The perpendicular equation is y = -1/3x + 10 Option A
How to find perpendicular of an equation?You can find this by first realizing that perpendicular lines have opposite and reciprocal slopes. So since it starts at 3 we flip it and make it a negative and the new slope is -1/3.
Now we can use that and the point to get the y intercept using slope intercept form.
y = mx + c
m = gradient of the line
c = y -intercept
8 = (-1/3)(6) + c
8 = -2 + c
10 = c
And now we can use our new slope and new intercept to model the equation. y = -1/3x + 10
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Use limit(s) to determine whether f(x) = x²+6x+5/x+5 has a vertical asymptote at x=-5. Find the limit(s) using tables. Do NOT use any algebra manipulations. Write the table and the limits you find on your paper. In D2L, write either yes or no, with a reason as to why there is/is not a vertical asymptote.
the limit of f(x) as x approaches -5 exists and is equal to 0.8. Since the limit exists, we can conclude that there is a vertical asymptote at x = -5.To determine if there is a vertical asymptote at x = -5 for the function f(x) = (x² + 6x + 5)/(x + 5), we can evaluate the limit of f(x) as x approaches -5 from both sides using a table.
First, we'll create a table by choosing x values that approach -5 from both sides:
x | f(x)
--------------
-6 | 1
-5.1 | 0.81
-5.01 | 0.801
-5.001 | 0.8001
-4.9 | 0.77
-4.99 | 0.799
-4.999 | 0.7999
-4.9999 | 0.79999
As x approaches -5 from the left side, the values of f(x) approach 0.8. Similarly, as x approaches -5 from the right side, the values of f(x) approach 0.8 as well.
Therefore, the limit of f(x) as x approaches -5 exists and is equal to 0.8. Since the limit exists, we can conclude that there is a vertical asymptote at x = -5.
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Find the distance between the pair of points: (2,3) and (-5, -3).
distance = ?
Answer:
9.219544457292887
Step-by-step explanation:
Use distance formula
√(−5−2)^2+(−3−3)^2
√(−7)^2+(−6)^2
√49+36
√85
√≈9.219544457292887
Hoped this helped!
: )
A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 170lb and each box of books weighs 50lb. The maximum capacity of the elevator is lb. How many boxes of books can the delivery person bring up at one time?
Step-by-step explanation:He can only hold 3 because 170 divivded by 50 = 3 Your welcome!!
Henry’s car averages 8 gallons of gasoline to travel 320 miles. At this rate, how many miles would he be able to drive if he purchased 24 gallons of gas?
Henry would be able to drive 960 miles if he purchased 24 gallons of gas.
Given that Henry's car uses 8 liters of gasoline on average to cover 320 miles.
Let x miles be able to drive if he purchased 24 gallons of gas.
According to the question, the ratio can be calculated as:
320 miles : 8 gallons = x miles : 24 gallons
⇒ 320/8 = x/24
⇒ (8)(x) = (24)×(320)
Divide each side by 8 to get,
⇒ x = (24)×(320)/(8)
⇒ x = 960
Therefore, he would be able to drive 960 miles if he purchased 24 gallons of gas.
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A square garden has an area of 5 square feet. Without using a calculator, find the side length of the garden to the nearest tenth of a foot
Answer:
2.23
Step-by-step explanation:
tune able to find the area you should x one side by the other side to find the area 2.23 * 2.23 equals close to 5 square feet
Aaliyah owns a small textile company that produces shirts. On a particular day,
Aaliyah has one worker come into the shop to make shirts. She must pay the worker
$28 per hour and also pay $2 per shirt for material costs. The worker created an
average of 4 shiris per hour and Aaliyah's total expenses for labor and materials were
$144. Write a system of equations that could be used to determine the number of
hours the worker worked and the number of shirts the worker made. Define the
variables that you use to write the system.
Let _ =
Let _=
System of equations:
1.
2
A system of equations that could be used to determine the number of hours the worker worked and the number of shirts the worker made is 28x + 2(4x) = 144
Let x be the number of working hours
She must pay the worker $28 per hour
So, Cost of labor for x hour = 28x
The worker created an average of 4 shirts per hour.
So, number of shirts produced in x hours = 4x
Cost of 1 shirt = 2
Cost of 4x shirts = 2 (4x)
Total expenses for labor and materials = 28x + 2(4x)
We are given that Aaliyah total expenses for labor and materials were $144
So, 28x + 2(4x) = 144
28x + 8x = 144
x = 4
Hence a system of equations that could be used to determine the number of hours the worker worked and the number of shirts the worker made is 28x + 2(4x) = 144
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Mrs. Lia has 17 pounds of modeling clay. She divides the clay into 1/2 pound blocks. If Mrs. Lia puts aside2 if the blocks and gives the rest to the students in her art class, how many 1/2 pound blocks of clay does Mrs. Lia give to her class?
Answer:
6
Step-by-step explanation:
Answer:
28
Step-by-step explanation:
A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s it strikes a second hockey puck with a mass 0.11 kg the first hockey puck comes to rest after the collision of conservation of momentum holds what is the total final momentum of the system (round your answer to the nearest tenth
Answer:
Conservation of momentum means that the final momentum must be the same as the initial momentum, where the momentum is defined as:
P = m*v
where m is mass, and v is velocity.
First, let's calculate Pi, the initial momentum.
Pi = Pi₁ + Pi₂
Where the subscripts 1 and 2 refer to each puck:
Pi₁ = 0.17kg*15m/s = 2.55 (kg*m/s)
Pi₂ = 0.11kg*0m/s = 0 (kg*m/s)
Pi = 2.55 (kg*m/s) + 0 (kg*m/s) = 2.55 (kg*m/s)
Now, after the collision we have that:
The first puck comes to rest, then:
Pf₁ = 0.17kg*0m/s = 0 (kg*m/s)
And the second puck will have a velocity v, that we want to find:
Pf₂ = 0.11kg*v
Pf = Pf₁ + Pf₂ = 0 (kg*m/s) + 0.11kg*v = 0.11kg*v
And by conservation of momentum we have:
Pi = Pf
2.55 (kg*m/s) = 0.11kg*v
We divide in both sides by 0.11kg
2.55 (kg*m/s)/0.11kg = v
23.2 m/s = v
And from this, the final momentum will be the same as the initial:
Pf = 23.2m/s*0.11kg = 2.55 (kg*m/s)
The total final momentum of the system is 2.55 Kg m/sec and this can be determined by conserving the momentum.
Given :
A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s it strikes a second hockey puck with a mass of 0.11 kg the first hockey puck comes to rest after the collision of conservation of momentum holds.
The formula of the momentum is given below:
P = mv
Now, let conserve the moment, that is:
\(\rm P_i=P_f\) --- (1)
where \(\rm P_i\) is the initial momentum and \(\rm P_f\) is the final momentum.
First, determine the initial momentum.
\(\rm P_i = 0.17\times 15 + 0.11\times 0= 2.55\;Kg\;m/sec\)
Now, determine the final momentum.
\(\rm P_f = 0.17\times 0+ 0.11\times v = 0.11v\;Kg\;m/sec\)
Now. substitute the value of \(\rm P_i\) and \(\rm P_f\) in the equation (1).
\(\rm 2.55=0.11v\)
v = 23.18 m/sec
So, the final momentum can be calculated as:
\(\rm P = 23.18 \times 0.11\)
P = 2.55 Kg m/sec
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The tensile strength of a metal part is normally distributed with mean 40lb and standard deviation 8lb. If the lower specification limit is 34lb and upper specification limit is 48lb, Find out the % of parts fail to meet specification? Exercise 3: The tensile strength of a metal part is normally distributed with mean 40lb and standard deviation 8lb. If the lower specification limit is 34lb and upper specification limit is 48lb, Find out the % of parts fail to meet specification?
Given the following details about the tensile strength of a metal part - normally distributed with mean μ = 40lb and standard deviation σ = 8lb. Lower specification limit LSL = 34lb and Upper specification limit USL = 48lb.
The probability of the parts that fail to meet the specification can be calculated by finding the area under the normal distribution curve to the left of the LSL and to the right of the USL.
The formula for z-score is,z = (X - μ)/σwhere X is the tensile strength of a metal part.z1 = (LSL - μ)/σz1 = (34 - 40)/8z1 = -0.75z2 = (USL - μ)/σz2 = (48 - 40)/8z2 = 1.0
The percentage of parts fail to meet specification isP(z < z1) + P(z > z2)P(z < -0.75) + P(z > 1.0)P(z < -0.75) = 0.2266 (from standard normal distribution table)P(z > 1.0) = 0.1587 (from standard normal distribution table)P(z < z1) + P(z > z2) = 0.2266 + 0.1587 = 0.3853The percentage of parts fail to meet specification is 38.53%.Hence, the answer is 38.53%.
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At football game eli gained 92 yards by rushing samuel gained 30 more yards than eli whats was the total number of yards gained by eli and samuel during the game
Eli gained 92 yards rushing, while Samuel gained 122 yards, totaling 214 yards between them during the football game.
Eli gained 92 yards rushing in the football game. Samuel gained 30 more yards than Eli. To find Samuel's total yards, we add the additional 30 yards to Eli's total. Therefore, Samuel gained a total of 92 + 30 = 122 yards.
To calculate the total number of yards gained by Eli and Samuel during the game, we sum their individual yardage. Eli gained 92 yards, and Samuel gained 122 yards, resulting in a combined total of 92 + 122 = 214 yards.
In summary, Eli gained 92 yards rushing, and Samuel gained 30 more yards than Eli, for a total of 122 yards. Together, they accumulated 214 yards during the football game.
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predict the number of people in a household with 2.5 pounds of waste pounds of waste 0.27,1.41,2.19,2.83,2.19,1.81,0.85,3.05
The number of people in a household with 2.5 pounds of waste are = 11
and we calculate this on the basis of question below
Predict the number of people in a household with 2.5 pounds of waste pounds of waste 0.27,1.41,2.19,2.83,2.19,1.81,0.85,3.05. In Home 2 3 3 6 4 2 1 5
pound 0.27 ,1.41, 2.19 ,2.83 ,2.19 ,1.81 ,0.85, 3.05
people 2 3 3 6 4 2 1 5
so now the question is complete
in pound section we have to take care which value are greater than 2.5
so 2.83 and 3.05 is greater than 2.5 so here number of people who's home have greater than 2.5 pound of waste are 6+6=11
and rest people who's home has less than 2.5 pound waste are 2+3+3+4+2+1=15
so final ans is 11.
so this question was in complete and this ans is valid for this Question only.
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in a carnival game, a player spins a wheel that stops with the pointer on one (and only one) of three colors. the likelihood of the pointer landing on each color is as follows: 65 percent blue, 21 percent red, and 14 percent green. note: your answers should be rounded to three decimal places. (a) suppose we spin the wheel, observe the color that the pointer stops on, and repeat the process until the pointer stops on blue. what is the probability that we will spin the wheel exactly three times?
The probability that we will spin the wheel exactly three times is 0.504 .
Probability of landing on blue: 65%
Probability of landing on red: 21%
Probability of landing on green: 14%
Probability of not landing on blue: 100% - 65% = 35%
1. Not landing on blue for the first two spins and landing on blue on the third spin.
Probability = (0.35) × (0.35) × (0.65) = 0.080
2. Not landing on blue for the first spin, landing on blue on the second spin, and landing on blue on the third spin.
Probability = (0.65) × (0.35) × (0.65) = 0.148
3. Landing on blue on the first spin, not landing on blue on the second spin, and landing on blue on the third spin.
Probability = (0.65) × (0.65) × (0.65) = 0.276
Total Probability = 0.080 + 0.148 + 0.276 = 0.504
The probability of spinning the wheel exactly three times until landing on blue is approximately 0.504
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Solve for x 12 + x = 27
Answer:
15
Step-by-step explanation:
subtract 12 on both sides and you get
x=27-12
x=15
Answer:
I think your answer is 15
Step-by-step explanation:
Hope this helped you
Giselle stars with the two parallel line segments shown. She correctly reflects the segments across
the x-axis and then translates them following the rule (x,y) → (x-2, y + 5).
Line Segment AB has endpoints (2,4) and (-2,-1). Line Segment CD has end points (3,1) and (-1.-4).
(image attached)
Which statements about the reflection and translation of the line segments are true? Select all that
apply.
omg what is the......................
I need to solve for x plz help
Answer:
x = 6
Step-by-step explanation:
Just a hunch
solve the following equation for q. 5q - 3p + 4 = 4q - 2
A function is graphed below. On which
interval of x is the average rate of change
of the function the smallest?
X
3
7
21
39
65
Y
3
18
28
36
40
Answer:
The x-axis interval of 39 to 65 has the smallest rate of change.
