What is the molar solubility of Pbl2 (Ksp 8.4x 10^-9) in a solution containing 0.15 M Kl(aq)? 0 a. 3.7x 10-7 M O b.6.1 x 10-4 M O c. 5.6 x 107 M O d. 1.9 x10-6 M

Answer:

initial velocity(u)=0

time(t)=3.5sec

acceleration (a)=9.8m/s²

final velocity (v)=?

Explanation:

we have

v=u+at=0+9.8×3.5=34.3m/s

Answer:

t = V0 sin theta / g      time to get max height

h = Voy t - 1/2 g t^2 = Vo^2 sin^2 theta / 2 g          max height

R = V0^2 sin 2 theta / g      range formula

h = 3 R        given

Vo^2 sin^2 theta / 2 g = 3 * V0^2 sin 2 theta / g

sin^2 theta = 6 * sin 2 theta = 12 * sin theta cos theta

tan theta = 12

theta = 85.2 deg

Can check:  

Vx = 8.37

Vy = 99.6     assuming V0 =100

t = 99.6 / 9.8 = 10.2 sec     to reach max height

Sx (total range) = 2 * 10.2 * 8.37 = 170 m

Sy = 1/2 * 9.8 * (10.2)^2 = 510 m

Height = 3 * range

Explanation:

The sun gravity keeps the solar system i.e planets in its place and orbits if there is no sun the planets would flying off and  It would be complete and utter chaos in our solar system

(a) Moment of the wedge shift is 21168 kg-m. (b) The moment of the centre of buoyancy shift is 36.7 kN-m. (c) The value of the righting moment or upsetting moment is 42.2 kN-m.

a. The moment of the wedge shift in kg-m can be calculated by multiplying the weight of water displaced by the area of the triangle formed by the triangle's centroid and the point at which the triangle intercepts the waterline.

The moment of the wedge shift is given by;

Moment of the wedge shift = weight of water displaced x distance from the centroid of the triangle to point of interception of the waterline

= (0.5 × AB × AC × BC) ρ g d= (0.5 × 4.5 × 2.4 × AB) ρ g d= 5.4 AB ρ g

where AB is the distance between the centerline of the barge and the point of interception of the waterline.ρ is the density of water = 1000 kg/m3.g is the acceleration due to gravity = \(9.81 m/s^2\).

Substituting \(AB = 0.4 m,\rho = 1000 kg/m^3,g = 9.81 m/s^2\) in the above equation:

Moment of the wedge shift = 21168 kg-m.

b. Moment of the centre of buoyancy shift is given by the formula,

Moment of the centre of buoyancy shift = GM x displacement

Where, Gm = the distance between the centre of gravity and the metacentre. Displacement = the weight of water displaced by the barge.

The distance Gm can be calculated using the formula:

Gm = I/V

where I is the second moment of area of the waterplane about its longitudinal axis and V is the volume of displacement.  

The second moment of area:

I = b x d3/12

where b is the breadth of the waterplane and d is the depth of the waterplane below the waterline.

The volume of displacement =\((12 * 4.5 * 2.4) m^3= 129.6 m^3\)

The distance Gm can be calculated as follows:

Gm = I/V= [4.5 × (2.4)3]/12 ÷ [12 × 4.5 × 2.4]= 0.28 m

The displacement of the barge is given by;

Displacement =\(12 * 4.5 * 2.4 * 1000 kg/m^3= 129.6 kN\)

Thus, the moment of the centre of buoyancy shift = GM x displacement

= (0.28 m × 129.6 kN) = 36.7 kN-m

c. Value of the righting moment or upsetting moment can be calculated using the formula;

Upsetting moment = W × GM

where W is the weight of the barge. The weight of the barge can be calculated using the formula:

Weight of barge = Displacement + weight of the wedge

= 129.6 + 21.12= 150.72 kN

The distance between the centre of gravity and the metacentre (Gm) has already been calculated as 0.28 m.

Therefore, the Upsetting moment = W × GM= 150.72 × 0.28= 42.2 kN-m

Therefore, the value of the righting moment or upsetting moment is 42.2 kN-m.

