What is the mass of one liter of liquid in grams, if the density of liquid
is 13.6 g/cm3?

Answer:

one advantage: no air pollutants, one disadvantage: gives off radioactive waste

Answer:

3 then 4 then 5 then 1 then 2

Explanation:

ordering 1 through 5 from top to bottom

The correct order of igneous rock can form at Mauna Loa is as follows:

3Rock beneath Mauna Loa melts to form magma.

4 Melted rock rises toward Earth's surface.

5 Lava erupts from Mauna Loa and flows down the volcano.

1 Lava flowing down the volcano enters the Pacific Ocean.

2 Ocean water cools the lava, causing it to crystallize and form igneous rock.

Igneous rocks are the form when hot, molten rock crystallizes and solidifies. Igneous rock is produced through the cooling and solidification of magma or lava.

Igneous rocks produce when magma from inside the Earth moves toward the surface, or is forced above the Earth's surface as lava and ash by a volcano.

Thus, The correct order of igneous rock can form at Mauna Loa is 3, 4, 5, 1, and 2.

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Answer:

Fear weakens our immune system and can cause cardiovascular damage. Fear can cause damage to some parts of our brains. Fear can interrupt processes in our brains that allow us to regulate emotions.

Explanation:

Hope this helps:)........if not then sorry for wasting your time and may God bless you:)

Answer:

Its when like two pure substances are like combined into one.

Explanation:

The kinetic-molecular theory is a model that describes the behavior of matter at a microscopic level.

In solids, this theory suggests that the particles (atoms or molecules) that make up the solid are in constant motion and are held together by strong intermolecular forces. The particles vibrate about their fixed positions and the amplitude of the vibration increases as the temperature increases. This theory also explains properties such as thermal expansion, specific heat, and thermal conductivity of solids.

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To make a 10% solution from 5g of solute, you would need to add 50 ml of solvent.

To determine the volume of solvent needed to make a 10% solution from 5g of solute, you need to consider the definition of a percentage concentration.

A 10% solution means that 10g of solute is dissolved in 100ml of solution. Therefore, if you have 5g of solute, you can set up a proportion to find the corresponding volume of solvent (V):

(5g solute) / (10g total solution) = (V ml solvent) / (100ml total solution)

Simplifying the proportion:

5/10 = V/100

Cross-multiplying:

10V = 500

Dividing both sides by 10:

V = 50 ml

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Answer:

The order of the reaction with respect to D is 2, and the order with respect to G is 1.

Explanation:

To determine the order of a reaction with respect to each reactant, we look at how changing the concentration of a reactant changes the rate of the reaction.

Looking at the initial concentrations and rates for D in experiments 1 and 2, when the concentration of D is doubled (from 0.025 to 0.050), the rate of reaction quadruples (from 0.00480 to 0.0192). This indicates that the order of the reaction with respect to D is 2, because the rate of reaction changes by the square of the change in concentration.

Next, we look at the initial concentrations and rates for G in experiments 3 and 4. In these experiments, when the concentration of G is quadrupled (from 0.020 to 0.080), the rate of the reaction also quadruples (from 0.0986 to 0.394). This indicates that the order of the reaction with respect to G is 1, because the rate of reaction changes directly with the change in concentration.

So, the order of the reaction with respect to D is 2, and the order with respect to G is 1.

Answer:

its B

Explanation:

this is pretty obvious since I know about this and did it already.

I Hope this helps!

GOODLUCK!!!!!!!

In a system, there are 2 singly linked lists. Another of the linked lists' end nodes was accidentally linked to a second list, creating an inverted E s list. Create a program to find the intersection of two linked lists.

The head of both the linked list is the first node. The value of said neck points to NULL if somehow the link list is empty. In a list, each node has at least two components:

The head of a list refers to the point at which a linked list can be accessed. Head is not an distinct node, it should be highlighted.

Items that show up in the same location in two related circumstances are said to be corresponding objects. Angles are a common example, as demonstrated here. Because they are located in the same spot in the two related shapes, angle A here on left corresponds to angle K on the right. We claim K is the equivalent of A.

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Answer:

The relationship of the speed of sound, its frequency, and wavelength is the same as for all waves: vw = fλ, where vw is the speed of sound, f is its frequency, and λ is its wavelength. ... The more rigid (or less compressible) the medium, the faster the speed of sound

Explanation:

Answer:

The speed of sound can change when sound travels from one medium to another. However, the frequency usually remains the same because it is like a driven oscillation and has the frequency of the original source. If vw changes and f remains the same, then the wavelength λ must change.

