What is the radius (in fm) of a lithium-7 nucleus? fm

The impact parameter that will give a deflection of 1 degree for an alpha particle of energy 7.7 MeV incident on a gold nucleus (Z = 79) is 9.38 x \(10^{-14}\) m.

The formula used to calculate impact parameter (b) is given by;

`b = [(z1*z2*\(e^2\))/(4πε0m\(v^2\))](cot(θ/2))`

Where, z1 and z2 are the atomic numbers of the interacting nuclei, e is the charge of an electron, ε0 is the permittivity of free space, m is the mass of the alpha particle, v is the velocity of the alpha particle, θ is the scattering angle.

The angle of deflection is 1 degree which is equal to 0.01745 radians. Given that an alpha particle of energy 7.7 MeV is incident on a gold nucleus (Z = 79).

The mass of the alpha particle (m) = 4u

Energy of the alpha particle (E) = 7.7 MeV

Charge of the alpha particle (e) = 2e

Atomic number of the gold nucleus (Z) = 79

Velocity of the alpha particle (v) can be calculated using the formula for kinetic energy given by;

`K = (1/2)\(mv^2\)

`Where, K is the kinetic energySubstitute the values to find v;`7.7*\(10^6\) eV = (1/2) * 4u * \(v^2\)``v = \(\sqrt{[(2*7.7*10^6)/(4*931.5*10^6)]`}\)

`v = 0.0132 m/s`

Now substitute all the known values in the formula for impact parameter;

b = [(z1*z2*\(e^2\))/(4πε0\(mv^2\))](cot(θ/2))`

= \([(79*2*1.6*10^{-19})^2/(4\pi *8.85*10^{-12}*4*3.14*0.0132*4*1.66*10^{-27})](cot(0.008725))\)`

= 9.38*\(10^{-14} m\)`

To learn more about alpha particle, refer:-

https://brainly.com/question/24276675

#SPJ11

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

To know more about modulus here https://brainly.com/question/30402322

#SPJ4

An 10.0-kg dog is moving at a pace of 5.00 meters per second. The amount of work that must be done to halt its dog in 2.40 seconds must be at least 125 joules.

Whenever an object is transported over a length by an external force, at least a portion of that force must be applied in the plane of the displacement. In physics, this is referred to as work.

The three categories below can be used to categorize the kinds of labor that are done. The three sorts are good work, negative collaborate, and zero work. The type of work that is performed depends on the connection between force and displacement. When a force is used and an item is pushed in that direction, positive work is produced.

Work is equal to force times distance.

Work done = kinetic energy

Kinetic energy is equal to 1/2 mv2 or 1/2 10*5² or 5 *25.

= 125 joules

Hence, work done is 125 joules.

To know more about work visit:

https://brainly.com/question/9150655

#SPJ4

The charge residing on the metal ball is approximately 6.87 × 10⁻⁹ C. The force exerted on the metal ball due to the electric field is approximately 2.58 × 10⁻⁶ N.

a) To find the charge residing on the metal ball, we can use Gauss's Law which states that the flux of the electric field through any closed surface is proportional to the charge enclosed within the surface. For a metal ball of radius R, the electric field just outside the ball is given by:

E = k * Q / R²

where k is the Coulomb constant, Q is the charge on the ball, and R is the radius of the ball.

Substituting the given values, we get:

3.75 × 10² N/C = (9 × 10⁹ N⋅m²/C²) * Q / (3.50 × 10⁻² m)²

Solving for Q, we get:

Q = (3.75 × 10² N/C) * (3.50 × 10⁻² m)² / (9 × 10⁹ N⋅m²/C²)

Q ≈ 6.87 × 10⁻⁹ C

Therefore, the charge residing on the metal ball is approximately 6.87 × 10⁻⁹ C.

b) To find the force exerted on the ball due to the electric field, we can use the formula:

F = Q * E

where Q is the charge on the ball and E is the electric field just outside the ball.

Substituting the given values, we get:

F = (6.87 × 10⁻⁹ C) * (3.75 × 10² N/C)

F ≈ 2.58 × 10⁻⁶ N

Therefore, the force exerted on the metal ball due to the electric field is approximately 2.58 × 10⁻⁶ N.

Learn more about Coulomb constant here: brainly.com/question/9658349

#SPJ4

We can use the principle of conservation of mass to find the exit speed of water when a nozzle is attached. We'll need to know the diameter of the nozzle to determine the speed.

Assuming that the diameter of the nozzle is provided as 'd' meters, we can use the equation of continuity:

A1 * v1 = A2 * v2

Here, A1 and v1 represent the initial area and velocity of the pipe, respectively. A2 and v2 represent the area and velocity of the nozzle, respectively.

Step 1: Find the areas of the pipe and nozzle.
A1 = (pi/4) * (0.8)^2
A2 = (pi/4) * d^2

Step 2: Plug the areas and initial velocity into the equation of continuity.
(0.8)^2 * 2 = d^2 * v2

Step 3: Solve for v2, the exit speed of water.
v2 = (0.8^2 * 2) / d^2

The exit speed of water (v2) from the nozzle depends on the diameter (d) of the nozzle and can be calculated using the formula v2 = (0.8^2 * 2) / d^2.

In order to find the exit speed of water when a nozzle is attached to the pipe, you need to know the diameter of the nozzle. By applying the principle of conservation of mass and using the equation of continuity, you can find the exit speed of water as it flows through the nozzle.

To know more about nozzle visit

https://brainly.com/question/30896816

#SPJ11

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Explanation:

The statement that is not true about asteroids is their images become blurry due to outgassing as the sun heats them up.

Asteroids, sometimes referred as the minor planets. They are rocky, airless remnants left over from the early formation of the solar system about 4.6 billion years ago.

Most of this ancient space rubble can be found orbiting the Sun between the planets Mars and Jupiter within the main asteroid belt. Some of these asteroids go in front of and behind Jupiter. These are known as Trojan asteroids. Asteroids which come close to Earth are called Near Earth Objects, NEOs for short.

They vary considerably in their composition, reflectivity, and size. These earth grazers can cross not only our orbit, but even those of Venus and mercury. Some of these asteroids have satellites of their own. They are treated as the left over from the formation of our solar system.

Learn more about Asteroids here

https://brainly.com/question/11996385

#SPJ4

The leg's estimated percentages of muscle and fat are 0.000758 and 0.999, respectively.

To estimate the fractions of muscle and fat in the leg, we can use the principle that electrical resistance is influenced by the amount of conductive tissue. In this case, we assume that muscle and fat have different resistivities.

First, let's calculate the resistance of the leg using Ohm's Law:

\(\[\text{Resistance (R)} = \frac{\text{Voltage (V)}}{\text{Current (I)}}\]\)

\(R = \frac{0.74 \, \text{V}}{1.6 \, \text{mA}} = \frac{0.74 \, \text{V}}{0.0016 \, \text{A}} = 462.5 \, \Omega\)

Next, we can calculate the resistance contributed by the muscle tissue alone. Since the leg diameter is given, we can use the formula for the resistance of a cylinder:

Resistance of muscle \(R_{\text{muscle}} = \frac{{\text{resistivity of muscle} \times \text{length of leg}}}{{\text{cross-sectional area of muscle}}}\)

Assuming the resistivity of muscle is constant, we can ignore it for the purpose of comparing the fractions of muscle and fat. Therefore, the resistance is directly proportional to the length of the leg and inversely proportional to the cross-sectional area of the muscle.

Now, let's calculate the resistance of the muscle:

\(R_{\text{muscle}} = \frac{{\text{length of leg}}}{{\text{cross-sectional area of muscle}}}\)

\(R_{\text{muscle}} = \frac{{40 \, \text{cm}}}{{\pi \times (6 \, \text{cm})^2}}\)

≈ 0.35 cm

Finally, we can find the fraction of muscle (\(f_{\text{muscle}}\)) by dividing the resistance of the muscle by the total resistance of the leg:

\(\( f_{\text{muscle}} = \frac{{R_{\text{muscle}}}}{{R}} \)\)

≈ 0.35 cm / 462.5 Ω

≈ 0.000758

To find the fraction of fat (\(f_{\text{fat}}\)), we can subtract the fraction of muscle from 1:

\(f_{\text{fat}} = 1 - f_{\text{muscle}}\)

≈ 1 - 0.000758

≈ 0.999

Therefore, the estimated fractions of muscle and fat in the leg are approximately 0.000758 and 0.999, respectively.

To know more about the fractions refer here :

https://brainly.com/question/30440291#

#SPJ11

The vehicle to undergo the greater change in velocity will be the lighter in mass.

According to the conservation of momentum principle, if there is no external force acting on the colliding objects, the total momentum before and after the collision will be the same.

Let masses of an oil tanker and a tug boat be M and m and velocities of them before collision be U and u and  velocities of them after collision be V and v.

When the net external force is zero, the system's momentum remains constant, according to the conservation of linear momentum formula.

Final momentum of them = initial momentum of them

MV + mv = MU + mu

⇒ M(V-U) = - m (v-u)

Hence, product of mass and change in velocity is same. So, the vehicle to undergo the greater change in velocity will be the lighter in mass.

Learn more about momentum here:

https://brainly.com/question/24030570

#SPJ1

Answer:

velocity = 29.4 m/s

Explanation:

We have been told to calculate the velocity of a ball after 3 seconds of freefall. To do this, we can use the following formula:

\(\boxed{v = u + at}\),

where:

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time of freefall

In this case, u = 0 m/s, because the ball is initially stationary before it is released. Also, a = 9.81 m/s² because the ball is falling while inside the Earth, where the acceleration of freefall is 9.81 m/s².

Using the above information along with the formula, we can calculate the velocity of the ball after 3 seconds of freefall:

v = 0 m/s + (9.81 m/s² × 3 s)

  = 29.4 m/s

Answer:

2.3 m/s2

Explanation:

F = ma

a = F/m

a = 10.8 / 4.6

a = 2.3 m/s2

I hope this helps.

Static friction is the type of force (force A) that keeps the eraser from falling when it is pressed against the chalkboard. The static friction force arises when two surfaces are in contact and there is no relative motion between them.

The force that keeps the eraser from falling is static friction. When the eraser is pressed against the chalkboard, a normal force (due to gravity) acts on it, pushing it perpendicular to the surface. Simultaneously, a horizontal force is exerted on the eraser by the finger. The static friction force arises as a response to this applied force, acting in the opposite direction to prevent the eraser from sliding down. As long as the applied force does not exceed the maximum static friction force, the eraser remains stationary. Once the applied force exceeds this threshold, the static friction force can no longer oppose it, and the eraser begins to slide, transitioning to kinetic friction.

learn more about Static friction here:

https://brainly.com/question/17140804

#SPJ11

Answer:

D

Explanation:

this is because the formula for frequency is

f = 1/T

and it is a reciprocal

Answer:

I tried and could not understand it sorry

Explanation:

The conditions that must be satisfied for momentum to be conserved in a system are; The total external force acting on a system must be zero. In other words, the net force on the system must be zero.

If there is no net force on the system, the momentum of the system will remain constant with time.The mass of the system must remain constant with time. If the mass of the system is changing with time, the momentum of the system will also change with time. Therefore, it is essential to keep the mass of the system constant.

The collision must be elastic. In an elastic collision, the total kinetic energy of the system is conserved, and the momentum of the system is conserved. In other words, the system behaves as if there were no external forces acting on it. If the collision is not elastic, the total kinetic energy of the system will not be conserved. Instead, some of the kinetic energy will be converted into other forms of energy, such as thermal energy or sound energy.If the above three conditions are satisfied, the momentum of the system will be conserved.

To know more about momentum visit:-

https://brainly.com/question/30677308

#SPJ11

a. No, all of the heat that is added to the water while the water is boiling is converting the liquid state to the gas state.

When water reaches its boiling point, it undergoes a phase transition from the liquid state to the gaseous state. During this transition, the temperature of the water remains constant even though heat is continuously added to the system. This is because the heat energy is primarily used to overcome the intermolecular forces holding the water molecules together rather than increasing the average kinetic energy of the molecules.

In the liquid state, water molecules are held together by cohesive forces, such as hydrogen bonding. When heat is applied to the water, it increases the kinetic energy of the molecules, causing them to move faster. As the temperature of the water rises, the kinetic energy of the molecules increases, but the average potential energy due to intermolecular forces remains relatively constant.

Once the water reaches its boiling point, the added heat energy is used to break the intermolecular forces completely. As water molecules escape from the liquid surface and enter the gas phase, they take away energy in the form of latent heat of vaporization. This latent heat is used solely for the phase transition, and it does not contribute to an increase in temperature.

As a result, the temperature of the boiling water remains constant until all the liquid water has been converted into water vapor. Only after the phase transition is complete and all the water has evaporated will further heat addition lead to an increase in temperature.

Therefore, during the process of boiling, the water temperature does not change as the heat energy is primarily utilized for the conversion of the liquid state to the gas state.

Learn more about gas state here :-

https://brainly.com/question/20593928

#SPJ11

After t = 4 seconds, ascertain the baseball's vx and vy horizontal and vertical speeds. Only the pressure applied on the object's vertical component—gravity—is recognized by us. This indicates that the perpendicular speed is unchanged.

A planet and maybe other bodies pull objects toward their centers through their gravitational force. The gravitational attraction of the sun keeps all of the planets in their orbit around it.

The size of an object and its distance from other things both have an impact on gravity. The mass of a thing is a gauge for its matter content. A heavier object will fall to the ground more quickly than a lighter one. Gravitational pull weakens when the separation between two objects grows.

To know more about gravity visit:

https://brainly.com/question/14874038

#SPJ4

When the slit spacing in a diffraction grating increases, so does the distance between neighboring slits. As a result, the number of slits per unit length decreases, causing the diffraction pattern to widen out.

Light is diffracted by each individual slit in a diffraction grating, and the diffracted waves interact constructively or destructively to generate a diffraction pattern. The phase difference between the waves is determined by the distance between the slits, which influences the interference pattern.

The interference pattern grows increasingly spread out as the slit spacing rises, as does the distance between the brilliant fringes. This implies that the diffraction grating may resolve spectral lines that are closer together, resulting in increased spectral resolution. Increasing the slit spacing, on the other hand, reduces the intensity of the diffracted light since less light goes through each individual slit.

Overall, increasing the slit spacing alters the physical configuration of the diffraction grating by changing the interference pattern and spectral resolution, as well as the intensity of the diffracted light.

Learn more about Diffraction:

https://brainly.com/question/30035662

#SPJ4

Answer:

\(\huge\boxed{\sf Circumstellar\ discs }\)

Explanation:

Astronomers discovered matter made up of gas, dust or asteroids etc. around nearby stars. This matter is called circumstellar disc (due to it being ring-shaped). These circumstellar discs are materials out of which planets form.

\(\rule[225]{225}{2}\)

Hope this helped!

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

                 \(P=\frac{F}{A}\)

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

             \(P=1atm=1.013*10^5Pascals\)

            \(F=mg=P*A=1.013*10^5*4.5=4.56*10^5N\)

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

Learn more about the pressure here:

https://brainly.com/question/12830237

#SPJ4

Answer:

1226.25 N

Explanation:

w = mg = 125 (9.81) = 1226.25 N

Answer:

G = 6.67

Explanation:

The elongation of the aluminium rod subjected to an axial tensile load is 0.00239 mm. So, the 3rd option is correct.

It is given to us that -

Initial length of the aluminium rod = 15 mm

Diameter of the aluminium rod = 37 mm

Axial tensile load on the aluminium rod = 65 kN

We have to find out the elongation of the aluminium rod in mm.

The deformation (in this case, elongation) of an aluminium rod with specific length and diameter which is subjected to an axial tensile load can be represented in the form of an equation given by -

δ = \(\frac{P*L}{A*E}\) ----- (1)

where,

δ = Deformation of the rod

P = Axial tensile load

L = Length of the rod

A = Area of the rod

E = \(2*10^{5}\) \(N/mm^{2}\)

According to the given information, we have

P = 65kN = \(65*10^{3}\) N

L = 15 mm

A = \(\frac{\pi }{2} d^{2}\) where d is diameter of rod

Substituting these values in equation (1), we have

δ = \(\frac{P*L}{A*E}\)

=> δ = \(\frac{65*10^{3}*15}{\frac{\pi }{2} (37)^{2}*2*10^{5}}\)

=> δ = 0.00239 mm

Thus, the elongation of the aluminium rod subjected to an axial tensile load is 0.00239 mm. So, the 3rd option is correct.

