What is the mass ratio for NH3?

Answer:

1577 °C

Explanation:

Step 1: Calculate the volume of the cylinder

The diameter of the base (d) is 13.0 cm and the height (h) is 15.6 cm. We will use the following expression.

V = h × π × (d/2)²

V = 15.6 cm × π × (13.0 cm/2)² = 8.28 × 10³ cm³ = 8.28 × 10³ mL = 8.28 L

Step 2: Calculate the moles of BF₃

We have 0.0985 kg (98.5 g) of BF₃, whose molar mass is 67.81 g/mol.

98.5 g × 1 mol/67.81 g = 1.45 mol

Step 3: Convert 2.70 MPa to atm

We will use the conversion factor 1 MPa = 9.86923 atm.

2.70 MPa × 9.86923 atm/1 MPa = 26.6 atm

Step 4: Calculate the maximum safe operating temperature

We will use the ideal gas equation.

P × V = n × R × T

T = P × V / n × R

T = 26.6 atm × 8.28 L / 1.45 mol × (0.0821 atm.L/mol.K) = 1850 K

We can convert 1850 K to Celsius using the following expression.

°C = K - 273.15 = 1850 K - 273.15 = 1577 °C

Answer:

\(P=361.2torr\)

Explanation:

Hello,

In this case, considering that the formed liquid is solution is ideal, we can relate the vapor pressure and molar fraction of water with the total vapor pressure of the solution by using the Dalton's equilibrium-based law:

\(P=x_{H_2O}P_{H_2O}^v\)

In such a way, we compute the molar fraction of water by computing its moles as well as diglyme:

\(n_{H_2O}=100mL*\frac{1g}{1mL} *\frac{1mol}{18g} =5.56molH_2O\\\\n_{C_6H_{14}O_3}=150g*\frac{1mol}{134g}=1.12molC_6H_{14}O_3\)

Thus, the mole fraction of water:

\(x_{H_2O}=\frac{5.56mol}{5.56mol+1.12mol}=0.832\)

Thereby, the vapor pressure of the solution:

\(P=0.832*434torr\\\\P=361.2torr\)

Regards.

The vapor pressure of the pure water with diglyme has been 361.28 torrs.

Vapor pressure of a solution can be given by :

Vapor pressure = Mole fraction of solvent \(\times\) Vapor pressure of the pure solvent

The pure solvent has been pure water.

The vapor pressure of pure water = 434 torr.

The mole fraction of the solvent can be given as:

Mole fraction of solvent = \(\rm \dfrac{Moles\;of\;solvent}{Moles\;of\;solution}\)

The solvent has been water. The density of water has been 1g/ml. It states that the mass of the 1 ml sample is 1 gram.

Mass of 100 ml water sample = 100 grams

Moles can be expressed as:

Moles = \(\rm \dfrac{weight}{molecular\;weight}\)

Moles of solvent (water) = \(\rm \dfrac{100}{18}\)

Moles of solvent (water) = 5.55 mol.

The moles of solute (Diglyme) can be given as:

Moles of solute (Diglyme) = \(\rm \dfrac{150}{134.17}\)

Moles of solute (Diglyme) = 1.117 mol.

The moles of solution = Solvent + solute

The moles of solution = 5.55 + 1.117 mol

The moles of solution = 6.667 mol.

The mole fraction of the solvent has been;

Mole fraction of solvent = \(\rm \dfrac{5.55}{6.667}\)

Mole fraction of solvent = 0.832

The vapor pressure of the solution will be:

Vapor pressure = 0.832 \(\times\) 434 torr

The vapor pressure of the solution = 361.28 torrs.

The vapor pressure of the pure water with diglyme has been 361.28 torrs.

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Answer:

A scientific control is an experiment or observation designed to minimize the effects of variables other than the independent variable. This increases the reliability of the results, often through a comparison between control measurements and the other measurements.A scientific control is an experiment or observation designed to minimize the effects of variables other than the independent variable. This increases the reliability of the results, often through a comparison between control measurements and the other measurements.

Explanation:

Let's all give it up for GOOGLE! where you can literally get an answer to something.

Answer:

\(\boxed{\bold { \Large { \boxed {0.28 \ kg}}}}\)

Explanation:

Use kinetic energy formula

\(\sf \displaystyle K.E=\frac{1}{2} mv^2\)

Solve for m

\(\displaystyle 125=\frac{1}{2} m \times 30^2\)

\(m=0.2777..\)

A man has a kinetic energy of 125J when he runs at 30m/s.  0.2777  is the mass of the man.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles.

Use kinetic energy formula:

Given data:

K.E = 125J

V = 30m/s

K.E = \(\frac{1}{2} mv^2\)

Solve for m

125J = \(\frac{1}{2} \;m \;{30m/s}^2\)

m = 0.2777

Hence,  0.2777 is the mass of the man.

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Answer:

The type of force is known as cohesive force

Answer:

it is propane

C3H8 it is propane

The Full name of the given compound is Propane.

Propane is a three-carbon alkane with the molecular formula C₃H₈.

It is a gas at standard temperature and pressure, but compressible to a transportable liquid.

In the figure given ;

In the given figure, there is single bond present between Carbon and Hydrogen. Hence, The Full name of the given compound is Propane.

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Answer:

i have that question too someone help pleaseeeee

Explanation:

Answer:

I don't know.

Explanation

Sorry, I don't know the answer, what I can give you though is this, "One mole of potassium chloride = 57.1436"

Hope this helps.

The molarity is an important method which is used to determine the concentration of a solution. So the term molarity is also known as the concentration. Here the grams of Kr which occupies a volume of 42.6 mL is

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. Its unit is mol L⁻¹ and it is essential to calculate the concentration of a binary solution.

Here M₁V₁ = M₂V₂

M₂ = M₁V₁ /  V₂

25.7 mL = 0.0257 L

42.6 mL = 0.0426 L

M₂ =  5.10 × 0.0257 / 0.0426  = 3.076 g

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71. The broad, painless, pink-gray, wart-like infectious lesions that may develop on the vulva, perineum, or anus in syphilis are called "condyloma lata."

72. In suspected syphilis infection, the term RPR stands for "Rapid Plasma Reagin." It is a blood test used to screen for syphilis.

73. The recommended dosage of Benzathine Penicillin in an adult in Zambia may vary depending on the stage and severity of the syphilis infection. It is best to consult local guidelines or a healthcare professional for the specific recommended dosage in Zambia.

74. The recommended drug for the treatment of gonorrhea when using syndromic management may vary depending on local guidelines and antibiotic resistance patterns. Commonly used antibiotics include ceftriaxone in combination with azithromycin or doxycycline.

75. The causative organism for chancroid is called "Haemophilus ducreyi."

76. The commonest type of HIV is "HIV-1."

77. The assertive, problem-solving approach to the identification and treatment of the patient's problems is called "clinical decision-making."

78. A tumor arising from the cells producing melanin is also known as "melanoma."

79. The type of sound described as drum-like, loud, and empty quality felt over a gas-filled stomach, intestine, or pneumothorax during percussion is called "tympany."

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Answer:

1. B

2. A

3. E

4. D

5. C

Explanation:

Explanation:

A buffer is a mixture of a weak acid and its conjugate base, or a weak base and its conjugate acid. In our case we are reacting a strong acid (HCl) and a weak base (sodium acetate). So we don't have a buffer. The strong acid will neutralize the weak base. We have to determine which of them is in excess and find the pH of the resulting solution.

HCl (aq) + CH₃COONa (aq) ----> NaCl (aq) + CH₃COOH (aq)

First we have to determine the number of moles of each reactant. We added 275 ml of a 0.676 M solution of HCl and 500 mL of a 0.525 M solution of CH₃COONa. We can use the definition of molarity concentration to determine the number of moles of each reagent.

Molarity = moles of solute/volume of solution in L

moles of solute = molarity * volume of solution in L

moles of HCl = 0.676 M * 0.275 L

moles of HCl = 0.186 moles

moles of CH₃COONa = 0.525 M * 0.500 L

moles of CH₃COONa = 0.262 moles

HCl (aq) + CH₃COONa (aq) ----> NaCl (aq) + CH₃COOH (aq)

In the equation of the reaction all the coefficients are 1. So 1 mol of HCl will completely neutralize 1 mol of CH₃COONa. The molar ratio between them is 1 to 1.

1 mol of HCl = 1 mol of CH₃COONa

We mixed 0.262 moles of CH₃COONa with 0.186 moles of HCl. The 0.186 moles of HCl will neutralize 0.186 moles of CH₃COONa. And CH₃COONa will be excess.

Excess of CH₃COONa = 0.262 moles - 0.186 moles

Excess of CH₃COONa = 0.076 moles

Now we have to determine the concentration of this excess. We mixed 0.275 L with 0.500 L. Then the total volume of solution is 0.775 L. And the concentration of CH₃COONa after the reaction is:

total volume = 0.500 L + 0.275 L

total volume = 0.775 L

Resulting molarity of CH₃COONa = 0.076 moles/0.775 L

Resulting molarity of CH₃COONa = 0.098 M

Finally to get our answer we have to determine the pH of this resulting solution. To determine the pH of a weak base we have to use the ICE table. In solution

Answer:

Answer:

C

Explanation:

Line graphs are better to show the relations between over time, as circle shows the amount or present of something in a cert time

The density of the rock with a mass of 13 g and is dropped into a graduated cylinder containing 12 mL of water is 0.57g/mL.

The density of a substance can be calculated using the following formula:

Density = mass ÷ volume

According to this question, a small rock with a mass of 13 g is dropped into a graduated cylinder containing 12 mL of water. The water rises to 35 mL.

This means that the volume of the rock is 35 - 12 = 23mL

Density of the rock = 13g ÷ 23mL

Density = 0.57g/mL

Therefore, the density of the rock with a mass of 13 g and is dropped into a graduated cylinder containing 12 mL of water is 0.57g/mL.

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The mass of sodium chloride produced by the chemical reaction between sodium bicarbonate and hydrochloric acid is 8.37g.

The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl):

NaHCO₃ + HCl → NaCl + H₂O + CO₂

1 mole of sodium bicarbonate (NaHCO3) reacts with 1 mole of hydrochloric acid (HCl) to produce 1 mole of sodium chloride (NaCl), 1 mole of water (H₂O), and 1 mole of carbon dioxide (CO₂).

NaCl: Molar mass = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

The number of moles of sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl) using their respective masses:

Number of moles of NaHCO₃ = Mass of NaHCO₃ / Molar mass of NaHCO₃

Number of moles of NaHCO₃ = 12 g / (22.99 g/mol + 1.01 g/mol + 48.00 g/mol + 16.00 g/mol)

Number of moles of NaHCO₃ = 12 g / 84.00 g/mol ≈ 0.143 moles

Number of moles of HCl = Mass of HCl / Molar mass of HCl

Number of moles of HCl = 5.58 g / (1.01 g/mol + 35.45 g/mol)

Number of moles of HCl = 5.58 g / 36.46 g/mol ≈ 0.153 moles

Since the reaction stoichiometry is 1:1 between NaHCO₃ and NaCl, the number of moles of NaCl produced will be the same as the number of moles of NaHCO₃ reacted. Therefore, the mass of NaCl produced can be calculated as follows:

Mass of NaCl produced = Number of moles of NaCl × Molar mass of NaCl

Mass of NaCl produced = 0.143 moles × 58.44 g/mol

The Mass of NaCl produced ≈ 8.37 g

Hence, the mass of sodium chloride produced is approximately 8.37 grams.

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Answer:

No you can't

Explanation:

The atomic number is the amount of protons in element's nucleus, that's one reason why. The second reason is that the atomic mass is protons and neutrons combined, their estimated value, which doesn't show how much neutrons are in an element. It does show combined, but not specifically neutrons

Answer:

Gravity is the force that holds everything in the universe together.

Hope that helps!

Answer:

V=12.6148888506L

Explanation:

using charles law Volume1/Temperature1 = Volume2/Temperature2

13.4L/(17C+273.15C)=V/273.15K

remember gas equations require kelvin not celcius so converting celcius to kelvin is Celcius + 273.15 which is standard temperature conditions

Metals and non-metals interact chemically to produce ionic bonds. If a metal gains enough electrons to create a full valence shell and becomes positively charged, it is by definition considered to be relatively stable. Similar to how a non-metal solid gains stability, a non-metal solid gains electrons to finish off its valence shell and acquire a negative charge.

Metals and non-metals interact chemically to produce ionic bonds. If a metal gains enough electrons to create a full valence shell and becomes positively charged, it is by definition considered to be relatively stable. Similar to how a non-metal becomes stable, a non-metal can do so by gaining electrons to finish out its valence shell and become negatively charged.

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Answer: Therefore, 70.7 mL of 9.89 M nitric acid solution should be used to prepare 3.50 L of 0.200 M HNO3.

Explanation:

To prepare 3.50 L of 0.200 M HNO3, we need to calculate the amount of HNO3 required and then determine the volume of 9.89 M nitric acid solution needed to prepare this amount of HNO3.

The amount of HNO3 required can be calculated using the formula:

amount of HNO3 (in moles) = volume of solution (in liters) x concentration of HNO3 (in moles per liter)

Substituting the given values:

amount of HNO3 = 3.50 L x 0.200 mol/L = 0.700 mol

Now, we can use the amount of HNO3 and the concentration of the nitric acid solution to calculate the volume of the nitric acid solution needed:

volume of nitric acid solution = amount of HNO3 (in moles) / concentration of nitric acid solution (in moles per liter)

Substituting the given values:

volume of nitric acid solution = 0.700 mol / 9.89 mol/L = 0.0707 L

Finally, we can convert the volume to milliliters:

volume of nitric acid solution = 0.0707 L x 1000 mL/L = 70.7 mL

Therefore, 70.7 mL of 9.89 M nitric acid solution should be used to prepare 3.50 L of 0.200 M HNO3.

Regenerate response

Answer:

Example 1

palladium(II) nitrate,

Example 2

Metal catalysts such as Fe, Ni, Mo, and Co are routinely used in the manufacture of CNMs.

Explanation

The three metals used in catalytic converters — rhodium, platinum and palladium — are part of a category known as platinum group metals, or PGMs, which are known for their catalytic properties.

No, a molecule with a \(C_2\)axis perpendicular to the \(C_n\)axis does not necessarily have a mirror plane perpendicular to the \(C_n\)axis.

The presence of a \(C_2\)axis perpendicular to the \(C_n\)axis implies that the molecule possesses rotational symmetry around the \(C_n\)axis. However, the presence of a mirror plane is determined by the presence of an additional symmetry element in the molecule.

A mirror plane is a symmetry element that divides the molecule into two halves, with one half being the mirror image of the other. In order for a mirror plane to be present perpendicular to the \(C_n\)axis, there needs to be an additional symmetry element that produces the reflection symmetry.

While a molecule with a \(C_2\) axis perpendicular to the \(C_n\)axis has rotational symmetry, it does not necessarily possess reflection symmetry. For example, consider a molecule with a \(C_2\)axis perpendicular to a \(C_3\)axis.

The rotational symmetry is evident, as the molecule can be rotated by 120 degrees around the \(C_3\) axis and still appear the same. However, this molecule does not possess a mirror plane perpendicular to the \(C_3\)axis.

The presence of a mirror plane perpendicular to the \(C_n\)axis depends on the specific molecular geometry and arrangement of atoms. It is possible for a molecule to possess both rotational symmetry and a mirror plane perpendicular to the \(C_n\)axis, but it is not a general rule.

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Answer:

Neutron

Explanation:

Neutrons has a neutral or no charge.

Answer: B.) -12.4

Explanation: This is because the sign of heat transfer is determined by the system's perspective. In this case, the system is releasing heat to the surroundings, which means that heat is flowing out of the system, making the heat transfer negative. The magnitude of the heat transfer is 12.4 J.

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

Explanation:

\(\text{From the information given:}\)

\(\text{The chemical reaction is : } 4 KClO_{3(s)} \to 3 KClO_{4(s)} + KCl_{(s)}\)

\(\text{To find} \ \Delta G^0_{rxn}\ \text{using the formula}: \\ \\ \Delta G^0_{rxn} = \sum n_p \times \Delta _f G^0 (Products) - \sum n_R \times \Delta _fG^0 ( Reactants) \\ \\ where; n_p = \text{no of moles of products } \ and; \\ \\ n_R = \text{no of moles of reactants }\)

\(\implies G^0_{rxn} = 3 \times \Delta _fG^0 [KClO_4{(s)}] + \Delta_fG^0[KCl_{(s)}] - 4 \times \Delta _f G^0 [ KClO_3 (s) ]\)

\(\Delta _fG^0 \ values \ at \ 25^0 \ C (298 \ K) are\ given \ as:\\\\ \Delta _fG^0 [KClO_4(s)] = -303.09 \ kJ \\ \\ \Delta _fG^0 [KCl(s) ] = - 409.14 \ kJ \\ \\ \Delta_f G^0 [KClO_3_{(s)}] = -296.25 \ kJ \\ \\ replacing \ the \ above \ values \ into \ equation (1) ; then:\\ \\ \\\Delta G^0_{rxn} = 3 *(-303.09) + (-409.14) - 4*(-296.25) \ kJ \\ \\ = (-909.27 - 409.14 + 1185) \ kJ \\ \\ = -133.41 \ kJ \\ \\ \mathbf{\Delta G^0_{rxn} = -133.4 \ kJ }\)

The standard free energy change of the reaction is -133 kJ.

From the reaction equation, we have; 4KClO3 ⇄ 3KClO4 (s) + KCl (s). The standard free energy of formation of each specie is given below;

ΔG°f KClO3 = -296.35 kJ

ΔG°f KClO4 = -303.09 kJ

ΔG°f KCl = -409.14 kJ

Hence;

ΔG°rxn = [3(-303.09)] + ( -409.14)] - [(4( -296.35))]

ΔG°rxn = (-909.27) + (-409.14) - (-1185.4)

ΔG°rxn = -133 kJ

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Answer:

Molecular formulas describe the exact number and type of atoms in a single molecule of a compound. The constituent elements are represented by their chemical symbols, and the number of atoms of each element present in each molecule is shown as a subscript following that element's symbol

Answer:

3.6

Explanation:

subtract both numbers!

Answer:Approx....

8

⋅

g

⋅

m

L

−

1

....

Explanation:

ρ

,

density

=

Mass

Volume

=

28.5

⋅

g

(

49.10

−

45.50

)

⋅

m

L

=

7.92

⋅

g

⋅

m

L

−

1

....

Explanation: