what is the mass % of carbon in dimethylsulfoxide?

Answer:

1533.6 kg NO

Explanation:

The reaction that takes place is:

First we convert the masses of ammonia (NH₃) and oxygen gas (O₂) into moles, using their respective molar masses:

77.5 kmol of O₂ would react completely with (77.5 kmol O₂ * \(\frac{4kmolNH_3}{5kmolO_2}\)) 62 kmol of NH₃. There are not as many kmol of NH₃, so NH₃ is the limiting reactant.

Now we calculate how many kmol of NO are produced, using the limiting reactant moles:

Finally we convert kmol of NO to mass, using its molar mass:

From the first equation, the mole ratio of NaOH to  \(H_2\) is 2:1.

39.3 g of NaOH = 39.3/40 = 0.98 mol

The equivalent mole of  \(H_2\) = 09.8/2 = 0.49 mol

1 mol of gas at STP = 22.4 L

0.49 mol = 0.49 x 22.4 = 10.98 L of \(H_2\)

From the second equation, the mole ratio of \(SnO_2\) and water is 1:2.

57.6 g of \(SnO_2\) = 57.6/150.7 = 0.38 mol

Equivalent mole of water = 0.38 x 2 = 0.76 mol

0.76 mol of water = 0.76 x 18 = 13.68 grams of water.

For the third equation, the mole ratio of propane and oxygen for a complete combustion reaction is 1:5. This can be converted to a volume ratio.

Thus, with 0.828 L of propane, the equivalent volume of oxygen required for complete combustion would be:

0.828 x 5 = 4.14 L

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Answer:

Because heat flows from warmer objects to cooler objects

Explanation:

Option 3 accurately represents the essence of an ethogram as an inventory of species-specific behaviors.

An ethogram can be best described as an inventory of the behavior of a particular species. It is a systematic catalog or list of behaviors exhibited by a specific animal species.

An ethogram provides a comprehensive overview of the behaviors displayed by the animals under study, documenting various activities, actions, and patterns of behavior.

While options 1 and 2 are related to visual representations or descriptions of behavior, they do not capture the comprehensive nature of an ethogram. Option 4 refers specifically to behaviors observed in response to an experimental intervention, which is more narrow in scope compared to an ethogram. Therefore, option 3 accurately represents the essence of an ethogram as an inventory of species-specific behaviors.

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Atomic orbitals are the areas to the left and right of the dashed lines. The possible molecular orbitals that they can form are indicated by the dashed lines.

Normally, in diatomic molecular orbitals, the atomic orbitals with the closest energy level can overlap with each other and form molecular orbitals. Therefore, the atomic orbitals generally tend to overlap one by one from the lowest potential energy to the highest potential energy. For example, in a homonuclear diatomic molecule, which means that both atoms are the same element, the same orbitals will overlap together and form molecular orbitals.

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Answer:

They are fossil fuels because they were formed because of fossilized remains of animals and plants that lived many years ago. They also have a high carbon content.

Answer:

Question One:

A kitchen recipe and a chemical equation are similar in that both involve the combination of specific ingredients in a specific manner to produce a desired outcome. However, there are some key differences between the two.

In a kitchen recipe, the ingredients are usually listed in a descriptive, qualitative manner, often with rough measurements (e.g. "one cup of sugar"). The recipe may also include instructions for preparation, such as cooking or mixing, that are not included in a chemical equation.

A chemical equation, on the other hand, represents a chemical reaction using quantitative, symbolic representations of the reactants and products. The reactants are listed on the left-hand side of the equation and the products on the right-hand side. The coefficients in a chemical equation indicate the number of molecules or moles of each substance participating in the reaction.

Overall, a kitchen recipe and a chemical equation both serve as guides for a process that involves the combination of ingredients, but the nature of the information and the type of outcome being described are different.

Question Two:

Balancing an equation could not directly apply to a kitchen recipe. A kitchen recipe does not have the same level of precision or quantitative detail as a chemical equation. Additionally, a kitchen recipe is more focused on taste and appearance, whereas a chemical equation must be balanced in terms of mass and charge to accurately represent the reaction. While the principles of measuring and combining ingredients in a recipe may be similar to balancing an equation, the end goals and criteria for success are quite different.

Explanation:

1. Both a kitchen recipe and a chemical equation provide a sequential set of instructions that guide the process to achieve a specific result, but while a recipe guides the preparation of food with descriptive language, a chemical equation represents a chemical reaction using chemical symbols and formulas.

2. Balancing an equation does not apply to a kitchen recipe because recipes focus on taste and presentation, allowing flexibility and adaptation.

