The molality of an aqueous NaOH solution made with 5.00 kg of water and 3.6 mol NaOH is (c) 0.72 m NaOH.
The molality (m) of a solution is defined as the number of moles of solute (in this case NaOH) per kilogram of solvent (in this case water).
First, we need to calculate the mass of NaOH used in the solution:
mass of NaOH = 3.6 mol x 40.00 g/mol = 144 g
Next, we convert the mass of water to kilograms:
mass of water = 5.00 kg
Now we can calculate the molality:
m = 3.6 mol / 5.00 kg = 0.72 m NaOH
Therefore, the answer is (c) 0.72 m NaOH.
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The variable placed on the horizontal or x-axis of a graph is what variable
Answer:
Independent variable
Explanation:
Why is resistance useful in
lightbulbs?
A. It allows the filament to cool off and get dim.
B. It allows the filament to heat up and glow.
C. It allows the filament to heat up and get dim.
D. It allows the filament to cool off and glow.
What is the p value for the following scenario: Out of 300 male inpatients, there are 195 that have a MCC and out of 450 female inpatients 205 have a MCC. Question 4 options: .A. 49
B.53
C.59
D.50
The p-value would depend on the calculated chi-square statistic and the degrees of freedom associated with the test.
To determine the p-value for the given scenario, we need to perform a statistical test, such as a chi-square test, to assess the association between gender and having a major co-existing condition (MCC).
The observed data can be summarized in a contingency table as follows:
Male 195 105
Female 205 245
To calculate the p-value, we would perform a chi-square test on this contingency table, comparing the observed frequencies to the expected frequencies under the assumption of independence between gender and MCC.
After conducting the chi-square test, the resulting p-value will indicate the probability of observing the given data or data more extreme if there is truly no association between gender and MCC.
However, without the expected frequencies or the results of the chi-square test, it is not possible to determine the exact p-value. Therefore, none of the provided options (A. 49, B. 53, C. 59, D. 50) can be considered as the correct answer. The p-value would depend on the calculated chi-square statistic and the degrees of freedom associated with the test.
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How many moles are there in 122 grams of NO2?
Answer:
1.47 × 10^(23) molecules
Explanation:
The figure shows a tank with two immiscrble liquid is andar. The vacuum gauges hown indicates a reading of 17.17KPo Determire a) Absolut pressure at point [ b) Relative pressure atpoint F, with respect to the ain in the tank; that is, if said air were the environrent of the instrument of measurerest Patm =77.17[kpa]g=81 g=9.81[m(s2] Environmental temperatice: 20[∘C] δ=0.68δ=0.8
a) The absolute pressure at point B cannot be determined based on the given information.
b) The relative pressure at point F, with respect to the air in the tank, is also indeterminable with the provided information.
a) The absolute pressure at point B cannot be determined because the information about the liquid levels or the densities of the liquids in the tank is not provided.
The absolute pressure depends on the height of the liquid column and the density of the liquid, which are missing from the given data. Without this information, it is not possible to calculate the absolute pressure at point B.
b) The relative pressure at point F, with respect to the air in the tank, is also indeterminable. To calculate the relative pressure, we need to know the absolute pressure at point F and subtract the atmospheric pressure.
However, the absolute pressure at point F is not given, so we cannot determine the relative pressure. Additionally, the value of atmospheric pressure (Patm) provided is not relevant to calculating the relative pressure at point F.
In order to determine the absolute pressure at point B or the relative pressure at point F, we would need additional information such as the liquid levels in the tank, the densities of the liquids, and possibly the atmospheric pressure at point F.
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show how to work out...Calculate the mass in grams of 3.50 x 1025 atoms of lithium. Answer: 404g Li
the s^2+ ion differs from the S atom in S^2+ that ion has a
Answer:
Explanation: The S^2+ ion would contain a smaller atomic radius when compared to the atomic radius of S. With the removal of electrons, the outermost electrons experience less shielding, and thus experience a greater columbic force, and effective nuclear charge. Pulling in the outside electrons closer to the nucleus, consequently shrinking the atomic radius.
the formation of carbonic acid from water and carbon dioxide is catalyzed by _______.
Water and carbon dioxide combine to induce carbonic acid, which is catalyzed by carbonic anhydrase.
A family of enzymes known as carbonic anhydrases catalysis the interconversion of carbon dioxide and water with carbonic acid's separated ions. utmost carbonic anhydrases have a zinc ion in their active point. As a result, they're categorised as metalloenzymes.
Because carbonic acid is the sole acid that's exhaled by mortal lungs in a gassy state, it's constantly appertained to as a respiratory acid. It's a weak acid that produces bicarbonate and carbonate mariners.
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What are the signs of a chemical reaction?
A. Color change and gas released
B. Color, Gas, Explosion, Smoke,
Precipitate
C. Color, Gas, Light, Temperature, Precipitate
Answer:
C
Explanation:
Because i just had to do this on my assignment and got 100
Answer:
hey , its option c because in chemical reaction colour + evolution of gas takes place + temp. + precipitation. but also light can come in the case of chemical reaction.
Which of the following elements can exist in more than one form in the same
state?
neon
iodine
carbon
iron
Answer:
neon
Explanation:
it comes in different colours
a solution of 25.0 ml of 0.10 m nacl is mixed with 50.0 ml of 0.20 m kcl. what is the concentration of [cl - ] ions in the mixture?
There are 0.1667 M chloride ions present in the mixture.
How would you make a 50 mL solution of 25% NaCl?This new solution should be 50ml in volume, as requested. As a result, 1 out of every 25 "units" of the new solution—each of which is equivalent to 50 ml / 25 = 2 ml—is created from the initial 1 M solution. 24 of the remaining units are just water. Hence, we require 48ml of water and 2ml of a 1M NaCl solution.
Hence, the total moles of chloride ions in the mixture are:
total moles of Cl- = 0.00250 moles + 0.0100 moles = 0.0125 moles
To calculate the concentration of chloride ions in the mixture, we must divide the total moles of chloride ions by the total volume of the mixture, which is:
total volume = volume of NaCl solution + volume of KCl solution
= 25.0 mL + 50.0 mL
= 75.0 mL
= 0.0750 L
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Twenty-seven pounds (27 lb) of chlorine gas is used for treating 750,000 gal of water each day. The chlorine used up by the microorganisms in the water is measured to be 2.6 mg/L. What is the residual (excess) chlorine concentration in the treated water
Answer:
\(1.7137\ \text{mg/L}\)
Explanation:
Chlorine gas available = 27 lbs = \(27\times 453.59237=12247\ \text{g}\)
Amount of water used each day = 750000 gal = \(750000\times3.785411784=2839058.84\ \text{L}\)
Rate at which chlorine gas used = 2.6 mg/L
Chlorine gas used
\(2839058.84\times 2.6\times 10^{-3}=7381.55\ \text{g}\)
Residual content of chlorine = \(12247-7381.55=4865.45\ \text{g}\)
Concentration of the residual chlorine is given by
\(\dfrac{4865.45}{2839058.84}=0.0017137\ \text{g/L}=1.7137\ \text{mg/L}\)
Concentration of the residual chlorine is \(1.7137\ \text{mg/L}\).
In the equation D=M/V, what does the M stand for?
The subject is SCIENCE I put CHEMISTRY because it wouldn't let me move on.
Answer:
Mass
Explanation:
The formula for density is d = M/V, where d is density, M is mass, and V is volume.
what relative masses of dimethyl amine and dimethyl ammonium chloride do you need to prepare a buffer solution of ph = 10.54?
To prepare a buffer solution of pH = 10.54, the relative masses of dimethyl amine and dimethyl ammonium chloride needed are 0.079 g and 0.067 g respectively.
A buffer solution is a solution that has the ability to resist changes in pH upon the addition of small amounts of acid or base. A buffer solution contains a weak acid and its conjugate base or a weak base and its conjugate acid. It can be prepared by mixing equal volumes of a weak acid and its conjugate base or a weak base and its conjugate acid.
Dimethyl amine is an organic compound with the formula (CH3)2NH. It is a weak base and can act as a proton acceptor. Dimethyl ammonium chloride is an organic compound with the formula (CH3)2NH2Cl. It is a salt of a weak base and a strong acid and can act as a proton donor.
Calculation of relative masses:
The pKa of dimethyl amine is 10.73.
To prepare a buffer solution of pH = 10.54,
the ratio of [A-]/[HA] should be 1/9.
Using the Henderson-Hasselbalch equation;
pH = pKa + log([A-]/[HA])10.54 = 10.73 + log([A-]/[HA])
log([A-]/[HA]) = -0.19[A-]/[HA] = 0.67/1.00
The sum of the masses of dimethyl amine and dimethyl ammonium chloride is 0.146 g. The ratio of their masses is 0.67:1.00.
So, the relative masses of dimethyl amine and dimethyl ammonium chloride needed are 0.079 g and 0.067 g respectively.
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how many grams of hydrogen gas will bep roduced from the reaction of zinc metal with 85 grams of hydrochloric acid?
2.33 grams of hydrogen gas will be produced from the reaction of zinc metal with 85 grams of hydrochloric acid.
To determine the grams of hydrogen gas produced from the reaction of zinc metal with 85 grams of hydrochloric acid, we must first examine the balanced chemical equation for this reaction:
Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
From the equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas. Now, we need to convert the given mass of hydrochloric acid into moles.
The molar mass of HCl is approximately 36.5 g/mol. Therefore, we have:
85 g HCl × (1 mol HCl / 36.5 g HCl) ≈ 2.33 mol HCl
Since 2 moles of HCl react with 1 mole of Zn to produce 1 mole of H₂, we can determine the moles of H₂ produced:
2.33 mol HCl × (1 mol H₂ / 2 mol HCl) ≈ 1.165 mol H₂
Lastly, we'll convert the moles of hydrogen gas into grams. The molar mass of H₂ is approximately 2 g/mol:
1.165 mol H₂ × (2 g H₂ / 1 mol H₂) ≈ 2.33 g H₂
Therefore, approximately 2.33 grams of hydrogen gas will be produced from the reaction of zinc metal with 85 grams of hydrochloric acid.
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What is the volume of 6.9 mol of oxygen at 233 K and a pressure of 4.0 atm
The volume of 6.9 mol of oxygen at 233 K and a pressure of 4.0 atm is approximately 12.0L.
To calculate volume of a gas, we can make use of Ideal Gas Law equation. It is a fundamental equation in thermodynamics that describes the behaviour of an ideal gas under certain circumstances. It relates pressure(P), volume(V), number of moles (n), and temperature(T) of an ideal gas using the equation:
PV = nRT
Where P = Pressure of the gas,
V = Volume of the gas,
n = Number of moles of the gas,
R = Ideal gas constant commonly expressed as 0.0821 L·atm/(mol·K) or 8.314 J/(mol·K),
T = Temperature of the gas.
In the question, we are given with:
n = 6.9 mol
T = 233 k
P = 4.0 atm
Substituting the above values in the equation to find the volume, we get:
4.0 * V = 6.9 * 0.0821 * 233
V = (6.9 * 0.0821 * 233) / 4.0
V = 11.9997 (approximately 12.0)
Therefore, The volume of 6.9 mol of oxygen at 233 K and a pressure of 4.0 atm is approximately 12.0L.
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please help me
16 1 point What is the decay rate of a sample of Oxygen-21 if the sample has 8.31x1017 atoms and a decay constant of 0.203/s? 4.09x1018Bq 1.69x10¹7Bq 0.203Bq 2.44x10-1⁹Bq Previous
decay rate of approximately 1.69x10^17 Bq (becquerels),
The decay rate of a radioactive sample is determined by the number of radioactive atoms present and the decay constant, which represents the probability of decay per unit of time.
To calculate the decay rate, we multiply the number of atoms in the sample by the decay constant. In this case, the sample has 8.31x10^17 atoms and a decay constant of 0.203/s. Multiplying these values gives a decay rate of approximately 1.69x10^17 Bq (becquerels), which represents the number of decays per second in the sample.
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draw a lewis structure for each of the following molecules, and then use the vsepr theory to predict the molecular geometry of each:
a. scl2
b. pi3
c. cl2o
d. nh2cl
e. sicl3br
f. oncl\
a. The Lewis structure for SCl₂ is S-Cl-Cl with a lone pair on sulfur. The VSEPR theory predicts a bent or V-shaped molecular geometry.
b. The Lewis structure for PI₃ is P-I-I-I with two lone pairs on the central phosphorus atom. The VSEPR theory predicts a trigonal pyramidal molecular geometry.
c. The Lewis structure for Cl₂CO is O=C=Cl with no lone pairs. The VSEPR theory predicts a linear molecular geometry for Cl2CO.
d. The Lewis structure for NH₂Cl is H-N-Cl with two lone pairs on the nitrogen atom. The VSEPR theory predicts a trigonal pyramidal molecular geometry.
e. The Lewis structure for SiCl₃Br is Br-Si-Cl-Cl-Cl with no lone pairs. The VSEPR theory predicts a trigonal pyramidal molecular geometry.
f. The Lewis structure for ONCl is O=N-Cl with no lone pairs. The VSEPR theory predicts a linear molecular geometry.
To draw the Lewis structure, you need to determine the number of valence electrons for each atom in the molecule and then arrange them to form covalent bonds while fulfilling the octet rule (except for hydrogen, which follows the duet rule). Once the Lewis structure is determined, you can use the VSEPR theory to predict the molecular geometry based on the arrangement of electron pairs around the central atom.
In each case, the molecular geometry is determined by the number of bonding and lone pairs of electrons around the central atom. The VSEPR theory provides a model for predicting the shapes of molecules based on the repulsion between electron pairs.
The molecular geometries predicted by the VSEPR theory are as follows:
a. SCl₂: Bent or V-shaped
b. PI₃: Trigonal pyramidal
c. Cl₂CO: Linear
d. NH₂Cl: Trigonal pyramidal
e. SiCl₃Br: Trigonal pyramidal
f. ONCl: Linear
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Methane gas is compressed isothermally from 1. 00 atm to 1. 75 atm. The
initial volume is 20 L. Find the final volume of the gas?
After solving the problem the final volume of the gas is 35L.
What is final volume?The final volume is the amount of space occupied by an object, gas, or liquid in its finished state. It is the total volume of a substance, regardless of any changes that may have occurred to it during a process.
The final volume of the gas can be calculated using the ideal gas law. The ideal gas law states that:
PV = nRT
where P is pressure, V is volume, n is the amount of substance, R is the ideal gas constant and T is temperature.
Since this is an isothermal process, the temperature is constant and can be cancelled out. We can rearrange the equation to:
V2 = V1 (P2/P1)
where V2 is the final volume and V1 is the initial volume.
Substituting in the values, we get:V2 = 20L (1.75/1.00)
V2 = 35L
Therefore, the final volume of the gas is 35L.
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12. What is the atomic number of the atom that forms an anion with 36 electrons and a Explain(words); write out formula, then solve for missing variable charge of -1?
The missing variable of (⁻¹) is bromine.
Let the missing variable be X.
No. of electrons in the monoatomic anion (X⁻¹ )= 36
No. of electrons in the monoatomic atom (X) = 35
Atomic No. = No. of protons = No. of electrons in neutral atom = 35
Mass No. = No. of protons + No. of neutrons
= 35 + 45 = 80
Hence, the element must be Br as its mass no is 80 and atomic no is 35.
And the ion is bromide ion or Br⁻¹ ion. It is an anion which gains an electron to achieve octet.
X → Br and X⁻¹ → Br⁻¹
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If one parent has sickle cell anemia and the other parent is a carrier, what is the possibility that their child will have sickle cell anemia
This law relates a planet's orbital period and its average distance to the Sun.
The orbits of planets are ellipses with the Sun at one focus.
The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames.
Answer:
These are Kepler's Laws of Planetary Motion
Explanation:
Answer:
its Keplers third law,
then first law,
then second law
Explanation:
I need help. A chemist wants to dilute 100.0 ml of 2.50 M Sulfuric acid to 0.50 M Sulfuric acid. To what volume must it be diluted?
Taking into account the definition of dilution, to a volume of 500 mL, a solution of 100.0 mL of 2.50 M Sulfuric acid must be diluted to 0.50 M Sulfuric acid.
DilutionWhen it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeFinal volumeIn this case, you know:
Ci= 2.50 MVi= 100 mLCf= 0.50 MVf= ?Replacing in the definition of dilution:
2.50 M× 100 mL= 0.50 M× Vf
Solving:
(2.50 M× 100 mL)÷ 0.50 M= Vf
500 mL= Vf
In summary, to a volume of 500 mL, a solution of 100.0 mL of 2.50 M Sulfuric acid must be diluted to 0.50 M Sulfuric acid.
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At the end of mitoi, the cell are:
a. Have ome genetic imilaritie
b. Genetically identical to each other
c. Genetically different from each other
At the end of mitosis, the cells are "genetically identical to each other." The correct answer is B.
Mitosis is a type of cell division that results in the formation of two identical daughter cells from a single parent cell. It is the process by which a single cell divides into two genetically identical daughter cells, each containing the same number of chromosomes as the parent cell.
During mitosis, the genetic material is precisely divided and distributed to each daughter cell, ensuring that both daughter cells have the exact same set of chromosomes as the parent cell. This ensures that each daughter cell has the same genetic information and is identical to the other daughter cell and to the parent cell. The genetic similarity of the daughter cells allows for the maintenance of specific traits and the continuation of a species' characteristics.
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Can someone double check this for me
Answer:
Yeah u valid
Explanation:
A client is to recieve 2.00g of a drug. The drug comes on a solution that has 500 mg per 5.0 mL. Each vial contains 10 milliliters. How many vials do you need?
Answer:
2 vials
Explanation:
The concentration (C) of the drug in the solution is:
C= 500 mg/5 mL = 100 mg/mL
Each vial with a volume (V) of 10 mL, contains the following mass of drug:
V= 10 mL ⇒ C x V = 100 mg/mL x 10 mL = 1000 mg
As you need 2.00 g, and 1 gram is equivalent to 1000 mg, the mass needed is 2.00 g x 1000 mg/1 g = 2000 mg
Thus, you have to divide the mass you need into the mass of each vial:
(2000 mg)/(1000 mg/vial) = 2 vials
Therefore, you need 2 vials.
what is the energy required to remove second electrons?
Answer: the second ionization energy.
Explanation:If you want to remove a second electron, the amount of energy required to remove the second electron is called the second ionization energy.
In the equation 2A1 + 3Fe(NO3)2 + 3Fe + 2AI(NO3),
iron has been replaced by what ?
Answer:
2Al +3Fe(NO3)2 --------> 3Fe + 2Al(NO3)3
In the above reaction Aluminum and iron nitrate reacts to produce iron metal and aluminum nitrate so aluminum is replace by iron
a block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm
A block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm, the density of lead is mathematically given as
x= 11.30 g/cm^3
This is further explained below.
What is the density of lead?Generally, in order to determine the lead's specific gravity; To begin, we would use the formula to find out how much space the block of lead takes up;
Volume= length * width * height
After plugging the values into the formula, we get the following:
Volume = 4.50 * 5.20 * 6.00
Volume = 140.4 cm^3
The next thing that we do is determine the density of lead;
After plugging the values into the formula, we get the following:
X = 11.30 g/cm^3
In conclusion, the density of lead is 11.30 g/cm^3
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CQ
A block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm. The block weighs 1587 g. From this information, calculate the density of lead.
A certain oxygen atom has the electron configuration 1s22s22px22py2. How many unpaired electrons are present?.
There are no unpaired electrons present in this atom of oxygen.
The molecular orbital configuration of the oxygen atom given is,
1s²2s²2px²2py².
As we can see, there is not electron in the configuration which is alone in the orbital, they all are present in pairs. So, there are no unpaired electrons present.
This state of the oxygen atom when there are no unpaired electron are present, this could be the ground state of the atom.
The ground state of the atom is when the potential energy of the electrons of the atom is minimum.
In this configuration, no electron is unpaired, all the electrons are paired.
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