what is the shape of the path traversed by the earth around the sun?

Answer:

No. ... UV light causes sunburn, whereas visible light does not.

Explanation:

The light energy produced from a light bulb is far low compared to the light energy produced by the sun. The heat energy also greatly differ in both.

Light energy is a form of energy produced by stars and man made devices. One form of energy can be transformed into other form without destroying the energy.

The source of light and heat energy in stars is nuclear fusion. Fusing of two light nuclei forming a heavy nuclei accompanies the release of tremendous amount of energy.

In a light bulb, the electrical energy is converted to light energy and some energy is lost in the form of heat energy. The light the white light produced by a bulb cannot be as intense as the white lite from sun.

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Answer:

1000m

Explanation:

Distance = speed x time = 50x20 = 1000

Answer:

The answer is 1000m

Explanation:

Now,

D = 50m/s × 20s

D = 1000 m

Thus, The car travels 1000 m.

-TheUnknownScientist 72

There was more erosion taking place in 2004 than deposition.

In 2004, a major setback had taken place with regards to shoreline erosion and little of deposition. The cause? The Indian Ocean tsunami which struck multiple countries within the area leaving a trail of destruction and change behind.

Its fierce waves proved potent enough to erode beaches, dunes as well as cliffs, so much so that it consumed entire islands along its path. The outcomes were catastrophic on both ecological and societal fronts for those living in afflicted locales.

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The Milky Way and the Milky Way Galaxy are actually the same things. However, term-wise, the "Milky Way" is the band of diffuse light around (our) celestial sphere, why the Milky Way Galaxy is a spiral galaxy (that our solar system is in).

The Milky Way is a spiral-shaped galaxy that contains our Solar System, including the Earth and the Sun. It is one of the billions of galaxies in the observable universe and is home to an estimated 100 billion stars.

The term "Milky Way" is often used to refer to the band of light that we can see in the night sky, which is actually the combined light of billions of stars in our galaxy. However, the term "Milky Way Galaxy" is also used to refer to the entire galaxy itself. So, in short, there is no difference between the Milky Way and the Milky Way Galaxy; they are two terms used to refer to the same thing.

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The force on a current-carrying wire in a magnetic field is given by the formula:

F = BIL

where F is the force in Newtons, B is the magnetic field strength in Tesla, I is the current in Amperes, and L is the length of wire in the magnetic field in meters.

In this case, we know that the current is 20.0 A and the length of wire in the field is 5.00 cm (or 0.050 m), and the force is 2.25 N. We can rearrange the formula to solve for the magnetic field strength:

B = F/(IL)

Substituting the given values, we get:

B = 2.25 N / (20.0 A x 0.050 m) = 2.25 N / 0.0100 T = 225 T

Therefore, the average field strength between the poles of the magnet is 225 T. This value is extremely high and not typical for most practical magnetic fields.

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A) The electron is in the region of nonzero field for 3.5 × 10^-9 seconds.b) The kinetic energy of the electron is 6.44 × 10^5 eV.

a) The formula used to find the time taken by the electron in the region of the nonzero field is given by,t = L / v

where L is the distance travelled and v is the velocity of the electron.t = 2.1 × 10^-2 / (6.0 × 10^6)t = 3.5 × 10^-9 secondsb)

The formula used to find the kinetic energy of the electron is given by,K.E = 1/2 × m × v^2

where m is the mass of the electron and v is its velocity.

Here, we can use the value of v obtained in part (a).K.E = 1/2 × 9.11 × 10^-31 × (6.0 × 10^6)^2K.E = 1.03 × 10^-13 J

To convert this into eV, we divide by the charge of an electron, which is 1.6 × 10^-19 C.K.E = 1.03 × 10^-13 / 1.6 × 10^-19K.E = 6.44 × 10^5 eV

Answer: a) The electron is in the region of nonzero field for 3.5 × 10^-9 seconds.b) The kinetic energy of the electron is 6.44 × 10^5 eV.

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The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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No, the driver of the northward-moving vehicle was not within the speed limit when the collision occurred.

To determine whether the driver of the northward-moving vehicle was within the speed limit, we need to analyze the collision and the resulting skid marks.

Given that the skid marks left by the collided vehicles are parallel and at an angle of 55.0 degrees north of east, it indicates that the vehicles were not moving directly along the east or north direction. Instead, they were moving at an angle.

If the northward-moving vehicle was within the speed limit of 35 mi/h, its speed would not have been sufficient to result in skid marks at an angle of 55.0 degrees. The collision and the resulting skid marks indicate a significant impact and angular momentum, which would require a higher speed than the speed limit allowed.

Therefore, based on the skid marks and the collision angle, the driver of the northward-moving vehicle was likely exceeding the speed limit when the collision occurred, and his claim of being within the speed limit is not valid.

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Answer:

True

Explanation:

I just took the test and got 100

a. The utility function U(x, y) = x + 2.67y represents Thirsty Ed's utility based on the quantities of 0.15-liter and 0.4-liter containers consumed. Indifference curves can be plotted by fixing utility levels and identifying combinations of x and y that yield the same utility.

b. Ed's budget line, I = pxx + pyy, considers his income (I) and the prices of the 0.15-liter container (px) and the 0.4-liter container (py). The demand for x will be zero if px/py > 0.15/0.4, indicating the prices at which Ed will not purchase any 0.15-liter containers.

a. The utility function for Thirsty Ed can be expressed as U(x, y) = x + 2.67y, where x represents the quantity of 0.15-liter containers and y represents the quantity of 0.4-liter containers. This utility function assumes that Ed's utility depends only on the quantity of water consumed, and the containers themselves yield no utility.

To graph the indifference curves, we can choose different combinations of x and y that give the same level of utility. For example, if we fix U = 2, we can have the following combinations: (x, y) = (1, 0), (0, 2), (2, 0.25), etc. Plotting these points on a graph will give us the indifference curves.

b. Ed's budget line can be graphed by considering his income (I) and the prices of the 0.15-liter container (px) and the 0.4-liter container (py). The budget line equation is I = px*x + py*y.

To find the prices of px and py at which the demand for x is zero, we need to consider the slope of the budget line. If px/py > 0.15/0.4, then the demand for x will be zero. This means that as long as the price of the 0.15-liter container is higher than the price of the 0.4-liter container, Ed will not purchase any 0.15-liter containers.

To graph this, plot the budget line with different values of px and py, and observe the point where the budget line intersects the x-axis (x=0). This will give you the prices of px and py at which the demand for x is zero.

In another diagram, graph the case where px/py < 0.15/0.4 to show that Ed will only purchase 0.15-liter containers.

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Answer:

41.52 m

Explanation:

Using,

v = d/t....................... Equation 1

v = speed of pulse of sound, d = distance travelled by the pulse of sound, t = total time taken.

From equation 1, make d the subject of the equation

d = vt............................ Equation 2

Given: t = 0.12 s.

Constant: v = 346 m/s

Susbtitute these values into equation 2

d = 346(0.12)

d = 41.52 m

Answer:

When the flower vase drops, it is due to gravity.

The acceleration of the rock is approximately 8.8 m/s².

To find the acceleration of the rock, we need to consider the net force acting on it. In this case, the net force is the difference between the force of gravity and the force of air resistance.

The force of gravity acting on the rock can be calculated using the equation F = mg, where m is the mass of the rock (7 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²).

F_gravity = (7 kg) × (9.8 m/s²) = 68.6 N

The net force can be determined by subtracting the force of air resistance from the force of gravity: Net force = F_gravity - F_air resistance = 68.6 N - 7 N = 61.6 N

Finally, we can calculate the acceleration using Newton's second law, F = ma, where F is the net force and m is the mass of the rock: 61.6 N = (7 kg) × a

Solving for a, we find: a = 61.6 N / 7 kg ≈ 8.8 m/s²

Therefore, the acceleration of the rock is approximately 8.8 m/s².

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"at symbol"

The at sign, "at symbol", is normally read aloud as "at"; it is also commonly called the at symbol or commercial at. It is used as an accounting and invoice abbreviation meaning "at a rate of" (e.g. 7 widgets "at symbol" £2 per widget = £14), but it is now seen more widely in email addresses and social media platform handles.

The calculate the total distance traveled by a particle on [0, Ï], we need to find the absolute value of the area under the velocity curve. This is because distance is the magnitude of displacement, which can be negative or positive depending on the direction of motion, but the area under the curve represents the total magnitude of the motion.

The start by finding the antiderivative of the velocity function v(t) = -sin (t - Ï/4) ∫v(t) dt = ∫-sin (t - Ï/4) dt = cos (t - Ï/4) + C
Next, we the antiderivative at the bounds of integration cos(Ï) - cos (0 - Ï/4) = cos(Ï) - cos(Ï/4) Finally, we take the absolute value of the difference between the two evaluated antiderivatives to get the total distance traveled:
|cos(Ï) - cos(Ï/4) | This is the answer to the question, expressed in 200 words. The total distance traveled by a particle on [0, Ï], given that the velocity is v(t) = -sin (t - Ï/4), is |cos(Ï) - cos(Ï/4) |. We find the total distance traveled by taking the absolute value of the difference between the antiderivative of the velocity function evaluated at the bounds of integration. This approach works because distance is the magnitude of displacement, which can be negative or positive, but the area under the curve represents the total magnitude of the motion.

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Answer:

(a) 0 (b) \(F=1.67\times 10^9\ N\)

Explanation:

Given that,

Mass of a supertanker, \(m=1.7\times 10^8\ kg\)

The engine of a generate a forward thrust of, \(F=7.4\times 10^5\ N\)

(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :

F = ma, a is the acceleration

For constant velocity, a = 0

So, F = 0

(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.

F = mg

\(F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N\)

Hence, this is the required solution.

The magnitude of the vector displacement is 15.65 m.

The resultant force acting on the object is calculated as follows;

\(F = \sqrt{F_x^2 + F_y^2} \\\\F = \sqrt{4^2 + 6^2} \\\\F = 7.21 \ N\)

The displacement of the vector is calculated as follows;

W = Fs cosθ

\(s = \frac{W}{Fcos(\theta)} \\\\s = \frac{106}{7.12 \times cos(18)} \\\\s = 15.65 \ m\)

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Answer:

idk ha ha ha

Explanation:

Calculate the centripetal acceleration of the child. Centripetal acceleration is the acceleration that occurs when a body moves in a circular path and it is always directed towards the center.

We can use the formula for centripetal acceleration which is: a = v²/r where: a is the centripetal acceleration v is the velocity of the body r is the radius of the circular path In this problem, the child has a velocity of 1.3 m/s and is moving in a circular path with a radius of 1.2 m. Thus, the centripetal acceleration of the child can be calculated as: a = v²/r = (1.3 m/s)²/1.2 m = 1.41 m/s²Therefore, the centripetal acceleration of the child is 1.41 m/s².b) Calculate the net horizontal force exerted on the child (mass = 25.0 kg).The net horizontal force exerted on the child can be calculated using the formula: F = ma where: F is the net force acting on the body m is the mass of the body a is the acceleration of the body The child has a mass of 25.0 kg and is experiencing a centripetal acceleration of 1.41 m/s². Therefore, the net force exerted on the child can be calculated as: F = ma = (25.0 kg)(1.41 m/s²) = 35.3 N Therefore, the net horizontal force exerted on the child is 35.3 N. In the above problem, we were asked to calculate the centripetal acceleration of a child who is sitting on a merry-go-round and moves with a speed of 1.30 m/s. We were also asked to calculate the net horizontal force exerted on the child who has a mass of 25.0 kg. To solve this problem, we used the formula for centripetal acceleration and the formula for force. Using the formula for centripetal acceleration, we calculated that the child has a centripetal acceleration of 1.41 m/s². This means that the child is experiencing an acceleration that is directed towards the center of the merry-go-round and is responsible for keeping the child in a circular path.Using the formula for force, we calculated that the net horizontal force exerted on the child is 35.3 N. This means that there is a force acting on the child in the horizontal direction that is responsible for producing the centripetal acceleration.

In conclusion, the child on the merry-go-round has a centripetal acceleration of 1.41 m/s² and is experiencing a net horizontal force of 35.3 N. These calculations help us understand the forces acting on a body in circular motion.

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Answer:

I've heard of many different names of isotopes of carbon, and they're Carbon-14, Deuterium, Hydrogen-1, Oxygen-18, boron-11, Nitrogen-14, and Neon-20.

(a) The tangential distance travelled by the ladybug is 1.57 m.

(b) The tangential velocity of the ladybug is 0.785 m/s.

(c) The angular distance traveled by the ladybug after one revolution is  0.5π radians.

(d) The angular velocity of the ladybug is 3.14 rad/s.

The tangential distance travelled by the ladybug is calculated as follows;

d = 0.5 ( 2πr )

d = ( πr )

d = π x 0.5 m = 1.57 m

The tangential velocity of the ladybug is calculated as follows;

v = d / t

where;

v = ( 1.57 m ) / ( 2 s )

v = 0.785 m/s

The angular distance traveled after after one revolution is calculated as follows;

2πr = 1 rev

2π x ( 0.25) = 1 rev

1 rev = 0.5π radians

The angular velocity of the ladybug is calculated as follows;

v = ωr

ω = v/r

ω = 0.785 m/s / 0.25 m

ω = 3.14 rad/s

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Apply Boyle's law:

P1 V1 = P2 V2 =P3 V3 = P4 V4

(33.3)(100) = P4 ( 12.5 )

3330 = 12.5 P4

3330/12.5 = P4

P4 = 266.4 kPA

Answer:

A. 266.4 kPa

Jogku is a Korean sport similar to Volleyball and Football.

It is played between two teams, the objective is to return the ball to the opponent using only their feet or shin.

Displacement is the change of position of an object, it can be positive or negative depending on the starting point and the direction.

D= d2-d1

Where:

D= displacement

d2= final position

d1= initial position

The ball has displacement, and moves in 2 dimensions, both up and forward. influenced by gravity. This is called Projectile motion.

Displacement is used to determine the change of position of the ball.

Answer:

Q3) B Q4) D

Explanation:

I looked at the photo and they were circled. Hope this helps!!

Answer:

C. Probably not since that system deals mostly with mobility.

Explanation:

The temperature of the box and floor eventually rise as a result of the thermal energy flowing as heat inside these two things.

This is further explained below.

Generally, The energy present in a system that determines its temperature is referred to as thermal energy.

Thermal energy flows as heat. Thermodynamics is a whole field of physics that studies how heat is transmitted across various systems and how work is performed in the process (see the first law of thermodynamics).

In conclusion, This thermal energy is transferred in the form of heat throughout the box as well as the floor, which eventually results in an increase in temperature for both of these locations.

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Answer:

The length of the load arm is 3 m

The length of the effort arm is 15 m

Spoons and scissors are class 1 levers

Explanation:

The data given in the force diagram of the lever (machine) are;

The length of the lever = 18 m = (Length of effort arm) + (Length of load arm)

The force applied at the effort = 100 N

The load lifted by the lever = 500 N

The mechanical advantage, MA is given as follows;

MA = Load/Effort = (Length of effort arm)/(Length of load arm)

∴ MA = 500 N/(100 N) = 5

Let 'x' represent the length of the effort arm, and let 'y', represent the length of the load arm, we have;

x + y = 18...(1) (given)

MA = 5 = x/y

∴ x = 5·y...(2)

Substituting the value of 'x' in equation (1) with x = 5·y gives;

x + y = 5·y + y = 6·y = 18

∴ y = 18/6 = 3

y = 3

The length of the load arm, y = 3 m

x = 5·y = 5 × 3 = 15

x = 15

The length of the effort arm, x = 15 m

When lifting food with a spoon, the fulcrum, which can be taken as the edge of the plate or the supporting finger, is in between bowl of the spoon and the point of application of the thumb towards the extremities of the spoon handle

Therefore a spoon is a class 1 lever

The pivot of a scissors is in between the item being cut (the load) and the holes where the finger applies an effort

Therefore, a scissors is a class 1 lever.

Option C is the sequence which correctly represents the displacement of the string as the pulses interfere. When a wave pulse encounters a free end then it reflects the same way as incident path which is depicted in option C.

Longitudinal waves are waves in which the medium is moved in the same direction as the wave's propagation. The wavelength determines the separation between the centres of two adjacent compression or rarefaction areas.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an aeroplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.

The amount of medication needed to replace 1 gramme of suppository base is known as the displacement value. Coca Butter or Theobroma oil is the most used foundation for suppository preparation. Suppositories are traditionally made in suppositories moulds, which typically accommodate 1 or 2 grammes of base.

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Answer:

\(100\ \text{meters}\).

Explanation:

Distance Skylar traveled North is \(50\ \text{meters}\)

Then she traveled \(30\ \text{meters}\) Westward.

After which she traveled \(20\ \text{meters}\) towards the South.

The total distance traveled would be the sum of the distances.

\(50+30+20=100\ \text{meters}\)

The distance traveled by Skylar was is \(100\ \text{meters}\).