What is the classification of the pair of angles shown?

F. complementary
G. supplementary
H. vertical
I. no relationship

Answer:

337285

Step-by-step explanation:

The quotient in polynomial form is C. x² - x ₊ 1.

In algebra, synthetic division is a method for manually performing Euclidean division of polynomials, with less calculation than long division.

The given problem is-

-3 | 1  2  -2  3

Using synthetic division method,

-3 | 1  2  -2  3

   |   -3    3  3

   |1   -1    1  6

So, the remainder from the calculation is 6 .

And the quotient polynomial is x² - x ₊ 1.

Hence, the correct answer for the given question is C. x² - x ₊ 1

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The inequality that represents the value of x is (b)  x > 80

from the question, we have the following parameters that can be used in our computation:

The figure

The general rule is that

The larger the side length, the larger the angle opposite it

using the above as a guide, we have the following:

1/8x > 10

So, we have

x > 80

Hence, the inequality is x > 80

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The (g.f)(x)  of the two functions is:

(g.f) (x) = 6x + 37

A function is an expression that shows the relationship between the independent variable and the dependent variable.  A function is usually denoted by letters such as f, g, etc.

To find (g.f) (x), follow the steps below:

1. Substitute the value of f(x) into the function g(x).

2. Then simplify the expression.

That is:

f(x) = 3x+18

g(x) = 2x+1

Thus, we have:

(g.f) (x) = g(f(x))

(g.f) (x) = g(3x+18)

(g.f) (x) = 2(3x+18) + 1

(g.f) (x) = 6x+36 + 1

(g.f) (x) = 6x + 37

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Answer:

y = 1/2 x + 3/2

Step-by-step explanation:

We need to start by finding the slope of the given line, since a line parallel to it will have the same slope. Then we need to solve for y in the given equation;

- 2 x + 4 y = 8

add 2x to both sides

4 y = 2 x + 8

divide both sides by 4 to isolate y

y = 1/2 x + 2

Then, the slope we are looking for is "1/2"

Now we write the equation of the parallel line we are trying to find, in "point slope form", using the point (-5, -1) we want to have on the line:

y = m (x - x1) + y1

replacing m with our slope 1/2, x1 with -5, and y1 with -1:

y = 1/2 (x - -5) + (-1)

y = 1/2 x + 5/2 - 1

y = 1/2 x + 3/2

Answer:

+ 0.5 then 1.5 n

Step-by-step explanation:

Answer:

f(x) = -3/2 x - 2

Step-by-step explanation:

The line rises to the left so the slope is negative, also:

the slope of the line is -3/2 and the y-intercept is at (0, -2)

The value of 14.5% of 1,800 is 261 by using the concept of percentage.

In mathematics, a percentage is a value or ratio expressed as a fraction of 100.

The term percent is derived from the Latin per centum, which means "hundred" or "by the hundred." The sign for "percent" comes from the Italian expression per cento, which means "for a hundred." The "per" was frequently shortened as "p." and finally disappeared entirely. The "cento" was reduced to two circles divided by a horizontal line, from which the present "%" symbol was derived.

A % is a relative figure that indicates one-tenth of a quantity. One percent (symbolized 1%) is the one-hundredth part; consequently, 100 percent denotes the complete amount, and 200 percent specifies twice the supplied amount.

Given,

14.5% of 1,800

=(14.5/100)×1800

=261

Therefore, the answer is 261.

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Answer:

-1.8

Step-by-step explanation:

move the numbers around a bit because there is no multiplication so 9.2-8+-3

then take out the plus so it doesn't confuse anyone 9.2-8-3

then add 8+3 which is 11 but remember to put the negative back

9.2 - 11

which gives you -1.8

Answer:

-1.8

Step-by-step explanation:

Because,

-8 + 9.2 +-3

=> 9.2 - 8 - 3 (Commutative property)

=> 9.2 - 11 (Because subtraction is done first, and a negative + a negative = a negative)

=> -1.8 will be the final answer

Hope this helped, Please mark me as brainliest, Thank you!

the answer is 8 because there is 4 sides on a square and 8 x 4 is 32.

Answer:

Step-by-step explanation:

Let the first term is n, then the second term must be an where a is a common ratio, and the third term is a^2 n

so, n + an = 24

n + an + a^2 n = 26

solve for a, then solve for n

Answer:

it can be A or B it doesn't matter because 25-5>10 and 20-5>10

Answer:

Move all terms not containing a to the right side of the inequality.
Inequality Form:
X> 15
Interval Notation:
(15

Step-by-step explanation:

The answers are:

27. P(6) = 0.2 , 28. P(even number) = 0.6 , 29. P(6) = 1/10 , 30. P(even number) = 5/10 = 0.5

The experimental probability of getting a 6 is 0.2, because 2 out of 50 displays were 6s.

The experimental probability of getting an even number is 0.6, because 30 out of 50 displays were even numbers.

The theoretical probability of getting a 6 is 1/10, because there is 1 chance out of 10 that the calculator will display a 6.

