Answer:
0.2
Explanation:
3/15
The voltage across a membrane forming a cell wall is 77.7 mV and the membrane is 9.02 nm thick. What is the electric field strength?
The electric field strength across the membrane is approximately 8.612 × 10⁶ V/m, given a voltage of 77.7 mV and a membrane thickness of 9.02 nm.
To determine the electric field strength across a membrane, we can use the formula:
Electric field strength = Voltage / Distance
Given that the voltage across the membrane is 77.7 mV (millivolts) and the membrane thickness is 9.02 nm (nanometers), we need to convert the units to be consistent.
1 mV = 0.001 V (volts)
1 nm = 1e-9 m (meters)
Converting the units:
Voltage = 77.7 mV × 0.001 V/mV = 0.0777 V
Distance = 9.02 nm × 1e-9 m/nm = 9.02e-9 m
Plugging the values into the formula:
Electric field strength = 0.0777 V / 9.02e-9 m
Calculating the electric field strength:
Electric field strength = 8.612 × 10⁶ V/m
Therefore, the electric field strength across the membrane is approximately 8.612 × 10⁶ V/m.
In summary, the electric field strength across the membrane is approximately 8.612 × 10⁶ V/m when the voltage across the membrane is 77.7 mV and the membrane thickness is 9.02 nm.
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A grinding wheel is initially at rest. A constant external torque of 50.0 m N is applied to the wheel for 20.0 s, giving the wheel an angular speed of 600 rpm. The external torque is then removed, and the wheel comes to rest 120 s later.
(a) Find the moment of inertia I of the wheel.
(b) Determine the frictional torque, which is assumed to be constant.
(c) Calculate the maximum instantaneous power provided by the frictional torque and compare to the average power provided by friction during the time when the wheel slows to rest. Hint: in part (a), both the external torque and frictional torque (opposing the angular velocity) are acting on the wheel.
(a) To find the moment of inertia (I) of the wheel, we can use the equation relating torque (τ), angular acceleration (α), and moment of inertia (I):
τ = I * α.
In the given scenario, an external torque of 50.0 mN is applied to the wheel for 20.0 s, resulting in an angular speed of 600 rpm.
First, let's convert the angular speed to radians per second:
Angular speed = 600 rpm = 600 * (2π rad/1 min) * (1 min/60 s) = 20π rad/s.
Since the wheel is initially at rest, the angular acceleration (α) is the change in angular speed divided by the time:
α = (20π rad/s - 0 rad/s) / 20.0 s = π rad/s^2.
Using the formula τ = I * α, we can rearrange it to solve for the moment of inertia:
I = τ / α = (50.0 mN) / (π rad/s^2) = 50.0 * 10^(-3) Nm / π rad/s^2.
Calculating this expression, we find:
I ≈ 15.92 * 10^(-3) Nms^2.
Therefore, the moment of inertia of the wheel is approximately 15.92 * 10^(-3) Nms^2.
(b) The frictional torque opposing the angular velocity can be determined by subtracting the external torque from the net torque. Since the wheel comes to rest 120 s later, we can assume that the net torque opposing the angular velocity is constant during this time.
Net torque = 0 (when the wheel comes to rest).
Frictional torque = Net torque - External torque = 0 - 50.0 mN = -50.0 mN.
Therefore, the frictional torque is -50.0 mN.
(c) The maximum instantaneous power provided by the frictional torque can be calculated using the equation:
Power = Frictional torque * Angular speed.
Substituting the given values, we have:
Power = (-50.0 mN) * (20π rad/s).\
Calculating this expression, we find:
Power ≈ -31.42 π mW.
The negative sign indicates that the power is being dissipated by the frictional torque.
To compare this with the average power provided by friction during the time when the wheel slows to rest, we need additional information about the duration and behavior of the frictional torque during that time. Without this information, we cannot calculate the average power.
Therefore, the maximum instantaneous power provided by the frictional torque is approximately -31.42π mW.
Hence, the moment of inertia of the wheel is approximately 15.92 * 10^(-3) Nms^2, the frictional torque is -50.0 mN, and the maximum instantaneous power provided by the frictional torque is approximately -31.42π mW.
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URGENT!!!
