Atoms are composed of protons, neutrons, and electrons. Protons have a positive charge, neutrons have no charge, and electrons have a negative charge. In a neutral atom, the number of protons is equal to the number of electrons.
However, when an atom gains or loses electrons, it becomes an ion. If an atom gains electrons, it becomes a negative ion, and if it loses electrons, it becomes a positive ion.
In the case of an ion that contains 7 protons and 10 electrons, we can determine its charge by first finding its atomic number. The atomic number is equal to the number of protons in an atom and is located on the periodic table. In this case, the atomic number is 7, which means the atom is nitrogen.
Since the ion has 10 electrons, it has gained 3 electrons from its neutral state. This means the ion has a charge of -3. Therefore, the charge of an ion that contains 7 protons and 10 electrons is -3.
The charge of an ion with 7 protons and 10 electrons can be calculated by finding the difference between the number of protons and electrons. In this case, the ion has 3 more electrons than protons. Therefore, the charge of this ion is -3.
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Question 8 of 35
Which item rotates in a magnetic field as an electric motor produces kinetic
energy?
A. Permanent magnet
B. Loop of wire
C. Lightbulb
D. Battery
SUBMIT
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Draw the principal organic product expected when 2-methylthiophene reacts with hno3. show minimized formal charges, if applicable.
Answer:
2-Methyl-5-nitrothiophene
Explanation:
The 2- and 5-positions of thiophene are the most susceptible to electrophilic aromatic substitution.
Thus, the major product from the reaction of 2-methylthiophene with HNO₃ in acetic acid is 2-methyl-5-nitrothiophene.
how many grams of hf form from the reaction of 22.2g of nh3 with an excess of fluorine
When 22.2g of NH₃ reacts with an excess of fluorine, 26.0 g of HF form. The balanced equation for this reaction is: NH₃ + F2 → HF + NHF₂
1. Calculate the molar mass of NH₃ and HF; Molar mass of NH₃ = 14.01 + 1.01 × 3 = 17.04 g/mol Molar mass of HF = 1.01 + 18.99 = 20.00 g/mol
2. Determine the number of moles of NH₃ used. Moles of NH₃ = 22.2 g ÷ 17.04 g/mol = 1.30 mol
3. Find the limiting reactant NH₃ + F₂ → HF + NHF₂
For every mole of NH₃ that reacts with F₂, one mole of HF is produced. Therefore, 1.30 mol of NH₃ will produce 1.30 mol of HF.
4. Calculate the number of moles of HF formed. Number of moles of HF = number of moles of NH₃ used = 1.30 mol5. Calculate the mass of HF formed. Mass of HF = number of moles × molar mass= 1.30 mol × 20.00 g/mol= 26.0 g
Therefore, 22.2g of NH₃ reacts with an excess of fluorine to form 26.0 g of HF.
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use information from appendix d to calculate the ph of (a) a solution that is 0.250 m in sodium formate (hcoona) and 0.100 m in formic acid (hcooh), (b) a solution that is 0.510 m in pyridine 1c5h5n2 and 0.450 m in pyridinium chloride 1c5h5nhcl2, (c) a solution that is made by combining 55 ml of 0.050 m hydrofluoric acid with 125 ml of 0.10 m sodium fluoride.
By using the Henderson-Hasselbalch equation, the pH of the given solutions are 4.17, 8.72, 3.83 respectively.
The Henderson-Hasselbalch equation can be used to determine how much conjugate base and acid should be mixed to create a buffer solution with a certain pH.
pH = pKa + \(log_{10}\) ([\(A^-\)]/[HA]), where [\(A^-\)] stands for the molar concentration of the conjugate base (of the acid), and [HA] for the molar concentration of the weak acid, is how the Henderson-Hasselbalch equation is expressed.
As per Henderson-Hasselbalch equation,
For weak acid buffer, pH = pKa + log ([salt] / [acid])
For weak base buffer, pH = pKa + log ([salt] / [base])
(a) pKa of HCOOH = 3.77
Therefore, pH = pKa + log ([salt] / [acid])
pH = pKa + log ([HCOONa] / [HCOOH])
pH = 3.77 + log (0.250/0.100)
pH = 4.17
(b) pKa of Pyridine = 8.77
Therefore, pH = pKa + log ([salt] / [base])
pH = pKa + log ([Pyridinium chloride] / [Pyridine])
pH = 8.77 + log (0.450/0.510)
pH = 8.72
(c) pKa of HF = 3.17
Therefore, pH = pKa + log ([salt] / [acid])
pH = pKa + log ([NaF] / [HF])
pH = 3.17 + log [(0.10x 125) / (0.05 x 55)]
pH = 3.83
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Using the following equation, determine the males of sucrose (CisH55011 ) produced given 100 g of 02.