Step-by-step explanation:
See the attached worksheet. The interval of x that results in the least change in y can be visually seen by plotting the points and drawing a curve. The curve begins to flatten as x increases. So the smallest rate of change is between the last two points, x = 39 to 65.
This can also be calculated by finding the change in y per a change in x. The table in the graph confirms the earlier observation. Dx and Dy represent the "delta," or difference, D, between the x (Dx) and y(Dy) values. The rate of change is calculated as Dy/Dx, or the change in y divided by the change in x. The results confirm that the 39 to 65 segment is the smallest, at 0.15.
the mean cost of a five pound bag of shrimp is 46 dollars with a standard deviation of 7 dollars. if a sample of 49 bags of shrimp is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 0.5 dollars? round your answer to four decimal places.
The probability that the sample mean would differ from the true mean by less than 0.5 dollars is approximately 0.0000.By calculating the z-score for a difference of 0.5 dollars, we can then determine the probability using the standard normal distribution.
To calculate the probability that the sample mean would differ from the true mean by less than 0.5 dollars, we can use the Central Limit Theorem. Given that the mean cost of a five pound bag of shrimp is $46 with a standard deviation of $7, and a sample size of 49 bags, we can consider the distribution of sample means. Since the sample size is large (n ≥ 30), we can assume that the distribution of sample means will be approximately normal.
According to the Central Limit Theorem, for a sample size of 49 or larger, the distribution of sample means will be approximately normal, regardless of the shape of the original population. In this case, the mean cost of a five pound bag of shrimp is $46 with a standard deviation of $7. Since we are interested in the probability that the sample mean differs from the true mean by less than 0.5 dollars, we need to calculate the z-score for a difference of 0.5 dollars.
The z-score can be calculated using the formula: z = (x - μ) / (σ / sqrt(n)), where x is the desired difference (0.5 dollars), μ is the true mean ($46), σ is the standard deviation ($7), and n is the sample size (49). Substituting the values into the formula, we get: z = (0.5 - 46) / (7 / sqrt(49)) = -45.5 / (7 / 7) = -45.5 / 1 = -45.5.
Now, we can use the standard normal distribution table or a calculator to find the probability corresponding to the z-score of -45.5. However, since the z-score is extremely large, the probability will be extremely close to 0. Therefore, we can round the answer to four decimal places and conclude that the probability that the sample mean would differ from the true mean by less than 0.5 dollars is approximately 0.0000.
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what is the dependent variable of the number of packages of hotdog buns needed for a certain number of packages of hotdogs?
Always check the quantity in each package to determine the appropriate number of hotdog bun packages needed for the given number of hotdog packages.
The dependent variable in this situation is the number of packages of hotdog buns needed, as it relies on the number of packages of hotdogs (the independent variable).
We want to know the dependent variable when considering the number of packages of hotdog buns needed for a certain number of packages of hotdogs.
Let me explain this relationship:
First, let's define the terms involved.
The dependent variable is the variable that depends on another variable (called the independent variable).
In this case, we are examining the relationship between the number of packages of hotdogs and the number of packages of hotdog buns needed.
The independent variable is the number of packages of hotdogs.
This is because the number of hotdog buns needed depends on the number of hotdogs you have.
The dependent variable, in this case, is the number of packages of hotdog buns needed.
This variable depends on the number of packages of hotdogs, as you need a certain amount of buns to accommodate the hotdogs.
To determine the relationship between these two variables, we would likely use a proportion or a ratio.
For example, if one package of hotdogs contains 10 hotdogs and one package of hotdog buns contains 10 buns, then the ratio is 1:1, meaning you need one package of hotdog buns for every package of hotdogs.
This relationship may vary depending on the number of hotdogs and buns in each package.
Remember to examine the proportion between the two variables to ensure you have the correct amount of buns for the hotdogs.
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When displaying quantitative data, what is an ogive used to plot? Multiple Choice Frequency or relative frequency of each class against the midpoint of the corresponding class Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class Frequency or relative frequency of each class against the midpoint of the corresponding class and cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class None of the above
An ogive is used to plot cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class when displaying quantitative data. Option B.
An ogive is a graph that represents a cumulative distribution function (CDF) of a frequency distribution. It shows the cumulative relative frequency or cumulative frequency of each class plotted against the upper limit of the corresponding class. In other words, an ogive can be used to represent data through graphs by plotting the upper limit of each class interval on the x-axis and the cumulative frequency or cumulative relative frequency on the y-axis.
An ogive is used to display the distribution of quantitative data, such as weight, height, or time. It is also useful when analyzing data that is not easily represented by a histogram or a frequency polygon, and when we want to determine the percentile or median of a given set of data. Based on the information given above, option B: "Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class" is the correct answer.
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13. A town has a population of 7,500. The mayor asked two different employees to conduct a
survey to determine whether residents of the town are in favor of the construction of a new
baseball stadium.
●
Denise surveyed 150 randomly selected residents at a recent baseball game.
Tamira surveyed 150 randomly selected residents living in different sections of town.
The table below shows the results of the two surveys.
New Baseball Stadium
In Favor
125
30
Denise's Survey
Tamira's Survey
Opposed
20
105
No Opinion
5.
15
Which statement identifies the more reliable survey and provides a valid conclusion based on
that survey?
A. Denise's survey is more reliable than Tamira's survey, and approximately 6,250 residents of
the town would likely be in favor of the construction of a new baseball stadium.
B. Denise's survey is more reliable than Tamira's survey, and approximately 1,250 residents of
the town would likely be opposed to the construction of a new baseball stadium.
C. Tamira's survey is more reliable than Denise's survey, and approximately 1,500 residents of
the town would likely be in favor of the construction of a new baseball stadium.
D. Tamira's survey is more reliable than Denise's survey, and approximately 6,000 residents of
the town would likely be opposed to the construction of a new baseball stadium.
C. The more reliable survey would be: Tamira's survey is more reliable than Denise's survey, and approximately 1,500 residents of the town would likely be in favor of the construction of a new baseball stadium.
How to get the reliable surveyTаmirа's survеy is mоre reliаble bеcаusе shе survеyed rеsidеnts frоm diffеrеnt sectiоns оf thе town, whiсh is а mоre representаtive sаmple оf thе entire populаtiоn. Denise's survеy, оn thе othеr hаnd, wаs cоnducted аt а bаsebаll gаme, whiсh might hаve introduced а biаs towаrds people who аre mоre likеly to bе in fаvor оf thе new stаdium.
Bаsed оn Tаmirа's survеy, 30 out оf 150 rеsidеnts (20%) аre in fаvor оf thе cоnstructiоn.
If we extrаpolаte this percentаge to thе entire populаtiоn оf 7,500 rеsidеnts, we cаn estimаte thаt аpproximаtely 1,500 rеsidеnts (20% оf 7,500) would likеly bе in fаvor оf thе new bаsebаll stаdium.
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The value of Kelsey's car will depreciate (decrease) by a rate of 15% each year. She wants to write an exponential equation to find out what it will be worth in 6 years. What is the multiplier for this situation?
So if you multiply 15 by 6 you get 90 and the 6 is from every years she has saved. So if you take any number 95000 and 15 percent of 95000 is 14250 so try breaking it down and divide as much as you can but not to much and slowly at a time and then when you get that try to get close to 9500 as much as you can cause 90 percent of 95000 is 9500.
which of these decimal numbers is equivalent to 87?
0.87
8.70
87.00
870.0
Answer: if its 87% then its 0.87, but if its 87 then its 87.00
Step-by-step explanation: I'm doing these questions for a challenge :D
What is the slope of a line segment with endpoints at (-1,1) and (1,5)?
O undefined
O 4.
O 0.5
O 2
public class BinarySearch \{ public static void main(Stringll args) f int [1]yl ist ={1,2,3,7,10,12,20}; int result = binarysearch ( inylist, 20); if (result =−1 ) System, out, println("Not found:"); else System.out.println("The index of the input key is " + result+ ". "): y public static int binarysearch(int]l List, int key) \{ int low =0; int high = iist. length −1 while (high >= low) \& int mid =( low + high )/2; if (key < List [mid] high = mid −1; else if (key =1 ist [ mid ] ) return inid; else low = mid +1; return −1; // Not found \} l TASK 4: Binary Search in descending order We have learned and practiced the implementation of the binary search approach that works on an array in ascending order. Now let's think about how to modify the above code to make it work on an array in descending order. Name your new binary search method as "binarysearch2". Implement your own code in Eclipse, and ensure it runs without errors. Submit your source code file (.java file) and your console output screenshot. Hint: In the ascending order case, our logic is as follows: int mid =( low + high )/2 if ( key < list [mid] ) else if (key = ist [mid]) return mid; In the descending order case; what should our logic be like? (Swap two lines in the above code.)
The task involves modifying the given code to implement binary search on an array in descending order. The logic of the code needs to be adjusted accordingly.
The task requires modifying the existing code to perform binary search on an array sorted in descending order. In the original code, the logic for the ascending order was based on comparing the key with the middle element of the list. However, in the descending order case, we need to adjust the logic.
To implement binary search on a descending array, we need to swap the order of the conditions in the code. Instead of checking if the key is less than the middle element, we need to check if the key is greater than the middle element. Similarly, the condition for equality also needs to be adjusted.
The modified code for binary search in descending order would look like this:
public static int binarysearch2(int[] list, int key) {
int low = 0;
int high = list.length - 1;
while (high >= low) {
int mid = (low + high) / 2;
if (key > list[mid])
high = mid - 1;
else if (key < list[mid])
low = mid + 1;
else
return mid;
}
return -1; // Not found
}
By swapping the conditions, we ensure that the algorithm correctly searches for the key in a descending ordered array.
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HURRYYYY Are these expressions equivalent? Explain why or why
not.
42 + 35
7(6 + 5)
Answer:
Yes, they are equivalent!
Step-by-step explanation:
42+35=77
PEMDAS calls for 6+5 ( in parentheses ) which equals 11.
11*7=77
Answer:
equivalent
Step-by-step explanation:
42+35=77
7(6+5)=42+35
which is 77
and 77=77
Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1) complete parts (a) through (d)
a. The probability that Z is less than 1.51 is _______
b. The probability that Z is greater than 1.86 is________
c. The probability that Z is between 1.51 and 1.86 is______
d. The probability that Z is less than 1.51 or greater than 1.86______
a. The probability that Z is less than 1.51 is 0.9345. b. The probability that Z is greater than 1.86 is 0.0314. c. The probability that Z is between 1.51 and 1.86 is 0.0249. d. The probability that Z is less than 1.51 or greater than 1.86 is 0.9659.
The standardized normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. We can use the standard normal table to find the probabilities for each part of the question.
a. The probability that Z is less than 1.51 is 0.9345. We can find this by looking up the value of 1.51 in the standard normal table.
b. The probability that Z is greater than 1.86 is 0.0314. We can find this by looking up the value of 1.86 in the standard normal table and subtracting it from 1.
c. The probability that Z is between 1.51 and 1.86 is 0.0314 - 0.0065 = 0.0249. We can find this by subtracting the probability that Z is less than 1.51 from the probability that Z is less than 1.86.
d. The probability that Z is less than 1.51 or greater than 1.86 is 0.9345 + 0.0314 = 0.9659. We can find this by adding the probability that Z is less than 1.51 to the probability that Z is greater than 1.86.
Overall, we can use the standard normal table to find the probabilities for each part of the question.
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PLEASE ANSWER THIS QUESTION ITS DUE SOON
Answer:
B and E
Step-by-step explanation:
An expression is a sentence with a minimum of two numbers and at least one math operation
So B and E are expressions
Answer: E & C
Step-by-step explanation:
An expression will not have an equal sign or greater than/less than signs
So, E is an expression and C is an expression
Complete the point-slope equation of the line through (1, 3) and (5, 1). Use exact numbers.
Answer:
\(The \ equation \ in \ point \ and \ slope \ form \ is; \ y - 3 = -\dfrac{1}{2} \cdot (x - 1)\)
Step-by-step explanation:
The coordinates of the points through which the line passes are (1, 3) and (5, 1)
The slope, m, of a line given the coordinates of two known points on the line, (x₁, y₁), (x₂, y₂) can be found as follows;
\(Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)
The slope of the given line is therefore \(m =\dfrac{1-3}{5-1} = \dfrac{-2}{4} = -\dfrac{1}{2}\)
The equation of the line in point and slope form is therefore, y - y₁ = m·(x - x₁) or y - y₂ = m·(x - x₂)
Therefore, by substituting the known values, we have the equation in point and slope form as follows;
\(y - 3 = -\dfrac{1}{2} \cdot (x - 1)\)
The cycling road race through the Adelaide Hills started at 11:50am and the winner
Took 74 minutes. The winner crossed the finishing line at