How can we show that air can do work?
Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.
Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.
To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.
The work done by the air can be calculated using the equation:
Work = Force * Distance * cos(θ)
Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.
In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:
Work = Force * Distance * 0
Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.
However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.
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On vacation, your 1400-kg car pulls a 560-kg trailer away from a stoplight with an acceleration of 2.00 m/s2 You may want to review (Pages 130 - 133). Part A What is the net force exerted by the car on the trailer? Assume that the positive x axis is directed toward the direction of motion. V AEO ... ? F = 2800 N Part B What force does the trailer exert on the car? Assume that the positive x axis is directed toward the direction of motion. Vo AEO ? F = N Part C What is the net force acting on the car? Assume that the positive x axis is directed toward the direction of motion. VOI AED ? F = N
a) The force of the car on the trailer is 2800 N
b) The force of the trailer on the car is 2800 N
c) The net force of the car 1120 N
What is the force on the car?We know that the force is the product of the mass and the acceleration of the object. Now we know that all we need to obtain the force is just to multiply the given mass of the object with the acceleration of the object.
a) Now, we have to consider the question that we have here. We are to find the net force that the car is going to exert on the trailer and this is just the product of the mass of the car and its acceleration since it is connected to the trailer by a rope and we would get that as;
F= 1400-kg * 2.00 m/s2 = 2800 N
b) The force that is exerted by the car on the trailer has the same magnitude as the force that the trailer exerts on the car because this is the tension on the cable that connects then and this force is 2800 N.
c) The net force on the car would be obtained from; 560-kg * 2.00 m/s2 = 1120 N
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What produces the magnetic field of an electromagnet?
An electromagnet is a magnet whose magnetic field is created when electricity is flowing.
What is an electromagnet?A device consisting of an iron or steel core that is magnetized by electric current in a coil that surrounds it.
What is magnetic field?Magnetic force is defined as the space surrounding a magnet in which magnetic force is exerted.
What is electricity?A form of energy created by charged or moving electrons or protons.
What does it mean when electricity is flowing?The movement of energy is called a flow. The flow of electricity through a wire can be thought of as being similar to the flow of water through a pipe. Electricity usually flows in specially protected wires, but it can also move around using many other objects.
How does a magnetic field and the flow of electricity relate?The electromagnetic force produces two related phenomena: electricity and magnetism. They combine to generate electromagnetism. A magnetic field is created by a moving electric charge. Electric charge movement is induced by a magnetic field, resulting in an electric current.
What produces a magnetic field?Electric charges in motion. Charged particles in motion have both an electric field and magnetic field associated with them.
How does an electromagnet work?An electric current flows through a coil of wire. This produces a magnetic field in the wire. The sides of the coil that carry current at 90 degrees to the magnetic field experience a force as they interact with the magnetic field.
A rifle is fired straight up, and the bullet leaves the rifle with an initial velocity
magnitude of 630 m/s. After 5.00 s, the velocity is 581 m/s. At what rate is the bullet
decelerated?
Explanation:
acceleration definition = change in velocity / change in time =
(630 - 581) m/s / 5 s = 49 / 5 = 9.8 m/s^2 was the deceleration
A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse
The amount of work done per second by the horse exerting a force of 1800 N on a wagon moving with a speed of 0.4 m/s is 720 J/s.
What is power?Power is the work done by a body in one second.
To calculate the work done by the horse in one seconds, we use the formula below
Formula:
P = Fv................ Equation 1Where:
P = work done on the horse in one secondF = Force of the horsev = Velocity of the wagonFrom the question,
Given:
F = 1800 Nv = 0.4 m/sSubstitute these values into equation 1
P = 1800×0.4P = 720 J/sHence, the amount of work done per second by the horse is 720 J/s.
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Complete question: A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse per second.
A driver loses control of a car, drives off an embankment, and lands in a canyon 6.0 m below. What was the car's speed just before touching the ground if it was traveling on the level surface at 12 m/s before the driver lost control?
Hi there!
The horizontal component of the car's velocity (12 m/s) remains CONSTANT in the absence of air resistance.
Its vertical component of its velocity is being affected by gravity. We can use the kinematic equation:
\(v_f^2 = v_i^2 + 2ad\)
vf = final velocity (? m/s)
vi = initial velocity (0 m/s)
a = acceleration due to gravity (9.8 m/s²)
d = displacement (6m)
Plug in the given values:
\(v_f^2 = 0 + 2(9.8)(6)\\\\v_f = 10.844 m/s \text{ downward}\)
The speed is derived by using the pythagorean theorem as the above are simply the COMPONENTS of the total speed.
\(Speed = \sqrt{v_x^2 + v_y^2}\\\\s = \sqrt{12^2+10.844^2} = \boxed{16.174 m/s}\)
A wheel 30 cm in diameter accelerates uniformly from 245 rpm to 380 rpm in 6.1 s . Part A How far will a point on the edge of the wheel have traveled in this time
Answer:
A point on the edge of the wheel will travel 199.563 radians at the given time.
Explanation:
Given;
initial angular velocity of the wheel; \(\omega _i = 245 \ rev/\min = 245\ \frac{rev}{\min} \times \frac{2\pi}{1\ rev} \times \frac{1 \ \min}{60 \ s} = 25.66 \ rad/s\)
final angular velocity of the wheel;
\(\omega _f = 380 \ rev/\min = 380 \ \frac{rev}{\min} \times \frac{2\pi}{1\ rev} \times \frac{1 \ \min}{60 \ s} = 39.80 \ rad/s\)
radius of the wheel, d/2 = (30 cm ) / 2 = 15 cm = 0.15 m
time of motion, t = 6.1 s
The angular distance traveled by the edge of the wheel is calculated as;
\(\theta = (\frac{\omega_f + \omega_i}{2} )t\\\\\theta = (\frac{39.8 + 25.66}{2} )\times 6.1\\\\\theta = 199.653 \ radian\)
Therefore, a point on the edge of the wheel will travel 199.563 radians at the given time.
The radius of the circular path of an ion in a mass spectrometer is given by r=1/B √2Vaccelm/q. Use this equation to explain how a mass spectrometer is able to separate ions of different masses.
The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path
What is the mass spectrometer?From the formula in the question;
B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.
The accelerating voltage used to move the ions is called Vaccelm.
The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.
The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.
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A tourist, who weighs 705 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops on the bridge. Assume that the board of the bridge has negligible weight. Where is he standing if the magnitude of the vertical force that a concrete support exerts on the bridge at the near end is 470 N?
а)one-fifth of the way along the bridge b)one-fourth of the way along the bridge c)one-third of the way along the bridge d)one-half of the way along the bridge f)one-sixth of the way along the bridge
The tourist is standing one-third of the way along the bridge (option c).
How to solveLet's denote the distance from the near end of the bridge to the point where the tourist is standing as x and the total length of the bridge as L.
According to the equilibrium condition, the sum of the forces exerted on the bridge is zero.
So, the vertical forces exerted by the two concrete supports should be equal to the weight of the tourist:
F_near + F_far = 705 N
Given that the magnitude of the vertical force exerted by the near end support is 470 N, we can calculate the force exerted by the far end support:
F_far = 705 N - 470 N = 235 N
Now, we can use the moment equilibrium condition, considering moments around the near end support:
Moment = Force × Distance
For the tourist:
Moment_tourist = 705 N × x
For the far end support:
Moment_far = 235 N × L
For equilibrium, the sum of the moments should be zero:
Moment_tourist - Moment_far = 0
Substituting the moments:
705 N × x - 235 N × L = 0
Now, we can solve for x/L, which represents the fraction of the way along the bridge where the tourist is standing:
x/L = (235 N × L) / 705 N
x/L = 235/705 = 47/141 ≈ 1/3
So, the tourist is standing one-third of the way along the bridge (option c).
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please help meee please please
Answer:
I think it's c but don't know for sure
An elevator filled with passengers has a mass of 1700 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 for 1.50 s. Calculate the tension in the cable supporting the elevator. (b) The elevator continues upward at constant velocity for 8.50 s. What is the tension in the cable during this time
Explanation:
mass m=1700 Kg
a = 1.20 m/s^2.
t_a= 1.50 sec
According to Newton's 2nd law the net force
\(F_{net} =ma\)
\(F_a=m(a+g)=1700(1.2+9.80)=1.87\times10^4 N\)
now,
\(F_{net} =0\\F_b= W =1700\times9.8 =1.67\times10^4 N\)
the variable resistor r in the circuit of fig. 11.50 is adjusted until it absorbs the maximum average power. find r and the maximum average power absorbed.
The load impedance ZL must be equal to the complex conjugate of the Thevenin impedance ZTh for maximum average power transfer. This indicates that the load impedance (or resistance) must be equal to the magnitude of the Thevenin impedance for the highest average power transfer to a fully resistive load.
How is the average amount of energy absorbed determined?
As a result, the total power used by a circuit over the course of one full cycle is the sum of the power saved and the power returned.
How do you calculate average power?
The formula for average power in mathematics is: Average power = Total energy consumed Average amount of time spent P = W t.
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what is the velocity of a 0.145kg baseball if its kinetic energy is 109 j
Answer:
The velocity of the 0.145 kg baseball is 38.7743 m/s.
General Formulas and Concepts:
Energy
Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)
m is mass (in kg)v is velocity (in m/s)KE is kinetic energy (in J)Explanation:
Step 1: Define
Identify.
m = 0.145 kg
KE = 109 J
Step 2: Solve for v
Substitute in variables [Kinetic Energy Formula]: \(\displaystyle 109 \ \text{J} = \frac{1}{2}(0.145 \ \text{kg})v^2\)Simplify: \(\displaystyle 109 \ \text{J} = (0.0725 \ \text{kg})v^2\)Isolate variable term: \(\displaystyle 1503.45 \ \text{J/kg} = v^2\)Isolate v: \(\displaystyle v = 38.7743 \ \text{m/s}\)Topic: AP Physics 1/C
Unit: Energy
An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
motionless (gravity force equalling electrostatic force) when the electric field is set to 370 N/C and directed
downward.
a) Determine the sign and magnitude of the charge on the oil droplet.
b) Determine the approximate number of excess electrons that are on the oil droplet.
Answer:
The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.
F = N e E where E is the value of the field and N e the charge Q
M g = N e E and M g is the weight of the drop
N = M g / (e E)
N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13
.00011 kg is a very large drop
Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs
Check: N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13 electrons
What exercises can help reduce stress?
During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of 26.0 kg and its horizontal component of velocity is 8.50 m/s just before the 65.0 kg performer catches it. If the performer is initially motionless on nearly frictionless roller skates, what is his speed immediately after catching the cannon ball
Answer:
the velocity of the elderly performer after catching the cannon ball is 3.4 m/s.
Explanation:
mass of the cannon ball, m₁ = 26 kg
initial velocity of the cannon ball, u₁ = 8.5 m/s
mass of the elderly performer, m₂ = 65 kg
Let the velocity of the elderly performer after catching the cannon ball = u₂
Apply the principle of conservation of linear momentum to determine the velocity of the elderly performer after catching the cannon ball.
m₁u₁ = m₂u₂
\(u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{26 \times 8.5}{65} \\\\u_2 = 3.4 \ m/s\)
Therefore, the velocity of the elderly performer after catching the cannon ball is 3.4 m/s.
A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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pressure problem solving..
We know that Formula to calculate Pressure is Pressure = Force/Area.
It is given that the Water jet exerts a pressure of 20 Mega Pascal on an area of 5m². We convert 20 Mega pascal to Pascal => 20 * 1000000 So, we get Pressure P = 20000000 Pascals, Area = 5 m² Putting values we get Force = P * A => Force = 20000000 * 5
=> Force = 100000000 N
Status weighs 2400 N and base area is 500 cm². Converting the base area from cm² to m², we get Area a = 0.05 m², Force F = 2400 N. Putting values we get Pressure = 2400 * 0.05=> Pressure = 48000 Pascal
It is given that the base area of an object = 3 cm² and the pressure exerted will be 21 Pa. Firstly, We will convert the area from cm² to m² and we get Area a = 0.0003 m², and P = 21 Pa. Putting values in equation we get Force/ Weight of object => F = P*A => F = 21 * 0.0003=> F = 0.0063 N
It is given that the lady weighs 50 kN so, Force F = 50 kN. We will convert force from kN to N => F = 50 * 1000 => F = 50000 N. And, the surface area of heels is 0.0001 m². Putting values in equation, We get : Pressure = F/A => P = 50000/0.0001=> P = 500000000 Pa
It is given that the pressure box exerts on the ground is 20 kPa. The weight of the box is 400 N. First, we will convert pressure from kPa to Pa. Pressure = 20 * 1000 => P = 20000 Pa and Force F = 400 N. Putting these values in equation we get Area = F/P =>Area = 400/20000 => Area = 0.02 m²
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Explain why a lorry loaded with bags of maize packed high up is likely to topple when negotiating a corner.
Answer:
Due to its centre of mass being too high and because of that it is at a high risk of toppling at the corner
a anormal human eye has a focal length of about 2.3cm if you look at the tib of a pencil 55.3 cm from your eye haw far is the image from the lens of your eye ?
The image would be 53 cm from the lens of your eye.
What is Lens?
A lens is a transmissive optical tool that uses refraction to focus or disperse a light beam. A compound lens is made up of multiple simple lenses (elements), typically arranged along a common axis, as opposed to a simple lens, which is one solid piece of transparent material. Glass or plastic are used to make lenses, which are then polished or moulded into the desired shape. In contrast to a prism, which simply refracts light without focusing it, a lens can focus light to create an image. Lenses are also devices that focus or disperse waves as well as radiation other than visible light, such as explosive lenses, microwave lenses, particle lenses, and acoustic lenses.
Lenses are a common component of telescopes, binoculars, and cameras, among other imaging devices.
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Air is a mixture of what?
1. Elements
2. Atoms
3. Compounds
4. Molecules
Answer:
gases......is the right ans. it means elements..
statics and strength of materials
The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.
What is the force P?The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;
Take moment about the joint to determine the magnitude of the force along part BC.
120 kN x 750 mm = F x 1000 mm
F = ( 120 kN x 750 mm ) / ( 1000 mm )
F = 90 kN
Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.
Stress in AB = 2 times stress in BC
P/A₁ = 2F/A₂
where;
A₁ is the area of segment ABA₂ is the area of segment BCA₁ = πd²/4 = π(50 x 10⁻³)²/4
A₁ = 1.96 x 10⁻⁵ m²
A₂ = πd²/4 = π(75 x 10⁻³)²/4
A₂ = 4.42 x 10⁻³ m²
P/A₁ = 2F/A₂
P = (2F x A₁) / (A₂)
P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = 798.2 N
P = 0.798 kN
P ≈ 0.8 kN
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use the theory of elasticity and given applied pressure at the end of construction, determine the settlements at 2p and 3p
Elasticity theory is concerned with the relationship between forces applied to an item and the subsequent deformations.
In practice, analyzing a material's elastic behavior is reduced to studying basic deformations and determining the appropriate elastic constants. Our bodily tissues are pliable. This mechanical feature is particularly significant in the lungs, skin, and arteries, because aging produces emphysema, loose skin, and arteriosclerosis. Elastic fibers are extracellular matrix fibers that resemble rubber and are responsible for tissue elasticity. Elasticity refers to an object's or material's capacity to return to its original shape after being stretched or crushed. Because of its elastic nature, a rubber regains its shape after a long stretch.
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A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at 32.4° above the forward direction. Find the magnitude and direction (relative to the forward direction) of the resultant force which these engines exert on the rocket.
The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
What is the resultant force the two engines exert on the rocket?The resultant force on the rocket is calculated thus:
The 513N thrust is resolved into vertical and horizontal components;
Horizontal component: 513N cos(32.4°) = 433.14 N
Vertical component: 513N sin(32.4°) = 274.88 N
Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N
Total force at right angles:
0 + 274.88 N = 274.88 N
The resultant force (F) is then given as follows:
F² = a² + b²
F² = (1158.14 N)² + (274.88 N)²
F = √1,416,847.27
F = 1,190.3
To find the direction:
tan X 274.88 N / 1,158.14 N
X = tan⁻¹ 0.237346089419241
X = 13.35°
Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.
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Which type of force is used by your legs to pedal a bicycle?
Answer:
kinetic energy
Explanation:
100 points really hard question
if i drop a big rock on my toe will it hurt
Answer: Yes
Explanation:
A tungsten light bulb is usually filled with some inert gases to a pressure of80 kPa at a temperature of 20 °C. The maximum internal pressure that thebulb can withstand is about 280 kPa. Find the temperature in °C of thegases at which the bulb bursts.
Given:
The initial pressure of the gas is,
\(P_1=80\text{ kPa}\)The initial temperature is,
\(T_1=20+273=293\text{ K}\)The final pressure is,
\(P_2=280\text{ kPa}\)Let the final temperature be,
\(T_2\)We know,
\(\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ T_2=\frac{P_2T_1}{P_1} \end{gathered}\)Substituting the values we get,
\(\begin{gathered} T_2=\frac{280\times293}{80} \\ T_2=1025\text{ K} \\ T_2=1025-273=752^{\circ}C \end{gathered}\)Hence the required temperature is 752 degrees celcius.
De que esta hecho el sol? plisss ayuda.no necesito un texto de 100 reglones, puede ser resumido en solo 2 renglones
Why is boiling water considered a physical change?
Answer:
Boiling water is an example of a physical change and not a chemical change because the water vapor still has the same molecular structure as liquid water.
(credits to lumenlearning)
Explanation:
Answer:
boiling of water forms steam which can be further condensed to form water again, thus this change is a temporary and reversible change
Which letters show moving from KINETIC to POTENTIAL.
Answer:
B to C
Explanation:
The object height decreases
Potential energy= mass x height x gravitational force
Which means that potential energy is directly proportional to height
Thus, a decrease in height will cause a decrease in potential energy.
ENERGY cannot be wasted, it is transformed to another form, and here this form is kinetic energy as according to the gravitational force the speed increases as the object falls downward.
And kinetic energy = 1/2 mv2
Which again means that speed is directly proportional to kinetic energy
And thus an increase in speed will cause an increase in kinetic energy.