Answer:
Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Ideally, the device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever.”
Explanation:
a person can pull approximately 60% of their own weight horizontally along the ground in good conditions. So if we need a 500 lb pull to get something done and we have a single groundman who weighs 200 lb and can therefore generate around 120 lb of pull, how can we accomplish this 500 lb pull? The simple answer is that the groundman can go find 4 or 5 good friends who are willing to drop everything and come and help him pull on the rope.
2 A spring requires a load of 7.5N to increase its length by 50 cm. What load will give it an extension of 12cm?
The load of 1.8 N will give it an extension of 12cm.
What is spring constant?Amount of force required to increase unit length of a spring is known as spring constant. Si unit of spring constant is Newton/meter.
Given parameters:
Loads on the spring; F₁ = 7.5 N.
Increase in length of the spring; x₁ = 50 cm = 0.5 m.
So, spring constant of it; k = F₁/x₁ = 7.5/0.5 N/m = 15 N/m.
Hence, to extent it of 12 cm; required load
= spring constant × increase in length
= 15 N/m × 12 cm.
= 15 N/m × 0.12 m.
= 1.8 N.
So, the required load is 1.8 N.
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What other kind of simple machine is a special kind of lever?
saitama is the strongest
A non relativistic proton is confined to a length of 2.0 pm on the x-axis. What is the kinetic energy of the proton if its speed is equal to the minimum uncertainty possible in its speed? (1 eV = 1.60 Ã 10-19 J, h= 1.055 Ã 10-34 J ? s, m proton = 1.67 Ã 10-27 kg) a. 0.13 eV b. 1.3 eV c. 13 eV d. 130 eV e. 1300 eV
According to the question the kinetic energy of the proton is 0.13 eV.
What is proton?Proton is a subatomic particle that is found in the nucleus of every atom. It has a positive electric charge and a mass that is roughly equal to 1/1800 of the mass of a hydrogen atom. Protons are the primary building blocks of atoms and are responsible for the stability of atoms. They are also the source of the chemical properties of atoms, enabling them to interact with other atoms and form molecules. Protons are composed of three quarks, two up quarks and one down quark, which are held together by the strong nuclear force.
The kinetic energy of the proton can be calculated using the equation \(E_k = (h/(2*π))*v\), where h is Planck's constant, v is the speed of the proton, and π is the mathematical constant pi.
The minimum uncertainty in the speed of the proton is given by the equation v = (h/(2*L)), where h is Planck's constant, and L is the length of the proton's confinement. Substituting the given values, we get v = \((1.055*10-34 J ? s) / (2*2.0*10-12 m) = 2.625*1023 m/s.\)
Substituting this value into the equation for kinetic energy, we get\(E_k = (h/(2*π))*v = (1.055*10-34 J ? s) / (2*3.14) * (2.625*1023 m/s) = 0.13 eV.\)
Therefore, the answer is A. 0.13 eV.
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True or False. The two metals in a battery are the electrolytes.
True
False
the radius of the earth is 6378 km and the mass is 5.97 x 1024 kg . what is the density of the earth? recall that koral expects answers in si units.
The mass of the earth is 5.97 x 1024 kg, and its radius is 6378 km. The density of the earth is 5.52 x 10³ kg/m³.
The density of the Earth can be found using the formula:
density = mass / volume
We know the mass of the Earth is 5.97 x 10²⁴ kg.
To find the volume of the Earth, we can use the formula for the volume of a sphere:
volume = (4/3)*π*r³
Reversing given values:
volume = (4/3)*π*6378 km³
volume = 1.08 x 10¹² km³
To convert km³ to m³, we can use the fact that 1 km = 1000 m, so:
1 km³ = (1000 m)³ = 10⁹ m³
Therefore:
volume = 1.08 x 10¹² km³ * (10⁹ m³/km³)
volume = 1.08 x 10²¹ m³
Now we can find the density of the Earth:
density = mass / volume
density = 5.97 x 10²⁴ kg / 1.08 x 10²¹ m³
density = 5.52 x 10³ kg/m³
Therefore, the density of the Earth is approximately 5.52 x 10³ kg/m³.
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Can mechanical waves travel in a vacuum?
O yes
O no
No mechanical waves cannot travel in a vacuum
What is the white part of a hurricane forecast called?
