What is the linear diameter (in meters) of an object that has an angular diameter of 110 arcseconds and a distance of 25,000 m?

Explanation:

, the net force will be felt on particle approximately 15.39 N to the right.

Answer:

i say it would be 32.5 m if the brakes comes and stops.  the road is 3.7 x 105

Explanation:

The power wasted in the transmission line connecting the power house to the consumer is 2kW.

The equation Power = Potential difference*Current, or P = VI, can be used to compute the amount of energy that is wasted.

We can see that it is given,

V1 = 600 V

V2 = 580 V

Current= I = 100 A

We need to figure out how much energy is lost in the transmission line that runs from the generator to the consumer.

In physics, power is the amount of energy that is transferred or transformed in a given amount of time.

The International System of Units uses the watt, or one joule per second, as the unit of power.

The formula for the voltage across the transmission line is V = V1 - V2.

Thus, V = 600 - 580

V = 20V

We've been told that I equals 100 A.

The power loss equation is given by P = VI, where V is the potential difference and I is the current.

Power loss = VI, therefore becomes

P = 20 × 100

P = 2000 W

P = 2kW

Therefore, 2 kW of power is lost in the transmission line that connects the power source to the customer.

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The option that  would increase the mechanical advantage of a lever is option A. Moving the fulcrum closer to the output force.

Mechanical advantage quantifies a lever's effectiveness (how easy it is to lift the load). - When compared to the distance between the load (resistance) and the fulcrum, the advantage relies on the distance between the effort and the latter (effort arm) (resistance arm).

Note that in Levers of Class 1:

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Answer: its a

Explanation: hope this help im sorry if its wrong

Answer:

NO 21 days wouldn't be enough because it takes at least one month to observe all of the moon's phases.

Explanation:

Hope this helps!!

Answer:

They are separated by a distance of 18 m. Find the gravitational attraction between them. r= 1 m r= 1 m 18 m. Mass = 1.5 kg. Mass = 8.5 kg.

Answer:

4.2 x 10⁵kg

Explanation:

Given parameters:

Speed of orbit  = 7660m/s

Kinetic energy  = 1.24 x 10¹³J

Unknown:

Mass  = ?

Solution:

Kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;

       K.E  = \(\frac{1}{2}\)mv²

m is the mass

v is speed

Now insert the parameters and find the mass;

   1.24 x 10¹³   =  \(\frac{1}{2}\) x m x 7660²  

   1.24 x 10¹³  = 2.93 x 10⁷m

  m  = \(\frac{1.24 x 10^{13} }{2.93 x 10^{7} }\)   = 0.42 x 10⁶kg = 4.2 x 10⁵kg

The wavelength of this radio signal is equal to 3.18 meters.

Given the following data:

Wavelength can be defined as the distance between two (2) successive crests (troughs) of a wave.

Mathematically, the wavelength of a wave is given by this formula:

\(\lambda = \frac{V}{F}\)

Where:

Substituting the given parameters into the formula, we have;

\(\lambda = \frac{3 \times 10^8}{9.45 \times10^7}\)

Wavelength = 3.18 meters.

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The wavelength of the radio signal travel at speed of light is 3.17m.

Given the data in the question;

Wavelength the spatial period of a periodic wave. That is to say, when the shapes of waves are Wavelength , the distance over which they are repeated is called wavelength. Wavelength  is expressed as;

\(\lambda = \frac{v}{f}\)

Where \(\lambda\) is wavelength, f is the frequency of the wave and c is the velocity or speed of light ( \(c = 3*10^8m/s\) )

We substitute our values into the expression above.

\(\lambda = \frac{c}{ f}\\ \\\lambda = \frac{3*10^8m/s}{9.45*10^7s^{-1}} \\\\\lambda = \frac{3*10^8ms/s}{9.45*10^7}\\\\\lambda = 3.17m\)

Therefore, the wavelength of the radio signal travel at speed of light is 3.17m.

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Answer:

 y = 0.1 m

Explanation:

The electrical power for point loads is

         V = \(k \sum \frac{q_i}{r_i}\)k Sum qi / ri

in this case

         V = k (\(- \frac{q_1}{r_1 } + \frac{q_2}{r_2}\))

indicate that V = 0

        \(\frac{q_1}{r_1} = \frac{q_2}{r_2}\)

        r₂ = \(\frac{q_2}{q_1} r_1\)

the distance r1 is

         r₁ = y -0

the distance r2

         r₂ = 0.14 -y

we substitute

        0.14 - y = \(\frac{10}{25}\)  y

          y ( \(\frac{10}{25} + 1\)) = 0.14

          y 1.4 = 0.14

          y = 0.14 / 1.4

          y = 0.1 m

The factors that affect the viscosity of magma include temperature, crystal and rock fragments (composition), and the different dissolved gases.

It is a mixture of solid, volatile and liquid materials.

Therefore, we can conclude that the fluidity or viscosity of magma depends on its chemical composition and, in particular, the liquids and solids that the magma contains and the various gases dissolved in it.

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Answer:

C because it literally in Australia but the pfp tho

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Given:

The negative charge q1 = 0.3 C

The positive charge q2 = 0.5 C

The distance between the charges is 0.4 m

To find the magnitude of the force between them.

Explanation:

The formula to calculate the magnitude of the force is

Here, k is Coulomb's constant whose value is

On substituting the values, the magnitude of force will be

Final Answer: The magnitude of the force is 8.4375 x 10^(9) N.

The speed of the wave that is propagated is 10 meters per second.

A wave is a disturbance or variation that gradually conducts electricity from point to point in a medium and can take the form of elastic deformation or a change in pressure, electric or magnetic intensity, electric potential, or temperature

The speed of a wave is determined by the frequency of the wave and its wavelength. In this case, the child is sending pulses down the rope at a rate of 2 pulses per second, so the frequency is f = 2 Hz.

The distance between the pulses is 5 meters, which is the wavelength of the wave, represented by lambda (λ).

The speed of the wave (v) is given by the formula:

v = f * λ

Substituting the values we have, we get:

v = 2 Hz * 5 m = 10 m/s

Therefore, the speed of the wave is 10 meters per second.

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V= IR

160 = I × 2

80 A = I = current

Answer:

80 A

Explanation:

by ohm's law, resistance is equal to the change in voltage over the current so if we plug and solve for current we get I = (160V)/(2V/A)= 80 A

A cesium-133 atom's radiation goes through 1.5 million cycles in around 0.1633 microseconds (or 163.3 nanoseconds).

9,192,631,770 hertz (cycles per second) is the frequency of the microwave spectral line that the isotope cesium-133 emits. The basic unit of time is provided by this. Cesium clocks have an accuracy and stability of 1 second in 1.4 million years.

The radiation emitted by cesium-133 has a frequency of 9,192,631,770 cycles per second, or 9.192631770 109 Hz.

The following formula may be used to determine how long 1.5 million radiation cycles take to complete:

Time is equal to the frequency of cycles.

Plugging in the numbers, we get:

time = 1.5 million / 9.192631770 × 10^9 Hz

time = 1.632995101 × 10^-7 seconds

So it takes approximately 0.1633 microseconds (or 163.3 nanoseconds) for radiation from a cesium-133 atom to complete 1.5 million cycles.

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Answer:

2.2m/s

Explanation:

a=v-u/t

12.5-2.5/4.5=2.222

~2.2m/s

Answer:

Ramp

Explanation:

All of the other things are fairly complex, bikes have to be made with multiple parts so do cars and steering wheels are another part of a boat, a ramp usually consists of two or fewer parts making it the simplest.

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

Explanation:

Given that,

Current, I = 0.015 A

Voltage, V = 240 volts

We need to find the resistance. Using Ohm's law we can find it as follows :

\(V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{240}{0.015}\\\\R=16000\ \Omega\)

So, When a current of 0.015 A passes through human body at 240 volts p.d it  causes​  16000 ohms of resistance.

The given graph is about velocity and time, the dependent and independent variable, respectively. As we can observe, line E crosses the zero level to the negative zone, which means the object didn't stop but changed its direction.

The charge on the ball developed will be  1.78 x 10⁻⁷ Coulomb.

The field developed when a charge is moved. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of charge,

Given is an electric field E = 100,000i N/C causes the 5.0 g point charge to hang at a 20° angle.

If T is the tension and θ is the angle, then

The force in  x direction Fx = T sinθ

Force in y direction Fy = T cosθ = mg

Dividing both the equation, we have

tan θ = qE /mg

Substitute the given values in the question, we have

q = 5 x10⁻³ x 9.81 x tan 20 /100000

q = 1.78 x 10⁻⁷ Coulomb.

Thus, the charge of ball is  1.78 x 10⁻⁷ Coulomb.

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A 1.0 kg block is pushed 20 m at a constant velocity up a vertical wall by a constant force applied at an angle of 26.0° with the horizontal.The acceleration of gravity is 9.81 m/s². Thus, calculated values are:

a)  the work done by the force on the block: 19.62 J

b)  the work done by gravity on the block: -19.62 J

c) the magnitude of the normal force between the block and the wall:  17.7 N

Anything that causes a change in velocity is referred to as an acceleration. You can only accelerate by changing the speed, direction, or both as velocity is a function of both speed and direction.

let m = 1.0 kg

d = 2.0 m

θ = 29°

let, F is the applied force.

let, Fx and Fy are components of F.

As the block is moving upward with constant velocity, net force acting on the block must be zero.

F×nety = 0

or, Fy - m×g = 0

or, Fy = m×g

or, Fy = 1×9.81 N

or, Fy = 9.81 N

a) The work done by the force on the block, WF = Fy×d×cos(0°)

= (9.81×2) J

= 19.62 J

b) The work done by gravity, Wg = Fg×d×cos(180°)

= 1 ×9.81×2×(-1)

= -19.62 J

c) we know, Fy = F×sin(29°)

Fx = F×cos(29°)

Fy/Fx = tan(29°)

Fx = Fy/tan(29°)

Fx = 9.81/tan(29)

Fx = 17.7 N

now use, Fnetx = 0

or, Fx - N = 0

or, N = Fx

or, N = 17.7 N

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Positive changes in the ball's total energy show that additional energy from outside the system was used to raise the ball and propel it into the basket.

If energy is conserved, the sum of an object's kinetic, gravitational potential, and heat energy—among others—might change forms as it moves about over time.

The ball's kinetic energy and potential energy combine to make its total energy:

E_total = U + K

Its initial potential energy is given by:

U_i = mgh = 2kg x 9.8m/s² x 0m = 0J

The amount of work done is equal to the ball's change in potential energy:

W = U_f - U_i

where U f is the ball's ultimate potential energy.

The ball's final potential energy is determined by:

U_f = mgh = 2kg x 9.8m/s² x 2.5m = 49J

As a result, the ball's work is as follows:

W = U_f - U_i = 49J - 0J = 49J

The ball's final kinetic energy is determined by:

K_f = 0.5mv^2

where v represents the ball's final speed.

Inputting the values provided yields:

K_f = 0.5 x 2kg x (3m/s)² = 9J

As a result, the ball's final total energy is as follows:

E_f = U_f + K_f = 49J + 9J = 58J

The change in total energy of the ball is:

ΔE = E_f - E_i = 58J - 0J = 58J

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Answer:

Explanation:

To solve for the mass of the football player, we can use the conservation of momentum principle, which states that the total momentum before a collision is equal to the total momentum after the collision. Assuming the collision is perfectly elastic, we have:

m1 * v1 + m2 * v2 = m1 * v1' + m2 * v2'

where m1 is the mass of the football player, v1 is the initial velocity of the football player, m2 is the mass of the referee, v2 is the initial velocity of the referee, v1' is the final velocity of the football player, and v2' is the final velocity of the referee.

Since the referee is at rest before the collision, we can set v2 = 0. Plugging in the given values, we get:

m1 * 8 + m2 * 0 = m1 * (-8) + m2 * 5

Expanding and solving for m1:

8m1 = -8m1 + 80

16m1 = 80

m1 = 5 kg

So, the mass of the football player is 5 kg.

Answer:

The velocity of the center of mass of the two-ball system is 13.1 m/s.

Explanation:

Given;

mass of the first ball, m₁ = 0.5 kg

mass of the second ball, m₂ = 0.25 kg

initial velocity of the second ball, u₂ = 19.6 m/s

At the highest point the velocity of the second ball, v₂ = 0

The highest point reached by the second ball is calculated as;

v₂² = u₂² - 2gh

0 = u₂² - 2gh

2gh = u₂²

h = u₂² / 2g

h = (19.6²) / (2 x 9.8)

h = 19.6 m

The final velocity of the first ball when it had traveled 19.6 m down;

v₁² = u₁² + 2gh

v₁² = 0 + 2gh

v₁ = √2gh

v₁ = √(2 x 9.8 x 19.6)

v₁ = 19.6 m/s

The velocity of the center of mass of the two-ball system is calculated as;

\(v = \frac{m_1v_1 \ + \ m_2v_2}{m_1 \ + \ m_2} \\\\v = \frac{0.5\times 19.6 \ + \ 0.25\times 0}{0.5 \ + \ 0.25} \\\\v = 13.1 \ m/s\)

Answer:

If the athlete speeds up between 2 points there is an increase of the athlete's "kinetic" energy

I guess this would imply a decrease in the athlete's chemical energy because the energy has to originate somewhere

(PLEASE GIVE BRIANLIEST)

The average speed is not equal to the sum of the speeds divided by 2 because the car takes different times to cover the distance while going up and coming down the hill.

The average speed can be calculated as the total distance covered divided by the total time taken. As the speeds are constant, we can use the formula:

distance = speed * time

Let the distance traveled be "d". The time taken to go up the hill is "t1" and the time taken to come down is "t2".

d = 35 * t1 = 69 * t2

The total time taken for the round trip is t1 + t2.

The average speed is given by:

average speed = d / (t1 + t2) = d / (d/35 + d/69)

So the average speed can be calculated as follows:

average speed = d / (d/35 + d/69) = d * (35 + 69) / (35 * 69) = 104 / 2445 = 8 / 205 km/h