What is the correct name for the following compound: P2Br5

Answer: Chloride and Chromate ions

Explanation:

Two anions used in this lab to perform selective precipitation of the unknowns are chloride and chromate ions.

Anions such as  Cl− ,  Br− ,  SO2−4 ,  CO2−3 ,  S2− ,  Cr2O2−4 ,  PO2−4 ,  OH−  etc., forms a mixture of metal ions in a solution which can be separated by precipitation. If a metal ion or a group of metal ions forms insoluble salts with a particular anion, then they can be separated from others by the precipitation.

Anions can also be separated by the precipitation with appropriate metal ions. There are no separation lines between insoluble salts, sparingly soluble, and soluble salts, but their concentrations of saturated solutions are small, medium, and large. For insoluble and sparingly soluble salts, solubility products are usually listed. But for soluble salts they are not given.

Solubility products for soluble salts are very large.

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The result of a chemical reaction or a process stage is a product (reaction product). a component of the reaction or mechanism stage that is not a substrate, reactant, reagent, beginning substance, or starting combination.

The organisms that result from chemical interactions are called products.  Reactants undergo a high energy transition stage during a chemical process before becoming products. The reactants are consumed as a result of this process. It can occur spontaneously or be facilitated by catalysts, which reduce the energy of the transition state, and solvents, which provide the favorable molecular conditions for the reaction to occur.

Even in the case of reversible reactions, it is customary to draw products on the right side of chemical equations. Several characteristics of a chemical reaction, such as whether the reaction is exergonic or endergonic, are determined by the properties of products, such as their energies.

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Foliar burn is a plant condition caused by the application of fertilizer in excess. It appears as a leaf-tip or marginal burn, with the burning and dying of plant tissues, and the leaves will also display the formation of necrotic tissue and spots.

This happens because of the process by which particles of fertilizer can cause foliar burn.Foliar burn occurs when a fertilizer solution is applied to the plant’s foliage, and the solution stays on the leaves for too long. The particles of fertilizer can create an osmotic pressure difference across the leaf membrane, which leads to an imbalance of water between the leaf cells and the external environment.

This imbalance causes the plant cells to leak out, leading to cell death. As the plant cells die, the leaves start to turn brown and become brittle. In some cases, the leaves will fall off entirely.A long answer to your question can be: The process by which particles of fertilizer can cause foliar burn is the imbalanced water between the leaf cells and the external environment.

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The frequency the concentration level of a high-level disinfectant must be tested. This statement is false.

The concentration level of a high-level disinfectant must be tested periodically to ensure its effectiveness. High-level disinfectants are used to kill or inactivate a wide range of microorganisms, including bacteria, viruses, and fungi. To ensure that the disinfectant is working as intended, it is necessary to monitor its concentration regularly. The frequency of testing the concentration level of a high-level disinfectant may vary depending on factors such as the specific disinfectant used, the frequency of use, and the manufacturer’s guidelines. Generally, it is recommended to test the concentration level at regular intervals, such as daily, weekly, or monthly, depending on the circumstances.

By regularly testing the concentration level, healthcare facilities, laboratories, or any other settings that use high-level disinfectants can ensure that the disinfectant is maintained at the appropriate concentration for effective disinfection. This helps to mitigate the risk of microbial contamination and maintain a safe and hygienic environment.

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Answer:

\(\boxed {\boxed {\sf 1.93 \ mol \ CO_2}}\)

Explanation:

We are asked to find how many moles of carbon dioxide are in 85.0 grams.

Grams are converted to moles using the molar mass (the mass of 1 mole of a substance). These values are found on the Periodic Table. They are equal to the atomic mass, but the units are grams per mole instead of atomic mass units.

Look up the molar masses of carbon and oxygen.

The formula CO₂ has a subscript of 2. There are 2 moles of oxygen in 1 mole of carbon dioxide. Multiply oxygen's molar mass by 2.

Set up a conversion factor using the molar mass.

\(\frac {44.009 \ g \ CO_2}{ 1 \ mol \ CO_2}\)

We are converting 85.0 grams of carbon dioxide to moles, so we multiply by this value.

\(85.0 \ g \ CO_2 *\frac {44.009 \ g \ CO_2}{ 1 \ mol \ CO_2}\)

Flip the fraction so the units of grams of carbon dioxide cancel.

\(85.0 \ g \ CO_2 *\frac { 1 \ mol \ CO_2}{44.009 \ g \ CO_2}\)

\(85.0 *\frac { 1 \ mol \ CO_2}{44.009}\)

\(\frac {85.0}{44.009} \ mol \ CO_2\)

\(1.931423118 \ mol \ CO_2\)

The original measurement of grams (85.0) has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 1 in the thousandth place tells us to leave the 3.

\(1.93 \ mol \ CO_2\)

There are approximately 1.93 moles of carbon dioxide in 85.0 grams.

