what is the Group II carbonate thermal stability pattern (same applies to nitrates but different products are formed)?

Answers

Answer 1

The Group II carbonate thermal stability pattern refers to the trend in which the carbonates of Group II elements (Be, Mg, Ca, Sr, Ba) become less stable as you move down the group. This is due to the increasing size of the cation, which leads to weaker bonding with the carbonate anion.

This means that heavier Group II metal carbonates require higher temperatures to decompose compared to lighter ones. This trend is due to the decrease in charge density as the cation size increases down the group, which results in weaker electrostatic attraction between the cation and anion, making it harder for the carbonate to decompose.
To explain in more detail, as the temperature is increased, the carbonates of Group II elements decompose into their corresponding oxide and carbon dioxide gas. For example, calcium carbonate (CaCO3) decomposes to form calcium oxide (CaO) and carbon dioxide (CO2) gas:

CaCO3(s) → CaO(s) + CO2(g)

The decomposition reaction is endothermic, meaning it requires energy input to proceed. Therefore, the thermal stability of the carbonates decreases as you move down the group because larger cations have weaker bonds with the carbonate anion and require less energy to decompose.

The same trend applies to Group II nitrates, but different products are formed upon decomposition. For example, calcium nitrate (Ca(NO3)2) decomposes to form calcium oxide (CaO), nitrogen dioxide (NO2) gas, and oxygen (O2) gas:

Ca(NO3)2(s) → CaO(s) + 2NO2(g) + 1/2O2(g)

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Related Questions

Mosquitoes breed in areas where there is often standing, still, svampy, water. Mosquitoes can cause malaria and other harmful diseases to humans and animals. Without causing damage to an existing ecosystem, what could you do to help control the current mosquitoes and their larvae? (what would eat them ?)

Answers

Answer:

Many natural scents that are appealing to humans actually repel mosquitoes, including lavender, peppermint, basil, and eucalyptus. Many of these scents can be worn as an essential oil on your skin to help keep these pesky pests from biting you.

What are the main group elements

Answers

The main group elements are classified as belonging to the s- and p-blocks in the periodic table. They range from gases such as fluorine and oxygen through nonmetals (e.g., boron, phosphorus, and sulfur) and semimetals (metalloids; e.g., germanium) to very reactive metals such as sodium and potassium.

Answer:

In chemistry and atomic physics, the main group is the group of elements whose lightest members are represented by helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, and fluorine as arranged in the periodic table of the elements. The main group includes the elements in groups 1 and 2, and groups 13 to 18.

HELP ME PLSSS ASAP!!!!!

Compare and contrast the paths that P-waves and S-waves take through Earth. How do you think this information helps geologists understand Earth's interior?

Answers

S waves can only pass through solids, whereas P waves can pass through liquid, solids, and gases. This data is used by scientists to calculate the composition of the Earth. Seismometers all across the world can measure the S and P waves that come from an earthquake that strikes on one side of the planet, for instance.

What is meant by seismic waves?

When materials suddenly move within the Earth, such when they slip along a fault during an earthquake, seismic waves are produced. Seismic waves can also be produced by volcanic eruptions, explosions, landslides, avalanches, and even swiftly flowing rivers.

Earthquakes typically result from subsurface rock breaking unexpectedly and rapid movement along a fault. The seismic waves that cause the ground to tremble are brought on by this quick release of energy.

S waves can only pass through solids, whereas P waves can pass through liquid, solids, and gases. This data is used by scientists to calculate the composition of the Earth. Seismometers all across the world can measure the S and P waves that come from an earthquake that strikes on one side of the planet, for instance.

There are two different types of waves produced by earthquakes: primary (P) and secondary (S). Based on when they come and how they feel on the surface, they are classified. P waves, also known as primary waves, arrive first, followed by S waves, even comprehended as secondary waves. The ground trembles when an earthquake happens because of both waves.

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Select how benzophenone and benzaldehyde can be distinguished using IR only. O Only one compound will show absorption at 1720 cm −1
O Only one compound will show absorptions at 1600 and 1650 cm −1
O Only one compound will show absorption at 1865 cm −1
O Only one compound will show absorptions at 2820 and 2720 cm −1
.

Answers

While benzaldehyde will exhibit absorption between 1600 and 1650 cm-1, benzophenone will exhibit absorption at 1720 cm-1. Furthermore, benzaldehyde and benzophenone also exhibit absorption at 1865 cm1 and 2820 and 2720 cm \(^-1\), respectively.

Using IR spectroscopy, these absorption peaks can be utilized to separate the two substances.

With a carbonyl group, benzophenone exhibits a maximum absorption at 1720 cm1, which is the same as the C=O stretching frequency. The absorption peaks of benzoaldehyde, which possesses an aldehyde group and corresponds to the C=C stretching frequency and the C-H bending frequency, respectively, are at 1600 and 1650 cm-1.

Additionally, benzaldehyde has a C-H stretching, giving it peaks at 2820 and 2720 cm1, while benzophenone has a phenyl ring, giving it a peak at 1865 cm1.

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Question 3 The flowchart of a steady-state process to recover crystalline chromate (K_CO) from an aqueous solution of this salt is shown below: 4500 kg/h 33.3% K,Cro EVAPORAT 49.4% K Cro OR Filtrate 3

Answers

The steady-state process flowchart to retrieve crystalline chromate (K_CO) from an aqueous solution of this salt is shown in the figure given below. Here are the steps and terms involved:4500 kg/h is the feed rate of the aqueous solution of K2CrO4 which contains 33.3% of K2CrO4 (w/w).

The solution is fed into an evaporator where it is evaporated until it reaches a concentration of 49.4% (w/w) K2CrO4.The concentrated solution is fed into a crystallizer where it is cooled and crystallized. The crystals of K2CrO4 are separated and sent to the product tank while the mother liquor from the crystallizer is sent to the filtration unit.

The solution is then filtered to recover any K2CrO4 crystals present in the mother liquor. The filtrate is recycled back to the evaporator, while the filter cake is sent to waste.

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Weathering and Erosion Unit Test
Explain how crustal deformation builds landforms.
O
When two tectonic plates start to push into each other they can rise up and build mountains, or sink under
and create deep valleys.
O When wind and rain slowly wear away rock, they leave behind new looking landforms.
If
o
When two tectonic plates slide away from each other the inner liquid layer of the mantle comes to the
surface as lava and creates new islands.
It
When sediments are laid down over vast areas the forces involved create rock over a very long period of
time.
It
HELP ME ASAPPP PLEASEEE

Answers

Crustal deformation builds landforms when two tectonic plates start to push into each other they can rise up and build mountains, or when they sink under, they create valleys.

How crustal deformation builds landforms?

Tectonic pressure in a crust can cause folding. Folding can end up with  the formation of valleys and mountains so we can conclude that when two tectonic plates start to push into each other they can rise up and build mountains, or when they sink under, they create deep valleys.

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A car with a mass of 1,000 kg is moving at a speed of 20 m/s. What is the car's kinetic energy?

Answers

The answer would be 200000 J. the equation for kinetic energy is 1/2 mass times velocity squared. 1/2 of 1,000 is 500. and 20*20 is 400. So, multiply 400 by 500, and that gives you your answer,

bacteria and virus are micro organisms​

Answers

The Answer is yesssssss

Answer:

Technically a microorganism or microbe is an organism that is microscopic. The study of microorganisms is called microbiology. Microorganisms can be bacteria, fungi, archaea or protists. The term microorganisms does not include viruses and prions, which are generally classified as non-living.

Who was the first person to show strong empirical evidence for the existence of atoms?.

Answers

Given what we know, we can confirm that John Dalton was the first person to show strong empirical evidence for the existence of atoms.

Who was John Dalton?He was a renowned scientist with knowledge in many fields. He was known to be a chemist, meteorologist, and physicist.He proposed the atomic theory and carried out experiments to provide supporting evidence.

Therefore, given his proposal of the atomic theory and the experiments he carried out to provide evidence to support his claims, we can confirm that John Dalton was the first person to show strong empirical evidence for the existence of atoms.

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What is the formula mass of CuSO4?

Answers

Copper Sulfate (CuSO4) has a formula mass of 159.60 g/mol.

What is Copper Sulfate?

A fungicide, herbicide, and algaecide, copper sulphate is a blue crystalline substance. CuSO4 is its chemical name, and it is made up of copper, sulphur, and oxygen.

Additionally, copper sulphate is utilised for metal recovery, colouring, and electroplating. It can be hazardous to both people and animals in excessive amounts.

How can you determine it?

It is determined by multiplying the atomic masses of all the formula's constituent elements. CuSO4, or one atom of copper (Cu), one atom of sulphur (S), and four atoms of oxygen, is the formula for copper sulphate (O). Copper has an atomic mass of 63.55 g/mol, sulphur has a mass of 32.06 g/mol, and oxygen has a mass of 16.00 g/mol. Thus, the mass of CuSO4 can be determined using the following formula:

159.60 g/mol is equal to 63.55 g/mol of copper, 32.06 g/mol of sulphur, 4 times 16.00 g/mol of oxygen, and 32.06 g/mol of sulphur.

Thus, 159.60 g/mol is the formula mass for copper sulphate.

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If 30 g of a drug is dissolved in 150 mL of a solvent having a specific gravity of 1.40, what is the percentage strength (%w/w) of the drug solution?

Answers

the percentage strength (%w/w) of the drug solution is 12.5%.To determine the percentage strength (%w/w) of the drug solution, we need to first calculate the weight of the solvent in the solution. We can do this using the specific gravity of the solvent, which tells us how much denser the solvent is compared to water.

To determine the percentage strength (%w/w) of the drug solution, we need to first calculate the weight of the solvent in the solution. We can do this using the specific gravity of the solvent, which tells us how much denser the solvent is compared to water.

Density of water = 1 g/mL
Density of solvent = 1.40 g/mL

Therefore, the weight of the solvent in 150 mL of the solution is:

Weight of solvent = Volume x Density = 150 mL x 1.40 g/mL = 210 g

Now, to find the percentage strength (%w/w) of the drug solution, we need to divide the weight of the drug by the total weight of the solution (drug + solvent) and multiply by 100.

Weight of drug = 30 g

Total weight of solution = 30 g + 210 g = 240 g

%w/w of drug solution = (Weight of drug / Total weight of solution) x 100
%w/w of drug solution = (30 g / 240 g) x 100
%w/w of drug solution = 12.5%

Therefore, the percentage strength (%w/w) of the drug solution is 12.5%.
To determine the percentage strength (%w/w) of the drug solution with 30 g of drug dissolved in 150 mL of a solvent with a specific gravity of 1.40, follow these steps:

1. Calculate the mass of the solvent:
Mass of solvent = Volume of solvent × Specific gravity
Mass of solvent = 150 mL × 1.40 g/mL = 210 g

2. Calculate the total mass of the solution:
Total mass = Mass of drug + Mass of solvent
Total mass = 30 g (drug) + 210 g (solvent) = 240 g

3. Calculate the percentage strength (%w/w):
Percentage strength = (Mass of drug / Total mass) × 100
Percentage strength = (30 g / 240 g) × 100 = 12.5 %

Therefore, the percentage strength (%w/w) of the drug solution is 12.5%.

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The activation energy of a certain reaction is 45.5 kJ/mol . At 21 ∘C , the rate constant is 0.0110s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?

Answers

The temperature in degrees Celsius that the reaction will go twice as fast is  32.4 ⁰C.

Temperature when the reaction rate is twice faster

ln(k₂/k₁) = E/R(1/T₁ - 1/T₂)

where;

T₁ is initial temperature = 21 ⁰C = 294 Kk₁ is initial ratek₂ is final rateT₂ is final temperatureE is activation energyR ideal gas constant

when rate is twice faster, k₂ = 2k₁ = 2(0.011) s⁻¹ = 0.022 s⁻¹

ln(0.022/0.011) = (45,500/8.31)(1/294 - 1/T₂)

0.693 = 5475.33(1/294 - 1/T₂)

1.2657 x 10⁻⁴ = 1/294 - 1/T₂

1/T₂ = 1/294 - 1.2657 x 10⁻⁴

1/T₂ = 3.275 x 10⁻³

T₂ = 305.4 K = 32.4 ⁰C

Thus, the temperature in degrees Celsius that the reaction will go twice as fast is  32.4 ⁰C.

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GIVING BRAINLIEST FAST HURRY

GIVING BRAINLIEST FAST HURRY

Answers

The answer is C

Explain: the answer is just C

Write an equation that represents the second ionization energy of nickel.

Answers

Ni+ (g) —> Ni 2+ (g) + e-

The equation that represents the second ionization energy of nickel is \(\rm Ni+ (g) \rightarrow Ni^2^+ (g) + e-.\)

What is the second ionization energy?

The energy needed to free the outermost, or least bound, an electron from an element's 1+ ion is known as the second ionization energy.

The second ionization energy of an element is usually greater than the first because positive charge more strongly attracts electrons than negative charge.

The chemical equation is the representation of the chemical reaction. The left side of the substance and compound is the reactant and the right side of the substance is the product.

Nickel is a chemical element. Its chemical symbol is Ni. Its atomic number is 28. It's a silvery luster metal.

Therefore, the equation is \(\rm Ni+ (g) \rightarrow Ni^2^+ (g) + e-.\)

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The alcohol in "gasohol" burns according to the following equation: C2H6O + 3 O2 → 2 CO2 + 3H2O. In a test, 60. 89 moles of water is collected from this reaction. How many moles of CO2 also formed?

Answers

Therefore, approximately 40.59 moles of CO2 were also formed in the given test where 60.89 moles of water were collected from the reaction of the alcohol in "gasohol."

According to the balanced equation, the stoichiometry shows that for every 1 mole of C2H6O, 2 moles of CO2 are formed. Therefore, we can use this ratio to determine the moles of CO2 formed when 60.89 moles of water are collected.

Since 3 moles of water are produced for every 2 moles of CO2, we can set up a proportion using the collected moles of water and the corresponding moles of CO2:

3 moles H2O / 2 moles CO2 = 60.89 moles H2O / x moles CO2

Solving for x, we find:

x = (2 moles CO2 * 60.89 moles H2O) / 3 moles H2O

x ≈ 40.59 moles CO2

Therefore, approximately 40.59 moles of CO2 were also formed in the given test where 60.89 moles of water were collected from the reaction of the alcohol in "gasohol."

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when equal molar amounts of the following sets of compounds are mixed in water, which could not form a buffer solution? nah2po4 with na2hpo4 nh3 with nh4cl hc2h3o2 with nac2h3o2 hno3 with nano3

Answers

The set of compounds that cannot form a buffer solution when mixed in equal molar amounts is HNO3 with NaNO3. This is the correct option.

A buffer solution is formed when a weak acid and its conjugate base or a weak base and its conjugate acid are mixed in water. To determine which set of compounds cannot form a buffer solution, we need to identify the strong acids or bases in the given sets.


1. NAH2PO4 with Na2HPO4: Both are a weak acid and its conjugate base, so they can form a buffer solution.

2. NH3 with NH4Cl: Both are a weak base and its conjugate acid, so they can form a buffer solution.

3. HC2H3O2 with NaC2H3O2: Both are weak acid and its conjugate base, so they can form a buffer solution.

4. HNO3 with NaNO3: HNO3 is a strong acid, so it cannot form a buffer solution with its conjugate base.

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how can freeze-fracture be used to determine the orientation of a protein in a membrane?

Answers

Freeze-fracture is a technique used to determine the orientation of proteins in a membrane. It involves freezing a sample, fracturing it, and examining the resulting membrane surfaces.

1. By using specific labeling techniques and electron microscopy, freeze-fracture can reveal the distribution and arrangement of proteins within the lipid bilayer.

2. Freeze-fracture begins by rapidly freezing a biological sample, preserving its structure. The frozen sample is then fractured, typically along the lipid bilayer, resulting in two complementary fracture faces: the fracture face (P-face), which corresponds to the protoplasmic (cytoplasmic) side of the membrane, and the complementary fracture face (E-face), which corresponds to the exoplasmic (extracellular) side of the membrane. These faces can be coated with heavy metals, such as platinum, to enhance their visibility under an electron microscope.

3. To determine the orientation of a protein within the membrane, specific labeling techniques can be employed. Antibodies or other protein-specific probes can be used to label the protein of interest with gold particles or other electron-dense markers. These markers selectively bind to the protein and can be visualized using electron microscopy. By examining the distribution and density of the markers on the P-face and E-face, it is possible to infer the orientation of the protein in the membrane.

4. If a protein is evenly distributed on both faces, it suggests that the protein spans the membrane, with portions exposed on both sides. If the protein is predominantly observed on one face, it indicates that it may be oriented asymmetrically in the membrane. By comparing the labeling patterns of various proteins, researchers can gain insights into their orientation and arrangement within the lipid bilayer.

5. In conclusion, freeze-fracture combined with specific labeling techniques and electron microscopy provides a valuable tool for determining the orientation of proteins in a membrane. This approach allows researchers to study the distribution and arrangement of proteins within the lipid bilayer, providing insights into their functional roles in cellular processes.

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Select the correct scientific notation form of this numeral using only 2 significant figures. 5,489.6654

Answers

Answer:

5.4 × 10 3

Explanation:

Answer:

5.4 × 10^3.

Explanation:

Not 5.49 × 10^3, 5.4 × 10^7, or 5.5 × 10^3.

6. Three ice cubes are placed inside a glass of hot chocolate. Which of the following best
explains the heat transfer occurring inside the glass?
bat abanslate
ITS NUMBER 6!!!
PLZZ HELP ASAP!!!

6. Three ice cubes are placed inside a glass of hot chocolate. Which of the following bestexplains the

Answers

It’s the first 1 M yea it’s the first one

how many liters are in 36.5 ounces

Answers

Answer:

1.097 liters are in 36.5 ounces

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" MARK MY ANSWER AS BRAINLIST ANSWER "

In any atom, the size of the nucleus with respect to the size of
the atom is
a
Large and located in the upper left quadrant of the
atom
b
Large and located in the upper right quadrant of
the atom
C Very large, almost covering the whole of the atom
Very small and dense and located in the center of
the atom

Answers

Answer:

Size of the nucleus of an atom is very small as compared to the size of the atom.

According to Rutherford gold foil experiment, nucleus is very small in size as compared to the size of the atom as a whole. Nucleus is very hard, dense and positively charged which consists of protons and neutrons.

Explanation:

HELP ME PLEASE I NEED THE ANDEER NOW

HELP ME PLEASE I NEED THE ANDEER NOW

Answers

the answer is 0.430 .

D Serum Levels Of 4 Mcg/mL, Calculate The Dose, In Milligrams, For A 120-lb Patient That May Be Expected To Result In A Blood Serum Gentamicin Level Of 4.5 Mcg/mL. This problem has been solved! See the answer If the administration of gentamicin at a dose of 1.75 mg/kg is determined to result in peak blood serum levels of 4 mcg/mL, calculate the dose, in milligrams, for a 120-lb patient that may be expected to result in a blood serum gentamicin level of 4.5 mcg/mL.

Answers

Answer:

The patient requires a dose of 107.2 mg of gentamicin

Explanation:

A dosage of 1.75 mg per Kilogram body weight results in blood serum levels of 4.5 mcg/mL

This means that; 1.75 mg/ kg = 4.0 mcg/mL

Therefore, dosage of gentamicin in  mg/kg that will result in 4.5 mcg/mL blood serum level = (1.75 mg/Kg * 4.5 mcg/mL) / 4.0 mcg/mL

Dosageof gentamicin = 1.97 mg/Kg

1-lb = 0.453592 Kg

Weight of 120-lb patient in Kg = 120 * 0.453592 = 54.43 Kg

Dose in mg required by patient = 1.97 mg/Kg * 54.43 Kg = 107.2 mg

Therefore, the 120-lb patient requires a dose of 107.2 mg of gentamicin to result in a blood serum level of 4.5 mcg/mL

What is coronavirus
Why do you need to be cautious

Answers

Answer:

IT IS CORONAAAAAAAAAAAAAAAAAAAAA

Answer:

coronavirus is a lung disease, it makes it so that you have a fever, cough, trouble breathing, mild headaches, and sometimes even nausea. you should be cautious because if your at high risk your gonna have trouble recovering from it. wearing a mask could help protect others from the spread of coronavirus. others wearing a mask prevents you from the spread of coronavirus. if you do catch it, make sure you see your doctor and isolate yourself for two weeks to a month and try not to go out as much.

The values used in the scale of pH and pOH are derived from a system designed by ______.

Curie
Gordonsen
Dalton
Sorenson

Answers

the answer to this question Is sorenson

When carbon dioxide enters the blood, some of it combines with ____________ to form carbaminohemoglobin, but most of it becomes ____________ ions that diffuse into the blood plasma.

Answers

Answer:

hemoglobin to become bicarbonate

Explanation:

When carbon dioxide enters the blood it combines with hemoglobin to form carbamino hemoglobin or carboxyhemoglobin but most of it becomes carbonate ions and diffuse into the blood plasma.

What is carboxyhemoglobin?

Hemoglobin is a blood protein giving red colour to the blood. It helps to transport oxygen everywhere. When oxygen fills in the air sack, it combines with oxygen and form oxyhemoglobin.

However, hemoglobin have more affinity towards carbon dioxide and and they combines to form carbaminohemoglobin which prevents the transportation of oxygen through blood.

The carbon dioxide will be converted into carbonic acid by combining with water. This acid then forms its carbonate ions and these ions helps to maintain the blood pH to be constant.The carbonate ions, CO₃²⁻can easily diffuse into blood plasma.

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___________________is the rate that an object moves in a certain direction. Question 3 options:

Speed

Displacement

Direction

Velocity

Answers

Answer: Velocity

Explanation:

i just took the quiz for k12

Velocity is the rate at that an object moves in a certain direction. The correct option is d.

What is velocity?

The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity. A vector is a velocity. It comprises both magnitude and direction.

The size of velocity is speed. In still air, a particle gravitationally settles and quickly reaches its terminal velocity. The term "settling velocity" refers to a particle's final speed in a still fluid (also known as the "sedimentation velocity").

The particle settling velocity in the foreshore region plays a significant role in understanding fluctuations in the hydraulic regime and interactions between sediment and fluid in the surf zone.

Therefore, the correct option is d, Velocity.

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compare pure substance with mixture

Answers

Answer:

here

Explanation:

a pure substance consists only of one element or one compound. a mixture consists of two or more different substances, not chemically joined together.

Please answer these. The tables needed for question 7 are in the picture. I got rid of some of the questions that you wouldn’t be able to answer without doing the lesson

Question 1: Electron Notation Example (2 points)

a. Give the electron configuration of vanadium (V), atomic number 23. (0.5 points)

b. Give the noble gas configuration of vanadium (V), atomic number 23. (0.5 points)

c. List the energy levels for the orbital configuration of vanadium (V), atomic number 23. (1 point)

Question 3: Trends on the Periodic Table (2 points)
a. How does the atomic radius change going down and across the periodic table? (0.5 points)

b. How does first ionization energy change going down and across the periodic table? (0.5 points)

c. How does electronegativity change going down and across the periodic table? (0.5 points)

d. How does the radius of a positive and negative ion compare to a neutral atom? (0.5 points)

Question 4: Chemical Bonds (1 point)
Match each chemical bond to its correct description. (1 point)
A. Ionic bond ___ Sharing of electrons
B. Covalent bond ___ Freely moving electrons
C. Metallic bond ___ Transfer of electrons
Question 5: Intermolecular Forces (3 points)

a. Describe the dipole-dipole force. (1 point)

b. Describe hydrogen bonding. (1 point)

c. Describe the Van der Waals forces. (1 point)

Question 6: Intermolecular Forces and You (2 points)
Imagine you need to take a medicine that the doctor has prescribed for you. Explain why scientists who developed that medicine would need to know whether or not the compound in that medicine is polar. How might a polar medicine behave differently within your body than a nonpolar medicine would? Answer in 1 to 2 paragraphs.

Question 7: Energy in Bonds (9 points)
Use these tables for reference for all parts of this question.

This table summarizes the average energies of single bonds between atom pairs in many different compounds.
a. According to Table 2, which is the strongest bond? Which is the weakest bond? Based on what you know about the atomic radii and electronegativity of the elements involved in the bonds, why do you think these two have the most extreme bond-energy values? (3 points)

b. How are the bond energies of each bond listed in Table 2 determined? (1 point)

c. Why do you think there aren't bond energy values given in Table 2 for N–S and S–I? (1 point)

d. Based on Tables 1 and 2, how would you describe the trend in bond strength of single, double, and triple bonds? (1 point)

e. Based on Table 2, how would you describe the trend in the strength of bonds formed by the elements carbon, nitrogen, and oxygen? Would you describe this trend as a periodic trend? Why or why not? (3 points)

Question 8: Causes of Molecular Shape (3 points)
a. What is the VSEPR theory? (1 point)

b. How does electron repulsion determine molecular shape? (1 point)

c. How do lone electron pairs affect molecular shape? (1 point)

Question 10: Lewis Structure (3 points)
a. Draw the Lewis structure for the Se and 2 H atoms. (1 point)

b. Draw the Lewis structure for the SeH2 molecule. (1 point)

c. What shape would SeH2 have? Draw the molecule. (1 point)

Question 11: Ionic and Covalent Compounds (5 points)
Identify each of the following as a covalent compound or ionic compound. Then provide either the formula for compounds identified by name or the name for those identified by formula. (1 point each)
a. Li2O:

b. Dinitrogen trioxide:

c. PCl3:

d. Manganese(III) oxide:

e. Calcium bromide:

Please answer these. The tables needed for question 7 are in the picture. I got rid of some of the questions

Answers

Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Therefore, the electronic configuration of vanadium is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³.

What is element?

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.

The systematic distribution of electrons in the various atomic orbitals is called its electronic configuration. The atomic number of vanadium is 23. The electronic configuration of vanadium is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³. The noble gas electronic configuration of vanadium is  [Ar]3d³4s². 1,2,3 represents the number of shells and s and represents the orbitals. The superscripts represents the number of electrons in each orbitals.

Therefore, the electronic configuration of vanadium is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³.

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when using a water-cooled condenser, the water should choose... the condenser. to make this happen, the water should flow in at the choose... and should flow out at the choose... .

Answers

When using a water-cooled condenser, the water should constantly move over the condenser. to make this happen, the water should flow in at the bottom part and should flow out at the top part.

Water cooled condenser is heat exchanger. it will removes heat from the refringent and transfer to the water running through. The advantages of this system is it is lasts year longer. it has higher heat transfer rate

Thus, When using a water-cooled condenser, the water should constantly move over the condenser. to make this happen, the water should flow in at the bottom part and should flow out at the top part.

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