what is the difference between test tube and boiling tube​

Answers

Answer 1

Test tubes heat small amounts of liquids while boiling tube boils liquids


Related Questions

Which is mainly responsible for preventing erosion?

A) Mining
B) Farming
c) Rooting of Plants
D) Logging

Answers

Answer:

B. Farming

Explanation:

A mass of 1.71 g pure barium hydroxide is transferred quantitatively to a 250 cm3
volumetric flask and made up to the mark with distilled water. Using a pipette, 25.0 cm3
of the barium hydroxide solution are placed in a conical flask and a few drops of methyl
orange indicator are added. Hydrochloric acid is added slowly from a burette until the
endpoint is reached. The titre value is 12.6 cm3



What will the colour change of the indicator at the endpoint be?

Answers

The methyl orange indicator will change from red to yellow at the titration's endpoint.

How can the color of the indicator's change at the terminus be determined?

An acid-base indicator called methyl orange changes color between the pH ranges of 3.1 and 4.4. In acidic and basic solutions it is red and yellow, respectively

In this instance, an acid, hydrochloric acid, is being used to titrate the barium hydroxide solution. The pH of the solution will fall as we add the acid since it will neutralize the base. The hue of the methyl orange indicator will vary when the pH ranges from 3.1 to 4.4

All of the barium hydroxide will have interacted with the hydrochloric acid by the time the titration is complete leaving a neutral solution. When the methyl orange indicator becomes yellow the solution's pH is in the basic range.

Therefore, the methyl orange indicator will change from red to yellow at the titration's endpoint.

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1. Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group 14) and oxygen (Group 16) would be attached to one another. In carbon dioxide (CO2), how is the compound structured? (Use “–” to represent a single bond and “=” to represent a double bond.)(1 point)

A) O=C–O

B) O=C=O

C) C=O–O

D) C–O–O

2. Methane’s chemical formula is CH4. Is there a bond between any of the hydrogen atoms? Why or why not?(1 point)

A) Yes, there is because they form a long chain in order to all have stable outer energy shells.

B) Yes, there is because there are one too many hydrogen atoms for carbon to handle alone, so one hydrogen must bond with another.

C) No, there is not because carbon needs four bonds, so it bonds with each hydrogen atom; hydrogen only forms one bond.

D) No, there is not because it would form H2 instead of methane if hydrogen-bonded with itself.

3. In hydrogen peroxide (H2O2), which option best shows how the atoms are ordered?(1 point)

A) H–O–O–H

B) O–H–O–H

C) H–O–H–O

D) O–H–H–O

Answers

From the fact that oxygen is in group 16 and carbon is in group 14, the structure of CO2 must be O=C=O. In methane, there is no bond between any of the hydrogen atoms. The structure of H2O2 is H–O–O–H.

Carbon is in group 14 hence it has four valence electrons and oxygen is in group 16 hence it has six valence electrons. This implies that each oxygen atom will share four electrons with carbon in a covalent bond to form the structure O=C=O.

In CH4, we know that carbon is tetravalent so it forms for bonds. Therefore, there is no bond between hydrogen atoms so it bonds with each hydrogen atom; hydrogen only forms one bond.

In H2O2, there is the peroxide ion that has the structure O-O. Hence, the correct structure of H2O2 is H–O–O–H.

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1. Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group

Consider the incorrectly balanced combustion equation:
2C6H6 + 602 => 12CO2 + 6H2O
Select ALL elements that are not balanced.
Carbon
Hydrogen
Oxygen

Answers

Oxygen is balanced incorrectly.
The correct balanced equation: 2C6H6+15O2=12CO2+6H2O

what are the products of pent-1-ene + hydrogen

Answers

Answer:

But-1-ene is another unsymmetrical alkene. As with all alkenes, unsymmetrical alkenes like propene react with hydrogen bromide in the cold. The double bond breaks and a hydrogen atom ends up attached to one of the carbons and a bromine atom to the other. In the case of propene, 2-bromopropane is formed.

Explanation:

how to find number of moles of metal for trial one?

how to find number of moles of metal for trial one?
how to find number of moles of metal for trial one?

Answers

The equation of our reaction is:

Mg (s) + 2 HCl (aq) ----> MgCl₂ (aq) + H₂ (g)

According to the coefficients of the reaction 1 mol of Mg will react with 2 moles of HCl to produce 1 mol of MgCl₂ and 1 mol of H₂.

So 1 mol of H₂ is produced by 1 mol of Mg. We can use that relationship to find the number of moles of Mg (metal).

1 mol of H₂ = 1 mol of Mg

moles of Mg = 0.00165 moles of H₂ * 1 mol of Mg/(1 mol of H₂)

moles of Mg = 0.00165 moles

Answer: 0.00165 moles of metal

mass of the metal = 0.039 g

moles of metal = 0.00165 moles

molar mass of metal = 0.039 g/0.00165 moles

molar mass of metal = 23.63 g/mol

Answer: 23.63 g/mol is the molar mass of the metal

How can a large object and a small object have equal momentum?

Answers

Answer:

answer

Explanation:

An object that has a small mass and an object that has a large mass have the same momentum. ... Since the kinetic energy of an object is momentum times of speed. Therefore, for the same momentum, the mass of higher speed will have more energy i.e. the smaller mass.

In cells, __________ are proteins that are needed to lower the amount of energy required to start chemical reactions

Answers

Answer: I think it’s enzymes

Explanation:

A compound of P and F was analyzed as follows: heating 0.2324 g of the compound in a 378-cm3 container turned all of it to gas, which had a pressure of 97.3 mmHg at 77°C. Then the gas was mixed with calcium chloride solution, which turned all of the F to 0.2631 g of CaF2. Determine the molecular formula of the compound.

Answers

The molecular formula of the compound is determined as P₂F₄.

What is meant by molecular formula?

Molecular formula tells us which atoms and how many of each type of atom are present in the molecule.

Molar mass of CaF₂ is 78.07 g/mol(0.2631 g  CaF₂) × (1 mol  CaF₂ / 78.07 g  CaF₂) = 0.00337 mol  CaF₂

2F- + Ca₂+ →  CaF₂

(0.00337 mol  CaF₂) × (2 mol F / 1 mol  CaF₂) = 0.00674 mol F

As, Molar mass of F is 18.9984 g/mol

So, (0.00674 mol F) × (18.9984 g F / 1 mol F) = 0.12805 g F

1 mmHg = 0.00131578947 atm

(97.3 mmHg) × (0.00131578947 atm / 1 atm) = 0.128 atm

(378 cm³) × (1L / 1000 cm³) = 0.378 L

Now, T = 77 + 273 = 350 K

As, PV = nRT

n(PxFy) = PV / RT

n(PxFy) = (0.128 atm × 0.378 L) / (0.0821 L atm mol-1 K-1 × 350 K) = 0.001684 mol

n(PxFy) = 0.001684 mol

n(PxFy) = m(PxFy) / M(PxFy)

M(PxFy) = m(PxFy) / n(PxFy) = (0.2324 g) / (0.001684 mol) = 138 g/mol

m(PxFy) = m(P) + m(F)

0.2324 g = m(P) + 0.12805 g

m(P) = 0.2324 - 0.12805 = 0.10435

m(P) = 0.10435 g

Molar mass of P is 30.9737 g/mol

so, (0.10435 g P) × (1 mol P / 30.9737 g P) = 0.003369 mol P

Now, n(P) : n(F) = 0.003369 mol : 0.00674 mol = 1 : 2

Therefore, empirical formula of PxFy is PF₂

Molar mass of PF₂ 68.9705 g/mol

Molecular formula of PxFy is ( PF₂)n

n = M(PxFy) / M( PF₂) = (138) / (68.9705) = 2

Therefore, the molecular formula of PxFy is P₂F₄.

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Which type of molecule gives plants their firm structure?
A. Carbohydrates
B. Lipids
C. Nucleic acids
D. Proteins
??

Answers

The type of molecule which gives plants their firm structure Carbohydrates   (option A) as there develop cellular structures like cell walls or stems .

What are the importance of carbohydrates to plants?

Complex organic compounds called carbohydrates serve multiple functions for plants- primarily as their primary energy source and secondly to build specific cellular structures like cell walls or stems. Undoubtedly, one of the most ubiquitous types of carbohydrates seen in these green wonders is cellulose which plays a dominant role in maintaining their structural integrity.

Cellulose consists of tightly intertwined chains formed by glucose molecules whose interaction results in exceptional durability making it paramount for plant rigidity and survival alike.

