What is the effect on the graph of f(x) = x² when it is transformed to
h(x) = 5x² + 10?

A. The graph of f(x) is vertically stretched by a factor of 5 and shifted 10 units up.

B. The graph of f(x) is horizontally compressed by a factor of 5 and
shifted 10 units to the left.

C. The graph of f(x) is horizontally stretched by a factor of 5 and
shifted 10 units up.

D. The graph of f(x) is vertically stretched by a factor of 5 and shifted 10 units to the left.

Answers

Answer 1

Answer:

A

Step-by-step explanation:

The '5' stretches it vertically by factor of 5  and the '10' shifts it UP 10 units

Answer 2
The answer would be A. Basically think of the stretching as multiplication. And the + or - after x refers to the y axis

Related Questions

Which fraction has a value that’s equal to7/8? A.49/64
B.56/8. D.15/8
C.22/24

Answers

Answer:

a 49/64

Step-by-step explanation:

7/8 multiply 7 ×7 = 49 then 8×8 is 64 so yeah a

Answee a 49/64 is the best answer

PLEASE HELP
The stem-and-leaf plot displays data collected on the size of 15 classes at two different schools.


Sky View School Riverside School
0 5, 6, 9
9, 7, 2, 0 1 0, 2, 4, 5, 6, 7
8, 7, 6, 5, 5, 5, 4, 3, 1, 0 2 0, 0, 2, 3, 5
0 3
4 2
Key: 2 | 1 | 0 means 12 for Sky View and 10 for Riverside


Part A: Calculate the measures of center. Show all work. (5 points)

Part B: Calculate the measures of variability. Show all work. (5 points)

Part C: If you are interested in a larger class size, which school is a better choice for you? Explain your reasoning. (2 points)

Answers

For  Sky View School mean is 7.933, median is 6, mode is 5

For Riverside School  mean is 8, median is 6.5, mode is 5

To calculate the measures of center, we can find the mean, median, and mode of each set of data.

For Sky View School:

Mean=119/15 = 7.933

Median: To find the median, we need to put the class sizes in order from smallest to largest.

0, 0, 1, 2, 3, 4, 5, 5, 5, 6, 6, 7, 8, 9, 9

The median is the middle value, which is 6.

Mode: The mode is the most common class size. In this case, the mode is 5.

For Riverside School:

Mean =120/15

= 8

Median:

0, 0, 1, 2, 2, 3, 4, 5, 5, 6, 7, 7, 8, 8, 10

The median is the average of the two middle values, which is 6.5

Mode: The mode is 5.

Part B:

To calculate the measures of variability, we can find the range and interquartile range (IQR) for each set of data.

For Sky View School:

Range: The range is the difference between the largest and smallest values.

$Range = 9 - 0 = 9$

IQR: To find the IQR, we first need to find the first quartile (Q1) and third quartile (Q3)

0, 0, 1, 2, 3, 4, 5, 5, 5 | 6, 6, 7, 8, 9, 9

Q1 is the median of the lower half, which is 3.

Q3 is the median of the upper half, which is 8.

IQR = Q3 - Q1 = 8 - 3 = 5

For Riverside School:

Range = 10 - 2 = 8$

IQR

Q1 is the median of the lower half, which is 2.

Q3 is the median of the upper half, which is 8.

IQR = Q3 - Q1 = 8 - 2 = 6

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Find the value of n so that the line perpendicular to y = (-1/3)X-4 passes through the points (n. 6) and (4,15).

How do I solve this ?

Answers

Answer:

1

Step-by-step explanation:

The slope of the perpendicular is the negative inverse of the slope of the line.

m = -1 / (-⅓)

m = 3

The slope between the two points is 3, so:

3 = (15 − 6) / (4 − n)

3 (4 − n) = 9

4 − n = 3

n = 1

The populations of two towns, town A and town B, are being compared. The population of town A is 4×104 and the population of B is 2×105. How many times greater is the population of town B than town A?


The masses of two objects are compared during a physics experiment. It is determined that object A has a mass of 4×10−3 grams and object B has a mass of 4×10−4 grams. How many times larger is the mass of object A than the mass of object B?

Answers

Answer:

1. 5 times

2. 10 times

Step-by-step explanation:

1. Here, we want to know the number of times the population of town B is greater than the population of town A

The simple thing to do here is to divide the population of town B by the population of town A

From the question; population of town B is 2 * 10^5 while the population of town A is 4 * 10^4

So the number of times greater will be;

(2 * 10^5) / (4 * 10^4) = 5

So population of town B is 5 times greater

2. Just like the first question, to know the number of times, we simply divide the mass of object A by the mass of object B

That will be;

(4 * 10^-3) / (4 * 10^-4) = 10 times

So therefore object A is 10 times larger than object B

You are driving 2760 miles across the country. During the first 3 days of your trip, you drive 1380 miles. If you continue to drive at the same rate each day, how many days will the entire trip take? Show your work and circle your answer.​

Answers

The entire trip will take 6 days.

(Encircle this answer, as said on the directions)

Step-by-step explanation:

We know that the first three days of the trip, we traveled 1380 miles.

Find the UNIT RATE of MILES PER day:

1380/3 = 460

Unit rate = 460 miles per day

If we were to drive at this (460 mi per day) rate EACH day and the whole journey takes 2760 miles across the country.

FInd the NUMBER of DAYS of the ENTIRE TRIP:

2760/460 = 6

It will take us 6 days to drive to the destination.

Math is multi-cultural, analytical, timeless and hands-on. Provide a piece of mathematical concept, hypothesis, law, paradox, rule or theorem to prove this statement.

Answers

It should be noted that mathematics is multicultural. This implies that mathematics applies to different cultures.

Mathematics is multicultural and it's neutral from the issues of races, gender, class, etc. Also, it should be noted that mathematics is analytical.

Furthermore, mathematics is timeless and hands-on. This implies that students need to touch and feel what they're learning through a concrete experience.

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2z-1= -9+ z i need the answer RIGHT NOW

Answers

Answer:

z = -8

Step-by-step explanation:

I'm guessing you want to find out what z is equal to, so here you go.

2z - 1 = -9 + z

2z = -8 + z

z = -8

Answer:

z = -8

Step-by-step explanation:

let's simplify the equation by getting the like terms together.

2z-1 = -9+z

first get the z's on the same side:

2z-z-1 = -9

z-1 = 9

then the constants:

z = -9+1

z = -8


A space ship travels at 24 miles per hour and traveled for 28 hours.

Select the answer that represents how many miles the space ship traveled.
A 212
B 24
C 22
D 232

A space ship travels at 24 miles per hour and traveled for 28 hours.Select the answer that represents

Answers

Answer:

2^4 = 16miles

2^8 = 256hrs

Step-by-step explanation:

16*256=4096

2^12=4096

so you answer is 2^12

To encode a message, James first replaces each letter within the message with its
corresponding number, where A = 1, B = 2, · · · , Y = 25, and Z = 26. Next, James
multiplies each number by 3 and then subtracts 5, and continues this process a total
of n times. For example, when n = 2 the letter D is encoded to the number 16.
If James encoded a four letter message to the four numbers 367 205 853 1339, what
is the value of n that he used?
(A) 2 (B) 3 (C) 4 (D) 5 (E) 6

Answers

Answer:

56

Step-by-step explanation:

its common sense

Answer:

E) (6)

Step-by-step explanation:

If you used rule of x^2/x^3 x cosh = x/100

You would contine this by using radionuklider thereom, you would obtain x/100=600. If this is further simplified tou would find the x=6, therefore y=18 accordingly.

                                       

20 points please help me i need this answer

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Weights of Dogs in Shelter A
2 box plots. The number line goes from 6 to 30. For the weights of dogs in shelter A, the whiskers range from 8 to 30, and the box ranges from 17 to 28. A line divides the box at 21. For shelter B, the whiskers range from 10 to 28, and the box ranges from 16 to 20. A line divides the box at 18.
Weights of Dogs in Shelter B

Which is true of the data in the box plots? Select three choices.
The median weight for shelter A is greater than that for shelter B.
The median weight for shelter B is greater than that for shelter A.
The data for shelter A are a symmetric data set.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.

Answers

The statements that are TRUE regarding the box plots are:

A, D, and E.

The box plots are given in the image attached below.

The Five-number Summary Displayed by a Box Plot

The values displayed by a box plot for a given data are:

MedianMinimumMaximumFirst QuartileThird Quartile

Interquartile range = Third Quartile - First Quartile.

Thus, shelter's A median is 21, shelter B's 18.

Interquartile range for shelter A = 28 - 8 = 20

Interquartile range for shelter B = 28 - 10 = 18

What is a Symmetric Data Set?If a data set is symmetric, a box plot that represents the data set will have the median in the middle of the box, while both whiskers will be about the same on both sides of the box.For example, the data set for shelter B is symmetric.

Therefore, the statements that are TRUE regarding the box plots are:

A, D, and E.

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20 points please help me i need this answer The box plots show the weights, in pounds, of the dogs in

x equation 27 x 3/4 =125​

Answers

Answer:

x = 500/81

Step-by-step explanation:

Find the x and y intercepts

Find the x and y intercepts

Answers

Answer:

x:(-1,0),(5,0)

y:(0,-2)

Answer:

see explanation

Step-by-step explanation:

The x- intercepts are where the graph crosses the x- axis

The graph crosses the x- axis at x = - 1 and x = 5 ← x- intercepts

The y- intercept is where the graph crosses the y- axis

The graph crosses the y- axis at - 2 ← y- intercept

solve the system of equations algebraically -5x+2y=4 2x+3y=6

Answers

(-5x+2y=4).2
(2x+3y=6).5

-10x+4y=8
10x+15y=30

[10x+(-10x)]+[15y+4y]=[30+8]

19y=38

y=38/19

y=2

2x+3y=6
2x+3(2)=6
2x=6-6=0

x=0

Step-by-step explanation:

-5x+2y= 4         <==== Multiply entire equation by -3 to get:

15x-6y = -12  

2x+3y= 6          <====  Multiply entire equation by 2 to get :

4x+6y = 12    Add the two underlined equations to eliminate 'y'

19x = 0     so x = 0

sub in x = 0 into any of the equations to find:  y = 2

(0,2)

The ratio of alternative songs to total songs is 9:14. My music library has 308 total songs. How many are NOT alternative songs? (Set up a proportion and solve.)

Answers

Answer:

110

Step-by-step explanation:

Rate or proportion shows the relationship between the variation in the  number of two variables.

Given that the ratio of alternative songs to total songs is 9:14.

Total songs = 308

Since the to every 14 total songs, there is 9 alternative songs.

Thus,

Number of alternative songs = \(\frac{9}{14}\) x 308

                                                = 198

There are 198 alternative songs in the music library.

The number of songs that are NOT alternative songs = 308 - 198

                                                                                         = 110

Thus, there are 110 songs that are NOT alternative songs.

In the following exercises, multiply the binomials. Use any method.
252. (3r − 8)(11r + 1)

Answers

Answer:

Hence the expression \($$(3r-8)(11r+1)=33r^2-85r-8$$\).

Step-by-step explanation:

Explanation

The given expression is (3 r-8)(11 r+1).We have to multiply the given expression.Multiply the (3 r-8) by 1 , multiply the (3 r-8) by 11r then add like terms.

\($$\frac{\begin{matrix}{} & {} & 3r & - & 8 \\ \times & {} & 11r & + & 1 \\ \end{matrix}}\)

___________

\({\frac{\begin{matrix}{} & {} & 3r & - & 8 \\ 33{{r}^2} & - & 88r & {} & {} \\ \end{matrix}}{\begin{matrix}33{{r}^2} & - & 85r & - & 8 \\ \end{matrix}}}$$\)

twice the difference of a number and 5

Answers

Answer:

(# - 5) x 2

or

(# - 5) 2

I think it should look Iike this but I might be wrong.

Two cards are selected at random from a deck of cards with replacement. Find the probability of selecting two kings, a king and a queen (order does not matter), or two queens.

Answers

The probability of selecting two kings, a king and a queen (order does not matter), or two queens is 14/663.

Given that a deck of cards is used, with replacement.

Therefore, the probability of selecting any card is the same for all the cards. Also, we need to find the probability of selecting two kings, a king and a queen (order does not matter), or two queens.

Let us consider each case separately.

Case 1:

Two Kings Two kings can be selected from a deck of cards in C(4, 2) ways.

The total number of ways of selecting two cards is C(52, 2). Hence, the probability of selecting two kings is:

P(King and King) = C(4, 2) / C(52, 2)

                            = (6 x 1) / (52 x 51)

                            = 6 / 1326.

Case 2:

A King and a Queen.

A king and a queen can be selected in 4 x 4 = 16 ways. The total number of ways of selecting two cards is C(52, 2).

Hence, the probability of selecting a king and a queen is:

P(King and Queen) = 16 / C(52, 2)

                                = (16 x 1) / (52 x 51)

                                = 16 / 1326.

Case 3:

Two Queens Two queens can be selected in C(4, 2) ways. The total number of ways of selecting two cards is C(52, 2).

Hence, the probability of selecting two queens is:

P(Queen and Queen) = C(4, 2) / C(52, 2)

                                    = (6 x 1) / (52 x 51)

                                    = 6 / 1326.

Therefore, the probability of selecting two kings, a king and a queen (order does not matter), or two queens is:

P(Two Kings or King and Queen or Two Queens)

= 6 / 1326 + 16 / 1326 + 6 / 1326

= 28 / 1326

= 14 / 663.

Hence, the probability of selecting two kings, a king and a queen (order does not matter), or two queens is 14/663.

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17. What is the area formula?

17. What is the area formula?

Answers

Answer:

Step-by-step explanation:

1/2b×h

Answer:

L x w / 2 or L x w x 1/2

Step-by-step explanation:

Btw the area to that problem is 15 I think


There are 12 students in a high school senior class in how many ways could the yearbook choose the winners of Most Athletic Class
Clown Best School Spirit, Best Looking and Most Likely to Succeed?

Answers

Answer:

28(27)(26) assuming that nobody can get multiple designations.

Step-by-step explanation:

what is the sentence

Answers

Answer: Unclear

Step-by-step explanation: I can't see your image/sentence, so I can't help u

Can yall help me with this math question fast

Can yall help me with this math question fast

Answers

The first step to solve the equation 3x/5 + 5 = 20,

3x/5 + 5 - 5 = 20 - 5

3x/5 (5/3) = 15 (5/3)

is known as Subtraction property of equality, So option B is correct.

What is an Subtraction property of equality?

It is a property of mathematics, in which we subtract the same number on both the sides of any equation.

for example, ax+b = c  ⇒ ax+b-5 = c-5

Given math equation,

3x/5 + 5  = 20

here we apply, Subtraction property of equality

So, we are subtracting -5 both the sides

3x/5 + 5 - 5 = 20 - 5

Hence, Used property is subtraction property of equality

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i need some help with these questions​

i need some help with these questions

Answers

Answer:

yuuu7

Step-by-step explanation:

you know what to do with a different person and you know what to do with a different person 3³333 you know what to do with a different person and you know what to do

find the area of the region enclosed by one loop of the curve. r = sin(10θ)

Answers

The area of the region enclosed by one loop of the curve r = sin(10θ) is π/40.

We have to find the area of the region enclosed by one loop of the curve.

The given curve is:

r = sin(10θ)

Consider the region r = sin(10θ)

The area of region bounded by the curve r = f(θ) in the sector a ≤ θ ≤ b is

A = \(\int^{b}_{a}\frac{1}{2}r^2d\theta\)

Now to find the area of the region enclosed by one loop of the curve, we have to find the limit by setting r=0.

sin(10θ) = 0

sin(10θ) = sin0   or    sin(10θ) = sinπ

So θ = 0             or      θ = π/10

Hence, the limit of θ is 0 ≤ θ ≤ π/10.

Now the area of the required region is

A = \(\int^{\pi/10}_{0}\frac{1}{2}(\sin10\theta)^2d\theta\)

A = \(\frac{1}{2}\int^{\pi/10}_{0}\sin^{2}10\theta d\theta\)

A = \(\frac{1}{2}\int^{\pi/10}_{0}\frac{(1-\cos20\theta)}{2}d\theta\)

A = \(\frac{1}{4}\int^{\pi/10}_{0}(1-\cos20\theta)d\theta\)

A = \(\frac{1}{4}\left[(\theta-\frac{1}{20}\sin20\theta)\right]^{\pi/10}_{0}\)

A = \(\frac{1}{4}\left[(\frac{\pi}{10}-\frac{1}{20}\sin20\frac{\pi}{10})-(0-\frac{1}{20}\sin20\cdot0)\right]\)

A = \(\frac{1}{4}\left[(\frac{\pi}{10}-\frac{1}{20}\sin2\pi)-(0-\sin0)\right]\)

A = 1/4[(π/10-0)-(0-0)]

A = 1/4(π/10)

A = π/40

Hence, the area of the region enclosed by one loop of the curve r = sin(10θ) is π/40.

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A rare disease exists with which only 1 in 500 is affected. A test for the disease exists, but of course it is not infallible. A correct positive result (patient actually has the disease) occurs 95% of the time, while a false positive result (patient does not have the disease) occurs 1% of the time. If a randomly selected individual is tested and the result is positive, what is the probability that the individual has the disease?

Answers

Answer:

The probability that the individual has the disease is 1/500

Step-by-step explanation:

i found the fraction of 1 in 500 which is 1/500, hope this helps :)

7. The quality control division of Rothschild's Blueberry Farm randomly inspects 100 of the containers in the truck being
sent to Stop and Shop. Identify the population and sample given in this scenario.

Answers

The 100 containers that the quality control division of Rothschild's Blueberry Farm randomly inspects.

Population: The containers of blueberries that are being sent to Stop and Shop.

Sample: The 100 containers that the quality control division of Rothschild's Blueberry Farm randomly inspects.

Therefore, the 100 containers that the quality control division of Rothschild's Blueberry Farm randomly inspects.

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john is at a cookout and wants to get a drink from the cooler. if there are 12 class, 10 bottles of water, and 5 root beers in the chest, what is the probability that john grabs a root beer? p(root beer)

Answers

John is likely to choose a root beer from the cooler 5/27 times, or 18.5% of the time.

p(root beer)=5/27=18.5%

John is likely to choose a root beer from the cooler 5/27 times, or 18.5% of the time. Divide the number of root beers in the cooler (five) by the total number of things in the cooler to arrive at this calculation (27). In this instance, the cooler is filled with 12 Coke cans, 10 water bottles, and 5 root beers. Hence, there are 27 things in the cooler, and the likelihood that John will choose a root beer is 5/27. By dividing the fraction by 100, this figure can be stated as a percentage, giving the answer of 18.5%.Hence, John has an 18.5% chance of grabbing a root beer from the cooler.

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Please solve question 6 with steps i’m having so much trouble

Please solve question 6 with steps im having so much trouble

Answers

If you still need help just respond, I'll type it out

MY NOTES ASK YOUR TEACHER Find the local maximum and minimum values and saddle point(s) of the function. If you have three dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function. (Enter NONE In any unused answer blanks.) fx, y)-8-2x+4y-²-4² maximum " (smaller x value) (larger x value) " minimum " (smaller x value) " (larger a value) saddle points Submit Answer ) (smallest x value) ) (largest x value)

Answers

The local maximum and minimum values of the function are as follows: maximum at (smaller x value), minimum at (larger x value), and there are no saddle points.

To find the local maximum and minimum values of the function, we need to analyze its critical points, which occur where the partial derivatives are equal to zero or do not exist.

Let's denote the function as f(x, y) = -8 - 2x + 4y - x^2 - 4y^2. Taking the partial derivatives with respect to x and y, we have:

∂f/∂x = -2 - 2x

∂f/∂y = 4 - 8y

To find critical points, we set both partial derivatives to zero and solve the resulting system of equations. From ∂f/∂x = -2 - 2x = 0, we obtain x = -1. From ∂f/∂y = 4 - 8y = 0, we find y = 1/2.

Substituting these values back into the function, we get f(-1, 1/2) = -9/2. Thus, we have a local minimum at (x, y) = (-1, 1/2).

There are no other critical points, which means there are no local maximums or saddle points. Therefore, the function has a local minimum at (x, y) = (-1, 1/2) but does not have any local maximums or saddle points.

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Are the lines y = 2 and x = 4 parallel, perpendicular, or neither? Explain using complete sentences.

Answers

The lines y = 2 and x = 4 are neither parallel nor perpendicular.

The given lines are y = 2 and x = 4.

The line y = 2 is a horizontal line because the value of y remains constant at 2, regardless of the value of x. This means that all points on the line have the same y-coordinate.

On the other hand, the line x = 4 is a vertical line because the value of x remains constant at 4, regardless of the value of y. This means that all points on the line have the same x-coordinate.

Since the slope of a horizontal line is 0 and the slope of a vertical line is undefined, we can determine that the slopes of these lines are not equal. Therefore, the lines y = 2 and x = 4 are neither parallel nor perpendicular.

Parallel lines have the same slope, indicating that they maintain a consistent distance from each other and never intersect. Perpendicular lines have slopes that are negative reciprocals of each other, forming right angles when they intersect.

In this case, the line y = 2 is parallel to the x-axis and the line x = 4 is parallel to the y-axis. Since the x-axis and y-axis are perpendicular to each other, we might intuitively think that these lines are perpendicular. However, perpendicularity is based on the slopes of the lines, and in this case, the slopes are undefined and 0, which are not negative reciprocals.

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Can some one help me plz I need this to up my grade I dont wanna fail

Can some one help me plz I need this to up my grade I dont wanna fail

Answers

Answer:

Srue what's your question

Step-by-step explanation:

Answer: 3rd answer, 3rd ten, adding was wrong.

Step-by-step explanation:

Just look at it, do the problem, and go back and forth. The answer choices weren't hard.

Other Questions
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