What is the equation of the line that is parallel to the line y =
Oy=-x+3
O y=-x+7
Oy= 3x - 13
Oy= 3x +5
-x+4 and passes through the point (6, 5)?

Elysa would have to save money for 6 weeks to afford the glove

46.50-15= 31.5/5.25= 6

The 7 m/s is greater when he is running and he will pay the least amount of money at shop 1.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

When Ron cycles, his maximum speed is 20 km/h when Ron runs, his maximum is 7 m/s.

= 20 km/h = 20(1000)/(60×60) m/s

= 5.55 m/s

7 > 5.55

The greater is 7 m/s.

Shop 1

3.99 tube: buy 2 get 1 free

2 tube cost = 2×3.99 = 7.98

Each unit cost = 7.98/3 = 2.66

Shop 2

3.99 a tube with 20% off:

= 20% of 3.99

= (20×3.99)/100

= 0.798

The cost of 1 tube = 3.99 - 0.798 = 3.192

He will pay the least amount of money at shop 1

Thus, the 7 m/s is greater when he is running and he will pay the least amount of money at shop 1.

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Answer:

The amount of money in Enid bank account can be written as a linear equation.

Ye = Xe + $4*m

where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.

For Jim, the equation is similar:

Yj = Xj + $3*m

where Yj and Xj are similar as above.

Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).

Then we have that:

Ye = $72 = Xe + $4*7 = Xe + $28

Xe = $72 - $28 = $44

So in May 15, Enid deposited $44.

For Jim we have:

Yj = $72 = Xj + $3*7 = Xj + $21

Xj = $72 - $21 = $51

So in May 15, Jim deposited $51.

It is not possible to provide a precise explanation or calculation for constructing a confidence interval or fitting a regression model in this context.

To construct a confidence interval, several key components are needed:

With these components, a confidence interval can be calculated to estimate the true population parameter (e.g., mean, proportion) within a certain range.

The formula for constructing a confidence interval depends on the specific parameter being estimated and the distribution of the data.

In the case of a regression model, additional information is needed, such as the equation or relationship between the dependent variable (Y) and explanatory variable (X).

This equation is used to estimate the fitted values and residuals.

Fitted values are the predicted values of the dependent variable based on the regression model, while residuals are the differences between the observed values and the fitted values.

Without the specific details of the sample size, mean, standard deviation, and the regression equation.

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Using exponential function concepts, it is found that the common ratio would be given by 0.989.

A decaying exponential function is modeled by:

\(A(t) = A(0)(1 - r)^t\)

In which:

In this problem, the amount decays 1.1% a year, hence:

The common ratio would be given by 0.989.

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Answer: C

Step-by-step explanation:

Trust

Answer:

Step-by-step explanation:

Given the total number of employee to be equal to 12 temporary employee.

Number of women employee = 5 women

Number of men employee = 12 - 5 = 7 men

If 4 will be hired as permanent employees, the possible ways they can be grouped so that the 4 temporary employees consists of 3 women and 1 man can be done by applying the combination formula.

Combination has to do with selection. For example, if r objects are to be selected from n pool of similar objects, this can be done in nCr different ways.

\(nCr = \frac{n!}{(n-r)!r!}\)

According to question, we are to select 3 women from 5 women and 1 man from 7 men. Based on similarity in sex, this can be done in (5C3* 7C1) different ways .

\(5C3 * 7C1\\= \frac{5!}{(5-3)!3!} * \frac{7!}{(7-1)!1!}\\\\= \frac{5!}{2!3!} * \frac{7!}{6!1!}\\\\= \frac{5*4*3!}{3!*2} * \frac{7*6!}{6!*1}\\\\= \frac{20}{2} * \frac{7}{1}\\ \\= 10*7\\\\= 70\ possible\ groups\)

The smallest number of eggs that could have been in the box is 1134

The problem is to find the smallest number of eggs that could have been in the box, given the remainder when taking them out by different numbers. Here are the moves toward tackling it:

Allow n to be the quantity of eggs in the container. Then we have the accompanying arrangement of congruences:

n ≡ 1 (mod 2)

n ≡ 1 (mod 3)

n ≡ 1 (mod 4)

n ≡ 1 (mod 5)

n ≡ 1 (mod 6)

n ≡ 0 (mod 7)

For this problem, we have k = 6 k = 6, a i = {1,1,1,1,1,0} a_i = {1,1,1,1,1,0}, M i = {1260,840,630,504,420,720} M_i = {1260,840,630,504,420,720}, and y i = {−1,−2,−3,-4,-5,-6} y_i = {-1,-2,-3,-4,-5,-6}.

