what is the ph of a 0.235m solution of kf ka = 6.6*10^-4

... I hope this helps

True

Answer:

True

Explanation:

Beacuse you use Fossil Fuels for gas and its oil as well

Answer:

0.25M

Explanation:

Since molarity is defined as the amount of substance in 1 liter of a solution, and amount in chemistry refers to the number of moles, molarity can be found using the equation below:

Molarity= number of moles ÷ volume in liters

Given: number of moles= 2

Volume= 8L

∴ Molarity of NaCl

= 2 ÷8

= 0.25M

The volume of the statue = 8 L

The density of the silver = 10.5 per \(cm^{3}\)

The mass of the statue is x kg

As we know,

\(Density = \frac{Mass}{Volume}\)

Therefore, \(10.5 = \frac{x}{8} \\x = 10.5\) × \(8 = 84 kg.\)

So, the weight of the statue is heavy. You have to took help of your friend to carry the statue.

The density of a substance indicates how dense it is in a particular area. Mass per unit volume is the definition of a material's density. In essence, density is a measurement of how closely stuff is packed.

It is a special physical characteristic of a certain thing. The Greek scientist Archimedes made the discovery of the density principle.

If you are familiar with the formula and the relevant units, calculating density is simple. The letter D can also be used to signify density instead of the symbol.

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Answer:

The list of quantities of components, ingredients, and materials required to produce a product is the. master schedule.

Answer:

1.51986 atm

Explanation:

You can also search "154 kPa to atm" and a converter will appear

Answer:

1) The volume occupied by an atom is composed of mainly empty space

2) Atoms have a very small, relatively dense, central nucleus that is positively charged

3) The region around the nucleus of an atom are orbited by negatively charged electrons in a the same fashion planets orbit around the Sun.

Explanation:

The selection of gold for the gold foil experiment was due to its ability to be rolled into extremely thin sheets such that it was expected for alpha particle to perforate or pass through the foil.

The overall order of the given reaction, considering the rate law, is 3. The rate law is given as Rate = k[NO]₂[H₂]. Here, the exponent of the concentration term of each reactant is added to find the overall order of the reaction.

The rate law equation can be represented as Rate = k[NO]₂[H₂].

The sum of the exponents is 3 (2+1), indicating that the reaction is a third-order reaction. Hence, the overall order of the given reaction, given the rate law, is 3. It is important to note that the order of a reaction refers to the sum of the exponents in its rate law.

The exponents can be either integers or fractions in different rate laws. For instance, a rate law with exponents of 2, 1/2, and 1 is second-order, one-half-order, and first-order with respect to the concentration of A, B, and C, respectively.

Therefore, the overall order of the given reaction can be obtained by adding the exponents of the concentration terms of each reactant present in the rate law.

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Complete Question:

What is the overall order of the following reaction, given the rate law?

2NO(G) + H₂(G) → N₂(G) + 2H₂O(G) Rate = K[NO]₂[H₂]

Answer: Mechanical: Mechanical energy is the ability to do work.

Thermal: Thermal energy refers to the energy contained within a system that is responsible for its temperature.

Chemical:  Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat.

Electromagnetic: Electromagnetic energy is a form of energy that is reflected or emitted from objects in the form of electrical and magnetic waves that can travel through space.

Electrical: Electrical energy is the power an atom's charged particles have to cause an action or move an object.

Nuclear: Nuclear energy is the energy in the nucleus, or core, of an atom.

The pH at the equivalence point is 4.48.

In this problem, we can use the Henderson-Hasselbalch equation to find the pH at the equivalence point. The Henderson-Hasselbalch equation is;

pH = pKa + log([A⁻]/[HA])

where pKa is the acid dissociation constant of the acid, [A⁻] is the concentration of the conjugate base, and [HA] is the concentration of the acid.

