what is the cause of the lunar phases (i.e. why doesn't the moon look the same every day)? what is the cause of the lunar phases (i.e. why doesn't the moon look the same every day)? clouds sometimes block a portion of the moon. sometimes the moon is partially or totally within earth's shadow. the moon's orbit around earth causes different amounts of the illuminated side of the moon to be visible from earth.

Answer:

A. reflects and absorbs light but does not transmit it

Explanation:

I'm pretty sure it's the first one

A ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building. The height of the point where the ball is thrown is 25 m from the ground. The height will the ball rise is 20m. 5s long will it be before the ball hip the ground.

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

A. for solving how high will ball go , velocity at the top point will be 0 this gives ,

s = v² - u² / 2a

= 0 - 20² / -2 × 10

= 20m

B. Time to reach maximum height can be obtained from v = u + at

0 = 20 + ( − 10 ) t

t = 2s

s = ut + 0.5at²

= 20 ( 2 ) + 0.5 ( −10 ) ( 2 )²

= 20m

Therefore, the total distance for maximum height is 45 m

s = ut + 0.5at²

45 = 0 + 0.5 ( 10 ) ( t )²

t = 3s

Then,

Total time = 3+2

= 5s

Thus, A ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building.The height will the ball rise is 20m. 5s long will it be before the ball hip the ground.

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Answer:

hello, yes or nou sorry jaja

Answer:

The uniy which is accepted all over the world is called SI unit.

Explanation:

The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.

Answer:

because of their web feet

Explanation:

oke

Answer:

Reptiles have an enormous number of extremely minuscule hairs on the stack of their feet called setae. These little cushions subsequently radically increment the surface zone and come in close contact with the surface on which the reptile is creeping, so the Van der Waals forces kick in.

Explanation:

Hope this helped!

              J = I / (4πR²),

             B(r) = μ0 I / (2πr),

              B(r) = μ0 I r² / (2 R³),

(a) The current density on the sphere can be found by dividing the total current by the surface area of the sphere.

               J = I / (4πR²)

(b) Due to the symmetry of the problem, the magnetic field will have no φ-component, and will only depend on the radial distance r and the polar angle θ.

By Ampère's law,

     The magnetic field at a point P inside the sphere of radius R can be found by integrating the current density J over a circular path C around the z-axis passing through P:

             ∮C B · dl = μ0 Ienc

where,

Since the current is distributed uniformly over the surface of the sphere, we can take a surface S with the same circular path C as its boundary.

Then, Ienc is equal to the total current passing through the sphere, which is equal to I.

By symmetry,

                         B = B(r) ẑ,

where,

                       B(r) ∫C dl = B(r) 2πr = μ0 I

               B(r) = μ0 I / (2πr)

(c) At the surface of the sphere, the magnetic field must be continuous across the boundary.

Therefore, we need to evaluate the magnetic field both inside and outside the sphere and make sure they match at r = R.

For r < R, we have:

                  B(r) = μ0 I / (2πr)

For r > R, the magnetic field is due to the current flowing on the surface of the sphere.

By Ampère's law,

               J = I / (4πR²),

             Ienc = J π r²

               B(r) ∫C dl = B(r) 2πr = μ0 Ienc

           B(r) = μ0 I r² / (2 R³)

          B(R) = μ0 I / (2πR) = μ0 I R / (2πR²) = μ0 J R

which is the same as the magnetic field due to the current density on the surface of the sphere.

Therefore, the magnetic field is continuous across the surface of the sphere, and our solution satisfies the magnetic field matching conditions.

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Answer:

E = h ν = h c / λ

E = (6.63E-34 J-s * 3.00E8 m/s) / 757.7E-9 m

E = 2.62E-19 J

Note 1 eV = 1.60E-19 J

ν = c / λ = 3.00E8 / 110.9E-9 = 2.71E15 / sec

How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

Substituting the given values, we get: E = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(757.7 x 10^-9 m)E = 2.61 x 10^-19 JTherefore, the energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. What is the frequency (in Hz) of light that has a wavelength of 110.9 nm  The frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. The frequency of light is given by the formula:f = c/λwhere f is the frequency, c is the speed of light, and λ is the wavelength of the light.

Substituting the given values, we get:f = (3.00 x 10^8 m/s)/(110.9 x 10^-9 m)f = 2.70 x 10^15 Hz Therefore, the frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

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Answer:

The correct option is (b).

Explanation:

Given that,

The height of the object, h = 15 cm

Object distance, u = -44 cm

Image distance, v = -14 cm

We need to find the focal length of the lens. Using the lens formula.

\(\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{f}=\dfrac{1}{(-14)}-\dfrac{1}{(-44)}\\\\f=-20.53\ cm\)

So, the focal length of the lens (-20.53 cm).