12 CO, + 11 H,0 - C2H2,0, + 12 0
Answer:
A --0.26 mol
Explanation:
using the stoichiometry ratio
1mol of sucrose -----> 12 moles of O2
no of mole of O2 = mass in g / mm
mm of O2 =2(16)
=32
no of mole of O2= 100/32
= 3.125 mol
recall
1 mol of sucrose ==> 12 mol of O2
1 mol of sucrose = 3.125/12
=== 0.2604 mol ✅✅
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experiment 3: which unknown solution contained more copper(ii) sulfate? this cannot be determined from the experiments performed here. copper solution
Based on the given information, it cannot be determined which unknown solution contained more copper(ii) sulfate. The experiments performed only involved a copper solution and did not provide any comparative measurements or quantities of copper(ii) sulfate in the unknown solutions. Therefore, further testing or analysis would be necessary to determine which unknown solution contained more copper(ii) sulfate.
To determine the amount of copper(II) sulfate in a solution, one could perform a quantitative analysis such as titration or gravimetric analysis. Without such experiments, it is impossible to determine which solution contained more copper(II) sulfate.The given information only suggests that there were two unknown solutions, and one of them contained copper(II) sulfate. Therefore, the only conclusion that can be made is that the copper solution contained copper(II) sulfate.
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Why isn't energy ever truly destroyed?
Answer:
In physics, the law of conservation of energy states that the total energy of an isolated system cannot change—it is said to be conserved over time. ... Energy can be neither created nor destroyed, but can change form; for instance, chemical energy can be converted to kinetic energy.
Explanation:
Draw the product you expect from the reaction of (R)-2-bromooctane with -CN. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Include H atoms at chiral centers only. If a group is achiral, do not use wedged or hashed bonds on it.
Answer:
See explanation and image attached
Explanation:
The reaction between (R)-2-bromooctane and -CN^- is an SN2 reaction. An SN2 reaction involves a synchronous attack of the nucleophile as the leaving group is departing.
This leads to a five member transition state in which a bond is being broken and another is being made. Since the nucleophile attacks from the backside, SN2 mechanism leads to inversion of configuration as shown in the image attached.
he chart shows the movement of a ball after several seconds. A 2-column table with 4 rows. The first column labeled A has entries 0, 4, 8, 12, 16. The second column labeled B has entries 0, 2.5, 6, 8, 10. Column A is on the x-axis, and Column B is on the y-axis. Which titles should replace A and B?
The chart is showing the position -time graph of the movement of ball. The x-axis represents the time of travel and y-axis represents the position of the ball with respect to the time.
What is position -time graph ?The position - time graph is plotting the position of a moving object in with respect to different time. From this plot we can easily understand the displacement by an object. Similarly we can determine the speed of the object from the slope of the line.
The position is expressed in meters and the time is expressed in seconds. If the plot shows a linear curve, then the object is moving with constant speed.
Here, the position of the moving ball is given in y-axis 0, 2.5 m, 6, 8 and 10 meters with respect to the time given in x-axis as 0 ,4,8,12 and 16 seconds.
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In a container with volume of 25.0 L, there are 40 g of CH4 gas. If the number of gas is reduced to 15.0 L, what is the new amount inmole?
Answer
1.50 mol
Explanation
Given:
Initial volume, V₁ = 25.0 L
Mass of CH4 gas in 25.0 L container = 40 g
Final volume, V₂ = 15.0 L
From the Periodic Table; molar mass of CH4 = 16.04 g/mol
What to find:
The new amount in mole.
Step-by-step solution:
According to Avogadro’s law: For a confined gas, the volume (V) and number of moles (n) are directly proportional if the pressure and temperature both remain constant. That is:
\(\frac{V_1}{n_1}=\frac{V_2}{n_2}\)n₁ = Mass/Molar mass = (40.0g/16.04 g/mol) = 2.493765586 mol
n₂ is the new amount in mole and can be calculated as follows:
\(\begin{gathered} \frac{25.0\text{ L}}{2.493765586\text{ mol}}=\frac{15.0\text{ L}}{n_2} \\ \text{Cross multiply} \\ n_2\times25.0\text{ L }=15.0\text{ L }\times2.493765586\text{ mol} \\ \text{Divide both sides by 25.0 L} \\ \frac{n_2\times25.0\text{ L}}{25.0\text{ L}}=\frac{15.0\text{ L }\times2.493765586\text{ mol}}{25.0\text{ L}} \\ n_2=1.496259352\text{ mol} \\ To\text{ 3 significant digits} \\ n_2=1.50\text{ mol} \end{gathered}\)The new amount in moles is 1.50 moles
How is the glucose level in the blood maintained? Which body system, organs, and hormones are used and what do they do?
