what is the maximum number of electrons that can occupy a principal of energy level (n) of an atom

Answer:

  1.7700×10^-22 g

Explanation:

A face-centered-cubic cell contains 4 atoms, so the volume per atom is ...

  (389.80×10^-12 m)³/(4 atoms) ≈ 1.4725×10^-29 m³

Then the mass of 1 atom is ...

  (12020 kg/m³)(1.4725×10^-29 m³) ≈ 1.76995×10^-25 kg

  ≈ 1.7700×10^-22 g

_____

Additional comment

That is the approximate mass of a Palladium atom.

Answer:

1.7700×10^-22 g

Explanation:

In a chromatography experiment, a mixture of red, blue, and green dyes is separated using a stationary phase and a mobile phase. The stationary phase has a length of 10 cm, and the mobile phase moves at a constant velocity of 2 cm/min. The red dye travels a distance of 6 cm, the blue dye travels a distance of 8 cm, and the green dye travels a distance of 9.5 cm.

What is the retention factor (Rf) for each dye?

Solution:

To calculate the retention factor (Rf) for each dye, we use the formula:

Rf = Distance traveled by the dye / Distance traveled by the mobile phase

For the red dye:

Distance traveled by the dye = 6 cm

Distance traveled by the mobile phase = 10 cm

Rf (red) = 6 cm / 10 cm = 0.6

For the blue dye:

Distance traveled by the dye = 8 cm

Distance traveled by the mobile phase = 10 cm

Rf (blue) = 8 cm / 10 cm = 0.8

For the green dye:

Distance traveled by the dye = 9.5 cm

Distance traveled by the mobile phase = 10 cm

Rf (green) = 9.5 cm / 10 cm = 0.95

Therefore, the retention factors (Rf) for the red, blue, and green dyes are 0.6, 0.8, and 0.95, respectively.

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The first element whose atomic number is 21 is Scandium and the second element whose atomic number is 7 is Nitrogen. Based on electronic configuration

Electronic configuration is a systematic way of distributing the electrons in their orbitals  Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells (with the number of electrons they hold written in superscript) are placed in a sequence.

Electron Configurations are useful for:

Determining the valency of an element.

Predicting the properties of a group of elements (elements with similar electron configurations tend to exhibit similar properties).

Interpreting atomic spectra.

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Answer:

I don't know sorry

Explanation:

ask tutor

The balanced reaction equation is given as;

\(2Al + 6HF(aq) ------- > 2AlF_{3} (aq) + 3H_{2} (g)\)

We know that a chemical reaction has to do with the interaction between the reactants which would lead to the formation of the products. We know that one of the rules that govern a chemical reaction is that a reaction equation would be said to be balanced if the number of the atoms of each of the elements on the reactants side is the same as the number of the atoms on the products side.

The balanced reaction equation of the reaction between solid aluminum reacting with aqueous hydrogen monofluoride to produce aqueous aluminum fluoride and hydrogen gas has been shown above.

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Answer:

Ecological succession is the process by which

Gradually, these communities replace one another until a “climax community”—like a mature forest—is reached, or until a disturbance, like a fire, occurs. Ecological succession is a fundamental concept in ecology.

Explanation:

i hope it helps uh.!!

Answer:

the wax is a nonpolar substance that will not mix with polar water

Explanation:

Water is polar by due to the uneven distribution of charge between the hydrogen and oxygen. T=This automatically eliminates options 3 and 4.

Wax on the other hand is a non polar substance. Due to this non polar characteristic, it would not dissolve in water. The correct option is;

- the wax is a nonpolar substance that will not mix with polar water

The correct answer to the problem expressed to the correct number of significant figures is option C, 3.1.

Significant figures are a way of measuring the precision of a value and indicate the digits that give meaning to a number. The rules for determining the number of significant figures are as follows:

1. All non-zero digits are significant.

2. Zeroes between non-zero digits are significant.

3. Trailing zeroes are significant if there is a decimal point.

4. Trailing zeroes are not significant if there is no decimal point.

5. In scientific notation, all digits are significant.

In the given problem, we have the addition of 2.13 and 1. The number 2.13 has two significant figures, and the number 1 has one significant figure. According to the rules, the result of the addition should have the same number of significant figures as the number with the fewest significant figures.

Performing the addition gives us 3.13. However, since the number 1 has only one significant figure, the result should be rounded to one significant figure after the decimal point. Therefore, the correct answer is 3.1.

The problem expressed to the correct number of significant figures yields the answer 3.1, rounded to one significant figure after the decimal point. This aligns with the rules for significant figures, which indicate that the result should have the same number of significant figures as the number with the fewest significant figures.

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Rusting is an electrochemical reaction. Iron rusts faster when alloyed with cobalt than when alloyed with manganese because, in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

An alloy is a combination of two metals. There are various reasons for producing alloys such as greater tensile strength, corrosion resistance and improved aesthetic appearance.

When iron is alloyed with cobalt, the iron rusts faster than pure iron because iron is rendered the anode and cobalt is rendered the cathode. When the iron is alloyed with manganese, it rusts more slowly than pure iron because in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode.

Missing parts;

An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese rusts less quickly than a pure iron object under the same conditions. This is true because

(1) cobalt is a stronger reducing agent than iron

(2) iron is a stronger reducing agent than manganese

(3) cobalt exhibits more metallic character than either iron or manganese

(4) in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

(5) in the iron-cobalt alloy, cobalt is rendered the anode and iron is rendered the cathode

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A silver precipitate is created when silver nitrate, AgNO3, and magnesium bromide, MgBr2, are combined in aqueous solutions.Create the net ionic equation as well as the balanced formula equation for this reaction.

The end products of the reaction between aqueous systems of magnesium chloride (MgCl2) and silver nitrate (AgNO3) are solid silver chloride and aqueous magnesium nitrate.

The right response is (CH3)3C-Cl.The most reliable 3° carbocation is formed by tert-butyl chloride, or (CH3)3C - Cl.As a result, it will immediately produce the white precipitate of AgCl in AgNO3 solution.

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Answer:(:

Explanation:

An example of the solar system is the eight planets including Earth that revolve around the sun. The sun together with the eight planets and all other celestial bodies that orbit the sun. A system of planets or other bodies orbiting a star. That portion of our galaxy which is subject to the gravity of the sun

The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

The mass of the excess reagent (iron) that remains after the reaction is complete is 12.1 grams.

The maximum mass of Iron(III) oxide that can be formed is 74.8 grams.

The formula for the limiting reactant is O₂, which is oxygen gas.

Calculate the number of moles of each reactant:

Number of moles of iron = 38.2 g / 55.845 g/mol = 0.683 moles

Number of moles of oxygen = 14.9 g / 32.00 g/mol = 0.466 moles

The balanced equation shows that the stoichiometric ratio between iron and oxygen is 4:3. Therefore, the mole ratio of iron to oxygen is 4:3.

Since the mole ratio of iron to oxygen is greater than 4:3, it means that there is an excess of iron and oxygen is the limiting reactant. So we need to use the number of moles of oxygen to calculate the maximum mass of Iron(III) oxide that can be formed.

The balanced equation shows that 1 mole of iron reacts with 1 mole of oxygen to produce 1 mole of Iron(III) oxide. The molar mass of Iron(III) oxide is 159.69 g/mol.

Number of moles of Iron(III) oxide = 0.466 moles (which is equal to the number of moles of oxygen)

The maximum mass of Iron(III) oxide = Number of moles of Iron(III) oxide x molar mass of Iron(III) oxide

Maximum mass of Iron(III) oxide = 0.466 moles x 159.69 g/mol = 74.8 grams

The maximum mass of Iron(III) oxide that can be formed is 74.8 grams.

The formula for the limiting reactant is O₂, which is oxygen gas.

To calculate the mass of the excess reagent (iron) that remains after the reaction is complete, we need to first calculate the mass of iron that reacted with the oxygen:

Mass of iron reacted = 0.466 moles x 55.845 g/mol = 26.1 grams

The initial mass of iron was 38.2 grams, so the mass of excess iron that remains after the reaction is complete is:

Mass of excess iron = initial mass of iron - a mass of iron reacted

Mass of excess iron = 38.2 g - 26.1 g = 12.1 grams

The mass of the excess reagent (iron) that remains after the reaction is complete is 12.1 grams.

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CD4 and CD8 T-cell numbers are decreased after blunt trauma.

A body damage brought on by a strong collision with a dull item or surface is known as blunt trauma, also known as non-penetrating trauma or blunt force trauma. It differs from penetrating trauma, which occurs when an object or surface pierces the body and leaves an open wound. To stabilize and care for the patient, trauma hospitals need to use a coordinated, multidisciplinary approach. For instance, a Level I trauma center has well-established treatment protocols in place and specific sorts of healthcare specialists on call around-the-clock, seven days a week.

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Answer:

B. Charges ( a slight positive charge on one end, and a slight negative charge on the other).

The Bohr model is a representation of the electronic configuration of the atom. According to this model, each energy level can hold a certain number of electrons. In the first energy there can only be 2 electrons, in the second and the following energy levels there can be a maximum of 8 electrons.

Sodium, Na which has 11 electrons in total so in the first level it will have two electrons, in the second level it will have 8 electrons and in the third level it will have the missing electron.

In the model proposed by the student, the electrons are represented in blue. The model proposed by the student is incorrect.

We see that in the second energy level he drew 9 electrons, this is incorrect since from the second energy level there can only be 8 electrons, the remaining electron must be located in the third energy level.

Answer:

wind and soil? north?

Explanation:

Answer:

2MgO is the chemical formula of the product formed

1a. The empirical formula of the compound is Fe₂O₃

1b. The molecular formula of the compound is Fe₂O₃

2a. The molecular formula of the anhydrous salt is MgSO₄

2b. The formula of the crystalline salt is MgSO₄.7H₂O

3i. The number of mole of carbon atoms in the compound is 6 moles

3ii. The number of mole of hydrogen atoms in the compound is 18 moles

3iii. The number of molecules in 3 moles of ethane is 1.806×10²⁴ molecules

Divide by their molar mass

Fe = 69.9 / 56 = 1.248

O = 30 / 16 = 1.875

Divide by the smallest

Fe = 1.248 / 1.248 = 1

O = 1.875 / 1.248 = 3/2

Multiply by 2 to express in whole number

Fe = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Fe₂O₃

Molecular formula = empirical × n = molar mass

[Fe₂O₃]n = 159.89

[(56×2) + (16×3)]n = 159.89

160n = 159.89

n = 159.89 / 160

n = 1

Molecular formula = [Fe₂O₃]n

Molecular formula = [Fe₂O₃] × 1

Molecular formula = Fe₂O₃

We'll begin by calculating the empirical formula

Divide by their molar mass

Mg = 20.0 / 24 = 0.83

S = 26.66 / 32 = 0.83

O = 53.33 / 16 = 3.33

Divide by the smallest

Mg = 0.83 / 0.83 = 1

S = 0.83 / 0.83 = 1

O = 3.33 / 0.83 = 4

Thus, the empirical formula of the anhydrous salt is MgSO₄

The molecular formula of the anhydrous salt can be obtained as follow:

Molecular formula = empirical × n = molar mass

[MgSO₄]n = 120

[24 + 32 + (16×4)]n = 159.89

120n = 120

n = 120 / 120

n = 1

Molecular formula = [MgSO₄]n

Molecular formula = [MgSO₄] × 1

Molecular formula = MgSO₄

Divide by their molar mass

MgSO₄ = 48.8 / 120 = 0.4

H₂O = 51.2 / 18 = 2.8

Divide by the smallest

MgSO₄ = 0.4 / 0.4 = 1

H₂O = 2.8 / 0.4 = 7

Thus, the formula of the crystalline salt is MgSO₄.7H₂O

1 mole of C₂H₆ contains 2 moles of carbon atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 2 = 6 moles of carbon atoms

1 mole of C₂H₆ contains 6 moles of hydrogen atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 6 = 18 moles of hydrogen atoms

From Avogadro's hypothesis,

1 mole of ethane = 6.02×10²³ molecules

Therefore,

3 moles of ethane = 3 × 6.02×10²³ molecules

3 moles of ethane = 1.806×10²⁴ molecules

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Complete question

2. A crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%. Ccalculate the molecular formula of the anhydrous and the crystalline salt. The molecular weight of the anhydrous salt is 120

Answer:

The answer is a trench

Answer: Hello i am confused are you asking a question?

Explanation:

To determine the temperature at which an exothermic reaction ceases to be spontaneous, we need to calculate the Gibbs free energy change (ΔG) and use the equation ΔG = ΔH - TΔS.

Given that ΔH = -71 kJ/mol and ΔS = -58 J/K·mol, we can calculate ΔG at different temperatures to determine the temperature at which the reaction becomes non-spontaneous.

At a temperature of 0 K, ΔG = ΔH, since TΔS = 0. Thus, ΔG = -71 kJ/mol.

As the temperature increases, TΔS becomes more negative, which means that ΔG becomes more negative, making the reaction more spontaneous.

At a certain temperature, however, ΔG will become positive, which means that the reaction is no longer spontaneous and will not proceed on its own. This temperature can be found by rearranging the equation ΔG = ΔH - TΔS to T = ΔH / ΔS, and substituting the known values for ΔH and ΔS:

T = ΔH / ΔS = -71 kJ/mol / (-58 J/K·mol) = 1230 K

So, the reaction will cease to be spontaneous at a temperature of approximately 1230 K.

Answer:

B) Ammonia gas

Explanation:

Ammonia gas: It consists of only one molecule namely ammonia throughout the substance so it is a pure single substance.

Answer:

When a substance is heated ,the kinetic energy of its molecules also increase.

Explanation:

K.E is directly proportional to T

Answer:

c.corn syrup

the egg shrinks due to osmosi.