A sample of 2.0 L of oxygen at 3.0 atm pressure if  the pressure to 5.0 atm . the volume is 1.2 L.

Given that :

the volume of oxygen , V1 = 2.0 L

the pressure of oxygen , P1 =  3.0 atm

the pressure P2 = 5.0 atm

volume V2 = ?

According to Boyles law :

P1V1 = P2V2

3 × 2 = 5 × V2

6 = 5V2

V2 = 6/5

V2= 1.2 L

Thus, A sample of 2.0 L of oxygen at 3.0 atm pressure if  the pressure to 5.0 atm . the volume is 1.2 L.

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Copper used in electric wires comes in two flavors (isotopes): Cu-63 and Cu-65. Cu-63 has an atomic mass of 62.9298 amu and an abundance of 69.09%. The other isotope, Cu-65, has an abundance of 30.91%. The average atomic mass between these two isotopes is 63.546 amu is 64.93 amu.

Average atomic mass = sum of masses of isotopes multiply by  % of abundance

Cu - 63, mass =  62.9298 amu,   % abundance = 69.09 %

Cu - 65, mass m2 = ?   % abundance = 30.91 %

average atomic mass = 63.546 amu

average atomic mass = ( 62.9298 × 0.6909 ) + ( m2 × 0.3091 )

63.546 =  ( 62.9298 × 0.6909 ) + ( m2 × 0.3091 )

m2 = 64.93 amu

Thus, Copper used in electric wires comes in two flavors (isotopes): Cu-63 and Cu-65. Cu-63 has an atomic mass of 62.9298 amu and an abundance of 69.09%. The other isotope, Cu-65, has an abundance of 30.91%. The average atomic mass between these two isotopes is 63.546 amu is 64.93 amu.

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The role of n-bromosuccinimide (NBS) in this experiment is to selectively brominate the double bonds in the molecule being tested.

NBS is a selective brominating agent that can be used to brominate the double bonds in organic molecules. In this experiment, NBS is added to the reaction mixture along with the molecule being tested. The NBS selectively adds a bromine atom to each double bond in the molecule, forming a dibromo product. This reaction is useful in synthesizing specific compounds and studying the reactivity of double bonds in organic molecules.

N-bromosuccinimide serves as a convenient source of bromine atoms, which allows it to brominate various substrates, such as alkenes or allylic positions in organic compounds.

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Answer:

I think the answer is distilled water...

Explanation:

Answer: 1.57 moles of H3PO4 react with 4.7 moles of K.

Explanation: To calculate the number of moles of H3PO4 that react with 4.7 moles of K, you need to use a mole ratio between H3PO4 and K. The balanced chemical equation for this reaction is:

H3PO4 + 3K → K3PO4 + 3H2

From the balanced equation we can see that for every 1 mole of H3PO4 that reacts, it consumes 3 moles of K. This relationship is known as the mole ratio.

To find out the number of moles of H3PO4 that react with 4.7 moles of K, we can use the following formula:

moles of H3PO4 = (moles of K) / (mole ratio of K to H3PO4)

Substituting in the given values, we get:

moles of H3PO4 = (4.7 moles) / (3 moles/1 mole) = 1.57 moles

Answer:

Sodium ion ( Na+) is known to have no smell at all but however appears salty which is the reason why the compound Sodium Chloride has the same type of taste.

Hydrogen ions ( H+) are known to have no taste which implies it being tasteless. It is also important to note that it has no smell too when perceived (odorless).

Answer:

mass ( g ) = 348 g

Explanation:

First you know : M = mole / volume (L)

in question you have the M and V and the formula of SUBSTANCE ( KF )

first you get the number of mole from equation above

so 3 = no of mole / 2

no of mole = 3 × 2 = 6 moles

and the moles equation is no of moles = mass ( g ) / molecular weight ( g/mole )

so you have already calculate the moles and you can know the MW from the Question

Mw of KF = 39 + 19 = 58

so n = mass / MW

so 6 = mass / 58

mass ( g ) = 348 g

GOOD LUCK

The answer is given below :For each of the given decay processes, the conservation of strangeness is given as follows:(a) Strangeness is conserved.(b) Strangeness is not conserved.(c) Strangeness is conserved.(d) Strangeness is conserved.(e) Strangeness is conserved.(f) Strangeness is conserved.