Plugging these values into the formula and simplifying modulo 5040, we get:

n = (−1260 + −1680 + −1890 + −2016 + −2100 + 0) mod 5040

n = (−8946) mod 5040

n = (−3906) mod 5040

n = 1134 mod 5040

Therefore, the smallest number of eggs that could have been in the box is 1134

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Answer:

3

8

Step-by-step explanation:

probability= no. of blue marbles

total no. of marbles

= 3

8

Step-by-step explanation:

Answer:

-20x

Step-by-step explanation:

Answer: 1/1 :)

Step-by-step explanation:

The answer to your question is that the fully qualified name of the fall constant would be "seasons.fall". This is because "seasons" is the name of the enum type, and "fall" is the name of the constant within that type.

To provide a more thorough explanation, an enum is a special type in programming that represents a fixed set of values. In this case, the "seasons" enum has four constants: spring, winter, summer, and fall. Each constant has a name that is unique within the enum type.

To access a specific constant within an enum, you use the syntax "enumName.constantName". In this case, the enum name is "seasons" and the constant name is "fall", so the fully qualified name of the fall constant is "seasons.fall".
Overall, the long answer to your question is that the fully qualified name of a constant within an enum includes both the name of the enum type and the name of the constant itself, separated by a period.

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Answer:

On the 7th floor

Step-by-step explanation:

0+1+5-3+4

1+5-3+4

6-3+4

3+4

7

Answer:

Hi,

Step-by-step explanation:

a) y=(x+1)² ==> graph C

b) y=x²-1 ==> graph A

c) y=2x² ==> graph B

Answer:

218.57

Step-by-step explanation:

Since it is an isoceles triangle, the sides are 32, 32, and 14.

Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2,  we can calculate the area.

(A+B+C)/2  = (32+32+14)/2=39.

A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.

Hope this helps have a great day :)

Check the picture below.

so let's find the height "h" of the triangle with base of 14.

\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=\sqrt{ 32^2 - 7^2}\implies h=\sqrt{ 1024 - 49 } \implies h=\sqrt{ 975 }\implies h=5\sqrt{39} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5\sqrt{39}})}\implies 35\sqrt{39} ~~ \approx ~~ \text{\LARGE 218.57}\)

<removed test question answer>

If the radius is 5 and the height is 8:

\(A=2\pi rh+2\pi r2=2*\pi*5*8+2*\pi*5^{2}\) ≈ \(408.41 m\)

If the radius is 8 and the height is 5:

\(A=2\pi rh+2\pi r2=2*\pi*8*5+2*\pi*8^{2}\) ≈ \(653.45m\)

The correct ratio to be able to find x would be B. tan ( x ) = 1 / 2.

In the right angled triangle given, the value of x is an angle and we are given the dimensions that are opposite that angle and adjacent to it. This means that the best operation would be tangent.

The value of x is therefore :

Tan ( angle ) = Opposite / Adjacent

Opposite = 5

Adjacent = 10

The value of x is:

Tan ( x ) = 5 / 10

In simplest form:

Tan ( x ) = 1 / 2

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Yes, g has a maximum and minimum on the set S.

Since S is a closed and bounded interval, by the Extreme Value Theorem, any continuous function on S will have both a maximum and minimum value. Therefore, g, defined on S, will have both a maximum and minimum value.

To find the global maxima and minima of g on the set S, we need to analyze the function g(x). However, since no specific function is defined for g, we cannot determine the exact maxima and minima values without further information. We can make some general observations about g(x) on S. Firstly, since S includes both negative and positive values, g(x) could be a piecewise function that changes at x = 0. Secondly, the behavior of g(x) will depend on the specific function used to define it. For example, if g(x) = x^2, then g(x) will have a minimum value of 0 at x = 0 and a maximum value of 100 at x = 10 or x = -10. Similarly, if g(x) = -x^3, then g(x) will have a maximum value of 1000 at x = 10 and a minimum value of -1000 at x = -10.

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Answer:

\(g(x) = - x\\ g( - 4) = - ( - 4) + 24 \\ g( - 4) = 4 \times 2 + 24 \\ g( - 4) =8 + 24 \\ g( - 4) = 32 \)

Answer:

A kid leaping happily to home after school

The graph represents the relationship between height and time.

Given that,
A curve has been shown we have to explain the behavior of the curve.

The graph is a demonstration of curves that gives the relationship between the x and y-axis.

Here,
The curve is shown, where the vertical axis represents the height above the ground and the horizontal axis represents the time. Let's assume a plane of paper is flying, the plane getting a rise and then a certain down and again rise and down as according to the height of the plane.

Thus, the graph represents the relationship between height and time.

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Answer:

Hello! answer: x = 29 and I don't know for sure but I think y = 61 answer that at your own risk though! Hope that helps!

Answer:

Step-by-step explanation:

Q = F(K,L) = 3K+2L.

Answer:

63 = 1 x 63, 3 x 21, or 7 x 9. Factors of 63: 1, 3, 7, 9, 21, 63. Prime factorization: 63 = 3 x 3 x 7, which can also be written 63 = 3² x 7.

(i) To find the solution for yt in the given equation yt = yt−1 + εt + 0.3εt−1, we can rewrite it as yt - yt−1 = εt + 0.3εt−1. By applying the lag operator L, we have (1 - L)yt = εt + 0.3εt−1.

Solving for yt, we get yt = (1/L)(εt + 0.3εt−1). The solution for yt involves lag operators and depends on the values of εt and εt−1.  (ii) For the equation yt = 1.2yt−1 + εt, to find the s-step-ahead forecast Et[yt+s], we can recursively substitute the lagged values. Starting with yt = 1.2yt−1 + εt, we have yt+1 = 1.2(1.2yt−1 + εt) + εt+1, yt+2 = 1.2(1.2(1.2yt−1 + εt) + εt+1) + εt+2, and so on. The s-step-ahead forecast Et[yt+s] can be obtained by taking the expectation of yt+s conditional on the available information at time t.

To make this model stationary, we need to ensure that the coefficient on yt−1, which is 1.2 in this case, is less than 1 in absolute value. If it is greater than 1, the process will be explosive and not stationary. To achieve stationarity, we can either decrease the value of 1.2 or introduce appropriate differencing operators.

(iii) For the equation yt = yt−1 + t + εt, finding the solution for yt and the s-step-ahead forecast Et[yt+s] involves incorporating the time trend t. By recursively substituting the lagged values, we have yt = yt−1 + t + εt, yt+1 = yt + t + εt+1, yt+2 = yt+1 + t + εt+2, and so on. The s-step-ahead forecast Et[yt+s] can be obtained by taking the expectation of yt+s conditional on the available information at time t.

To make this model stationary, we need to remove the time trend component. We can achieve this by differencing the series. Taking first differences of yt, we obtain Δyt = yt - yt-1 = t + εt. The differenced series Δyt eliminates the time trend, making the model stationary. We can then apply forecasting techniques to predict Et[Δyt+s], which would correspond to the s-step-ahead forecast Et[yt+s] for the original series yt.

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Answer:

9000 panels

Step-by-step explanation:

See attached for detailed explanation.

Remember that percent means division by a 100.

Answer:

A and C

Step-by-step explanation:

A) Two squares with the same side lengths are always congruent

C) Two rhombuses with the same side lengths are always congruent.

Two geometric shapes are called congruent if they have the same size and the same shape.

Therefore the true statements are A and C.

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Answer:

brainliest plss

Step-by-step explanation:

5p(2p-3)(p+7)=0

p=0

(2p-3)=0

(p+7)=0

p=0

p=3/2

p=-7

Answer:

p = 0, p = ³/₂, p = -7

Step-by-step explanation:

\(\boxed{\begin{minipage}{9 cm}\underline{Zero Product Property}\\\\If\; $a \cdot b = 0$ \;then either \;$a = 0$ \;or\; $b = 0$ (or both).\\\end{minipage}}\)

Given equation:

\(5p(2p-3)(p+7)=0\)

Using the Zero Product Property, set each factor equal to zero and solve for p.

Factor 1

\(\begin{aligned}5p&=0\\5p \div 5&=0 \div 5\\p&=0\end{aligned}\)

Factor 2

\(\begin{aligned}2p-3&=0\\2p-3+3&=0+3\\2p&=3\\2p \div 2&=3 \div 2\\p&=\dfrac{3}{2}\end{aligned}\)

Factor 3

\(\begin{aligned}p+7&=0\\p+7-7&=0-7\\p&=-7\end{aligned}\)

Therefore, p = 0, p = ³/₂, p = -7.

Answer:

answer 1

Step-by-step explanation:

x^2+4x+7

=(x^2+4X+4)+3

=(x+2)^2+3

Answer: Population Parameter

The characteristic or value of a population that is under consideration is called a parameter, which represents a numerical summary of the population's attributes or features.

The characteristic or value of a population that is under consideration is called a parameter.

In statistics, a parameter refers to a numerical value that describes a specific characteristic of a population.

It is often used to make inferences or draw conclusions about the entire population based on a sample.

Parameters can include measures such as the population mean, population standard deviation, population proportion, or any other characteristic that helps describe the population of interest.

It is important to distinguish parameters from statistics, which are the corresponding values calculated from a sample and used to estimate or infer the population parameters.

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