Answers
I looked it up
Answer:
b. 4.5
Explanation:
Since it is hydronium ion concentration, that means it is an acid.
pH formula = -log[H3O+]
-log(3.2 x 10^{-5} = 4.5
Related Questions
Which portion of a molecule of F2O has partial positive charge?
Question 3 options:
A)
The F atoms
B)
The central O atom
C)
The partial charge on each atom is zero
D)
The partial charge on each atom is negative
Answers
The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B
The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of \(F_2O\), fluorine (F) is more electronegative than oxygen.
Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.
In \(F_2O\), each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.
Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.
Option B
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calculate the number of moles for the quanity 8.06 x 1021 atoms of Pt
Answers
The number of moles for the quanity 8.06 x\(10_{21\) atoms of Pt is approximately 2.61 grams.
To calculate the number of moles for a given quantity of atoms, we can use Avogadro's number and the molar mass of the element. Avogadro's number is 6.022 x 10²³ atoms/mol.
In this case, you have 8.06 x 10²¹ atoms of Pt. To find the number of moles, divide this quantity by Avogadro's number:
8.06 x 10²¹ atoms Pt / 6.022 x 10²³ atoms/mol = 0.0134 mol Pt
So, there are approximately 0.0134 moles of Pt in 8.06 x 10²¹ atoms of Pt.
The molar mass of Pt (platinum) is 195.08 g/mol. To convert the number of moles to grams, multiply the number of moles by the molar mass:
0.0134 mol Pt x 195.08 g/mol = 2.61 g Pt
Therefore, there are approximately 2.61 grams of Pt in 8.06 x10²¹ atoms of Pt.
In summary, the number of moles for the quantity 8.06 x 10²¹ atoms of Pt is approximately 0.0134 moles. This is equivalent to approximately 2.61 grams of Pt. Remember to use Avogadro's number and the molar mass to perform these calculations accurately.
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What happens to the energy produced by blocks of Earth's crust slipping past each other? (1 point)
O It disappears at it moves through the crust.
OIt spreads out in random directions.
OIt radiates outward in all directions.
OIt increases as it reaches the surface.
Answers
What happens to the energy produced by blocks of Earth's crust slipping past each other is it radiates outward in all directions. (Option C).
What happens to the energy?When blocks of the Earth's crust slip past each other during an earthquake, the energy that is released does not disappear, spread out randomly, or increase as it reaches the surface.
Instead, the energy radiates outward in the form of seismic waves. These seismic waves travel through the Earth in all directions from the point of the earthquake's origin causing the ground to shake.
The energy carried by these waves is what is felt as the shaking during an earthquake and can be detected and measured by seismometers.
Thus, what happens to the energy produced by blocks of Earth's crust slipping past each other is it radiates outward in all directions.
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how do i solve this? The EA values are:Argon -1.0 Cesium 45.5Selenium 195.0Phosphorus 72Bromine 324.6
Answers
Answer
Explanation
Electron affinity is one of the periodic properties of elements in the periodic table. The electron affinity of an atom or molecule is the propensity for that particle to gain an electron.
There are general trends in electron affinity across and down the periodic table of elements. Electron affinity generally increases across a period in the periodic table and sometimes decreases down a group.
Therefore the EA ranking of the given elements from most positive to most negative are:
NaBr(aq) + F2(g) ->NaF(aq)+Br2(g)
Single Replacement
Synthesis
O Double Replacement
Decomposition
Combustion
O Acid/Base Neutralization
Answers
Answer: Single Replacement
Explanation:
This is single replacement because the Fluorine replaces Bromine in the Sodium Bromide solution. This happens because Fluorine is higher on the halogens activity series.
6. Observe the reaction below and choose the best answer which completes the
reaction.
C-C=C + HOH ===> ?
(will you be able to determine the answer?)
Answers
Answer:
The answer to this reaction would be C-C-OH + H2.
write any two differences between autotrophs and heterotrophs . subject-science
Answers
Answer:
Autotrophs are organisms that prepare their own food through the process of photosynthesis, whereas heterotrophs are organisms that cannot prepare their own food and depend upon autotrophs for nutrition.
Explanation:
Btw I searched this up found it on a website called byjus.com. Hope this helps!
How do you know the correct number of significant figures to include in an answer?
Answers
Answer:
Explanation:
1 Non-zero digits are always significant.
2 Any zeros between two significant digits are significant.
3 A final zero or trailing zeros in the decimal portion ONLY are significant.
What is the molar mass
MgCrO4
Answers
The molar mass of MgCrO4 is approximately 140.30 g/mol.
To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.
The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).
The atomic masses of the elements can be found on the periodic table:
Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.
Chromium (Cr) has an atomic mass of around 51.99 g/mol.
Oxygen (O) has an atomic mass of about 16.00 g/mol.
Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:
Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)
Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)
Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol
Molar mass ≈ 140.30 g/mol
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hot lead with a mass of 200.0 g of (Specific heat of Pb = 0.129 J/gºC) at 176.4°C was dropped into a calorimeter containing an unknown volume of water. The temperature of the water increased from 21.7°C to 56.4°C. What volume of water is in the calorimeter?
Answers
the Calorimetry relationships you can find the amount of water in the calorimeter is m = 21.3 g
given parameters
Lead mass M = 200.0 gInitial lead temperature T₁ = 176.4ºCSpecific heat of Lead \(c_{e Pb}\) = 0.129 J / g ºCSspecific heat of water \(c_{e H_2O}\) = 4.186 J / g ºCInitial water temperature T₀ = 21.7ºCEquilibrium temperature T_f = 56.4ºCto find
The body of water
Thermal energy is the energy stored in the body that can be transferred as heat when two or more bodies are in contact. Calorimetry is a technique where the energy is transferred between the body only in the form of heat and in this case the thermal energy of the lead is transferred to the calorimeter that reaches the equilibrium that the thematic energy of the two is equal
Q_{ceded} = Q_{absorbed}
Lead, because it is hotter, gives up energy
Q_{ceded} = M c_{e Pb} (T₁ - T_f)
The calorimeter that is colder absorbs the heat
Q_{absrobed} = m c_{e H_2O} (T_f - T₀)
where M and m are the mass of lead and water, respectively, c are the specific heats, T₁ is the temperature of the hot lead, T₀ the temperature of cold water and T_f the equilibrium temperature
M c_{ePb} (T₁ - T_f) = m c_{eH2O} (T_f - T₀)
m = \(\frac{ M\ c_{ePb} \ (T_1 - T_f)}{c_{eH_2O} \ (T_f - T_o)}\)
let's calculate
m = \(\frac{200 \ 0.129 (176.4-56.4)}{ 4.186 \ (56.4 -21.7)}\)
m = 3096 / 145.25
m = 21.3 g
Using the Calorimetry relationships you can find the amount of water in the calorimeter is:
m = 21.3 g
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How many moles of gas will occupy a volume of 5.50 L at 6.20 kPa and 45.0 °C?
Answers
even one or two crystals of copper sulphate can make its solution in water coloured blue. why
Answers
this also may happen because of the water molecules that get attached
4 Al(s) + 302(g)2Al2O3(s)How many grams of Al2O3 can be formed from 99.20 g of Al and 30.22 g of O2?(Hint: You need to determine which one is the limiting reactant).
Answers
First, we have to convert each compound to moles, using the molar mass of each of them. The molar mass of Al is 27 g/mol and the molar mass of O2 is 32 g/mol (you can calculate the molar mass using the periodic table).
The conversion for 99.20 g of Al and 30.22 g of O2 would be:
\(99.20\text{ g Al}\cdot\frac{1\text{ mol Al}}{27\text{ g Al}}=3.674\text{ moles Al.}\)\(30.22gO_2\cdot\frac{1molO_2}{32gO_2}=0.9444molesO_2.\)Now, let's see how many moles of Al2O3 each of them produces. In the reaction, you can see that 4 moles of Al produce 2 moles of Al2O3:
\(3.647\text{ moles Al}\cdot\frac{2molesAl_2O_3}{\text{4 moles Al}}=1.824\text{ moles }Al_2O_3.\)And 3 moles of O2 produce 2 moles of Al2O3:
\(0.944molesO_2\cdot\frac{2\text{ moles }Al_2O_3}{3molesO_2}=0.6293\text{ moles }Al_2O_3.\)You can realize that we can just produce a minimum of 0.6293 moles of Al2O3 because there is an excess of Al, meaning that the limiting reactant is O2 and we take into account the number of moles of Al2O3 (0.6293 moles) produced by this compound.