To learn more about tensile load visit https://brainly.com/question/15208291

#SPJ4

Answer:

t = 0 1.697 seconds

Explanation:

Comment

This is a standard question where the time is the same for both the vertical distance the ball has to drop and the time it takes to go horizontally.

Formulas

dv = vi*t + 1/2 a t^2

dv is the vertical distance that the ball has to travel in a downward direction

dh = vh * t

Givens

a = 9.81

dv = 1.44

vi = 0

t = ?

dh = 2 m

t = same as above (but not given)

Solution

dv = 1/2 a * t^2

1.44 = 1/2 * 9.81 *t^2                 Multiply by 2

2*1.44 = 1/2 * 2 * t^2

2.88 = t^2

t = 1.697 seconds

Note that you do not have to use the horizontal information to get the time. You only have to realize that the ball has no vertical velocity to begin with.

Answer:

down below in image

Explanation:

The magnitude of the electric field is approximately 46,822 N/C.

To find the magnitude of the electric field, we can use the equation:

E = F / q

Where:

E is the electric field strength

F is the force acting on the mass

q is the charge on the mass

Given:

Mass (m) = 43 grams = 0.043 kg

Charge (q) = 9 μC = 9 × 10^(-6) C

Gravity (g) = 9.8 m/s² (acceleration due to gravity)

The force acting on the mass is the gravitational force:

F = m g

Substituting the values:

F = 0.043 kg × 9.8 m/s²

F = 0.4214 N

Now  calculate the electric field strength:

E = F / q

E = 0.4214 N / 9 × 10^(-6) C

E = 46,822 N/C

Therefore, the magnitude of the electric field is approximately 46,822 N/C.

To know more about magnitude

https://brainly.com/question/31022175

#SPJ2

Answer:

a) La magnitud del desplazamiento es de 5 m

La magnitud de la fuerza es 20 N

b) El trabajo realizado por la fuerza es de 100 J

c) El ángulo entre la fuerza y el plano es 0 °

Explanation:

a) La magnitud del desplazamiento se encuentra por la relación;

\(\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}\)

Lo que da;

\(\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m\)

De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;

\(\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}\)

Lo que da;

\(\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N\)

b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X

∴ Ancho = 20 N × 5 m = 100 N · m = 100 J

c) La dirección de la fuerza viene dada por la siguiente fórmula;

\(tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right ) = 38.9^{\circ}\)

La dirección del plano viene dada por la siguiente fórmula;

\(tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right ) = 38.9^{\circ}\)

Por tanto, el ángulo entre la fuerza y el plano = 0 °

La fuerza actúa a lo largo del plano.

Answer:

Explanation:

thumbs down

thumbs up

thumbs up

thumbs down

thumbs up

Answer:

64 ohms =R

Explanation:

R is directly proportional to V

R is inversely proportional to I(Current

Sources of mineral resources are most commonly magma, sediments, or hydrothermal fluids.

Examples of mineral resources are iron, diamond, gold, silver, copper, aluminum, granite, marble, clay, salt, rare earths or fossil fuels.

What are mineral resources?

A mineral resource is a concentration of natural solid inorganic or fossilized organic matter, including metals, coal and minerals, in sufficient quantity and quality to have reasonable prospects for economic exploitation. This definition has a broader scope than mineral reserves that are likely to be economically recovered based on consideration of technical, economic, and legal concerns.

Mineral resources means minerals, naturally occurring solid inorganic substances, or naturally occurring solid fossilized organic substances (including base metals, precious metals, coal and industrial minerals), in or on the earth's crust, such Means concentrated or occurring in form and quantity and in its grade or quality. There are reasonable prospects for economic development. The location, quantity, grade, geological features and continuity of Mineral Resources are known, estimated or interpreted on the basis of specific geological evidence and knowledge.

To know more about mineral resources, visit:

https://brainly.com/question/24514288

#SPJ1