Answer:
Explanation:
Insulin is an hormone used to regulate blood glucose, as it helps to maintain a balance. It allows for transport of glucose to organs such as liver.
The process of glucose regulation is a complex process. When food is eating glucose is absorbed into the bloodstream this happen from the gut and it raises the blood glucose level this causes insulin(hormone) to be released from the pancreas so glucose can move inside the cells and be used.
As glucose moves inside the cells, the glucose level inside the bloodstream returns to normal and insulin release slows down.
Glucose which is the main energy source used by cells is allowed to be taken up by muscles, liver and fat (adipose tissue) and use as a source of energy so they can function properly.
Given the biaryl compound below, select the two reactants that would give this product via a Suzuki coupling. Drag and drop the appropriately labeled reactants into the starting box. Pd (PPh,) heat, Na,CO, E F G A CIB D SnBu 3 MgBr o Previous Give Up & View Solution Check Answer 0 Next AExit
The product shown in the structure can be generated from a Suzuki coupling reaction using the reactants Na2CO3, Pd(PPh3)4, SnBu3 and MgBr.
First, the palladium (Pd) catalyst is activated by the Na2CO3 under basic conditions, which then reacts with the organoboron compound SnBu3 to form a palladium-boron complex. This complex then reacts with the aryl halide, E, under mildly basic conditions and the reaction is accelerated by heating. The aryl halide is then replaced with the aryl Grignard, MgBr, which undergoes a transmetalation to give the desired product A.
In summary, the two reactants needed for the Suzuki coupling are Na2CO3, Pd(PPh3)4, SnBu3 and MgBr.
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what is the percent chance that the offspring will be dwarf plants with yellow fruit
Answer:
Yellow fruit and dwarf vines are recessive traits in tomatoes. Red fruit and tall vines are dominant. Complete a Punnett square and answer the questions for a completely dominant red and tall plant crossed with a heterozygous red and dwarf plant.
Explanation:
What is the estimated effective nuclear charge, zeff, experienced by an electron in a 3p orbital of a chlorine atom?.
Therefore, +17 + (-10) = +7 is the effective nuclear charge. Simply counting the number of electrons in the outer shell—without applying any charges—will get the same result. That would be the 3s2 3p5 for Cl, where 2 + 5 = 7.
Use the formula Zeff = Z - S, where Z is the atomic number and S is the number of shielding electrons, to calculate the effective nuclear charge of an atom. By deducting the number of valence electrons from the total number of electrons in the atom or ion, one can calculate the number of shielding electrons. Effective nuclear charge (Zeff) is an atom's net positive charge that attracts an electron. The closest estimate of this net charge is. Effective nuclear charge (Zeff) is calculated as Z minus Zcore.
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Trimethylamine, (CH3)3N is a weak base (Kb = 6.3 × 10–5). What volume of this gas, measured at STP, must be dissolved in 2.5 Lof solution to give that solution a pOH of 2.50?
Answer:
8.9L is the volume of the gas that must be dissolved.
Explanation:
For a weak base, we can find [(CH₃)₃N] using the equation:
Kb = [OH⁻] [[(CH₃)₃NH⁺] / [(CH₃)₃N]
As [OH⁻] = [[(CH₃)₃NH⁺] and [OH⁻] = 10^-pOH = 3.16x10⁻³M:
6.3x10⁻⁵ = [3.16x10⁻³M][3.16x10⁻³M] / [(CH₃)₃N]
[(CH₃)₃N] = 0.1587M
As the volume is 2.5L, moles are:
2.5L * (0.1587mol / L) = 0.3968moles
Using:
PV = nRT
We can solve for volume of the gas as follows:
P = 1atm at STP; n = 0.3968moles; R = 0.082atmL/molK; T = 273.15K at STP
V = 0.3968mol*0.082atmL/molK*273.15K/1atm
V = 8.9L is the volume of the gas that must be dissolved.
How can one show that elements that have different appearances have similar chemical properties?
Answer:
Elements within the same group have the same number of electrons in their valence (outermost) shells, and they have similar electron configurations. They exhibit similar chemical properties.
How many kilojoules of energy would be required to heat a 37.0 g chunk of copper from 14.1 °C to 100.0 °C?
The specific heat capacity of Copper = 0.385 J/g °C. Watch your significant figures!
The amount of energy required to heat the 37.0 g chunk of copper from 14.1 °C to 100.0 °C is approximately 1.214 kJ
To calculate the amount of energy required to heat the copper, we use the formula:
Energy = mass * specific heat capacity * change in temperature
Given:
Mass of copper = 37.0 g
Specific heat capacity of copper = 0.385 J/g °C
Change in temperature = (100.0 °C - 14.1 °C) = 85.9 °C
Plugging the values into the formula:
Energy = 37.0 g * 0.385 J/g °C * 85.9 °C
Calculating the result:
Energy = 1214.055 J
To convert the energy from joules to kilojoules, we divide by 1000:
Energy = 1214.055 J / 1000 = 1.214055 kJ
Therefore, the amount of energy required to heat the 37.0 g chunk of copper from 14.1 °C to 100.0 °C is approximately 1.214055 kJ
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if a substance has a half-life of 4.4 hr, how many hours will it take for 28 g of the substance to be depleted to 3.5 g?
It will take 13.2 hours for 28 g of the substance to be depleted to 3.5 g.
How to calculate hours that will take for 28 g of the substance to be depleted to 3.5 g?We can use the following radioactive decay formula to solve this problem:
N = N0 * (1/2)^(t/T)
Where:
N = Final amount of the substance
N0 = Initial amount of the substance
t = Time passed
T = Half-life of the substance
Let's first find the number of half-lives that will pass as 28 g of the substance is depleted to 3.5 g:
28 g * (1/2)^(n) = 3.5 g
(1/2)^(n) = 3.5 g / 28 g
(1/2)^(n) = 0.125
n = log(0.125)/log(1/2)
n = 3
So, 3 half-lives will pass. Since the half-life is 4.4 hours, the total time it will take is:
t = n * T
t = 3 * 4.4 hr
t = 13.2 hr
Therefore, it will take 13.2 hours for 28 g of the substance to be depleted to 3.5 g.
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How many atoms of both elements are there in this molecule: 3N205; O 3 Nitrogen and 15 Oxygen 6 Nitrogen and 5 Oxygen KD 2 Nitrogen and 5 Oxygen 6 Nitrogen and 15 Oxygen
Answer:
Explanation:
oxygen is a 15 and nitrogen science chemistry i'm guessing
explain what keeps the electrons confined in the space surrounding the nucleus
Answer:
Electrons are trapped inside the atom because of the attraction forces with positively charged protons that are found in the nucleus.
name that compound...
iupac name??
....
Answer:
The IUPAC name is therefore: 2,5,5-trimethyl-2-hexene. In example (2) the longest chain incorporating both carbon atoms of the double bond has a length of five. There is a seven-carbon chain, but it contains only one of the double bond carbon atoms. Consequently, the root name of this compound will be pentene.
Explanation:
the name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).
The diagram below shows the geometric structure of the molecule of water H2O what do the symbols (the bigger gray circle) and (the smaller black circle) represent in the model?
1) genetic material
2) cells
3) chemical bonds
4) atoms
Answer:
Chemical bonds
Explanation:
Because it has an image of atoms being held together by chemical bonds.
how much potassium hydroxide is needed to make 1.00 liter of a 1 molar solution of potassium hydroxide ?
we need 56.11 grams of KOH to make 1.00 liter of a 1 molar solution of potassium hydroxide.
To make a 1 molar solution of potassium hydroxide (KOH), we need to dissolve enough KOH in water to make a solution where the concentration of KOH is 1 mole per liter of solution. The molarity (M) is defined as the number of moles of solute (KOH in this case) per liter of solution, so we can use this equation:
M = moles of solute / liters of solution
We can rearrange this equation to solve for the moles of solute:
moles of solute = M x liters of solution
Since we want to make 1.00 liter of a 1 molar solution of KOH, we can substitute those values into the equation:
moles of solute = 1.00 mol/L x 1.00 L = 1.00 mol
So we need 1.00 mole of KOH to make 1.00 liter of a 1 molar solution. To find the mass of KOH needed, we need to use its molar mass:
KOH molar mass = 39.10 g/mol (for K) + 16.00 g/mol (for O) + 1.01 g/mol (for H) = 56.11 g/mol
So, the mass of KOH needed to make 1.00 liter of a 1 molar solution is:
mass of KOH = moles of KOH x molar mass of KOH
= 1.00 mol x 56.11 g/mol
= 56.11 g
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Explain the difference between aliphatic hydrocarbons and aromatic hydrocarbons.
Answer:
Explanation:
Aliphatic compounds are those hydrocarbons that are the open chain compounds and also closed chains. Aromatic compounds are those who have only a closed chain structure. They can be saturated as well as unsaturated where the system can be open as well as closed chain.
Which of the following show the formula unit mass of ammonium sulphate (NH42SO? Atomic
mass of N-14, H-1, S-32, 0-16 )
The formula unit mass of ammonium sulphate [(NH₄)₂SO₄] is 132g/mol (option D).
What is formula unit mass?Formula unit mass of a compound signifies the total sum of the atomic masses of all the atoms present in the given compound.
It is calculated by summing the atomic masses of each element that makes up a compound. According to this question, ammonium sulphate with the chemical formula; [(NH₄)₂SO₄] is given.
Since; N = 14, H = 1, S = 32, O = 16, the formula unit mass can be calculated as follows:
{14 + 1(4)}2 + 32 + 16(4)
36 + 32 + 64
= 132g/mol
Therefore, 132g/mol is the formula unit mass of ammonium sulphate.
The options to the incomplete question are as follows;
148g/mol152g/mol208g/mol132g/molLearn more about formula unit mass at: https://brainly.com/question/29353833
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How does a homogeneous mixture differ from a pure substance?
Considering the definition of pure substance and homogeneous mixture, the main difference is that a pure substance consists of only one type of particle and it cannot be separated or divided into more substances whereas a homogeneous mixture is made up of two or more different substances and can be separated into various pure substances.
Definition of pure substance and homogeneous mixtureA pure substance is one that is made up of a single type of particle, whether atoms or molecules, and therefore has the same properties in all its parts. The composition and properties of an element or compound are uniform anywhere in a given sample, or in different samples of the same element or compound.
When a substance is made up of two or more simple substances, it is known as a mixture. Homogeneous mixtures are characterized by being formed by two or more components that cannot be distinguished visually. The composition and properties are uniform throughout any given sample, but may vary from sample to sample. In general, the components of a homogeneous mixture can be in any proportion, and can be recovered using physical separation methods.
DifferenceThe main difference between a pure substance and a mixture is that a pure substance consists of only one type of particle and it cannot be separated or divided into more substances whereas a homogeneous mixture is made up of two or more different substances and can be separated into various pure substances.
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For the following Bronsted acid-base reaction, complete the reaction, identify the acid, base, conjugate
acid and conjugate base. HF + PO4^-3
Answer:
algun moderador puede acabar a este otro este me borró respuesta que no debió borrar
2. Describe how baking cake is an example of irriversible change.
Answer:
Baking a cake is a chemical and irreversible change, because once the raw materials are chemically converted during baking, one cannot recover the raw materials from the cake
Which of the following compounds are likely to form? (Select all that apply)
A. Sr₂F
B. SrCl₂
C. Sro
D. Srl3
E. None of these
Among the options, the compounds likely to form are:
B. SrCl₂ (strontium chloride)D. SrI₃ (strontium iodide)What makes a compound formation?The formation of these compounds is possible because strontium (Sr) is a metal with a positive charge, and chlorine (Cl) and iodine (I) are nonmetals with negative charges. Strontium can lose two electrons to form Sr²⁺, and it can also lose three electrons to form Sr³⁺.
Chlorine can gain one electron to form Cl⁻, and iodine can gain one electron to form I⁻. Therefore, strontium can combine with chlorine to form SrCl₂ and with iodine to form SrI₃.
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How to Convert Celsius to Kelvin?
In other words, Celsius is equal to Kelvin since Kelvin is simply Celsius multiplied by 273.15. A value other than 273.15 is used, which is 273.
What other names have 1 kelvin?In thermodynamic terms, the triple point of pure water's thermodynamic temperature is equal to 1/273.16 (3.6609 x 10 -3) of one kelvin (H 2 O). The Kelvin scale differs from the more popular Celsius or centigrade (o C) temperature scale in that there is no such thing as a Kelvin value below zero.
Using the Kelvin scale, what can be measured?It is equivalent to 273.15 and 373.15 degrees Kelvin for water to freeze at 0 degrees Celsius and to have a specific heat of 100 degrees Celsius, respectively.
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