What is the ph at the equivalence point of a weak acid-strong base titration?
a) ph < 7
b) ph = 7
c) ph > 7
d) ph = 14.00

Answers

Answer 1

option (b) is correct .

The ph at the equivalence point is 7 for a weak acid-strong base titration.

What is the distinction between titration of strong acid and titration of the strong base?

There is no hydrolysis in the case of titration of a strong acid with a strong base (or strong base with strong acid), and the solution pH is neutral - 7.00 (at 25°C). The weak acid salt hydrolysis determines the pH at the equivalence point in the case of titration of a weak acid with a strong base.

What is the pH at the equivalence point?

The weak acid salt hydrolysis determines the pH at the equivalence point in the case of titration of a weak acid with a strong base. That means we must first determine the pK b of the conjugated base and calculate the concentration of OH, and then apply the pH=14-pOH formula.

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Related Questions

what predictions did mendeleev make, and why did he make them

Answers

Mendeleev's periodic table was helped more in creating modern periodic table as he arranged elements in the increasing order of atomic mass and moreover, he tried to arrange the elements on the basis of their reaction with hydrogen and oxygen because they are most reactive elements, react with most of other elements. In his period, 63 elements were known. So, this made quite easy for modern periodic table.

Here are some predictions of Mendeleev

Advantages of Mendeleev's periodic table

\({ \star}\)Elements were grouped on more fundamental basis.

\({ \star}\)Because of their placement in the periodic table, properties of several elements yet to be discovered like scandium, gallium and germanium could be predicted.

scandium predicted as Eka boron

gallium predicted as Eka aluminum

germanium predicted as Eka silicon

\({ \star}\)Gaps for 40 new elements were kept.

\({ \star}\)The discovery of new elements inert gases did not disturbed the arrangement and they found their place as a new group.

Answer:

Explanation:

Soon, Mendeleev was predicting the properties of three elements – gallium, scandium and germanium – that had not then been discovered. So convinced was he of the soundness of his periodic law that he left gaps for these elements in his table.

Need help with these 2 questions

Need help with these 2 questions

Answers

Answer:

go to google

Explanation:

it all ways work

if you a had a mole of soft drinks how many times could you cover the surface of the earth

Answers

Answer: Not possible

     

Explanation: A mole is a unit of measurement in chemistry used to express the amount of a substance. One mole of a substance is equal to Avogadro's number of particles, which is 6.0022X10^23.

A soft drink is a liquid beverage that contains sugar, caffeine or other stimulants, and other ingredients such as carbonated water and artificial flavors. The volume of a soft drink is usually measured in liters.

The surface area of the earth is about 510.1 million square kilometers. TO find out how many times a mole of soft drink can cover the surface of the earth, We need to know the volume of a mole of soft drink and convert it to square kilometers. However, it's impossible to know the volume of a mole of soft drink without knowing the density of the specific beverage.

Amole is a unit of measurement that is used to express the amount of a substance, it;s not related to the volume or surface area of a physical object like the earth. so it's not possible to know how many times a mole of soft drink could cover the surface of the earth.

A student was given a sample of food and asked to determine the types of nutrients present in the sample. The student placed half of the sample in a test tube with Benedict’s solution and heated it. The solution turned brick red. When an iodine solution was added to the remaining half of the sample, it turned blue black. The student can correctly conclude that the food sample contained

Answers

The food sample contained starch and reducing sugar (carbohydrates).

The Benedict's test is used to test for the presence of reducing sugars, such as glucose, in a sample. When the Benedict's solution is added to a sample containing reducing sugars and heated, the solution will turn brick red.

The iodine test is used to test for the presence of starch in a sample. When iodine solution is added to a sample containing starch, it will turn blue-black.

So, in this case, the student can conclude that the food sample contained both starch and reducing sugars, as both tests produced positive results.

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The greater the speed of gas particles in a container, the
a. fewer collisions there will be.
b. lower the temperature.
c. greater the pressure.
d. lower the pressure

Answers

Answer:

C. The greater the pressure

Explanation: If they move faster, the particles will exert a greater force on the container each time they hit the walls, which leads to an increase in the pressure of the gas. If the walls of the container are flexible, it will expand until the pressure of the gas once more balances the pressure of the atmosphere.

Answer: Greater The Pressure

Explanation: Greater velocity results in a greater pressure

what is the difference in mean solar time between 30 N 75 W and 30 N 90 W​

Answers

Answer:

Every 15 degrees is an hour

Explanation:

What is the time difference in mean solar time between 30° N 75° W and 30° N 90° W?

What kind of intermolecular forces act between a potassium cation and a chlorine monofluoride molecule?

Answers

The dipole-dipole  of intermolecular forces will act between a potassium cation and a chlorine monofluoride molecule.

Intermolecular forces, such as electromagnetic electrostatic interactions that occur between atoms as well as other kinds of nearby particles, such as atoms or ions, mediate interactions between molecules.

Hydrogen bromide (HBr), as well as chlorine monofluoride (ClF), as well as chlorine monofluoride (ClF), would both be highly polar molecules in this situation. Dipole intermolecular forces exist between polar molecules. In comparison to non-polar molecules, polar molecules are much more likely to stick to their atomic neighbors and seem to have higher boiling points. The positive end of one polar molecule would be drawn mostly by the negative end of another polar molecule, but also vice versa.

Therefore, the dipole-dipole of intermolecular forces will act between a potassium cation and a chlorine monofluoride molecule.

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A problem with the use of bromides is _____. Select one: a. the resulting high is measured in seconds b. bromides build up in the body c. bromides induce hallucinations d. bromides are carcinogenic

Answers

A problem with the use of bromides is bromides build up in the body.

Bromides have a tendency to accumulate in the body over time, leading to a buildup known as bromism. This can occur with prolonged or excessive use of bromide compounds. Bromism can cause various symptoms, including neurological effects such as fatigue, memory impairment, irritability, and even psychiatric symptoms. It is important to note that the effects of bromide accumulation are not immediate, as suggested by option (a) stating that the resulting high is measured in seconds. Hallucinations, mentioned in option (c), are not typically associated with bromides. Additionally, while certain bromide compounds may have carcinogenic properties, it is not a general problem with the use of bromides, as indicated in option (d).

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who developed the idea of the atomic nature of matter

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The idea of the atomic nature of matter was first developed by John Dalton.

He introduced the atomic theory, which proposed that matter was made up of tiny, indivisible particles called atoms. This theory was based on his observations and experiments on the behavior of gases

.Dalton's atomic theory had several postulates that helped explain the properties of matter. These postulates were:

All matter is made up of atoms, which are tiny, indivisible particles

.Each element is composed of atoms that are identical in size, shape, and chemical properties.

Atoms of different elements have different sizes, shapes, and chemical properties.

Atoms combine in fixed ratios to form compounds, and the ratios of their masses are related by whole numbers.

Atoms are indestructible and cannot be created or destroyed in chemical reactions

.However, Dalton's atomic theory was later modified and expanded upon by other scientists, including J.J. Thomson, Ernest Rutherford, and Niels Bohr, as new discoveries about the structure and behavior of atoms were made.

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PLS HELP HURRYYYYY!!!!!!!


The half-life of a radioactive kind of protactinium is 27 days. How much will be left after 54
days, if you start with 488 grams of it?

Answers

Answer:

122 gm

Explanation:

54 days is 2 half lives :    ( 27 * 2 = 54)

  1/2   * 1/2 = 1/4 will be left

      1/4 * 488 = 122 gm

Pls help ASAP!!! 70 points for answer

Which of the following is an explanation of how the natural world works, based on experimentation? An analysis A law An opinion A theory

Answers

the answer is a theory

Answer:

A theory

Explanation:

Which of the following statements does not describe the structure of an atom? (3 points) a Inside the nucleus of an atom are protons and neutrons. b Protons are positively charged sub-atomic particles. c Electrons are negatively charged sub-atomic particles. d Most of the mass of an atom comes from the electron cloud.

Answers

Answer:

D.

Explanation:

The electron cloud has negligible mass. Most mass come from the nucleus.

the right to ___________ is a second chance for a seller to make a proper tender of conforming goods.

Answers

The right to cure is a second chance for a seller to make a proper tender of conforming goods.

The right to cure refers to a legal concept in the context of contracts, particularly in the sale of goods. It grants the seller the opportunity to correct a non-conforming delivery of goods by providing a second chance to deliver conforming goods.

When a seller initially fails to deliver goods that meet the contractual requirements or specifications, the buyer may have the right to reject the non-conforming goods. However, in certain circumstances, the seller is granted the right to cure the defect by offering a replacement or by repairing the non-conforming goods. This allows the seller to make a proper tender of conforming goods to fulfill their contractual obligations.

The right to cure serves as a means of resolving disputes and avoiding the termination of the contract due to a single instance of non-conformity. It provides an opportunity for the seller to rectify the situation and fulfill their obligations, while also providing the buyer with the benefit of receiving the goods they initially intended to purchase.

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At 25 %C, only 0.0450 mol of the generic salt AB is soluble in 1.00 L of water: What is the Ksp of the salt at 25 %C? AB(s) ~^ A+(aq) + B (aq) Ksp

Answers

The Ksp of the salt AB at 25 °C is 1.8 x 10^-7 M^2. Option A is the correct answer.

The given information states that only 0.0450 mol of the salt AB is soluble in 1.00 L of water at 25 °C. Using this information, we can determine the molar solubility of AB, which is the amount of AB that dissolves per liter of water. In this case, the molar solubility is 0.0450 M.

The Ksp (solubility product constant) is a measure of the equilibrium between the dissolved ions and the undissolved solid in a saturated solution. For the dissociation of AB into A+ and B- ions, the equilibrium expression is [A+][B-]. Since the stoichiometry of the reaction is 1:1, the Ksp can be calculated as the square of the molar solubility: Ksp = (0.0450)^2 = 1.8 x 10^-7 M^2.

Therefore, the Ksp of the salt AB at 25 °C is 1.8 x 10^-7 M^2, which corresponds to option A).

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what two features must a sample have if it is to accurately represent a population

Answers

Answer:

It must be large

Random

Explanation:

For a sample to represent a population accurately, it must be large and contain random sample spaces.

A population is a group of organism of the same species living in a particular place where they can reproduce.

A sample must be representative of a given populationBy so doing, sampling space must be large so as to properly represent the species there in. The sampling must be done without any bias i.e. it must be randomly carried out.

3. A fixed quantity of gas at 23.0°C has a volume of 10.3 L. Calculate the volume the gas will occupy if the
temperature is increased to 145°C while the pressure is held constant.

Answers

The volume of that gas would be 14.54 L.

The volume of an ideal gas is proportional to its absolute temperature at constant pressure according to Charles' Law for ideal gases. The law can be stated simply as follows:

V/T = k

Given that we have volume and temperature.

According to Charle's Law

V1 = 10.3 L

T1 = 23.0 C = 296 K

V2 =?

T2 = 145 C = 418 K

V1 / T1 = V2 / T2

10.3/296 = V2/418

V2 = 14.54 L

The volume of that gas would be 14.54 L.

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The water level in a granulated cylinder raised up 6.2 ml after a 16.74 metal sample is lowered into the cylinder. What is the density of the sample? What metal is the sample most likely to be?

Answers

Answer:

The density of the mystery metal is 2.7g/cm^3.  It is likely aluminum, Al.

Explanation:

Density is defined as (mass/unit volume).  We know the volume of the metal sample by the fact it displaced 6.2 ml of water.  Since the mateal sample had a mass of 16.74 grams, we find the density by dividing the mass by the volume:

Density = (mass)/(volume) = (16.74g)/(6.2ml)

Density = 2.7 g/ml

Note that the ubntis for density can vary greatly. kg/cm^3 is a possible unit.

since 1 ml = 1 cm^3, we can also say the density of the metal sample is 2.7 g/cm^3.  [This is a more common unit for this type of measurement]

A reference book of densities can be search to find what metals have this density.  See the attached excerpt form one such table.

While not definitive, it can be seen that aluminum, Al, is a good candidate for the ID of this metal.  It has a density of 2.7 g/cm^3, although different forms may deviate slightly.  The metal is most likely aluninum.

The water level in a granulated cylinder raised up 6.2 ml after a 16.74 metal sample is lowered into

A 34.0 g metal cylinder is dropped into a graduated cylinder. If the water level increases from 22.3 mL to 25.3mL, what is the density of the cylinder?

Answers

Answer:

The answer is

11.33 g/mL

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question

mass of metal = 34 g

volume of metal = final volume of water - initial volume of water

volume = 25.3 - 22.3 = 3.0 mL

The density is

\(density = \frac{34}{3} \\ = 11.33333...\)

We have the final answer as

11.33 g/mL

Hope this helps you

In 20 moles of copper (II) phosphate, there are _____ moles of copper ions and _____ moles of oxygen atoms.
(a) 20, 60
(b) 20, 80
(c) 40, 80
(d) 60, 120
(e) 60, 160

Answers

The answer is (e) 60, 160: there are 60 moles of copper ions and 160 moles of oxygen atoms in 20 moles of copper (II) phosphate.

The formula for copper(II) phosphate is Cu3(PO4)2.

To find the number of moles of copper ions in 20 moles of copper (II) phosphate, we must first find the number of moles of copper in one mole of copper (II) phosphate.

We have 3 moles of copper in one mole of copper (II) phosphate.

Therefore, we have:3 x 20 = 60 moles of copper ions

To find the number of moles of oxygen atoms in 20 moles of copper (II) phosphate, we first need to find the total number of oxygen atoms in 20 moles of copper (II) phosphate.

In one mole of copper (II) phosphate, there are 8 oxygen atoms (2 from each phosphate ion).

We have:8 x 20 = 160 oxygen atoms.

So, the answer is (e) 60, 160: there are 60 moles of copper ions and 160 moles of oxygen atoms in 20 moles of copper (II) phosphate.

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state one factor that effects the rate of change of the liquid colour​

Answers

Answer:

Temperature is one of the major factors that affects the rate of change of the liquid colour, this is because ; like when if you freeze hot water the ice formed will be clear transparent, while on the other hand, if we freeze cold water it would be foggy inside the ice. This change occurs because of the temperature difference of the cold and hot water.

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What do each of the variables in Coulomb’s law stand for and what are their units?

Answers

Answer:

File down there

Explanation:

What do each of the variables in Coulombs law stand for and what are their units?

when a gas is heated and becomes a plasma, its electric charge is usually. A) negative. B) non-existent C) balanced. D) positive. E) none of these.

Answers

When a gas is heated and becomes a plasma, its electric charge is usually D) positive.

This is because plasma is an ionized gas consisting of positive ions and free electrons. When gas is heated, the electrons gain energy and become free from their parent atoms, resulting in a cloud of positively charged ions and negatively charged electrons. However, the charge balance of plasma can vary depending on the nature of the gas, the temperature, and the external conditions. For example, in a neon plasma, the charge balance is nearly equal between positive and negative ions. In contrast, a plasma in a magnetic field can lead to an excess of one type of charge, either positive or negative. In summary, while the charge balance of plasma can be influenced by external factors, the most common situation is for the electric charge to be D) positive when a gas is heated and transformed into a plasma.

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The pressure, temperature, and volume of an ideal gas are related by the equation n=
PV/RT

. Solve this equation for R.

Answers

If he pressure, temperature, and volume of an ideal gas are related by the equation n=

PV/RT,solving this for R will give us , R = PV/nT

We are to solve the given equation, which is PV=nRT, for R. The equation is ideal gas law equation.The ideal gas law is expressed mathematically as PV = nRT, where P, V, n, R, and T represent pressure, volume, number of moles, ideal gas constant, and temperature respectively.To solve this equation for R we need to follow these steps;Step 1 : Rearrange the equation so that R is on one side of the equals sign. PV=nRT can be rearranged into PV = nRT by dividing each side by n. PV/n = RT.  Step 2: Divide both sides of the equation by PT/ nV = RThe final equation we obtain after the above two steps is;R = PV/nT Therefore, we have successfully solved the given equation for R.

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1. Compare and contrast the properties of carbon dioxide and methane in terms of atmospheric lifetimes and their global warming potential. Explain why these differences are significant to climate chan

Answers

The differences between CO2 and methane and their respective impacts, policymakers and researchers can develop effective strategies for mitigating climate change and reducing greenhouse gas emissions.

Carbon dioxide (CO2) and methane (CH4) are both greenhouse gases that contribute to climate change, but they differ in terms of atmospheric lifetimes and global warming potential (GWP). These differences are significant to climate change because they affect the persistence and intensity of their impact on the Earth's climate system.

Atmospheric Lifetimes:

Carbon Dioxide: CO2 has a long atmospheric lifetime of several hundred years. This is because it is primarily removed from the atmosphere through natural processes such as ocean uptake and photosynthesis.

Methane: Methane has a relatively short atmospheric lifetime of around 12 years. It is primarily removed from the atmosphere through chemical reactions with hydroxyl radicals (OH) in the troposphere.

Global Warming Potential (GWP):

Carbon Dioxide: CO2 has a GWP of 1 over a specific time horizon (usually 100 years). This means that it is used as the reference gas to compare the warming potential of other greenhouse gases. The GWP of CO2 is relatively low compared to other greenhouse gases.

Methane: Methane has a much higher GWP compared to CO2. Over a 100-year time horizon, its GWP is approximately 28-36 times greater than that of CO2. However, over a shorter time horizon (e.g., 20 years), methane's GWP is even higher, reaching around 84-87 times that of CO2. This high GWP reflects methane's potent warming effect, especially in the near term.

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que es la nanotecnologia ?
porfis lo nesecito urgente para antes de las 10

Answers

Answer:

Se aclama la nanotecnología por tener el potencial de aumentar la eficiencia del consumo de energía, ayudar a limpiar el medio ambiente y resolver los principales problemas de salud. Se dice que puede aumentar masivamente la producción de fabricación a costos significativamente reducidos.

espero que esto ayude

You read a primary source and a secondary source that discuss the same
experiment. There is a difference in the conclusions made by these two
sources. Which should you trust more, and why?
A. The secondary source, because it is easier to understand
B. The primary source, because it contains more charts
C. The primary source, because it was written by the researcher
D. The secondary source, because it was printed on paper
SUBM

Answers

Answer:

C

Explanation:

I am not 100% sure, but it might be the answer.

C

That should be right

recent studies suggest that small rnas may have evolved for which of the following functions?

Answers

Small RNAs may have evolved for gene regulation, defense against viruses, epigenetic regulation, chromatin remodeling, and post-transcriptional modifications.

For which functions may small RNAs have evolved according to recent studies?

Recent studies suggest that small RNAs may have evolved for various functions, including:

Gene regulation: Small RNAs, such as microRNAs (miRNAs) and small interfering RNAs (siRNAs), can bind to messenger RNA (mRNA) molecules and regulate gene expression by either degrading the mRNA or inhibiting its translation into proteins.Defense against viruses: Small interfering RNAs play a crucial role in the RNA interference (RNAi) pathway, which is a defense mechanism used by cells to target and destroy viral RNA. Epigenetic regulation: Certain small RNAs, such as piwi-interacting RNAs (piRNAs), are involved in regulating the epigenetic state of the genome, including the silencing of transposable elements and maintaining genome stability.Chromatin remodeling: Small nuclear RNAs (snRNAs) are involved in the splicing of pre-mRNA molecules and the assembly of the spliceosome, a complex involved in the removal of introns. Post-transcriptional modifications: Small nucleolar RNAs (snoRNAs) guide the modification of ribosomal RNA (rRNA) and other non-coding RNAs, ensuring proper function and stability.

It is important to note that the understanding of small RNA functions is an active area of research, and additional functions may be discovered in the future.

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Occurs in many complex organisms such as plants, animals and fungi

Answers

Answer:

DNA

Explanation:

The eukaryotic cell participates in the formation of complex organisms and contains a nucleus, cytoplasmic organelles, and a cytoskeleton.

In a eukaryotic cell, DNA is contained in a compartment called the nucleus, which is enclosed by a membrane.

The answer should be DNA based on the wording of the question. Hopefully this helped a little bit.

How many moles of KC1 are in 1250 mL of 0.75 M KC1

Answers

The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) is equal to the moles of solute per litre of solution.

In this instance, the volume of the solution is 1250 mL, and the molarity of KC1 is 0.75 M. The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) times the number of litres in the solution equals 0.75 M times (1250 mL/1000 mL/L) or 0.9375 moles of KC1.

Consequently, 0.9375 moles of KC1 are present in 1250 mL of 0.75 M KC1. It is significant to remember that a solution's molarity is a measurement of the amount of a solute present in a given volume of the solution.

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A titration of 200.0 mL of 1.00 M H2A was done with 1.38 M NaOH. For the diprotic acid H2A, Ka1 = 2.5  10–5, Ka2 = 3.1  10–9. Calculate the pH after 100.0 mL of 1.38 M NaOH have been added.

Answers

Answer:

4.95

Explanation:

1.00 M H2A

1.38 m NaOH

Titration = 200.0 mL

Calculate moles of NaOH

= \(\frac{100*1.38}{300}\)  = 0.46

calculate moles of H2A

= \(\frac{200 * 1.0}{300}\) = 0.667

therefore the moles of acid left = moles of H2A - moles of NaOH

                                                    = 0.667 - 0.46 = 0.207

pka = - log( ka )

       = - log ( 2.5 * 10^-5 ) = 4.61

calculate PH after 100 ml of 1.38 M NaOH have been added

PH = pka + log \((\frac{salt}{acid} )\)

     = 4.61 + log \((\frac{0.46}{0.207} )\) = 4.95

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