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We know the formula

So

if magnitude of charge is increased the force between them also increased.

And if the distance between them is decreased them also the force will be increased.

So Force increases

Answer:

D. 125 kg-m/s east

Explanation:

     N

W        E

     S

momentum of box moving east: 52 * 9 = 468 kg-m/s east

momentum of box moving west:  49 * 7 = 343 kg-m/s west

so finally moving towards, 468 - 343 = 125 kg-m/s east

Answer: 0.488  m

Explanation: I have my ways ;>

The conditions established by forward- and reverse-bias conditions on a P-N junction diode are: For forwarding bias, the current flows easily without opposition, this causes more current to pass, For reversed bias, the current flow is restricted and this causes less amount of current to pass.

A forward bias is a state attained by a diode as a result of its positive terminal that is connected to the positive part of a circuit and its negative terminal connected to the negative part of the circuit.

A reversed bias is a state attained by a diode as a result of its positive terminal that is connected to the negative part of a circuit and its negative terminal connected to the positive part of the circuit.

In conclusion, The conditions established by forward- and reverse-bias conditions on a P-N junction diode are: For forwarding bias, the current flows easily without opposition, which causes more current to pass, For reversed bias, the current flow is restricted and this causes less amount of current to pass.

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The conditions established by forward- and rear- bias conditions on a P- N junction diode are For encouraging bias, the current flows fluently without opposition, this causes further current to pass, For reversed bias, the current inflow is confined and this causes lower quantum of current to pass.

Meaning of a Forward and reversed bias-

A reversed bias is a state attained by a diode as a result of its positive outstation that's connected to the negative part of a circuit and its negative terminal connected to the positive part of the circuit.

In conclusion, The conditions established by forward- and rear- bias conditions on a P- N junction diode are For encouraging bias, the current flows fluently without opposition, which causes further current to pass, For reversed bias, the current inflow is confined and this causes lower quantum of current to pass.

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Answer:

The fluid friction or drag can be reduced are minimised by giving special shape called streamlined shape to the objects which Move through fluids like air or water

Answer:

ggggggggggggggggggggggggg

Answer:

We have the position vector given in terms of time t. r(t) = t^3*i + t^2*j

To find the velocity vector we have to differentiate r(t) with respect to time.

r'(t) = 3t^2*i + 2t*j

The vector representing acceleration is the derivative of the position vector

r''(t) = 6t*i + 2*j

When time t = 2.

The velocity vector is 3*2^2*i + 2*2*j

=> 12*i + 4*j

The speed is the absolute value of the velocity vector or sqrt(12^2 + 4^2) = sqrt (144 + 16) = sqrt 160

The acceleration vector is 6*2*i + 2*j

=> 12*i + 2*j

The required acceleration at t=2 is 12*i + 2*j and the speed is sqrt 160.

Explanation:

Can I have thx and brainliest?

Answer: a fuse wire is a wire of high resistance and low melting point.

Answer: density = 1.36g/cm3

Explanation: 0.025L = 25cm3 and 0.034kg = 34 grams

  Density= mass/volume

           = 34/25

           = 1.36g/cm3

Answer:

Explanation:

Given:

V = 0.025 l;   or V = 25 cm³

m = 0.034 kg = 34 g

______________

ρ - ?

ρ = m / V

ρ = 34 / 25 = 1.36 g/cm³

To determine the magnitude of the acceleration of the motorcycle, we need to know the force of friction acting on the wheels. The force of friction is equal to the coefficient of friction multiplied by the normal force acting on the wheels, which is equal to the weight of the motorcycle and rider. The weight of the motorcycle and rider can be calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s^2). So, the force of friction acting on the wheels of the motorcycle is equal to 0.88 * 196 kg * 9.8 m/s^2 = 1661.28 N.

The acceleration of the motorcycle is equal to the force of friction divided by the mass of the motorcycle and rider. So, the acceleration of the motorcycle is equal to 1661.28 N / 196 kg = 8.45 m/s^2.

Answer:  8.45 m/s^2

Troposphere, stratosphere, mesosphere, thermosphere and exosphere.

Earth's atmosphere has five major layers.