Help please I give brainliest science l
Four different balls with different masses (measured in grams) were dropped from the same height on Earth. Assuming no other forces acted on the balls, match each ball with the gravitational force (measured in newtons) it experienced as it fell.gravitational force = 9.8 m/s2
We will have the following:
1. 143 g = 0.143 kg:
\(F=(0.143kg)(9.8m/s{}^2)\Rightarrow F=1.4014N\)2. 110 g = 0.110 kg:
\(F=(0.110kg)(9.8m/s^2)\Rightarrow F=1.078N\)3. 410 g = 0.410 kg:
\(F=(0.410kg)(9.8m/s^2)\Rightarrow F=4.018N\)4. 46 g = 0.046 kg:
\(F=(0.046kg)(9.8m/s^2)\Rightarrow F=0.4508N\)From this we can see that the given weights do not correspond to any of the values of column B, since the calculations to obtain the values of column B were done using grams, instead of kg, thus those values do not correspond to the unit of force Newtons.
What is the noon solar zenith angle if you are in san diego (32° north latitude) during the winter solstice (solar declination = 23.5° south latitude)?
The noon solar zenith angle is 55.5°.
How do you calculate the solar zenith angle ?Zenith Angle = latitude where you are at ± subsolar point
If the subsolar point and your latitude are in the same hemisphere, subtract.
If the subsolar point and your latitude are in different hemispheres, add.
In this case you are in north latitude and the winter solstice in south latitude. So according to the formula,
Zenith Angle = latitude where you are at + subsolar point
⇒Zenith Angle = 32°+23.5°
⇒Zenith Angle =55.5°
Hence, the noon solar zenith angle for this case is 55.5°.
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suppose that the equation of motion for a particle (where is in meters and in seconds) is . (a) find the velocity and acceleration as functions of . velocity at time
Velocity is the displacement of an object with respect to the time taken by it and acceleration is the rate at which the velocity of the object changes. (a) the velocity and acceleration as functions of t are "v = t² -16t + 64, a = 2t - 18" (b) acceleration at the instant when velocity is 0 is "a = 0 m/s²"
Given the function,
s=(1/3)t³−8t²+64t+3 , where s is the position with respect to time t.
a) velocity and acceleration at time t.
As velocity is the rate at which displacement changes, it can be written as
v = ds / dt
⇒ d((1/3)t³−8t²+64t+30/ dt
⇒ t² -16t + 64
As acceleration is the rate at velocity changes it can be written as,
a = dv / dt
⇒ d(t² -16 t + 64) / dt
⇒ 2t - 16
b) acceleration at v = 0
Substituting v = 0 in v = t² -16 t + 64
⇒0 = t² - 16 t + 64
⇒(t - 8)² = 0
⇒t = 8
∴the time at which the object is having velocity 0 is 8s
⇒a = (2 x 8) - 16
⇒a= 0 m/s²
Hence, (a) the velocity and acceleration as functions of t are "v = t² -16t + 64, a = 2t - 18" (b) acceleration at the instant when velocity is 0 is "a = 0 m/s²"
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The complete question is -
Suppose that the equation of motion for a particle (where s is in meters and t in seconds) is s=(1/3)t3−8t2+64t+3 (a) Find the velocity and acceleration as functions of t. (b) Find the acceleration at the instant when the velocity is 0.
A ball weighted 20 Newton's rolls 20 meters in a straight line on a level surface. What is its change in potential energy?
A. 0 J
B. 1 J
C. 40 J
D. 400 J
\(\\ \rm\Rrightarrow Work\:done=Force(Distance)\)
\(\\ \rm\Rrightarrow Work\:done=20(20)=400J\)
Option D
The change in the potential energy of the ball is equal to 0J. Therefore, option (A) is correct.
What is the work?Work can be described as the energy used when a force is exerted to move an object through a specific displacement. The work done can be defined as it depends upon both the force on the object and the displacement by the object.
The displacement in a straight line in the direction of the applied force over a distance 'd'.
W= F × d
Where 'F' is the exerted force and 'd' is the displacement by the object.
The change in the potential energy or kinetic energy is equal to the work done.
The change in the potential energy = mgh₂ - mgh₁
The ball roll over the surface, h₂ = h₁
Therefore, the change in the potential energy is equal to zero.
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21. Explain why a passenger who is not wearing a safety belt will likely hit the windshield in a head-on collision. please answer in full sentences
what kind of object do we think lies in the center of the milk way galxy
The object believed to lie at the center of the Milky Way galaxy is a **supermassive black hole**.
Extensive observational evidence, including the motion of stars and gas clouds in the galactic center, indicates the presence of a massive and compact object. This object, known as Sagittarius A* (Sgr A*), has a mass of approximately four million times that of our Sun. It is located within a region called the Galactic Center, which is obscured by dust and gas, making direct observations challenging in visible light. However, observations using other wavelengths, such as radio and X-rays, have provided compelling evidence for the presence of a supermassive black hole. The behavior of stars in close proximity to Sgr A*, as well as the energetic processes observed in its vicinity, strongly suggest that it is a black hole with an incredibly strong gravitational pull at the center of our galaxy.
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Impulse is _____________.
1 :A force exerted over a time period that causes a change in an object's momentum
2:A collision in which some of the kinetic energy is converted into other forms of energy
3:A collision in which an objects total momentum and kinetic energy stay the same
4:The product of an object's mass and velocity
If the force is constant, the resulting force, F, and its duration, t, are multiplied to form the force's impulse. Force's impulse is what alters motion, which in turn changes momentum.
What is Impulse?If the force is constant, the resulting force, F, and its duration, t, are multiplied to form the force's impulse. Force's impulse is what alters motion, which in turn changes momentum. An impulse is a specific amount of force applied for a specific amount of time to change the motion of something. Because of that, it is F × t. For instance, when you hit a ball with a cricket bat, you exert force on the ball for a brief moment to change (or transfer) its momentum.A huge force is applied to the wall in this instance by the car in a very brief period of time, which is known as an impulse.To learn more about Impulse, refer to:
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A biology student views several different prokaryotic and eukaryotic cells under a microscope. How do the prokaryotic cells appear different from the eukaryotic cells? Choose 1 answer: (Choice A) A The prokaryotic cells have mitochondria. (Choice B) B The eukaryotic cells have cytosol. (Choice C) C Eukaryotic cells have ribosomes and prokaryotic cells do not. (Choice D) D The prokaryotic cells are smaller than the eukaryotic cells.
Answer:
The prokaryotic cells are smaller than the eukaryotic cells.
Explanation:
Its just the simple process of elimination. Prokaryotic cells lack of a lot of things, including mitochondria, so it couldn't be option C. BOTH prokaryotic and eukaryotic cells have cytosol AND ribosomes, so the answer couldn't be D or A, and you're left with option B. Meaning option B is the correct choice.
Which statement about a HORIZONTAL projectile is false?
The horizontal velocity is constant.
The horizontal acceleration is constant.
The vertical velocity is constant.
The vertical acceleration is constant.
Answer:
the vertical velocity is constant.
Explanation:
The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; thus, the vertical velocity of a projectile changes. and the horizontal motion of a projectile is independent of its vertical motion.
A person with a mass of 60.0 kg is traveling at 18 m/s.
How much kinetic energy does this person have?
Kinetic energy
K = 1 /2 m v ²
= 1 /2 × 60 × 18² = 9720J
A cart of mass m is moving with speed v on a smooth track when it encounters a vertical loop of radius r, as shown above. the cart moves along the inside of the entire loop without leaving the track. all frictional forces are negligible.Which of the following must be true for the cart to remain on the track when it is at point P?
Therefore for cart to stay here on track when it arrives at point P, the net force applied to it must be greater or equal than for the heaviness of the cart.
Describe force.The force is an impact that has the power to alter an object's motion. A mass-containing object's velocity can be altered by a force. An obvious way to describe force is as a pushed or a pull. A vector quantity is called a force since it has both strength and the direction.
Which force is the most crucial?The strongest force in existence is thought to be the strong force. The gravitation, weak, and electromagnetism forces come after it in lowest to highest.
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i dont understand ..............
Take the upward and to-the-right directions to be positive (so down and to-the-left are negative).
The vertical forces acting on the object cancel, 6 N - 6 N = 0.