The final step is to convert from 0.6293 moles of Al2O3 to grams using the molar mass of Al2O3 which is 102 g/mol:
\(0.6293\text{ moles }Al_2O_3\cdot\frac{102\text{ g }Al_2O_3}{1\text{ mol }Al_2O_3}=64.19\text{ g }Al_2O_3.\)The answer would be that we're producing 64.19 g of Al2O3 from the reaction of 99.20 g of Al and 30.22 g of O2.
how does terrain affect forest fires
Answers
The terrain can have a significant impact on the behavior and spread of forest fires. Understanding the terrain and its effect on fires can help firefighters and land managers develop effective strategies for preventing and managing wildfires.
How does terrain affect forest fires?
Terrain plays a significant role in the behavior and spread of forest fires. Here are some ways that terrain can affect forest fires:
Slope: The slope of the terrain can affect the speed and direction of the fire. Fires tend to spread faster uphill due to the preheating effect of the rising heat, which dries out the fuel and ignites it more easily. Steep slopes can also create a chimney effect, where hot gases and flames rise rapidly, increasing the intensity of the fire and making it more difficult to control.
Aspect: The aspect, or the direction that a slope faces, can also impact the behavior of a forest fire. South-facing slopes tend to be warmer and drier, and may ignite more easily. North-facing slopes, on the other hand, may be cooler and moister, and may not burn as easily.
Topography: The topography of the terrain can affect the spread of fire by creating wind patterns, funneling the fire, or obstructing firefighting efforts. For example, canyons, ridges, and valleys can channel and accelerate the spread of the fire, while cliffs, boulders, and waterways can create natural fire breaks that help to contain the fire.
Fuel type and density: The type and density of vegetation in a forest can vary depending on the terrain. For example, steep slopes may have thinner vegetation cover, while flat areas may have thicker vegetation. The type of vegetation can also vary by elevation, with lower elevations having more grasses and shrubs, and higher elevations having more trees. Different types of vegetation burn at different rates and temperatures, and can affect the intensity and behavior of the fire.
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If one of your samples had a mass of 25.62 g and a volume of 21.9 cm3, would this sample also be the same material you have been working with
Answers
Answer:
If the density of the material is equal to the density of the material you have been working with it is possible that the samples are the samples
Explanation:
Density is an intensive property of the matter (Doesn't depends of its amount) that is widely used to identify a substance. Density is the ratio between the mass of the substance (In this case 25.62g) and the volume this amount occupies (21.9cm³). The density is:
25.62g / 21.9cm³ =
1.17g/cm³.
If the density of the material is equal to the density of the material you have been working with it is possible that the samples are the samplesRepeating many forms a crystal structure inside each of these repeated units is the ?
Answers
Answer:
unit cells; lattice
Explanation:
Which situation provides the best evidence that a chemical reaction is taking place?
A metal strip bends when heated.
A solution freezes in the freezer.
Two solutions mixed in a beaker produce a solid.
O A chemical completely dissolves in water and the temperature of the solution remains constant.
Answers
Answer: two solutions mixed in a beaker produce a solid
Explanation: it formed a new substance
ORDS ONLY. 71.A broad, painless, pink-gray, wart like infectious lesions may develop on the vulva, perineum, or anus in syphilis is called----- 72. In suspected syphilis infection the term RPR stands for? 73. The recommended dosage of Benzathine Penicillin in an adult in Zambia is je 74. The recommended drug for treatment of gonorrhea when using syndromic management is 75. The causative organism for chancroid is called- 76. The commonest type of HIV is 77.The assertive, problem solving approach to identification and treatment of the patient's problems is called --- 78. A tumour arising from the cells producing melanin is also known as 1 79. The type of sound described as drum like, loud, empty quality felt over gas-filled stomach, intestine or pneumothorax which is heard during percussion is called host wall into the pleural space to obtain
Answers
71. The broad, painless, pink-gray, wart-like infectious lesions that may develop on the vulva, perineum, or anus in syphilis are called "condyloma lata."
72. In suspected syphilis infection, the term RPR stands for "Rapid Plasma Reagin." It is a blood test used to screen for syphilis.
73. The recommended dosage of Benzathine Penicillin in an adult in Zambia may vary depending on the stage and severity of the syphilis infection. It is best to consult local guidelines or a healthcare professional for the specific recommended dosage in Zambia.
74. The recommended drug for the treatment of gonorrhea when using syndromic management may vary depending on local guidelines and antibiotic resistance patterns. Commonly used antibiotics include ceftriaxone in combination with azithromycin or doxycycline.
75. The causative organism for chancroid is called "Haemophilus ducreyi."
76. The commonest type of HIV is "HIV-1."
77. The assertive, problem-solving approach to the identification and treatment of the patient's problems is called "clinical decision-making."
78. A tumor arising from the cells producing melanin is also known as "melanoma."
79. The type of sound described as drum-like, loud, and empty quality felt over a gas-filled stomach, intestine, or pneumothorax during percussion is called "tympany."
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2 A high school student takes a lump of magnesium with a volume of 150.0 mL and adds it to a beaker of
an aqueous solution of aluminum nitrate. What is the mass of the solid aluminum that forms?
Solid magnesium has a density of 1.738 g/cm³.
Answers
The mass of the solid aluminum that forms are 192.73 grams
To determine the mass of solid aluminum that forms, we need to use stoichiometry and the balanced chemical equation for the reaction between magnesium and aluminum nitrate.
The balanced chemical equation is:
3 Mg + 2 Al(\(NO_{3}\))3 → 3 Mg(\(NO_{3}\))2 + 2 Al
The equation shows that 3 moles of magnesium react with 2 moles of aluminum to produce 2 moles of aluminum nitrate.
To calculate the mass of solid aluminum, we need to know the amount of magnesium used. Given that the volume of the magnesium is 150.0 mL and its density is 1.738 g/cm³, we can calculate the mass of magnesium using the formula:
Mass = Volume × Density
Mass of magnesium = 150.0 mL × 1.738 g/cm³ = 260.7 g
Now, using the molar mass of magnesium (24.31 g/mol) and the molar ratio from the balanced equation, we can determine the moles of magnesium used:
Moles of magnesium = Mass of magnesium / Molar mass of magnesium
= 260.7 g / 24.31 g/mol
= 10.72 mol
According to the stoichiometry of the balanced equation, the ratio of moles of magnesium to moles of aluminum is 3:2. Therefore, the moles of aluminum formed will be:
Moles of aluminum = (2/3) × Moles of magnesium
= (2/3) × 10.72 mol
= 7.15 mol
Finally, we can calculate the mass of solid aluminum using its molar mass (26.98 g/mol):
Mass of aluminum = Moles of aluminum × Molar mass of aluminum
= 7.15 mol × 26.98 g/mol
= 192.73 g
Therefore, the mass of the solid aluminum that forms is approximately 192.73 grams.
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Explain how they would make solutions of the sulfuric acid at five different concentrations
Answers
The sulfuric acid can be constituted into different concentrations using distilled water as a diluent.
What is dilution of acid?Dilution of acid is defined as the decrease in the concentration of an acid using water.
For sulfuric acid to be diluted, it is slowly added to distilled water using the following guidelines:
Add 150 ml of water to the beaker and add the desired amount of acid. This will give a diluted concentration of the given acid.Learn more about acid here:
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A pure substance made of two two or more elements that are chemically combined is a(n)
Answers
Answer:
A pure substance made up of two or more elements that are chemically combined is a compound
Explanation:
Mathematical Literacy/Gr.11 P1
Answers
Answer:
Mathematical Literacy refers to the ability to reason with quantitative expressions in comparative, proportional and percentage terms. It is this definition that most lends itself to an examination of skill levels across Canada's education system - which ones are required for success in society (in the simplest sense) and which ones are superfluous.
*ANSWER MADE BY AN AI*
Consider the titration of sulfuric acid with sodium hydroxide. What volume (mL) of a 2.658M NaOH solution is required to fully titrate 10.00mL of a 0.426M H2SO4 solution
Answers
The volume of base required to completely neutralize the acid is 3.2 mL of NaOH.
The equation of the reaction is;
2NaOH(aq) + H2SO4(aq) -----> Na2SO4(aq) + 2H2O(l)
From the question;
Concentration of acid CA = 0.426M
Concentration of base CB = 2.658M
Volume of acid VA = 10.00mL
Volume of base VB = ?
Number of moles of acid NA = 1
Number of moles of base NB = 2
Using the relation;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VB = CAVANB/CBNA
VB = 0.426M × 10.00mL × 2/ 2.658M × 1
VB = 3.2 mL
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The first-order rate constant for the decomposition of N2O5
2N2O5(g)→4NO2(g)+O2(g)
at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.70×10−2 mol of N2O5(g)
in a volume of 2.5 L
1) How many moles of N2O5 will remain after 7.0 min?
2)How many minutes will it take for the quantity of N2O5 to drop to 1.7×10−2 mol?
