell's inner radius is 10 cm, and the outer radius is 16 cm. The maximum and minimum hoop stresses in the cylindrical shell are determined below.

For an element of thickness dr at a distance r from the center, the hoop stress is given by equation i:

σθ = pdθ...[i]Where, p is the internal pressure.

The thickness of the shell is drThe circumference of the shell is 2πr.

Therefore, the force acting on the element is given by:F = σθ(2πrdr)....[ii]

Let σmax be the maximum stress in the shell. The stress at radius r = a, which is at the maximum stress, is given by:σmax = pa/b....[iii]

Here a = radius of the shell, and b = thickness of the shell.

According to equation [i], the hoop stress at radius r = a is given by:σmax = pa/b....[iii].

Substitute the given values:σmax = 70 × 10^6 × (16 - 10)/(2 × 10) = 56 × 10^6 Pa.

The minimum hoop stress in the shell occurs at the inner surface of the shell. Let σmin be the minimum stress in the shell.σmin = pi/b....[iv].

According to equation [i], the hoop stress at radius r = b is given by:σmin = pi/b....[iv]Substitute the given values:

σmin = 70 × 10^6 × 10/(2 × 10) = 35 × 10^6 Pa.

Therefore, the maximum hoop stress in the shell is 56 × 10^6 Pa and the minimum hoop stress is 35 × 10^6 Pa.

A thick cylindrical shell with an inner radius of 10 cm and an outer radius of 16 cm is subjected to an internal pressure of 70MPa. Maximum and minimum hoop stresses in the cylindrical shell can be determined using equations and the given data. σθ = pdθ is the formula for hoop stress in the cylindrical shell.

This formula calculates the hoop stress for an element of thickness dr at a distance r from the center.

For the cylindrical shell in question, the force acting on the element is F = σθ(2πrdr).

Let σmax be the maximum stress in the shell. According to equation [iii], the stress at the radius r = a, which is the maximum stress, is σmax = pa/b.σmax is calculated by substituting the given values.

The maximum hoop stress in the shell is 56 × 10^6 Pa according to this equation.

Similarly, σmin = pi/b is the formula for minimum hoop stress in the shell, which occurs at the inner surface of the shell.

The minimum hoop stress is obtained by substituting the given values into equation [iv].

The minimum hoop stress in the shell is 35 × 10^6 Pa.As a result, the maximum and minimum hoop stresses in the cylindrical shell are 56 × 10^6 Pa and 35 × 10^6 Pa, respectively.

Thus, the maximum hoop stress in the shell is 56 × 10^6 Pa and the minimum hoop stress is 35 × 10^6 Pa. These results are obtained using equations and given data.

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The Alameda Corridor provides direct access from the railroad terminals into downtown Los Angeles and the ports of Los Angeles and Long Beach.

The Alameda Corridor is a transportation route that connects the railroad terminals near downtown Los Angeles to the ports of Los Angeles and Long Beach. It is a dedicated freight rail corridor designed to improve the flow of goods and reduce congestion in the region.

The corridor includes a 20-mile railroad trench, which allows trains to bypass road crossings, and it provides efficient access for the movement of cargo between the ports and the inland rail network. By connecting the railroad terminals directly to the ports, the Alameda Corridor plays a crucial role in facilitating the transportation of goods and supporting international trade.

The Alameda Corridor serves as a vital transportation link between the railroad terminals, downtown Los Angeles, and the ports of Los Angeles and Long Beach. It enhances the efficiency and capacity of freight transportation, supporting the movement of goods and contributing to the economic growth of the region.

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C: 41 is the missing value in the table

The minimum requirements for a class i aluminum main lightning conductor are a strand size, 95 pounds/1,000 feet weight per length, and a cross-sectional area of 98,600 circular mils.

These requirements are set by industry standards and regulations to ensure the safety and effectiveness of the lightning protection system. The strand size refers to the diameter of the individual wires that make up the conductor, which must meet a minimum size to withstand the forces of a lightning strike. The weight per length is a measure of the conductor's strength and durability, with a higher weight indicating a more robust design. Finally, the cross-sectional area is the total area of the conductor's circular shape, which impacts its ability to conduct electrical current and dissipate the energy from a lightning strike.

Overall, meeting these minimum requirements is essential for ensuring that a lightning protection system is capable of effectively capturing and directing the energy from a lightning strike to the ground, protecting the building and its occupants from potential harm.

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Answer:

i think it is b but I can be wrong

Answer:

Its B sorry if im wrong im 75% sure its b tho

Step-by-step explanation:

<3

Answer:

need the diagram

Step-by-step explanation:

The standard error formula for sample is the estimated standard deviation of the sampling distribution of a statistic.

It is used to measure the accuracy of a statistic, such as the mean, when it is based on a sample of data instead of a complete population. This formula is calculated by dividing the standard deviation of the sample by the square root of the sample size (n). The standard error helps to provide an idea of the precision of the statistic, or how close the sample mean is to the population mean.

In other words, the standard error formula can be used to measure the reliability of a statistic, such as the mean, based on a sample of data. The standard error formula provides an estimate of the standard deviation of a statistic based on a sample of data, and can be used to compare the reliability of different statistics. The standard error formula can also be used to measure the precision of a statistic, or how close the sample mean is to the population mean. Finally, the standard error formula can also be used to measure the accuracy of a statistic, or how close the sample mean is to the population mean.

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The standard error formula for sample is the estimated standard deviation of the sampling distribution of a statistic.

It is used to measure the accuracy of a statistic, such as the mean, when it is based on a sample of data instead of a complete population. This formula is calculated by dividing the standard deviation of the sample by the square root of the sample size (n). The standard error helps to provide an idea of the precision of the statistic, or how close the sample mean is to the population mean.In other words, the standard error formula can be used to measure the reliability of a statistic, such as the mean, based on a sample of data. The standard error formula provides an estimate of the standard deviation of a statistic based on a sample of data, and can be used to compare the reliability of different statistics. The standard error formula can also be used to measure the precision of a statistic, or how close the sample mean is to the population mean. Finally, the standard error formula can also be used to measure the accuracy of a statistic, or how close the sample mean is to the population mean.

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Answer:

a)2 * 2 = 4

b)2 * 3/2 = 3

c) 20 * 3/2 = 30

d) 100 * 8/5 = 160

e)473*1/100=4.73

f)111*1/100=1.11

Answer:

answers are written

Step-by-step explanation:

The standard deviation of x is 3 cars. So the option A is correct.

Suppose that x is the number of cars per minute that pass through a certain intersection, and that x has the Poisson distribution.

If the mean of x is equal to 9 cars, then we have to determine the standard deviation of x.

An indicator of how much variance from the mean there is is the standard deviation, which can be expressed as spread, dispersion, or spread. A "typical" departure from the mean is represented by the standard deviation. As a result of returning to the data set's original units of measure, it is a well-liked measure of variability.

The Mean = 9 cars

Standard Deviation = Square Root of Mean

Standard Deviation = √9

Standard Deviation = 3 cars

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Answer:

x is greater than or equal to 5

Step-by-step explanation:

Hope this helps! :))

Have a nice day<3

Answer:

497.8

Step-by-step explanation:

500-2.23=497.77=497.8

Answer:

hope it helps

Answer:

one 90 rotation

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Check the picture below.

so, since we know the height of the triangle and its base is simply a + b, then

\(\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=\stackrel{a}{9}+\stackrel{b}{3}\\ \qquad 12\\ h=3\sqrt{3} \end{cases}\implies A=\cfrac{1}{2}(12)(3\sqrt{3})\implies A=18\sqrt{3}\)

The surface area of that part of the plane 10x+7y+z=4 that lies inside the elliptic cylinder \(\frac{x^2}{25} +\frac{y^2}{9}\) is 15π√150 and this can be determined by using the given data.

We are given the two equations are:

10x + 7y + z = 4---------(1)

\(\frac{x^2}{25} +\frac{y^2}{9} =1-------------(2)\)

equation(1) is written as

z = 4 - 10x - 7y-----------(3)

The surface area is given by the equation:

A(S) = ∫∫√[(∂f/∂x)² + (∂f/∂y)² + 1]dA------------(4)

compare equation(4) with equation(3) we get the values of ∂f/∂x and

∂f/∂y

∂f/∂x = -10

∂f/∂y = -7

substitute these values in equation(4)

A(S) = ∫∫√[(-10)² + (-7)² + 1]dA

A(S) = ∫∫√[100 + 49 + 1]dA

A(S) = ∫∫√[150]dA

A(S) = √150 ∫∫dA

Where ∫∫dA is the elliptical cylinder

From the general form of an area enclosed by an ellipse with the formula;

comparing x²/a² + y²/b² = 1  with x²/25 + y²/9 = 1, from that we get the values of a and b

a = 5 and b = 3

So, the area of the elliptical cylinder = πab

Thus;

A(S) = √150 × π(5 × 3)

A(S) = 15π√150

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Therefore, the volume of liquid needed to fill a sphere of radius r to height h = r/3 is (92/81)πr^3.

To find the volume of liquid needed to fill a sphere of radius r to a height h = r/3, we first need to find the volume of the spherical cap that makes up the top portion of the sphere.

The volume of a spherical cap is given by the formula:

V = (1/3)πh^2(3r - h)

where h is the height of the spherical cap and r is the radius of the sphere.

Substituting h = r/3, we get:

V = (1/3)π(r/3)^2(3r - r/3)

= (1/3)π(r^2/9)(8r/3)

= (8/27)πr^3

This is the volume of the spherical cap that makes up the top portion of the sphere. To find the volume of liquid needed to fill the sphere to the given height h, we need to subtract this volume from the total volume of the sphere.

The total volume of the sphere is given by the formula:

V = (4/3)πr^3

Substituting the value of V for the spherical cap, we get:

V = (4/3)πr^3 - (8/27)πr^3

= (92/81)πr^3

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Answer:

1. blank is 23.1×10^9

2.blank is 2.31×10^3

3.blank is square meter

Answer:

1) 23.1×10^9

2) 2.31×10^3

3)square meter

Step-by-step explanation: