what is the same as 2/3

The Margin of error is 0.3 when assuming a 90% confidence level.

It is given that among 320 randomly selected airline travelers, the mean number of hours spent traveling per year is 24 hours and the standard deviation is 2.9.

It is required to find the margin of error when the confidence level is 90%.

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

\(\rm MOE= Z_{score}\times\frac{s}{\sqrt{n}}\)

Where  \(\rm Z_{score}\) is the z score at the confidence interval

             s is the standard deviation

             n is the number of samples.

We have in the question:

\(\rm Z_{score}\) at 90% confidence interval = 1.645 (From the Z score table)

s = 2.9

n = 320

Put the above values in the formula, we get:

\(\rm MOE= 1.645\times\frac{2.9}{\sqrt{320}}\)

MOE = 0.2666

Rounding the nearest tenth:

MOE = 0.3

Thus, The Margin of error is 0.3 when assuming a 90% confidence level.

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Answer:

0.3

Step-by-step explanation:

edg

Minkowski geometry is called a pseudo inner product space because it violates the positive definiteness axiom of an inner product space.

An inner product is a mathematical operation that takes two vectors and returns a scalar value. It satisfies some properties known as axioms. There are four axioms in an inner product space:

1. Linearity in the first argument

2. Conjugate symmetry

3. Positive definiteness

4. Linearity in the second argument

However, the Minkowski geometry, which is used to describe the geometry of spacetime in special relativity, is called a pseudo inner product space because it violates the positive definiteness axiom.

Positive definiteness axiom states that the inner product of a vector with itself is always greater than or equal to zero. In other words, the inner product of any non-zero vector with itself is always positive. However, in the Minkowski geometry, the inner product of a vector with itself can be negative or zero. This is because the Minkowski geometry involves a time component that can have a negative sign. Therefore, the Minkowski geometry violates the positive definiteness axiom of an inner product space.

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The correct proof that proves that BE ≅ CF is the proof in option C. (see attachment).

Recall the following:

The isosceles triangle ABC given is shown in the image attached below.

To prove that, BE ≅ CF, establish the fact that △ABE ≅ △ACF by the AAS Congruence Theorem.

Since △ABE ≅ △ACF, therefore BE ≅ CF by the CPCTC Theorem.

Thus, the correct proof that proves that BE ≅ CF is the proof in option C. (see attachment).

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The probability that the nurse will find the two patients is P =  0.49.

We know that the probability that the nurse finds the client on a particular day is 0.7

So, each time that the nurse goes that a home, that probability is the same and is independent of what happened before.

So if the nurse goes to two houses, the probability that she will find the client on the first home is 0.7

And the probability that she will find the client on the second home is 0.7

Then the joint probability (the product of the two individual ones) is:

P = 0.7*0.7 = 0.49

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Answer:

-1/6

Step-by-step explanation:

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The slope is -1/6

Step-by-step explanation:

We simply use the slope formula here

Mathematically, we have this as;

m = (y2-y1)/(x2-x1)

thus;

m = (10-8)/(-21 + 9) = 2/-12 = -1/6

The slope of a line that passes through the points (-9,8) and (-21,10) is -1/6

The slope of a linear graph is the rate of change of the graph

From the question, we have the following ordered pairs

(x,y) = (-9,8) and (-21,10)

So, the rate of change (m) is then calculated as:

\(m =\frac{y_2 -y_1}{x_2 -x_1}\)

This gives

\(m =\frac{10 - 8}{-21 + 9}\)

Evaluate the differences

\(m =\frac{2}{-12}\)

Evaluate the quotient

\(m =-\frac{1}{6}\)

Hence, the slope is -1/6

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As a fraction of c, the length will be 60% at v/c = 0.76

The length of the moving rod = 60%

Using the formula for length contraction-

L = L_o(√(1 - (v²/c²))

Where;

v = The speed of the object

c = The speed of light

L = The length of the object at a moving speed

L_o = The length of the object at rest

Thus,

L = 65%

L_o = 0.65

Substituting the values -

0.65L_o = L_o[√(1 - (v²/c²))]

Dividing both sides by L_o -

0.65 = √(1 - (v²/c²))

Squaring both sides -

0.65² = (1 - (v²/c²))

v²/c² = 1 - 0.65²

v²/c² = 0.5775

Taking the square root of both sides gives;

v/c = 0.76

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Answer:

1.24

Step-by-step explanation:

start by multiplying each term by the LCM which is 5

then you ahead and simply the equation

Answer:Hkgjhdhg5dtrjdieuy kytdckyrt etyj6487 78thg

Step-by-step explanation:Hkgjhdhg5dtrjdieuy kytdckyrt etyj6487 78thg

The distance between the planes after 20 minutes = 15496.8

What is Distance?

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

1st planes = 570mph at a bearing of s 62e plane

2nd planes = 525 mph at a bearing of n 18e plane

Coverting 20 minutes into hour = 0.3333 hours

speed of 1st plane = 570mph

Distance travelled by plane after 0.3333 hours= 570*0.3333 hours

= 189.981

speed of 2st plane = 525mph

Distance travelled by plane after 0.3333 hours= 525*0.3333 hours

= 174.982

Angle made by both plane between their is 62 + 18 = 80° ≅ 90°

Distance between both the planes

= \(\sqrt{(189.981)^{2} + (174.982)^{2} }\)

= \(\sqrt{36092.78 + 30618.700}\)

= \(\sqrt{66711.48}\)

= 258.28 hours

Converting hours into minutes

=15496.8

The distance between the planes after 20 minutes = 15496.8

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Answer:

is there a pic to go along? i need more to this..

Using the t-distribution, as we have the standard deviation for the sample, it is found that the test statistic is given by -4.47

What are the hypothesis tested?

At the null hypothesis, it is tested if they spend 7 hours a week answering their email, that is:

H₀ : μ = 7

At the alternative hypothesis, it is tested if they spend less than 7 hours, that is:

H₁ : μ < 7

What is the test statistic?

The test statistic is given by:

\(t = \frac{mean - null value}{\frac{\alpha }{\sqrt{n} } }\)

In this problem, the parameters are given as follows:

sample mean = 6. 02 sample size = 1264. standard deviation = 7.80

Hence, the test statistic is:

\(t = \frac{6.02-7}{\frac{7.80}{\sqrt{1264} } }\)

t = -4.466

t = -4.47

Therefore, the test statistic is  -4.47

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The correct population parameter for shop at this dealership that will purchase a Peterbilt truck is p that is option C.

In statistics, a population parameter characterises an individual or population. A population parameter describes the distribution of all values within a group and is a fixed but unknowable property. The parameters used in other sorts of maths should not be confused with this. These are the parameters of a mathematical function that never change. An indicator of the population is not a statistic. This information only applies to a portion of a certain demographic. You can determine the genuine population value with the aid of a well-designed research.

Statistics and parameters share many similarities. Both express a characteristic of the group, such as the fact that 20% of M&Ms are red. Yet, the fundamental distinction is in who and what they are describing. The entire population is referred to by parameters. The part or sample that was examined in a study is referred to as the statistic.

You might count the quantity of red M&Ms in the aforementioned example's various packs. Your statistic will be provided by this. If your study was well-designed, the statistic you obtain should precisely reflect the population parameter.

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Complete question:

A recent flyer claimed that 2 out of every 9 trucks sold at a local dealership are manufactured by Peterbilt. Find a 95% confidence interval for those who shop at this dealership that will purchase a Peterbilt truck. Identify the correct population parameter.

μ

х

р

p^

\(\mu_1 - \mu_2\)

Xi – X2

î

Pi – P2

The expected value of XA is 0.35, and the variance of XA is 0.2275.

To find the expected value of XA, we simply multiply the probability of A occurring (0.35) by 1 (the indicator variable when A occurs) and add the product of the probability of A not occurring (1 - 0.35 = 0.65) and 0 (the indicator variable when A does not occur). So, E(XA) = 0.35 * 1 + 0.65 * 0 = 0.35.

To find the variance of XA, we need to calculate the probability of each outcome (0 or 1) and its squared difference from the expected value. The variance formula for an indicator variable is Var(XA) = P(A)(1 - P(A)). Therefore, Var(XA) = 0.35 * (1 - 0.35) = 0.35 * 0.65 = 0.2275.

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Answer:

these teachers b expectin u to do this bs

Step-by-step explanation:

The congruency relationship which hold true after transformation is

YZ ≅ AB

What is congruent ?

In mathematics, the term "congruent" refers to figures and shapes that can be flipped or rearranged to match up with other ones. These forms can be mirrored to produce related shapes.

Explanation:

A translation is known as a rigid transformation.  This is because it preserves congruence.  Since CAB is created from XYZ, this tells us that:

X corresponds to C; Y corresponds to A; Z corresponds to B; XY corresponds to CA; YZ corresponds to AB; and XZ corresponds to CB.

Since the triangles are congruent, the corresponding pieces are congruent as well.

Out of these corresponding congruent pieces of triangles, the only one in our options is YZ ≅ AB.

Hence the answer is YZ≅AB.

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Answer:71

Step-by-step explanation:

the equation of the quadratic function that is moved to the left three, up four, and stretched by a scale factor of two is \(y = 2(x + 3)^2 + 4.\)

What is quadratic equation?

A quadratic equation is a type of polynomial equation of degree two, meaning it contains one or more terms that involve x raised to the power of two (i.e., x²

The equation of a quadratic function is generally given by:

\(y = a(x - h)^2 + k\)

where (h, k) is the vertex of the parabola and "a" determines the shape of the parabola.

To move the function to the left by three units, we need to replace "x" with "(x + 3)" inside the parentheses:

\(y = a(x + 3 - h)^2 + k\)

To move the function up by four units, we need to add four to the value of "k":

\(y = a(x + 3 - h)^2 + (k + 4)\)

To stretch the function by a scale factor of two, we need to multiply "a" by two:

\(y = 2a(x + 3 - h)^2 + 2(k + 4)\)

Combining these transformations, we get the final equation:

\(y = 2(x + 3 - 0)^2 + (0 + 4)\)

\(y = 2(x + 3)^2 + 4\)

Therefore, the equation of the quadratic function that is moved to the left three, up four, and stretched by a scale factor of two is \(y = 2(x + 3)^2 + 4.\)

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Answer:=

=(x^2+4x)+(7x+28)

=x(x+4)+7(x+4)

=(x+4)(x+7)

Step-by-step explanation:

Answer:

\((x+4) (x+7)\)

Step-by-step explanation:

Factor x^2 + 11x + 28 using the AC method.

Answer: 7

Step-by-step explanation:

10.5÷2\(\frac{2}{3}\)=7.875

So the answer is not 7.875, but 7 complete whole decorations.

Answer:

Step-by-step explanation:

Correct choice is C

Answer:

4

Step-by-step explanation:

Hence, there are 4 zeros for the square of 200.

Now the angle in the degree is,

The speed at which the distance between the ships is changing at 7 PM is 207.3 knots.

To find the speed at which the distance between the ships is changing, we can use the concept of relative velocity.

At noon, ship A is 40 nautical miles due west of ship B.

From then until 7 PM, a total of 7 hours have passed.

Ship A is sailing west at 17 knots, so it would have traveled a distance of 17 knots x 7 hours = 119 nautical miles westward.

Ship B is sailing north at 19 knots, so it would have traveled a distance of 19 knots x 7 hours = 133 nautical miles northward.

Using the Pythagorean theorem, the distance between the two ships at 7 PM can be calculated as follows:

Distance = √((40 + 119)² + (133)²)

= √(159² + 133²)

= √(25281 + 17689)

= √42970

= 207.3 nautical miles

Therefore, the speed at which the distance between the ships is changing at 7 PM is 207.3 knots.

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The distance between the ships is changing at a rate of 552 knots at 7 PM. At 7 PM, ship A will have been sailing west for 7 hours, covering a distance of 7 x 17 = 119 nautical miles. Similarly, ship B will have been sailing north for 7 hours, covering a distance of 7 x 19 = 133 nautical miles.

To find the distance between the ships at 7 PM, we can use the Pythagorean theorem. Let's call the distance between the ships at noon D.

Using the Pythagorean theorem, we have:
\(D^2 = (40 + 119)^2 + (133)^2\)

Simplifying, we get:
\(D^2 = 159^2 + 133^2\)

Calculating, we find:
D ≈ 204 nautical miles

Now, we need to find how fast the distance between the ships is changing at 7 PM. To do this, we differentiate the equation for D with respect to time t:

\(\frac{dD}{dt} = 2(40 + 119)(17) + 2(133)(0) = 552\; knots\)

Therefore, the distance between the ships is changing at a rate of 552 knots at 7 PM.

In conclusion, the distance between the ships is changing at a rate of 552 knots at 7 PM.

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Answer:

\(\displaystyle m\angle RTU=73^\circ\)

Step-by-step explanation:

Interior Angle of a Circle

An interior angle of a circle is formed at the intersection of two lines that intersect inside a circle.

Lines AC and BD of the figure attached below intersect forming arcs p and q. The measure of the interior angle x  is:

\(\displaystyle x=\frac{p+q}{2}\)

The question includes the drawing of a circle with lines US and RV intersecting at point T. The measure of the interior angle RTU is:

\(\displaystyle m\angle RTU=\frac{68^\circ+78^\circ}{2}\)

\(\displaystyle m\angle RTU=\frac{146^\circ}{2}\)

\(\boxed{\displaystyle m\angle RTU=73^\circ}\)

Answer:

I got \(27\sqrt{3}\) which is 46.76537.... in decimal form.

Step-by-step explanation:

The size of angle ACB in triangle ABC is approximately 35.5 degrees.

To calculate the size of angle ACB, we can use the Law of Cosines, which states that in any triangle, the square of one side is equal to the sum of the squares of the other two sides minus twice the product of those sides and the cosine of the included angle.

The formula for the Law of Cosines is:

c^2 = a^2 + b^2 - 2ab * cos(C)

Where:

c is the side opposite to angle C (in this case, side AB with length 7cm)

a and b are the other two sides (in this case, sides AC and BC with lengths 6cm and 8cm, respectively)

C is the angle we want to find (angle ACB)

Plugging in the given values, we have:

7^2 = 6^2 + 8^2 - 2 * 6 * 8 * cos(C)

Simplifying the equation, we get:

49 = 36 + 64 - 96 * cos(C)

49 = 100 - 96 * cos(C)

96 * cos(C) = 100 - 49

96 * cos(C) = 51

cos(C) = 51 / 96

To find the angle ACB, we need to take the inverse cosine (also known as arccos) of the value we just calculated:

C = arccos(51 / 96)

Using a calculator, we find that C is approximately 35.5 degrees.

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Answer:

1. 10

2. 12

Step-by-step explanation:

1. 8² + 6² = y² (Taking the unknown side as y)

64 + 36 = 100

y² = 100

y = 10

2. 5² + x² = 13² (Taking the unknown side as x)

x² = 13² - 5²

= 169 - 25

= 144

x² = 144

x = 12

System of equations that models the situation is Option C . 2x+3y = 7.20 , 4x+3y = 8.80 and the price per pound for oranges is $1.40.

Given:

Part A

Steve buys 2 lb of grapefruit and 3 lb of oranges for $7.20. Kennedy buys 4 lb of grapefruit and 2 lb of oranges for $8.80.

Let x represent the price per pound for grapefruit, and let y represent the price per pound for oranges.

2x + 3y = 7.20

4x + 2y = 8.80

Part B

on solving two equations:

2x + 3y = 7.20 and 4x + 2y = 8.80

2(2x + 3y) - 4x - 2y = 2*7.20 - 8.80

4x + 6y - 4x - 2y = 14.40 - 8.80

4y = 5.60

y = 5.60/4

= $1.40

hence price of oranges per pound is $1.40.

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The critical t-value for a one-mean t-test at the 5% significance level with a sample size of 28 can be denoted as \(\[t_{0.05, 27}\]\).

To determine the critical value or values for a one-mean t-test at the 5% significance level for a right-tailed test (Ha: μ > μ0) with a sample size of 28, we need to find the t-value corresponding to the desired significance level and degrees of freedom.

For a right-tailed test at the 5% significance level, we want to find the t-value that leaves 5% of the area in the right tail of the t-distribution. Since the test is one-mean and we have a sample size of 28, the degrees of freedom (df) will be 28 - 1 = 27.

The critical t-value for a right-tailed t-test at the 5% significance level can be denoted as follows:

\(\[t_{\alpha, \text{df}}\]\)

where \(\(\alpha\)\) represents the significance level and \(\(\text{df}\)\) represents the degrees of freedom.

In this case, the critical t-value for a one-mean t-test at the 5% significance level with a sample size of 28 can be denoted as:

\(\[t_{0.05, 27}\]\)

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The probability P(n < 10 | n is prime) is 4/6, which simplifies to 2/3 or approximately 0.67 (rounded to the nearest hundredth).

To find the probability P(n < 10 | n is prime), we need to determine the number of prime integers less than 10 and divide it by the total number of integers from 1 to 15 that are prime.

The prime numbers less than 10 are 2, 3, 5, and 7. So, there are 4 prime numbers less than 10.

The total number of integers from 1 to 15 that are prime is 6 (2, 3, 5, 7, 11, and 13).

As a result, the chance P(n 10 | n is prime) is 4/6, which can be expressed as 2/3 or, rounded to the nearest hundredth, as around 0.67.

Thus, 0.67 is the answer.

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