The theoretical probability of getting an even number is 5/10, because there are 5 chances out of 10 that the calculator will display an even number.

As you can see, the experimental probabilities are close to the theoretical probabilities. This is because the calculator was programmed to randomly display a digit from 0 to 9, so the results should be evenly distributed. However, there is always some chance of variation, so the experimental probabilities may not be exactly equal to the theoretical probabilities.

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Answer:

The \(66\)th term is \(363\).

Step-by-step explanation:

To find the \(n\)th term, the formula is \(7n - 99\). Since we want to find the \(66\)th term, we can plug \(n\) for \(66\). So our expression is now \(7 \cdot 66 - 99 =\) \(66\)th term. Solving this we have

\(462 - 99 = 66\text{th term}\\363 = 66\text{th term}\\\). Therefore, the \(66\)th term is \(\boxed{363}\).

Answer:

a₆₆ = 363

Step-by-step explanation:

the nth term of an arithmetic sequence is

\(a_{n}\) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = - 92 and d = a₂ - a₁ = - 85 - (- 92) = - 85 + 92 = 7 , then

a₆₆ = - 92 + (65 × 7)

      = - 92 + 455

     = 363

Consider the continuous random variable x that has a uniform distribution over the interval from 40 to 44. The variance of 'x' is approximately C: 1.155.

The variance of a continuous uniform distribution over the interval [a, b] is determined by the formula given as follows:

Var(x) = (b-a)^2 / 12

For the given distribution, a = 40 and b = 44, so the variance is calculated by putting these values into the above formula:

Var(x) = (44 - 40)^2 / 12 = 1.155

Therefore, the variance of 'x' is approximately 1.155

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▹ Answer

-191/162

▹ Step-by-Step Explanation

Answer:

-191/162

Step-by-step explanation:

Substitute the numbers for the variables:

64 1/2 - 27 1/3 ÷ 27 - 64 2/3

Convert the mixed numbers to improper fractions:

129/2 - 82/3 * 1/27 - 194/3

Multiply the improper fractions:

129/2 - 82/81 - 194/3

= -191/162

Hope this helps!

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Considering the p-value of the test, it is found that the result has neither statistical nor practical significance, as it does not give sufficient evidence that the IQ is increases by 10 to 20 points.

Depends on if the p-value is less or more than the significance level:

In this problem, the p-value is of 0.28, which is greater than 0.05, hence there is not enough evidence that the IQ increase is as stated, meaning that the result has neither statistical nor practical significance.

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The area of the entire floor is: C. 140 square feet.

The entire floor of the building given is composed of a trapezoid, rectangle, and a triangle.

Therefore, the area of the entire floor = area of the trapezoid + area of the rectangle + area of the triangle.

The formula are:

Area of entire floor = 1/2(a + b)h + (l × w) + 1/2(b)(h)

The variables are:

Base (a) = 4 ft

Base (b) = 8 ft

Height of trapezoid (h) = 6 ft

Length of rectangle (l) = 10 ft

Width of rectangle (w) = 8 ft

Base of triangle = 6 ft

Height of triangle (h) = 8 ft

Area of entire floor = 1/2(4 + 8)6 + (10 × 8) + 1/2(6)(8)

Area of entire floor = 36 + 80 + 24 = 140 square feet.

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Answer: the probability that the critical path for this project will be completed within 210 days is 0.99725

Step-by-step explanation:

Given that;

Work break down is;  

 Time Estimates (days)

Activity  Precedes  Optimistic  Most Likely  Pessimistic  

Start          A,B              -                    -                   -  

A               C,D             44                50                 56  

B               D                45                60                  75  

C               E                42                45                   48  

D               F                31                 40                   49  

E               F                27                36                   39  

F              End            58                70                   82

we know that;

Expected Time = ( Optimistic Time + ( 4 × most likely time) + pessimistic time) / 6

and

Variance = [( pessimistic time - Optimistic time) / 6 ]²

so

ACTIVITY              EXPECTED TIME                                 VARIANCE

A                   (44 + (4 × 50) + 56) / 6 = 50                    ((56 - 44) / 6)² = 4

B                   (45 + (4 × 60) + 75) / 6 = 60                    ((75 - 45) / 6)² = 25

C                  (42 + (4 × 45) + 48) / 6 = 45                    ((48 - 42) / 6)² = 1

D                   (31 + (4 * 40) + 49) / 6 = 40                     ((49 - 31) / 6)² = 9

E                   (27 + (4 * 36) + 39) / 6 = 35                     ((39 - 27) / 6)² = 4

F                   (58 + (4 * 70) + 82) / 6 = 70                     ((82 - 58) / 6)² = 16

ACTIVITY     DURATION      ES        EF        LS        LF        SLACK

A                   50                      0        50         0         50            0

B                   60                      0        60        30        90           30

C                   45                     50       95        50        95            0

D                   40                     60      100        90       130          30

E                    35                    95       130        95       130           0

F                    70                    130     200       130      200           0

FORWARD PASS:

ES = MAXIMUM EF OF ALL PREDECESSOR ACTIVITIES; 0 IF NO PREDECESSORS ARE PRESENT.

