What is the molarity of a solution prepared by dissolving 6.0 grams of NaOH (molecular mass = 40.0 g/molto a total volume of 300 ml.

Answers

Answer 1

The molarity of the solution prepared by dissolving 6.0 grams of NaOH to a total volume of 300 ml is 0.5 M.

To calculate the molarity of a solution, we need to use the formula:
Molarity (M) = moles of solute / liters of solution
First, we need to find the number of moles of NaOH in 6.0 grams.
moles = mass / molecular mass
moles = 6.0 g / 40.0 g/mol = 0.15 mol
Next, we need to convert the volume of the solution from milliliters to liters:
300 ml = 0.3 L
Now we can plug in the values into the formula:
Molarity (M) = 0.15 mol / 0.3 L = 0.5 M
In chemistry, molarity is a unit of concentration that measures the number of moles of solute per liter of solution. It is denoted by the symbol "M." To calculate the molarity of a solution, we need to know the number of moles of solute and the volume of the solution in liters. The molecular mass of the solute is also important in determining the number of moles. It is calculated by adding up the atomic masses of the elements in the molecule. In the given question, we were asked to find the molarity of a solution prepared by dissolving 6.0 grams of NaOH to a total volume of 300 ml. By using the formula for molarity and the molecular mass of NaOH, we were able to calculate the molarity as 0.5 M. This information is useful in many applications, such as in chemical reactions, where the concentration of a solution can affect the rate and yield of the reaction.

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Related Questions

IF A CAPPED GLASS BOTTLE IS THROWN INTO A FIRE, WHAT WILL HAPPEN TO THE BOTTLE AND WHY?​

Answers

Answer:

it will explode (not intensely) there is some oxygen in the bottle so the cap would pop off violently, the longer it stays in the fire the more energy is being pent up.

Explanation:

Answer:

The bottle will increase in both temperature and pressure which will cause the bottle to crack/shatter! Hope this helps :)

Explanation:

The law of Gay-Lussac states that as temperature increases so will pressure.

Consider a 5.430 g mixture of FeO and Fe3O4. You react this mixture with excess of oxygen to form 5.779 g Fe2O3. Calculate the percent mass of FeO in the original mixture.​

Answers

Answer:

Explanation:

A 5.430 g mixture of FeO and Fe3O4 is reacted with excess of oxygen to form 5.779 g Fe2O3. Find the masses of FeO and Fe3O4 present in the mixture.

I found the answer by doing the following:

Fe2O3 = 159.69 g/mol

FeO = 71.745 g/mol

Fe3O4 = 231.535 g/mol

5.779 g Fe2O3 / 159.69 g/mol = 0.03619 mol Fe2O3

x + y :rarrow: 0.03619 mol Fe2O3, where x = FeO and y = Fe3O4.

This implies that y = 0.03619 - x.

5.430 g = x*71.745 g/mol + (0.03619 - x)*231.535g/mol

x = 0.01846 mol * 71.745 g/mol = 1.324 g FeO

y = 0.03619 - 0.01846 = 0.01773 mol * 231.535 g/mol = 4.105 g Fe3O4

My question is why doesn't the following work:

4FeO + O2 :rarrow: 2Fe2O3

4Fe3O4 + O2  :rarrow: 6Fe2O3

_______________________

2FeO + 2Fe3O4 + O2 :rarrow: 4Fe2O3

5.779 g Fe2O3 / 159.69 g/mol = 0.03619 mol Fe2O3

Product:reactants in question are in a 2:1 ratio as given by the stoichiometric coefficients.

0.03619 mol / 2 = 0.01810 mol of FeO and 0.01810 mol Fe3O4.

0.01810 mol FeO * 71.745 g/mol = 1.299 g FeO

0.01810 mol Fe3O4 * 231.535 g/mol = 4.191 g Fe3O4

Obviously this doesn't work because the original mixture is 5.430 g and not 1.299 g + 4.191 g = 5.490 g. Why doesn't this work the way I think it should? Thank you.

A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.
(⋅0.030 μg/dL) * [ ] = ? g/mL

Answers

The equation for converting a measurement from μg/dL to g/mL is as follows : (0.030 μg/dL) x 16 = 0.48.

To solve for the desired result in 0.48 g/mL, we need to multiply the given measurement (0.030 μg/dL) by the desired result (g/mL).

For example, if the desired result is 2 g/mL, then the equation is: (0.030 μg/dL) x (16 g/mL) = 0.480. This means that 2 g/mL is equivalent to 0.480 μg/dL. This can be done with any desired result.

In conclusion, the equation to convert a measurement from μg/dL to g/mL is (0.030 μg/dL) x [0.16] = 0.48. To find the desired result, simply multiply the given measurement (0.030 μg/dL) by the desired result (g/mL).

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What would happen if I removed a resistor from a parallel circuit? What would
happen if I removed a resistor from a series circuit? Explain in complete
sentences

Answers

Answer:

In a parallel circuit, current divides through resistors and current might be different depending upon the resistor and all resistors have the same potential difference. Therefore, if a parallel resistor was removed then the total resistance of the circuit will increase.

How many carbon atoms are there in .500 mol of CO2?

Answers

Answer: There are \(3.011 \times 10^{23}\) atoms present in 0.500 mol of \(CO_{2}\).

Explanation:

According to the mole concept, there are \(6.022 \times 10^{23}\) atoms present in 1 mole of a substance.

In a molecule of \(CO_{2}\) there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of \(CO_{2}\) are as follows.

\(1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}\)

Thus, we can conclude that there are \(3.011 \times 10^{23}\) atoms present in 0.500 mol of \(CO_{2}\).

which is more reactive hydrogen or Oganesson based on Electron affinity

Answers

The negatively charged atoms are known to show the electron affinity. Hydrogen is more reactive than oganesson based on electron affinity.

What is electron affinity ?

The amount of energy released when an electron is added to a neutral atom to create a negatively charged ion is known as electron affinity in chemistry.

Due to the difficulty in determining atoms' electron affinities, values are only known for a small number of chemical elements, primarily halogens.

Similar towards how chlorine can achieve the configuration of noble gases and become an electronegative ion, hydrogen has a high attraction for electrons, becoming the hydrogen anion and obtaining the stable configuration of helium.

The first synthetic element to belong to group 18 (the noble gases), oganesson has the potential to be substantially more reactive than the other members of that group.

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salts are composed of both cations and anions, both of which can potentially affect ph. which of the following salts would you test if you wanted to observe how just anions affect ph? group of answer choices nach3coo cacl2 nahco3 tris-hcl na2co3 nh4cl

Answers

The salt which you would test if you wanted to observe how just anions affect pH is Na2CO3.

What is salt? Salts are inorganic compounds made up of a cation and an anion. Salts are formed by the neutralization of an acid with a base, for example, hydrochloric acid and sodium hydroxide form table salt: NaCl. The cation is typically a metal or a positively charged organic compound, whereas the anion is generally a non-metal or a negatively charged organic compound. The salt's properties are a function of the cation and anion and are hence unique.

Salt's effect on pH: Salts are made up of cations and anions, both of which can have an impact on pH. Cations and anions can both have an impact on the pH of the solution, but they can do it in different ways. The pH of a solution can be affected by the anion of the salt since it can act as a base or an acid. The pH of a solution can be affected by the cation of the salt since it can act as an acid or a base. For instance, if we dissolve copper sulfate in water, the pH of the solution will be acidic since the sulfate ion will be hydrolyzed to create sulfuric acid, H2SO4.

However, if we dissolve sodium carbonate in water, the pH of the solution will be basic because the carbonate ion acts as a base, picking up H+ ions from water molecules to generate HCO3- ions. Hence, Na2CO3 is the salt which you would test if you wanted to observe how just anions affect pH.

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Which statement about cellular respiration in plants and animals is true?

Both plants and animals need water to start cellular respiration.

Both plants and animals release energy from glucose in cellular respiration.

Both plants and animals take in carbon dioxide to break down glucose in cellular respiration.

Both plants and animals need chlorophyll to make glucose before using it in cellular respiration.

Answers

Answer:

Both plants and animals release energy from glucose in cellular respiration.

1.
Sabrina was asked by a classmate why she would place hydrogen in the first column of the periodic tab le. Which of the following reasons could she give as a response?
1. Hydrogen combines with chlorine in the same atomic ratio as sodium.
II. Hydrogen is a gas at room temperature.
III. Hydrogen forms diatomic molecules.
А A
I and II
B. Oll and III
COI only
D. Ill only

Answers

Answer:

The correct option is;

C. I only

Explanation:

Given that in a chemical reaction, the number of valence electrons in the outermost shell of an atom determines the ratio in which the atom combines with other atoms to have the stable 8 (octet) valence electrons in their outermost shell, we have that atoms in a group combines with atoms in other groups, where possible, in the same ratio.

Therefore, sodium, which is in the first column (group I) combines with atoms of elements in other groups, in the same ratio as atoms of the other elements of the column 1

Since hydrogen combines with chlorine in the same ratio as sodium which is from the first column, hydrogen is also an element from the first column.

PART OF WRITTEN EXAMINATION:
What is the first line of defense in Cathodic Protection?
A) impressed current systems
B) grounding rods
C) coating of the pipe
D) holidays
E) carbon

Answers

The first line of defense in Cathodic Protection is the coating of the pipe. This is because the coating serves as a barrier that prevents the pipe from coming into contact with the corrosive environment. The coating, if applied properly, can last for many years and protect the pipe from corrosion.

The coating such as holidays areas where the coating is missing, then the pipe will be exposed to the corrosive environment and will start to corrode. This is where Cathodic Protection comes in. It is a technique used to protect metallic structures from corrosion by making the structure the cathode of an electrochemical cell. By doing so, the metal is protected from corrosion as it is the cathode and not the anode. Impressed current systems and grounding rods are both methods of providing Cathodic Protection, but they are not the first line of defense. Carbon is not a relevant term in the context of Cathodic Protection. In summary, the coating of the pipe is the first line of defense in Cathodic Protection, and if it is damaged, then Cathodic Protection methods such as impressed current systems and grounding rods can be used to protect the structure.

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A 10 kg bicycle is rolling down a hill at 5 m/s, what is its momentum?

Answers

Answer:

50 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 10 × 5

We have the final answer as

50 kg.m/s

Hope this helps you

Question One: Compare and contrast a kitchen recipe to a chemical equation. Be specific and use academic vocabulary.
Questoin Two: Do you think balancing an equation could also apply to a kitchen recipe? Why or why not?

Answers

Answer:

Question One:

A kitchen recipe and a chemical equation are similar in that both involve the combination of specific ingredients in a specific manner to produce a desired outcome. However, there are some key differences between the two.

In a kitchen recipe, the ingredients are usually listed in a descriptive, qualitative manner, often with rough measurements (e.g. "one cup of sugar"). The recipe may also include instructions for preparation, such as cooking or mixing, that are not included in a chemical equation.

A chemical equation, on the other hand, represents a chemical reaction using quantitative, symbolic representations of the reactants and products. The reactants are listed on the left-hand side of the equation and the products on the right-hand side. The coefficients in a chemical equation indicate the number of molecules or moles of each substance participating in the reaction.

Overall, a kitchen recipe and a chemical equation both serve as guides for a process that involves the combination of ingredients, but the nature of the information and the type of outcome being described are different.

Question Two:

Balancing an equation could not directly apply to a kitchen recipe. A kitchen recipe does not have the same level of precision or quantitative detail as a chemical equation. Additionally, a kitchen recipe is more focused on taste and appearance, whereas a chemical equation must be balanced in terms of mass and charge to accurately represent the reaction. While the principles of measuring and combining ingredients in a recipe may be similar to balancing an equation, the end goals and criteria for success are quite different.

Explanation:

1. Both a kitchen recipe and a chemical equation provide a sequential set of instructions that guide the process to achieve a specific result, but while a recipe guides the preparation of food with descriptive language, a chemical equation represents a chemical reaction using chemical symbols and formulas.

2. Balancing an equation does not apply to a kitchen recipe because recipes focus on taste and presentation, allowing flexibility and adaptation.

1. A kitchen recipe and a chemical equation share some similarities but also have distinct differences. Both involve a set of instructions or steps to produce a desired outcome, but they serve different purposes and use different language and symbols.

Similarities:

a) Both a kitchen recipe and a chemical equation provide a sequential set of instructions that guide the process to achieve a specific result.

b) Ingredients/Reactants: In both cases, there is a list of ingredients (in a recipe) or reactants (in a chemical equation) that are combined to produce the final product.

Differences:

a) Purpose: The primary purpose of a kitchen recipe is to guide the preparation of food, focusing on taste, texture, and presentation. On the other hand, a chemical equation's purpose is to represent a chemical reaction, focusing on the transformation of reactants into products and the conservation of mass and charge.

b) Language and Symbols: Kitchen recipes typically use descriptive language, measurements (cups, teaspoons, etc.), and cooking times, whereas chemical equations use chemical symbols and formulas to represent elements and compounds, along with coefficients to balance the equation.

2. Balancing an equation, as it is done in chemical reactions, is not applicable to kitchen recipes. The concept of balancing an equation is specific to chemical reactions and is based on the fundamental laws of conservation of mass and charge.

In kitchen recipes do not involve chemical reactions, and there are no strict conservation laws to follow. The focus of a recipe is to create a dish with a specific taste, texture, and presentation, rather than ensuring the conservation of mass or other chemical properties.

Recipes are designed to be flexible, allowing adjustments based on personal preferences, dietary restrictions, and ingredient availability. Balancing a kitchen recipe, as in a chemical equation, would not have any meaningful significance or practical application in the culinary context. Instead, recipes are intended to be adaptable and creative, leaving room for individual tastes and culinary experimentation.

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Boyle's law foc endosed gases states that if the volume is kept constant, the pressure P and temperature T are related by the equinton P/T
=k Where k is a constant. If the tenperature is increasing at 3 kelvins per hour, what is the rate of charge of pressure when the temperature is 150keivins and the pressure is 300 pounds per squ inch? The rate of change of pressure is pounds per square inch per hous, (Simplity your answer) Find the relative rate of change of f(x)=100x−0.2x .2
.The relative rate of change of f(x) is

Answers

The rate of change of pressure is -900 pounds per square inch per hour.

According to Boyle's law, if the volume is kept constant, the pressure P and temperature T are inversely proportional, as expressed by the equation P/T = k, where k is a constant. To find the rate of change of pressure, we need to differentiate the equation with respect to time.

Since temperature is increasing at a rate of 3 kelvins per hour, we can substitute the given values into the equation.

Temperature (T) = 150 kelvins

Pressure (P) = 300 pounds per square inch

Differentiating the equation P/T = k with respect to time, we get:

dP/dt = (dP/dT) * (dT/dt)

Since the volume is constant, dP/dT is equal to -k. Therefore, we have:

dP/dt = -k * (dT/dt)

Substituting the given values:

dT/dt = 3 kelvins per hour

P = 300 pounds per square inch

We can simplify the equation to find the rate of change of pressure:

dP/dt = -k * (dT/dt) = -k * 3 = -3k

To determine the value of k, we need additional information. Since the problem statement does not provide a specific value for k, we cannot determine the exact rate of change of pressure.

However, we can express the rate of change of pressure as -900 pounds per square inch per hour, as k would cancel out when dividing the pressure by time.

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How much heat is produced from the complete combustion of 30.0 g of methane, if the enthalpy of reaction is -890 kj/mol?

Answers

The heat produced from the complete combustion of methane is 1,664.59 kJ.

The chemical energy from the combustion reaction is converted into thermal energy. The thermal energy or heat produced by a mole of a substance, methane, would be the same as the enthalpy of reaction/combustion.

First, we need to determine the number of moles of methane. As stated in the problem, complete combustion is achieved for 30.0g of methane. The molecular weight (MW) of methane is 16.04 g/mol.

Mole methane= mass methane/MW methane

Mol methane= 30 g / 16.04 g/mol

Mol methane= 1.87 mol

We can now multiply it by the given enthalpy of the reaction to determine the heat produced.

Heat produced= enthalpy of reaction * mol methane

Heat produced= 890 kJ/mol * 1.87 mol

Heat produced= 1,664.59 kJ

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List three specific examples of a physical change.

Answers

Answer:

Cutting hair is a physical change since it doesn't change the substance its still hair

bending a paper clips since it's also the same substance

Ice cube melting

Explanation:

All of these are physical change since there reversible and they all still stay the same substance

Physical change is something reversible ,

So if u melt ice it is a physical change because you can freeze it again.

Cutting your hair and nails are physical because they grow again.

Boiling water is also a physical change.

bro needs help

32.5 grams of NaOH reacts with an excess of CO2

2NaOH(s) + CO2(g) ⇒ Na2CO3(s) + H20

What is the theoretical yield of Na2CO3 in grams?

*** I NEED YOU TO SHOW YOUR WORK BROS, I ALREADY HAVE THE ANSWER (43.1g) ***

Answers

i tried and got 6.89g of Na2CO3

The reaction nC2H4 + (-C2H4-)n is
an
example of
1.
saponification
2.
esterification
3.
polymerization
4.
fermentation

Answers

Answer:

Polymerization

Explanation:

Polymerization is the process by which molecules of small organic compounds combine repeatedly, in a regular manner, to form a complex organic compound. These small organic repeated units are called monomers, while the complex product formed are referred to as polymer.

In this reaction,

nC₂H₄ + -(C₂H₄-)n is the combination of smaller units of C₂H₄(ethene) to form larger units of (C₂H₄)n (polyethene).

Polyethene is formed due to addition polymerization which is the process where ethene break their double bonds to form links, so that the empirical formula of both are the same. This occurs in a chain reaction and the process is known as polymerization.

Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. What is the mass in grams of 355 mL of ethylene glycol?

Answers

Density=1.11g/mLVolume=355mL

\(\\ \bull\tt\leadsto Density=\dfrac{Mass}{Volume}\)

\(\\ \bull\tt\leadsto Mass=Density\times Volume\)

\(\\ \bull\leadsto Mass=1.11(355)\)

\(\\ \bull\leadsto Mass=394.05g\)

What percentage of the Earth's surface is covered by oceans?

Answers

Question:

What percentage of the Earth's surface is covered by oceans?

Answer:

71 percentage

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Question:

What percentage of the Earth's surface is covered by oceans?

Answer:

71 percent/%

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Which anaplerotic reaction balances the input of oxaloacetate with acetyl-CoA in the citrate cycle by converting pyruvate into oxaloacetate

Answers

The answer is that the anaplerotic reaction that balances the input of oxaloacetate with acetyl-CoA in the citrate cycle by converting pyruvate into oxaloacetate is called pyruvate carboxylase

. Pyruvate carboxylase is an enzyme that catalyzes the carboxylation of pyruvate to form oxaloacetate, which can then enter the citrate cycle as a substrate for the condensation with acetyl-CoA.

The citrate cycle is a complex metabolic pathway that involves the conversion of acetyl-CoA into ATP through a series of enzyme-catalyzed reactions. One of the key substrates required for this process is oxaloacetate, which combines with acetyl-CoA to form citrate, the first product of the cycle. However, the amount of oxaloacetate available in the cell is often limited, and its concentration can fluctuate depending on the metabolic state of the cell.

To maintain a steady supply of oxaloacetate, the cell relies on anaplerotic reactions, which are biochemical pathways that replenish the intermediates of the citrate cycle. Pyruvate carboxylase is one such anaplerotic reaction that converts pyruvate, a product of glycolysis, into oxaloacetate. This reaction is important because it allows the cell to balance the input of acetyl-CoA with the input of oxaloacetate, ensuring that the citrate cycle can continue to produce ATP efficiently.

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Which image shows a cumulonimbus cloud

1

2

3

4

Answers

Answer:

2

Explanation:

Answer:

2

Explanation:

i took the test on edg 2022 good luck on you test :)

Calculate the mass of nitrogen dissolved at room temperature in an 92.0 l home aquarium. assume a total pressure of 1.0 atm and a mole fraction for nitrogen of 0.78.

Answers

The mass of nitrogen dissolved in the 92.0 L home aquarium at room temperature is 778.48 grams.

The mass of gases refers to the amount of matter or substance present in a gaseous state. It represents the total mass of all the gas particles within a given volume.

In the study of gases, the mass of gases is often expressed in terms of molar mass, which is the mass of one mole of the gas. Molar mass is typically measured in grams per mole (g/mol).

The mass of gases can be calculated using the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas. The ideal gas law equation is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

n = X × P × V / (R × T)

Given :

P = 1.0 atm

V = 92.0 L

X = 0.78 (mole fraction of nitrogen)

T = 25 + 273.15 = 298.15 K.

n = 0.78 × 1.0 atm × 92.0 L / (0.0821 L.atm/mol.K × 298.15 K)

n = 27.86 moles

Mass of nitrogen = n × molar mass

Mass of nitrogen = 27.86 moles × 28.0 g/mol

Mass of nitrogen = 778.48 g

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A student investigated temperature changes during a reaction. Figure 2 shows the apparatus the student usesWhat is the biggest error in this investigation.Suggest two improvements to the apparatus which would increase the accuracy of the experiment.
[3 marks]

A student investigated temperature changes during a reaction. Figure 2 shows the apparatus the student

Answers

Answer:

it is becuse the students used wrong apparatus

The biggest error in this investigation is the use of inappropriate types of equipment.

The types of equipment used in the given setup are inappropriate. Suggested improvements in the apparatus to increase the accuracy are given below:

1. The use of a polystyrene cup in the laboratory for any reaction is inappropriate. As a slight increase in temperature causes the decomposition of the chemicals in the cup as well.

2. The use of a thermometer stand is a must. Without using the stand, the tip of the thermometer touches the lid of the container, which causes inaccuracies in the result.

Hence, all the suggestions are listed above.

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PLEASE HELP SOMEONE !!!!!!!!!!!!!!!!!!!

PLEASE HELP SOMEONE !!!!!!!!!!!!!!!!!!!

Answers

Answer:

sodium

Explanation:

sodium has 11 electrons.

which theory explains how glacial material can be observed today near sea level at the equator, even though sea level glaciers probably never existed there

Answers

The theory that explains how glacial material can be observed today near sea level at the equator, even though sea level glaciers probably never existed there, is called glacial erratics.

Glacial erratics are large rocks that have been transported from their place of origin by glaciers and deposited far away. During the Pleistocene era, glaciers covered much of the earth, including areas near the equator. As these glaciers retreated, they left behind glacial erratics that can still be observed today. These rocks provide evidence of the extent of past glaciation and help scientists understand the history of the earth's climate.
The theory that explains the presence of glacial material near sea level at the equator is Plate Tectonics. This theory describes Earth's crust as being composed of large, moving plates that interact with one another. Over millions of years, these plates have shifted continents, leading to the distribution of glacial material in various locations, including equatorial regions. Glaciers likely formed at higher latitudes and altitudes during past ice ages, and as the plates moved, the glacial deposits were carried along, eventually reaching their current positions near sea level at the equator. This process demonstrates the dynamic nature of Earth's surface and its geological history.

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Bakelite is one of the first known synthetic polymers and was used to make radio and telephone casings as well as automobile parts in the early twentieth century.


a. True

b. False

Answers

True, Bakelite was used to make radio and telephone casings as well as automobile parts in the early twentieth century.

Was Bakelite used to make radio and telephone casings as well as automobile parts in the early twentieth century?

Bakelite, one of the first known synthetic polymers, was indeed used extensively in the early twentieth century to manufacture radio and telephone casings, as well as automobile parts.

Developed by Belgian chemist Leo Baekeland in the early 1900s, Bakelite was a groundbreaking material that revolutionized the field of plastics. It offered exceptional electrical insulating properties, heat resistance, and durability, making it ideal for applications in the burgeoning electronics and automotive industries of that time.

Bakelite's ability to be molded into various shapes and its affordability further contributed to its widespread use in these specific industries during the early twentieth century. Bakelite marked a significant milestone in the development of synthetic polymers, paving the way for the production of countless plastic materials we rely on today.

Its successful application in radio and telephone casings and automobile parts demonstrated the potential of synthetic polymers to replace traditional materials like wood, metal, and glass.

Bakelite's impact on industrial manufacturing, as well as its historical significance in the early days of plastics, underscores the role of scientific advancements in shaping various industries and technologies.

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Determine if the following reaction is a redox reaction. Use evidence from the equation to explain your reasoning.

Determine if the following reaction is a redox reaction. Use evidence from the equation to explain your

Answers

A redox reaction is a chemical reaction in which one or more of the reacting species undergoes oxidation and one or more undergoes reduction. An oxidizing agent is an element or compound that oxidizes another substance, while a reducing agent is an element or compound that reduces another substance.

The following reaction is a redox reaction based on the following evidence: 2Al + 3FeO → Al2O3 + 3Fe2+ In this reaction, Fe is being reduced because the FeO is changing to Fe2+. Additionally, the Al is being oxidized because it is losing electrons and forming Al2O3. Therefore, the reaction is a redox reaction. Let us take a look at the oxidation state of the elements in the given equation. Oxidation state of Al: (2) for the reactant and (3+) for the product. Oxidation state of Fe: (2+) for the reactant and (2+) for the product. Oxidation state of O: (-2) for the reactant and (-2) for the product. We can tell that oxidation is happening because of the increase in the oxidation state of Al from 2 to 3+. We can tell that reduction is happening because of the decrease in the oxidation state of Fe from 2+ to 2. As a result, the given equation is a redox reaction.

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PLEASE HELP NEED ANSWER ASAP!!!!
Use 3 H2(g) + N2(g) <--> 2 NH3 (g) + 92.4 kJ

At equilibrium, if the hydrogen (H2) concentration is increased, the ammonia(NH3) concentration will

Select one:
a. decrease
b. shifts back and forth
c. increase
d. remain the same

Answers

Answer:

the correct answer is option A. decrease

1. the ball has no energy
2. it has both potential and kinetic energy
3. all of the ball's energy is kinetic
4. all of the ball's energy is potential

1. the ball has no energy2. it has both potential and kinetic energy3. all of the ball's energy is kinetic4.

Answers

Answer:

2

Explanation:

It is going through the air and is moving so that means that it has kinetic energy. But it is also going to go the down, which gives it potential energy.

What is the freezing point, in °C, of a 0.407 m solution of C5H4 in benzene? FP (benzene) = 5.5 °C Kf(benzene) = 5.12 °C/m​

Answers

The freezing point, in °C, of a 0.407 m solution in benzene is 3.42°C

How to calculate freezing point?

Freezing point refers to the temperature at which a liquid freezes, and the solid and liquid phases are in equilibrium.

According to this question, a 0.407 m solution is in benzene solution. The freezing point of the solution can be calculated as follows:

∆T = K × m

Where;

K = freezing point constant∆T = freezing pointm = molality

∆T = 5.12 × 0.407

∆T = 2.084°C

Freezing point in benzene = 5.5°C - 2.084°C = 3.42°C

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Answer:

b, d,  -13.4

Explanation:

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