Answer:

I like both but if I have to choose one then it would be dogs

Explanation:

Answer: during a chemical reaction, matter cannot be created or destroyed

Explanation:

The chromium ion has been oxidized, meaning it has lost electrons while the dichromate ion has been reduced, meaning it has gained electrons.

The oxidation of the chromium ion (Cr) to dichromate ion (Cr2O7^-2) in basic aqueous solution is given as follows:

Cr → Cr2O7^-2

Since we are in a basic solution, we need to balance the charge of the reaction by adding OH^- ions to both sides of the reaction. The number of OH^- ions added should be equal to the number of H^+ ions that would be produced by the oxidation reaction.

The equation becomes:

Cr → Cr2O7^-2 + 14OH^- + 6e^-

The oxidation half-reaction of Cr is therefore:

Cr → Cr2O7^-2 + 14OH^- + 6e^-

You can write the state of the different compounds to get the complete balanced half-reaction as follows:

Cr(s) → Cr2O7^-2(aq) + 14OH^-(aq) + 6e^-(aq)

You should note that the chromium ion has been oxidized, meaning it has lost electrons while the dichromate ion has been reduced, meaning it has gained electrons.

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All of the statements are true

\(\huge \boxed{\mathcal {\gray { A nswer :}}}\)

While balancing the chemical equations, the sub scripts aren't changed because by changing sub script we actually change the compound formed, hence coefficients are changed so the compound remains the same.

for example : ( for understanding )

in balancing the given reaction,

H2 + O2 =》H2O

if we change Oxygen's sub script in " H2O "

we get,

H2O + O2 =》H2O2

but here the compound formed isn't water, it is "H2O2" (hydrogen peroxide), so we can't change the sub script.

but by changing the coefficient, we get :

2 H2 + O2 =》2 H2O

Answer:

c

Explanation:

I just learned all this in chemistry too lol

got 100 on the test last week so its good

Experiments with gold foil indicated that atoms contain a positively charged, dense center and the correct option is option C.

Experiments with gold foil, known as the Rutherford gold foil experiment, were conducted by Ernest Rutherford in 1911. In this experiment, he bombarded a thin gold foil with alpha particles.

Most of the alpha particles passed through the foil with little deflection, but some of them were deflected at large angles, and a small fraction even bounced back. This observation led Rutherford to conclude that the atom contains a positively charged, dense center called the nucleus, where most of its mass is concentrated. He proposed the nuclear model of the atom, which became a significant advancement in the understanding of atomic structure.

Thus, the ideal selection is option C.

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Answer:

Neutral

Explanation:

A pH below 7 is acidic and a pH above 7 is basic, and a pH of 7 is neutral.

True statement for a nuclear reactions is that it changes the identity of the element.

Nuclear reactions are those reactions in which changes in the nucleus of atoms take place in the form of fission and fussion.

Hence identity of element changes.

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Answer:

Power

Explanation:

That’s the answer

Unsaturated fats are least abundant in beef oil. Monounsaturated and polyunsaturated fats are good fats that help reduce the risk of heart disease.

In contrast to unsaturated fatty acids, which have at least one double bond in the fatty acid chain, saturated fatty acids have no double bonds between the individual carbon atoms. Unsaturated fats are often liquid and come from plants, whereas saturated fats are normally solid at room temperature and come from animal sources.

Unsaturated fats, which are liquid at room temperature, are regarded as healthy fats because they can lower blood cholesterol levels, reduce inflammation, maintain healthy cardiac rhythms, among other positive effects.

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Answer:

C) Chalk powder

Explanation:

that's why it's often used in gymnastics ~~sweaty hands yk

With one cis-isomer and two trans-enantiomers, 1,2-dimethylcyclopropane contains three stereoisomers. The trans-isomers exhibit chirality and are enantiomers of each other, whereas the cis-isomer is achiral.

There are three stereoisomers of 1,2-dimethylcyclopropane, distinguished based on the relative positions of the methyl groups in the ring. These stereoisomers are:

These trans-isomers are enantiomers of each other, meaning they are non-superimposable mirror images. They have the same connectivity but differ in their spatial arrangement.

The presence of a chiral center in 1,2-dimethylcyclopropane allows for the existence of enantiomers. In this case, the trans-isomers represent a pair of enantiomers.

Thus, 1,2-dimethylcyclopropane has three stereoisomers: one cis-isomer and a pair of trans-enantiomers. The cis-isomer is achiral, while the trans-isomers are enantiomers of each other and exhibit chirality.

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Answer:

Boron

Explanation:

Using the periodic table we can see that Period 2 represents the second row. Group 13 indicates the 13th column.

A chemical that bonds to the active site of an enzyme, thus blocking its function, is known as a competitive inhibitor.

A competitive inhibitor is a type of inhibitor that binds to the active site of an enzyme, preventing the substrate from binding and blocking the enzyme's function.

The active site is the specific region of the enzyme where the substrate binds and undergoes a chemical reaction.

By occupying the active site, the competitive inhibitor competes with the substrate for binding, reducing the enzyme's catalytic activity.

The term "competitive" refers to the competition between the inhibitor and the substrate for binding to the active site.

When the concentration of the competitive inhibitor is high, it becomes more likely to bind to the active site, reducing the availability of the active site for the substrate.

However, the binding of a competitive inhibitor can be reversed by increasing the substrate concentration, as it can outcompete the inhibitor and regain access to the active site.

Competitive inhibitors are important in understanding enzyme kinetics and designing drugs that target specific enzymes.

By selectively blocking enzyme activity, competitive inhibitors can regulate biological processes and serve as potential therapeutic agents.

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The number of avocados in an average selection of 12 crates is 500 avocadoes.

The total number of avocadoes in the truck is determined from the correct insurance value f the avocadoes.

The total number of avocadoes in the truck is calculated as follows:

Weight of one avocado = 0.4 pound

Value of avocado per pound = $0.30

Value of one avocado = $0.30 * 0.4

Value of one avocado = $0.12

Value of one crate of avocado = $2000/400

Value of one crate of avocado = $5

Number of avocadoes per crate = 5/0.12 41 avocadoes

Number of avocados in an average selection of 12 crates =  5/0.12 * 12

Number of avocados in an average selection of 12 crates = 500 avocadoes

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Answer:

False because it is chemical change

Answer:

The answer is "2736.1 J"

Explanation:

\(m= 59.0 \ g\\\\t_2 = -22\\\\\Delta t= t_1-t_2\\\\\)

     \(= 0-(-22)\\= 22\)

specific heat for ice = 2.108 \(\frac{J}{gk} \\\)

Formula:

\(\bold{Q= mc \Delta t} \\\)

   \(= 59 \times 2.108 \times 22\\\\= 2736.1 \ \ J\)

Answer

The freezing point o the solution = 273.714153 K

The boiling point of the solution= 373.1955328 K

Explanation

Given:

Mass of glucose = 5.00 g

Volume of water = 72.8 g

What to find:

The freezing point and the boiling point of the solution.

Step-by-step solution:

Note: (Freezing point of water = 273K, Kf for water =1.87K kg/mol, atomic weight C = 12, H = 1, O = 16).

The freezing point of the solution:

The molecular weight of glucose C6H12O6 = 6(12) + 12(1) + 6(16) = 180 g/mol

The number of moles of glucose = (Mass of glucose/Molecular weight) = 5.00 g/180.0 g/mol = 0.0278 moles

Mass of water = 72.8 g = 0.0728 kg

So molality of glucose = (Moles o glcsose/Volume of solution) = 0.0278 mol/0.0728 kg = 0.3819 mol/kg

The depression in the freezing point, ∆T = Kf x molality = 1.87 K kg/mol x 0.3819 mol/kg = 0.714153 K

Since the freezing point of water = 273 K

Therefore, the freezing point of the solution= 273 K + 0.714153 K = 273.714153K

The boiling point of the solution:

∆T = i x m x Kb

∆T = change in temperature i.e boiling point elevation

i = van't Hoff factor = 1 for glucose since it does not ionize or dissociate. It is a single particle.

m = molality = moles solut/kg solvent = 0.0278 mol/0.0728 kg = 0.3819 mol/kg

Kb = boiling poin constant = 0.512 K kg/mol

∆T = 1 x 0.3819 mol/kg x 0.512 K kg/mol

∆T = 0.1955328 K

Since the freezing point of water = 373 K

Therefore, the boiling point of the solution = 373 K + 0.1955328 K = 373.1955328 K

The balanced equation for the combustion of butane with the smallest whole numbers possible is:

2C4H10 + 13 O2 → 8 CO2 + 10 H2O.

Note that this equation is balanced because there are an equal number of atoms of each element on both sides of the equation.

The balanced equation for the combustion of butane with the smallest whole numbers possible is:

C4H10 + 13/2 O2 → 4 CO2 + 5 H2O.

However, since we need whole numbers, we can multiply the entire equation by 2 to achieve this:

2(C4H10) + 13(O2) → 8(CO2) + 10(H2O)

So, the final balanced equation with whole numbers is:

2C4H10 + 13O2 → 8CO2 + 10H2O

The equation shows that when two molecules of butane (C4H10) react with 13 molecules of oxygen (O2), they produce eight molecules of carbon dioxide (CO2) and 10 molecules of water (H2O).

The coefficients in front of each compound represent the number of molecules involved in the reaction.

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Physical chemistry a  major branch of chemistry would be most concerned with studying a series of chemical reactions in order to measure the amount of heat being released in each one.

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