What is the pH of an aqueous solution of 4.83×10-2 M barium hydroxide?pH =

Answer:

B and C

Explanation:

is it multiple choice question??

Van der Waals forces are the interaction between the molecules and the atoms. It increases with an increase in the molecular size and the number of electrons. Thus, options B and C are correct.

Van der Waals forces are the weak forces of attraction and repulsion present between the atoms and the molecules of the compounds. They are also called London Dispersion Forces and dipole-dipole forces.

An increase in the number of electrons and size of the molecule increases the surface area and the electron cloud which in turn, increases the Van der Waals force.

The intermolecular force increases as in large atoms or molecules the valence are held loosely as they are far from the nucleus or the center of the atom.

Therefore, the size and the electron increase the Van der Waals force.

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The addition of 2 mL of 6.0 M HCl caused the equilibrium to shift in the reverse direction.

This is because the HCl added to the solution decreases the amount of SbClz in solution. This dilutes the solution by increasing the total volume, and increases the moles of H' and CH in solution.

To reach equilibrium, the system must increase the amount of reactants, so an equilibrium shift in the reverse direction is observed. The reaction of the SbClz in solution with the added H' and Cl' in solution also contributes to the shift in equilibrium, as more products are formed. The net effect of the addition of HCl is an equilibrium shift in the reverse direction.

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Answer:

59.92 × 10²³ atoms are in 9.95 moles of iron

1.8 ×10²² molecules are in 0.03 moles of Carbon dioxide

1.19 moles are found in 7.20 x 10^23 atoms of platinum

The decomposition rate (k) for the leaves in the Coweeta forest stand is 0.4502 per year.

The decomposition rate (k) can be calculated using the litterbag method formula: k = -ln(m₂/m₁)/t, where m₁ is the initial mass of the sample, m₂ is the mass of the sample after time t, and ln is the natural logarithm.

In this case, m₁ = 100 g, m₂ = 30 g, and t = 2 years.

Plugging these values into the formula, we get

k = -ln(30/100)/2 = 0.4502.

This means that the leaves in the Coweeta forest stand have a decomposes at rate of 0.4502.

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The concentration of nitric acid in moles per litre in a sample with a density of 1.412 g l-1 and a mass percent of HNO3 of 69 % is 0.01547 mol l-1.

The concentration of nitric acid (HNO3) in moles per litre in a sample with a density of 1.412 g l-1 and a mass percent of HNO3 of 69 % can be calculated as follows:
1. Convert the mass percent of HNO3 to grams per litre by multiplying 69 % by 1.412 g l-1. This gives us 0.972 g l-1.
2. Determine the molecular weight of nitric acid (HNO3). This is 63.01 g/mol.
3. Divide the amount of nitric acid in grams (0.972 g l-1) by the molecular weight of HNO3 (63.01 g/mol). This gives us 0.01547 mol l-1.
Therefore, The concentration of nitric acid in moles per litre in a sample with a density of 1.412 g l-1 and a mass percent of HNO3 of 69 % is 0.01547 mol l-1.

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Answer:

It is propyl amine.

as amine =H-N-H

and it contain 3C =prop

The oxidation number of manganese (Mn) in potassium permanganate (KMnO4) is B.  +7.

Potassium permanganate is a strong oxidizing agent that is commonly used in organic chemistry to oxidize alcohols, aldehydes, and ketones to carboxylic acids. Its formula is KMnO4.The oxidation state of manganese in KMnO4 is determined by subtracting the sum of the oxidation states of potassium, oxygen, and hydrogen from the overall charge of the molecule. The oxidation state of potassium is +1, and the oxidation state of oxygen is -2. Hydrogen's oxidation state is +1, and it is usually removed from the organic compound in question, so it is not included in the final calculation. For KMnO4, the overall charge is -1. Using this information,

we can calculate the oxidation state of manganese as follows: Oxidation state of Mn + Oxidation state of K + 4(Oxidation state of O) = -1Oxidation state of Mn + 1 + 4(-2) = -1Oxidation state of Mn - 7 = -1 Oxidation state of Mn = +7Therefore, the oxidation state of manganese in potassium permanganate is +7. Therefore the correct option is B

The complete question is :

What is the oxidation number of manganese (MN) in potassium permanganate (KMnO4)?

A. +5,

B. +7,

C. +8,

D. +9

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Answer:

NaOH(aq) + HCl(aq) --- NaCl(aq) +H2O(l)

Explanation:

Neutralization reaction occurs when an acid and a base react together to give salt and water. So NaCl is the salt produced in this reaction with H2O (Water)

The pressure inside a container of gas increases if more gas is added to the container due to the increase in the number of molecules striking the walls of the container per unit time and the increase in the force of the collisions between the molecules and the walls of the container.

Pressure is defined as force per unit area and is usually measured in atmospheres (atm), millimeters of mercury (mmHg), or kilopascals (kPa).The molecules of gas in a container are in constant motion and collide with the walls of the container. When more gas is added to the container, the molecules have less space to move around and collide with the walls more frequently.

This leads to an increase in the number of collisions per unit time and therefore an increase in the force per unit area exerted on the walls of the container. This increase in force leads to an increase in pressure inside the container.In summary, the pressure inside a container of gas increases if more gas is added to the container due to an increase in the number of collisions and the force of the collisions between the molecules and the walls of the container.

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The standard entropy change  ∆s° for the reaction c(g) + 2H₂(g) → CH₄(g) is -80.7 J/K*mol.

To calculate ∆s° for the reaction c(g) + 2H₂(g) → CH₄(g), we need to use the standard entropy values for each of the species involved in the reaction.

The standard entropy of carbon in its gaseous state (c(g)) is 5.7 J/K*mol. The standard entropy of hydrogen in its gaseous state (H₂(g)) is 130.6 J/K*mol. The standard entropy of methane in its gaseous state (CH₄(g)) is 186.3 J/K*mol.

Using these values, we can calculate the standard entropy change (∆s°) for the reaction as follows:

∆s° = ∑S°(products) - ∑S°(reactants)
∆s° = [S°(CH₄(g))] - [S°(c(g)) + 2S°(H₂(g))]
∆s° = [186.3 J/K*mol] - [5.7 J/K*mol + 2(130.6 J/K*mol)]
∆s° = [186.3 J/K*mol] - [267 J/K*mol]
∆s° = -80.7 J/K*mol

Therefore, the standard entropy change for the reaction c(g) + 2H₂(g) → CH₄(g) is -80.7 J/K*mol.

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Answer:

3. C6H12O6 → 2CH3CH2OH + 2CO2

Explanation:

 In fermentation a catabolic process occurs, where an organic substance (C6H12O6) is transformed into a simpler one (CH3CH2OH), through incomplete oxidation, which does not require oxygen. Sugars are transformed into ethyl alcohol and carbon dioxide.

The equation C₆H₁₂O₆ → 2CH₃CH₂OH + 2CO₂ represents fermentation

Fermentation is an enzyme catalyzed, metabolic process whereby organisms convert starch or sugar to alcohol or an acid anaerobically releasing energy.

In this process a large molecule is broken down to a smaller molecule.

Among the Equations given Equation 3  

C₆H₁₂O₆ → 2CH₃CH₂OH + 2CO₂

represents fermentation due to two reasons

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The appropriate symbol for an isotope of potassium-39 using isotope notation would be written as "39K".

The isotope notation, also known as nuclear notation, is used to represent different isotopes of an element. It consists of the element's atomic number (Z), the element's symbol (A), and the mass number (X). The atomic number represents the number of protons in the nucleus of an atom and is used to determine the element to which an atom belongs. The mass number represents the total number of protons and neutrons in the nucleus of an atom. The symbol represents the element to which the isotope belongs.

In this case, 39 is the mass number (X) and K is the symbol of the element Potassium (A).

So, in isotope notation for Potassium-39 it would be represented as 39K.

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Answer:

The volume of the gas when it is released from the tanks will be equal to 10.00 L x (150.0 mmHg / 3.400 x 10⁴ mmHg) = 0.004412 L.

Explanation:

An amino acid is a hydrocarbon in which one or more hydrogen atoms are replaced by a -COOH (carboxyl) and a -NH₂ (amine) group. The correct answer is an amino acid.

Amino acids are classified into two groups: essential and non-essential. Essential amino acids cannot be synthesized by the body and must be obtained from dietary sources, while non-essential amino acids can be synthesized by the body.

Amino acids are the building blocks of proteins and play essential roles in biological processes. They consist of an amino group, a carboxyl group, and a variable side chain (R group) that gives each amino acid its unique properties. The presence of both the carboxyl and amino groups makes amino acids amphoteric, meaning they can act as both acids and bases in chemical reactions.

Therefore, a compound that fits the description of a hydrocarbon in which one or more hydrogen atoms are replaced by a -COOH (carboxyl) and a -NH₂ (amine) group is called an amino acid.

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A) HCO3- , carbonic acic

The ratio indicates that the hydrogen ion concentration of chemical A is 0.158 times lower than that of chemical B. Alternatively, the hydrogen ion concentration of chemical B is 6.31 times more acidic than that of chemical A.

The pH value of a substance is an essential indicator of its acidity or alkalinity. The pH scale ranges from 0 to 14. The midpoint of the scale is 7.0, which is neutral. Solutions with pH values below 7.0 are acidic, while those with pH values above 7.0 are alkaline.

Acid solutions have a high concentration of hydrogen ions. The negative logarithm of the hydrogen ion concentration (H+) is referred to as the pH. Similarly, solutions with a high hydroxide ion concentration have high pH values. The formula for pH is pH = -log[H].

1. Calculation of [H+] for Chemical A:Hence, we can rearrange the pH equation to calculate the hydrogen ion concentration as follows:[H] = 10^-pH= 10^-9= 1.0 × 10^-9 mol/L2. Calculation of [H+] for Chemical B:pH = -log[H]log[H] = -pHlog[H] = -8.2[H] = 10^-pH[H] = 6.31 × 10^-9 mol/L3.

Calculation of the ratio of [H+] for Chemical A and Chemical B:The ratio of [H+] for chemical A to that of chemical B can be found using the following formula:Ratio = [H+] of Chemical A / [H+] of Chemical B= (1.0 × 10^-9) / (6.31 × 10^-9)= 0.158The ratio indicates that the hydrogen ion concentration of chemical A is 0.158 times lower than that of chemical B. Alternatively, the hydrogen ion concentration of chemical B is 6.31 times more acidic than that of chemical A.

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A chemical reaction has a Q10 of 3 option  c. a rate of 9 at 20°C and 3 at 30°C is the rates that characterizes this reaction

The Q10 value is a measure of how much the rate of a chemical reaction changes with a 10°C change in temperature. A Q10 of 3 indicates that the rate of the reaction will increase by a factor of 3 when the temperature is raised by 10°C.

Looking at the answer choices, we can see that option a and b have a Q10 value of 2, which is not the same as the given Q10 value of 3. Option e has a Q10 value of 4, which is also not the same.

Option d has a Q10 value of 3, but the rates given are at 20°C and 40°C, which is not a 10°C change in temperature.

Therefore, the only option that fits the given Q10 value and has rates that are 10°C apart is option c, which has a rate of 9 at 20°C and 3 at 30°C. Therefore, the answer is c.

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Option c states that the rate of the reaction is 9 at 20°C and 3 at 30°C. The ratio of rates between 20°C and 30°C is 9/3 = 3, which matches the Q10 value of 3.  

c. a rate of 9 at 20°C and 3 at 30°C

The Q10 value is a measure of the temperature sensitivity of a reaction, and it is defined as the factor by which the rate of a reaction changes for every 10-degree Celsius change in temperature. A Q10 value of 3 indicates that the rate of the reaction increases by a factor of 3 for every 10-degree Celsius increase in temperature.

This means that the rate of the chemical  reaction is consistent with the temperature sensitivity indicated by the given Q10 value, making option c the correct answer.

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The chemist should observe the formation of solid copper metal, a change in color of the solution, and the disappearance of the aluminium foil through this unbalanced equation.

The balanced equation for the reaction between copper (II) chloride and aluminum is:

3CuCl2 + 2Al → 2AlCl3 + 3Cu

In this reaction, aluminum replaces copper in the copper chloride solution to form aluminium chloride and copper metal.

The likely observations when the reaction stops are:

1. The solution may change color, indicating that a chemical reaction has occurred. Copper (II) chloride is blue, while aluminum chloride is colorless.

2. Solid copper metal may form and settle at the bottom of the container, indicating that a precipitation reaction has occurred.

3. The aluminum foil may appear to have dissolved or disintegrated, as it has been consumed in the reaction.

4. The reaction mixture may become warmer due to the exothermic nature of the reaction.

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The resulting pH of the solution formed by adding 200 ml of 0.30 M formic acid to 400 ml of water, with a pKa of 3.75, is approximately 2.3.

To determine the resulting pH of the solution, we need to consider the dissociation of formic acid (HCOOH) in water. Formic acid is a weak acid that partially dissociates into hydrogen ions (H⁺) and formate ions (HCOO⁻). The dissociation constant of formic acid is represented by pKa, which is equal to -log(Ka), where Ka is the acid dissociation constant.

Given the pKa of formic acid as 3.75, we can use the Henderson-Hasselbalch equation to calculate the pH:

pH = pKa + log([A⁻]/[HA])

In this case, [A⁻] represents the concentration of the formate ions and [HA] represents the concentration of the undissociated formic acid. The total volume of the resulting solution is 200 ml + 400 ml = 600 ml.

Using the given concentration of 0.30 M formic acid, we can calculate the concentration of formate ions ([A⁻]) and undissociated formic acid ([HA]):

[HA] = concentration of formic acid = 0.30 M x (200 ml/600 ml) = 0.10 M

[A⁻] = concentration of formate ions = 0.30 M x (400 ml/600 ml) = 0.20 M

Substituting these values into the Henderson-Hasselbalch equation:

pH = 3.75 + log(0.20/0.10) = 2.3 (rounded to one decimal place)

Therefore, the resulting pH of the solution is approximately 2.3 when 200 ml of 0.30 M formic acid is added to 400 ml of water with a pKa of 3.75.

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Complete Question:

if 200ml of 0.30M formic acid is added to 400 ml of water, what is the resulting PH of the solution? round the answer to one decimal place Pka 3.75

Answer:

B their larger size . this is right

Answer:

The answer is B. here is proof. Plz mark brainliest.

Explanation:

Answer: D?  

Explanation: The mitochondrion (plural mitochondria) is a membrane-bound organelle found in the cytoplasm of eukaryotic cells. It is the power house of the cell; it is responsible for cellular respiration and production of (most) ATP in the cell.

The influence of various wet chemical treatments on the germanium wafer surface has been examined. The GeO2 part of the native oxide is readily dissolved in water. The solubility of the GeO2 in aqueous solutions and the fast oxidation of germanium makes commonly used silicon treatments nonapplicable due to the relatively high etch rates. In various etching chemistries, the underlying suboxide is not attacked. A hydroxylated suboxide might be an ideal starting surface for ALD, because of its low contribution to electrical thickness. HBr removes even the suboxide and yields a completely oxide-free germanium surface which makes it a candidate surface preparation technique for epitaxial growth. The same result is obtained using a HI dip followed by a DIW rinse. Oxide is growing in CR-air, while in N 2 ambient the surface remains stable.

An oxide is a category of chemical compound that has one or more oxygen atoms as well as another element in its composition such as Li2O, CO2, H2O, etc.

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Answer:

Introduction. Alongside fat and protein, carbohydrates are one of the three macronutrients in our diet with their main function being to provide energy to the body. They occur in many different forms, like sugars and dietary fibre, and in many different foods, such as whole grains, fruit and vegetables.

Explanation:

pleaseee consider as brainlest if i helped you

Answer:

I think that the statement is relative to speed because it is saying km per second.

Answer:

Speed

Explanation:

Answer:

Burning of the candle is both physical and chemical change. Burning of the candle melts the wax and hence physical state of wax has changed from solid to liquid.  

Again the wax combines with the atmospheric oxygen and changes to carbon dioxide, heat and light.  

Thus both the changes are accompanied by the burning of the candle.

Explanation:

hope this helps!

~mina

Answer:

23.29+2.14=25.313es la respuesta

Answer:

S Atomic mass:  32.06 AMU

Al Atomic mass:  26.98 AMU

S Molar mass:    32.06 g/mole

Al Molar mass:​    26.98 g/mole

Explanation:

The Periodic Table has the unique property that the atomic masses are numerically the same as the molar masses. Thus, g/mole may be subastituted for AMU:  they are equivalent.  Just change AMU to g/mole.

The molarity of copper sulfate in the diluted solution if 4 ml of 0.0250 m cuso4 is diluted to 10.0 ml with pure water is 0.02M.

Molarity is defined as the ratio of moles of solute to the volume of solution.

Mathematically,

Molarity = moles of solute / volume of solution

Given,

Initial volume of CuSO4 = 4 ml = 4/1000 = 0.004 l

Molarity of CuSO4 = 0.0250 m

By substituting all the values, we get

0.025 = moles/ 0.004

moles = 0.025 × 0.004 = 0.000100 mol

Moles = 0.0001 mol.

Total volume = 0.004 l + 10 ml

= 0.004 + 0.001 = 0.005 l

Moles of CuSO4 = 0.0001 mol

Molarity = 0.0001 / 0.005 = 0.02 M

Thus, we concluded that the molarity of copper sulfate in the diluted solution if 4 ml of 0.0250 m cuso4 is diluted to 10.0 ml with pure water is 0.02M.

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