*The category is the closest I could get
gular velocity w suddenly collapses to half of its original radius without any loss of mass. assume the star has uniform density before and after the collapse. what will the angular velocity of the star be after the collapse?
The angular velocity of the star after the collapse will be twice its original value.
Angular momentum is conserved in the absence of external torque. The moment of inertia of a uniform-density sphere with radius R is (2/5)MR². If the radius of the star suddenly collapses to half of its original value:
(2/5)M(R/2)² = (1/10)MR².
Since angular momentum is conserved, we can equate the initial angular momentum of the star to its final angular momentum:
I₁w₁ = I₂w₂
where I₁ and w₁ are the initial moment of inertia and angular velocity, and I₂ and w₂ are final moment of inertia and angular velocity.
Substituting the values :
(2/5)MR₁²w₁ = (1/10)MR₁²w₂
Simplifying and solving for w₂, we get:
w₂ = 2w₁
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In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?
Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.
Thermal energy is the energy possesed by a system due to its temperature.
In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.
Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy
ANSWER:
A. Entropy
If the cement bag has a mass of 100.0 kg and 1=67.00, 82=53.00, what is the tension T₂?490 N1130 N442 N681.N
The value of tension T₂ is calculated to be
442 NHow to find the tension T₂The concept of balance of forces is applied here to find the formula of the form
T3 = mg upward force = downward force
and T3 = T1 sin ∅1 + T2 sin ∅2,
therefore
T1 sin ∅1 + T2 sin ∅2, = mg
where
m = mass of the cement = 100 kg
g = acceleration due to gravity = 9.8
Using trigonometry relations follows
T1 cos ∅1 = T2 cos ∅2
T1 = T2 cos ∅2/cos ∅1
substituting T1 into the equation T1 sin ∅1 + T2 sin ∅2, = mg gives
T1 sin ∅1 + T2 sin ∅2, = mg
T2 (cos ∅2/cos ∅1) (sin ∅1) + T2 sin ∅2, = mg
T2 [ (cos ∅2/cos ∅1) (sin ∅1) + sin ∅2] = mg
T2 = mg / [ (cos ∅2/cos ∅1) (sin ∅1) + sin ∅2 ]
T2 = 100 * 9.81 / [ (cos 53/cos 67) * sin 67 + sin 53]
T2 = 981 / [1.540 * 0.921 + 0.799]
T2 = 981 / [2.217]
T2 = 442.42 N
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The complete question is attached
Which of the following can be determined from the location of a main-sequence star on the H-R diagram? (Select all that apply.) a. temperature b. luminosity c. radius d.…Which of the following can be determined from the location of a main-sequence star on the H-R diagram? (Select all that apply.)a. temperatureb. luminosityc. radiusd. mass
The figure can be used to determine the temperature, luminosity, radius, and mass of a main sequence star.
Mass; B.) Radius; D.) Luminosity; F.) Temperature
The H-R diagram: what is it?The relationship that exists between a star's luminosity and its temperature is depicted in the Hertzsprung-Russell diagram. The H-R diagram and the color-magnitude diagram are other names for it. Because it can be used to plot a star's life cycle, it is a very useful graph. It can be used to investigate groups of stars in galaxies or clusters.
What exactly is the H-R diagram and what is its significance?One of the most significant diagrams in astronomy is the Hertzsprung-Russell diagram, also known as the H-R diagram. This diagram shows the evolutionary course that a star will take, which is influenced by its mass.
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The brakes on your automobile are capable of slowing down your car at a rate of 4.7 m/s2. (a) If you are going 134 km/h and suddenly see a state trooper, what is the minimum time in which you can get your car under the 90 km/h speed limit
Answer:
It's should be 7.0m/s.....i hope it helps
A jewelry thief needs to jump across a 3-meter-wide alleyway as she makes her escape. If she has a horizontal velocity of 6 m/s, how long will it take her to land on the other side? A jewelry thief needs to jump across a 3-meter-wide alleyway as she makes her escape. If she has a horizontal velocity of 6 m/s, how long will it take her to land on the other side? 0.6 s 0.5 s 1.1 s 1.2 s
The time it will take her to land on the other side is 0.5 seconds.