Using the given data and the slope from the graph, the acceleration of gravity on the planet can be determined.

To obtain a straight-line relationship on the graph, the quantities that need to be plotted are the horizontal distance D (in meters) as the dependent variable and the square of the initial velocity of the ball (v₀²) as the independent variable.

(a) Reasoning: When an object is projected as a projectile, neglecting air resistance, the horizontal distance traveled is given by the equation:

D = (v₀² * sin(2θ)) / g,

where v₀ is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity. In this experiment, the ball is released from rest, so the angle of projection is 45 degrees, and sin(2θ) is equal to 1. Therefore, the equation simplifies to:

D = v₀² / g.

This equation shows that D is directly proportional to v₀²/g. Since v₀² is a square term and g is a constant, plotting D against v₀² will yield a straight-line relationship.

(b) The graph should have the horizontal axis labeled as v₀² (m²/s²) and the vertical axis labeled as D (m). The axes should be scaled appropriately. The data points should be plotted, and a best-fit line should be drawn through them.

(c) The slope of the best-fit line represents the ratio of v₀² to g, as given by the equation D = (v₀² / g). By examining the slope, we can extract the value of g. The slope can be calculated as the change in D divided by the change in v₀² between any two data points. Once the slope is obtained, the value of g can be calculated by rearranging the equation:

g = v₀² / slope.

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Answer:

2. Mathew Maury

Explanation:

2. Mathew Maury

4. Cousteau and Gagnon

Explanation:

they made the first successful scuba in 1942

Answer:

Wood is lighter than iron of the same volume because wood has a lower density. Density is a measure of mass per unit volume, and iron is denser than wood. Iron has tightly packed atoms with strong metallic bonds, while wood has a porous structure with empty spaces between its fibers and cells. These empty spaces in wood reduce its overall mass for a given volume, resulting in its lighter weight compared to iron.

Explanation:

appreciate you helping me, what shall one do if he thinks he has done a mistake and wants to reverse it? related to bul l yinging stuffs in school

Answer:

65meters

Explanation:

Given data

velocity= 10m/s

time= 6.5seconds

Applying the expression

velocity= distance/time

substitute

10=distance/6.5

distance= 10*6.5

distance= 65meters

Hence the displacement is 65meters

The force diagram of the given situation is shown below:

As you can notice, force due to the friction of the box with the flat surface is opposite to the applied force.

Answer:

The Sun derives all its energy from a fusion cycle. In that process, tiny hydrogen molecules combine into a continuous proton-proton chain to create larger helium nuclei. The above figure illustrates the fusion of hydrogen into helium.

Explanation:

Hope this helps.

Answer:

nuclear fusion

Explanation:

In this process, small hydrogen molecules fuse together to form bigger helium nuclei in a continuous proton-proton chain.

A) Minimum recommended spiral parameter: 150.03m.

b) Distance P: 150.03m.

c) Distance Q: 4.122m.

d) Angle Φs: 16°30'14.0".

e) Distance Tc: 150.03m.

a) Calculation for the minimum recommended spiral parameter:

Design radius (R) = 300 m

Maximum superelevation (e_max) = 0.06 m/m

Spiral Parameter (A) = (R + e_max) / 2

A = (300 m + 0.06 m/m) / 2

A ≈ 150.03 m

b) Calculation for the distance P:

Distance P is equal to the length of the first spiral curve, which is the same as the minimum recommended spiral parameter.

P ≈ 150.03 m

c) Calculation for the distance Q:

Distance Q represents the length of the circular curve. It is given by the formula:

Q = (Deflection angle at Point of Intersection) / (Degree of Curve, D)

Deflection angle at Point of Intersection = 16°30'14.0"

Converting the angle to decimal degrees:

16° + (30'/60) + (14.0"/3600) = 16.504°

Q = 16.504° / (360° / D)

Q ≈ D / 21.814

Since the RAU80 has 4 lanes, the degree of curve (D) is 360° / 4 = 90°.

Q ≈ 90° / 21.814

Q ≈ 4.122 m

d) Calculation for the angle Φs:

The angle Φs is the deflection angle at the Point of Intersection.

Φs = 16°30'14.0"

e) Calculation for the distance Tc:

Distance Tc is equal to the length of the second spiral curve, which is the same as the minimum recommended spiral parameter.

Tc ≈ 150.03 m

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The ball will decelerate as it moves upwards.

The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

The given parameters;

As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.

Thus, the ball decelerate as it moves upwards.

The acceleration of the ball is calculate as;

\(a = \frac{v_f -v_0}{t} \\\\\)

at the highest point on the incline plane, the final velocity \(v_f\) is zero

\(a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2\)

Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

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The force experienced by a 27 μC charge is 51 N rounded off to 2 significant figures.

The force that a 27 μC charge would experience in the same field can be calculated by multiplying the field strength (1.92 N/C) by the charge (27 μC), giving a result of 52.24 mN with two significant figures.

The first part of the question requires us to calculate the field strength, whereas the second part of the question requires us to calculate the force that a 27 μC charge would experience in the same field. Therefore, we can start by calculating the field strength as shown below:

Field strength (E) can be calculated using the formula shown below:F = Eq => E = F/qWhere,F = 138 mNq = 72 nC=> F/q = (138 × 10^-3)/(72 × 10^-9) = 1916.7 × 10^3 N/C≈ 1.9 × 10^6 N/CTherefore, the field strength is 1.9 × 10^6 N/C rounded off to 2 significant figures.Next, we can calculate the force experienced by a 27 μC charge as shown below:

The force experienced by a 27 μC charge (F2) can be calculated using the formula shown below:F2 = Eq2=> F2 = E × q2Where,E = 1.9 × 10^6 N/Cq2 = 27 μC = 27 × 10^-6 C=> F2 = (1.9 × 10^6) × (27 × 10^-6) = 51.3 N ≈ 51 NTherefore, the force experienced by a 27 μC charge is 51 N rounded off to 2 significant figures.

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The velocity of particle B travels 265 meters more than particle A during the first ten seconds (from t = 0 to t = 10).

Given :v_{a}(t) = 8.4t - 0.6t^{2}v_{b}(t) = 13.8t - 0.3t^{2}

Distance travelled by a particle is given by the integration of the velocity of the particle.

Therefore, we get:s_{a}(t) = ∫ v_{a}(t)dt = 4.2t^{2} - 0.2t^{3}s_{b}(t) = ∫ v_{b}(t)dt = 6.9t^{2} - 0.1t^{3}

The distance travelled by both particles in the first 10 seconds will be:

s_{a}(10) = 4.2(10)^{2} - 0.2(10)^{3} ≈ 400 meterss_{b}(10) = 6.9(10)^{2} - 0.1(10)^{3} ≈ 665 meters

Hence, particle B travels farther than particle A during the first ten seconds by approximately 665 - 400 = 265 meters.

Rounding off to the nearest meter, we get the answer as 265 meters.

Therefore, particle B travels 265 meters more than particle A during the first ten seconds (from t = 0 to t = 10).

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If the reciprocal of time since the Big Bang was 100 km/s/Mpc, the universe would be approximately 9.8 billion years old.

To calculate the answer, we must first understand what the reciprocal of the time since the Big Bang means. Essentially, reciprocal in this case means the opposite, or the inverse, of the time since the Big Bang. This reciprocal time is the distance that light can travel in a second, which is known as the speed of light.

Therefore, the answer is calculated by dividing the speed of light by the reciprocal to get the amount of time (in seconds) which the light has traveled, and then converting that to years for a more useful answer. We can simplify this process to calculations of multiplication and subtraction, which easily reveals the answer of 9.8 billion years.

All in all, the calculation of this answer requires a thorough understanding of the reciprocal of the time since the Big Bang, as well as an accurate calculation of conversion from seconds to years.

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Answer:

f = 5000 N

Explanation:

Given that,

The weight of a car = 11000 N

Driving force on the car = 5000 N

We need to find the force opposing the motion of the car. The net force on th car is given by :

F-f = ma

As it moves with constant velocity, a = 0

i.e.

F - f = 0

F = f

f = 5000 N

Hence, the opposing force is 5000 N.

Explanation:

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The speed of light is 3 * 10⁸ m/s.

Mirrors with different faces revolving at extremely high speeds are used in Michelson's method to calculate the speed of light.

Given,

period = 1/528

period = 0.001894 secs

for 1/8th of a revolution, it will be,

period = 0.001894 * 1/8

period for 1/8th of a revolution = 0.0002367424 secs

we know that,

speed = distance/ time

speed of light = 71000m / 0.0002367424 secs

speed of light = 299904000 m/s

Rounding up we get the speed of light as 3 * 10⁸ m/s.

Hence, the speed of light is 3 * 10⁸ m/s

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A mass of approximately 0.92 kg must be attached to the spring to result in a 0.50-s period of oscillation.

To find the mass needed for a 0.50-s period of oscillation, we can use the formula for the period of a mass-spring system: T = 2π√(m/k)
Where T is the period, m is the mass attached to the spring, and k is the spring constant.

We know that when a 0.60-kg mass is attached to the spring, the spring stretches by 17 cm. This means that the spring constant can be found using Hooke's law:
F = kx

Where F is the force applied to the spring, x is the displacement from the equilibrium position, and k is the spring constant. Since the mass is at rest when it is attached to the spring, the force applied is equal to the weight of the mass:

F = mg
Where g is the acceleration due to gravity (9.8 m/s^2). Therefore:

\(k = F/x = mg/x = (0.60 kg)(9.8 m/s^2)/(0.17 m) = 35.294 N/m\)

Now we can solve for the mass needed for a 0.50-s period of oscillation:

\(T = 2π√(m/k)0.50 s = 2π√(m/35.294 N/m)m = (0.50 s/2π)^2(35.294 N/m) = 0.92 kg\)

Therefore, a mass of approximately 0.92 kg (with two significant figures) must be attached to the spring to result in a 0.50-s period of oscillation.

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To transfer a satellite from a circular orbit to an elliptical orbit, the rocket motor must do work equal to the change in the satellite's potential energy. This is because the potential energy of the satellite is directly related to its distance from the center of the planet.

As the satellite moves from a circular orbit to an elliptical orbit, its distance from the center of the planet changes, which results in a change in its potential energy.

The amount of work required to change the potential energy of the satellite can be calculated using the following formula: Work = ∆PE = GMm(1/a - 1/b), where G is the gravitational constant, M is the mass of the planet, m is the mass of the satellite, a is the initial radius of the circular orbit, and b is the maximum radius of the elliptical orbit.

Therefore, the rocket motor must do work equal to GMm(1/a - 1/b) to transfer the satellite from the circular orbit to the elliptical orbit.

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Answer:

88.89kg

Explanation:

The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.

For a 1.00 m (100 cm) crumple zone, about 200 kN of deformation is needed in order to keep the passengers safest.

Crumple zones, also known as crush zones or crash zones, are structural safety features used in vehicles, primarily in automobiles, to extend the time before a change in velocity and consequently momentum results from the impact during a collision by means of a controlled deformation.

In recent years, they have also been added to trains and railcars. As the average force delivered to occupants is inversely proportional to the time over which it is applied, crumple zones are intended to extend the duration over which the overall force from the change in momentum is applied to a person.

The equation for the impulse here is:

F Δt = m Δv

where, v is the velocity and m is the mass.

The survival rate of dummy experiments shows about 90% for a 1 m crumple zone. Hence, a deformation of 200-300 kN is needed to keep the passengers safest.

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The see saw would move in the direction of the girl.

We know that the moment can be obtained as the product of the mass and the distance that have been covered. According to the principle of the moments. We know that the sum of the clockwise moments is equal to the sum of the anti clockwise moments.

In the case of see saw that we have here, we can see that it is moving towards the position of the girl and that would be the direction of the weight as shown in the figure that have been shown above.

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Thus, simulated freefall is a method of creating zero gravity conditions by allowing a spacecraft to travel in orbit, resulting in a constant state of freefall. During this process, the gravitational pull of the Earth and the centripetal force generated by the spacecraft’s motion are balanced, resulting in a state of weightlessness or zero gravity inside the spacecraft.

Simulated free fall is a process that is used to create zero gravity conditions in space. It is done by allowing a spacecraft to travel in an orbit, which results in a constant state of freefall. The conditions in a spacecraft during a simulated freefall are similar to those in a state of zero gravity. In simulated freefall, the spacecraft moves at a speed that allows it to remain in orbit while constantly falling towards the Earth. During this process, the gravitational pull of the Earth and the centripetal force that is generated by the spacecraft’s motion are balanced. This balance results in a state of weightlessness or zero gravity inside the spacecraft. In addition to being used for research and experimentation, simulated freefall is also used to train astronauts for spaceflight. By creating a zero gravity environment on Earth, astronauts can get a feel for what it will be like to work and live in space. They can practice tasks such as moving around and handling equipment, which are much different in zero gravity than they are on Earth.

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After a gamma ray is produced in the core of the sun, it will typically travel outward through the layers of the sun's interior. As it moves through these layers, it will likely interact with other particles and lose energy. Eventually, it will reach the sun's surface and be emitted into space as part of the sun's overall radiation output.

A gamma ray is produced in the core of the sun. After that, the gamma ray goes through several processes, including:

1. Photon Scattering: The gamma ray, being a high-energy photon, interacts with charged particles like protons and electrons in the solar core, changing direction and losing energy through scattering.

2. Conversion to Lower-Energy Photons: As the gamma ray scatters and loses energy, it is converted into lower-energy photons, such as X-rays, ultraviolet, visible light, and infrared radiation.

3. Radiative Transfer: Lower-energy photons gradually make their way to the outer layers of the sun through a process called radiative transfer, which involves multiple scattering events and absorption/re-emission processes.

4. Reaching the Photosphere: The photons eventually reach the photosphere, which is the visible surface of the sun. This process takes thousands of years due to the numerous interactions the photons go through during their journey.

5. Emission into Space: Once the photons reach the photosphere, they are emitted as sunlight and travel through space, eventually reaching Earth and other celestial bodies.

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