What is the oxidation number for bromine in Libro3

Answer:

We actually output other gases like methane lol

Explanation:

Well since most of the air we breathe is made up of nitrogen we also breathe out nitrogen

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Answer:

our body needs oxygen for certain processes in the body .When the work is done oxygen is transformed into carbon dioxide .So, oxygen is inhaled while carbon dioxide is exhaled.

Answer:

1. 0.14 g of NO2.

2. 0.27 g of CO2.

Explanation:

The balanced equation for the reaction is given below:

2C8H10N4O2 + 27O2 —> 16CO2 + 10H2O + 8NO2

Next, we shall determine the mass of caffeine, C8H10N4O2 that reacted and the masses of nitrogen (iv) oxide, NO2 and carbon (iv) oxide, CO2 produced from the balanced equation. This can be obtained as follow:

Molar mass of of C8H10N4O2 = 194.19 g/mol

Mass of C8H10N4O2 from the balanced equation = 2 × 194.19 = 388.38 g

Molar mass of CO2 = 44.01 g/mol

Mass of CO2 from the balanced equation = 16 × 44.01 = 704.16 g

Molar mass of NO2 = 46.01 g/mol

Mass of NO2 from the balanced equation = 8 × 46.01 = 368.08 g

Summary:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2 and 368.08 g of NO2.

1. Determination of the mass of NO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 368.08 g of NO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 368.08) / 388.38 = 0.14 g of NO2.

Therefore, 0.14 g of NO2 was obtained from the reaction.

2. Determination of the mass of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 704.16) / 388.38 = 0.27 g of CO2.

Therefore, 0.27 g of CO2 was obtained from the reaction.

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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Answer:

n = 0.0814 mol

Explanation:

Given mass, m = 35.7g

The molar mass of Tin(IV) bromate, M = 438.33 g/mol

We need to find the number of moles of bromine. We know that,

No. of moles = given mass/molar mass

So,

\(n=\dfrac{35.7}{438.33}\\\\n=0.0814\ mol\)

So, there are 0.0814 moles of bromine in 35.7g of  Tin(IV) bromate.

Answer:

Mass of Oxygen = 32 grams

Explanation:

Given:

Mass of water = 36 grams

Mass of Hydrogen = 4 grams

Find:

Mass of Oxygen

Computation:

Using Law of Conservation of mass

Mass of water = Mass of Hydrogen + Mass of Oxygen

36 grams = 4 grams + Mass of Oxygen

Mass of Oxygen = 32 grams

Answer:32

                    jdusidncyvuygtuguutvytvbjhbu

Answer:

The carbon cycle is the biogeochemical cycle by which carbon is exchanged among the biosphere, pedosphere, geosphere, hydrosphere, and atmosphere of the Earth. Carbon is the main component of biological compounds as well as a major component of many minerals such as limestone

mol = conc × v

= 1.5 × 0.09

= 0.135 moles of HCl

HCl + NaOH > NaCl + H2O

1 mole HCl = 1 mole NaOH

0.135 mol HCl = x

x = 0.135 mol NaOH

mass = mol × molar mass

= 0.135 × 40

= 5.4 g

NaOH = 23 + 16 + 1 = 40 g/mol

I'm not a 100% sure if it's correct

MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2

Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2

Explanation:

The percent yield, given that the theoretical yield is 73 grams and the actual yield is 62 grams, is 84.9%

Percentage yield is defined according to the following formula:

Percentage yield = (Actual yield / Theoretical yield) × 100

From the question given above, the following data were obtained:

Using the above formula, we can obtain the percentage yield as shown below:

Percentage yield = (Actual yield / Theoretical yield) × 100

Percentage yield = (62 / 73) × 100

Percentage yield = 84.9%

Thus, from the above calculation, we can conclude that the percentage yield is 84.9%

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Answer:

when placed in water, a sodium pellet catches on fire as hydrogen gas is liberated and sodium hydroxide forms. chemical change = fire is a sign of chemical reaction.

Explanation:

When placed in water the sodium pellets catch the fire and liberate the hydrogen gas. On mixing with water solid sodium forms a colorless basic solution.

Sodium is a soft metal. It is a very reactive element with a low melting point. Sodium reacts very quickly with water, snow, and ice to produce sodium hydroxide and hydrogen. It is an alkali metal and the sixth most abundant metal on earth. It has a silvery white color.

It has a strong metallic luster. On reacting with oxygen it produces sodium oxide which on reacting with the water produces sodium hydroxide.

It is used to improve the structure of certain alloys and soaps. It is also used in the purification of metals. Sodium is also present in sodium chloride, an important compound found in the environment.

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Answer:

A plastic ball

Explanation:

A plastic ball has less density than water because plastic has low density so

Answer:

C₂H6 + O2 → 2CO2 + 3H2O

Answer:

I think that gravity can be considered a force.

Explanation:

As the object falls, it moves faster and faster. Gravity is considered a universal force because it acts between any two masses anywhere in the universe. For example, there is a gravitational pull between the Sun and the Moon. Even small masses attract one another.

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The mole ratio of the compound and its constituent elements are as follows:

Mole ratio is the ratio of the moles of one or more elements or compounds to another.

The given compound is Ca₄Si₂O₆(CO₃)(OH)₂

Moles of oxygen present in 1 mole of compound = 11 moles

Moles of Si present in 1 mole of compound = 2 moles

Moles of Ca present in 1 mole of compound = 4 moles

Moles of C present in 1 mole of compound = 1 mole

Given the equation of the reaction below;

the mole ratio of the reactants and products are as follows:

In conclusion, the mole ratio of reaction is the ratio in which moles of the substances combine.

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(a) the molecular formula of the compound is C₆H₁₂.

(b)  the molecular formula of the compound is NH₂Cl.

(a) Given the empirical formula CH₂ and a molar mass of 84 g/mol, we need to determine the molecular formula. To do so, we need to find the factor by which the empirical formula needs to be multiplied to achieve the given molar mass.

The empirical formula CH₂ has a molar mass of 14 g/mol (12 g/mol for carbon + 2 g/mol for hydrogen).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 84 g/mol / 14 g/mol = 6

Therefore, the molecular formula is obtained by multiplying the empirical formula by the factor:

CH₂ × 6 = C₆H₁₂

Thus, the molecular formula of the compound is C₆H₁₂.

(b) Given the empirical formula NH₂Cl and a molar mass of 51.5 g/mol, we follow a similar approach.

The empirical formula NH₂Cl has a molar mass of 51.5 g/mol (14 g/mol for nitrogen + 2 g/mol for each hydrogen + 35.5 g/mol for chlorine).

To find the factor, we divide the molar mass by the empirical formula mass:

Factor = (molar mass) / (empirical formula mass) = 51.5 g/mol / 51.5 g/mol = 1

Therefore, the molecular formula is the same as the empirical formula: NH₂Cl

Hence, the molecular formula of the compound is NH₂Cl.

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A)Nuclear fusion releases protons and neutrons, so the total number of protons and neutrons in a star changes throughout its life is the true statement.

A suggested method of producing energy would use heat from nuclear fusion processes to produce electricity. A heavier atomic nucleus is created by the fusion of two lighter ones, which also produces energy. Fusion reactors are devices created to use this energy.

Nuclear fusion is less risky than nuclear fission because the fuel rods produced by nuclear fission include dangerous radioactive waste that may be used in weapons and must be maintained carefully for thousands of years.

Powering the Sun and other stars are nuclear fusion processes. Two light nuclei combine to produce one heavy nucleus during a fusion process. The resultant single nucleus's total mass is less than the mass, which causes the process to release energy.

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Answer:

The correct answer is -2878 kJ/mol.

Explanation:

The reaction that takes place at the time of the oxidation of glucose is,  

C₆H₁₂O₆ (s) + 6O₂ (g) ⇒ 6CO₂ (g) + 6H₂O (l)

The standard free energy change for the oxidation of glucose can be determined by using the formula,  

ΔG°rxn = ∑nΔG°f (products) - ∑nΔG°f (reactants)

The ΔG°f for glucose is -910.56 kJ/mol, for oxygen is 0 kJ/mol, for H2O -237.14 kJ/mol and for CO2 is -394.39 kJ/mol.  

Therefore, ΔG°rxn = 6 (-237.14) + 6 (-394.39) - (-910.56)

ΔG°rxn = -2878 kJ/mol

Answer:  The image from the question has the correct answers.

Explanation:  

As summarized in the attached table.

Explanation:

Vanadium is in Period 4 and in the d-block of elements. The highest energy subshell is 4s. (because as electrons fill the 3d subshell, the subshell becomes of lower energy than 4s)

We have 1s²2s²2p⁶3s²3p⁶3d³4s².

Answer:

Vanadium (V) --- d-block element

Location on the periodic table :

Atomic number=23

Atomic mass=51 g/mol

The correct electron configuration for Vanadium is:

V= [Ar]4s²3d³ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³

3. 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³ is the right answer.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

ask a pro

Explanation:

hope this was helpful

Explanation:

Formula for Dichlorine trioxide is: Cl2O3

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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Answer:

I hope this helps

Explanation:

a.) The balanced equation for the reaction is:

\(H2O2 + 2H+ + 2e- → 2H2O E° = +1.78 V\\Ni2+ + 2e- → Ni E° = -0.25 V\)

b.) The balanced equation for the reaction is:

\(2H2O + Mg2+ + 2e- → H2O2 + Mg E° = -2.37 V\)

c.) The balanced equation for the reaction is:

\(2Al3+ + 3OH- → Al + 3/2O2 + 3H2O E° = +1.67 V\)

a) Assuming standard conditions of 1 M concentration for all species, the Nernst equation can be used to calculate the open circuit potential:

\(Ecell = E°cell - (RT/nF)lnQ\)

Where:

R = gas constant = 8.314 J/(mol*K)

T = temperature in Kelvin

n = number of electrons transferred in the balanced equation (in this case, 2)

F = Faraday constant = 96,485 C/mol

Q = reaction quotient =\([Ni2+]/([H2O2][H+]^2)\)

At standard conditions, Q = 1, so the equation simplifies to:

Ecell = E°cell

Ecell = +2.03 V

b) Assuming standard conditions of 1 M concentration for all species, the Nernst equation can be used to calculate the open circuit potential:

\(Ecell = E°cell - (RT/nF)lnQ\)

Where:

R = gas constant = 8.314 J/(mol*K)

T = temperature in Kelvin

n = number of electrons transferred in the balanced equation (in this case, 2)

F = Faraday constant = 96,485 C/mol

Q = reaction quotient = \([H2O2][Mg]/([H2O]^2[Mg2+])\)

At standard conditions, Q = 1, so the equation simplifies to:

Ecell = E°cell

Ecell = +2.37 V

c) Assuming standard conditions of 1 M concentration for all species, the Nernst equation can be used to calculate the open circuit potential:

\(Ecell = E°cell - (RT/nF)lnQ\)

Where:

R = gas constant = 8.314 J/(mol*K)

T = temperature in Kelvin

n = number of electrons transferred in the balanced equation (in this case, 6)

F = Faraday constant = 96,485 C/mol

Q = reaction quotient =\([Al][OH-]/([Al3+][H2O]^3)\)

At standard conditions, Q = 1, so the equation simplifies to:

Ecell = E°cell

Ecell = -1

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Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

The answer is

Explanation:

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