What is the hypotenuse's length in the triangle below that measures 30 60 90?In a triangle with three angles of 30°, 60°, and 90°, the hypotenuse is twice as long as the shorter leg and three times as long as the latter. To understand why this is the case, consider that the triangle is a right triangle given these numbers according to the Converse of the Pythagorean Theorem. The lengths of the three sides in a triangle of this kind are referred to as a Pythagorean triple.
distance = velocity x time
In this case, the distance is 3 meters and the velocity is 6 m/s, so:
3 = 6 x time
Solving for time, we get:
time = 3/6 = 0.5 seconds
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you walk 5km north for 3 hrs and 2km south for 1 hr what your speed , velocity
Answer: Probably 0.33km/hr south is the net velocity
Explanation:
Speed= Distance/ Time
Speed in North = 5km/3hrs=1.67km/hr
Speed in South= 2/1hrs=2.00km/hr
Since north and south are in opposite directions, and taking north as the +ve y, we get 1.67-2.00= -0.33km/hr, (-ve represents south direction).
What are the si units
Answer:
The uniy which is accepted all over the world is called SI unit.
Explanation:
The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.
10 An electron is accelerated from rest to 0.9 times the speed of light in 4.0 s. How far does it travel in this time? (Take the speed of light, c, as 3.0 x 108 m/s.)
The distance traveled by the electron in 4.0 s would be 1.44 x 10^5 meters.
Distance traveled by an electronUsing the formula: d = (1/2) * a * t^2
The acceleration of the electron can be calculated using the relativistic formula:
a = (e/m) * E
Assuming the electron starts at rest, its initial kinetic energy is zero. Therefore, its final kinetic energy is equal to the work done by the electric field, which is given by:
W = (1/2) * m * v^2
where m is the mass of the electron and v is its final velocity. We can solve this equation for v:
v = sqrt(2 * W / m)
where W is the work done by the electric field.
The work done by the electric field can be calculated using the formula:
W = q * E * d
where q is the charge of the electron, E is the electric field, and d is the distance traveled.
Equating the expressions for W and v, we get:
q * E * d = (1/2) * m * v^2
q = -1.6 x 10^(-19) C (since the electron has a negative charge)
m = 9.11 x 10^(-31) kg
v = 0.9 c = 0.9 * 3.0 x 10^8 m/s
t = 4.0 s
We can solve for E using the relativistic acceleration formula:
a = (e/m) * E
a = (q/m) * E = (v/t)
E = (m * v/t) / q
Thus:
E = (9.11 x 10^(-31) kg * 0.9 * 3.0 x 10^8 m/s / 4.0 s) / (1.6 x 10^(-19) C)
E = 1.026 x 10^5 N/C
Now we can solve for d:
d = (1/2) * a * t^2
where a = (e/m) * E, as given above.
d = (1/2) * (q/m) * E * t^2
d = (1/2) * (-1.6 x 10^(-19) C / 9.11 x 10^(-31) kg) * (1.026 x 10^5 N/C) * (4.0 s)^2
d = 1.44 x 10^5 m
Therefore, the electron travels approximately 1.44 x 10^5 meters in 4.0 seconds.
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a heat engine accepts heat from a source at a rate of 500 kw, and it rejects heat to a sink at a rate of 300 kw. the remainder of the heat is converted to net work output. determine the thermal efficiency of the engine. multiple choice question. 40% 20% 30% 60%
The thermal efficiency of the engine is 40%. The correct answer is (a).
The thermal efficiency of a heat engine is given by:
efficiency = (net work output) / (heat input)
We are given the heat input rate as 500 kW and the heat output rate as 300 kW. The net work output rate can be found by subtracting the heat output rate from the heat input rate:
net work output = heat input - heat output = 500 kW - 300 kW = 200 kW
Substituting these values into the efficiency equation, we get:
efficiency = 200 kW / 500 kW = 0.4 = 40%
Option a is correct.
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One U.S. fluid gallon contains a volume of 231 cubic inches. How many liters of gasoline would you have to buy in Canada to fill a 14-gallon tank? (Note: 1L = 10 +3 cm 3.)
Since we have a 14 gallon tank this means that in total we need:
\(14\cdot231=3234\)cubic inches.
Now, we know that one inche is equal to 2.54 cm then we have that:
\(3234in^3\cdot\frac{2.54\text{ cm}}{1\text{ in}}\cdot\frac{2.54\text{ cm}}{1\text{ in}}\cdot\frac{2.54\text{ cm}}{1\text{ in}}=54995.76cm^3\)finally, and since a liter is equal to 1000 cubic centimeters we have that:
\(54995.76cm^3\cdot\frac{1\text{ L}}{1000cm^3}=54.99576\)Therefore we need 54.99576 liters of gasoline (this is approximately 55 liters)
Obstructions that prevent a safe and orderly exit are an example of which type of unsafe behavior?
Select one:
a. Unintentional ignition sources
b. Inadequate housekeeping
c. Improper storage of flammable liquids
d. Improper storage of combustible liquids
Obstructions that prevent a safe and orderly exit are an example of inadequate housekeeping, which is a type of unsafe behavior. Option B is the correct answer.
Inadequate housekeeping refers to a failure to keep the workplace clean, organized, and free of hazards. It can result in slips, trips, falls, and other accidents that can cause injury or even death.
Proper housekeeping includes keeping floors free of debris, ensuring that tools and equipment are properly stored, and maintaining a clutter-free workspace.
By practicing good housekeeping, employers can help prevent accidents, improve productivity, and create a safer work environment for their employees.
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the graph below shows the speed of an object during a 10 s time interval. In which of the following time intervals is the speed of the object was constant?
a. between 6 s and 8 s
b. between 2 s and 4 s
c. between 0 s and 2 s
d. between 2 s and 5 s
Answer:
b. between 2 s and 4 s
Explanation:
2-4 was both 3m/s
the parallax angle for the star 61 cygni is measured to be 0.29"" and it has an apparent magnitude of m=5.21. calculate the absolute magnitude of 61 cygni; m= a) 0.21. b) 2.9. c) 5.21. d) 7.6.
The absolute magnitude of 61 Cygni is calculated to be 7.6. The correct option is d).
To calculate the absolute magnitude of a star, we need to use the parallax angle and the apparent magnitude. The formula relating parallax angle (π), apparent magnitude (m), and absolute magnitude (M) is as follows:
m - M = 5 * log10(d/10)
m = apparent magnitude
M = absolute magnitude
d = distance to the star in parsecs
In this case, we are given the parallax angle for 61 Cygni as 0.29 arcseconds (0.29"), and the apparent magnitude as 5.21.
Step 1: Convert the parallax angle from arcseconds to parsecs
The formula for converting parallax angle to distance is:
d = 1/π
where π is the parallax angle in arcseconds.
Using the given parallax angle of 0.29", we can calculate the distance (d) as:
d = 1/0.29
d ≈ 3.448 parsecs
Calculate the absolute magnitude
Using the formula mentioned earlier, we can rearrange it to solve for the absolute magnitude (M):
M = m - 5 * log10(d/10)
Substituting the values:
M = 5.21 - 5 * log10(3.448/10)
M ≈ 7.6
Therefore, the absolute magnitude of 61 Cygni is approximately 7.6. The correct option is d).
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The Physics of Energy | 1st Edition Chapter 31, Problem 1P Compute the pressure at a depth Z below the surface in a reservoir behind a hydroelectric dam. Compute the work done by a volume of water as it passes from this pressure on one side of a turbine to essentially zero pressure on the other side. Show that this analysis yields the same formula (31.2)[P = e * dV/dt = rho * g * Z * e * Q] for the power output as the energy analysis presented in §31.1.1.
The analysis using pressure and work yields the same formula for power output as the energy analysis presented in §31.1.1.
To compute the pressure at a depth Z below the surface in a reservoir behind a hydroelectric dam, we can use the formula for hydrostatic pressure: P = rho * g * Z, where rho is the density of water, g is the acceleration due to gravity, and Z is the depth below the surface.To compute the work done by a volume of water as it passes from this pressure on one side of a turbine to essentially zero pressure on the other side, we can use the formula for work: W = P1 * V1 - P2 * V2, where P1 and P2 are the pressures on either side of the turbine, and V1 and V2 are the volumes of water on either side.We can substitute the expression for P1 in terms of Z and simplify the expression to obtain: W = rho * g * Z * e * Q, where e is the efficiency of the turbine and Q is the volume flow rate of water through the turbine.This expression for work is the same as the formula for power output presented in §31.1.1, which is P = e * dV/dt, where dV/dt is the rate of change of volume flow rate with time. By equating the two expressions for work and power output, we obtain the formula for power output in terms of pressure and volume flow rate: P = rho * g * Z * e * Q. Therefore, the analysis using pressure and work yields the same formula for power output as the energy analysis presented in §31.1.1.For more such question on power
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Exercise 17.69 - Enhanced - with Feedback and Hints MISSED THIS? Read Section 17.6 (Pages 745-753); Watch KCV - Part A 17.6. IWE 17.8. A 0.190M solution of a weak acid (HA) has a pH of 2.93. Calculate the acid ionization constant (K
a
) for the acid. Express your answer using two significant figures
The acid ionization constant (\(K_{a}\)) for the weak acid HA in the given question for the shared values will be around 0.