1. A kitchen recipe and a chemical equation share some similarities but also have distinct differences. Both involve a set of instructions or steps to produce a desired outcome, but they serve different purposes and use different language and symbols.

Similarities:

a) Both a kitchen recipe and a chemical equation provide a sequential set of instructions that guide the process to achieve a specific result.

b) Ingredients/Reactants: In both cases, there is a list of ingredients (in a recipe) or reactants (in a chemical equation) that are combined to produce the final product.

Differences:

a) Purpose: The primary purpose of a kitchen recipe is to guide the preparation of food, focusing on taste, texture, and presentation. On the other hand, a chemical equation's purpose is to represent a chemical reaction, focusing on the transformation of reactants into products and the conservation of mass and charge.

b) Language and Symbols: Kitchen recipes typically use descriptive language, measurements (cups, teaspoons, etc.), and cooking times, whereas chemical equations use chemical symbols and formulas to represent elements and compounds, along with coefficients to balance the equation.

2. Balancing an equation, as it is done in chemical reactions, is not applicable to kitchen recipes. The concept of balancing an equation is specific to chemical reactions and is based on the fundamental laws of conservation of mass and charge.

In kitchen recipes do not involve chemical reactions, and there are no strict conservation laws to follow. The focus of a recipe is to create a dish with a specific taste, texture, and presentation, rather than ensuring the conservation of mass or other chemical properties.

Recipes are designed to be flexible, allowing adjustments based on personal preferences, dietary restrictions, and ingredient availability. Balancing a kitchen recipe, as in a chemical equation, would not have any meaningful significance or practical application in the culinary context. Instead, recipes are intended to be adaptable and creative, leaving room for individual tastes and culinary experimentation.

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Answer: A! The soup will become saltier because evaporation removes the water and leaves the salt behind.

Explanation:

Just finished the test and got a 90%! <3

Answer:

A

Explanation:

Answer:The answer is potassium.

The ΔHf° (heat of formation) for acetic acid is approximately -1119.29 kJ/mole.

To find the ΔHf° (heat of formation) for acetic acid (HC₂H₃O₂), use Hess's Law and the given thermochemical data.

The given equation for the combustion of acetic acid is:

HC₂H₃O₂(l) + 2O₂(g) → 2CO₂(g) + 2H₂O(l) ΔH = -875 kJ/mole

The formation of carbon dioxide (CO₂):

C(s) + O₂(g) → CO₂(g) ΔH = -394.51 kJ/mole

The formation of water (H₂O):

H₂(g) + 1/2O₂(g) → H₂O(l) ΔH = -285.8 kJ/mole

Now, rearrange these reactions to obtain the formation reaction for acetic acid:

HC₂H₃O₂(l) = C(s) + 2H₂(g) + 1/2O₂(g)

Adding the enthalpy changes of the individual reactions:

ΔHf° (acetic acid) = ΣΔHf° (products) - ΣΔHf° (reactants)

ΔHf° (acetic acid) = [2ΔHf° (CO₂)] + [2ΔHf° (H₂O)] - [ΔHf° (C)] - [ΔHf° (H₂)] - [1/2ΔHf° (O₂)]

Substituting the values from the given thermochemical data:

ΔHf° (acetic acid) = [2(-394.51 kJ/mole)] + [2(-285.8 kJ/mole)] - [0 kJ/mole] - [0 kJ/mole] - [1/2(-875 kJ/mole)]

Calculating the expression:

ΔHf° (acetic acid) ≈ -1119.29 kJ/mole

Therefore, the ΔHf° (heat of formation) for acetic acid is approximately -1119.29 kJ/mole.

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Answer:

True

Explanation:

Answer:

True

Explanation:

A neutral atom must have an equal amount of protons as electrons.  

Superheating the steam to a higher temperature improves the cycle efficiency.

Superheating the steam to a higher temperature in a simple ideal Rankine cycle improves the cycle efficiency. In a Rankine cycle, the working fluid undergoes four processes: expansion in a turbine, condensation in a condenser, pumping to increase pressure, and heating in a boiler. The cycle efficiency depends on the temperature at which heat is added to the working fluid (boiler temperature) and the temperature at which heat is rejected (condenser temperature). By superheating the steam to a higher temperature before it enters the turbine, the temperature difference between the boiler and the condenser increases. This leads to an improvement in the cycle efficiency.

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Warmth and mοisture are indeed the primary factοrs that cοntribute tο micrοbial grοwth in mοst buildings.

The humidity in the atmοsphere is called mοisture. The prοpοrtiοn οf mοisture in the atmοsphere depends οn the temperature. Air with higher temperature hοlds a greater amοunt οf mοisture.

Dampness, in particular, creates a favοrable envirοnment fοr fungi tο thrive. Micrοbes, like all living οrganisms, require water tο survive and carry οut their metabοlic prοcesses.

In additiοn tο warmth and mοisture, pH levels and οxygen levels alsο play significant rοles in micrοbial grοwth. Different micrοοrganisms have different pH preferences, and extreme pH cοnditiοns can inhibit their grοwth. Similarly, οxygen availability οr the absence thereοf can determine the types οf micrοbes that can thrive in a given envirοnment.

Understanding these physical and chemical factοrs is crucial fοr managing micrοbial grοwth in buildings, as cοntrοlling mοisture levels and maintaining apprοpriate cοnditiοns can help prevent the prοliferatiοn οf harmful micrοοrganisms and minimize pοtential health risks.

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The volume occupy at 415K and 12.3atm is 37.25ml.

Ideal gas:

An ideal gas is a theoretical gas composed of many randomly moving point particles that are not subject to interparticle interactions. It is one for which both the volume of molecules and forces between the molecules are so small that they have no effect on the behavior of the gas.

Here we have to find the volume occupied.

The formula for an ideal gas:

P1 V1 / T1 = P2 V2 / T2

V2 = P1 V1 T2 / T1 P2

P1 = 14.8atm

P2 = 12.3atm

V1 = 23.5 ml

T1 = 315K

T2 = 415K

Now putting these values in the equation we get:

V2 = (14.8× 23.5 × 415)/ ( 12.3 × 315)

     = 144,337 / 3874.5

    = 37.25 ml

Therefore the 37.25ml is the volume.

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Answer:

The answer is 46.0055. We assume you are converting between grams NO2 and mole. You can view more details on each measurement unit: molecular weight of NO2 or mol This compound is also known as Nitrogen Dioxide.

Explanation:

hope this helps

518.5 atm pressure of hydrogen is needed to maintain a \(H_2\) concentration of 0.42 m

The given Henry's law constant for \(H_2\) is 8.1 × 10^-4 M atm^-1 at 25°C. To find the pressure of hydrogen needed to maintain a \(H_2\) concentration of 0.42 M, we can use Henry's law.

The equation for Henry's law is:

C = kH*P

where C is the concentration of gas in moles per liter, P is the partial pressure of the gas in atmospheres, and kH is Henry's law constant in M/atm.

Plugging the values in Henry's law equation, we get:

0.42 = (8.1 × 10^-4)P

Dividing both sides by (8.1 × 10^-4), we get:

P = (0.42)/(8.1 × 10^-4)

P = 518.5 atm

Hence, the pressure of hydrogen needed to maintain a \(H_2\) concentration of 0.42 M is 518.5 atm.

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Answer:

3m/s²

Explanation:

Force applied to an object can be calculated thus;

F = ma

Where;

F = force applied (Newtons)

m = mass of substance (kg)

a = acceleration (m/s²)

According to the information provided in this question, F = 12.0 newtons, m = 4.0 kg, a = ?

Derived from F = m.a

We have; a = F/m

a = 12/4

a = 3

The resultant acceleration of the object is 3m/s².

2.56 moles of HCl are required to react with 0.64 moles of KMnO4.

The balanced chemical equation is given as;2KMnO4 + 8HCl → 3Cl2 + 2MnO2 + 4H2O + 2KCl.This equation is balanced in such a way that 2 moles of KMnO4 reacts with 8 moles of HCl to produce 3 moles of Cl2, 2 moles of MnO2, 4 moles of H2O and 2 moles of KCl.We are given the number of moles of KMnO4 as 0.64 moles.Now, we can use stoichiometry to find the number of moles of HCl required to react with 0.64 moles of KMnO4.The balanced chemical equation shows that 8 moles of HCl reacts with 2 moles of KMnO4.

So, one mole of KMnO4 would react with 8/2 = 4 moles of HCl.Now, the number of moles of HCl required to react with 0.64 moles of KMnO4 would be;Moles of HCl = Moles of KMnO4 x (Moles of HCl / Moles of KMnO4) Moles of HCl = 0.64 x 4 = 2.56 moles of HCl.

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Answer:

Argon is a chemical element with the symbol Ar and atomic number 18.

Explanation:

Answer:

Avogadro's number is a very important relationshiptoremember: 1 mole = 6.022×1023 6.022 × 1023atoms, molecules, protons, etc.

...

Explanation:

jayfeather friend me

Answer:

1st one: carbon dioxide

2nd: Glucose

3rd: Oxygen

4th: Energy

Sorry if this is wrong because I don't see the options!

Hope this helps!

The process of heating a solid fuel so that it liberates gaseous fuel vapors is called B. Pyrolysis.

Pyrolysis is a chemical process in which a substance is decomposed by heat in the absence of oxygen or with limited oxygen. This process involves the thermal decomposition of organic material at elevated temperatures in the absence of oxygen.

Pyrolysis is used to convert solid fuels, such as coal, into gaseous fuels, such as methane and hydrogen. The resulting gaseous fuels can then be used for energy production or other industrial processes.

Therefore, the correct answer is option B. Pyrolysis.

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Answer:

1 cl =10 ml

so

4.22cL= 4.22×10= 42.2 mL

the pH of a 0.000125 M HBr solution is 3.90. The pH of a diluted 175 mL 0.000125 M HBr solution in a total volume of 3.00 L is 2.22. Calculate the pH of a 0.000125 M HBr solution. The dissociation of HBr can be written as follows: HBr ⇌ H+ + Br-

The pH of a 0.000125 M HBr solution is 3.90. The pH of a diluted 175 mL 0.000125 M HBr solution in a total volume of 3.00 L is 2.22.

Solution:

Calculate the pH of a 0.000125 M HBr solution

The dissociation of HBr can be written as follows: HBr ⇌ H+ + Br-

According to the law of mass action, the equilibrium expression for the dissociation of HBr can be written as follows:

[H+][Br-] / [HBr] = k [H+][Br-] = k[HBr]

Here, k is the dissociation constant of HBr, which is 8.7 × 10^-10.

[H+][Br-] = (8.7 × 10^-10)[HBr]

M = [H+]; M = [Br-]

M = 0.000125 M, so [H+] = [Br-] = 0.000125 M

[H+] = 0.000125 M

The pH of a solution is defined as follows:

pH = -log[H+]

pH = -log[0.000125]

pH = 3.90

What is the pH of the diluted solution if 175 mL of this solution is diluted to a total volume of 3.00 L?

To solve this problem, we'll use the following formula: M1V1 = M2V2

M1 = 0.000125 M

M2 = ?

V1 = 175 mL

V2 = 3000 mL = 3.00 L

Before we begin, we'll convert the volume to liters.

175 mL ÷ 1000 = 0.175 L

Now, we can solve for M2: M1V1 = M2V2

(0.000125 M)(0.175 L) = M2(3.00 L)

M2 = 0.00000729 M

The pH of this solution can now be calculated: pH = -log[M2]

pH = -log[0.00000729]

pH = 2.22

Answer: So, the pH of a 0.000125 M HBr solution is 3.90. The pH of a diluted 175 mL 0.000125 M HBr solution in a total volume of 3.00 L is 2.22.

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The number of moles of the cyclopropane that remains after 1.00 s is  6.1 * 10^-4 M.

By the use of the equation of the first order reaction, we can be able to find out the concentration at a given time.

The equation of the first order reaction can be written as;

ln[A] = ln[Ao] - kt

[A] = Concentration at time t

[Ao] = Initial concentration

k = rate constant

t = time

Then;

[A] = e^ln[Ao] - kt

[A] = e^ln6.00 - (9.2 * 1)

[A] = 6.1 * 10^-4 M

The amount of the cyclopropane left is  6.1 * 10^-4 M.

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Answer: Neil Armstrong

Explanation

On July 20, 1969, Neil Armstrong became the first human to step on the moon. He and Aldrin walked around for three hours. They did experiments. They picked up bits of moon dirt and rocksExplanation:

Answer:

In 1969, Neil Armstrong was the first person to reach the moon.

Explanation:

Answer:

Homeostasis, as currently defined, is a self-regulating process by which biological systems maintain stability while adjusting to changing external conditions.

Explanation:

Answer:

2

Explanation:

The least number of significant figures in any term is 2.

Each crew member receives three wholesome meals daily along with snacks. The food for each astronaut is kept onboard the Shuttle and is given a unique color dot to identify it.

This is further explained below.

Generally, Being bigger than only Mercury, Mars is the second-smallest planet in the Solar System and is located four planets from the Sun. The Roman god of battle is the inspiration for the name of Mars in English.

It provides each member of the crew with three meals that are well-balanced, in addition to snacks. On board the Space Shuttle is where all of the astronauts' food is kept, and each individual box has a colorful dot that identifies it.

In conclusion, For example, traveling to Mars and returning may take more than three years and need the supply of thousands of kg of food. If the crew of four were to consume merely three meals per day while on their three-year voyage to Mars, they would need to bring more than 24,000 pounds (10,886 kilograms) of food with them.

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