An arrow pointing from the bottom of the ramp to the top, I assume it would be friction.
A student heats the same amount of two different liquids over Bunsen burners. Each liquid is at room temperature when the student begins. If Liquid 1 has a higher specific heat than Liquid 2, then Liquid 1 will
Answer: Liquid 1 heats more slowly than 2
Explanation:
Liquid 1 heats more slowly than 2 because it has a higher specific heat.
(Hope this helps!)
A 750 kg race car accelerates to the right. The engine applies a force of
+7000 N to the car. The total friction on the car in the opposite
direction is -200 N.
Find the net force on the car then use 'Fnet = m a' to find the
acceleration.
O a
b
Oc
Od
12.4 m/s2
10.5 m/s2
8.0 m/s2
9.1 m/s2
An army tank division leaves base and travels 30 miles at [W30*S] and then turns and travels 70 miles at [W10*N]. What is their total displacement from base at the end of the trip?
The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.
How to calculate the displacement?To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.
We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.
To add vectors, we need to break them down into their horizontal and vertical components.
For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).
For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).
Now we can add these components to get the total displacement:
Horizontal component = -30 + 0 = -30
Vertical component = 0 + 70 = 70
So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.
We can use the Pythagorean theorem to find the magnitude of this vector:
|displacement| = √((-30)² + 70²) ≈ 75.9 miles
And we can use trigonometry to find the direction of this vector:
\(\theta = tan^{-1}\dfrac{70} { -30}\)
θ ≈ -67.4°
So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.
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If a person wanted to engineer a new type of communication device, what field of study would be the most useful?
A ) electrical engineering
B ) chemical engineering
C ) optical engineering
D ) mechanical engineering
Answer: Option A: electrical engineering.
Explanation: The field of electrical engineering, sometimes called electronics engineering, mostly outside the US, is a field of engineering that covers a number of subtopics that include large scale power systems, electronics, control systems, signal processing and telecommunications. In this case the engineer would specifically have to know about electronics (computer chips), signal processing (cell signals) and telecommunications.
You have to run 18,900 feet in track. How far is this in miles? Note: There are 5280 feet in 1 mile.
O A. 0.8 mi
O B. 2.4 mi
O C. 1.5 mi
D. 3.6 mi
The conversion factor of 5280 feet per mile is used to convert the distance, and rounding to the nearest tenth gives us approximately 3.6 miles. The correct answer is option D: 3.6 mi.
To convert 18,900 feet to miles, we can use the conversion factor of 5280 feet per mile. By dividing the distance in feet by this conversion factor, we will obtain the equivalent distance in miles.
Distance in miles = 18,900 feet ÷ 5280 feet/mile
Calculating this expression, we find:
Distance in miles = 3.57 miles
Rounding to the nearest tenth, the distance is approximately 3.6 miles.
Therefore, the correct answer is option D: 3.6 mi.
It is important to note that the conversion factor of 5280 feet per mile is derived from the definition of a mile as 5,280 feet. This conversion factor is widely used to convert measurements between feet and miles in various contexts, such as distance calculations, road signs, and sports events. Here option D is the correct answer.
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A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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this is a FRQ test for AP Physics I NEED IT DONE IN 2 HOURS: A dart with mass md
is launched toward a block of mass mb
that is suspended from a string of length L, as shown at left above. The dart is moving horizontally with speed v immediately before it strikes the block and remains embedded. The dart-block system then swings up to a point at which its center of mass reaches a maximum height H above its starting position, as shown at right above. The block’s mass mb
is greater than the dart’s mass md
.
(a) Indicate which object, the dart or the block, if either, experiences an impulse of larger magnitude during the collision. If the impulse is the same magnitude for both objects, state this explicitly. Briefly explain your reasoning.
The dart experiences an impulse of larger magnitude during the collision. This is because the dart has less mass than the block, so the same amount of momentum change will result in a larger impulse.
What is momentum ?Momentum is a physical concept that describes the tendency of an object to remain in motion with the same speed and direction unless it is acted on by an outside force. It is a measure of an object's inertia and is often expressed as the product of its mass and velocity. Momentum is a vector quantity, meaning that it has both magnitude and direction. Momentum is conserved in closed systems, meaning that the momentum before an interaction is equal to the momentum after the interaction. This is known as the law of conservation of momentum and can be used to solve many problems involving collisions and other interactions between objects.
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HELP! An electron is accelerated from 0 m/s to 8 x 10^7 m/s by a uniform electric field. What is the potential difference (voltage) between the plates that make the field?
The potential difference (voltage) between the plates is approximately 1.45 kV.
The kinetic energy of an electron can be related to the potential difference between the plates of an electric field using the equation:
KE = qV,
where KE is the kinetic energy of the electron, q is its charge, and V is the potential difference between the plates.
We know that the electron is accelerated from rest to a final velocity of 8 x 10^7 m/s, so its change in kinetic energy is given by:
ΔKE = 1/2 mv^2 - 1/2 m(0)^2 = 1/2 mv^2
where m is the mass of the electron.
The potential difference between the plates can be found by rearranging the equation to solve for V:
V = ΔKE / q
Substituting the values we have:
V = (1/2) mv^2 / q
The mass of an electron is approximately 9.11 x 10^-31 kg, and its charge is -1.6 x 10^-19 C. Substituting these values and the final velocity of 8 x 10^7 m/s, we get:
V = (1/2) (9.11 x 10^-31 kg) (8 x 10^7 m/s)^2 / (-1.6 x 10^-19 C)
V = -1.45 kV
Therefore, the potential difference (voltage) between the plates is approximately 1.45 kV.
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g:p:e = gravitational field strength x height
gravitational field strength = 9.8N/kg
Answer:
kdfihiyfxnlL chapter kar kaam
Explanation:
off influx teenon Palin
What characterizes moral development in middle and late childhood? Give an Example?
Answer: what characterizes moral development in mid to late childhood is
People at this level of moral development base their decisions on what their parents and/or law enforcement says is right. Stage 3 is about social conformity. ... Stage 4 is all about law and order for all. For example, someone may think, 'If I steal, I will break the law and breaking the law is wrong.Feb 17, 2016
Explanation:
Water has higher specific heat than aluminum. This is all what you should know to answer following questions. An aluminum rod of mass 1 kg at temperature of 80^0C is placed into 1l of water of temperature 10^0C . there is no heat exchange with surroundings. Which material experiences greater change in temperature while system is reaching the thermal equilibrium
Answer:
The Aluminum
Explanation:
With a larger specific heat, water requires more heat to raise its temperature by a temperature degree.
In this system, with equal masses of water and aluminum, the heat moving from the aluminum lowering its temperature by one degree is not sufficient to raise the water temperature by one degree.
As a ball is released inside Earth's gravitational field and begins to fall to the ground
Select one:
A) there is no gravitational potential energy between them
B) the amount of gravitational potential energy stays the same.
C) the amount of gravitational potential energy increases.
D) the amount of gravitational potential energy decreases.
When flying, the pressure inside the cabin of an aircraft is kept at 70 kPa. The aircraft window has an area of 810 cm2 . Use data from Figure 1 to calculate the resultant force acting on an aircraft window when the aircraft is flying at an altitude of 12 km.
The resultant force acting on an aircraft window is 5670 Newton when the aircraft is flying at an altitude of 12 km.
What is pressure?The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. The pressure relative to the surrounding air is referred to as gauge pressure.
The pressure applied = 70 kPa = 70000 Pa.
The cross-sectional rea = 810 cm² = 0.081 m².
Hence, the force applied on the window = 70000 Pa × 0.081 m².
= 5670 Newton.
So, the resultant force acting on an aircraft window is 5670 Newton.
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You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?
Answer:
Explanation:
A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:
Output force = Weight of object = m * g
where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:
Output force = 15 kg * 9.81 m/s^2 = 147.15 N
Therefore, the output force required to lift a 15 kg object would be 147.15 N.
B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.
C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:
Mechanical advantage = Output force / Input force = 40 N / 10 N = 4
So, the ramp multiplies your force by a factor of 4.
Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.
The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?
4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.
The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.
To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.
Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.
ΔE = 4×10^26 W
c = 3×10^8 m/s (speed of light)
Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².
Substituting the values, we have:
Δm = (4×10^26 W) / (3×10^8 m/s)²
Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.
This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.
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Two objects are dropped from a bridge, an interval of 1.0 s apart, and experience no appreciable air resistance. As time progresses, the DIFFERENCE in their speeds
a.
increases.
b.
remains constant.
c.
decreases.
d.
increases at first, but then stays constant.
e.
decreases at first, but then stays constant.
Answer: a
Explanation:
to increase the frequency by 2 octave (s), to 4 f , by what factor would you have to increase the tension
Answer:
16
Explanation:
Since frequency in a stretched string f = (n/2L)√T/μ and n, L and μ are constant, f ∝ √T where T = tension in string
Now f₂/f₁ = √T₂/√T₁
Since f₁ = f (frequency at tension T₁) and f₂ = 4f (since its frequency increases by 2 octaves to 4f at tension T₂).
So,
f₂/f₁ = √T₂/√T₁
4f/f = √T₂/√T₁
√T₂/√T₁ = 4
squaring both sides, we have
(√T₂/√T₁)² = 4²
T₂/T₁ = 16
T₂ = 16T₁
So, the tension would have to increase by a factor of 16
Which quantity describes the gravitational force between two objects?(1 point)
Responses
A the sum of the masses of the two objects divided by the distance between them
B the product of the masses of the two objects divided by the distance between them
C the product of the masses of the two objects divided by the square of the distance between them
D the sum of the masses of the two objects divided by the square of the distance between them
The quantity that describes the gravitational force between two objects is as follows: the product of the masses of the two objects divided by the square of the distance between them (option C).
What is gravitational force?Gravitational force is a very long-range, but relatively weak fundamental force of attraction that acts between all particles that have mass; believed to be mediated by gravitons.
It is called the gravitational force attraction because it always tries to pull masses together, it never pushes them apart.
The gravitational force of an object can be calculated using the following formula:
F = Gm1m2/r²
Where;
F = gravitational forceG = gravitational constantm1 and m2 = masses of objectr = distance between objectsTherefore, the product of the masses divided by the square of the distance is how gravitational force is calculated.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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You have two electrical devices plugged into the same socket in parallel and draws 120 V. The first device has a resistance of 20 Ω the other device has a resistance of 10 Ω.
What is the total resistance?
The devices don't "draw" 120v. The 120v comes to your house from the power company. They decide it should be 120v and that's what they send you. It's hypothetically technically possible for you to change that, but if you try it, you'll definitely burn the house down.
The total resistance of those two devices in parallel is 6 and 2/3 ohms. That doesn't depend on what they're plugged into. It would still be 6 and 2/3 ohms if they were connected in parallel, wrapped in tissue, sealed in a jar of chicken soup and stored in a box on a high shelf.
But since they ARE plugged into 120v, they draw 18 Amperes from the socket, and they turn all of that electrical energy into 2160 watts of heat. That's about the same as a good size toaster oven, and you have to figure out a way to get rid of all that heat before you burn the house down.
Calculate the volume of a parallelepiped with sides give as
a
=
(
7,2
,
4
)
,
b
=
(
4,7
,
6
)
and
c
=
(
3,4
,
7
)
Select one:
105
cubic units
125
cubic units
115
cubic units
135
cubic units
To calculate the volume of a parallelepiped given the sides, we can use the scalar triple product. The formula for the volume of a parallelepiped with sides a, b, and c is:
Volume = |a · (b × c)|
where · represents the dot product and × represents the cross product.
Using the given sides:
a = (7, 2, 4)
b = (4, 7, 6)
c = (3, 4, 7)
First, calculate the cross product of b and c:
b × c = (7*7 - 4*4, 6*3 - 7*7, 4*4 - 2*3)
= (49 - 16, 18 - 49, 16 - 6)
= (33, -31, 10)
Next, calculate the dot product of a and the cross product (b × c):
a · (b × c) = 7*33 + 2*(-31) + 4*10
= 231 - 62 + 40
= 209
Finally, take the absolute value of the result to obtain the volume:
Volume = |209| = 209 cubic units
Therefore, the correct answer is:
209 cubic units
which particles do not affect the stability of the atom
Electrons are the particle pr4esent inside the atom that does not affect the stability of the atom,
What is radioactivity?The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.
An overabundance of neutrons or protons can make the nucleus of an atom unstable.
A radioactivity atom will try to become stable by extruding other particles, such as protons or neutrons, or by releasing energy in various ways.
Thus, Electrons are the particle present inside the atom that does not affect the stability of the atom,
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When does a scatter plot show a correlation?
Answer:
Mark brainliest please
Explanation:
If the data points make a straight line going from the origin out to high x- and y-values, then the variables are said to have a positive correlation .When there is no clear relationship between the two variables, we say there is no correlation between the two variables.
If a quantity of heat equal to the magnitude of the change in mechanical energy of the water goes into the water, what is its increase in temperature
Rocks in the asteroid belt are traveling around the Sun at a distance of 3.2 Astronomical Units (AU). According to Kepler's Third Law, what is the orbital period of these rocks?
Recall Kepler's Third Law can be written as
P 2 = a 3
if the period is measured in (Earth) years and the distance is measured in AU. Follow the steps in Example 3.1 (just with a different distance value).
Pick the answer that's closest to your result:
The orbital period of the rocks in the asteroid belt is approximately 5.73 years.
What is the average distance, a, between the sun and the asteroid, expressed in astronomical units?
The distance from the Sun to the asteroid belt is between 2-4 AU, or between 300 and 600 million kilometers (186-272 million mi).
Using Kepler's Third Law, we have:
P² = a³
where P is the orbital period of the rocks in years, and a is the semi-major axis of their orbit in astronomical units (AU).
Substituting a = 3.2 AU, we get:
P² = (3.2 AU)³
P² = 32.768 AU³
P = \(\sqrt{32.768}\) years
P ≈ 5.73 years
Therefore, the orbital period of the rocks in the asteroid belt is approximately 5.73 years.
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Pete is driving down 7th street. He drives 0.150km in 18 seconds. Assuming he does not speed up or slow down, what is his speed in meters per second?
Answer:
150m/s
Explanation:
0.150km to m is multiplying by 1000.
Find the Magnitude of the resultant vector (the actual
path of the boat).
The picture is a little blurry, so here are the stats:
Velocity of the boat is 0.75 m/s
Velocity of the river is 1.2 m/s
The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.
To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.
Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.
To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:
Resultant magnitude = √(boat velocity^2 + river velocity^2)
Plugging in the given values, we have:
Resultant magnitude = √(0.75^2 + 1.2^2)
= √(0.5625 + 1.44)
= √2.0025
≈ 1.42 m/s
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Calculate the net force on the particle q1.
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
in each of the images, two blocks are attached to a balance. Use the position and size of the blocks to determine which block is more dense in each image.
A scale weighs two boxes. The green box on the left has a large volume and pulls lower on the scale. The blue box on the right has a smaller volume and is higher on the scale.
Which block is more dense in the first image?
Which block is more dense in the second image?
Which block is more dense in the third image?
First image: Green block is larger and heavier than the blue block.
Second image: Blue and green block are the same size, but blue is heavier
Third image: Green block is smaller and heavier than the blue block
It is impossible to estimate the relative density of the blocks. The rightmost blue chunk is denser. The chunk of green on the left is denser. The mass of a material per unit volume is the definition of density.
Describe density with an example:Its density refers to how much material can fit into a specific quantity of space. For instance, a block of lead (Pb), which is heavier and less durable, will have a lower density than a block of gold (Au), which is stronger and lighter (Au).
Mass and density: what are they?The term "mass" refers to a thing's total amount of matter. The term "density" describes how tightly atoms are packed or how close together they are in a material. To calculate inertia, utilize the idea of mass.
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When work is done by the force of gravity, the path that the object takes isn't important. What matters
is the object's change in height, regardless of the path taken to get there. We have already discussed
that when there is a net force on an object, it's kinetic energy changes. We can see that in the
previous example of the brick falling towards the Earth over a distance h. As it falls the net force on it
is F,-mg, and it gains kinetic energy as it falls. Let's consider what must happen before the brick
falls. If the brick starts on the ground, let's assume that someone has to lift it up a distance h before it
falls.
10) If you lift a brick (mass m) up a distance h, what is the minimum force you need to apply to the
brick to lift it up?
11) If you apply that much force to the brick, how much work does your force do on the brick over the
distance h?
12) While lifting the brick, what is the net force acting on the brick?
13) While you are lifting up the brick, the net force on it is zero. Therefore, the net work done on the
brick is zero, and its kinetic energy remains the same. However, your force is still doing work on
the brick. If it's not causing a gain of kinetic energy then what is that work doing?
Answer:
Explanation:
10) mg
11) mgh
12) 0
13) Increasing potential energy