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Evaporation Rate
Various Compounds
The data below shows the change in
temperature when 4 different compounds
are exposed to room temperature air for
over 2 minutes.
Compound Temperature
Change (C)
A
B
"C
-12.5
-9.2
-7.6
-4.8
D
Type of IMF
DF
DF
DF, DD
DF, DD, HB
DF-dispersion forces, DD-dipole-dipole,
HB-hydrogen bonding
What is the likely cause for the
difference in evaporation
points of the compounds A
and D?
A. The atoms have different types of bonds
holding the molecule together.
B. The molecules have different amounts of
dispersion forces.
C. The molecules have different numbers of
oxygen atoms.
D. The molecules have different
intermolecular forces.

Evaporation RateVarious CompoundsThe data below shows the change intemperature when 4 different compoundsare

Answers

The atoms have different types of bonds holding molecules together and leads to evaporation.

Thus, A crucial stage in the Earth's water cycle is evaporation, which is the process by which water transforms from a liquid to a gas or vapor. Evaporation at the molecular level requires the interface to break at least one extremely strong intermolecular connection between two water molecules.

The chemical mechanism by which an evaporating water molecule acquires sufficient energy to escape from the surface has remained mysterious despite the significance of this activity.

Here, we demonstrate that the high kinetic energy of the evaporated water molecule is enabled by a precisely timed formation and dissolution of hydrogen bonds involving at least three water molecules at the interface, the recoil of which allows one water molecule to escape.

Thus, The atoms have different types of bonds holding molecules together and leads to evaporation.

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The reactant concentration in a zero-order reaction was 8.00×10−2 M
after 140 s and 4.00×10−2 M after 400 s
. What is the rate constant for this reaction?

Answers

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.

Determining the rate constant

The rate of the reaction is given by the equation:

Rate = -k[A]

where k is the rate constant and [A] is the concentration of the reactant.

Rate at t=140 s:

Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)

= 5.71×10−4 M/s

Rate at t=400 s:

Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)

= 1.00×10−4 M/s

Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:

k = Rate / [A]

Using the rate at t=140 s:

k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1

Using the rate at t=400 s:

k = 1.00×10−4 M/s / 4.00×10−2 M

= 2.50×10−3 s−1

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.

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Which has a higher lattice energy? Na3n or Na2O. And why?

Answers

Because the extent of ionic charge is more important than ionic radius in calculating the lattice energy of ionic compounds. Because the ionic charge of the N3-ion is greater than that of the F-ion, the Na3N molecule has a higher lattice energy than the NaF complex.

The lattice energy increases when the ion charge variable is increased. As a result, ions with higher charge values generate ionic compounds with higher lattice energies. As a result, ions with lower charges lower the lattice energies of their compounds.

C6H12O6 + 602 → 6CO2 + 6H₂O
The most efficient ratio is
1 C6H12O6 6 02.
Which set of reactants will be the most
efficient (least wasteful of materials) for
the reaction?
A. 1.0 mol C6H12O6 and 3.0 mol O₂
B. 1.5 mol C6H₁2O6 and 3.0 mol O₂
C. 3.0 mol C6H₁2O6 and 6.0 mol O₂
D. 0.5 mol C6H₁2O6 and 3.0 mol O₂

Answers

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

The element X has three naturally occurring isotopes. The isotopic masses (amu) and % abundances of the isotopes are given in the table below. Calculate the average atomic mass of the element in amu. PLEASE HELP ASAP THANK YOU SO MUCH

The element X has three naturally occurring isotopes. The isotopic masses (amu) and % abundances of the

Answers

Answer:

162.35 amu

Explanation:

Let A represent isotope X-159

Let B represent isotope X-163

Let C represent isotope X-164

The following data were obtained from the question:

Isotope >>> Abundance >>> Mass no

A >>>>>>>> 30.60 >>>>>>>> 159.37

B >>>>>>>> 15.79 >>>>>>>>> 162.79

C >>>>>>>> 53.61 >>>>>>>>> 163.92

Average Atomic mass =.?

The average atomic mass of element X can be obtained as follow:

Average atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100]

= [(159.37 × 30.60)/100] + [(162.79 × 15.79)/100] + [(163.92 × 53.61)/100]

= 48.77 + 25.70 + 87.88

= 162.35 amu

Therefore, the average atomic mass of element X is 162.35 amu

Which statements describe inorganic compounds? Check all that apply
Inorganic compounds contain carbon
Inorganic compounds usually lack carbon
Inorganic compounds are not associated with or made from living things,
Inorganic compounds include fruits and vegetables,
Inorganic compounds include salt and water​

Answers

Answer:

b, c, e

Explanation:

Inorganic compounds usually lack carbon.

Inorganic compounds are not associated with or made from living things.

Inorganic compounds include salt and water​.

Answer:

yes the answer id bce

Explanation:

what volume litters of oxygen would be ptoduced in the electrolysis which forms 548 litters of hydrogen both gases measured at stp?

Answers

The ideal gas law may be used to determine the volume of oxygen created in the electrolysis that produces 548 litres of hydrogen at STP (Standard Temperature and Pressure). PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature, according to the ideal gas equation.

The pressure is 1 atm, the temperature is 273 K, and the number of moles of hydrogen is 548/22.4 = 24.5 in this example. We may compute the volume of oxygen created by rearranging the ideal gas law: V = nRT/P = 24.5*0.082*273/1 = 483.3 litres.

As a result, the volume of oxygen created in the electrolysis at STP that produces 548 litres of hydrogen is 483.3 litres.

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:
CaC2(s) + 2H2O(l) → C2H2(g) + Ca(OH)2(s)ΔH = −414kJ
In the second step, acetylene, carbon dioxide and water react to form acrylic acid:
6C2H2(g) + 3CO2(g) + 4H2O(g) → 5CH2CHCO2H(g)ΔH = 132kJ
Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water, and carbon dioxide from these reactions. Round your answer to the nearest kJ.

Answers

Answer:

ΔH = -470.4kJ

Explanation:

It is possible to sum 2 or more reactions to obtain the ΔH of the reaction you want to study (Hess's law). Using the reactions:

1. CaC2(s) + 2H2O(l) → C2H2(g) + Ca(OH)2(s)ΔH = −414kJ

2. 6C2H2(g) + 3CO2(g) + 4H2O(g) → 5CH2CHCO2H(g)ΔH = 132kJ

6 times the reaction 1.

6CaC2(s) + 12H2O(l) → 6C2H2(g) + 6Ca(OH)2(s)ΔH = −414kJ*6 = -2484kJ

This reaction + 2:

6CaC2(s) + 3CO2(g) + 16H2O(l) →  + 6Ca(OH)2(s) + 5CH2CHCO2H(g) ΔH = -2484kJ + 132kJ = -2352kJ

As we want to calculate the net change enthalpy in the formation of just 1 mole of acrylic acid we need to divide this last reaction in 5:

6/5CaC2(s) + 3/5CO2(g) + 16/5H2O(l) →  + 6/5Ca(OH)2(s) + CH2CHCO2H(g) ΔH = -2352kJ / 5

ΔH = -470.4kJ

Scientists have discovered marine fossils in rock layers all over the world. The discovery is supported by the story of what in the Bible A Adam and Eve B Cain and Abel C Noah’s ark d Daniel in the lion’s den

Answers

Answer:

d. lions den

Helpful or not?

Answer: Noah’s ark

Explanation:

The flood is what killed everything

Which is the balanced equation for V2O5 + CaS → CaO + V2S5?
V2O5 + CaS → CaO + V2S5
5V2O5 + 5CaS → 10CaO + 5V2S5
3V2O5 + 3CaS → 3CaO + 3V2S5
V2O5 + 5CaS → 5CaO + V2S

Answers

To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. Therefore, the correct option is option D.

What is Balanced equation?

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.

The other characteristic of balanced reaction is that physical state should be written with each compound or molecule on reactant and product side. Physical state should be written in brackets. s means solid, l means liquid, g means gas.

The balanced equation for V\(_2\)O\(_5\) + CaS → CaO + V\(_2\)S\(_5\) is

V\(_2\)O\(_5\) + 5CaS → 5CaO + V\(_2\)S\(_5\)

Therefore, the correct option is option D.

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Nombre para la siguiente estructura de compuesto orgánico

Nombre para la siguiente estructura de compuesto orgnico

Answers

Explanation:

Introducción:

La designación de los compuestos orgánicos puede hacerse utulizando alguno de los

siguientes sistemas:

a) Mediante nombres triviales o comunes, que expresen alguna propiedad característica

(sabor, color, acción fisiológica, etc.) o hagan referencia a la materia de la cual se extrajo el

compuesto.

b) Mediante nombres racionales que proporcionen una idea de su constitucion química y

destaquen sus analogías estructurales.

La necesidad de una nomenclatura sistemática, que expresara en forma clara, conforme

a normas precisas, el nombre y la estructura de los compuestos orgánicos, ha sido motivo de

preocupación permanente y observada a través de los numerosos congresos internacionales

que, al efecto, se han realizado en diversas oportunidades.

Las bases del actual sistema de nomenclatura fueron establecidas por una comisión que

se reunió en Ginebra en 1892. Posteriormente, fue perfeccionado y ampliado por el Comité de

Nomenclatura de la Unión Internacional de Química Pura y Aplicada, por lo que se conoce

como sistema I.U.P.A.C. (International Union of Pure and Applied Chemistry).

En las reglas aprobadas se ha tratado de introducir los menores cambios posibles a la

terminología universalmente adoptada. El sistema tiene la necesaria flexibilidad como para

adaptar la forma precisa de las palabras, de las terminaciones, etc. a las características de

distintos idiomas.

El nombre de los hidrocarburos consta de tres partes: a) la raíz, que indica el esqueleto

carbonado; b) la terminación o sufijo, que indica el grado de saturación, y c) el prefijo que

diferencia las distintas estructuras isoméricas (distintas estructuras construidas con exactamente

los mismos átomos).

Ej.: CH3-CH2-CH2-CH2-CH3 pentano (tambien llamado n-pentano)

penta: raíz que señala el número de átomos de carbono que componen la cadena principal

del compuesto.

-ano: sufijo que indica que el hidrocarburo es saturado

A car's engine block is made of steel and has a mass of 21080g. How much heat (J) is absorbed by the engine block when its temperature is raised from 20°C to 90°C? ​

Answers

The heat absorbed by the engine block when its temperature is raised from 20°C to 90°C is 665,640 J.

To calculate the heat absorbed by the engine block, we can use the equation:

Q = mcΔT

where Q is the heat absorbed, m is the mass of the engine block, c is the specific heat capacity of steel, and ΔT is the change in temperature.

First, we need to calculate the specific heat capacity of steel. The specific heat capacity of steel is typically around 0.45 J/g°C.

Using this value and the given values of mass and temperature change, we can calculate the heat absorbed by the engine block as follows:

Q = (21080 g) x (0.45 J/g°C) x (90°C - 20°C)

Q = 21080 g x 0.45 J/g°C x 70°C

Q = 665,640 J

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benzen has a boiling point of 80.10 c we know the change in boiling point for a solution of c6h14 in benzen is 2.25 what is the new boiling point for the solution

bp= ? c

Answers

The pressure of the environment affects the liquid's boiling point. The boiling point of the liquid is higher when it is under high pressure than when it is under normal atmospheric pressure. For a given pressure, various liquids have different boiling points.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapour all affect its boiling point.

We know that change in temperature of a system is given by the following formula:

Initial boiling point (T₁) = 80.1 °C

ΔT = T₂ - T₁

2.25 = T₂ - 80.1

T₂ = 82.35  °C

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Answer:

82.35

Explanation:

acellus

Which of the following describes the role of water in supporting the chemical reactions that occur within various life forms?

It is a non-polar molecule with weak hydrogen boding.
It is critical in the process of cellular respiration.
It has a huge electronegativity difference between its atoms.
It allows sunlight to pass through it.

Answers

Answer:

It's critical in the process of cellular respiration

It is critical in the process of cellular respiration; is the correct answer; as water plays a very important role in transportation of oxygen and maintaining cell structure.

What is cellular Respiration ?

The process by which organisms combine food molecules with oxygen to form energy , which is used for life sustaining activities is called Cellular Respiration.

Carbon Di-Oxide and Water are produced as by products.

Water acts as a solvent in facilitating the transport of oxygen in respiration.

At the molecular level, water permits everything inside the cell to have the proper structure which is very important for biological processes.

Hence option B , i.e. It is critical in the process of cellular respiration; is the correct answer.

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Describe the advantages of the hydrogen-rich fuel cell when compared to the conventional electrochemical cells such as lead-acid battery. (4)​

Answers

The hydrogen-rich fuel cell offers advantages in terms of efficiency, environmental impact, operating time, refueling speed, weight, size, and lifespan when compared to conventional electrochemical cells like the lead-acid battery.

The hydrogen-rich fuel cell offers several advantages over conventional electrochemical cells like the lead-acid battery. Here are some of the key advantages:

1. Higher Efficiency: Hydrogen fuel cells have higher energy conversion efficiencies compared to lead-acid batteries. Fuel cells can convert chemical energy directly into electrical energy with minimal loss, while lead-acid batteries have inherent energy losses due to factors such as internal resistance and heat dissipation.

2. Clean and Environmentally Friendly: Hydrogen fuel cells produce electricity through the reaction of hydrogen and oxygen, with water being the only byproduct. They do not produce harmful emissions or contribute to air pollution, making them a cleaner and more sustainable power source compared to lead-acid batteries, which require the use of chemicals like sulfuric acid.

3. Longer Operating Time: Fuel cells have longer operating times compared to lead-acid batteries. Lead-acid batteries have a limited capacity and need to be recharged frequently, while fuel cells can continuously generate electricity as long as there is a supply of hydrogen.

4. Faster Refueling: Refueling a fuel cell is faster compared to recharging a lead-acid battery. Fuel cells can be refueled by replenishing the hydrogen supply, which can be done relatively quickly. In contrast, lead-acid batteries require a longer time to recharge, typically hours, depending on the battery's capacity and charging rate.

5. Lighter Weight and Compact Size: Hydrogen fuel cells have a higher energy density compared to lead-acid batteries, meaning they can store more energy in a smaller and lighter package. This makes fuel cells more suitable for applications where weight and space are critical, such as in portable devices or electric vehicles.

6. Longer Lifespan: Fuel cells generally have a longer lifespan compared to lead-acid batteries. Lead-acid batteries can experience degradation over time due to factors like sulfation, which can reduce their overall capacity and lifespan. Fuel cells, on the other hand, can provide consistent performance over an extended period with proper maintenance.

These advantages make fuel cells a promising technology for various applications, including transportation, stationary power generation, and portable electronics.

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PLEASE HELP WITH THIS CHEMISTRY!! It is on elements, shells, charges etc. This is year eight to nine work so easy for most you just have to finish the table pleasee help i’ll give you brainliest!

PLEASE HELP WITH THIS CHEMISTRY!! It is on elements, shells, charges etc. This is year eight to nine

Answers

Answer:

substances

broken

118

shiny or lustrous

conductor

electricity

two

combined

Explanation:

calculating formal charge

calculating formal charge

Answers

The carbonate ion has the simplest oxo carbon anion structure. One carbon atom is surrounded by three oxygen atoms in a trigonal planar arrangement, giving it D3h molecular symmetry. Its molecular mass is 60.01 g/ mol and its formal charge overall is HCO3.

Explain about the structure of carbonate ion?

Carbonate Organization its structure is a trigonal planar arrangement of three oxygen atoms surrounding a carbon atom. Two single bonds to the negative oxygen atom and two double bonds to the neutral oxygen atom make up the carbonate ion's Lewis structure.

The carbonate ion, a salt of carbonic acid, is the most basic form of the oxo carbon anion. A polyatomic ion, it has the chemical formula CO32-. The term "carbonate" can also refer to a carbonate ester, an organic molecule with the carbonate group C(=O)(O-)2.

The carbonate has a valency of two because it may combine with two hydrogen atoms.

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Strontium hydroxide reacts with hydrobromic acid to produce Strontium bromide and
water.
Write and balance the chemical reaction above, use it for problems 1-4 below:
1. If 5.50 moles of strontium hydroxide were consumed, how much moles of water are
produced?
2. Find the mass of hydrobromic acid used to produce 7.50 moles water.
3. If 10.8 g of strontium hydroxide were used, how much moles of strontium bromide are
produced?
4. If 13.3 g of hydrobromic acid were consumed, find the mass of the water produced.

Answers

The chemical reaction for the reaction of strontium hydroxide with hydrobromic acid is:

Sr(OH)2 + 2 HCl --> SrCl2 + 2 H2O

To find the moles of water produced when 5.50 moles of strontium hydroxide are consumed, we need to apply the law of conservation of mass. The mass of water produced is equal to the mass of strontium hydroxide consumed. Since strontium hydroxide has a molar mass of 142 g/mol and water has a molar mass of 18 g/mol, 1 mol of strontium hydroxide can produce 9 mol of water. Therefore, 5.50 moles of strontium hydroxide can produce 49.5 mol of water.

Similarly, 7.50 moles of water can be produced by reacting 18 moles of hydrobromic acid with strontium hydroxide. Hydrobromic acid has a molar mass of 79.9 g/mol, so 18 moles of hydrobromic acid would have a mass of 79.9 * 18 = 1435.2 g.

To find the moles of strontium bromide produced when 10.8 g of strontium hydroxide is used, we need to apply the law of conservation of mass again. The mass of the strontium bromide produced is equal to the mass of strontium hydroxide consumed. Since strontium bromide has a molar mass of 410 g/mol and strontium hydroxide has a molar mass of 142 g/mol, 1 mol of strontium bromide can consume 3.23 moles of strontium hydroxide. Therefore, 10.8 g of strontium hydroxide can produce 10.8 / 3.23 = 3.34 moles of strontium bromide.

Finally, to find the mass of water produced when 13.3 g of hydrobromic acid is consumed, we need to apply the law of conservation of mass yet again. The mass of the water produced is equal to the mass of hydrobromic acid consumed. Since hydrobromic acid has a molar mass of 79.9 g/mol, 13.3 g of hydrobromic acid would produce 13.3 / 79.9 = 0.166 moles of water.

Which treatment(s) will help remove contaminants from minerals or from the pipes carrying water from a source? you can select more than one (Water Contamination Gizmos) **ONLY ANSWER IF YOU ACTUALLY KNOW ❗️❗️**
answer choices:
Sedimentation
Disinfection
Filtration
Coagulation

Which treatment(s) will help remove contaminants from minerals or from the pipes carrying water from

Answers

Sedimentation, filtration, and coagulation are the treatments that will help remove contaminants from minerals or from the pipes carrying water from a source.

Sedimentation is a process in which suspended particles settle out of water. It is one of the most basic techniques for removing particles from water. As particles settle, they become trapped in the bottom of a container or settle to the ground in an outdoor setting

Filtration is a method of removing particles from a fluid. It is a physical or chemical separation method that separates solids from fluids (liquids or gases) by adding a medium through which only the fluid can pass.

Coagulation is the process of using chemicals to remove contaminants from water. By creating a chemical reaction, coagulation destabilizes particles and causes them to clump together. This helps to remove the contaminants from the water.

Disinfection is the process of eliminating or destroying pathogens that cause infection. Disinfection eliminates harmful microorganisms by destroying or inactivating them. The disinfectant is a chemical or physical agent that is used to destroy or inactivate harmful microorganisms.

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Reflect on the learning activities titled “Hypothesis”, “Variables and Hypothesis” and “Constructing a Hypothesis”. Describe some similarities and differences between a question that comes in response to an observation, and a scientific research question? Cite quotes from the readings to support your answer. Where do variables fit into this thinking? In other words, if you imagine a number line with observation questions at one end and scientific research questions at the other, what role do variables play anywhere along this continuum?

Answers

The learning activities titled "Hypothesis," "Variables and Hypothesis," and "Constructing a Hypothesis" all share certain similarities and differences. A question that arises in response to an observation is similar to a scientific research question in that both require some level of investigation to achieve an answer. However, scientific research questions are typically more specific and refined, with a defined methodology for obtaining data and verifying results.

The following quotes from the readings illustrate this distinction:"A scientific question is one that can be answered by using scientific investigation. In contrast, an observation question is one that comes in response to observing or experiencing something in the natural world" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."An important feature of a scientific question is that it should be answerable within a reasonable amount of time and with the resources available" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Research questions can be narrow or broad, depending on the scope of the research" (Constructing a Hypothesis).The concept of variables is crucial to both observation and scientific research questions, but they play different roles depending on where they fall on the continuum. Observation questions are usually less precise and may not require much consideration of variables. On the other hand, scientific research questions are likely to include a rigorous examination of variables and their potential effects."Variables are an essential part of a scientific experiment. They are the things that change in an experiment" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Variables are important because they can affect the outcome of the research" (Constructing a Hypothesis).In summary, observation questions and scientific research questions share some similarities, but the latter is more specific, has a defined methodology, and may require more consideration of variables.

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