From lowest to highest, layers are the troposphere, stratosphere, mesosphere, thermosphere and exosphere.

a) What are the conditions in the troposphere?

The atmospheric temperature descends upward with a slope of ~10 K km−1 for dry air and ~7 K km−1 for wet air in troposphere.

The temperature of troposphere decreases with an increase in height.

B) What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere?

The temperature in the stratosphere ranges from- 60° F at the troposphere boundary to -5°F at the top.

The temperature increase is due to the ozone layer that absorbs ultraviolet light from solar radiation.

C)What sort of temperatures would she experience in the mesosphere?

The temperature in the mesosphere ranges from -2.5°C to -90°C

The temperature decreases because of a decrease in the absorption of penetrating solar radiation.

The atmosphere gets cooler with an increase in altitude because an increase in distance from the Earth's surface.

D)What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere?

4,500°F is the temperature of thermosphere.

Temperatures climb sharply in the lower thermosphere , then level off and hold fairly steady with increasing altitude above that height.

Temperatures in the upper thermosphere can range from about 500° C (932° F) to 2,000° C (3,632° F) or higher.

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Answer:

Sections 3 and 4

Explanation:

The correct answer would be sections 3 and 4.

The velocity of an object is the speed of the object in a particular direction. In this case, the speed of the racer is constant irrespective of the distance or the direction. Hence, the sections of the race during which the racer's velocity would be the same would be the sections in which the racer faces the same direction - which is sections 3 and 4.

The lump of clay at 10 m/s has a larger initial momentum compared to the clay at 5 m/s. When the clay comes to a stop, the change in momentum for the clay at 10 m/s is greater than that of the clay at 5 m/s. Thus, the 1 kg lump of clay moving at 10 m/s experiences a greater impulse.

Impulse is defined as the change in momentum of an object and is calculated by multiplying the force exerted on an object by the time interval over which the force acts. In this case, impulse is given by the equation:

Impulse = Force × Time

Since we are comparing two scenarios with the same mass, the impulse depends solely on the velocity and time. The greater the change in velocity and the longer the time interval, the greater the impulse.

In the given scenario, the 1 kg lump of clay has a velocity of 10 m/s. Therefore, its initial momentum is given by:

Initial momentum = mass × initial velocity

                = 1 kg × 10 m/s

                = 10 kg·m/s

If this lump of clay comes to a stop, its final momentum would be zero. The change in momentum is therefore:

Change in momentum = final momentum - initial momentum

                 = 0 - 10 kg·m/s

                 = -10 kg·m/s

However, impulse is a scalar quantity, meaning it only represents magnitude. Therefore, the negative sign is disregarded, and the magnitude of the impulse is 10 kg·m/s.

Now let's consider the other scenario, where the lump of clay has a velocity of 5 m/s. The initial momentum in this case is:

Initial momentum = 1 kg × 5 m/s

                = 5 kg·m/s

If this lump of clay comes to a stop, its final momentum would be zero. The change in momentum is therefore:

Change in momentum = final momentum - initial momentum

                 = 0 - 5 kg·m/s

                 = -5 kg·m/s

Again, we disregard the negative sign and consider the magnitude of the impulse, which is 5 kg·m/s.

Comparing the two scenarios, we can conclude that the 1 kg lump of clay at 10 m/s has a greater impulse (10 kg·m/s) compared to the 1 kg lump of clay at 5 m/s (5 kg·m/s).

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The total of all forces acting on an object is known as the net force. A mass can accelerate due to net force.

The total of all forces acting on an object is known as the net force. A mass can accelerate due to net force. Whether a body is at rest or in motion, it is subject to another force. When there are a lot of forces acting on a system, the term "net force" is used.

here r12 = 0.550m r23= = 0.550m Then the distance from the first charge to the third one will be:

r13 =r12+r23=0.550+0.550 = 1.1m

According to the Coulomb's law, the net force on particle q2 will be equal to the sum of the forces on particle q2 from the particle q1 and q3.

