what is the equation of parallel line of C(3,6); y= -2+5​

Answer:

25

Step-by-step explanation:

5^2 means 5 multiplied by itself 2 times, so therefore: 5x5

5x5 = 25 so 5^2=25

Hope this helped!

Answer:

Step-by-step explanation:

\(5^2 = 5\times 5\\=25\\\)

Answer: Evaluate the findings to compare to his hypothesis

Step-by-step explanation: Since the biologist already has the findings and has a hypothesis, he now has to compare both of them together.

The simplified value of the expression √900 + √0.09 + √0.000009 is 30.303.

To simplify the given expression, let's evaluate the square roots individually and then perform the addition.

√900 = 30, since the square root of 900 is 30.

√0.09 = 0.3, as the square root of 0.09 is 0.3.

√0.000009 = 0.003, since the square root of 0.000009 is 0.003.

Now, we can add these simplified values together

√900 + √0.09 + √0.000009 = 30 + 0.3 + 0.003 = 30.303

Therefore, the simplified value of the expression √900 + √0.09 + √0.000009 is 30.303.

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125 = 5³, and the given expression reduces to

\(\left(\sqrt{125}\right)^{\frac13}\cdot\left(\sqrt[3]{125}\right)^{\frac12}=\left(125^{\frac12}\right)^{\frac13}\cdot\left(125^{\frac13}\right)^{\frac12}=125^{\frac16}\cdot125^{\frac16}=125^{\frac13}\)

so it has a value of 5.

Now:

• the first choice is equivalent, since 625 = 25², so

\(\dfrac{\sqrt[3]{625}}{5^{\frac13}}=\dfrac{25^{\frac23}}{5^{\frac13}}=\dfrac{5^{\frac43}}{5^{\frac13}}=5\)

• the second choice is not equivalent, since

\(5 \cdot 25^{\frac13} = 5 \cdot 5^{\frac23} = 5^{\frac43}\)

• the third choice is also equivalent, since

\(\dfrac{\left(\sqrt[4]{5}\right)^7}{125^{\frac14}}=\dfrac{5^{\frac74}}{5^{\frac34}}=5\)

• the fourth choice is also equivalent, since

\(\dfrac{5^{\frac12}\cdot25^{\frac13}}{\sqrt[6]{5}}=\dfrac{5^{\frac12}\cdot5^{\frac23}}{5^{\frac16}}=\dfrac{5^{\frac76}}{5^{\frac16}}=5\)

(a) The real discrete Fourier transform (DFT) is calculated for the given data set to analyze the helicopter's acoustic signature.

(b) To obtain the ck values and illustrate the relative size of each term in the Fourier series, we calculate the magnitude of each coefficient and plot their amplitudes on a bar graph against the corresponding frequency component, k.

To analyze the helicopter's acoustic signature, the real DFT is computed for the provided data set. The DFT transforms the time-domain measurements of acoustic pressure into the frequency domain, revealing the different frequencies present and their corresponding amplitudes. This analysis helps in understanding the spectral characteristics of the helicopter's acoustic signature and identifying prominent frequency components.

Using the Fourier series representation, the amplitudes (ck's) of the different frequency components in the Fourier series are determined. These amplitudes represent the relative sizes of each term in the series, indicating the contribution of each frequency component to the overall acoustic signature. By plotting the amplitudes on a bar graph, the relative strengths of different frequency components become visually apparent, enabling a clear comparison of their importance in characterizing the helicopter's acoustic signature.

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In analyzing the performance of implementing the given methods over Singly Linked List and Doubly Linked List data structures, we consider the Big-O notation, which provides insight into the time complexity of these operations as the size of the list increases.

Add to Start of List:

Singly Linked List: O(1)

Doubly Linked List: O(1)

Both Singly Linked List and Doubly Linked List offer constant time complexity, O(1), for adding an element to the start of the list.

This is because the operation only involves updating the head pointer (for the Singly Linked List) or the head and previous pointers (for the Doubly Linked List). It does not require traversing the entire list, regardless of its size.

Add to End of List:

Singly Linked List: O(n)

Doubly Linked List: O(1)

Adding an element to the end of a Singly Linked List has a time complexity of O(n), where n is the number of elements in the list. This is because we need to traverse the entire list to reach the end before adding the new element.

In contrast, a Doubly Linked List offers a constant time complexity of O(1) for adding an element to the end.

This is possible because the list maintains a reference to both the tail and the previous node, allowing efficient insertion.

Add at Given Index:

Singly Linked List: O(n)

Doubly Linked List: O(n)

Adding an element at a given index in both Singly Linked List and Doubly Linked List has a time complexity of O(n), where n is the number of elements in the list.

This is because, in both cases, we need to traverse the list to the desired index, which takes linear time.

Additionally, for a Doubly Linked List, we need to update the previous and next pointers of the surrounding nodes to accommodate the new element.

In summary, Singly Linked List has a constant time complexity of O(1) for adding to the start and a linear time complexity of O(n) for adding to the end or at a given index.

On the other hand, Doubly Linked List offers constant time complexity of O(1) for adding to both the start and the end, but still requires linear time complexity of O(n) for adding at a given index due to the need for traversal.

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Let's define the following variables first.

A = number of tickets sold for adults

C = number of tickets sold for children

From the question, we can say that or form the following equations:

1. A + C = 790 tickets

2. $7A + $4C = $4, 390

The first equation can also be written as A = 790 - C. We can use this equation and replace "A" in the second equation.

From that, we can solve "C" by solving the equation formed above.

Therefore, 380 tickets for children were sold.

Since there are 790 tickets in total that are sold and 380 tickets for children were sold, we can say that 410 tickets for adult was sold.

Answer:

14 6/11

Step-by-step explanation:

Answer:

\( \sqrt{8} \)

Step-by-step explanation:

an

irrational number can only be written in the form with never ending,non-repeatinng digits after the decimal comma

Answer:

A

Step-by-step explanation:

Well considering how the graph looks, from the x-axis(0,0), the line(x) moves upwards on the left before itf(x) moves downwards on the right

Answer:

Step-by-step explanation:

In order to figure out how much money was left in the account after the interest was withdrawn, we have to first find out how much money was initially deposited to earn that amount of interest! The means to find that initial investment is found in the simple interest formula

prt = I, where

p is the initial investement,

r is the interest rate in decimal form,

t is the time in years, and

I is the interest earned. Notice that we have all those things but the p.

Filling in:

p(.0425)(4) = 2380 and

.17p = 2380 so

p = 14000

That means that 14000 was initially invested. If the depositor withdrew the 2380, then

14000 - 2380 is the amount left in the account, namely, $11620

Step-by-step explanation:

Let's solve your equation step-by-step.

15+10x=75x+25

Step 1: Simplify both sides of the equation.

10x+15=75x+25

Step 2: Subtract 75x from both sides.

10x+15−75x=75x+25−75x

−65x+15=25

Step 3: Subtract 15 from both sides.

−65x+15−15=25−15

−65x=10

Step 4: Divide both sides by -65.

−65x

−65

=

10

−65

x=

−2

13

Answer:

x=

−2

13

The predicted spending amount on a hotel for the night for a customer that falls into the leaf node with six cases (312.00, 350.00, 285.00, 295.00, 380.00, 220.00) in the training set is $307.17.

Regression tree is a type of decision tree which is used for regression analysis. Regression tree is a data mining technique that is used to find the relationship between a target variable and multiple predictor variables.

Regression trees are built by dividing the input space into smaller regions using the input variables, and then fitting a simple model (constant) in each region. In regression tree, the input space is divided into non-overlapping regions based on the independent variables.

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Barrett should record the note payable and corresponding merchandise purchased on January 1, 2021 at $232,144.00.To calculate the amount at which Barrett should record the note payable and corresponding merchandise purchased on January 1, 2021, we need to find the present value of the note payable.

The note requires five annual payments of $26,000, which can be treated as an annuity due with a future value of zero. Using the PV of an annuity due table with n=5 and i=9%, we find the present value factor to be 4.9384. Therefore, the present value of the annuity due is:

$26,000 x 4.9384 = $128,160.00

In addition to the annuity due, there is a lump-sum payment of $160,000 due on December 31, 2025. To find the present value of this lump-sum payment, we can use the PV of a single sum table with n=5 and i=9%, which gives us a present value factor of 0.6499. Therefore, the present value of the lump-sum payment is:

$160,000 x 0.6499 = $103,984.00

The total present value of the note payable and corresponding merchandise purchased is the sum of the present values of the annuity due and lump-sum payment:

$128,160.00 + $103,984.00 = $232,144.00

Therefore, Barrett should record the note payable and corresponding merchandise purchased on January 1, 2021 at $232,144.00.

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Answer:

Step-by-step explanation:

-7/2t = 3x^2 - 5

t =  -2(3x^2 - 5)/7

The value of t is given by the equation t = [2/7](5 - 3x²) if the function g(x) = 3x² - 5.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

The function:

g(x) = 3x² - 5

To find the value of such that g(x) = -(7/2)t

Equate both the equations:

3x² - 5 = -(7/2)t

After simplification:

t = [2/7](5 - 3x²)

The above equation represents the value of t.

Thus, the value of t is given by the equation t = [2/7](5 - 3x²) if the function g(x) = 3x² - 5.

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Answer:

$10000

Step-by-step explanation:

50x25=1250sqfeet

1250x$8=$10000

Answer:

Cost = $10,000

Step-by-step explanation:

Finding the area of the wooden floor:

To find the cost of replacing the wooden floor, we need to calculate the area of the floor. To calculate the area of the floor, we need to multiply the length with the width. Seek below for calculations.

⇒ Area of floor = LB

⇒ Area of floor = 50 x 25

⇒ Area of floor = 1250 feet²

Finding the cost of replacing the floor:

⇒ Cost = Area of floor × Rate

⇒ Cost = 1250 × $8/foot

⇒ Cost = $10,000

The number of 6-card hands  in which at least one card from each suit is equal to 8,184,220.

Total number of 6-card hands that can be formed from a deck of 60 cards is,

Using combination formula,

C(60, 6) = 50,063,860

Now, subtract the number of 6-card hands that do not contain at least one card from each suit.

There are 5 ways to choose the suit that will be missing from the hand.

Once this suit is chosen, there are 48 cards remaining in the other suits.

Choose 6 cards from this set, so the number of 6-card hands that do not contain any cards from the chosen suit is,

C(48, 6) = 12,271,512

Overcounted the number of hands that are missing more than one suit.

There are C(5, 2) ways to choose 2 suits that will be missing from the hand.

Once these suits are chosen, there are 36 cards remaining in the other 3 suits.

Choose 6 cards from this set, so the number of 6-card hands that do not contain any cards from the chosen suits is,

C(36, 6) = 1,947,792

We cannot have a 6-card hand that is missing more than 2 suits.

3 suits with no cards in the hand, which is not allowed.

Number of 6-card hands that have at least one card from each suit is,

C(60, 6) - 5×C(48, 6) + C(5, 2)×C(36, 6)

=50,063,860 - 5×  12,271,512 + 10 × 1,947,792

= 50,063,860 -61,357,560 + 19,477,920

= 8,184,220

Therefore, there are 8,184,220 of 6-card hands that have at least one card from each suit.

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Step-by-step explanation:

remember, the domain is the interval or set of all valid x values, the range is the interval or set of all valid y values (functional result values).

1.

domain : -infinity < x < +infinity

range : -1 <= y < +infinity

due to the x² term that part can never be negative. the minimum is 0, and then -1 gives us a overall minimum -1. and then up ... the sky is the limit ...

2.

domain : every value of x that does not turn (3x + 5) to 0 and therefore does not cause a 1/0 situation.

the only forbidden value of x is therefore

3x + 5 = 0

3x = -5

x = -5/3

so, (-infinity < x < -5/3) OR (-5/3 < x < +infinity)

range : -infinity < y < +infinity

3.

domain : -infinity < x < +infinity

range : 0 <= y < +infinity

due to the x⁴ term (even exponent) all results will be positive starting with 0. similar to 1.

4.

this is 1/(2x) as I understand it.

similar to 2. we must avoid at 1/0 situation.

so, x must not be 0. everything else is possible

domain : (-infinity < x < 0) OR (0 < x < +infinity)

range : -infinity < y < +infinity

5.

everything is allowed and possible.

domain : -infinity < x < +infinity

range : -infinity < y < +infinity

Answer:

7/12

Step-by-step explanation:

3*4=12. 4/12+3/12=7/12.

Answer:

5/12

Step-by-step explanation:

you find the common factor of 12, divide 12 by the denominator, multiply the numerator by that, add the new numerators, put it on the denominator of 12, subtract it from 12/12

Answer:

segment IG ≅ segment LJ

Step-by-step explanation:

Please refer to the attached image as per the triangles as given in the question statement.

\(\triangle HGI, \triangle JKL\)

\(G\left(-3,1\right),\ H\left(-1,1\right),\ I\left(-2,3\right)\)

\(J\left(3,3\right),K\left(1,3\right),L\left(2,1\right)\)

Given that:

\(HI\cong KL\) and

\(\angle I \cong \angle L\)

SAS congruence between two triangles states that two triangles are congruent if two corresponding sides and the angle between the two sides are congruent.

We are given that one angle and one sides are congruent in the given triangles.

We need to prove that other sides that makes this angle are also congruent.

To show the triangles are congruent i.e. \(\triangle GHI \cong \triangle JKL\) by SAS congruence we need to prove that

segment IG ≅ segment LJ

Let us use Distance formula  to find IG and LJ:

\(D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

\(IG =\sqrt{(-2+3)^2+(3-1)^2} =\sqrt5\ units\)

\(LJ =\sqrt{(2-3)^2+(1-3)^2} =\sqrt5\ units\)

Hence, segment IG ≅ segment LJ

\(\therefore\) ΔGHI ≅ ΔJKL by SAS

Answer: C

Step-by-step explanation:

The slope-intercept form of a line is given by

y = mx + b

m - slope

b - y-intercept

Segment AB lies on the line 6x + 3y = 12

6x + 3y = 12

3y = -6x + 12

​​y = -6/3​x +  12/3​  

y = -2x + 4

Comparing with the slope-intercept form,

Slope = - 2

y-intercept = 4

Segment CD lies on the line 4x + 2y = 8

4x + 2y = 8

2y = -4x + 8

y = -4/2​x +  8/2

y = - 2x + 4

Comparing with the slope-intercept form,

Slope = - 2

y-intercept = 4

Both the line segments have the same slope and the same y-intercept, so the two line segments will lie exactly on top of one another.

Therefore, the correct option is (c)

Answer:

They will buy 15 hamburger

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Answer:

he made $31.50 in commission

the jewelry store made $418.50

Step-by-step explanation:

turn the percent to a decimal by moving it 2 places 7%=.07

then multiply .07 by 450 to get his commission =31.50

then subtract 31.50 and 450 = 418.50

The polling agency must survey at least 3075 college students to estimate the proportion of students who voted in the last election within a 0.025 margin of error with a 95% confidence level.

In order to determine the sample size needed for a public opinion polling agency to estimate the proportion of college students who voted in the last election within a 0.025 margin of error, you can follow these steps:

1. Determine the desired level of confidence, usually expressed as a percentage (e.g., 95% confidence level).

2. Calculate the z-score corresponding to the desired level of confidence. For a 95% confidence level, the z-score is 1.96.

3. Use the formula for estimating sample size:
  n = (z^2 * p * (1-p)) / E^2

  Here, n is the sample size, z is the z-score, p is the estimated proportion of students who voted, E is the desired margin of error (0.025 in this case).

4. Since we don't know the actual proportion (p) of students who voted, we can use the conservative assumption of p = 0.5 (50%), as this will result in the largest required sample size.

5. Plug the values into the formula:
  n = (1.96^2 * 0.5 * (1-0.5)) / 0.025^2
  n = (3.8416 * 0.5 * 0.5) / 0.000625
  n = 1.9208 / 0.000625
  n ≈ 3074.08

6. Since the sample size must be a whole number, round up to the nearest whole number: n = 3075.

Therefore, the polling agency must survey at least 3075 college students to estimate the proportion of students who voted in the last election within a 0.025 margin of error with a 95% confidence level.

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Mallory should adjust her consumption of candy and cookies until the marginal utility per dollar for each good is equal, and she has spent all of her income.

Marginal utility refers to the additional satisfaction or benefit that a person receives from consuming one additional unit of a good or service. It is a concept in economics that is based on the idea that the value of each additional unit of a good or service diminishes as a person consumes more of it.

For example, if you are hungry and you eat a slice of pizza, the first slice of pizza may provide a high level of satisfaction or utility. However, as you continue to eat more slices of pizza, the marginal utility of each additional slice decreases. At some point, you may become full and may even start to feel sick if you continue to eat more pizza.

To determine whether Mallory should consume more cookies, more candy, or leave her consumption unchanged, we need to calculate the marginal utility per dollar for each good. This will tell us which good is providing the most additional utility for each dollar spent.

The marginal utility per dollar for candy is calculated as follows:

MUc/Pc = 12 utils / $1 = 12 utils per dollar

The marginal utility per dollar for cookies is calculated as follows:

MUk/Pk = 6 utils / $0.50 = 12 utils per dollar

Since the marginal utility per dollar for cookies and candy is the same (12 utils per dollar), Mallory should consume either more cookies or more candy, or a combination of both, until the marginal utility per dollar for both goods is equal. This means that the last dollar spent on both goods should provide the same additional utility.

Therefore, to maximize her total utility, Mallory should adjust her consumption of candy and cookies until the marginal utility per dollar for each good is equal, and she has spent all of her income.

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The value of "p" will be "0.002".

According to the question,

By subtracting "0.25p" from both sides, we get

→ \(100+0.05p-0.25p=0.25p-0.25p\)

                 \(100-0.2p=0\)

                            \(100=0.2p\)

                               \(p = \frac{0.2}{100}\)

                                  \(= 0.002\)

Thus the above approach is right.

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Answer:

About 29%

Step-by-step explanation:

Answer: 98

Step-by-step explanation: 180 - 82 = 98

180 - 80 = 100, and 100 - 2 is 98.