Now, we can calculate the concentration of the conjugate base at the equivalence point;

moles of acetic acid = concentration x volume = 0.567 mol/L x 0.025 L = 0.01418 mol

moles of NaOH added = concentration x volume = 0.432 mol/L x volume

At the equivalence point, moles of acetic acid = moles of NaOH added, so;

0.01418 mol = 0.432 mol/L x volume

volume = 0.0328 L

The total volume of the solution at the equivalence point is the sum of the volumes of acetic acid and NaOH solutions;

\(V_{total}\) =\(V_{(aceticacid)}\) + \(V_{(NaOH)}\) = 0.025 L + 0.0328 L

= 0.0578 L

The concentration of acetate ion at equivalence point is;

[acetate] = moles of acetate / \(V_{total}\) = 0.01418 mol / 0.0578 L = 0.245 M

Now we can use the Ka expression for acetic acid to find the pKa;

Ka = [H⁺][CH₃COO⁻]/[CH₃COOH] = 1.8 x 10⁻⁵

At equilibrium, the concentration of H+ equals the concentration of acetate ion;

[H⁺] = [acetate] = 0.245 M

Substituting these values into the Ka expression and solving for [CH₃COOH], we get;

1.8 x 10⁻⁵ = (0.245)² / [CH₃COOH]

[CH₃COOH] = (0.245)² / 1.8 x 10⁻⁵

= 3.34 M

Now we can use the Henderson-Hasselbalch equation to find the pH at the equivalence point;

pH = pKa + log([A⁻]/[HA]) = pKa + log(1) = pKa

pH = -log(3.34 x 10⁻⁵)

= 4.48

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Answer:

Nvr XD

Explanation:

Answer:

the world may never know

Explanation:

The bases given that can be used to deprotonate a terminal alkyne include a. NaNH₂ and c. NaH.

Terminal alkynes are organic compounds that contain a carbon–carbon triple bond at the end of the carbon chain. They are relatively acidic and can be deprotonated by a strong base to form an acetylide ion.

Sodium amide is a very strong base ( pKa of its conjugate acid, NH3, is ~38 ), so it can deprotonate a terminal alkyne. Sodium hydride is a very strong base ( pKa of its conjugate acid, H2, is ~35 ), so it can deprotonate a terminal alkyne.

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The actual molecule of SeO2 is a resonance hybrid of the two resonance structures. In the correct resonance structure (B), there is a double bond between each oxygen atom and the selenium atom. This gives SeO2 a resonance hybrid that is the average of the two resonance structures.

Resonance structure is a hypothetical structure which represents the actual bonding in a molecule. It is different from the actual structure but provides a better description of the bonding in the molecule. The correct resonance structures for SeO2 are:

A: It is incorrect as it has an extra double bond.

B: It is the correct resonance structure of SeO2

C: It is incorrect as it has no resonance effect in the molecule.

D: It is incorrect as it has an extra double bond, which is not present in the actual molecule.

In the actual molecule, the Se atom is bonded to two O atoms, and each O atom is bonded to Se by a double bond. Therefore, the actual molecule of SeO2 is a resonance hybrid of the two resonance structures. In the correct resonance structure (B), there is a double bond between each oxygen atom and the selenium atom. This gives SeO2 a resonance hybrid that is the average of the two resonance structures.

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The two resonance structures for SeO2 (selenium dioxide) depict the different ways the bonds and electrons could be arranged within the molecule. The molecule has a V-shape with Selenium at the center, connected to two Oxygen atoms. The delocalization of pi electrons is shown by two major resonance structures.

The resonance structures for the compound SeO2 (selenium dioxide) are determined by the placement of electrons and bonds within the molecule. A molecule can have multiple possible structures, known as resonance structures, which depict the various ways that bonds and electrons can be arranged.

The molecule SeO2 features a V-shaped molecular geometry, with the Selenium (Se) atom at the center connected to two Oxygen (O) atoms, and has two pairs of lone electrons on Selenium. There are two major resonance structures: one with a double bond between Selenium and one Oxygen atom, and a single bond with the other Oxygen atom, and another with the positions of these bonds reversed. This shows the delocalization of pi electrons.

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Therefore, the amount of heat released on the reaction of 4.15 g of Al is -1408.4 kJ. It is negative because the reaction releases heat (exothermic).

To calculate the amount of heat released on the reaction of 4.15 g of Al, we need to use the stoichiometry of the reaction and the given enthalpy change.
First, we need to convert the mass of Al to moles:
4.15 g Al x (1 mol Al/26.98 g Al) = 0.1534 mol Al
Next, we use the stoichiometry of the reaction to determine the amount of heat released:
2 mol Al x (-1408.4 kJ/2 mol Al) = -1408.4 kJ
we can explain that the amount of heat released on the reaction of 4.15 g of Al can be calculated by using the stoichiometry of the reaction and the given enthalpy change. Stoichiometry is the relationship between the amounts of reactants and products in a chemical reaction, while enthalpy change is the amount of heat absorbed or released during a reaction. In this case, we know that the reaction of aluminum and chlorine produces aluminum chloride and releases 1408.4 kJ of heat per two moles of aluminum reacted. By converting the mass of aluminum to moles and using the stoichiometry, we can calculate that the reaction of 4.15 g of aluminum releases -1408.4 kJ of heat. The negative sign indicates that the reaction is exothermic, meaning it releases heat to the surroundings. This calculation is important for understanding the thermodynamics of the reaction and its potential applications in industry.

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The compound with the highest boiling point is \(CH_{3} CH_{2} OH\) .

So, option C is correct one.

The boiling point depend two factors,

The boiling point of ether is less than alcohols because alcohol form hydrogen-bonding .The hydrogen bond is strongest bond. So, ethyl alcohol and methyl alcohol has more boiling point than dimethy ether.

The propane molecules have only van-der waals force of attraction, which is weakest force of attraction.So, propane has lowest boiling point.

The molecular mass of ethanol is greater than methaol. So, ethanol has higher boiling point.

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Answer:

102 g Al₂O₃

Explanation:

The theoretical yield is the mass of product calculated via the molar masses and balanced chemical equation.

The limiting reagent is the reactant that is completely reacted before the other reactant(s) are used up. Since Al produces the smaller amount of product, it appears that Al is the limiting reactant. You can only make as much product as the limiting reactant allows. As such, the theoretical yield is 102 grams Al₂O₃.

The mass of the second isotope is 49.08 u.

Average atomic mass is 45.737 u, while the abundance of isotope 1 is 40.149 u.

? isotope 2?

Process

1.- Determine the isotope 2 abundance: abundance isotope 1 plus abundance isotope 2 equals 100%

100 = 37.46 + abundance isotope 2

Amount isotope 2 equals 100 - 37.46 Amount isotope 2 equals 62.54

2.- Determine the mass of isotope 2. Average atomic mass = (abundance x mass isotope 1) + (abundance x mass isotope 2) 45.737 = (0.3746 x 40.149) + (62.54 x mass isotope 2) Mass isotope 2 = [45.737 - (0.3746 x 40.149)]

62.54 mass isotope 2 equals [45.737 - 15.0398] 62.54 mass isotope 2 equals 30.6972 62.54 mass isotope 2 equals 0.4908 x 100 mass isotope 2 equals 49.08 u

Isotopes are members of the same family of elements as that element but have varying numbers of neutrons. The Periodic Table's atomic number of an element is determined by the number of protons it contains. The atomic number 6 of carbon, for instance, has six protons.

Any of two or more types of chemical element atoms that have the same atomic number and essentially the same chemical behavior, but different atomic masses or mass numbers and different physical qualities

Uranium-235, uranium-238, tritium (hydrogen-3), chlorine-36, and carbon-14 are a few examples of radioactive isotopes. There are certain isotopes that have exceptionally lengthy half-lives (in the order of hundreds of millions of years). Stable nuclides or stable isotopes are the terms used to describe these isotopes.

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The  prokaryotic cell and eukaryotic cell both contain the ribosomes. The Ribosomes are the non - membrane bound organelles.

The Eukaryotic cells contain the membrane - bound the organelles, such as the nucleus, the endoplasmic reticulum, the mitochondria while the prokaryotic cells do not contain the nucleus, endoplasmic and the mitochondria but the ribosome is the organelle that can be seen in the  both the prokaryotic cell and the eukaryotic cell.

The Prokaryotic and the eukaryotic ribosomes that is perform by the same functions that is the protein synthesis, however, the eukaryotic ribosomes are the much larger than the prokaryotic cell.

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If heat is released by the substances undergoing a chemical process in an aqueous solution, two of the following are true regarding the measurable temperature change in the solution and the heat exchange related to the reaction:

1. The temperature of the solution will increase: When heat is released during a chemical process, it causes the surrounding temperature to rise. In this case, the temperature of the aqueous solution will increase as a result of the heat released by the reaction.

2. The heat exchange will be exothermic: Heat exchange can be either endothermic or exothermic. In this case, since heat is released by the substances undergoing the chemical process, the heat exchange will be exothermic. Exothermic reactions release heat energy into the surroundings.

It's important to note that these statements hold true only if heat is indeed released during the chemical process. If heat is absorbed instead, the temperature of the solution would decrease, and the heat exchange would be endothermic.

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Answer: because they take a lot of tie to form  

The mole fraction of ethanol (C₂H₅OH) in the solution is approximately 0.042. The molality of the aqueous solution is approximately 1.21 mol/kg.

1. Mole fraction of ethanol (C₂H₅OH):

The mole fraction of a component in a solution is the ratio of the moles of that component to the total moles of all components in the solution. To calculate the mole fraction of ethanol, we first need to determine the moles of ethanol and water in the solution.

The molar mass of C₂H₅OH is calculated as follows:

(2 * molar mass of C) + (6 * molar mass of H) + molar mass of O

(2 * 12.01 g/mol) + (6 * 1.01 g/mol) + 16.00 g/mol = 46.07 g/mol

Next, we calculate the moles of ethanol:

moles of ethanol = mass of ethanol / molar mass of ethanol

moles of ethanol = 47.5 g / 46.07 g/mol ≈ 1.03 mol

Then, we calculate the moles of water:

moles of water = mass of water / molar mass of water

moles of water = 850 g / 18.02 g/mol ≈ 47.2 mol

Now, we can calculate the mole fraction of ethanol:

mole fraction of ethanol = moles of ethanol / (moles of ethanol + moles of water)

mole fraction of ethanol = 1.03 mol / (1.03 mol + 47.2 mol) ≈ 0.021

Therefore, the mole fraction of ethanol in the solution is approximately 0.042.

2. Molality of the aqueous solution:

Molality is a measure of the concentration of a solute in a solution, expressed in moles of solute per kilogram of solvent. In this case, the solute is ethanol (C₂H₅OH), and the solvent is water.

The molality is calculated as follows:

molality = moles of solute / mass of solvent (in kg)

We have already determined the moles of ethanol to be approximately 1.03 mol. The mass of water in kg can be obtained by dividing the mass of water by 1000:

mass of water (in kg) = 850 g / 1000 = 0.85 kg

Now, we can calculate the molality:

molality = 1.03 mol / 0.85 kg ≈ 1.21 mol/kg

Therefore, the molality of the aqueous solution is approximately 1.21 mol/kg.

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Answer:

carcinogen

Explanation:

cigarette smoke and UV radiation both of the capability to cause cancer cells in living tissue, meaning they can both be classed as carcinogens

Answer:

C

Explanation:

The law of conservation of mass states that the added mass of the reactants is equal to the added mass of the products.

A cannot be because it says that for example if you have two hydrogens in the reactants, those two hydrogens transform in for example 2 oxygen and the hydrogen disappear. that's impossible in chemistry.

B. Volume does not directly deal with that law of conservation of mass

C. Is correct, you can rearrange the atoms but if you keep the same amount of mass for each atom and you do not omit any atom, you are respecting the law of conservation of matter.

D.Same explanation for A

Answer:

b

Explanation:

.

Answer:

c. A nucleus with a large mass will be on the left side, and there will be neutrons in the equation.

Explanation:

In the process of nuclear fission, a neutron collides with a nucleus with a large mass and that nucleus splits into isotopes (substances that have the same atomic number that the original substance, but different weight number).

In this case, the nucleus with a large mass is U and n represents the neutrons.

The molarity of the sodium nitrate solution is 1.47 M. To calculate the molarity of the sodium nitrate solution, we need to first calculate the number of moles of NaNO3 present in one liter (1000 mL) of the solution.

Let's assume we have 1 liter of the solution, which would weigh 1.02 kg since its density is 1.02 g/mL.

The percentage by mass of NaNO3 in the solution is 12.5%. This means that 100 g of the solution contains 12.5 g of NaNO3. Therefore, in 1 kg (1000 g) of the solution, the mass of NaNO3 is:

mass of NaNO3 = 12.5% x 1000 g

mass of NaNO3 = 125 g

The molar mass of NaNO3 is:

molar mass of NaNO3 = 23 + 14 + 3(16)

molar mass of NaNO3 = 85 g/mol

The number of moles of NaNO3 present in 1 liter of the solution can be calculated as follows:

moles of NaNO3 = (mass of NaNO3) / (molar mass of NaNO3)

moles of NaNO3 = (125 g) / (85 g/mol)

moles of NaNO3 = 1.47 mol

Therefore, the molarity of the sodium nitrate solution is:

Molarity = (moles of solute) / (volume of solution in liters)

Molarity = (1.47 mol) / (1 L)

Molarity = 1.47 M

Therefore, the molarity of the sodium nitrate solution is 1.47 M.

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Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

Answer:

metallic bond but not completely sure

Explanation: