When many atoms are split in a chain reaction, a large explosion occurs. This is an example of what type of energy conservation.
Nuclear to chemical or Nuclear to mecanical? Why?
Explanation:
Nuclear to chemical is the type of energy conversion that occurs when atoms are split in a chain reaction and a large explosion occurs.
Jack starts walking east (+ x-direction) at a pace of 2 m/s. Jill, who is very upset with Jack, is running west (- x-direction) towards him at a rate of 4 m/s and is initially 200 meters to the east of Jack when she sees him. When and where does she run into him?
A.
Cannot be determined.
B.
x_f = 66.7 m and t_f = 66.7 sec
C.
x_f = 33.3 m and t_f = 66.7 sec
D.
x_f = 66.7 m and t_f = 33.3 sec
D. The time at which she meets him is 33.33 seconds and she had traveled a distance of 66.7 m.
Time when jack meets jill
The time at which Jack and Jill meet each other is calculated as follows;
(4 m/s - -2 m/s)t = 200
(4 + 2)t = 200
6t = 200
t = 200/6
t = 33.33 seconds
Distance traveled by JackD = 2 m/s x 33.33 seconds
D = 66.7 m
Thus, the time at which she meets him is 33.33 seconds and she had traveled a distance of 66.7 m.
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5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?
The traffic cop needs 23.3 seconds to pass the automobile.
What is the acceleration of a car moving in a straight line at a constant speed?When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.
\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)
\(d = d1 = 35.0 m\)
\(d2 = v2*t + (1/2)at^2\)
\(d2 = (1/2)at^2\)
\(v2*t + (1/2)at^2 = (1/2)at^2\)
\(v2*t = (1/2)at^2\)
Solving for t, we get:
\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)
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What are two important factors to consider when describing the effect of an applied force on an object’s motion
The magnitude of the applied force and the mass of the object, together determine how an object's motion will change in response to the applied force.
When describing the effect of an applied force on an object's motion, two important factors to consider are:
Magnitude of the Force: The magnitude or strength of the applied force determines the amount of acceleration or deceleration experienced by the object. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. A greater force will result in a greater acceleration, while a smaller force will result in a smaller acceleration. Additionally, the direction of the force relative to the object's initial motion will determine if it speeds up, slows down, or changes direction.
Mass of the Object: The mass of the object being acted upon is another crucial factor. As mentioned earlier, according to Newton's second law, the acceleration of an object is inversely proportional to its mass. This means that for a given force, an object with a larger mass will experience a smaller acceleration compared to an object with a smaller mass. In simpler terms, it requires more force to accelerate a heavier object compared to a lighter object.
These two factors, the magnitude of the applied force and the mass of the object, together determine how an object's motion will change in response to the applied force.
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A 12 V battery is connected in series to a 50.0 ohm resistor and a 70.0 ohm resistor. What is the total resistance in the circuit?
Series connection
Net resistance
R1+R250+70120ohmExplanation:
We need to determine the total resistance also known as the net resistance that is occurring in the circuit. We need to combine the two resistors that are being used and that will give us the net.
50.0 ohm + 70.0 ohm
120.0 ohm
Answer: The net resistance is 120.0 ohm
You are traveling through the forest and encounter an ancient well. You want to know how deep the well is. If you drop a coin and hear it hit the bottom of the well in 3 seconds, how deep is the well?
1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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Which of the following is NOT something
the atmosphere does?
A. traps in warmth
B. keeps Earth in a spherical shape
C. provides oxygen to breathe
D. protects Earth from meteoroids
Answer:
I think the answer is B, keeps Earth in a spherical shape
A woman on a bridge 82.2 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an attempt to hit the raft. The stone is released when the raft has 5.04 m more to travel before passing under the bridge. The stone hits the water 2.13 m in front of the raft. Find the speed of the raft.
Answer:
0.71 m/s
Explanation:
We find the time it takes the stone to hit the water.
Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.
So, substituting the values of the variables into the equation, we have
y = ut - 1/2gt²
82.2 m = (0m/s)t - 1/2( -9.8 m/s²)t²
82.2 m = 0 + (4.9 m/s²)t²
82.2 m = (4.9 m/s²)t²
t² = 82.2 m/4.9 m/s²
t² = 16.78 s²
t = √16.78 s²
t = 4.1 s
This is also the time it takes the raft to move from 5.04 m before the bridge to 2.13 m before the bridge. So, the distance moved by the raft in time t = 4.1 s is 5.04 m - 2.13 m = 2.91 m.
Since speed = distance/time, the raft's speed v = 2.91 m/4.1 s = 0.71 m/s
Two identical rooms in a house are connected by an open doorway. The temperatures in the two rooms are maintained at different values. Which room contains more air
Answer:
The room with the lower temperature
Explanation:
Using
PV=nRT
Since both the rooms same volume and are connected, so they will have same pressure
PV=nRT=constant
nT=Constant/R=constant
If T is more n has to be less
Thus, lower the temperature, more the number molecules.
assignment questions
Answer:
which on a is the question
Question 4(Multiple Choice Worth 2 points)
Satellite technology has allowed us to monitor areas that were once so remote that we had no way of monitoring them. Review the statements and choose the one that best describes how we can use this technology to benefit the environment.
Large ocean liners use satellites to aid in navigation. This type of navigation aid is also used on cruise ships. Using satellites can help these large ships navigate waters during bad storms.
Satellite surveillance can be used to aid in port security. Satellite data can be monitored and evaluated by complex computer systems. These systems can alert officials when something unusual occurs.
Satellite technology allows us to monitor and track the changes in the polar ice sheets. This can help us plan and direct conservation efforts for the animals that depend on polar ice in order to survive.
Satellite surveillance has allowed us to map areas that were previously too remote to observe. This helps developers to locate and choose sites for large resorts.
Answer:
satellite technology helped large ocean liners guide you to our space mission.
Explanation:
Large ocean liners use satellites to aid in navigation. This type of navigation aid is also used on cruise ships. Using satellites can help these large ships navigate waters during bad storms.
Satellite surveillance can be used to aid in port security. Satellite data can be monitored and evaluated by complex computer systems. These systems can alert officials when something unusual occurs.
Satellite technology allows us to monitor and track the changes in the polar ice sheets. This can help us plan and direct conservation efforts for the animals that depend on polar ice in order to survive.
Satellite surveillance has allowed us to map areas that were previously too remote to observe. This helps developers to locate and choose sites for large resorts.
The social model was created by
A uniform metre rule of mass 100g balance the 40cm mark when a mass x is placed at the 20cm mark
what is the value of x
Answer:
X = 50 g
Explanation:
Please see attached photo for explanation.
From the attached photo,
Anticlock–wise moment = X × 20
Clockwise moment = 100 × 10
Anticlock–wise moment = clockwise moment
X × 20 = 100 × 10
X × 20 = 1000
Divide both side by 20
X = 1000 / 20
X = 50 g
Therefore, the value of X is 50 g
no i dont have one soory
Answer:
u dont have a question
Explanation:
?? bc i would gladly help u
A satellite has a mass of 6463 kg and is in a circular orbit 4.82 × 105 m above the surface of a planet. The period of the orbit is 2.0 hours. The radius of the planet is 4.29 × 106 m. What would be the true weight of the satellite if it were at rest on the planet’s surface?
Answer:
The weight of the planet is 29083.5 N .
Explanation:
mass of satellite, m = 6463 kg
height of orbit, h = 4.82 x 10^5 m
period, T = 2 h
radius of planet, R = 4.29 x 10^6 m
Let the acceleration due to gravity at the planet is g.
\(T = 2\pi\sqrt\frac{(R+h)^3}{gR^2}\\\\2\times 3600 = 2\times3.14\sqrt\frac{(4.29+0.482)^3\times10^{18}}{g\times 4.29\times 4.29\times 10^{12} }\\\\24.2 g =108.67\\\\g = 4.5 m/s^2\)
The weight of the satellite at the surface of the planet is
W = m g = 6463 x 4.5 = 29083.5 N
Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. A satellite of mass mis orbiting Earth in a stable circular orbit of radius R. The mass and radius of Earth are Mg and Rg , respectively. Express your answers to parts (a), (b), and (c) the following in terms of m, R, ME, Rg , and physical constants, as appropriate.
(a) Derive an expression for the speed of the satellite in its orbit.
(b) Derive an expression for the total mechanical energy of the satellite-Earth system in its orbit.
(c) Derive an expression for the period of the satelliteâs orbit.
(d) The satellite is replaced with a similar satellite that has twice the mass. The new satellite is placed into the same orbit as the original satellite. Is the new satelliteâs orbital speed greater than, less than, or equal to the original satelliteâs orbital speed?
A satellite of mass mis orbiting Earth in a stable circular orbit of radius R, (a) Speed of satellite is v = sqrt(G x Mg/R). (b) total mechanical energy is E = KE + PE. (c) the period of the satellite as orbit is T = 2 x pi x sqrt(R^3 / (G x Mg)).
(a) The speed of the satellite in its orbit can be derived using Kepler's second law of planetary motion, which states that a planet or satellite's orbital speed is inversely proportional to the square root of the distance from the center of the planet or satellite to the center of the primary body. This can be expressed mathematically as:
v = sqrt(G x Mg / R)
where v is the orbital speed of the satellite, G is the gravitational constant, Mg is the mass of Earth, and R is the radius of the satellite's orbit.
(b) The total mechanical energy of the satellite-Earth system in its orbit can be calculated using the formula for kinetic energy and the formula for gravitational potential energy. The kinetic energy of the satellite is given by:-
= KE
= 1/2 x m x v^2
The satellite's gravitational P.E. determined by:
= PE
= -G x Mg x m / R
The total mechanical energy of the satellite-Earth system is the sum of the kinetic energy and gravitational potential energy, so:
= E
= KE + PE
= 1/2 x m x v^2 - G x Mg x m / R
(c) The period of the satellite's orbit is the time it takes for the satellite to complete one full orbit around Earth. This can be calculated using the formula:-
= T
= 2 x pi x sqrt (R^3 / (G x Mg))
where T is the period of the orbit, G is the gravitational constant, Mg is the mass of Earth, and R is the radius of the satellite's orbit.
(d) If the new satellite has twice the mass of the original satellite, then its kinetic energy will be four times greater, since KE is proportional to m. However, the gravitational potential energy of the new satellite will also be four times greater, since PE is proportional to m. Since the total mechanical energy of the satellite-Earth system is the sum of the kinetic and gravitational potential energy, the total mechanical energy of the new satellite-Earth system will be the same as the total mechanical energy of the original satellite-Earth system. Therefore, the new satellite's orbital speed will be the same as the original satellite's orbital speed.
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را Three forces acting at a point of 300N forces may varies but the angle between is always 40. Determine the value of the angle for which the value of the resultant force is parallel to BB.
The value of the angle for which the value of the resultant force is parallel to b-b is 6.35°. Therefore, the correct option is A.
What is an angle?An angle can be defined as the figure that is formed when two rays or lines shares a common endpoint.
Let the x and y-axis be shown here. If the resultant is directed along the x-axis, then its component in the y direction is zero.
0 = ΣFy = 300 sin θ + 300 sin (40 + θ) – 500 sin 30°
Therefore, sin θ+ sin (40+ θ)= 500 sin 30°÷ 300
⇒ sin θ + sin (40 + θ) = 0.833
⇒ 2 sin (40 + θ + θ)÷ 2 × cos 40 + θ—θ) ÷ 2 = 0.833
⇒ 2 sin (20 + θ) × cos (20) = 0.833
⇒ θ = 6.35°
Hence, the value of angle is 6.35°. Therefore, the correct option is A.
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The question is incomplete, but most probably the complete question is,
Three forces acting at a point are shown in Fig. The direction of the 300 N forces may vary, but the angle between them is always 40°. Determine the value of θ for which the resultant of the three forces is directed parallel to b-b.
A. 6.35°
B. 6.00°
C. 7.40°
D. 4.81°
Liquid water is nearly 1,000 times denser than air. Thus, for every 32.0 feet (9.75 m) a scuba diver descends below the water's surface, the pressure increases by 1.00 atm. Human lungs have a volume of approximately 3.50 L. If a scuba diver descends to a depth of 80.0 feet where the pressure is 3.50 atm (2.50 atm from the water and 1.00 atm from the air pressure), then by how much does the volume of a 3.50 L surface sample of air decrease
Answer:
ΔV = -2.1 L
Explanation:
To solve this exercise we can use the ideal gas equation for two points
PV = nRT
P₁V₁ = P₂ V₂
where point 1 is on the surface and point 2 is at the desired depth,
V₂ = \(\frac{P_1}{P_2} \ V_1\)
let's calculate
V₂ = ( \(\frac{1 atm}{2.5 atm}\) ) 3.5 L
V₂ = 1.4 L
this is the new volume, the change in volume is
ΔV = V₂ -V₁
ΔV = 1.4-3.5
ΔV = -2.1 L
A swimmer swims the length of a 50-meter pool, swims back to their starting point, and finally swims back to the opposite side again.
What is their overall displacement?
What total distance did they swim?
SHOW YOUR WORK or explain your answer.
The distance that is covered is 150 m
The displacement is 50 m.
What is the displacement?We have to know that the displacement has to do with the distance that is covered in a specific direction. We have to take note of the direction that we have there as that is what does make the difference between the distance and the displacement.
The distance does not involve the direction. It can then be safe to say that displacement is a vector and that distance is a scalar. Once again let us recall that these are so because the distance does not take cognizance of the direction while the displacement would always take cognizance of the direction of the motion.
Then we have;
Distance = 50 m + 50 m + 50 m = 150 m
For displacement calculation;
Moving towards the opposite side and back = 50 m - 50 m = 0 m
Moving again to the opposite side;
Displacement = + 50 m
Note that the backward motion of the swimmer would be taken as negative.
Therefore total displacement = 50 m
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In the electric of capacitance 4 ,3 and 2 microfaradas, respectively, are connected in senes to a battery of 260 V , calculate the charge?
The total charge in the circuit is 240 microcoulombs.
To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.
In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.
To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.
Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.
Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.
Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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What do you mean by pressure of a liquid? Write its Sl unit.
Explanation:
Pressure of a liquid :
Liquids also exert pressure as that in case of solids. We can understand it as the fact that it is impossible to hammer a nail with liquid. That's why liquid exert pressure on its surface. The formula for the pressure in liquid is given by :
\(P=\rho gh\)
Where
\(\rho\) = density of liquid
g = acceleration due to gravity
h = height
The SI init of pressure is Pascal and it is dented by Pa.
an aircraft with a landing speed of 295km/h lands on an aircraft carrier with a landing area 205m long. find the minimum constant decleration required for a safe landing
Answer:
20.38 m/s^2 deceleration
Explanation:
295 km/hr = 91.94 m/s
v goes from 91.94 to 0 average v = 40.97 m/s
d = vt
205 = 40.97 t t = 5 seconds
d = vo t - 1/2 a t^2
205 = 91.94 ( 5) - 1/2 (a)(5^2)
a = 20.38 m/s^2 (DECELERATION)
PLEASE HELP ME!!!1
Differentiate between the distance and displacement for an object that started at point A and traveled as shown to point B.
Distance: _____ units and Displace: _____ units to the left.
"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.
"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.
An airplane accelerates from the rest. Down a run way at 3.20 m/s2 for 32.8s until it finally lifted off the ground . Determine the distance traveled before takeoff
The plane's acceleration is 3.22 m/s2, and the travel duration is 3.28 seconds. The distance traveled before takeoff is 1720m.
How is the distance travelled prior to takeoff calculated?The kinematic equation gives us the distance travelled before to takeoff: d=v 0 t+1/2 at2, where d is the distance prior to takeoff, v 0=0 is the airplane's starting velocity, an is its acceleration, and t is the time.
A plane travels down a runway at 3. 20 m/s2 for 32. 8 seconds before ultimately taking off.
U=0 m/s is the airplane's initial speed.
The plane's acceleration is 3.22 m/s2, and the travel duration is 3.28 seconds.
Distance travelled using a formula S=ut+ 2 1 2
⇒ S=0(32.8)+0.5(3.2)(32.8) 2 =1721.3∼ 1720m
The distance traveled before takeoff is 1720m
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A mechanical lift is used to pull an engine out of a car. The engine is attached
to the lift with chains and lifted straight up. The free-body diagram below
shows the engine when it is suspended in the air.
Force 1
Force 2
What is force 2 in this diagram?
O A. Weight
B. Tension
C. Normal force
D. Friction
Answer:
the answer is weight
Explanation:
Answer:
Weight
Explanation: Just took the quiz
A square loop, length l on each side, is shot with velocity v0 into a uniform magnetic field B. The field is perpendicular to the plane of the loop. The loop has mass m and resistance R, and it enters the field at t = 0s. Assume that the loop is moving to the right along the x-axis and that the field begins at x = 0m.
Required:
Find an expression for the loop's velocity as a function of time as it enters the magnetic field.
Answer:
v₀(1 + B²L²t/mR)
Explanation:
We know that the force on the loop is F = BIL where B = magnetic field strength, I = current and L = length of side of loop. Now the current in the loop I = ε/R where ε = induced e.m.f in the loop = BLv₀ where v₀ = velocity of loop and r = resistance of loop
F = BIL = B(BLv₀)L/R = B²L²v₀/R
Since F = ma where a = acceleration of loop and m = mass of loop
a = F/m = B²L²v₀/mR
Using v = u + at where u = initial velocity of loop = v₀, t = time after t = 0 and v = velocity of loop after time t = 0
Substituting the value of a and u into v, we have
v = v₀ + B²L²v₀t/mR
= v₀(1 + B²L²t/mR)
So the velocity of the loop after time t is v = v₀(1 + B²L²t/mR)
The expression for the loop's velocity as a function of time as it enters the magnetic field is v = v₀(1 + B²L²t/mR).
Calculation of the loop velocity:As we know that
Force on the loop
F = BIL
here
B = magnetic field strength,
I = current
and L = length of side of loop.
Now
the current in the loop I = ε/R
where
ε = induced e.m.f in the loop = BLv₀
where v₀ = velocity of loop
and r = resistance of loop
So,
F = BIL = B(BLv₀)L/R = B²L²v₀/R
Also, F = ma where a = acceleration of loop and m = mass of loop
Now
a = F/m = B²L²v₀/mR
We have to use
v = u + at
where
u = initial velocity of loop = v₀,
t = time after t = 0
and v = velocity of loop after time t = 0
So, it be like
v = v₀ + B²L²v₀t/mR
= v₀(1 + B²L²t/mR)
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which one of the following is a correct statement......
1)increasing temperature will decrease a pressure of gas
2)increase in amount of gas will decrease the pressure of gas
3)increasing the volume of gas will decrease the pressure of gas
4)all of the above
Answer:
Just 3
Explanation:
I believe the other two are incorrect
Two students were climbing stairs at school. Student 1 has a weight of 700 N. Student 2 has a weight of 650 N. How much power would each student have if each took 6 s to climb a 4 m tall flight of stairs?
Student 1 would have 4200 W, and Student 2 would have 3900 W of power.
Student 1 would have 116 W, and Student 2 would have 108 W of power.
Student 1 would have 2800 W, and Student 2 would have 2600 W of power.
Student 1 would have 467 W, and Student 2 would have 433 W of power.
Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
From the question,
We are to calculate the power each student would have to climb the flight of stairs.
Power can be calculated using the formula
\(P = \frac{F \times d}{t}\)
Where
P is Power
F is the force
d is the distance
and t is the time
NOTE: The weight of the students represent the force
For student 1F = 700 N
d = 4 m
t = 6 s
∴ \(P = \frac{700 \times 4}{6}\)
P = 467 W
For student 2
F = 650 N
d = 4 m
t = 6 s
∴ \(P = \frac{650 \times 4}{6}\)
P = 433 W
Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
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