The relationship between the mass of a student and the amount of work they do is that the greater the mass, the more work.
What is Work?This is referred to as any type of activity which requires the use of physical or mental effort by an individual or thing.
In a scenario where an individual has a greater mass then there will be more work done and vice versa as a result of the formula of work being Force × distance where the Force = mass × acceleration which therefore explains the relationship between the mass of a student and the amount of work they do.
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1. A record with a radius of 0.3m spins in a clockwise circle with a centripetal
acceleration of 4.7 m/s2. How long does it take the record to make one revolution?
(Hint: Find tangential velocity first!)
Solve for the linear/tangential speed:
a = v²/r
where a = centripetal acceleration, v = speed, and r = radius.
4.7 m/s² = v²/(0.3 m)
v² = (0.3 m) (4.7 m/s²)
v ≈ 3.96 m/s
For every time the record completes one revolution, a fixed point on the edge of the record travels a distance equal to its circumference, which is 2π (0.3 m) ≈ 1.88 m. So if 1 rev ≈ 1.88 m, then the angular speed of the record is
(3.96 m/s) (1/1.88 rev/m) ≈ 7.46 rev/s
Take the reciprocal of this to get the period:
1 / (7.46 rev/s) ≈ 0.134 s/rev
So it takes the record about 0.134 seconds to complete one revolution.
question 1-8: how does the current produced by the battery in the single bulb circuit compare to that produced by the battery with the two bulbs that are connected? Does the addition of this second bulb in this manner affect the current through the original bulb? explain
The current produced by the battery and its effect on the original bulb will vary depending on whether the bulbs are connected in series or parallel.
When comparing a single bulb circuit to a circuit with two bulbs connected, the current produced by the battery will depend on how the bulbs are connected.
If the bulbs are connected in series, the total resistance in the circuit will increase, resulting in a lower current produced by the battery. In this case, the addition of the second bulb will also cause the current through the original bulb to decrease.
However, if the bulbs are connected in parallel, the total resistance in the circuit will decrease, resulting in a higher current produced by the battery. In this scenario, the addition of the second bulb will not affect the current through the original bulb, as each bulb will have its own separate current pathway.
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which car has a westward acceleration? a. a car moving west at constant speed. b. a car moving east and speeding up. c. a car moving east and slowing down. d. a car moving west and slowing down
C. If a car has a westward acceleration, the car moving east and slowing down.
What is westward acceleration?
Westward acceleration is the acceleration of an object directed towards the west of the object's motion.
The acceleration of an object is defined as the change in the velocity of an object with time.
Mathematically, the acceleration of an object is given as;
a = Δv/Δt
where;
Δv is change in velocity of the objectΔt is change in time of motion of the objecta = (v - u) /t
where;
v is the final velocityu is the initial velocityWhen the car is slowing down, it implies that the final velocity is smaller compared to the initial velocity.
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how much do clouds weigh
The weight of a cloud can vary widely depending on its size, height, and the amount of moisture it contains, so there isn't a fixed weight for all clouds.
Clouds consist of water droplets or ice crystals that are suspended in the air, so they don't have a specific weight that can be measured. However, the amount of water vapor contained in a cloud can be estimated, and this can be converted to a weight using the density of water. On average, a cumulus cloud weighing about 1 million pounds contains around 100 tons of water.
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explain how potential and kinetic energy are at play when we talk about Newton's second law of motion
Potential and kinetic energy are at play when we talk about Newton's second law of motion through the various positions in relation to the bodies involved.
What is Newton's second law of motion?This law states that force is equal to the rate of change of momentum and is denoted as F = mv where m is mass and v is velocity.
Potential energy is the energy is possessed by a body by virtue of its position while kinetic energy is possessed by a body by virtue of its motion. Both forms of energy are influenced by forces and are equal to the total momentum.
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A car with a mass of 750 kg moving at a speed of 23 m/s rear-ends a truck with a mass of 1250 kg and a speed of 15 m/s. (The two vehicles are initially traveling in the same direction.) If the collision is elastic, find the final velocities of the two vehicles. (This is a 1-dimensional collision.)
The final velocities of the two vehicles, if the collision is elastic, then v₁ = 18 m/s and v₂ = 48 m/s.
It is given that, Mass of car, m₁ = 750 kg, Initial velocity of car, u₁ = 23 m/s, Mass of truck, m₂ = 1250 kg, Initial velocity of truck, u₂ = 15 m/s and the collision is elastic. Therefore, the total momentum of the system is conserved, i.e.,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Putting the values, we get,
750 × 23 + 1250 × 15 = 750v₁ + 1250v₂
(17250 + 18750) = (750v₁ + 1250v₂)
36000 = 750v₁ + 1250v₂
(6 × 6000) = 750v₁+ 1250v₂
Now, we have two variables and only one equation. We need another equation. We can use the conservation of kinetic energy to get another equation.
Since the collision is elastic, the total kinetic energy of the system is conserved, i.e.,
(1/2)m₁*2u₁ + (1/2)m₂*2u₂ = (1/2)m₁*2v₁ + (1/2)m₂*2v₂
Putting the values, we get,
(1/2) × 750 × (23)2 + (1/2) × 1250 × (15)2 = (1/2) × 750 × 2v₁ + (1/2) × 1250 × 2v₂
Solving further, we get,
195375 = 375v₁ + 937.5v₂(195375 / 375) = v₁ + (937.5 / 375)v₂(521 / 5) = v₁ + (25 / 2)v₂
Multiplying the first equation by 25 and subtracting the second equation, we get,
15000 = (625/2)v₂
v₂ = 48 m/s
Putting the value of v₂ in the first equation, we get,
6 × 6000 = 750v1 + 1250(48)
v₁ = 18 m/s
Therefore, the final velocities of the two vehicles are:v₁ = 18 m/s , v₂= 48 m/s.
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the position of the particle as a function of time is given by x(t) = e-(t - 3)2, where x is in meters and t is in seconds. what is the velocity of the particle, in meters per second, at t = 2.9 s?
For a particle having a position of function e^-(t - 3)², the velocity at 2.9 s is calculated to be 0.198008 m/s.
The position of a particle is denoted by a function x(t) = e^-(t - 3)², where x is the distance and t is the time.
Differentiate the function, to find velocity.
v(x) = d/dt(x) = d/dt[e^-(t - 3)²]
v(x) = e^-(t - 3)²[-2(t - 3)]
Now, substitute the value of t = 2.9 in the equation
v(2.9) = e^-(2.9 - 3)²[-2(2.9 - 3)]
v(2.9) = e^-(-0.1)²[-2(-0.1)]
Use the exponent formula a^-b = 1/a^b
v(2.9) = 1/e^(-0.1)²[0.2]
v(2.9) = 1/e^(0.01)[0.2]
Substitute the value of e^0.01 = 1.01005
v(2.9) = (1/1.01005)[0.2]
Use the arithmetic operation of division,
v(2.9) = (0.99004)[0.2]
v(2.9) = 0.198008
Therefore, the velocity of the particle is 0.198008 m/s.
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Which one is best for health? A) Boiled Seeds B) roasted seeds c) wet swollen seeds d)Sprouted seeds
Answer:
d.) "Sprouted seeds"Explanation:
Sprouted seeds - are the best for health.
I hope it helps! Please mark my answer answer as bräinliest (if my answer is correct). Thank You!
you do work when pushing a cart with a constant force. if you push the cart twice as far, say a distance 2d, with half the force, say f/2, then what is the work that you do? use the symbols to work out an expression for the work done.
The work done when pushing the cart twice as far with half the force is equal to the product of the original force and the original displacement, which is given by f × d.
The work done (W) is given by the formula:
W = force × distance × cos(θ)
where force is the magnitude of the applied force, distance is the displacement of the object, and θ is the angle between the force and the direction of displacement.
In this case, if you push the cart twice as far (2d) with half the force (f/2), the work done can be calculated as follows:
W = (f/2) × (2d) × cos(θ)
Since cos(θ) is the cosine of the angle between the force and the displacement, and in this case, the force and displacement are in the same direction, the angle is 0 degrees, and cos(0) is equal to 1. Therefore, the expression for the work done is:
W = (f/2) × (2d) × 1
Simplifying the expression:
W = f × d
So, the work done when pushing the cart twice as far with half the force is equal to the product of the original force and the original displacement, which is given by f × d.
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A 800hz tuning fork is vibrating, producing a sound wave in the air.
what is the frequency of the sound wave?
800 hz
what is the speed of the sound wave?
what is the wavelength of the sound wave?
Answer:
The frequency of the sound wave is 800Hz
The speed of sound in a is about 340m/s.
Velocity = frequency x wavelength
making wavelength the subject formula
wavelength = Velocity/frequency.
wavelength = 340/800
wavelength = 0.425m.
A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple harmonic motion with a period of 1s. If that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case?.
The period of the pendulum is √2 seconds.
We need to know about pendulum experiments to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by
g = 4π² . L / T²
where g is gravitational acceleration, L is the length of the string and T is the period.
From the question above, we know that:
T1 = 1 s
L1 = 5 cm
L2 = 10 cm
By using proportionality, the squared period is proportional to the length. Hence,
T² ~ L
Using the ratio, we can write
T1² / T2² = L1 / L2
1² / T2² = 5 / 10
1 / T2² = 1 / 2
T2² = 2
T2 = √2 second
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Please help me with these few questions! I need them done soon. Only 3 questions.
Answer:
Block A - 19.3 Kg/L
Block B - 0.64 Kg/L
Block C - 0.70 Kg/L
Block D - 0.917 Kg/L
Block E - 3.53 Kg/L
1) Which block has the greatest density?
Block A
Block B
Block C
Block D
Block E
2) Which block has the lowest density?
Block A
Block B
Block C
Block D
Block E
3) Submit your data table and identify the substance each block is made of.
The block with the greatest density = Block A
The block with the lowest density = Block B
What is density?
The density of an object is the ratio of mass to volume of the object.
density = mass/volume
The given density of the object;
Density Block A = 19.3 Kg/LDensity Block B = 0.64 Kg/LDensity Block C = 0.70 Kg/LDensity Block D = 0.917 Kg/LDensity Block E = 3.53 Kg/LThus, we can conclude the following based on the density of the objects;
The block with the greatest density = Block A
The block with the lowest density = Block B
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What is directly created when radiation from the Sun heats air in the atmosphere?
erosion
humidity
precipitation
wind
Answer:
Wind
Explanation:
I had this question on one of my tests, and I got it right
A 1. 5-mole sample of an ideal gas is gently cooled at constant temperature 320 K. It contracts
from initial volume 19 L to final volume V2. A total of 1. 2 kJ of heat is removed from the gas during the contraction process. What is V2? Let the ideal-gas constant R = 8. 314 J/(mol. K).
A mole sample of an ideal gas is gently cooled at constant temperature 320 K.
What happens when gas is cooled at constant temperature?Since the internal energy of an ideal gas is proportional to temperature, it does not change when the temperature is held constant. The first law, which governs changes in internal energy, changes to 0 = Q - W, resulting in Q = W. Both the temperature and the volume of the gas decrease as it cools at a constant pressure. The fundamental behaviour of fluids with respect to volume, pressure, and temperature is described by Boyle's, Charles', and Gay Lussac's Laws. When heat is applied at constant pressure, some of it is utilised to cause gas to expand while the remainder is used to raise the gas' temperature, which increases the gas' internal energy.To learn more about constant temperature refer to:
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can someone tell me the ans of this question quick
Answer:
6m/s
Explanation:
speed=distance÷time
speed=150÷25
speed=6m/s
What are the 3 main approaches to the identification of unknown bacteria?
The three main approaches to the identification of unknown bacteria are as follows:Phenotypic identification, Molecular identification and Biochemical identification
What is Phenotypic, Molecular and Biochemical identification?1. Phenotypic identification
Phenotypic identification involves the physical and chemical characteristics of the bacterial colonies and cells. In this method, bacterial cells are studied through microscopy, their ability to grow on various types of media, cellular morphology, and other factors that are easy to observe.
2. Biochemical identification
Biochemical identification is based on the biochemical reactions of bacteria. This method involves the use of different chemical and biochemical tests to identify the bacteria. The tests are designed to identify specific enzymes or metabolic pathways. The results of the tests are then used to identify the bacteria.
3. Molecular identification
Molecular identification involves the use of DNA analysis to identify bacteria. In this method, the DNA of the bacterial cells is isolated and analyzed. This method has become popular in recent years due to its accuracy and speed.
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Briefly explain how Earth's movements result in the seasons we experience on Earth. What
conditions cause us to experience Summer in the Northern Hemisphere? What conditions
cause us to experience Winter?
Answer:
Earth's tilted axis causes the seasons. Throughout the year, different parts of Earth receive the Sun's most direct rays. So, when the North Pole tilts toward the Sun, it's summer in the Northern Hemisphere. And when the South Pole tilts toward the Sun, it's winter in the Northern Hemisphere.
Explanation:
is carbon dioxide a element?
Answer:
Carbon Dioxide is a compound and not an element.
Answer:
Carbon dioxide is a compound.
Explanation:
Elements are when you only have one type of atom that makes it up. Carbon dioxide is made up of two different types of atoms.
PLEASE DO THIS SCIENCE QUESTION I WILL MARK YOU THE BRAINLIEST NO LINKS
Answer:
Float
Explanation:
The objects weight 14n and the buoyant force is 12n, so it will sink because the weight is greater than the buoyant force.
Equation: p = m/v
what effect does an energy change have on the identity of a substance
An energy change can have different effects on the identity of a substance depending on the type of energy involved and the nature of the substance itself. In general, an energy change does not alter the fundamental identity or chemical composition of a substance. The identity of a substance is determined by its unique arrangement of atoms and the types of chemical bonds present.
When considering changes in energy, it is important to distinguish between physical and chemical changes. In a physical change, the substance undergoes a transformation that does not alter its chemical composition. For example, heating water to its boiling point causes a physical change from liquid to gas, but the water molecules remain intact. In this case, the energy change (heat) affects the physical state of the substance but not its identity.
On the other hand, in a chemical change, the substance undergoes a transformation that involves the breaking and forming of chemical bonds, resulting in a different chemical composition. Energy changes, such as heat or light, can drive chemical reactions by providing the necessary activation energy. However, even in a chemical change, the identity of the substance is determined by the arrangement of its atoms and the types of elements involved.
In summary, an energy change, whether in the form of heat, light, or other forms, can affect the physical or chemical properties of a substance, but it does not alter its fundamental identity. The identity of a substance is determined by its unique composition and arrangement of atoms, which remain unchanged during most energy changes.
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Light passes from air (n=1) into another medium at 30.0 degrees to the normal. If the angle of refraction is 18.0 degrees, what is the index of refraction of the new medium?
The refractive index of the new medium is approximately 1.59.
Snell's law relates the angles of incidence and refraction of light passing through a boundary between two media with different refractive indices (n). The formula is:
n₁ sin θ₁ = n₂ sin θ₂
where n₁ is the refractive index of the first medium, θ₁ is the angle of incidence, n₂ is the refractive index of the second medium, and θ₂ is the angle of refraction.
In this problem, we know that the angle of incidence is 30.0 degrees and the angle of refraction is 18.0 degrees. We also know that the refractive index of air (n₁) is 1.00. Therefore, we can use Snell's law to solve for the refractive index of the new medium (n₂):
n₁ sin θ₁ = n₂ sin θ₂
1.00 sin 30.0° = n₂ sin 18.0°
n₂ = (1.00 sin 30.0°) / sin 18.0°
n₂ ≈ 1.59
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What happens to scientific laws if new, unexpected data is discovered? a They become scientific theories. b They are revised. c Nothing, the new data is ignored.
Answer:
revised
Explanation:
A 2.0 kg 2.0kg2, point, 0, start text, k, g, end text cart moving right at 5.0 m s 5.0 s m 5, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction on a frictionless track collides with a 3.0 kg 3.0kg3, point, 0, start text, k, g, end text cart initially at rest. The 2.0 kg 2.0kg2, point, 0, start text, k, g, end text cart has a final speed of 1.0 m s 1.0 s m 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction to the left. What is the final speed of the 3.0 kg 3.0kg3, point, 0, start text, k, g, end text cart?
The final speed of the 3.0 kg cart is 4 m/s.
What is conservation of momentum principle?When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.
The external force is not acting here, so the initial momentum is equal to the final momentum. For elastic collision, final velocities is different for both the bodies.
m₁u₁ +m₂u₂ = m₁v₁ +m₂v₂
A 2.0 kg cart moving right at 5.0 m/s on a frictionless track collides with a 3.0 kg cart initially at rest. The 2.0 kg cart has a final speed of 1.0 m/s to the left.
Substitute the values for m₁ = 2kg, m₂ =3kg, u₁ =5 m/s and u₂ =0 m/s, then the final velocity will be
3x0 +2x5 = -2x1 + 3v₂
v₂ = 4 m/s
Thus, the the final velocity 3.0 kg cart is 4 m/s.
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Two cars collide head on while each is traveling at 70 km/h. Suppose all their kinetic energy is transformed into the thermal energy of the wrecks. What is the temperature increase of each car? Part A You can assume that each car's specific heat is that of iron. Express your answer with the appropriate units
To determine the temperature increase of each car, we can use the principle of conservation of energy. The total kinetic energy of the cars before the collision is converted into thermal energy (heat) after the collision.
The formula to calculate the temperature increase is:
ΔT = (ΔE) / (m * c)
Where:
ΔT is the temperature increase,
ΔE is the change in thermal energy (equal to the initial kinetic energy of the cars),
m is the mass of each car, and
c is the specific heat capacity of iron.
Since the specific heat capacity of iron is approximately 450 J/(kg·°C), and the mass of each car is not given in the question, we cannot determine the specific temperature increase without that information. Therefore, the answer cannot be expressed with the appropriate units without knowing the mass of the cars.
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How does the strength of a magnetic field around a wire vary?
Answer:
By pointing one's right thumb along the direction of the current, the direction of the magnetic field can by found by curving one's fingers around the wire. The strength of the magnetic field depends on the current I in the wire and r, the distance from the wire.
A plane mirror moves towards the object with a velocity of 2m/s and the object itself moves towards the mirror with a velocity of 5m/s. What is the velocity of the image approaching towards the object?
We have that the velocity of the image approaching towards the object is
\(x=3.33m/s\)
From the question we are told
A plane mirror moves towards the object with a velocity of 2m/s and the object itself moves towards the mirror with a velocity of 5m/s. What is the velocity of the image approaching towards the object?
Generally the equation for the velocity of the image is mathematically given as
\(\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\\Therefore\\\\\frac{1}{2}=\frac{1}{x}+\frac{1}{5}\\\\\frac{1}{x}=\frac{1}{2}-+\frac{1}{5}\\\\\frac{1}{x}=0.3\)
\(x=3.33m/s\)
Therefore
the velocity of the image approaching towards the object is
\(x=3.33m/s\)
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The constructor equation of the geometric optics allows to find the result for the speed of the image is 7 m/s
Geometric optics analyzes the formation of images with different objects, for this it uses the constructor equation
\(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)
Where f is the focal length, p the distance a to the object and q the distance to the image
In this case we have a plane mirror, a plane object has its radius of curvature at infinity (f = ∞), consequently
p = q
If we derive this expression with respect to time
\(\frac{dp}{dt} = \frac{dq}{dt}\)
The speed of the object and the image is the same.
In all these equation is the mirror or lens are considered fixed in space
In this case we have that the object moves towards the mirror at v₀ = 2 m / s and the mirror moves towards the object at \(v_m\) = 5 m / s
To consider the mirror fixed in space, we must find the relative velocity of the object with respect to the mirror; the body approaches the speeds add
\(v_{om} = v_o +v_m\)
Where \(v_{om}\) speed of the object with respect to the mirror, v₀ and \(v_m\) are the velocities of the object and the mirror, respectively
\(v_{om}\) = 5 + 2
v_{om} = 7 m / s
The speed of the image and the object are equal, therefore the image speed is:
v = 7 m / s
In conclusion using the constructor equation allow to find the result for the image speed is 7 m / s
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How much work is required to move an electron
through a potential difference of 3.00 volts?
(1) 5.33 × 10^–20 J (3) 3.00 J
(2) 4.80 × 10^–19 J (4) 1.88 × 10^19 J
Answer:
(2) the work required to move the electron is 4.8 x 10⁻¹⁹ J.
Explanation:
Given;
potential difference, V = 3.00 volts
charge of electron, q = 1.6 x 10⁻¹⁹ C
The work required to move an electron is calculated as;
W = Vq
where;
W is the work done in Joules
Substitute the given values and solve for W;
W = (3.00)(1.6 x 10⁻¹⁹)
W = 4.8 x 10⁻¹⁹ J.
Therefore, the work required to move the electron is 4.8 x 10⁻¹⁹ J.
what is the change in kinetic energy of a 100 kg object that accelerate from 5m/s to 12.5 m/s?
Answer:
K.E = 1/2 M(V^2-U^2)
___________________________________
/ /
/ M = mass
/ V = final velocity
/ U = initial velocity
/ __________________________________/
= 1/2(100Kg) ( ( 12.5m/s )^2 - ( 5m/s) ^2 )
= 50kg ×( (156.25) - (25) ) m^2/s^2
= 50 kg ×131.25 m^2/s^2
= 6562.5 J
so kinitic energy of object is 6562.5 J .
The initial kinetic energy of the object can be calculated using the formula:
KE = 1/2 * m * v1^2
where KE is the kinetic energy, m is the mass of the object, and v1 is the initial velocity.
KE1 = 1/2 * 100 kg * (5 m/s)^2
KE1 = 1250 J
The final kinetic energy of the object can be calculated using the same formula, but with the final velocity v2:
KE2 = 1/2 * 100 kg * (12.5 m/s)^2
KE2 = 7812.5 J
The change in kinetic energy is then:
ΔKE = KE2 - KE1
ΔKE = 7812.5 J - 1250 J
ΔKE = 6562.5 J
Therefore, the change in kinetic energy of the object is 6562.5 J.
If the work done on a object is 100 J and it comes to a rest on a surface with a mass of 10
kg and a SHC of 1000 J/kg-C calculate the change in temperature.
Calculate the displacement of a motorcycle that accelerates forward from rest to 7.0 m/s in 3.5 s.
I need solution and statement.
Answer:
12.25 meters
Explanation:
s=1/2(v+u)t
s= displacement
v= final velocity
u= initial velocity
t= time
7m/s+0m/s divide by 2= 3.5 m/s velocity Times 3.5 seconds= 12.25 meters