The horizontal forces exert a net force of 20 N - 3 N = 17 N. This net force is positive, so it points to the right. So the answer is A.
the term ________ refers to an object's ability to take different forms.
The term "flexibility" refers to an object's ability to take different forms. High degree of flexibility is found in objects made by flexible materials.
Flexibility is a property that describes the ability of an object or material to bend, stretch, or change shape without breaking or losing its structural integrity. It is a measure of how easily an object can be deformed under the influence of external forces.
The flexibility of an object is determined by its composition, structure, and physical properties. Objects that are made of flexible materials, such as rubber or certain types of plastics, have a high degree of flexibility. They can be bent, twisted, or stretched without permanently deforming or breaking. In contrast, objects made of rigid materials, like metal or glass, have lower flexibility and are less prone to deformation.
Flexibility is an important characteristic in various fields, including engineering, materials science, and biomechanics. It allows for the design of structures and materials that can withstand different forces, adapt to different environments, and perform specific functions effectively.
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An object has a mass of 5.20g. The mass of the object in kg is
Answer:
0.0520kg
Explanation:
divide by 1000
c) The value of the membrane potential at the peak of the action potential is +25 mV. Which ion species is most conductive at the peak of the action potential?
During the peak of the action potential, the voltage-gated sodium channels open, allowing a large influx of positively charged sodium ions (Na+) into the cell, which causes the membrane potential to rapidly become more positive and Na+ ions are the most conductive.
The peak of the action potential is characterized by a large influx of positively charged ions, primarily Na+ ions. The value of the membrane potential at the peak of the action potential is +25 mV. This positive value indicates that the inside of the cell is more positively charged relative to the outside of the cell.
During the peak of the action potential, the voltage-gated sodium channels open, allowing a large influx of positively charged sodium ions (Na+) into the cell, which causes the membrane potential to rapidly become more positive.
This rapid depolarization of the membrane is the result of the increased conductivity of the Na+ ions. Therefore, at the peak of the action potential, Na+ ions are the most conductive.
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Waves Problem set *use units*
1.A tall, thin tree sways back and forth in the breeze with a frequency of 58.0 Hz. What is the period of the tree?
2.A periodic transverse wave that has a frequency of 24.9 Hz, travels along a string. The distance between the crest and the adjacent trough is 3.4 m. What is its wavelength?
3.What is the speed of a sound wave that has a frequency of 285 Hz and a wavelength of 1.5 m?
4.A person yells across a canyon and hears the echo 5.5 seconds later. If the speed of sound is 336.0 m/s, how far away is the other side of the canyon?
5.Radio station WKLB in Boston broadcasts at a frequency of 97.1 kHz. What is the wavelength of the radio waves emitted by WKLB? ( Radio waves travel at the speed of light 3x108 m/s) ps. no decimals
6. Water waves at a lake cross a distance of 7 m in 3.9 s. The period of oscillation is 3 s. What is the speed of the water waves?
7.Water waves at a lake cross a distance of 9 m in 2.9 s. The period of oscillation is 3.1 s. What is the wavelength of the water waves?
8.One pulse is generated every 0.84 s in a tank of water. What is the frequency of the pulses?
9. One pulse is generated every 0.95 s in a tank of water. What is the speed of propagation of the wave if the wavelength of the surface wave is 1.9 cm?
10.Dog whistles are inaudible to humans because dogs can hear at much higher frequencies than humans are capable of detecting. If a dog whistle has a wavelength of 2.3 x 10-3 m, what is the frequency of sound emitted? *Sound travels at 340 m/s.
11. What is the speed of sound in air that has a temperature of 29.2 o C?
12. What is the wavelength of sound in air that has a temperature of 7.9 o C has a frequency of 40.7 Hz?
To solve problems involving waves, it's important to know the relationships between frequency, wavelength, and speed, which are given by the formulas v = f λ and T = 1/f, where v is the speed of the wave, f is the frequency, λ is the wavelength, and T is the period of oscillation.
The period of the tree is T=1/f= 1/58.0 Hz = 0.0172 s.
The wavelength of the wave is λ = 2 (crest to trough distance) = 2 (3.4 m) = 6.8 m.
The speed of the sound wave is v = f λ = (285 Hz) (1.5 m) = 427.5 m/s.
The distance to the other side of the canyon is d = (speed of sound) × (time for echo to return) / 2 = (336.0 m/s) × (5.5 s) / 2 = 924 m.
The wavelength of the radio waves emitted by WKLB is λ = c / f = 3 x 10^8 m/s / 97.1 x 10^3 Hz = 3.09 m.
The speed of the water waves is v = λ / T = (7 m) / (3 s) = 2.33 m/s.
The wavelength of the water waves is λ = v T = (2.9 s) (2.33 m/s) = 6.74 m.
The frequency of the pulses is f = 1/T = 1/0.84 s = 1.19 Hz.
The speed of the wave is v = λ / T = (1.9 cm) / (0.95 s) = 2 cm/s.
The frequency of the sound wave is f = v / λ = 340 m/s / 2.3 x 10^-3 m = 1.48 x 10^5 Hz.
The speed of sound in air at 29.2°C is v = 331 m/s + (0.6 m/s/°C) × (29.2°C) = 349.5 m/s.
The wavelength of the sound wave is λ = v / f = (331 m/s + (0.6 m/s/°C) × (7.9°C)) / (40.7 Hz) = 8.06 m.
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A rock is thrown horizontally from a 65 meter high cliff with an initial velocity of 8 m/s. What is the vertical component of the velocity of the rock
when it hits the ground?
Answer:
Projectile motion is a combination of horizontal and vertical motion. - The horizontal ... What are the horizontal and vertical components of the initial velocity? Round your ... A rock is thrown horizontally at a speed of 5.0 m/s from the top of a cliff 64.7 m high. The rock hits the ground 18.0 m from the base of the cliff.
Explanation:
The human jaw muscle is the strongest in the body for its size. Does this mean that the jaw muscle is the also the overall strongest muscle as well? Explain why or why not. (Our unit is on work and power)
The sartorius muscle is the solution. A superficial muscle that runs the full length of the leg, the sartorius is involved in the flexion of the knee and hip.
What is Sartorius muscle?The heart's wall is made up of cardiac muscle, which also causes the heart to contract vigorously. Intestinal, uterine, blood vessel, and internal ocular muscles are all made of smooth muscles.
The epidermis and some skeletal muscles are linked to the bones (muscles in our face). The skeletal muscles' contraction aids in the movement of the limbs and other bodily parts.
Although some estimates go as high as 840, the majority of sources claim that there are over 650 identified skeletal muscles in the human body.
Therefore, The sartorius muscle is the solution. A superficial muscle that runs the full length of the leg, the sartorius is involved in the flexion of the knee and hip.
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Most car engines have air cooling systems. True or False.
Answer:
true
hopefully, it's right
Answer:
true
Explanation:
hopefully this is what you needed
A plane flies along a straight line path after taking off, and it ends up 220 km farther east and 100.0 km farther north, relative to where it started. In what direction did it fly on the straight line path?
Answer:
North east
Explanation:
The distance travelled by a plane from one point to another is the shortest distance between the two points. This distance travelled is usually a straight line path from point 1 to point 2.
Since the plane ends up 220 km farther east and 100.0 km farther north, the direction of flight for the plane is in the North-East direction.
Let x represent the distance travelled by the plane. Hence:
x² = 100² + 220²
x² = 58400
x = 241.66 km
A rectangular block of mass M, with vertical faces, rolls on a horizontal surface between two opposing jets. At t = 0, the block is set into motion at speed Uo. Subsequently, it moves without friction parallel to the jet axes with speed U(t). Neglect the mass of any liquid adhering to the block compared with M. Obtain a general expression for the block acceleration a(t) and the block speed U(t).
To obtain a general expression for the block acceleration a(t) and the block speed U(t) in this scenario, we can analyze the forces acting on the block.
Since the block is rolling without friction, the opposing jets provide the only external forces acting on the block. Let's assume the jets apply equal and opposite forces on the block in the horizontal direction.
The force exerted by each jet can be expressed as F(t), where t represents time. As the block moves parallel to the jet axes, the forces applied by the jets do no work on the block since the displacement is perpendicular to the force. Therefore, the work done by the jets is zero, and the total mechanical energy of the block is conserved.