We must use the pH and concentration of the acid solution to determine the acid ionization constant (Ka) for the weak acid HA.
The amount to which the weak acid dissociates in water is indicated by the acid ionization constant.
Assumed: pH = 2.93.
HA concentration: 0.190 M.
We will use the following relationship between pH and the number of hydronium ions ( \(H_{3} 0^{+}\) ) to address this issue:
pH equals -log \(H_{3} 0^{+}\)
First, using the provided pH, we must determine the hydronium ion concentration:
\(H_{3} O^{+}\) = \(10^{-pH}\)
\(H_{3} O^{+}\)= \(10^{-2.93}\)
\(H_{3} 0^{+}\) = 7.33 × \(10^{-3}\) M
As we know that HA is a weak acid, it dissociates into its conjugate base
(\(A^{-}\)) and hydronium ions like the following reaction:
\(HA\) ⇄ \(A^{-}\) + \(H_{3} 0^{+}\)
Expression for equilibrium to the above reaction:
\(K_{a\)= (concentration of conjugate base x concentration of hydronium ions)/ concentration of HA
We don't know the concentration of the conjugate base.
But we do know that the solution is very dilute so we can say that the dissociation of the given acid is very less compared to the concentration.
So we can take its value to be 0.
\(K_{a}\) = (0 × \(H_{3} 0^{+}\)) / HA
\(K_{a}\) = 0
So, the acid ionization constant for the given acid will be zero.
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The acid ionization constant (Ka) for the weak acid is \(1.7 * 10^{-3}\).
To calculate the acid ionization constant (Ka), we need to use the pH value and concentration of the weak acid solution. The pH of the solution indicates the concentration of H+ ions, which is related to the concentration of the weak acid and its dissociation.
The pH can be converted to the concentration of H+ ions using the formula: \([H+] = 10^{(-pH).\)
In this case,\([H+] = 10^{(-2.93).\)
Since the weak acid is not completely dissociated, the concentration of the weak acid ([HA]) can be approximated as its initial concentration, which is given as 0.190M.
The dissociation of the weak acid can be represented as follows:
HA ⇌ H+ + A-
The equilibrium expression for the dissociation is \(K_a = [H+][A-] / [HA]\).
Substituting the values into the equation:
\(Ka = (10^{(-2.93)})(10^{(-2.93)}) / 0.190.\)
Calculating the value gives us:
\(Ka = 1.7 * 10^{-3.\)
Therefore, the acid ionization constant (Ka) for the weak acid is approximately \(1.7 * 10^{-3}\).
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High tide from Moon's pull on
oceans
High tide from Moon's pull on
solid ground
Low tide ahead of Moon's
orbit
Low tide behind Moon's orbit
3
TE
Label the diagram with descriptions of the tides at each location.
Sign out
ES
Feb 2
8:
PLEASE HURRY
I'm sorry but I don't know
PLEASE HELP
Approximate grams per spoonful:
g
Which of the following is a true statement?
A 380-kg piano slides 2. 9 m down a 2 5 ∘ 25 ∘ incline and is kept from accelerating by a man who is pushing back on it parallel to the incline (Fig. 6–36). Determine: the force exerted by the man, the work done on the piano by the man, the work done on the piano by the force of gravity, and the net work done on the piano. Ignore friction
The force exerted by the man is 1566.82 N.and the work done on the piano by the man is 4535.05 J and the work done on the piano by the force of gravity is 4535.05 J and the net work done on the piano is 9070.10 J.
To determine the force exerted by the man, we need to consider the forces acting on the piano. The only horizontal force acting on the piano is the force exerted by the man, since we are ignoring friction.
The force exerted by the man is equal in magnitude and opposite in direction to the component of the weight of the piano that is parallel to the incline.
First, let's find the weight of the piano. The weight (W) of an object is given by the formula W = m * g, where m is the mass and g is the acceleration due to gravity. In this case, the mass of the piano is 380 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. So, the weight of the piano is W = 380 kg * 9.8 m/s² = 3724 N.
Now, let's find the component of the weight that is parallel to the incline. This can be calculated using the formula F_parallel = W * sin(theta), where theta is the angle of the incline. In this case, the angle of the incline is 25 degrees. So, the force exerted by gravity parallel to the incline is F_parallel = 3724 N * sin(25 °) = 1566.82 N.
Since the man is pushing back on the piano parallel to the incline to keep it from accelerating, the force exerted by the man is equal in magnitude and opposite in direction to the force exerted by gravity parallel to the incline. Therefore, the force exerted by the man is 1566.82 N.
To find the work done on the piano by the man, we can use the formula W = F * d * cos(Ф), where F is the force exerted by the man, d is the distance the piano slides down the incline, and theta is the angle between the force exerted by the man and the direction of motion.
In this case, the angle between the force exerted by the man and the direction of motion is 0 degrees, since the force and the motion are parallel. So, the work done on the piano by the man is W = 1566.82 N * 2.9 m * cos(0 °) = 4535.05 J.
The work done on the piano by the force of gravity can be calculated using the formula W = F * d * cos(Ф), where F is the force exerted by gravity parallel to the incline, d is the distance the piano slides down the incline, and Ф is the angle between the force exerted by gravity and the direction of motion.
In this case, the angle between the force exerted by gravity and the direction of motion is also 0 degrees. So, the work done on the piano by the force of gravity is W = 1566.82 N * 2.9 m * cos(0 °) = 4535.05 J.
Finally, the net work done on the piano is the sum of the work done by the man and the work done by the force of gravity. So, the net work done on the piano is 4535.05 J + 4535.05 J = 9070.10 J.
In summary:
- The force exerted by the man is 1566.82 N.
- The work done on the piano by the man is 4535.05 J.
- The work done on the piano by the force of gravity is 4535.05 J.
- The net work done on the piano is 9070.10 J.
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A 3.49-kg centrifuge spins up from rest with constant angular acceleration so that, after 130 s, a point 7.3 cm from the axis of rotation is moving at 124 m/s. Calculate the magnitude of the centrifuge's angular acceleration.
the magnitude of the centrifuge's angular acceleration is approximately 13.07 rad/s². To find the angular acceleration of the centrifuge, we'll first determine its angular velocity, then use the angular kinematic equation to calculate the angular acceleration. We'll use these terms in our explanation: angular acceleration (α), angular velocity (ω), initial angular velocity (ω₀), time (t), linear velocity (v), and radius (r).
1. Find the angular velocity (ω):
Given that the linear velocity of a point 7.3 cm (0.073 m) from the axis is 124 m/s, we can use the formula:
v = rω
Solving for ω:
ω = v / r = 124 m/s / 0.073 m ≈ 1698.63 rad/s
2. Use the angular kinematic equation to find the angular acceleration (α):
Since the centrifuge starts from rest, the initial angular velocity (ω₀) is 0. The equation is:
ω = ω₀ + αt
Solving for α:
α = (ω - ω₀) / t = (1698.63 rad/s - 0 rad/s) / 130 s ≈ 13.07 rad/s²
Therefore, the magnitude of the centrifuge's angular acceleration is approximately 13.07 rad/s².
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what if the water around the hot metal wasnot stirred but the thermometer were rested away
If the water around the hot metal was not stirred but the thermometer was rested away, the temperature readings you obtain may not be representative of the actual temperature of the water.
Stirring the water is important in a heat capacity experiment because it ensures that the temperature is uniform throughout the water. If you don't stir the water during the experiment, the temperature readings you take will only reflect the temperature of the part of the water that is closest to the thermometer, rather than the temperature of the entire sample.
If the water around the hot metal was not stirred but the thermometer was rested away, the temperature readings you obtain may not be representative of the actual temperature of the water. This is because the temperature around the hot metal will be higher than the temperature in other parts of the water that are not in direct contact with the metal.
As a result, the measured heat capacity value may be higher or lower than the actual value, depending on the extent to which the temperature around the metal deviates from the average temperature of the entire water sample.
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How is the speed trap gun used to measure speed?
Answer:
the speed of light, the difference in frequency between the radio waves that receive back by the gun.
Explanation: