What is the length of a segment with endpoints at (-3,4) and (4,4)

Answer: The answer would be 4

Step-by-step explanation:

Subsitute the variables with the number given so in This case it would be

(2(4)+2^3)/-2(-2)

Use orders of Operations

Solve parenthesis first.

8+8/-2(-2)

16/4

Divide

4

Answer:

C.14ײ+5

Step-by-step explanation:

Hope It Help

Brainliest please

The 2nd one or either the last one, I suggest the last one hope this helps!!

One triangles can be made with these conditions.

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Answer:

about $1.67

Step-by-step explanation:

Divide.

\(\frac{20}{12}\) = about $1.67

You can check your answer by multiplying:

1.67 x 12 = about 20

Answer:

32

Step-by-step explanation:

12 + 4y

Evaluate the expression when y = 5.

12 + 4(5)

12 + 20

32

Answer:

32

Step-by-step explanation:

Answer:

She put in $7.50

Step-by-step explanation:

Randomly selecting 50 out of 200 campers at Leonard's camp to count the number of pencils in their backpacks is likely to give a reasonably accurate estimate of the mean number of pencils carried by campers at his camp, assuming the selection process is truly random and representative of the overall camp population.

Leonard's approach of randomly selecting 50 campers out of the 200 campers at his camp to estimate the mean number of pencils they carry in their backpacks is a reasonable sampling method.

However, the accuracy of the estimate depends on certain assumptions and conditions.

One important consideration is the representativeness of the selected sample.

If the 50 campers are truly chosen randomly and without bias, meaning that every camper has an equal chance of being selected, then the sample is likely to be representative of the larger population of campers. This assumes that there are no specific factors that could significantly affect the number of pencils in a camper's backpack and that the campers in the selected sample are similar to those not included.

The accuracy of the estimate also depends on the variability within the population.

If the number of pencils carried by campers in their backpacks varies greatly, then a larger sample size might be needed to obtain a more accurate estimate.

However, if there is relatively low variability in the number of pencils, a smaller sample size can still provide a reasonable estimate.

It's worth noting that there is always a margin of error associated with any sample-based estimate.

The accuracy of the estimate can be quantified by calculating a confidence interval, which provides a range within which the true population mean is likely to fall.

In conclusion, while Leonard's method of randomly selecting 50 campers can provide a reasonable estimate of the mean number of pencils carried in their backpacks, the accuracy of the estimate depends on the representativeness of the sample and the variability within the population.

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Given:

The lightsaber is filled with full of confetti.

The lightsaber:

The confetti bag is 10oz.

To find:

The number of bags of confetti.

Explanation:

The radius of the lightsaber is,

The volume of the lightsaber is,

In oz,

So, the number of bags will be,

The number of bags required is 8.

Final answer:

The volume of the lightsaber is 81.66 ounces.

The number of bags required is 8.

Each of the individual data items in a "structure" or single unit is an entity by itself that is referred to as a "member" or "field."

In programming or computer science, a "structure" is a data type that allows combining different data items of different types into a single unit. Each of these individual data items within the structure is called a "member" or "field." Each member represents a distinct piece of information within the structure and can have its own data type and value. The members of a structure can be accessed and manipulated individually, allowing for organized and efficient handling of related data.

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Answer:

A dilation always produces a similar figure. Similar figures have the same shape but different sizes.

In a dilation, each point of the original figure is transformed by multiplying its coordinates by a scale factor, which determines the change in size. However, the shape and proportions of the figure remain unchanged. Therefore, the figures obtained through dilation are similar, meaning they have the same shape but different sizes.

Answer:

x=1

Step-by-step explanation:

since the other side is 12 and both sides are even, the right side would be 12 as well

13(1)-1=12

Answer:

x=1

Step-by-step explanation:

I'm not completely sure I'm correct but if 12 and 13x-1 are equal, then try different numbers for x until you find the number that makes 13x-1 equal 12. For example: If x=0, 13(0)-1 equals -1.

if x=1, 13(1)-1 equals 12.

Therefore, x is 1.

Answer:

The speed of the slower train is 60km/hr or 80km/hr and the speed of the faster train is 70km/hr or 90km/hr.

       For C1(Q) = 3 - 2Q.

        For C2(Q) =  4.

     2. The AVC function

           For C1(Q) = 5/Q + 3 + 20/Q - Q.

           For C2(Q) = 3/Q + 4 + 2/Q.

     3. The AFC function

              For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)

              For C2(Q) = 0.

     4.  To find the AC function

        For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

         For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

    5.To find the ATC function

    For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)

     For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

1. To find the MC function, we take the derivative of the cost functions with respect to Q.

For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.

For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.

2. To find the AVC function, we divide the cost functions by Q.

For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.

For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.

3. To find the AFC function, we subtract the AVC function from the ATC function.

For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)

= 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.

4. To find the AC function, we add the AVC function to the AFC function.

For

C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

5. To find the ATC function, we divide the AC function by Q.

For

C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q

= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).

For

C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q

= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

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Answer:

1200 square inches

Step-by-step explanation:

First find area of rectangle which is length x width

20 x 30 = 600

then to find area of the two right triangles multiply the legs then divide by 2

20 x 30 = 600

600/2 = 300

since there is 2 multiply 300 by 2

600

then add everything together

600+600 = 1200

An inscribed angle is formed by two chords of a circle that intersect at a vertex located on the circle.

The angle itself is formed by the two sides of the angle, which are the line segments connecting the vertex to the endpoints of the chords. The property that makes inscribed angles interesting is that the measure of an inscribed angle is half the measure of the intercepted arc on the circle.

This relationship holds true for any inscribed angle in a circle, making it a useful concept in geometry for solving problems involving angles, arcs, and circles.

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A hypothesis that explains the difference between the weather on April 29, 2020, and May 11th is that there is a lower chance of precipitation in May due to the lower humidity and higher temperature in May.

We can test the hypothesis by collecting, analyzing and comparing data on precipitation, temperature, and humidity for both the months.

Based on the provided information, there are some differences between the weather of April 29, 2020, and May 11th. The difference is that April had a higher chance of precipitation than in May.

Hence, a hypothesis that would explain this observation would be that there is lower chance of precipitation in May because May is usually a warmer month with lower humidity.

To test this hypothesis, the following steps can be taken:

1. Collect the necessary data on precipitation, temperature, and humidity for April and May.

2. Analyze the data collected to compare the precipitation, temperature, and humidity of April and May.

3. If the data shows that May has a lower humidity than April, and that the temperature is higher, it can be inferred that this is what causes May to have a lower chance of precipitation than April.

Therefore, it can be concluded that a hypothesis that explains the difference between the weather on April 29, 2020, and May 11th is that there is a lower chance of precipitation in May due to the lower humidity and higher temperature in May.

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B. Function f has exactly two complex solutions.

The graph of the quadratic function is an equation of the variable that has the highest power of two. This function is related to quadratic equations. The general form of the quadratic equation is, a² + bx + c = 0.

The graph of the quadratic function in mathematics is characterized by f(x) = y which is the dependent variable, x is the independent variable, while a and b are coefficients called quadratic equations, which are quadratic equations, have a variable with the highest power of two and are in the form of an equation .

The general form of the quadratic equation is: where x is the independent variable, a and b are the coefficients, and c is a constant. A function is closely related to the graph of the function. So do quadratic functions, which have their own function graphs.

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Angle-Angle (AA) similarity postulate,  if two angles of one triangle are congruent to two angles of another, then the triangles are similar.

Similar triangles are the triangles that have corresponding sides in proportion to each other and corresponding angles equal to each other. Similar triangles look the same but the sizes can be different.

As per the diagram,

Triangles RPQ & RST are similar since

∠P = ∠S & ∠Q = ∠T

Side - side - side (SSS) similarity theorem - If the lengths of the corresponding sides of two triangles are proportional, then the triangles are similar.

Triangles RPQ & RST are similar since

RP/RS = RQ/RT = ST/PQ

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Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

We know that there's a probability of \(p=\frac{40}{50}=\frac{4}{5}=0.8\) of choosing an electronic component that is not defective and a probability of \(q=\frac{10}{50}=\frac{1}{5}=0.2\) of choosing an electronic component that is defective:

\(\displaystyle P(X\geq4)=P(X=4)+P(X=5)+P(X=6)\\\\P(X\geq4)=\binom{6}{4}(0.8)^4(1-0.8)^{6-4}+\binom{6}{5}(0.8)^5(1-0.8)^{6-5}+\binom{6}{6}(0.8)^6(1-0.8)^{6-6}\\\\P(X\geq4)=\frac{6!}{4!(6-4)!}(0.8)^4(0.2)^2+\frac{6!}{5!(6-5)!}(0.8)^5(0.2)^1+\frac{6!}{6!(6-6)!}(0.8)^6(0.2)^0\\ \\P(X\geq4)=0.90112\)

So, if 6 components are drawn at random from the container, the probability that at least 4 are not defective is 0.90112

Problem 2

\(\displaystyle P(X=3)=\binom{8}{3}(0.2)^3(1-0.2)^{8-3}\\\\P(X=3)=\frac{8!}{3!(8-3)!}(0.2)^3(0.8)^5\\ \\P(X=3)\approx0.1468\)

So, if 8 components are drawn at random from the container, the probability that exactly 3 are defective is 0.1468

The probability of exactly 3 of the containers being defective is given as 0.1468

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

here, we have,

to solve for the probability

We have to set p as the  probability of container being non- defective

We have p as the  probability of container being defective 50 - 10 = 40

p = 40/50

= 0.8

q = 10/50

= 0.2

P(3) = 8c3 * 0.2² * 0.8⁵

= 0.1468

Hence the probability that the container has exactly 3 defective containers is 0.1468

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Answer:

a. x = 2 , x = -5

b. no real roots

Step-by-step explanation:

a. x² + 3x – 10

= x² - 2x + 5x - 10

= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)

= (x - 2) (x + 5)

x - 2 = 0                            x + 5 = 0

 + 2    +2                             -5     -5

--------------                         ---------------

x = 2                                   x = -5

x = 2 , x = -5

b. 2x² - 4x + 3

This can't be solved because the equation has no real roots, and also the discriminant is negative.

The difference between the proportion registered to vote for ages 18 to 24 compared with those 25 to 34 is P(25 to 34)- P(18 to 24). We will do a one-tailed test. Use an alpha level of 05 unless otherwise instructed.

Data is given below:

Age Registered Not Registered Total 18 to 2458510925 to 34934714035 to 44963945 to 541164215855 to 61123314565 to 747319275 and over 551570 Total 603245849 Pooled Variance for this Hypothesis Test:

The formula for pooled variance is given by;

${S_p}^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{(n_1+n_2-2)}$

Where, n1 and n2 are the sample sizes for the 1st and 2nd samples, S1² and S2² are the variances for the 1st and 2nd samples respectively.

Substituting the values in the above formula, we get; ${S_p}^2=\frac{(109-1)S_1^2+(140-1)S_2^2}{(109+140-2)}$

For the Age group 18 to 24, Sample size (n1) = 109, Variance (S1²) = 0.4978.

For the Age group 25 to 34, Sample size (n2) = 140, Variance (S2²) = 0.5696.

Substituting the values, we get; ${S_p}^2=\frac{(108)(0.4978)+(139)(0.5696)}{(247)}$${S_p}^2=\frac{54.8424+79.12944}{247}$${S_p}^2=\frac{133.97184}{247}$Sp² = 0.5423 (approx.).Therefore, the Pooled Variance for this Hypothesis Test is 0.5423 (approx.). Now, considering the second part of the question; If a priori, we thought private schools should have a higher 6-year average graduation rate than public schools, the conclusion of the hypothesis test for this problem would be to reject the null hypothesis at alpha. The answer is 'alpha.'Therefore, the conclusion of the hypothesis test for this problem would be to reject the null hypothesis at alpha.

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Answer:

165.065% increase

Step-by-step explanation:

Answer:

1170

Step-by-step explanation:

Total Population = 900

Annual rate of increase = 30 % of 900

=> \(\frac{30}{100}*900\)

=> 30 * 9

=> 270

Population next Year = 900+270

=> 1170

2n^3 + 3n + 10 can be written as a polynomial of the form Q(n^3), where Q(n^3) represents the set of polynomials of the form a(n^3).

To prove that the expression 2n^3 + 3n + 10 is in the set Q(n^3), where Q(n^3) represents the set of polynomials of the form a(n^3), we need to show that the expression can be written in the form a(n^3) for some constant "a".

Let's start by factoring out the common factor of n^3 from each term:

2n^3 + 3n + 10 = n^3(2 + 3/n^2 + 10/n^3)

Now, let's rewrite the expression as a single term multiplied by n^3:

2n^3 + 3n + 10 = (2 + 3/n^2 + 10/n^3)n^3

Simplifying the expression inside the parentheses:

= (2n^3 + 3n^2 + 10n^3)/n^3

= (12n^3 + 3n^2)/n^3

= 12 + 3/n

ow, we can see that the expression can be written in the form a(n^3), where a = 12 and n^3 = 3/n.

Therefore, we have shown that 2n^3 + 3n + 10 can be written as a polynomial of the form Q(n^3), where Q(n^3) represents the set of polynomials of the form a(n^3).

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The weight of the melted ice cream would be the same as the weight of the original ice cream, which is 5 ounces.

a quantity or thing weighing a fixed and usually specified amount. : a heavy object (such as a metal ball) thrown, put, or lifted as an athletic exercise or contest. 3. : a unit of weight or mass see Metric System Table.

When the ice cream melts, it undergoes a change in state from solid to liquid, but the total mass or weight remains unchanged. Therefore, the weight of the melted ice cream is still 5 ounces.

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Answer: The answer is 16

Step-by-step explanation:

Answer:

It's 4+33-37 so that's the answer

Answer:

0

Step-by-step explanation:

........

Answer:

g=-10

Step-by-step explanation:

-g+2(3+g) = -4

-g+6+2g=-4

g=-4-6

g=-10