EF = ES + DURATION OF THE ACTIVITY.

CRITICAL PATH = PATH WITH THE LONGEST COMBINED DURATION VALUE AND 0 SLACK.

CRITICAL PATH = ACEF

DURATION OF PROJECT = 200

Now the probability

VARIANCE OF CRITICAL PATH = SIGMA(VARIANCE OF THE CRITICAL PATH) = 25

STANDARD DEVIATION OF CRITICAL PATH = SQRT(VARIANCE OF CRITICAL PATH) = 5

EXPECTED TIME = DURATION OF THE PROJECT = CRITICAL PATH = 200

DUE TIME = 210

Z = (DUE TIME - EXPECTED TIME) / STANDARD DEVIATION OF CRITICAL PATH)

Z = (210 - 200) / 5 = 2

Now form the Normal Distribution Table;

Z = 0.99725

Therefore, the probability that the critical path for this project will be completed within 210 days is 0.99725

Answer:

Image 1

Step-by-step explanation:

It has a varitiy of differnt circles, while the others only have one kind of circle.

first off, let's take a peek at the picture above

hmmm the hyperbola is opening sideways, that means it has a horizontal traverse axis, it also means that the positive fraction will be the one with the "x" variable in it.

now, the length of the horizontal traverse axis is 4 units, from vertex to vertex, that means the "a" component of the hyperbola is half that or 2 units, and 2² = 4, with a center at the origin.

\(\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(x- 0)^2}{ 2^2}-\cfrac{(y- 0)^2}{ (\sqrt{3})^2}=1\implies {\Large \begin{array}{llll} \cfrac{x^2}{4}-\cfrac{y^2}{3}=1 \end{array}}\)

The value of common ration r is 4.

Given that,

a₁ = 9

a₅ = 2304

We know that,

A geometric sequence  is a sequence in which each term (except from the first term) is multiplied by a fixed amount to obtain the following term.

The following term in the geometric sequence must be obtained by multiplying it by a set term (referred to as the common ratio), and the previous term in the sequence can be obtained by dividing it by the same common ratio.

Since we know that nth term of GP is,

\(a_{n}\) = a₁ \(r^{n-1}\)

Therefore,

a₅ = a₁ \(r^{4}\)  = 2304

⇒  9 x \(r^{4}\)  = 2304

⇒        \(r^{4}\)  = 256

⇒           r = 4

Hence, r = 4

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Answer:

22/3

Step-by-step explanation:

\(4\times\:7-\frac{62}{3}\\\\\mathrm{Multiply\:the\:numbers:}\:4\times\:7=28\\=28-\frac{62}{3}\\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:28=\frac{28\times\:3}{3}\\=\frac{28\times\:3}{3}-\frac{62}{3}\\\\=\frac{28\times\:3-62}{3}\\\\28\times\:3-62=22\\\\=\frac{22}{3}\)

Answer:

(5 + 16)=7 + (4 x 7)

Step by step - explanation:

Solve:

Add the numbers

(5 + 16)= 21.

(4 x 7) = 28 + 7 = 35.

So the result is 21 = 35.

Hope that helps. x

Answer:

Step-by-step explanation:

(5+16)=7+(4.7)

(21)=7+(4.7)

21=7+(4.7)

21=7+(28)

21=7+28

21=35

Answer: 21=35

(c) The argument is valid, and we can conclude that Penelope missed class because she got a detention.

(e) The argument is valid, and we can conclude that Penelope did not miss class because she got an A and did not get a detention.

(c) To prove this argument's validity, we need to define the predicates and express the hypotheses and conclusion using them:

Let "M(x)" be the predicate "x missed class", and "D(x)" be the predicate "x got a detention".

Hypotheses: M(Penelope), D(Penelope)

Conclusion: M(Penelope)

Using modus ponens, which states that if P implies Q and P is true, then Q must be true, we can conclude that M(Penelope) is true:

From M(Penelope) and "Every student who missed class got a detention", we have D(Penelope)

From D(Penelope), we have M(Penelope)

So, the argument is valid, and we can conclude that Penelope missed class because she got a detention.

(e) To prove this argument's validity, we need to define the predicates and express the hypotheses and conclusion using them:

Let "M(x)" be the predicate "x missed class", "D(x)" be the predicate "x got a detention", and "A(x)" be the predicate "x got an A".

Hypotheses: A(Penelope), ~D(Penelope)

Conclusion: ~M(Penelope)

Using modus tollens, which states that if P implies Q and Q is false, then P must be false,

we can conclude that M(Penelope) is false:

From A(Penelope) and "Every student who missed class or got a detention did not get an A",

we have ~M(Penelope) & ~D(Penelope)

From ~D(Penelope), we have ~M(Penelope)

So, the argument is valid, and we can conclude that Penelope did not miss class because she got an A and did not get a detention.

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Answer:

36

Step-by-step explanation: