what is the ratio of $12 dollars for 3 tickets as a unit rate

Answer:

$17,204.28

Step-by-step explanation:

So first of all you want to start by finding what P, r and t would be.

Once I found all of those I put them into the equation (l = Prt) and solved (by putting it into a calculator obviously). That is how I came up with my answer. Check the screenshot provided to see what P, r and t would be and to see all my work! :)

Hope this helps! :)

Have a great day!

Answer:

22.7°

Step-by-step explanation:

22.714° to nearest 10th is 22.7

Answer:

y = - 8

The line is horizontal and it passes through y= - 8

Step-by-step explanation:

Slope: (-8 - - 8)/(-4 - - 9) = 0

The line doesn’t have x

y= -8

Answer:

Step-by-step explanation:

To find the number that Grace thought:

We'll represent the unknown number as "x."

"Added 7": This can be represented as (x + 7).

"Multiplied by 3": This becomes 3 * (x + 7).

"Took away 5": This is represented as 3 * (x + 7) - 5.

"Divided by 4": This gives (3 * (x + 7) - 5) / 4.

"To give an answer of 7": The equation is (3 * (x + 7) - 5) / 4 = 7.

Now we can solve for x:

(3 * (x + 7) - 5) / 4 = 7

Multiply both sides by 4 to eliminate the denominator:

3 * (x + 7) - 5 = 28

Simplify the left side:

3x + 21 - 5 = 28

Combine like terms:

3x + 16 = 28

Subtract 16 from both sides:

3x = 12

Divide both sides by 3:

x = 4

Therefore, the number that Grace thought of is 4.

Answer:

=0

Step-by-step explanation:

4(11+7)-9•8=

(44+28)-72=

72-72=0

Answer:

n = 1.92

Step-by-step explanation:

Multiply both sides of the equation by 3.2

\(3.2*\frac{2}{3.2} =3.2*\frac{9.6}{16}\)

Simplify both sides of the equation.

n = 1.92

good luck, i hope this helps :)

By using the concept of dilation factor, length of BC obtained is 3 units

What is dilation factor?

Dilation is a transformation which changes the size of a figure by a certain factor.

That factor is called the scale factor

In the figure, A'B'C'D' is the image of ABCD under dilation with a scale factor of 3

A'B'C'D' is the dilated figure

Length of B'C' = 9 units

Length of BC = \(9 \div 3\) = 3 units

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Complete Question

The figure has been attached here

As a result, $17.55 should be chosen as the selling price to sell 480,000 units for a profit of $1,500,000.

We must add the desired net profit of $1,500,000 to the total cost of producing the 480,000 units to determine the selling price.

You can determine the overall cost as follows:

Total cost equals fixed costs plus. (Variable costs per unit x Number of units)

Total expense equals $984,000 plus ($14.50 x 480,000)

Cost in total is $7,224,000.

To reach a net profit of $1,500,000, we must add the following sum to the whole expense:

Selling price is calculated as Total Cost + Desired Net Profit / Units Sold.

($7,224,000 + $1,500,000) / 480,000 = selling price

Price to Sell: $17.55

As a result, $17.55 should be chosen as the selling price to sell 480,000 units for a profit of $1,500,000.

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Answer:

--------------------------

To determine the selling price, we first need to calculate the total  variable cost:

Now calculate the required revenue:

Find the required selling price per unit:

Answer: C

Step-by-step explanation:

Angles opposite congruent sides in a triangle are congruent, so angle B measures 30 degrees.

So, as angles in a triangle add to 180 degrees, angle A measures 120 degrees.

Answer:

1/8

Step-by-step explanation:

Answer:

25/2

Step-by-step explanation:

see if we break it down

12 1/2

(12x2+1)/2

25/2

we cant break it down so leave it like that

The dairy farmer should use 1330 pounds of the 70% protein supplement and 570 pounds of the 20% protein ratio to make a 1900-pound high-grade 55% protein ration.

To determine the amounts of the 70% protein supplement and the 20% protein ratio needed to make a 1900-pound high-grade 55% protein ration, we can set up a system of equations.

Let's assume x represents the pounds of the 70% protein supplement and y represents the pounds of the 20% protein ratio.

The total weight equation is given by:

x + y = 1900

The protein content equation is given by:

(0.70x + 0.20y) / 1900 = 0.55

Simplifying the second equation, we get:

0.70x + 0.20y = 0.55 × 1900

0.70x + 0.20y = 1045

Now, we can solve this system of equations to find the values of x and y.

Rearrange the first equation to solve for x:

x = 1900 - y

Substitute this expression for x in the second equation:

0.70(1900 - y) + 0.20y = 1045

1330 - 0.70y + 0.20y = 1045

1330 - 0.50y = 1045

-0.50y = 1045 - 1330

-0.50y = -285

y = -285 / -0.50

y = 570

Now substitute this value of y back into the first equation to find x:

x + 570 = 1900

x = 1900 - 570

x = 1330

Therefore, the dairy farmer should use 1330 pounds of the 70% protein supplement and 570 pounds of the 20% protein ratio to make a 1900-pound high-grade 55% protein ratio.

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Answer: 50/110 simplified is 5/11

Step-by-step explanation:

50/110

50/10=5

110/10=11

5/110=5/11

Answer:

Change in profit per member = - 65.25

Step-by-step explanation:

Given that :

Number of members involved in business = 4

Amount lost = $261

If loss is shared equally :

Loss per member = amount lost / number of members

Loss per member = $261 / 4

Loss per member = $65.25

Change in profit per member = - $65.25

Answer:

22,590

Step-by-step explanation:

Step 1: Use PEMDAS, according to PEMDAS, multiply first. (You might see that some of the operations are in the same place, that is because if for example multiplication is on the left, and division is on the right, do the multiplication first. It is a common misconception to do addition/subtraction first than multiplication/division because they are on the left.)

P = Parentheses 1st

E = Exponent 2nd

M = Multiplication 3rd/4th

D = Division 3rd/4th

A = Addition 5th/6th

S = Subtraction 5th/6th

90 + (50 x 450)

50 x 450 = 22,500

Step 2: Add 90 to the product

90 + 22,500 = 22,590

The equation of the line is with the coordinates f(-6) = 9 and f (20) = 5. is y = (-2/13)x + 117/13.

Y = mx + b, where m is the line's slope and b is the y-intercept, is the slope-intercept form of a linear equation. This form is helpful since it provides information about the line's slope and y-intercept in a clear and understandable manner. We can quickly determine the slope of the line (m) and its point of intersection with the y-axis by glancing at the equation (b). By beginning at the y-intercept and using the slope to determine other locations along the line, we can also graph the line using this method.

The slope of the line is given as:

m = (y2 - y1) / (x2 - x1)

Substitute the given coordinates:

m = (5 - 9) / (20 - (-6))

m = -4 / 26

m = -2 / 13

Using the point slope form we have:

y - y1 = m(x - x1)

Using the point (-6, 9):

y - 9 = (-2/13)(x - (-6))

y - 9 = (-2/13)x - 12/13

y = (-2/13)x + 117/13

So the equation of the line is y = (-2/13)x + 117/13.

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Answer:  x = -3/2

Step-by-step explanation:

Answer:

-2<=y<=-7

Step-by-step explanation:

The expression that is equivalent to StartRoot \(8 x^7 y^8\) EndRoot is (\(2 x^3 y^4\) StartRoot 2 x EndRoot)^2.

To understand why this is the case, let's break down each expression and simplify them step by step:

StartRoot \(8 x^7 y^8\) EndRoot:

We can rewrite 8 as \(2^3\), and since the square root can be split over multiplication, we have StartRoot \((2^3) x^7 y^8\) EndRoot. Applying the exponent rule for square roots, we get StartRoot \(2^3\) EndRoot StartRoot \(x^7\) EndRoot StartRoot \(y^8\) EndRoot.

Simplifying further, we have 2 StartRoot \(2 x^3 y^4\) EndRoot StartRoot \(2^2\) EndRoot StartRoot \(x^2\) EndRoot StartRoot \(y^4\) EndRoot. Finally, we obtain 2 \(x^3 y^4\) StartRoot 2 x EndRoot, which is the expression in question.

(\(2 x y^2\) StartRoot 8 x^3 EndRoot)^2:

Expanding the expression inside the parentheses, we have \(2 x y^2\)StartRoot \((2^3) x^3\) EndRoot. Applying the exponent rule for square roots, we get \(2 x y^2\) StartRoot \(2^3\) EndRoot StartRoot \(x^3\) EndRoot.

Simplifying further, we have \(2 x y^2\) StartRoot 2 x EndRoot. Squaring the entire expression, we obtain (\(2 x y^2\) StartRoot 2 x EndRoot)^2.

Therefore, the expression (\(2 x^3 y^4\) StartRoot 2 x EndRoot)^2 is equivalent to StartRoot \(8 x^7 y^8\) EndRoot.

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a) A negative number on the x-axis (-a, b) would move in the left direction by one unit.

To find out why, check point (0, b) on the y-axis and point (-a, b) on the x-axis.

The distance between these two points is a unit, meaning that the point (-a, b) is one unit to the left of the point (0, b).

b) A positive number on the x-axis (+a, b) would move in the right direction by a unit.

Again, let's look at the point (0, b) on the y-axis and the point (+a, b) on the x-axis.

The distance between the two points is also one unit, which means the point (+a, b) is one unit to the right of the point (0, b).

c) A negative number on the y-axis (a, -b) would move in the downward direction by b units.

Assume that point (a, 0) is on the x-axis and point (a, -b) is on the y-axis. The distance between them is b units, which means that the point (a, -b) is b units below the point (a, 0).

d) A positive number on the y-axis (a, +b) would move in the upward direction by b units.

Also, check the point (a, 0) on the x-axis and point (a, +b) on the y-axis. The distance between these two points is b units, which means that the point (a, +b) is b units above the point (a, 0).

A number is a mathematical term used to show the quantity or value of a thing. It can be depicted using numerals, symbols, or words.

Examples include 30, hundred, -8, 6x, "5", 0.67, etc.

Numbers can be Positive - numbers greater than zero, or negative - numbers less than zero.

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63:

2x3=6

3x5=15

6+15=21

x 3 =…

63

Step-by-step explanation:

Answer:

1.9.75x> 195

2.9.75x> 195

9.75/9.75x>195/9.75

x>20hrs

Answer:

Cost for each pound of jelly beans:  $2.75

Cost for each pound of almonds:  $3.75

Step-by-step explanation:

Let J be the cost of one pound of jelly beans.

Let A be the cost of one pound of almonds.

Using the given information, we can create a system of equations.

Given 3 pounds of jelly beans and 5 pounds of almonds cost $27:

\(\implies 3J + 5A = 27\)

Given 9 pounds of jelly beans and 7 pounds of almonds cost $51:

\(\implies 9J + 7A = 51\)

Therefore, the system of equations is:

\(\begin{cases}3J+5A=27\\9J+7A=51\end{cases}\)

To solve the system of equations, multiply the first equation by 3 to create a third equation:

\(3J \cdot 3+5A \cdot 3=27 \cdot 3\)

\(9J+15A=81\)

Subtract the second equation from the third equation to eliminate the J term.

\(\begin{array}{crcrcl}&9J & + & 15A & = & 81\\\vphantom{\dfrac12}- & (9J & + & 7A & = & 51)\\\cline{2-6}\vphantom{\dfrac12} &&&8A&=&30\end{array}\)

Solve the equation for A by dividing both sides by 8:

\(\dfrac{8A}{8}=\dfrac{30}{8}\)

\(A=3.75\)

Therefore, the cost of one pound of almonds is $3.75.

Now that we know the cost of one pound of almonds, we can substitute this value into one of the original equations to solve for J.

Using the first equation:

\(3J+5(3.75)=27\)

\(3J+18.75=27\)

\(3J+18.75-18/75=27-18.75\)

\(3J=8.25\)

\(\dfrac{3J}{3}=\dfrac{8.25}{3}\)

\(J=2.75\)

Therefore, the cost of one pound of jelly beans is $2.75.

Since the units are in feet, the answer would be in 25.5 square feet.

Perimeter is the total length of the boundary or outer edge of a two-dimensional shape. It is the sum of the lengths of all sides or edges of the shape. The perimeter is usually measured in units such as centimeters, meters, or feet. For example, the perimeter of a square with sides of length 5 centimeters would be 20 centimeters (5 + 5 + 5 + 5), and the perimeter of a rectangle with length 6 meters and width 4 meters would be 20 meters (6 + 4 + 6 + 4). The concept of perimeter is commonly used in geometry to calculate the amount of material needed to surround a shape, such as fencing a garden or laying tiles on a floor.

The given values represent lengths, so we cannot directly calculate an area. However, we can add them to find the perimeter of a shape with sides of these lengths.

The perimeter is the total distance around a shape, which is the sum of the lengths of all its sides. So:

Perimeter = 10ft + 9.5ft + 6ft

Perimeter = 25.5ft

Since the units are in feet, the answer would be in square feet.

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The complete question is: Find the distance perimeter around a shape, which is the sum of the lengths of all its sides.10ft+9.5ft+6ft in square units

The expression that is equal to the given Polynomial expression is (x^3-4)(2x+5).

The polynomial expression given is 2x^4+5x^3-8x-20. We have to identify the expression that is equal to this given polynomial expression.

We will factor the given polynomial expression to determine the equivalent expression. We can use factorization by grouping to factor the expression completely and determine the equivalent expression .

Factorization by grouping:

We can group the first two terms 2x^4 and 5x^3 together and factor out x^3 from them. We can also group the last two terms -8x and -20 together and factor out -4 from them.

This gives us;2x^4+5x^3-8x-20= x^3(2x+5)-4(2x+5) =(x^3-4)(2x+5)

Therefore, the expression that is equal to the given polynomial expression is (x^3-4)(2x+5).

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Answer: 18

Step-by-step explanation:

\(\triangle HJK \cong \triangle HLK\) by HL. Therefore, \(JK=2\) by CPCTC.

Using the segment addition postulate, \(GK=9\).

Furthermore, \(\triangle HGK \cong \triangle HMK\) by HL. This means that \(MK=9\) by CPCTC.

Using the segment addition postulate again, \(GM=9+9=18\).

Answer:

\(C.y = - 5x + 7\)

Step-by-step explanation:

Hope thai HELPS!

Answer:

b

Step-by-step explanation:

Answer:

\(\cos G=\dfrac{2}{3}\)

\(\csc E=\dfrac{3}{2}\)

\(\cot G=\dfrac{2}{\sqrt{5}}\)

Step-by-step explanation:

If the right angle of right triangle EFG is ∠F, then EG is the hypotenuse, and EF and FG are the legs of the triangle. (Refer to attached diagram).

Given ΔEFG is a right triangle, and EG = 6 and FG = 4, we can use Pythagoras Theorem to calculate the length of EF.

\(\begin{aligned}EF^2+FG^2&=EG^2\\EF^2+4^2&=6^2\\EF^2+16&=36\\EF^2&=20\\\sqrt{EF^2}&=\sqrt{20}\\EF&=2\sqrt{5}\end{aligned}\)

Therefore:

\(\hrulefill\)

To find cos G, use the cosine trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cosine trigonometric ratio} \\\\$\sf \cos(\theta)=\dfrac{A}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle G, the adjacent side is FG and the hypotenuse is EG.

Therefore:

\(\cos G=\dfrac{FG}{EG}=\dfrac{4}{6}=\dfrac{2}{3}\)

\(\hrulefill\)

To find csc E, use the cosecant trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cosecant trigonometric ratio} \\\\$\sf \csc(\theta)=\dfrac{H}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle E, the hypotenuse is EG and the opposite side is FG.

Therefore:

\(\csc E=\dfrac{EG}{FG}=\dfrac{6}{4}=\dfrac{3}{2}\)

\(\hrulefill\)

To find cot G, use the cotangent trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cotangent trigonometric ratio} \\\\$\sf \cot(\theta)=\dfrac{A}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle G, the adjacent side is FG and the opposite side is EF.

Therefore:

\(\cot G=\dfrac{FG}{EF}=\dfrac{4}{2\sqrt{5}}=\dfrac{2}{\sqrt{5}}\)