F3+=F13+F23=q1q2/r²13 + k q3q2/r²23

Where k = 9×\(10^{9}\) N m²/C²

Substituting numerical values, obtain:

F3= 9×\(10^{9}\)(-66.3 × \(10^{-6}\))(-43.2×9×\(10^{-6}\))/1.45²+9 ×\(10^{9}\) 108×\(10^{-6}\)(-43.2 ×\(10^{-6}\))/0.550²

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Answer:

ammeter

Explanation:

hope this helps

Answer:

70 km/h

Explanation:

70 divided by 2 = 35

Answer:

The correct choice is D. Its gravitational potential energy must increase

Explanation:

Conservation of Mechanical Energy

The total amount of mechanical energy, in a closed system in the absence of dissipative forces like friction or air resistance, remains constant.

This means that energy cannot disappear or appear and that potential energy can become kinetic energy or vice versa.

In a closed system like a pendulum, two types of energies are considered: Gravitational potential (U) and kinetic (K). Thus, the sum of both energies must remain constant in time.

Suppose the pendulum is at a state where U=150 J, and K=350 J. The total mechanical energy is:

M = 150 J + 350 J = 500 J

If the kinetic energy decreases to a new value, say K = 200 J, then the gravitational potential must increase to compensate for this new condition, that is: U = 300 J

The correct choice is D. Its gravitational potential energy must increase

Taking into account the definition of kinetic, potencial and mechanical energy, the correct answer is option D:  If  the pendulum's kinetic energy decreases Its gravitational potential energy must increase.

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and at rest, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its state of rest by applying a force.

On the other hand, potential energy is the energy that measures the ability of a system to perform work based on its position. In other words, this is the energy that a body has at a certain height above the ground.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the force of gravity.

Finally, mechanical energy is that which a body or a system obtains as a result of the speed of its movement or its specific position, and which is capable of producing mechanical work. Then:

Potential energy + kinetic energy = total mechanical energy

The principle of conservation of mechanical energy indicates that the mechanical energy of a body remains constant when all the forces acting on it are conservative (a force is conservative when the work it does on a body depends only on the initial and final points and not the path taken to get from one to the other.)

Therefore, if the potential energy decreases, the kinetic energy will increase. In the same way, if the kinetics decreases, the potential energy will increase.

This principle can be applied in this case. The mechanical energy of the pendulum remains constant when all the forces acting on it are conservative.

So, the correct answer is option D:  If  the pendulum's kinetic energy decreases Its gravitational potential energy must increase.

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Answer: 2.390 J (joules).

Explanation:

Given:

Mass of tennis ball = 0.051 kg

Velocity of tennis ball = 9.7 m/s

To find:

Kinetic energy of the tennis ball

Solution:

Using the formula for kinetic energy:

Kinetic energy = (1/2) * mass * velocity^2

Plugging in the values:

Kinetic energy = (1/2) * 0.051 kg * (9.7 m/s)^2

Kinetic energy = (1/2) * 0.051 kg * 94.09 m^2/s^2

Kinetic energy = 2.390 J

Therefore, the kinetic energy of a 0.051 kg tennis ball moving at 9.7 m/s is 2.390 J (joules).

Explanation:

Research in humans should be based on from library and animal experimentation . Research protocols should be reviewed by an independent committee prior to initiation

a) The A-parameters of the cascaded network are defined by (4 points)Answer:a_11 = 0.149 S^0.5 - 0.0565a_12 = -0.115 S^0.5 - 0.0352a_21 = 136 S^0.5 - 133a_22 = -89.5 S^0.5 + 135b) Find ZL such that maximum power is transferred from the cascaded network to ZL. (2 pointsZ). The maximum power transfer to load impedance ZL occurs when the load is equal to the complex conjugate of the source impedance.

We can calculate the source impedance as follows: Rs = 30 Ω || 1/0.167^2 = 31.2 ΩThe equivalent impedance of circuits 2 and 3 connected in cascade is: Zeq = Z2 + Z3 + Z2 Z3 Y2Z2 + Y3 (Z2 + Z3) + Y2 Y3If we substitute the corresponding values: Zeq = 6.875 - j10.75ΩNow we can determine the value of the load impedance: ZL = Rs* Zeq/(Rs + Zeq)ZL = 17.6 - j8.9Ωc) Evaluate the maximum power that the cascaded two-port network can deliver to ZI. (2 points). The maximum power that can be delivered to the load is half the power available in the source.

We can determine the available power as follows: P = (I_s)^2 * Rs /2P = 558 mW. Now we can calculate the maximum power transferred to the load using the value of ZL:$$P_{load} = \frac{V_{load}^2}{4 Re(Z_L)}$$$$V_{load} = a_{21} I_s Z_2 Z_3$$So,$$P_{load} = \frac{(a_{21} I_s Z_2 Z_3)^2}{4 Re(Z_L)}$$Substitute the corresponding values:$$P_{load} = 203.2 m W $$. Therefore, the maximum power that can be delivered to the load is 203.2 mW.

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The difference between the wavelengths of diffraction grating that has 900 slits/cm and screen distance from the grating is 2.20 m, and the separation between maxima is 3.20 mm (3.20 × 10⁻³ m) is 4.58 × 10⁻⁷ m.

To calculate the difference between these wavelengths, the first-order spectrum is given:

dsinθ = mλ

Where:

For m = 1, d = 1/90000 m, sinθ = 1 and λ = d/1 = d = 1/90000 m

For the first-order spectrum, the difference between the wavelengths of the two diffracted beams separated by 3.20 mm on the screen is given by:

Δλ = λ₂ - λ₁ = y(Δθ)λ = yλ / d

Here, Δθ = θ₂ - θ₁ = sin⁻¹(y/D) - sin⁻¹(0/D) = sin⁻¹(y/D)

D = distance between grating and screen = 2.20 m

On substitution,

Δλ = y(Δθ)λ / d

= (3.20 × 10⁻³ m) (sin⁻¹(3.20 × 10⁻³ m/2.20 m))(1/90000 m)

= 4.58 × 10⁻⁷ m

Therefore, the difference between the wavelengths of the two diffracted beams separated by 3.20 mm on the screen is 4.58 × 10⁻⁷ m.

Your question is incomplete, but most probably your full question was

Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed on a screen that is 2.20m from the grating. In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.20mm. What is the difference between these wavelengths?

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Answer:

c...........................

Distance = (30+40+50) = 120 km

It's back where it started, so displacement = zero

The distance traveled by truck is equal to 70 km and its displacement is 50 km.

The distance of an object can be described as the total path traveled by an object. It is a scalar quantity as it has only magnitude, not direction. The distance is always positive, it can never be zero.

The displacement can be described as the shortest distance between two points. The displacement is a vector quantity with both direction and magnitude. The displacement of an object can be positive, negative, or zero and can increase or decrease with time.

Given, a truck moves 30 km along AB in the West as shown in the attached figure below, and then 40 km North along BC.

The distance of the truck will be = AB + BC = 30 + 40 = 70Km

The displacement (AC) can be calculated by using Pythagoras' theorem:

AC² = AB² + BC²

AC² = (30)² + (40)²

AC² = 2500

AC = 50 Km

Therefore, the distance is 70 Km and the displacement of the truck is 50 Km.

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Answer:

Two objects that are the same volume will displace the same amount of water even if they have different masses.

Answer:

From spectral lines astronomers can determine not only the element, but the temperature and density of that element in the star.

Answer:

The answer would be the chemicals in the atmosphere of the star.

Sometimes no. such as in other types of waves like electromagnetic waves, the medium does not physically move with the wave.

The medium in which a wave travels can move with the wave under certain circumstances, but it is not always the case. The movement of the medium depends on the type of wave and the nature of the medium itself. In mechanical waves, such as sound waves or water waves, the medium particles do indeed move as the wave propagates through them. For example, in a water wave, the water molecules move in a circular or elliptical motion as the wave passes through the water. Electromagnetic waves, including light waves, can travel through vacuum, which has no physical medium. In this case, the wave consists of oscillating electric and magnetic fields that propagate through space without the need for a medium to physically move. Therefore, whether the medium moves with the wave or not depends on the specific characteristics of the wave and the medium it is traveling through.

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Answer:

a) reflect off each other

Explanation: