Answer: 42
Step-by-step explanation: got it right
Area =
Help me please thank :)
Answer:
12
Step-by-step explanation:
B x H x 1/2 = area of a triangle
we can break this figure into 4 different triangles and since we have the length of the chords (dotted lines) in the diamond we can easily solve it.
half of QS is 2 and half of PR is 3
2 x 3 = 6
6 / 2 = 3
since there are four triangles multiply 3 by 4 (3 x 4)
and you get 12.
I really need help..im confused
If
x
2
+ 4y = 8 and x + 5y = 7 , then what does y – x = ?
The value of y - x based on the mentioned two equations is -29/5 or 219/5.
We have equation 1: x² + 4y = 8 and equation 2: x + 5y = 7
Rewriting equation 2 in terms of x
x = 7 - 5y : equation 3
Substitute the value of x from equation 3 into equation 1
(7 - 5y)² + 4y = 8
Expand the bracket
49 + 25y² - 70y + 4y = 8
Rewriting the equation
25y² - 66y + 41 = 0
y = 1/5 or 41/5.
Keep the value of y in equation 2 to find the value of x for solving expression y - x.
If value of y is 1/5
x = 7 - 5(1/5)
x = 7 - 1
x = 6
If value of y is 41/5
x = 7 - 5(41/5)
x = 7 - 41
x = - 34
The possible values of y - x will be :
If y is 1/5 and x is 6, then
y - x = 1/5 - 6
y - x = -29/5
If y is 41/5 and x is -34, then
y - x = 41/5 - (-34)
y - x = 219/5
Hence, the value of y - x can be -29/5 or 219/5.
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Holly Krech is planning for her retirement, so she is setting up a payout annuity with her bank. She wishes to receive a payout of $1,800 per month for twenty years. She must deposit $218,437.048 and the total amount that Holly will receive from her payout annuity will be $432,000.
A. How large a monthly payment must Holly Krech make if she saves for her payout annuity with an ordinary annuity, which she sets up thirty years before her retirement?
B. how large a monthly payment must she make if she sets the ordinary annuity up twenty years before her retirement?
A. To save for her payout annuity with an ordinary annuity set up thirty years before her retirement, Holly Krech must make a monthly payment of $175.97.
B. If she sets up the ordinary annuity twenty years before her retirement, Holly Krech must make a monthly payment of $432.00.
What is the monthly payment required for an ordinary annuity set up 30 years before retirement?To calculate the monthly payment for an ordinary annuity set up thirty years before retirement, we can use the formula for the present value of an ordinary annuity. Given the deposit amount of $218,437.048 and the total amount received from the annuity of $432,000, and solving for the monthly payment, we find that Holly must make a monthly payment of $175.97.
How much must be paid monthly for an ordinary annuity set up 20 years before retirement?For an ordinary annuity set up twenty years before retirement, we use the same formula for present value. With the deposit amount and total amount received unchanged, we solve for the monthly payment, which comes out to be $432.00.
It's important to note that the monthly payment increases when the annuity is set up closer to the retirement date. This is due to the shorter time period available for saving, resulting in a higher required contribution to reach the desired payout amount.
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Where should you plot the ordered pair (3,4) in relation to the origin?
CLEAR CHECK
4 spaces to the right and 3 spaces up
3 spaces to the right and 4 spaces up
3 spaces to the right, 4 times
3 spaces up and 4 spaces to the right
Answer:
3 spacesto the right and 4 spaces up
What list all of the y-intercepts of the graphed functions?
The coordinate of the y-intercept of the given quadratic graph is: (0, -3)
What is the coordinate of the y-intercept?The general form of the equation of a line in slope intercept form is:
y = mx + c
where:
m is slope
c is y-intercept
The general form of quadratic equations is expressed as:
y = ax² + bx + c
Now, from the term y-intercept, we know that it is the point where the graph crosses the y-axis and as such, we have the coordinate from the graph as:
(0, -3)
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Pre cal help please due tonight
The point where the equation of the line touch the circle is (2.166, 3.083).
and
Where does the equation of the line touch the circle in the first quadrantThe equation of a circle with center (h, k) and radius r is:
(x - h)^2 + (y - k)^2 = r^2
So the equation of the circle with center (0, 2) and radius 5 is:
x^2 + (y - 2)^2 = 25
We can solve for the intersection of the circle and the line y = 0.5x + 2 by substituting y = 0.5x + 2 into the equation of the circle:
x^2 + (0.5x)^2 + 2x + 2^2 - 25 = 0
Simplifying and solving for x:
1.25x^2 + 2x - 9 = 0
Using the quadratic formula, we get:
x = (-2 ± √(2^2 - 41.25(-9))) / (2*1.25)
x = (-2 ± √(104)) / 2.5
x ≈ -6.166 or x ≈ 2.166
Since we are looking for a point in the first quadrant, we take the positive value of x:
x ≈ 2.166
Now we can use the equation of the line to find the corresponding y-coordinate:
y = 0.5x + 2
y ≈ 3.083
Therefore, the point where the line y = 0.5x + 2 intersects the circle with radius 5 and center (0, 2) in the first quadrant is approximately (2.166, 3.083).
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PLEASE HELP I WILL GIVE BRAINLIST!
What is the length of the square’s side?
Answer:
x = 6 / sqrt(2)
Step-by-step explanation:
We are given the diagonal of a square
The side length is x
Using the Pythagorean theorem
x^2 + x^2 = h^2 where h is the length of the hypotenuse which is 6
x^2+x^2 = 6^2
2x^2 = 36
x^2 = 18
Taking the square root of each side
sqrt(x^2) = sqrt(18)
x = 3 sqrt(2)
This can be rewritten as
x = 3 sqrt(2) * sqrt(2)
------------------------
sqrt(2)
x = 3*2
-------
sqrt(2)
x = 6 / sqrt(2)
Write the standard form of the equation of a parabola passing through the point (1, 32) with a minimum point at (-2, 5).
Answer:
\(y=3x^2+12x+17\)
Step-by-step explanation:
The equation in vertex form is \(y=a(x+2)^2+5\).
We can use the point \((1,32)\) to solve for \(a\).
\(32=a(1+2)^2+5 \\ \\ 27=9a \\ \\ a=3 \\ \\ \\ \therefore y=3(x+2)^2 + 5 \\ \\ =3(x^2+4x+4)+5 \\ \\ =3x^2+12x+12+5 \\ \\ =3x^2+12x+17\)
Let f (x) = px 2 + qx - 4 p, where p 0. Find the number of roots for the equation f (x) = 0 . Justify your answer.
Answer:
f(x) = 0
px^2 + qx - 4p = 0
abc-Formula: x = (-b ± √(b^2 - 4·a·c))/(2·a)
x = (-q ± √(q^2 - 4·p·(-4p)))/(2·p)
x = (-q ± √(q^2 + 4^2·p^2))/(2·p)
Because q^2 + 4^2·p^2 > 0 there are two roots.
Question 4 of 10
The standard form of the equation of a parabola is y=x²-6x+14.
What is the vertex form of the equation?
OA y=(x-3)2 +15
OB. y = (x+3)(x-3) +5
O C. y=(x-3)2 +23
OD. y=(x-3)² +5
The vertex form of the equation is y = (x - 3)² - 4, which corresponds to option OD.
To convert the given equation from standard form to vertex form, we need to complete the square.
The vertex form of a parabola's equation is y = a(x-h)² + k, where (h, k) represents the vertex of the parabola.
Given equation: y = x² - 6x + 14
Move the constant term to the right side:
y - 14 = x² - 6x
Complete the square by adding and subtracting the square of half the coefficient of x:
y - 14 + 9 = x² - 6x + 9 - 9
Group the terms and factor the quadratic:
(y - 5) = (x² - 6x + 9) - 9
Rewrite the quadratic as a perfect square:
(y - 5) = (x - 3)² - 9
Simplify the equation:
y - 5 = (x - 3)² - 9
Move the constant term to the right side:
y = (x - 3)² - 9 + 5
Combine the constants:
y = (x - 3)² - 4
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limit x tends to 0 (x cot 2x)
Step-by-step explanation:
\( = \lim \limits_{x \to0}x \cot(2x) \)
\( = \lim \limits_{x \to0} \frac{x}{ \tan(2x) } \)
\( = \lim \limits_{x \to0} \frac{x}{ \tan(2x) } \times \frac{2x}{2x} \)
\( = \lim \limits_{x \to0} \frac{2x}{ \tan(2x) } \times \lim \limits_{x \to0} \frac{x}{2x} \)
\( = \lim \limits_{u \to0} \frac{u}{ \tan(u) } \times \frac{1}{2} \)
\( = \frac{1}{2} \)
in base $10$, the number $2013$ ends in the digit $3$. in base $9$, on the other hand, the same number is written as $(2676) {9}$ and ends in the digit $6$. for how many values of $b$ does the base-$b$-representation of $2013$ end in the digit $3$?
There are no values of $b$ for which the base-$b$-representation of $2013$ ends in the digit $3$. For a number to end in the digit $3$ in base-$b$ representation, it must be congruent to $3$ modulo $b$.
We can rewrite $2013$ as $2 \cdot 10^3 + 0 \cdot 10^2 + 1 \cdot 10^1 + 3 \cdot 10^0$. Now, if $2013$ is congruent to $3$ modulo $b$, it means that $2 \cdot 10^3 + 0 \cdot 10^2 + 1 \cdot 10^1 + 3 \cdot 10^0$ is also congruent to $3$ modulo $b$.
Simplifying the expression, we have $2000 + 0 + 10 + 3$. Since the base-$b$-representation is formed by multiplying each digit by the corresponding power of $b$, we can rewrite the expression as $2 \cdot b^3 + 1 \cdot b^1 + 3 \cdot b^0$. We can now observe that the constant term $3 \cdot b^0$ will always be congruent to $3$ modulo $b$. However, the other terms $2 \cdot b^3$ and $1 \cdot b^1$ will not be congruent to $3$ modulo $b$ for any positive value of $b$. Therefore, the base-$b$-representation of $2013$ cannot end in the digit $3$ for any value of $b$.
Hence, there are no values of $b$ for which the base-$b$-representation of $2013$ ends in the digit $3$.
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A friend says that if A equals 196, then s can be 14 or -14 since the area A will be positive in either case. Do you agree or disagree.Explain.
Answer:
Disagree. Even though \((-14)^{2} =196\), it is impossible to have a negative length.
A square cannot have a length of a negative value.
Can someone please help me?
B.
Explanation:
Well, I choose B. Hope I helped... trying to helppp u!!!!!
Nikki had a $50 gift card for her favorite store. She used the gift card to buy 4 DVDs and still had money available on the card after the purchase. If the DVDs were all the same price, which inequality best represents the possible price of each DVD?
A. P>12. 50
B. P≥12. 50
C. P<12. 50
D. P≤12. 50
The best inequality that represents the possible price of each DVD is P≤12.50, found by dividing the total cost of 4 DVDs ($50) by 4.
Let's assume the price of each DVD to be P dollars.
Then the total cost of 4 DVDs would be 4P dollars.
Since Nikki had money left on the gift card after the purchase, the cost of the DVDs must be less than or equal to $50, the value of the gift card.
So we have the inequality:
4P ≤ 50
Dividing both sides by 4, we get:
P ≤ 12.50
So the best inequality that represents the possible price of each DVD is D) P≤12.50.
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solve for x in the diagram below
Please answer it now in two minutes
Answer:
135.5
hope this helps :)
Help please ASAP for 12pts
Consider an activity with these estimates for optimistic, most likely, and pessimistic time: 11, 21, 35 . Find the mean value of the activity time. (Please provide answer accurate to two decimal place
the main answer is that the mean value of the activity time is 21.67. This is calculated using the formula (optimistic + 4 * most likely + pessimistic) / 6.
To find the mean value of the activity time, we can use the three estimates provided: optimistic, most likely, and pessimistic time.
1. The optimistic time is the shortest possible time for completing the activity, which is 11 units.
2. The most likely time is the time that is most likely to be taken to complete the activity, which is 21 units.
3. The pessimistic time is the longest possible time for completing the activity, which is 35 units.
To calculate the mean value, we can use the following formula:
Mean value = (optimistic + 4 * most likely + pessimistic) / 6
Substituting the given values, we get:
Mean value = (11 + 4 * 21 + 35) / 6
Calculating the numerator first:
11 + 4 * 21 + 35 = 11 + 84 + 35 = 130
Now, we can calculate the mean value:
Mean value = 130 / 6
Dividing 130 by 6, we get:
Mean value = 21.67 (rounded to two decimal places)
Therefore, the mean value of the activity time is 21.67.
the main answer is that the mean value of the activity time is 21.67. This is calculated using the formula (optimistic + 4 * most likely + pessimistic) / 6.
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find k such that x(t)=13t is a solution of the differential equation dxdt=kx.
The result x(t) = 13t is a solution of the differential equation dx/dt = kx where k = 1/t
In this question, we are given a differential equation dx/dt = kx.
This equation is called a first-order homogeneous linear differential equation.
This means that the highest derivative that appears in the equation is the first derivative, and there are no nonlinear terms.
The coefficient k is a constant that represents the rate at which the quantity x(t) changes with respect to time t.
Given the differential equation
dx/dt = kx
And,
x(t) = 13t is a solution
We need to find k.
In order to find the value of k, we differentiate the given solution with respect to time t and equate it to the given differential equation.
dx/dt = d/dt (13t)
= 13
Substituting the value of x and dx/dt in the differential equation, we get:
13 = k (13t)
⇒ k = 1/t
Therefore, k = 1/t.
Substituting the value of k in the given differential equation, we get:
dx/dt = (1/t) x .............................(1)
Now, let’s verify whether x(t) = 13t is a solution of the differential equation (1).
LHS of (1) = d/dt (13t)
= 13
RHS of (1) = (1/t) (13t)
= 13
Therefore, x(t) = 13t is a solution of the differential equation dx/dt = kx where k = 1/t
To find a particular solution of the differential equation, we are given that x(t) = 13t is a solution.
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Casey turned age 65 on May,2020. During the year, she received distributions from her health savings account (HSA) totaling $728.96. She paid for electrolysis
on March 3, 2020 .Casey paid $44.87 to her ENT doctor Junie 4, 2020 and $315 to her chiropractor in July and August . The penalty on Casey's nonqualified distributions is
a.$ 0
B. $63
C $74
D. $146
The penalty on Casey's nonqualified distributions is a) $0.
The penalty on Casey's nonqualified distributions is $74. Casey turned age 65 on May, 2020 and during the year she received distributions from her health savings account (HSA) totaling $728.96. She paid for electrolysis on March 3, 2020. Casey paid $44.87 to her ENT doctor on June 4, 2020, and $315 to her chiropractor in July and August.
Non-qualified distributions from a health savings account (HSA) before the age of 65 are subject to a 20% penalty. This penalty is imposed in addition to the usual taxes on non-qualified distributions. However, once an account holder reaches the age of 65, the penalty no longer applies, but normal taxes are still imposed.
In this case, Casey was 65 years of age in May 2020. Thus, she is not subject to a penalty on any of her HSA distributions. She received $728.96 in HSA distributions over the year. The penalty on her nonqualified distributions is $0.
Therefore, the correct option is a. $0.
Hence, the penalty on Casey's nonqualified distributions is $0.
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Question 1-6
In PQR, PQ=QR. If m/P = (2x - 26) and m/R= (x+17), classify PQR. Select all that apply.
The triangle PQR is an equilateral triangle
How to classify the triangleFrom the question, we have the following parameters that can be used in our computation:
PQ=QR.
m/P = (2x - 26) and m/R= (x+17)
When two sides of a triangle are congruent, then the triangle is an isosceles triangle
Using the above as a guide, we have the following:
2x - 26 = x + 17 --- base angles of an isosceles triangle
So, we have
x = 43
This gives
m/P = 2 * 43 - 26 = 60
m/R= 43 + 17 = 60
If two angles of a triangle measure 60 degrees, then the third angle is 60 degrees
This implies that the triangle is an equilateral triangle
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The measure of the angle Q is 46.4°
How to find the angle?Recall that the sum of the angles of a triangle is equal to 180 degrees
We are told that
PQ = QR
Q = 100°
As PQ and QR are equal so,
By theorem angle opposite to equal sides are equal so,
We can say that angle P = angle R = X
Therefore by angle sum property of the triangle,
angle P + angle Q + angle R = 180°
X +(2x - 26)+ (2x - 26) = 180°
This implies that 5x-52=180
Collecting like terms
5x=180+52
5X = 232°
X =46.4°
Therefore the measure of R = 40°
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Alissa has two pieces of carpet runner one is 2 1/3 yards long and the other is 3 1/3 yard long she needs 10 yards of carpet runner altogether how much more does she need to buy
Write the equation of a parabola that has a complex root at 4+5i and goes through the point (2,87)
Answer:
John is verey not smart
Step-by-step explanation:
Because he has fat
Label the place value of 74.92.
Answer: 7 tens, 4 ones, 9 tenths, and 2 hundredths.
I need help with this important question it's for a important grade
Answer:
50
Step-by-step explanation:
29+42+61+?=180
add (29,42,61) that gives you 132
now 132-180=48
48 rounded to the nearest tenth is 50 sooo....
X= 50
the distributive property for 72+12
if 3.142×110 = 345.62, why is the decimal point not infront of the 5?
Answer:
It is not infront of the 5 because when mutiplying it goes above a whole number so the . has to move back.
Step-by-step explanation:
Answer:
It has to be in front of the 5 since you have to move the decimal 2 places to the right and it lands beside the 5
Ehat is (-2,-4) rotated 270⁰ counterclockwise about the origin?