(a) The decay process given as $K^0 \right arrow \pi^+ + \pi^-$ is the decay of a $K^0$ meson, which is an example of the strong force at work. Strangeness is conserved in this process.

(b) The decay process $ \Lambda^0 \right arrow p + \pi^-$ is a decay of a $\Lambda^0$ baryon. Strangeness is not conserved in this process.

(c) The reaction given as $n + n \right arrow K^- + K^+ + n$ is an example of a strong force interaction. Strangeness is conserved in this process.

(d) The reaction given as $X + n \right arrow \Lambda^0 + K^0$ is an example of a strong force interaction. Strangeness is conserved in this process.

(e) The reaction given as $A^{00} + n \right arrow \Sigma^+ + K^0$ is an example of a strong force interaction. Strangeness is conserved in this process.

(f) The reaction given as $X + p \right arrow A^0 + K^-$ is an example of a strong force interaction. Strangeness is conserved in this process.

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Lactic acid fermentation is not a reasonable long-term solution to a lack of oxygen because it is an inefficient process in terms of energy production and can lead to the accumulation of lactic acid.

During lactic acid fermentation, glucose is converted into lactic acid in the absence of oxygen. This process allows for the regeneration of NAD+ to sustain glycolysis, which is the primary pathway for ATP production in the absence of oxygen. However, lactic acid fermentation produces only a limited amount of ATP compared to aerobic respiration, which is the process that occurs in the presence of oxygen.

Additionally, lactic acid buildup can lead to a decrease in intracellular pH, causing acidification of the cells. This acidic environment can negatively impact cellular processes and potentially lead to cell damage. The accumulation of lactic acid also limits the ability of cells to perform essential functions, including muscle contraction.

In contrast, aerobic respiration, which occurs in the presence of oxygen, is a much more efficient process for ATP production. It generates a significantly higher amount of ATP per glucose molecule compared to lactic acid fermentation. Therefore, in the long term, relying solely on lactic acid fermentation would result in reduced energy production and potential harm to cellular function.

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Answer: 0.910 moles NA+

Definition: of Like Decimal: Two or more decimal fractions are called like ... 0.910; 10.819; 89.637; 142.800 (b) 12.01; 180.3; 1446.105; 180.19

Gold is found in various ionic compounds, but one of the most well-known and commercially significant compounds is gold chloride, also known as auric chloride or gold(III) chloride.

The chemical formula for gold chloride is AuCl₃. Gold chloride is an ionic compound composed of gold cations (Au³⁺) and chloride anions (Cl-). It is a yellow-orange solid that is highly soluble in water. Gold chloride can be formed by reacting the gold metal with chlorine gas or by dissolving the gold metal in aqua regia, which is a mixture of concentrated nitric acid and hydrochloric acid.

Gold chloride has several uses and applications. It is commonly used in the field of nanotechnology for the synthesis of gold nanoparticles. These nanoparticles have unique optical, electronic, and catalytic properties, making them valuable in various fields such as medicine, electronics, and materials science.

In addition to gold chloride, gold can also form other ionic compounds with different anions, such as gold bromide (AuBr), gold iodide (AuI), gold sulfide (Au2S), and gold cyanide (AuCN). These compounds have their own unique properties and applications.

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The heat required to increase the temperature of 3.0 g of argon by 100∘C at constant volume,  use the formula Q = nCvΔT.the number of moles of argon, which is  0.075 mol, that the heat required is  3,750 J.

To begin, we need to find the number of moles of argon in the container. By dividing the mass of argon (3.0 g) by the molar mass of argon (39.95 g/mol), we obtain approximately 0.075 mol.

Next, we determine the molar heat capacity at constant volume, Cv, for argon. This value represents the amount of heat required to raise the temperature of one mole of a substance by 1 Kelvin. For argon, the molar heat capacity at constant volume is approximately 12.5 J/(mol·K).

Using the formula Q = nCvΔT, we substitute the values: n = 0.075 mol, Cv = 12.5 J/(mol·K), and ΔT = 100 K (since the temperature change is given in Kelvin). By multiplying these values together, we find that the heat required, Q, is approximately 3,750 J.

Therefore, approximately 3,750 J of heat is needed to increase the temperature of 3.0 g of argon by 100∘C at a constant volume.

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Answer:

Im not sure what you mean but I hope what I wrote helps you!

The Law of Conservation of Matter says that the amount of matter stays the same, even when matter changes form. Sometimes it may seem that matter disappears during a science experiment, but this law tells us that matter cannot magically appear or disappear, it simply changes from one form to another.

Explanation:

Answer:

F

Explanation:

The mass of zinc that the company can expect to produce is 5g.

The reaction is given as follows:

Ca + ZnCO₂ → Zn + CaCO₃

15g       25g      ? g        35g

To find: mass of zn

The above given reaction is an example of a displacement reaction.

According to law of conservation of mass, in a chemical reaction the mass of reactants is equal to the mass of products.

Here, mass of reactants

= mass of Ca + mass of ZnCO₂

= 15g + 25g

mass of products

= mass of Zn + mass of CaCO₃

=mass of Zn + 35g

∵ mass of reactants = mass of products

⇒ 15g + 25g= mass of Zn + 35g

⇒mass of Zn = (15+25)g - 35g

⇒mass of Zn = 40g- 35g

⇒mass of Zn = 5g

Hence, 5g of Zinc is expected to be produced.

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Solution,

Mass of Mg - 21gm

molar mass of Mg - 24gm

moles = Given mass/ Molar mass

moles = 21/24 = 0.875

1 mole of Mg produce 1 mole of H2 gas

so 0.875 mole of Mg will produce 0.875 moles of H2 gas

One mole of H2 gas = 22.4 litre

0.875 mole of H2 gas = 0.875×22.4

0.875 mole of H2 gas = 19.60 litre

So the nearest ANSWER is Option four 19.37 litre.

STP is the standard temperature and the pressure of the gases of the system. The volume of the hydrogen that will be produced as STP is 19.37 litres.

Volume is the amount of the substance or the solution occupied in an area or object and is estimated in L or mL. It is a scalar quantity.

Given,

Mass of magnesium = 21 gm

Molar mass of magnesium = 24 gm/mol

Moles of magnesium can be calculated as,

\(\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\;mass}\\\\&= \dfrac{21}{24}\\\\&= 0.875 \;\rm mol\end{aligned}\)

If 1-mole magnesium = 1-mole hydrogen gas

Then 0.875-mole magnesium = 0.875 moles of hydrogen gas

If 1 mole of hydrogen gas = 22.4 L

Then, 0.875 moles of hydrogen gas = x L

Solving for x:

\(\begin{aligned}\rm x &= 0.875 \times 22.4\\\\&= 19.60 \;\rm litre\end {aligned}\)

Therefore, the volume of hydrogen at STP would be option 4. 19.37 litres.

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Answer:

hydrological cycle

Explanation:

water cycle is also known as hydrological vycle

Answer:

Hydrological Cycle :)

Explanation:

The presence of an electron-withdrawing group in aniline makes it a poorer nucleophile than diethylamine, which does not have any electron-withdrawing groups.

Aniline is a poorer nucleophile than diethylamine due to the presence of an electron-withdrawing group, the phenyl ring, which decreases the electron density on the nitrogen atom. This results in a weaker nucleophilicity of the nitrogen atom in aniline compared to the nitrogen atoms in diethylamine, which do not have any electron-withdrawing groups.

In organic chemistry, nucleophilicity is a measure of the ability of a molecule or an atom to donate a pair of electrons to another atom or molecule. A nucleophile is a molecule or an atom that can donate a pair of electrons to an electrophile, which is an atom or molecule that is electron deficient and can accept a pair of electrons.

When comparing the structures of aniline and diethylamine, we can see that aniline has a phenyl ring attached to the nitrogen atom, while diethylamine has two ethyl groups attached to the nitrogen atom. The phenyl ring is an electron-withdrawing group due to its delocalized pi-electron system, which attracts electron density away from the nitrogen atom. This decreases the electron density on the nitrogen atom, making it less nucleophilic. In contrast, the ethyl groups in diethylamine are electron-donating groups, which increase the electron density on the nitrogen atom, making it more nucleophilic.

Therefore, the presence of an electron-withdrawing group in aniline makes it a poorer nucleophile than diethylamine, which does not have any electron-withdrawing groups. This demonstrates the importance of understanding the electronic properties of molecules and how they influence their reactivity in organic chemistry.

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