3)What is the half-life of N2O5 at 70 ∘C?
Answers
ln([N2O5]t/[N2O5]0) = -kt
where [N2O5]t is the concentration of N2O5 at time t, [N2O5]0 is the initial concentration of N2O5, k is the rate constant, and t is the time. Rearranging this equation, we get:
[N2O5]t = [N2O5]0 * e^(-kt)
Plugging in the given values, we get:
[N2O5]t = (2.70×10^−2 mol) * e^(-6.82×10^−3 s^-1 * 7.0 min * 60 s/min) = 1.20×10^−2 mol
Therefore, 1.20×10^−2 mol of N2O5 will remain after 7.0 min.
2) To calculate the time it takes for the quantity of N2O5 to drop to 1.7×10−2 mol, we can rearrange the equation from part 1 and solve for t:
t = -ln([N2O5]t/[N2O5]0)/k
Plugging in the given values, we get:
t = -ln(1.7×10^-2 mol/2.70×10^-2 mol)/(6.82×10^-3 s^-1) = 9.5 min
Therefore, it will take 9.5 min for the quantity of N2O5 to drop to 1.7×10^-2 mol.
3) The half-life of a first-order reaction is given by:
t1/2 = ln(2)/k
Plugging in the given rate constant, we get:
t1/2 = ln(2)/(6.82×10^-3 s^-1) = 101.6 s
Therefore, the half-life of N2O5 at 70°C is 101.6 s.
Dwight made this model using a golfball, a baseball, and a basketball
How could Dwight improve his model?
Group of answer choices
Make the moon smaller than the earth
Place the sun between the Earth and the moon
Place Earth between the moon and the sun
Use a flat object, such as a coin, to represent the objects
Answers
He could improve the model if he place Earth between the moon and the sun.
What is the model?We know that the solar system is composed of the sun and the planets and we can have a model of the solar system when we get together the sun and the other parts of the solar system as has been done in the model that was put together by Dwight .
Since the model was intended to show the eclipse of the moon then the model can be improved if he place Earth between the moon and the sun in the image of the model
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What is the product of the reaction?
Please answer with the correct answer! Thanks.
Answers
Answer:
compound
Explanation:
it is calcium oxide, also known as quicklime
In which of the following, are all the elements non-metals?
A. Na, Mg, O, N
B. C, Si, Ge, As
C. Fe, Ni, Cr, O
D. He, Ne, Ar, Kr
E. Ca, Ba, Sr, S
Answers
Answer:
The answer is D
Explanation:
Non metals are:
Hydrogen (H)
Sulphur (S)
Phosphorus (P)
Carbon (C)
Fluorine (F)
Oxygen (O)
Nitrogen (N)
Chlorine (Cl)
Bromine (Br)
Helium (He)
Argon (Ar)
Iodine (I)
Neon (Ne)
Krypton (Kr)
Radon (Rn)
Selenium (Se)
Xenon (Xe)
what mass of glucose c6h12o6 would be required to prepare 5000 mL of a 0.215 M solution
Answers
Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.
To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's convert the volume of the solution from milliliters (mL) to liters (L):
5000 mL = 5000/1000 = 5 L
Now, we can rearrange the formula to solve for moles of solute:
moles of solute = Molarity (M) x volume of solution (L)
moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol
Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:
mass of solute = moles of solute x molar mass of solute
mass of glucose = 1.075 mol x 180.16 g/mol
mass of glucose = 194.0 g (rounded to three significant figures)
Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.
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Stephan’s mother cuts a twig from a rose bush and plants it in the soil. After a few days, Stephan observes a new plant growing. Which characteristic does the growth of the new plant depict?
Answers
The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.
Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.
The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.
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Sometimes a fossil is formed as a result of the movement of an organism in soft sediment. Which of these are two kinds of trace fossils?
*
1 point
shells and bones
tracks and burrows
a bee and a beetle in amber
petrified and mummified fossils
Answers
Answer:The two kinds of trace fossils mentioned in the options are:
tracks
burrowsTracks and burrows are both examples of trace fossils, which are fossils thatprovide evidence of an organism's activity, rather than the organism itself.Tracks are impressions left by an organism's feet or other body parts as itmoved across soft sediment, while burrows are tunnels or other structurescreated by an organism as it burrowed into the sediment. Both types of tracefossils can provide valuable information about an organism's behavior, habitat, and interactions with other organisms.