The total mechanical energy (E) of the block can be expressed as the sum of its kinetic energy and potential energy due to its vertical position:
E = 0.5 * M * U(t)^2 + M * g * h(t)
Where M represents the mass of the block, U(t) is the block speed at time t, g is the acceleration due to gravity, and h(t) is the vertical position of the block.
Since the block is moving parallel to the jet axes, its vertical position h(t) remains constant, and the potential energy term becomes constant. Therefore, we can differentiate the expression for the total mechanical energy with respect to time to obtain the block acceleration a(t):
dE/dt = 0.5 * d(M * U(t)^2)/dt = 0
Differentiating the expression and simplifying, we get:
M * U(t) * dU(t)/dt = 0
From this equation, we can deduce that either M = 0 (which is not possible) or dU(t)/dt = 0. In other words, the block speed U(t) is constant over time, and the block acceleration a(t) is zero.
In conclusion, in this scenario where the block rolls on a horizontal surface between opposing jets, the block speed U(t) remains constant, and the block acceleration a(t) is zero.
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A 3.5 m long frictionless pendulum of mass 2.0 kg is released from point A at an angle θ of 10 degrees. What is the speed of the pendulum at point D, half the height up to point E?
Answer:
5
Explanation:
melsun slemalawkew melsun asawkecn
How many electrodes should be attached to the left forearm to record a 3 lead ECG?
A. 0
B. 1
C. 2
D. 3
Number of electrodes should be attached to the left forearm to record a 3 lead ECG is option (c) 2
A 3 lead ECG uses three electrodes to measure the electrical activity of the heart from different angles. To record a 3 lead ECG, two electrodes are placed on the left forearm and one electrode is placed on the left leg. The two electrodes on the left forearm are placed in a bipolar configuration, with one electrode placed just above the wrist and the other placed just below the elbow.
The electrode on the left leg is placed on the ankle, and it serves as a reference point for the other two electrodes on the left forearm. By measuring the electrical activity of the heart from three different angles, a 3 lead ECG can provide information about the functioning of the heart and detect abnormalities in its electrical activity.
Therefore, the correct option is (c) 2
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Brian Berg of lowa built a house of cards 4.88 m tall. Suppose Berg throws a ball from ground level
with a velocity of 9.98 m/s straight up. What is the velocity of the ball as it first passes the top of
the card house?
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f}^{2}=v_{o}^{2}-2*g*x\)
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
\(v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s]\)
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
the net force on a vehicle is accelerating at a rate of 1.5 milliseconds is 1800 Newtons. What is the mass of the vehicles nearest kilogram?
Answer:
The mass is 1200 kilograms
Explanation:
Because Force is equal to mass times acceleration (F=m×a)
F=m×a
1800N=?×1.5
1800÷1.5=1200
1800N=1200Kg×1.5
When the current in a toroidal solenoid is changing at a rate of 0.0260 A/s, the magnitude of the induced emf is 12.2 mV. When the current equals 1.40 A, the average flux through each turn of the solenoid is 0.00308 Wb. How many turns does the solenoid have?
Answer:
The solenoid has 213 turns.
Explanation:
The number of the solenoid's turns (N) can be found as follows:
\( N = \frac{L*I}{\phi_{B}} \) (1)
Where:
L: is the self-inductance of the solenoid
I: is the current = 1.40 A
\(\phi_{B}\): is the magnetic flux = 0.00308 Wb
The self-inductance of the solenoid (L) is:
\( L = \frac{|\epsilon|}{|dI/dt|} \) (2)
Where:
ε: is the induced emf = 12.2x10⁻³ V
dI/dt: is the rate changing of the current = 0.0260 A/s
By entering equation (2) into (1) we can find the number of turns:
\( N = \frac{|\epsilon|*I}{\phi_{B}|dI/dt|} = \frac{12.2 \cdot 10^{-3} V*1.40 A}{0.00308 Wb*0.0260 A/s} = 213 \)
Therefore, the solenoid has 213 turns.
I hope it helps you!
Why did Archimedes shout eureka what did he find out?
Answer:
I believe he shouted eureka after he stepped into a bath and noticed that the water rose. He then realized that the volume of water displaced must be equal to the volume of the part of his body he had submerged
Explanation: